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• problem with network-manager-pptp

  - by Riuzaki90

  I've a problema with the VPA CAble connection of my university... on the website of the university there's a .sh file that set all the variables of the connection in ETC/PPP/PEERS and another .sh file that call the connection...I'm on ubuntu 11.10 and when I run the setup.sh I have this error: impossible to find network-manager-pptp these are the two file that I had talk about: #!/bin/bash echo "Creazione della connessione in corso attendere........." apt-get update apt-get install pptp-linux network-manager-pptp echo -n "Digitare la propria Username: " read USERNAME echo -n "Digitare la propria Password: " read PASSWORD pptpsetup --create UNICAL_Campus_Access --server 160.97.73.253 --username $USERNAME --password $PASSWORD echo 'pty "pptp 160.97.73.253 --nolaunchpppd"' >/etc/ppp/peers/UNICAL_Campus_Access echo 'require-mppe-128' >>/etc/ppp/peers/UNICAL_Campus_Access echo 'file /etc/ppp/options.pptp'>>/etc/ppp/peers/UNICAL_Campus_Access echo 'name '$USERNAME''>>/etc/ppp/peers/UNICAL_Campus_Access echo 'remotename PPTP'>>/etc/ppp/peers/UNICAL_Campus_Access echo 'ipparam UNICAL_Campus_Access'>>/etc/ppp/peers/UNICAL_Campus_Access echo $USERNAME' PPTP '$PASSWORD' *'>>/etc/ppp/chap-secrets rm /etc/ppp/options.pptp echo '###############################################################################'>/etc/ppp/options.pptp echo '# $Id: options.pptp,v 1.3 2006/03/26 23:11:05 quozl Exp $'>>/etc/ppp/options.pptp echo '#'>>/etc/ppp/options.pptp echo '# Sample PPTP PPP options file /etc/ppp/options.pptp'>>/etc/ppp/options.pptp echo '# Options used by PPP when a connection is made by a PPTP client.'>>/etc/ppp/options.pptp echo '# This file can be referred to by an /etc/ppp/peers file for the tunnel.'>>/etc/ppp/options.pptp echo '# Changes are effective on the next connection. See "man pppd".'>>/etc/ppp/options.pptp echo '#'>>/etc/ppp/options.pptp echo '# You are expected to change this file to suit your system. As'>>/etc/ppp/options.pptp echo '# packaged, it requires PPP 2.4.2 or later from http://ppp.samba.org/'>>/etc/ppp/options.pptp echo '# and the kernel MPPE module available from the CVS repository also on'>>/etc/ppp/options.pptp echo '# http://ppp.samba.org/, which is packaged for DKMS as kernel_ppp_mppe.'>>/etc/ppp/options.pptp echo '###############################################################################'>>/etc/ppp/options.pptp echo '# Lock the port'>>/etc/ppp/options.pptp echo 'lock'>>/etc/ppp/options.pptp echo '# Authentication'>>/etc/ppp/options.pptp echo '# We do not need the tunnel server to authenticate itself'>>/etc/ppp/options.pptp echo 'noauth'>>/etc/ppp/options.pptp echo '#We won"t do PAP, EAP, CHAP, or MSCHAP, but we will accept MSCHAP-V2'>>/etc/ppp/options.pptp echo '#(you may need to remove these refusals if the server is not using MPPE)'>>/etc/ppp/options.pptp echo 'refuse-pap'>>/etc/ppp/options.pptp echo 'refuse-eap'>>/etc/ppp/options.pptp echo 'refuse-chap'>>/etc/ppp/options.pptp echo 'refuse-mschap'>>/etc/ppp/options.pptp echo '# Compression Turn off compression protocols we know won"t be used'>>/etc/ppp/options.pptp echo 'nobsdcomp'>>/etc/ppp/options.pptp echo 'nodeflate'>>/etc/ppp/options.pptp echo '# Encryption'>>/etc/ppp/options.pptp echo '# (There have been multiple versions of PPP with encryption support,'>>/etc/ppp/options.pptp echo '# choose with of the following sections you will use. Note that MPPE'>>/etc/ppp/options.pptp echo '# requires the use of MSCHAP-V2 during authentication)'>>/etc/ppp/options.pptp echo '# http://ppp.samba.org/ the PPP project version of PPP by Paul Mackarras'>>/etc/ppp/options.pptp echo '# ppp-2.4.2 or later with MPPE only, kernel module ppp_mppe.o'>>/etc/ppp/options.pptp echo '#{{{'>>/etc/ppp/options.pptp echo '# Require MPPE 128-bit encryption'>>/etc/ppp/options.pptp echo '#require-mppe-128'>>/etc/ppp/options.pptp echo '#}}}'>>/etc/ppp/options.pptp echo '# http://polbox.com/h/hs001/ fork from PPP project by Jan Dubiec'>>/etc/ppp/options.pptp echo '#ppp-2.4.2 or later with MPPE and MPPC, kernel module ppp_mppe_mppc.o'>>/etc/ppp/options.pptp echo '#{{{'>>/etc/ppp/options.pptp echo '# Require MPPE 128-bit encryption'>>/etc/ppp/options.pptp echo '#mppe required,stateless'>>/etc/ppp/options.pptp echo '# }}}'>>/etc/ppp/options.pptp echo "setup di 'UNICAL Campus Access' terminato correttamente" echo "per connettersi eseguire lo script 'UNICAL_Campus_Access.sh' " and the second: #!/bin/bash echo "Connessione alla Rete del Centro Residenziale in corso attendere........." modprobe ppp_mppe pppd call UNICAL_Campus_Access sleep 30 tail -n 8 /var/log/messages echo "Connessione Stabilita" echo -n "Per terminare la connessione premere invio (in alternativa eseguire il commando 'killall pppd'):----> " read CONN killall pppd echo "Connessione terminata" I've correctly installed network-manager-pptp to the latest version...help?

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• LexisNexis and Oracle Join Forces to Prevent Fraud and Identity Abuse

  - by Tanu Sood

  Author: Mark Karlstrand About the Writer:Mark Karlstrand is a Senior Product Manager at Oracle focused on innovative security for enterprise web and mobile applications. Over the last sixteen years Mark has served as director in a number of tech startups before joining Oracle in 2007. Working with a team of talented architects and engineers Mark developed Oracle Adaptive Access Manager, a best of breed access security solution.The world’s top enterprise software company and the world leader in data driven solutions have teamed up to provide a new integrated security solution to prevent fraud and misuse of identities. LexisNexis Risk Solutions, a Gold level member of Oracle PartnerNetwork (OPN), today announced it has achieved Oracle Validated Integration of its Instant Authenticate product with Oracle Identity Management.Oracle provides the most complete Identity and Access Management platform. The only identity management provider to offer advanced capabilities including device fingerprinting, location intelligence, real-time risk analysis, context-aware authentication and authorization makes the Oracle offering unique in the industry. LexisNexis Risk Solutions provides the industry leading Instant Authenticate dynamic knowledge based authentication (KBA) service which offers customers a secure and cost effective means to authenticate new user or prove authentication for password resets, lockouts and such scenarios. Oracle and LexisNexis now offer an integrated solution that combines the power of the most advanced identity management platform and superior data driven user authentication to stop identity fraud in its tracks and, in turn, offer significant operational cost savings. The solution offers the ability to challenge users with dynamic knowledge based authentication based on the risk of an access request or transaction thereby offering an additional level to other authentication methods such as static challenge questions or one-time password when needed. For example, with Oracle Identity Management self-service, the forgotten password reset workflow utilizes advanced capabilities including device fingerprinting, location intelligence, risk analysis and one-time password (OTP) via short message service (SMS) to secure this sensitive flow. Even when a user has lost or misplaced his/her mobile phone and, therefore, cannot receive the SMS, the new integrated solution eliminates the need to contact the help desk. The Oracle Identity Management platform dynamically switches to use the LexisNexis Instant Authenticate service for authentication if the user is not able to authenticate via OTP. The advanced Oracle and LexisNexis integrated solution, thus, both improves user experience and saves money by avoiding unnecessary help desk calls. Oracle Identity and Access Management secures applications, Juniper SSL VPN and other web resources with a thoroughly modern layered and context-aware platform. Users don't gain access just because they happen to have a valid username and password. An enterprise utilizing the Oracle solution has the ability to predicate access based on the specific context of the current situation. The device, location, temporal data, and any number of other attributes are evaluated in real-time to determine the specific risk at that moment. If the risk is elevated a user can be challenged for additional authentication, refused access or allowed access with limited privileges. The LexisNexis Instant Authenticate dynamic KBA service plugs into the Oracle platform to provide an additional layer of security by validating a user's identity in high risk access or transactions. The large and varied pool of data the LexisNexis solution utilizes to quiz a user makes this challenge mechanism even more robust. This strong combination of Oracle and LexisNexis user authentication capabilities greatly mitigates the risk of exposing sensitive applications and services on the Internet which helps an enterprise grow their business with confidence.Resources:Press release: LexisNexis® Achieves Oracle Validated Integration with Oracle Identity Management Oracle Access Management (HTML)Oracle Adaptive Access Manager (pdf)

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• SQL SERVER – Importance of User Without Login

  - by pinaldave

  Some questions are very open ended and it is very hard to come up with exact requirements. Here is one question I was asked in recent User Group Meeting. Question: “In recent version of SQL Server we can create user without login. What is the use of it?” Great question indeed. Let me first attempt to answer this question but after reading my answer I need your help. I want you to help him as well with adding more value to it. Answer: Let us visualize a scenario. An application has lots of different operations and many of them are very sensitive operations. The common practice was to do give application specific role which has more permissions and access level. When a regular user login (not system admin), he/she might have very restrictive permissions. The application itself had a user name and password which means applications can directly login into the database and perform the operation. Developers were well aware of the username and password as it was embedded in the application. When developer leaves the organization or when the password was changed, the part of the application had to be changed where the same username and passwords were used. Additionally, developers were able to use the same username and password and login directly to the same application. In earlier version of SQL Server there were application roles. The same is later on replaced by “User without Login”. Now let us recreate the above scenario using this new “User without Login”. In this case, User will have to login using their own credentials into SQL Server. This means that the user who is logged in will have his/her own username and password. Once the login is done in SQL Server, the user will be able to use the application. Now the database should have another User without Login which has all the necessary permissions and rights to execute various operations. Now, Application will be able to execute the script by impersonating “user without login – with more permissions”. Here there is assumed that user login does not have enough permissions and another user (without login) there are more rights. If a user knows how the application is using the database and their various operations, he can switch the context to user without login making him enable for doing further modification. Make sure to explicitly DENY view definition permission on the database. This will make things further difficult for user as he will have to know exact details to get additional permissions. If a user is System Admin all the details which I just mentioned in above three paragraphs does not apply as admin always have access to everything. Additionally, the method describes above is just one of the architecture and if someone is attempting to damage the system, they will still be able to figure out a workaround. You will have to put further auditing and policy based management to prevent such incidents and accidents. I guess this is my answer. I read it multiple times but I still feel that I am missing something. There should be more to this concept than what I have just described. I have merely described one scenario but there will be many more scenarios where this situation will be useful. Now is your turn to help – please leave a comment with the additional suggestion where exactly “User without Login” will be useful as well did I miss anything when I described above scenario. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Security, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• why my code still cannot connect with database? [closed]

  - by Wen Teng

  package com.mems.travis; import java.util.ArrayList; import java.util.List; import org.apache.http.NameValuePair; import org.apache.http.message.BasicNameValuePair; import org.json.JSONObject; import android.app.Activity; import android.app.AlertDialog; import android.content.DialogInterface; import android.content.Intent; import android.os.AsyncTask; import android.os.Bundle; import android.util.Log; import android.view.View; import android.widget.Button; import android.widget.EditText; import android.widget.RadioButton; public class UserRegister extends Activity { JSONParser jsonParser = new JSONParser(); EditText inputName; EditText inputUsername; EditText inputEmail; EditText inputPassword; RadioButton button1; RadioButton button2; Button button3; int success = 0; // url to create new product private static String url_register_user = "http://192.168.1.100/MEMS/add_user.php"; // JSON Node names private static final String TAG_SUCCESS = "success"; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_user_register); // Edit Text inputName = (EditText) findViewById(R.id.nameTextBox); inputUsername = (EditText) findViewById(R.id.usernameTextBox); inputEmail = (EditText) findViewById(R.id.emailTextBox); inputPassword = (EditText) findViewById(R.id.pwTextBox); // Create button //RadioButton button1 = (RadioButton) findViewById(R.id.studButton); // RadioButton button2 = (RadioButton) findViewById(R.id.shopownerButton); Button button3 = (Button) findViewById(R.id.regSubmitButton); // button click event button3.setOnClickListener(new View.OnClickListener() { public void onClick(View view) { String name = inputName.getText().toString(); String username = inputUsername.getText().toString(); String email = inputEmail.getText().toString(); String password = inputPassword.getText().toString(); if (name.contentEquals("")||username.contentEquals("")||email.contentEquals("")||password.contentEquals("")) { AlertDialog.Builder builder = new AlertDialog.Builder(UserRegister.this); // 2. Chain together various setter methods to set the dialog characteristics builder.setMessage(R.string.nullAlert) .setTitle(R.string.alertTitle); builder.setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int id) { // User clicked OK button } }); // 3. Get the AlertDialog from create() AlertDialog dialog = builder.show(); } else { new RegisterNewUser().execute(); } } }); } class RegisterNewUser extends AsyncTask<String, String, String>{ protected String doInBackground(String... args) { String name = inputName.getText().toString(); String username = inputUsername.getText().toString(); String email = inputEmail.getText().toString(); String password = inputPassword.getText().toString(); // Building Parameters List<NameValuePair> params = new ArrayList<NameValuePair>(); params.add(new BasicNameValuePair("name", name)); params.add(new BasicNameValuePair("username", username)); params.add(new BasicNameValuePair("email", email)); params.add(new BasicNameValuePair("password", password)); // getting JSON Object // Note that create product url accepts POST method JSONObject json = jsonParser.makeHttpRequest(url_register_user, "GET", params); // check log cat for response Log.d("Send Notification", json.toString()); try { int success = json.getInt(TAG_SUCCESS); if (success == 1) { // successfully created product Intent i = new Intent(getApplicationContext(), StudentLogin.class); startActivity(i); finish(); } else { // failed to register } } catch (Exception e) { e.printStackTrace(); } return null; } } }

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• Why do I get "Invalid Column Name" errors in EF4?

  - by camainc

  I am trying to learn Entity Framework 4.0. Disclaimer 1: I am brand new to Entity Framework. I have successfully used LinqToSQL. Disclaimer 2: I am really a VB.Net programmer, so the problem could be in the C# code. Given this code snippet: public int Login(string UserName, string Password) { return _dbContext.Memberships .Where(membership => membership.UserName.ToLower() == UserName.ToLower() && membership.Password == Password) .SingleOrDefault().PrimaryKey; } Why do you suppose I get "Invalid column name" errors? {"Invalid column name 'UserName'.\r\nInvalid column name 'Password'.\r\nInvalid column name 'UserName'.\r\nInvalid column name 'Password'."} Those column names are spelled and cased correctly. I also checked the generated code for the entity in question, and those columns are properties in the entity. The intellisense and code completion also puts the column names into the expression just as they are here. I am stumped by this. Any help would be much appreciated. https://docs.google.com/leaf?id=0B-xLbzoqGvXvNjBmZmNjNDAtY2RhNC00NDA2LWIxNzMtYjhjNTYxMDIyZmZl&hl=en

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• VBA WinHTTPRequest and submitting forms

  - by Hazerider

  Hi. I spent all day yesterday trying to figure out how to submit a form using WinHTTPRequest. I can do it pretty easily with an InternetExplorer object, but the problem is that I need to save a PDF file that gets returned, and I am not sure how to do this with the IE object. Here is the relevant HTML code snippet: <div class="loginHome-left"> <fieldset> <h3>Log in Using</h3> <form> <label for="standardLogin" accesskey="s"> <input name="useLogin" id="standardLogin" value="standard" type="radio" checked="true">Standard Login</label> &nbsp; <label for="rsaSecurID" accesskey="r"> <input name="useLogin" value="rsaSecur" type="radio" id="rsaSecurID" onclick="redirectLogin('ct_logon_securid');return false;">RSA SecurID</label> &nbsp; <label for="employeeNTXP" accesskey="e"> <input name="useLogin" id="employeeNTXP" value="employee" type="radio" onclick="redirectLogin('ct_logon_external_nt');return false; "> Employee Windows Login<br></label> </form> <br> <div class="error">Error: ...</div><br> <form onSubmit="if(validate(this)) {formSubmit();} return false;" name="passwdForm" method="post" action="/UAB/ct_logon"> <input value="custom" name="pageId" type="hidden"> <input value="custom" name="auth_mode" type="hidden"> <input value="/UAB/ct_logon" name="ct_orig_uri" type="hidden"> <INPUT VALUE="" NAME="orig_url" TYPE="hidden"> <input value="" name="lpSp" type="hidden"> <label for="user"> <strong>Username</strong> </label> <input autocomplete="off" name="user" type="text" value="" class="txtFld" onkeypress="return handleEnter(this, event);"> <br> <label for="EnterPassword"> <strong>Password</strong>&nbsp;&nbsp;(<a tabindex="-1" href="/UAB/BCResetWithSecrets">Forgot Your Password?</a>) </label> <input autocomplete="off" name="password" type="password" class="txtFld" onkeypress="return handleEnter(this, event);"> <INPUT id="rememberLogin" name="lpCookie" type="checkbox"> <label for="rememberLogin">Remember My Login Information</label><br> </form> <div class="right"> <br> <input type="image" src="/BC_S/images/bclogin/btn_login.gif" name="" value="Submit" onClick="if(validate(document.forms['passwdForm'])){formSubmit();}return false;"> </div> <div class="clearfix"></div> </fieldset> </div> In order to log in through InternetExplorer, I do the following: Sub TestLogin() Dim ie As InternetExplorer, doc As HTMLDocument, form As HTMLFormElement, inp As Variant Set ie = New InternetExplorer ie.Visible = True ie.navigate "https://URL of the login page" Do Until ie.readyState = READYSTATE_COMPLETE Loop Set doc = ie.document For Each form In doc.forms If InStr(form.innerText, "Password") <> 0 Then form.elements("user").Value = "my_name" form.elements("password").Value = "my_password" Exit For Else End If Next 'This is the unnamed input with an image that is used to submit the form' doc.all(78).Click ie.navigate "https://url of the PDF" Do Until ie.readyState = READYSTATE_COMPLETE Loop Dim filename As String, filenum As Integer filename = "somefile.pdf" filenum = FreeFile Open filename For Binary Access Write As #filenum Write #filenum, doc.DocumentElement.innerText Close #filenum ie.Quit Debug.Print Set ie = Nothing End Sub What I really would like to do is something along the lines of the following: Sub TestLogin3() Dim whr As New WinHttpRequest, postData As String whr.Open "POST", "https://live.barcap.com/UAB/ct_logon", False whr.setRequestHeader "User-Agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)" whr.setRequestHeader "Connection", "Keep-Alive" whr.Send whr.WaitForResponse postData = "user=paschom1&password=change01" 'Or the following?' postData = "user=paschom1&password=change01&orig_url=&pageId=custom&auth_mode=custom&ct_orig_uri=/BC/dispatcher&lpSp=&lpCookie=off" whr.Send postData whr.WaitForResponse Debug.Print whr.responseText End Sub It just refuses to work though. Not sure if I need to use more setRequestHeader with Content-Form or something similar, and if I do, not sure what exactly I am supposed to pass it. If anyone has any advice regarding this, it would be hugely appreciated. I could probably use a perl module to do it, but I would rather keep it all in VBA if possible. Thanks, Marc.

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• Help With Proxy Username & Pass with GeckoFX??!!

  - by John

  Hello, I am trying to set the proxy username and password. I saw this posting (http://geckofx.org/viewtopic.php?id=832) and I thought it might be a similar setting for the username/password, such as : Skybound.Gecko.GeckoPreferences.User["network.proxy.user"] = (user); Skybound.Gecko.GeckoPreferences.User["network.proxy.password"] = (password); But, nothing has worked so far. Can anyone help? I would really appreciate it!!! I am using VB.net if that helps. Thanks!!

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• How to create datetime string in soapui using groovy

  - by Arunkumar

  Hi am using Soapui for testing web services. i need to create a customer record with email address and password. create customer record service contains emailid and password, wen i click the run(submit request) button in create customer record in soapui, i should get the emailid appended with current time of creation and any password. how to do this with groovy?

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• Set Proxy Credential in Web Browser Control

  - by rockacola

  I am working on a legacy code where an application uses AxSHDocVw.AxWebBrowser (NOT System.Windows.Forms.Control) to open up web pages and am extending it to take proxy into considerations. I have following example on http://www.pinvoke.net/default.aspx/wininet/internetsetoption.html to use InternetSetOption() to go through specified proxy and tested that it works. Now the hurdle is I tried everything but failed to pass username and password with following code: //-- Set Proxy Username bool resultF = InternetSetOption(IntPtr.Zero, INTERNET_OPTION_PROXY_USERNAME, username, username.Length+1); var errorF = Marshal.GetLastWin32Error(); //-- Set Proxy Password bool resultG = InternetSetOption(IntPtr.Zero, INTERNET_OPTION_PROXY_PASSWORD, password, password.Length+1); var errorG = Marshal.GetLastWin32Error(); Both resultF and resultG return true and has no errors but it still working. Any hint on what may be happening here? and what method do I have to debug this? Thanks in advance.

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• org.apache.struts2.dispatcher.Dispatcher: Could not find action or result Error

  - by peterwkc

  i tried to code the following simple struts but encounter this error during run time. [org.apache.struts2.dispatcher.Dispatcher] Could not find action or result: No result defined for action com.peter.action.LoginAction and result success index.jsp <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%> <%@ taglib prefix="s" uri="/struts-tags" %> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Struts Tutorial</title> </head> <body> <h2>Hello Struts</h2> <s:form action="login" > <s:textfield name="username" label="Username:" /> <s:password name="password" label="Password:"/> <s:submit /> </s:form> </body> </html> LoginAction.java /** * */ package com.peter.action; //import org.apache.struts2.convention.annotation.Namespace; import org.apache.struts2.convention.annotation.ResultPath; import org.apache.struts2.convention.annotation.Result; import org.apache.struts2.convention.annotation.Action; import com.opensymphony.xwork2.ActionSupport; /** * @author nicholas_tse * */ //@Namespace("/") To define URL namespace @ResultPath("/") // To instruct Struts where to search result page(jsp) public class LoginAction extends ActionSupport { private String username, password; /** * */ private static final long serialVersionUID = -8992836566328180883L; /** * */ public LoginAction() { // TODO Auto-generated constructor stub } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Override @Action(value = "login", results = {@Result(name="success", location="welcome.jsp")}) public String execute() { return SUCCESS; } } /* Remove * struts2-gxp-plugin * struts2-portlet-plugin * struts2-jsf-plugin * struts2-osgi-plugin and its related osgi-plugin * struts-rest-plugin * * Add * velocity-tools-view * * */ web.xml <?xml version="1.0" encoding="UTF-8"?> <web-app id="WebApp_ID" version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"> <display-name>Struts</display-name> <!-- org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter org.apache.struts2.dispatcher.FilterDispatcher --> <filter> <filter-name>Struts_Filter</filter-name> <filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class> <init-param> <param-name>actionPackages</param-name> <param-value>com.peter.action</param-value> </init-param> </filter> <filter-mapping> <filter-name>Struts_Filter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> </web-app> Besides the runtime error, there is deployment error which is ERROR [com.opensymphony.xwork2.util.finder.ClassFinder] (MSC service thread 1-2) Unable to read class [WEB-INF.classes.com.peter.action.LoginAction]: Could not load WEB-INF/classes/com/peter/action/LoginAction.class - [unknown location] at com.opensymphony.xwork2.util.finder.ClassFinder.readClassDef(ClassFinder.java:785) [xwork-core-2.3.1.2.jar:2.3.1.2] AFAIK, the scanning methodology of struts will scan the default packages named struts2 for any annotated class but i have instructed struts2 to scan in com.peter.action using init-param but still unable to find the class. It is pretty weird. Please help. Thanks.

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• NSData-AES Class Encryption/Decryption in Cocoa

  - by David Schiefer

  hi, I am attempting to encrypt/decrypt a plain text file in my text editor. encrypting seems to work fine, but the decrypting does not work, the text comes up encrypted. I am certain i've decrypted the text using the word i encrypted it with - could someone look through the snippet below and help me out? Thanks :) Encrypting: NSAlert *alert = [NSAlert alertWithMessageText:@"Encryption" defaultButton:@"Set" alternateButton:@"Cancel" otherButton:nil informativeTextWithFormat:@"Please enter a password to encrypt your file with:"]; [alert setIcon:[NSImage imageNamed:@"License.png"]]; NSSecureTextField *input = [[NSSecureTextField alloc] initWithFrame:NSMakeRect(0, 0, 300, 24)]; [alert setAccessoryView:input]; NSInteger button = [alert runModal]; if (button == NSAlertDefaultReturn) { [[NSUserDefaults standardUserDefaults] setObject:[input stringValue] forKey:@"password"]; NSData *data; [self setString:[textView textStorage]]; NSMutableDictionary *dict = [NSDictionary dictionaryWithObject:NSPlainTextDocumentType forKey:NSDocumentTypeDocumentAttribute]; [textView breakUndoCoalescing]; data = [[self string] dataFromRange:NSMakeRange(0, [[self string] length]) documentAttributes:dict error:outError]; NSData*encrypt = [data AESEncryptWithPassphrase:[input stringValue]]; [encrypt writeToFile:[absoluteURL path] atomically:YES]; Decrypting: NSAlert *alert = [NSAlert alertWithMessageText:@"Decryption" defaultButton:@"Open" alternateButton:@"Cancel" otherButton:nil informativeTextWithFormat:@"This file has been protected with a password.To view its contents,enter the password below:"]; [alert setIcon:[NSImage imageNamed:@"License.png"]]; NSSecureTextField *input = [[NSSecureTextField alloc] initWithFrame:NSMakeRect(0, 0, 300, 24)]; [alert setAccessoryView:input]; NSInteger button = [alert runModal]; if (button == NSAlertDefaultReturn) { NSLog(@"Entered Password - attempting to decrypt."); NSMutableDictionary *dict = [NSDictionary dictionaryWithObject:NSPlainTextDocumentType forKey:NSDocumentTypeDocumentOption]; NSData*decrypted = [[NSData dataWithContentsOfFile:[self fileName]] AESDecryptWithPassphrase:[input stringValue]]; mString = [[NSAttributedString alloc] initWithData:decrypted options:dict documentAttributes:NULL error:outError];

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• Subsonic 3, MySql, won't update record.

  - by Warspawn

  [WebMethod] public string GetAuthToken(string username, string password) { var db = new LogicDB(); //var results = from u in db.Users // where u.Username == username && u.Password == password // select u; User u = db.Select .From<User>() .Where(UsersTable.UsernameColumn).IsEqualTo(username) .And(UsersTable.PasswordColumn).IsEqualTo(password) .ExecuteSingle<User>(); if (u == null) { return "{'success': false, 'reason': 'Invalid username and/or password.'}"; } else { // really there should only be one match... Guid code = Guid.NewGuid(); u.Securitycode = code.ToString(); u.Securityexp = System.DateTime.Now.AddHours(24); //u.Save(db.Provider); return "{'id':'" + u.Id.ToString() + "', 'code':'" + code.ToString() + "', 'exp':'" + u.Securityexp.ToString() + "'}" + "\n\n<br/><br/>" + u.GetDirtyColumns().ToArray().ToString(); } } When I run that, I keep getting: System.Collections.Generic.KeyNotFoundException: The given key was not present in the dictionary. This is when u.Save(db.Provider); is uncommented. And happens even with just u.Save(); or using the linq query above results instead.

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• Brute force characters into a textbox in c#

  - by Fred Dunly

  Hey everyone, I am VERY new to programming and the only language I know is C# So I will have to stick with that... I want to make a program that "test passwords" to see how long they would take to break with a basic brute force attack. So what I did was make 2 text boxes. (textbox1 and textbox2) and wrote the program so if the text boxes had the input, a "correct password" label would appear, but i want to write the program so that textbox2 will run a brute force algorithm in it, and when it comes across the correct password, it will stop. I REALLY need help, and if you could just post my attached code with the correct additives in it that would be great. The program so far is extremely simple, but I am very new to this, so. Thanks in advance. private void textBox2_TextChanged(object sender, EventArgs e) { } private void button1_Click(object sender, EventArgs e) { if (textBox2.Text == textBox1.Text) { label1.Text = "Password Correct"; } else { label1.Text = "Password Wrong"; } } private void label1_Click(object sender, EventArgs e) { } } } `

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• How to reproduce System.Security.Cryptography.SHA1Managed result in Python

  - by joetyson

  Here's the deal: I'm moving a .NET website to Python. I have a database with passwords hashed using the System.Security.Cryptography.SHA1Managed utility. I'm creating the hash in .NET with the following code: string hashedPassword = Cryptographer.CreateHash("MYHasher", userInfo.Password); The MYHasher block looks like this: <add algorithmType="System.Security.Cryptography.SHA1Managed, mscorlib, Version=2.0.0.0, Culture=neutral, PublicKeyToken=blahblahblah" saltEnabled="true" type="Microsoft.Practices.EnterpriseLibrary.Security.Cryptography.HashAlgorithmProvider, Microsoft.Practices.EnterpriseLibrary.Security.Cryptography, Version=3.0.0.0, Culture=neutral, PublicKeyToken=daahblahdahdah" name="MYHasher" /> So for a given password, I get back and store in the database a 48 byte salted sha1. I assume the last 8 bytes are the salt. I have tried to reproduce the hashing process in python by doing a sha1(salt + password) and sha1(password + salt) but I'm having no luck. My question to you: How are the public keys being used? How is the password rehashed using the salt. How is the salt created? (e.g., When I say saltEnabled="true", what extra magic happens?) I need specific details that don't just reference other .NET libraries, I'm looking for the actual operational logic that happens in the blackbox. Thanks!

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• ExtJS: Login with 'Remember me' functionality

  - by Chau

  I'm trying to create a simple login window with the very common 'Remember me' functionality. The login validation is done AJAX style, thus the browser won't remember my input. My approach is to use the built-in state functionality, but how to use it confuses me. Ext.state.Manager.setProvider(new Ext.state.CookieProvider({ expires: new Date(new Date().getTime()+(1000*60*60*24*7)), //7 days from now })); ... { xtype: 'textfield', fieldLabel: 'User name', id: 'txt-username', stateful: true, stateId: 'username' }, { xtype: 'textfield', fieldLabel: 'Password', id: 'txt-password', inputType: 'password', stateful: true, stateId: 'password' }, { xtype: 'button', text: 'Validate', stateEvents: 'click' } I know I have to implement the getState method, but on what component (my guess is on the two textfields)? Another thing I fail to realize is, how is my click event on the button connected to the state properties of my textfields?

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• How to Send user to two different web pages when login

  - by Pradeep

  protected static Boolean Authentication(string username, string password) { string sqlstring; sqlstring = "Select Username, Password, UserType from Userprofile WHERE Username='" + username + "' and Password ='" + password + "'"; // create a connection with sqldatabase System.Data.SqlClient.SqlConnection con = new System.Data.SqlClient.SqlConnection( "Data Source=PRADEEP-LAPTOP\\SQLEXPRESS;Initial Catalog=BookStore;Integrated Security=True"); // create a sql command which will user connection string and your select statement string System.Data.SqlClient.SqlCommand comm = new System.Data.SqlClient.SqlCommand(sqlstring, con); // create a sqldatabase reader which will execute the above command to get the values from sqldatabase System.Data.SqlClient.SqlDataReader reader; // open a connection with sqldatabase con.Open(); // execute sql command and store a return values in reade reader = comm.ExecuteReader(); // check if reader hase any value then return true otherwise return false if (reader.Read()) return true; else return false; } Boolean blnresult; blnresult = Authentication(Login2.UserName, Login2.Password); if (blnresult == true) { Session["User_ID"] = getIDFromName(Login2.UserName); Session["Check"] = true; Session["Username"] = Login2.UserName; Response.Redirect("Index.aspx"); } so a user like Staff or even Administrators loging to same Index.aspx. i want to change it to different web pages. how to change sites for each user types. i have seperate user types. and i have taken UserType in the Authentication function.

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• Get paperclip to crop the image without validating

  - by Micke

  Hello fellow stackoverflow members. I have been following this guide to enable users to have their own avatar. But i have bumped in to a litle problem. When the user is cropping the image the model tries to validate all my validations. My user model looks like this: class User < ActiveRecord::Base has_attached_file :avatar, :styles => { :small => "100x100>", :large => "500x500>" }, :processors => [:cropper] attr_accessor :password, :crop_x, :crop_y, :crop_w, :crop_h attr_accessible :crop_x, :crop_y, :crop_w, :crop_h validates_confirmation_of :password validates_presence_of :password And when the user runs the crop updating script the user model tries to validate the password. But because i have no password field on the cropping page it can't validate it. Here is the updating of the crop: @user = User.find(current_user.id) if @user.update_attributes(params[:user]) flash[:notice] = "Successfully updated user." end How can i bypass this in a easy and clean way?

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• Salt, passwords and security

  - by Jonathan

  I've read through many of the questions on SO about this, but many answers contradict each other or I don't understand. You should always store a password as a hash, never as plain text. But should you store the salt (unique for each user) next to the hashed password+salt in the database. This doesn't seem very clever to me as couldn't someone gain access to the database, look for says the account called Admin or whatever and then work out the password from that?

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• Problem with a test method in Yii web services

  - by Conrad

  Hi There, Is there anyone here who might be familiar with web services in the yii framework? I declared the following test method: /** * Send a single SMS message * * @param string $username Username * @param string $password Password * @param string $identifier Valid Identifier to use * @param string $mobileNumber Mobile Number to send message to * @param string $message Message to send * @return string 'OK' on success, error message on failure * @soap */ public function singleSms($username, $password, $identifier,$mobileNumber, $message){ return "username=$username, pwd=$password, source=$identifier, mobno=$mobileNumber, msg=$message"; } But when I try to call this method I get the following response: - - WSDL - SOAP-ERROR: Parsing WSDL: Couldn't load from 'http://sms.chillnethosting.co.za/index.php?r=sms/webservice' : Start tag expected, '<' not found The WSDL generates when I call my URL: Web Service URL Any Ideas?

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• How to pass a random User/Pass (for Basic Authentication) with JMeter?

  - by Pure.Krome

  Hi folks, I'm using JMeter to stress test an API. I've got Basic Authentication set up - seems to be working great. Now, i'm trying to randomize the credentials that JMeter passes across the wire. So, there's two ways I know I can do this. Add a custom HTTP Header (via an HTTP Header Manager Element) and set then value to the random fields (ie. something I've read in from a csv file) Use the HTTP Authorization Manager Element and pass in the username and password there. Now, if I try and use method (1) above, I need to create the following header/data :- Authorization: Basic <some Base64 encoded string in the format username:password> eg. Authorization: Basic OnVzZXIxOnBhc3Mx Kewl. simple. BUT that header value is not getting passed across the wire :( I can add any other header type and it's passed across the wire.. hmm .. ok then .. lets try method (2). Now that works .. but I can only hardcode in the username & password. I can't see how I can pass in a username VARIABLE (ie. ${usernmae} ) or a password VARIABLE (ie. ${password} ).... If it's hardcoded, then the server correctly replies with the correct page/data. so .. can someone please help?

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• Preferred place to store username

  - by Rudiger

  I am dealing with a single username and password in an App, I'm storing the password in the keychain for security but where best to store the username? In NSUserDefaults, CFPreferences or is there a way to retrieve it out of the keychain along with the password. Later on there might be two entries in the keychain so I think this might be out of the question. Or does it not matter at all?

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• Cannot login to Activeadmin after gem update

  - by user1883793

  After bundle update I cannot login to my Activeadmin, here is the log. Is it because the unpermitted params? do I need to config strong parameter to make admin login work? I already have this code for devise: def configure_permitted_parameters devise_parameter_sanitizer.for(:sign_in) { |u| u.permit(:email, :password, :remember_me) } devise_parameter_sanitizer.for(:sign_up) { |u| u.permit(:username, :email, :password) } end Started POST "/admin/login" for 127.0.0.1 at 2013-10-30 22:33:25 +1300 Processing by ActiveAdmin::Devise::SessionsController#create as HTML Parameters: {"utf8"=>"?", "authenticity_token"=>"MhoM/R/oVfad/iiov2zpqfoJ5XOSLda6rTl/V2cMIZE=", "admin_user"=>{"email"=>"[email protected]", "password"=>"[FILTERED]", "remember_me"=>"0"}, "commit"=>"Login"} Completed 401 Unauthorized in 0.6ms Processing by ActiveAdmin::Devise::SessionsController#new as HTML Parameters: {"utf8"=>"?", "authenticity_token"=>"MhoM/R/oVfad/iiov2zpqfoJ5XOSLda6rTl/V2cMIZE=", "admin_user"=>{"email"=>"[email protected]", "password"=>"[FILTERED]", "remember_me"=>"0"}, "commit"=>"Login"} Unpermitted parameters: email, password, remember_me Rendered /home/jcui/.rvm/gems/ruby-1.9.3-p194/gems/activeadmin-0.6.2/app/views/active_admin/devise/shared/_links.erb (0.6ms) Rendered /home/jcui/.rvm/gems/ruby-1.9.3-p194/gems/activeadmin-0.6.2/app/views/active_admin/devise/sessions/new.html.erb within layouts/active_admin_logged_out (118.2ms) Completed 200 OK in 130.7ms (Views: 129.9ms | ActiveRecord: 0.0ms | Solr: 0.0ms)

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• Memory Troubles with UIImagePicker

  - by Dan Ray

  I'm building an app that has several different sections to it, all of which are pretty image-heavy. It ties in with my client's website and they're a "high-design" type outfit. One piece of the app is images uploaded from the camera or the library, and a tableview that shows a grid of thumbnails. Pretty reliably, when I'm dealing with the camera version of UIImagePickerControl, I get hit for low memory. If I bounce around that part of the app for a while, I occasionally and non-repeatably crash with "status:10 (SIGBUS)" in the debugger. On low memory warning, my root view controller for that aspect of the app goes to my data management singleton, cruises through the arrays of cached data, and kills the biggest piece, the image associated with each entry. Thusly: - (void)didReceiveMemoryWarning { // Releases the view if it doesn't have a superview. [super didReceiveMemoryWarning]; UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Low Memory Warning" message:@"Cleaning out events data" delegate:nil cancelButtonTitle:@"All right then." otherButtonTitles:nil]; [alert show]; [alert release]; NSInteger spaceSaved; DataManager *data = [DataManager sharedDataManager]; for (Event *event in data.eventList) { spaceSaved += [(NSData *)UIImagePNGRepresentation(event.image) length]; event.image = nil; spaceSaved -= [(NSData *)UIImagePNGRepresentation(event.image) length]; } NSString *titleString = [NSString stringWithFormat:@"Saved %d on event images", spaceSaved]; for (WondrMark *mark in data.wondrMarks) { spaceSaved += [(NSData *)UIImagePNGRepresentation(mark.image) length]; mark.image = nil; spaceSaved -= [(NSData *)UIImagePNGRepresentation(mark.image) length]; } NSString *messageString = [NSString stringWithFormat:@"And total %d on event and mark images", spaceSaved]; NSLog(@"%@ - %@", titleString, messageString); // Relinquish ownership any cached data, images, etc that aren't in use. } As you can see, I'm making a (poor) attempt to eyeball the memory space I'm freeing up. I know it's not telling me about the actual memory footprint of the UIImages themselves, but it gives me SOME numbers at least, so I can see that SOMETHING'S happening. (Sorry for the hamfisted way I build that NSLog message too--I was going to fire another UIAlertView, but realized it'd be more useful to log it.) Pretty reliably, after toodling around in the image portion of the app for a while, I'll pull up the camera interface and get the low memory UIAlertView like three or four times in quick succession. Here's the NSLog output from the last time I saw it: 2010-05-27 08:55:02.659 EverWondr[7974:207] Saved 109591 on event images - And total 1419756 on event and mark images wait_fences: failed to receive reply: 10004003 2010-05-27 08:55:08.759 EverWondr[7974:207] Saved 4 on event images - And total 392695 on event and mark images 2010-05-27 08:55:14.865 EverWondr[7974:207] Saved 4 on event images - And total 873419 on event and mark images 2010-05-27 08:55:14.969 EverWondr[7974:207] Saved 4 on event images - And total 4 on event and mark images 2010-05-27 08:55:15.064 EverWondr[7974:207] Saved 4 on event images - And total 4 on event and mark images And then pretty soon after that we get our SIGBUS exit. So that's the situation. Now my specific questions: THE time I see this happening is when the UIPickerView's camera iris shuts. I click the button to take the picture, it does the "click" animation, and Instruments shows my memory footprint going from about 10mb to about 25mb, and sitting there until the image is delivered to my UIViewController, where usage drops back to 10 or 11mb again. If we make it through that without a memory warning, we're golden, but most likely we don't. Anything I can do to make that not be so expensive? Second, I have NSZombies enabled. Am I understanding correctly that that's actually preventing memory from being freed? Am I subjecting my app to an unfair test environment? Third, is there some way to programmatically get my memory usage? Or at least the usage for a UIImage object? I've scoured the docs and don't see anything about that.

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• Credentials can not be delegated - Alfresco Share

  - by leftcase

  I've hit a brick wall configuring Alfresco 4.0.d on Redhat 6. I'm using Kerberos authentication, it seems to be working normally, and single sign on is working on the main alfresco app itself. I've been through the configuration steps to get the share app working, but try as I may, I keep getting this error in catalina.out each time a browser accesses http://server:8080/share along with a 'Windows Security' password box. WARN [site.servlet.KerberosSessionSetupPrivilegedAction] credentials can not be delegated! Here's what I've done so far: Using AD users and computers, selected the alfrescohttp account, and selected 'trust this user for delegation to any service (Kerberos only). Copied /opt/alfresco-4.0.d/tomcat/shared/classes/alfresco/web-extension/share-config-custom.xml.sample to share-config-custom.xml and edited like this: <config evaluator="string-compare" condition="Kerberos" replace="true"> <kerberos> <password>*****</password> <realm>MYDOMAIN.CO.UK</realm> <endpoint-spn>HTTP/[email protected]</endpoint-spn> <config-entry>ShareHTTP</config-entry> </kerberos> </config> <config evaluator="string-compare" condition="Remote"> <remote> <keystore> <path>alfresco/web-extension/alfresco-system.p12</path> <type>pkcs12</type> <password>alfresco-system</password> </keystore> <connector> <id>alfrescoCookie</id> <name>Alfresco Connector</name> <description>Connects to an Alfresco instance using cookie-based authentication</description> <class>org.springframework.extensions.webscripts.connector.AlfrescoConnector</class> </connector> <endpoint> <id>alfresco</id> <name>Alfresco - user access</name> <description>Access to Alfresco Repository WebScripts that require user authentication</description> <connector-id>alfrescoCookie</connector-id> <endpoint-url>http://localhost:8080/alfresco/wcs</endpoint-url> <identity>user</identity> <external-auth>true</external-auth> </endpoint> </remote> </config> Setup the /etc/krb5.conf file like this: [logging] default = FILE:/var/log/krb5libs.log kdc = FILE:/var/log/krb5kdc.log admin_server = FILE:/var/log/kadmind.log [libdefaults] default_realm = MYDOMAIN.CO.UK default_tkt_enctypes = rc4-hmac default_tgs_enctypes = rc4-hmac forwardable = true proxiable = true [realms] MYDOMAIN.CO.UK = { kdc = mydc.mydomain.co.uk admin_server = mydc.mydomain.co.uk } [domain_realm] .mydc.mydomain.co.uk = MYDOMAIN.CO.UK mydc.mydomain.co.uk = MYDOMAIN.CO.UK /opt/alfresco-4.0.d/java/jre/lib/security/java.login.config is configured like this: Alfresco { com.sun.security.auth.module.Krb5LoginModule sufficient; }; AlfrescoCIFS { com.sun.security.auth.module.Krb5LoginModule required storeKey=true useKeyTab=true keyTab="/etc/alfrescocifs.keytab" principal="cifs/server.mydomain.co.uk"; }; AlfrescoHTTP { com.sun.security.auth.module.Krb5LoginModule required storeKey=true useKeyTab=true keyTab="/etc/alfrescohttp.keytab" principal="HTTP/server.mydomain.co.uk"; }; com.sun.net.ssl.client { com.sun.security.auth.module.Krb5LoginModule sufficient; }; other { com.sun.security.auth.module.Krb5LoginModule sufficient; }; ShareHTTP { com.sun.security.auth.module.Krb5LoginModule required storeKey=true useKeyTab=true keyTab="/etc/alfrescohttp.keytab" principal="HTTP/server.mydomain.co.uk"; }; And finally, the following settings in alfresco-global.conf authentication.chain=kerberos1:kerberos,alfrescoNtlm1:alfrescoNtlm kerberos.authentication.real=MYDOMAIN.CO.UK kerberos.authentication.user.configEntryName=Alfresco kerberos.authentication.cifs.configEntryName=AlfrescoCIFS kerberos.authentication.http.configEntryName=AlfrescoHTTP kerberos.authentication.cifs.password=****** kerberos.authentication.http.password=***** kerberos.authentication.defaultAdministratorUserNames=administrator ntlm.authentication.sso.enabled=true As I say, I've hit a brick wall with this and I'd really appreciate any help you can give me! This question is also posted on the Alfresco forum, but I wondered if any folk here on serverfault have come across similar implementation challenges?

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• storing user info/pass in web.config authentication

  - by Tomaszewski

  Hello, I am trying to write a simple internal app with some simple authentication. I'm also trying to make this quick and learn about the forms authentication via web.config. So i have my authentication working if I hard code my 'user name' and 'password' into C# code and do a simple conditional. However, I'm having a tough time storing the a user/pass to be checked against in the web.config file. The MSDN manual says to put this into the web.config: <authentication mode="Forms"> <forms loginUrl="login.aspx"> <credentials passwordFormat="SHA1"> <user name="user1" password="27CE4CA7FBF00685AF2F617E3F5BBCAFF7B7403C" /> <user name="user2" password="D108F80936F78DFDD333141EBC985B0233A30C7A" /> <user name="user3" password="7BDB09781A3F23885CD43177C0508B375CB1B7E9"/> </credentials> </forms> </authentication> However, the minute I add 'credentials' into the 'authentication' section, I get this error: Server Error in '/' Application. Configuration Error Description: An error occurred during the processing of a configuration file required to service this request. Please review the specific error details below and modify your configuration file appropriately. Parser Error Message: Unrecognized element 'credentials'. Source Error: Line 44: <authentication mode="Forms"> Line 45: <forms loginUrl="login.aspx" /> Line 46: <credentials> Line 47: Line 48: </credentials> Source File: C:\inetpub\wwwroot\asp\projects\passwordCatalog\passwordCatalog\web.config Line: 46 So my question is, how and where would I add the following in the web.config file? <credentials passwordFormat="SHA1"> <user name="johndoe" password="mypass123" /> </credentials>

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