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• What is the fastest way to pull a few element values out of XML files in Perl?

  - by Anon Guy

  I have a bunch of XML files that are about 1-2 megabytes in size. Actually, more than a bunch, there are millions. They're all well-formed and many are even validated against their schema (confirmed with libxml2). All were created by the same app, so they're in a consistent format (though this could theoretically change in the future). I want to check the values of one element in each file from within a Perl script. Speed is important (I'd like to take less than a second per file) and as noted I already know the files are well-formed. I am sorely tempted to simply 'open' the files in Perl and scan through until I see the element I am looking for, grab the value (which is near the start of the file), and close the file. On the other hand, I could use an XML parser (which might protect me from future changes to the XML formatting) but I suspect it will be slower than I'd like. Can anyone recommend an appropriate approach and/or parser? Thanks in advance.

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• Flash gets XML but the values are wrong, as3

  - by VideoDnd

  Flash receives the XML, but the values are wrong. How do I fix this? Problem I can see the XML loaded with no errors, but my output is way off. It's as though it's not receiving any values. Numbers in the output window and animation move rapidly. The Flash file runs as if it's variables where set to zero. I changed the order of my code, but that didn't help with this. Please explain how I can correct this. SWF //load xml var myXML:XML; var myLoader:URLLoader = new URLLoader(); myLoader.load(new URLRequest("xml.xml")); myLoader.addEventListener(Event.COMPLETE, processXML); //parse XML function processXML(e:Event):void { myXML = new XML(e.target.data); trace(myXML); //receive values from XML delay = parseInt(myXML.DELAY.text()); trace(delay); repeat = parseInt(myXML.REPEAT.text()); trace(repeat); } //variables var delay:uint = 0; var repeat:uint = 0; //timer and event var timer:Timer = new Timer(uint(delay),uint(repeat)); timer.addEventListener(TimerEvent.TIMER, countdown); //counter function countdown(event:TimerEvent) { myText.text = String(0 + timer.currentCount); trace(0 + timer.currentCount); } timer.start(); XML <?xml version="1.0" encoding="utf-8"?> <SESSION> <DELAY TITLE="starting position">1000</DELAY> <REPEAT TITLE="starting position">60</REPEAT> </SESSION>

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• Java Application for handling records(CRUD)

  - by LivingThing

  I am new to JavaEE and am faced with a tight situation here. I have to develop a Java application for (CRUD) handling records and saving and loading an XML concerning that record. Obviously, I won't be asking you to do this for me. What I would be asking you is to give me some hints/pointer. Initially I thought JAXB would be enough for this but after putting a lot of time learning it and implementing the program I realized that it just can create the XML and read it but for update, delete I would have to do something else. Even if it wasn't for update and delete features requirement for my project I would still think that by just using JAXB is not a good implementation. I was wondering if "REST with Java (JAX-RS) using Jersey" should do the trick for me. ?

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• How do I add a default namespace with no prefix using XMLSerializer

  - by OldBob

  Hi Using C# and .Net 3.5; I am trying to generate an XML document that contains the default namespace without a prefix using XMLSerializer. eg. <?xml version="1.0" encoding="utf-8" ?> <MyRecord ID="9266" xmlns="http://www.website.com/MyRecord"> <List> <SpecificItem> using the following code string xmlizedString = null; MemoryStream memoryStream = new MemoryStream(); XmlSerializer xs = new XmlSerializer(typeof(ExportMyRecord)); XmlSerializerNamespaces xmlnsEmpty = new XmlSerializerNamespaces(); xmlnsEmpty.Add(string.Empty, string.Empty); XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8); xs.Serialize(xmlTextWriter, myRecord, xmlnsEmpty); memoryStream = (MemoryStream)xmlTextWriter.BaseStream; xmlizedString = this.UTF8ByteArrayToString(memoryStream.ToArray()); and class structure [Serializable] [XmlRoot("MyRecord")] public class ExportMyRecord { [XmlAttribute("ID")] public int ID { get; set; } Now, I've tried various options XmlSerializer xs = new XmlSerializer(typeof(ExportMyRecord),"http://www.website.com/MyRecord"); or [XmlRoot(Namespace = "http://www.website.com/MyRecord", ElementName="MyRecord")] gives me <?xml version="1.0" encoding="utf-8"?> <q1:MylRecord ID="9266" xmlns:q1="http://www.website.com/MyRecord"> <q1:List> <q1:SpecificItem> I need the XML to have the namespace without the prefix as it's going to a third party provider and they reject all other alternatives. Any suggestions? No responses so far. Has anyone experienced this or know how to solve it?

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• Can't seem to load a webview from xml, why?

  - by Bilthon

  Well, I'm trying to follow the tutorial from http://rapidandroid.org/wiki/Graphing. But I found a problem just in the first part of it. I'll describe the problem here, I just cannot understand how this could be wrong, it's pretty simple stuff. What am I doing wrong here? First I created a xml file called statistics.xml, in it among other things I put this code: <WebView android:id="@+id/webview" android:layout_height="fill_parent" android:layout_width="fill_parent"/> Now in the activity that is supposed to display this webview I'm doing this: public class DisplayStatistics extends Activity { public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); WebView wv = (WebView) findViewById(R.id.webview); The problem arises here, as I seem to be getting null for wv whenever I test for it. Which means of course that findViewById(R.id.webview) couldn't find the view. But again, what am I doing wrong?? Of course I know I could also instantiate the webview directly from code without the need to specify it from the xml, but I was just wondering what was wrong about this way of doing it. Just in case I also added the following line in my android manifest file: <uses-permission android:name="android.permission.INTERNET" /> I'm not really sure if it's necessary for displaying the webview (I think not) but I just put it there to see if that was the problem, and it turned out it isn't. Thanks Nelson

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• How to wrtie a XML License Line(ended with a forward slash '/') in C#?

  - by Nano HE

  I want to write a XML file as below: <?xml version="1.0" encoding="UTF-8"?> <books xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <License licenseId="" licensePath="" /> Some piece of my code attached here // Create a new file in D:\\ and set the encoding to UTF-8 XmlTextWriter textWriter = new XmlTextWriter("D:\\books.xml", System.Text.Encoding.UTF8); // Format automatically textWriter.Formatting = Formatting.Indented; // Opens the document textWriter.WriteStartDocument(); // Write the namespace declaration. textWriter.WriteStartElement("books", null); // Write the genre attribute. textWriter.WriteAttributeString("xmlns", "xsd", null, "http://www.w3.org/2001/XMLSchema"); textWriter.WriteAttributeString("xmlns", "xsi", null, "http://www.w3.org/2001/XMLSchema-instance"); And now I need to write the License Line below in C# <License licenseId="" licensePath="" /> But I don't know how to move on for I found the Line ended with the forward slash / .Thank you.

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• Deserialize inherited classes into the same list in XNA

  - by M0rgenstern

  I am writing a Gui for a game (for what else ...). Therefor I wrote a class GuiElement which has some serializeable fields. From this class I deflect a Class "Button" which has one serializeable field more. Furthermore, I have a Class GuiWindow, which is as well deflected from "GuiElement". An Object of this Class has a Field "HandledElements" of the type "List". To know the layout of the Menues, I use XML-Files, which look like that (for example): <?xml version="1.0" encoding="utf-8" ?> <XnaContent xmlns:Generic="System.Collections.Generic"> <Asset Type="System.Collections.Generic.List[GUI.GuiWindow]"> <Item> <Position>0 0</Position> <AlternativeImagePath></AlternativeImagePath> <IsActive>true</IsActive> <Name>MainMenu</Name> <HandledElements> <Item> <Position>100 100</Position> <AlternativeImagePath></AlternativeImagePath> <IsActive>true</IsActive> <Name>Optionen</Name> <Caption>Optionen</Caption> </Item> </HandledElements> </Item> <Item> <Position>0 0</Position> <AlternativeImagePath></AlternativeImagePath> <IsActive>false</IsActive> <Name>Options</Name> <HandledElements> </HandledElements> </Item> </Asset> </XnaContent> As you can see, the first window has in its "HandledElements" List an Item with the Field . This is a field which only a Button has. The Problem is now: I can't deserialize this XML file, because GuiElement does not have this Field, it only has the few fields above. I thought it would know automatically which Class to use,but it doesn't. Do I really have to give my windows a list for each child class of GuiElement? Or can I do another workaround?

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• Getting "" at the beginning of my XML File after save()

  - by Remy

  I'm opening an existing XML file with c# and I replace some nodes in there. All works fine. Just after I save it, I get the following characters at the beginning of the file:  (EF BB BF in HEX) The whole first line: <?xml version="1.0" encoding="UTF-8" standalone="yes"?> The rest of the file looks like a normal XML file. The simplified code is here: XmlDocument doc = new XmlDocument(); doc.Load(xmlSourceFile); XmlNode translation = doc.SelectSingleNode("//trans-unit[@id='127']"); translation.InnerText = "testing"; doc.Save(xmlTranslatedFile); I'm using a C# WinForm Application. With .NET 4.0. Any ideas? Why would it do that? Can we disable that somehow? It's for Adobe InCopy and it does not open it like this. UPDATE: Alternative Solution: Saving it with the XmlTextWriter works too: XmlTextWriter writer = new XmlTextWriter(inCopyFilename, null); doc.Save(writer);

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• Oracle: how to use updateXML to update multiple nodes in a document?

  - by Alessandro Vernet

  I can write: update my_table set xml = updateXML(xml, '/a/b', '1') where document_id = 123 Now what if in the same update query I also want to set /a/c to 2 (in addition /a/b to 1)? I am tempted to write: update my_table set xml = updateXML(xml, '/a/b', '1'), xml = updateXML(xml, '/a/c', '2') where document_id = 123 But this give me a "ORA-00957: duplicate column name". Any suggestion on how to do this?

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• What MS technology to use for HTTP service returning XML?

  - by Borek

  I need to create a service that: accepts HTTP requests (with query string or HTTP POST parameters) does some processing on the requests (checking if the request is valid, authentication etc.) reads data from a custom store (another HTTP call in our case) returns the result as custom XML (defined with XSD) I'm trying to think of various MS technologies that could help me and how good they would be for this scenario (pretty standard one I guess). The tasks above are relatively separate, this is what comes to mind: HTTP front-end: ASP.NET Web Forms ASP.NET MVC (seems more appropriate here as I won't need server controls, view state etc.) WCF? Don't know much about it or how well it would suit my task. Custom logic on the server: this will probably be a generic C# code in all cases (sometimes "plugged into" or called from MVC controllers or some equivalent place in other technologies) Reading data from internal data stores: As said, this is another HTTP server in our case. Options that come to mind: Just read the data using something like WebClient (Just theoretically) implement a LINQ provider (Just even more theoretically) implement an EF provider Output the data as custom XML: Linq2XML Serialization? Is it flexible enough? Does WCF provide some tools for this? Some "OXM" - Object/XML mapper if there is something like that for .NET I may be wrong in many of my assumptions, this is just a quick list that comes to mind after a quick research. Some general notes / questions: Testing is important Solution with a clear domain model would be much preferred over the one without Can Entity Framework actually help somewhere in my scenario? If so, where and how? Would WCF be an appropriate technology for this? I don't know much about it.

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• Hibernate - Problem in parsing mapping file (.hbm.xml)

  - by Yatendra Goel

  I am new to Hibernate. I have an exception while running an Hibernate-based application. The exception is as follows: 16 [main] INFO org.hibernate.cfg.Environment - Hibernate 3.3.2.GA 16 [main] INFO org.hibernate.cfg.Environment - hibernate.properties not found 16 [main] INFO org.hibernate.cfg.Environment - Bytecode provider name : javassist 31 [main] INFO org.hibernate.cfg.Environment - using JDK 1.4 java.sql.Timestamp handling 94 [main] INFO org.hibernate.cfg.Configuration - configuring from resource: /hibernate.cfg.xml 94 [main] INFO org.hibernate.cfg.Configuration - Configuration resource: /hibernate.cfg.xml 219 [main] INFO org.hibernate.cfg.Configuration - Reading mappings from resource : app/data/City.hbm.xml 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(12) Attribute "coloumn" must be declared for element type "property". 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(13) Attribute "coloumn" must be declared for element type "property". 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(14) Attribute "coloumn" must be declared for element type "property". It seems that it is not finding coloumn attribute of the property element in the mappings file but my mappings file do have the coloumn attribute. Below is the mappings file (City.hbm.xml) <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="app.data"> <class name="City" table="CITY"> <id column="CITY_ID" name="cityId"> <generator class="native"/> </id> <property name="cityDisplyaName" coloumn="CITY_DISPLAY_NAME" /> <property coloumn="CITY_MEANINGFUL_NAME" name="cityMeaningFulName" /> <property coloumn="CITY_URL" name="cityURL" /> </class> </hibernate-mapping>

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• XML Schema: How to specify an attribute with a custom 'simpleType' type?

  - by mackenir

  In my XML schema definition, I'm trying to restrict the value of an attribute to be an integer between 0 and 100. With reference to the sample schema below, I want attribute 'attr' on element 'root' to have this restriction. To achieve this I define a simpleType 'Percentage' and set this as the 'type' of 'attr'. However, my XML schema editor (VS 2008) flags the attribute up as having a problem: "Type 'Percentage' is not declared or is not a simple type". <?xml version="1.0" encoding="utf-8"?> <xs:schema elementFormDefault="qualified" id="test" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="http://testtttt"> <xs:simpleType name="Percentage"> <xs:restriction base="xs:integer"> <xs:minInclusive value="0"/> <xs:maxInclusive value="100"/> </xs:restriction> </xs:simpleType> <xs:element name="root"> <xs:complexType> <xs:attribute name="attr" type="Percentage" use="optional" /> </xs:complexType> </xs:element>

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• How to syntax-highlight XML in CDATA elements in Vim?

  - by Jim Hurne

  Vim's syntax highlighting for XML/XSL is great, except it turns off all syntax highlighting in CDATA regions. Is there a way to turn on syntax highlighting on in CDATA regions? At work, we have a lot of XSL code embedded within other XML documents. It would be great if I could get all of the goodness of XML editing for the embedded XSL code as well without having to temporarily remove the CDATA tags, or copy the CDATA content into a temporary file. Example: <root> <someTag><![CDATA[ <xsl:template match="/"> <!-- XSL content here --> </xsl:template> ]]> </someTag> </root> Note that the name of the tag (in the example, someTag) containing the content could be anything. We also sometimes embed Javascript inside CDATA regions as well, and again, it would be nice to turn on Javascript syntax highlighting for those regions. Again, the tag the data is embedded in is usually arbitrary and can be anything.

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• Parsing log files in a folder in ColdFusion

  - by Simon Guo

  The problem is there is a folder ./log/ containing the files like: jan2010.xml, feb2010.xml, mar2010.xml, jan2009.xml, feb2009.xml, mar2009.xml ... each xml file would like: <root><record name="bob" spend="20"></record>...(more records)</root> I want to write a piece of ColdFusion code (log.cfm) that simply parsing those xml files. For the front end I would let user to choose a year, then the click submit button. All the content in that year will be show up in separate table by month. Each table shows the total money spent for each person. like: person cost bob 200 mike 300 Total 500 Thanks.

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• How to define multiple elements in XML Schema with the same name and different attribute value allow

  - by David Skyba

  I would like to create XML Schema for this chunk of xml, I would like to restrict the values of "name" attribute, so that in output document on and only one instance of day is allowed for each week day: <a> <day name="monday" /> <day name="tuesday" /> <day name="wednesday" /> </a> I have tried to use this: <xs:complexType name="a"> <xs:sequence> <xs:element name="day" minOccurs="1" maxOccurs="1"> <xs:complexType> <xs:attribute name="name" use="required"> <xs:simpleType> <xs:restriction base="xs:string"> <xs:enumeration value="monday" /> </xs:restriction> </xs:simpleType> </xs:attribute> </xs:complexType> </xs:element> <xs:element name="day" minOccurs="1" maxOccurs="1"> <xs:complexType> <xs:attribute name="name" use="required"> <xs:simpleType> <xs:restriction base="xs:string"> <xs:enumeration value="tuesday" /> </xs:restriction> </xs:simpleType> </xs:attribute> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> but XML Schema validator in eclipse says error "Multiple elements with name 'day', with different types, appear in the model group.". Is there any other way?

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• How can I create/update an XML node that may or may not exist?

  - by ScottBai

  Is there a method available (i.e. without me creating my own recursive method), for a given xpath (or other method of identifying the hierarchical position) to create/update an XML node, where the node would be created if it does not exist? This would need to create the parent node if it does not exist as well. I do have an XSD which includes all possible nodes. i.e. Before: <employee> <name>John Smith</name> </employee> Would like to call something like this: CoolXmlUpdateMethod("/employee/address/city", "Los Angeles"); After: <employee> <name>John Smith</name> <address> <city>Los Angeles</city> </address> </employee> Or even a method to create a node, given an xpath, wherein it will recursively create the parent node(s) if they do not exist? As far as the application (if it matters), this is taking an existing XML doc that contains only populated nodes, and adding data to it from another system. The new data may or may not already have values populated in the source XML. Surely this is not an uncommon scenario?

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• WCF service reference namespace differs from original

  - by Thorarin

  I'm having a problem regarding namespaces used by my service references. I have a number of WCF services, say with the namespace MyCompany.Services.MyProduct (the actual namespaces are longer). As part of the product, I'm also providing a sample C# .NET website. This web application uses the namespace MyCompany.MyProduct. During initial development, the service was added as a project reference to the website and uses directly. I used a factory pattern that returns an object instance that implements MyCompany.Services.MyProduct.IMyService. So far, so good. Now I want to change this to use an actual service reference. After adding the reference and typing MyCompany.Services.MyProduct in the namespace textbox, it generates classes in the namespace MyCompany.MyProduct.MyCompany.Services.MyProduct. BAD! I don't want to have to change using directives in several places just because I'm using a proxy class. So I tried prepending the namespace with global::, but that is not accepted. Note that I hadn't even deleted the original assembly references yet, and "reuse types" is enabled, but no reusing was done, apparently. However, I don't want to keep the assembly references around in my sample website for it to work anyway. The only solution I've come up with so far is setting the default namespace for my web application to MyCompany (because it cannot be empty), and adding the service reference as Services.MyProduct. Suppose that a customer wants to use my sample website as a starting point, and they change the default namespace to OtherCompany.Whatever, this will obviously break my workaround. Is there a good solution to this problem? To summarize: I want to generate a service reference proxy in the original namespace, without referencing the assembly. Note: I have seen this question, but there was no solution provided that is acceptable for my use case. Edit: As John Saunders suggested, I've submitted some feedback to Microsoft about this: Feedback item @ Microsoft Connect

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• XSLT: Add namespace to root element

  - by Ingrid

  I need to change namespaces in the root element as follows: input document: <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <foo xsi:schemaLocation="urn:isbn:1-931666-22-9 http://www.loc.gov/ead/ead.xsd" xmlns:ns2="http://www.w3.org/1999/xlink" xmlns="urn:isbn:1-931666-22-9" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> desired output: <foo audience="external" xsi:schemaLocation="urn:isbn:1-931666-22-9 http://www.loc.gov/ead/ead.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns="urn:isbn:1-931666-22-9"> I was trying to do it as I copy over the whole document and before I give any other transformation instructions, but the following doesn't work: <xsl:template match="* | processing-instruction() | comment()"> <xsl:copy copy-namespaces="no"> <xsl:for-each select="."> <xsl:attribute name="audience" select="'external'"/> <xsl:namespace name="xlink" select="'http://www.w3.org/1999/xlink'"/> </xsl:for-each> <xsl:apply-templates/> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> Thanks for any advice!

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• How to parse XML to flex Data Grid contents.

  - by Jeeva

  My xml file which is in a webserver is show below. <root> <userdetails> <username>raja</username> <status>offline</status> </userdetails> <userdetails> <username>Test</username> <status>online</status> </userdetails> </root> How can i parse this to flex data grid contents. I tried with below coding < ?xml version="1.0" encoding="utf-8"? < mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" creationComplete="initApp()" < mx:HTTPService id="userList" result="handleData(event)" resultFormat="object" url="http://apps.facebook.com/ajparkin/user_list.xml" / <mx:Script> <![CDATA[ import mx.collections.ArrayCollection; import mx.rpc.events.ResultEvent; import mx.controls.Alert; public function initApp():void { userList.send(); } [Bindable] var userdetailsArray:ArrayCollection; private function handleData(evt:ResultEvent):void { this.userdetailsArray= evt.result.userdetails; } ]]> </mx:Script> <mx:DataGrid dataProvider="{userdetailsArray}"> <mx:columns> <mx:DataGridColumn dataField="username" headerText="User Name"/> <mx:DataGridColumn dataField="status" headerText="Status" /> </mx:columns> </mx:DataGrid> </mx:Application> I'm getting only the field names not the data.

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• Parse large XML file w/ script or use BioPython API ?

  - by jeremy04

  Hey guys this is my first question on here. I'm trying to make a local copy of the UniprotKB in SQL. The UniprotKB is 2.1GB, and it comes in XML and a special text format used by SwissProt Here are my options: 1) Use a SAX parser (XML) - I chose Ruby, and Nokogiri. I started writing the parser, but my initial reaction: how would I map the XML schema to the SAX parser? 2) BioPython - I already have BioSQL/Biopython installed, which literally created my SQL schema for me, and I was able to successfully insert one SwissProt/Uniprot txt file into the database. I'm running it right now (crosses fingers) on the entire 2.1gb. Here is the code I'm running: from Bio import SeqIO from BioSQL import BioSeqDatabase from Bio import SwissProt server = BioSeqDatabase.open_database(driver = "MySQLdb", user = "root", passwd = "", host="localhost", db = "bioseqdb") db = server["uniprot"] iterator = SeqIO.parse(open("/path/to/uniprot_sprot.dat", "r"), "swiss") db.load(iterator) server.commit() Edit: it's now crashing because the transactions are getting locked (since the tables are Innodb) Error Number: 1205 Lock wait timeout exceeded; try restarting transaction. I'm using MySQL version: 5.1.43 Should I switch my database to Postgrelsql ?

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• jquery how to access the an xml node by index?

  - by DS

  Hi, say I've an xml returned from server like this: <persons> <person> <firstname>Jon</firstname> </person> <person> <firstname>Jack</firstname> </person> <person> <firstname>James</firstname> </person> </persons> If I want to access the 3rd firstname node (passed dynamically and stored in i, assumed to be 3 here), how do I do that? My weird attempt follows: var i=3; $(xml).find('firstname').each(function(idx){ if (idx==i) alert($(this).text()); }); It does fetch me the right content... but it just feels wrong to me especially the looping part. Basically I'm looping through the whole tree using .each()! Is there any better approach than this? Something that'd take me to the nth node directly like: alert( $(xml).find('firstname')[idx].text() ); // where idx=n I'm new to jquery so please excuse my jquery coding approach.

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• How to fix Eclipse validation error "No grammar constraints detected for the document"?

  - by Casey

  Eclipse 3.5.2 is throwing an XML schema warning message: No grammar constraints (DTD or XML schema) detected for the document. The application.xml file: <?xml version="1.0" encoding="UTF-8"?> <application xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/application_5.xsd" version="5"> </application> I do not want to disable the warning. How can I get Eclipse to correctly validate the XML document?

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• Recursion Problem in PHP

  - by streetparade

  I need to create a valid xml from a given array(); My Method looks like this, protected function array2Xml($array) { $xml = ""; if(is_array($array)) { foreach($array as $key=>$value) { $xml .= "<$key>"; if(is_array($value)) { $xml .= $this->array2Xml($value); } $xml .= "</$key>"; } return $xml; } else { throw new Exception("in valid"); } } protected function createValidXMLfromArray($array,$node) { $xml = '<?xml version="1.0" encoding="ISO-8859-1"?>'; $xmlArray = $this->array2Xml($array); $xml .= "<$node>$xmlArray</$node>"; return $xml; } if i execute the above i just get keys with empty values; like <node> <name></name> </node> What i need is if i pass this array("name"=>"test","value"=>array("test1"=>33,"test2"=>40)); that it return this <node> <name>test</name> <value> <test1>33</test1> <test2>40</test2> </value> </node> Where is the error what did i wrong in the above recursion?

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• How to wrtie a XML License Line in C#?

  - by Nano HE

  My want to write a XML file as this: <?xml version="1.0" encoding="UTF-8"?> <Equipment xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <License licenseId="" licensePath="" /> Some piece of my code attached here // Create a new file in D:\\ and set the encoding to UTF-8 XmlTextWriter textWriter = new XmlTextWriter("D:\\books.xml", System.Text.Encoding.UTF8); // Format automatically textWriter.Formatting = Formatting.Indented; // Opens the document textWriter.WriteStartDocument(); // Write the namespace declaration. textWriter.WriteStartElement("books", null); // Write the genre attribute. textWriter.WriteAttributeString("xmlns", "xsd", null, "http://www.w3.org/2001/XMLSchema"); textWriter.WriteAttributeString("xmlns", "xsi", null, "http://www.w3.org/2001/XMLSchema-instance"); And now I need to write the License Line below in C# <License licenseId="" licensePath="" /> But I don't know how to move on for I found the Line ended with the special / .Thank you.

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• C# XML parsing with LINQ storing directly to a struct?

  - by Luke

  Say I have the following XML schema: <root> <version>2.0</version> <type>fiction</type> <chapters> <chapter>1</chapter> <title>blah blah</title> </chapter> <chapters> <chapter>2</chapter> <title>blah blah</title> </chapters> </root> Would it be possibly to parse the elements which I know will not be repeated in the XML and store them directly into the struct using LINQ? For example, could I do something like this for "version" and "type" //setup structs Book book = new Book(); book.chapter = new Chapter(); //use LINQ to parse the xml var bookData = from b in xmlDoc.Decendants("root") select new { book.version = b.Element("version").Value, book.type = b.Element("type").Value }; //then for "chapters" since I know there are multiple I can do: var chapterData = from c in xmlDoc.Decendants("root" select new { chapter = c.Element("chapters") }; foreach (var ch in chapterData) { book.chapter.Add(getChapterData(ch.chapter)); }

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