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  • Object Oriented PHP books

    - by user275074
    Hi, I've realised just how rusty my knowledge of PHP 5 and advanced PHP programming is after completing some questions for a test. I seriously need to read a book or something. Any recommendations for PHP 5 books?

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  • PHP: cannot matching string "<br />

    - by Patrick
    hi, I'm having problems with string matching in PHP. I've 2 html elements in my page, I've copy pasted here the content with Firebug <div class="field-item odd"> <div class="field-label-inline-first"> Year:</div> 2009 </div> <div class="field-item odd"> <div class="field-label-inline-first"> Synopsis:</div> &lt;br /&gt; </div> This php line works perfectly (the element with 2009 is detected) <?php if ($items[0]['view'] == '2009') : echo "ok"; ?> However I'm not able to match the string containing element: <?php if ($items[0]['view'] == '<br />') : echo "ok"; ?> //doesn't work <?php if ($items[0]['view'] == '&lt;br /&gt;') : echo "ok"; ?> //again doesn't work any tip ? To give you some context: The strings are produced by CKEditor, an editor I'm using in my Drupal back-end. When I leave empty this editor, the tag is displayed on the string as plain text (because I set "plain text" as formatting option in the back-end) Thanks

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  • Pass PHP variables without being seen when working with a database generated list

    - by Wilcoholic
    Looking for any help regarding the problem. Here's the deal: I have a database that has a teams table and it contains team_id. On one of my pages, I generate a list of links that contain the team_id of the creator in their get URL. I need the team_id on the next page but can't figure out how to pass it through any other way. Using a form and POST isn't an option because this method would only pass through the last links data on the list. Storing in a session isn't an option either because there is no way to discretely pass the the variables I need to a function to set the session variables. I have tried and it can pretty easily be viewed from viewing the source code. So here's some sample code to see exactly what I'm dealing with. <? if(mysql_num_rows($result2)>0){ ?> <a class="fltrt btn btn-danger btn-small" onclick="test()" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=cancel">Cancel Match</a> <?}else{?> <a class="fltrt btn btn-success btn-small" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=accept">Accept Match</a> <?} ?> The code above is generated multiple times on a page via a while loop that was excluded. I want to pass the match_id and team_id variables without being seen anywhere. If I made this a form, it wouldn't pass the correct variables unless there is only one result at the time (not likely). I'm sure there has to be an easy method that is eluding me, so please share thoughts on how to solve this. I feel as though I am not explaining it well enough, but it's not really easy to explain. I basically want something that works like GET but acts like POST and can be hidden from people viewing source code or link locations. Thanks

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  • how to make PHP lists all Linux Users?

    - by Data-Base
    Hello I want to build a php based site that (automate) some commands on my Ubuntu Server first thing I did was going to the file (sudoers) and add the user www-data so I can execute php commands with root privileges! # running the web apps with root power!!! www-data ALL=(ALL) NOPASSWD: ALL then my PHP code was <?php $command = "cat /etc/passwd | cut -d\":\" -f1"; echo 'running the command: <b>'.$command."</b><br />"; echo exec($command); ?> it returns only one user (the last user) !!! how to make it return all users? thank you

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  • jQuery, Ajax & PHP submit multiple forms dilemma

    - by user557563
    This is a very simple form that I have found on the web (as I am a jQuery beginner). <!-- this is my jquery --> <script> $(document).ready(function(){ $("form#submit_wall").submit(function() { var message_wall = $('#message_wall').attr('value'); var id = $('#id').attr('value'); $.ajax({ type: "POST", url: "index.php?leht=pildid", data:"message_wall="+ message_wall + "&id="+ id, cache: false, success: function(){ $("ul#wall").prepend(""+message_wall+"", ""+id+""); $("ul#wall li:first").fadeIn(); alert("Thank you for your comment!"); } }); return false; }); }); </script> <!-- this is my HTML+PHP --> some PHP ... while($row_pilt = mysql_fetch_assoc($select_pilt)){ print <form id="submit_wall"> <label for="message_wall">Share your message on the Wall</label> <input type="text" id="message_wall" /> <input type="hidden" id="id" value="'.(int)$row_pilt['id'].'"> <button type="submit">Post to wall</button> </form> and down below is my PHP script that writes to mySQL. It is a pretty straight forward script. However, it is getting little complicated when I submit it. Since I have more than one form on my page (per WHILE PHP LOOP), thus when I submit - only the FIRST form gets submitted. Furthermore, any other subsequent forms that I submit - data is being copied from the first form. Is there any jQuery functions that clear the data? - or is there a better solution. Thanks, Nick

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  • MySQL, PHP, and Apache errors while connecting to DB

    - by cypherdelton
    I'm having two errors when I test the "mysql_connect()" function in php. I just installed PHP and MySQL from scratch. These errors may be related, so I will post them both here: Warning: mysql_connect() [function.mysql-connect]: Headers and client library minor version mismatch. Headers:50158 Library:50518 in /usr/local/apache2/htdocs/index.php on line 6 Warning: mysql_connect() [function.mysql-connect]: Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) in /usr/local/apache2/htdocs/index.php on line 6 Many websites say to start the mysql server if you are getting error #2. Whenever I execute the command mysqld start --user=mysql I get the error "mysqld: Too many arguments (first extra is 'start'); Adding the "&" to the end of the command makes no difference (I don't know if it is supposed to). Thanks, Cypher Delton

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  • Why won't my PHP script work?

    - by sadicool
    I have a script that reports the following error: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'admin'@'localhost' (using password: YES) in C:\wamp\www\bits\includes\connect.inc.php on line 10 Notice: Undefined variable: l_error in C:\wamp\www\bits\includes\connect.inc.php on line 12 Notice: Undefined variable: l_cannotconnecttodatabase in C:\wamp\www\bits\includes\connect.inc.php on line 12 Why would this be?

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  • Broken php/localhost/something

    - by ghego1
    I was trying to install the mcrypt libraries following this tutorial (http://www.glenscott.co.uk/blog/2011/08/29/install-mcrypt-php-extension-on-mac-os-x-lion/), but something must have gone wrong and now when I load a php page on my localhost I see this: query="SELECT DISTINCT ".$field." as a,".$field2." as b FROM ".$tab." ".$where. " Group by ".$field." order By ".$orderBy; return $this->query; } And all the remaining code of the php page that should get loaded. I've retrieved the previous versions of the private/etc folder and usr/lib/php folder with time machine but it didn't help. And now if I execute sudo pachectl restart it gives me this error: sudo: no valid sudoers sources found, quitting (while before it worked. PS I'm on a mac with Mountain Lion

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  • javascript send one way message to php

    - by user360322
    How can I use javascript to send a one way message to php? I would like to get the browser information from javascript and just send it to php in the background. I know I can get some of this from php, but I'd rather use javascript. Is there a way to do this without a framework like jquery?

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  • I want the actual file name that is returned by a PHP script

    - by Aymon Fournier
    I am writing a python script that downloads a file given by a URL. Unfortuneatly the URL is in the form of a PHP script i.e. www.website.com/generatefilename.php?file=5233 If you visit the link in a browser, you are prompted to download the actual file and extension. I need to send this link to the downloader, but I can't send the downloader the PHP link. How would I get the full file name in a usable variable?

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  • Possibly simple PHP/MYSQL issue with retrieving and showing data

    - by envoys
    I have been racking my brains over this for a while now. Here is the data i have in the sql data base as an example: ID | TYPE | DATA 1 | TXT | TEST 2 | PHP | php 3 | JS | JAVASCRIPT That is just an example, there are multiple listing for TXT, PHP and JS throughout the table. What I want to do is retrive all the data and display it all into separate drop down/select boxes. Meaning, select box one would list all data with type TXT, select box two would list all data with type PHP and select box 3 would list all data with type JS. The only way I have came about doing this is doing individual sql queries for each different type. I know there is a way to do it all in 1 query and then display it the way I want to but I just can't seem to figure out how and I know its going to drive me nuts when someone helps and I see just how they did it. Thanks for the input.

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  • need to loop through a PHP array in JavaScript

    - by user296516
    Hi guys, For example I have a PHP array, such as this one <?php $s= array('a','b','c','d','e','f') ; ?> And I need to loop through it in JavaScript, any ideas how do I do that? for ( i=0 ; i < <?php echo sizeof($s) ?> ; i++) { document.write('<?php echo $s [somehow need to get the 'i' value into here] ?>'); } Any suggestions? Thanks!

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  • Google app engine-php: script handler

    - by Eve
    I try to create php web app using GAE. In the GAE tutorial, "A script handler executes a PHP script to handle the request that matches the URL pattern. The mapping defines a URL pattern to match, and the script to be executed" Now I want to map the url with the file having same name in the folder, e.g. if the url is /hello.* , it will map the file name hello.php in the folder. And if it is /hello1.*, hello1.php in the folder will be responded to the server. I thought this should be done directly by mapping the name of the url with the name in the folder. But if I left empty for the handler in the app.yaml, I got an error. So I want to know how to set up the handler in app.yaml?

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  • trying to use PHP extract() within a function

    - by samuelf
    Hi, I have the two following files: main.php include("functions.php") __EXTRACT(); echo $testvar; functions.php function __EXTRACT(){ extract($_POST, EXTR_SKIP); } However, having a form with a textbox called testvar I can't get the extract function to extract the data.. if I remove the function call and insert it the extract statement directly into main.php it works. The include is not a problem as other functions in it works. Any ideas? Cheers

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  • Execute PHP file in background

    - by Spyric
    I have some php code, that execute for a very long time. I need to realise next scheme: User enter on some page(page 1) This page starts execution of my large PHP script in background .(Every change is writting to database) We sent every N seconds query to database to get current status of execution. I don't want to use exec command because 1000 users makes 1000 php processes. It's not way for me...

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  • PHP Localhost Application connect to server database

    - by Cross Vander
    I want to ask about how to connect my localhost application (C:xampp/htdocs/myproject) to database at my server host (www.someweb.somedomain)? Am I possible to do that? If it is, how to connect it at my php config? Right now my config (server.php) is: <?php $host = "my web IP public:3306"; $user = "root"; $pass = ""; $db = "dispatcherDB"; $conn = mysql_connect($host, $user, $pass) or die ("Cant connect to mySQL"); mysql_select_db($db); ?> what I got: Warning: mysql_connect(): No connection could be made because the target machine actively refused it. in C:\xampp\htdocs\XMS\server.php on line 7 So, what must I filled for $host? I'm trying using website IP, it still can't connect. Maybe there's someone here have experience at this problem? Sorry for my bad English

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  • Javascript in php

    - by user506539
    I have a form where user enters category, it gets inserted into db and it has to go to other page to select an image, after selection image id has to get into category table. I am doing some thing like this <?php error_reporting(E_ALL ^ E_NOTICE); $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mydocair", $con); $ThirdPartyCategoryName =$_POST['ThirdPartyCategoryName']; $checkformembers = mysql_query("SELECT * FROM thirdpartycategorymaster WHERE ThirdPartyCategoryName = '$ThirdPartyCategoryName'"); if(mysql_num_rows($checkformembers) != 0) { header('location:newcat.php?msg=category exists'); } else { $sql="INSERT INTO thirdpartycategorymaster (ThirdPartyCategoryID, ThirdPartyCategoryName) VALUES ('$_POST[ThirdPartyCategoryID]', '$_POST[ThirdPartyCategoryName]' )"; } if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } mysql_close($con); ?> <?php $res = mysql_query("SELECT ThirdPartyCategoryID FROM thirdpartycategorymaster"); while($row = mysql_fetch_array($res)) { "<script type='text/javascript'> if(window.confirm("Do you want to insert image for category?")) { document.location = "imgcat.php?id="<?php echo row2['ThirdPartyCategoryID']; ?>"" } </script>"; } ?>

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