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• Why is the software world full of status codes?

  - by David V McKay

  Why did programmers ever start using status codes? I mean, I guess I could imagine this might be useful back in the days when a text string was an expensive resource. WAYYY back then. But even after we had megabytes of memory to work with, we continued to use them. What possible advantage could there be for obfuscating the meaning of an error message or status message behind a status code?

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• Help needed with MySQL query to join data spanning multiple tables with data used as column names

  - by gurun8

  I need a little help putting together a SQL query that will give me the following resultsets: and The data model looks like this: The tricky part for me is that the columns to the right of the "Product" in the resultset aren't really columns in the database but rather key/value pairs spanned across the data model. Table data is as follows: My apologies in advance for the image heavy question and the image quality. This just seemed like the easiest way to convey the information. It'll probably take someone less time to write the query statement to achieve the results than it did for me to assemble this question. By the way, the "product_option" table image is truncated but it illustrated the general idea of the data structure. The MySQL server version is 5.1.45.

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• subset in geom_point SOMETIMES returns full dataset, instead of none.

  - by Andreas

  I ask the following in the hope that someone might come up with a generic description about the problem.Basically I have no idea whats wrong with my code. When I run the code below, plot nr. 8 turns out wrong. Specifically the subset in geom_point does not work the way it should. (update: With plot nr. 8 the whole dataset is plottet, instead of only the subset). If somebody can tell me what the problem is, I'll update this post. SOdata <- structure(list(id = 10:55, one = c(7L, 8L, 7L, NA, 7L, 8L, 5L, 7L, 7L, 8L, NA, 10L, 8L, NA, NA, NA, NA, 6L, 5L, 6L, 8L, 4L, 7L, 6L, 9L, 7L, 5L, 6L, 7L, 6L, 5L, 8L, 8L, 7L, 7L, 6L, 6L, 8L, 6L, 8L, 8L, 7L, 7L, 5L, 5L, 8L), two = c(7L, NA, 8L, NA, 10L, 10L, 8L, 9L, 4L, 10L, NA, 10L, 9L, NA, NA, NA, NA, 7L, 8L, 9L, 10L, 9L, 8L, 8L, 8L, 8L, 8L, 9L, 10L, 8L, 8L, 8L, 10L, 9L, 10L, 8L, 9L, 10L, 8L, 8L, 7L, 10L, 8L, 9L, 7L, 9L), three = c(7L, 10L, 7L, NA, 10L, 10L, NA, 10L, NA, NA, NA, NA, 10L, NA, NA, 4L, NA, 7L, 7L, 4L, 10L, 10L, 7L, 4L, 7L, NA, 10L, 4L, 7L, 7L, 7L, 10L, 10L, 7L, 10L, 4L, 10L, 10L, 10L, 4L, 10L, 10L, 10L, 10L, 7L, 10L), four = c(7L, 10L, 4L, NA, 10L, 7L, NA, 7L, NA, NA, NA, NA, 10L, NA, NA, 4L, NA, 10L, 10L, 7L, 10L, 10L, 7L, 7L, 7L, NA, 10L, 7L, 4L, 10L, 4L, 7L, 10L, 2L, 10L, 4L, 12L, 4L, 7L, 10L, 10L, 12L, 12L, 4L, 7L, 10L), five = c(7L, NA, 6L, NA, 8L, 8L, 7L, NA, 9L, NA, NA, NA, 9L, NA, NA, NA, NA, 7L, 8L, NA, NA, 7L, 7L, 4L, NA, NA, NA, NA, 5L, 6L, 5L, 7L, 7L, 6L, 9L, NA, 10L, 7L, 8L, 5L, 7L, 10L, 7L, 4L, 5L, 10L), six = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L), .Label = c("2010-05-25", "2010-05-27", "2010-06-07"), class = "factor"), seven = c(0.777777777777778, 0.833333333333333, 0.333333333333333, 0.888888888888889, 0.5, 0.888888888888889, 0.777777777777778, 0.722222222222222, 0.277777777777778, 0.611111111111111, 0.722222222222222, 1, 0.888888888888889, 0.722222222222222, 0.555555555555556, NA, 0, 0.666666666666667, 0.666666666666667, 0.833333333333333, 0.833333333333333, 0.833333333333333, 0.833333333333333, 0.722222222222222, 0.833333333333333, 0.888888888888889, 0.666666666666667, 1, 0.777777777777778, 0.722222222222222, 0.5, 0.833333333333333, 0.722222222222222, 0.388888888888889, 0.722222222222222, 1, 0.611111111111111, 0.777777777777778, 0.722222222222222, 0.944444444444444, 0.555555555555556, 0.666666666666667, 0.722222222222222, 0.444444444444444, 0.333333333333333, 0.777777777777778), eight = c(0.666666666666667, 0.333333333333333, 0.833333333333333, 0.666666666666667, 1, 1, 0.833333333333333, 0.166666666666667, 0.833333333333333, 0.833333333333333, 1, 1, 0.666666666666667, 0.666666666666667, 0.333333333333333, 0.5, 0, 0.666666666666667, 0.5, 1, 0.666666666666667, 0.5, 0.666666666666667, 0.666666666666667, 0.666666666666667, 0.333333333333333, 0.333333333333333, 1, 0.666666666666667, 0.833333333333333, 0.666666666666667, 0.666666666666667, 0.5, 0, 0.833333333333333, 1, 0.666666666666667, 0.5, 0.666666666666667, 0.666666666666667, 0.5, 1, 0.833333333333333, 0.666666666666667, 0.833333333333333, 0.666666666666667), nine = c(0.307692307692308, NA, 0.461538461538462, 0.538461538461538, 1, 0.769230769230769, 0.538461538461538, 0.692307692307692, 0, 0.153846153846154, 0.769230769230769, NA, 0.461538461538462, NA, NA, NA, NA, 0, 0.615384615384615, 0.615384615384615, 0.769230769230769, 0.384615384615385, 0.846153846153846, 0.923076923076923, 0.615384615384615, 0.692307692307692, 0.0769230769230769, 0.846153846153846, 0.384615384615385, 0.384615384615385, 0.461538461538462, 0.384615384615385, 0.461538461538462, NA, 0.923076923076923, 0.692307692307692, 0.615384615384615, 0.615384615384615, 0.769230769230769, 0.0769230769230769, 0.230769230769231, 0.692307692307692, 0.769230769230769, 0.230769230769231, 0.769230769230769, 0.615384615384615), ten = c(0.875, 0.625, 0.375, 0.75, 0.75, 0.75, 0.625, 0.875, 1, 0.125, 1, NA, 0.625, 0.75, 0.75, 0.375, NA, 0.625, 0.5, 0.75, 0.875, 0.625, 0.875, 0.75, 0.625, 0.875, 0.5, 0.75, 0, 0.5, 0.875, 1, 0.75, 0.125, 0.5, 0.5, 0.5, 0.625, 0.375, 0.625, 0.625, 0.75, 0.875, 0.375, 0, 0.875), elleven = c(1, 0.8, 0.7, 0.9, 0, 1, 0.9, 0.5, 0, 0.8, 0.8, NA, 0.8, NA, NA, 0.8, NA, 0.4, 0.8, 0.5, 1, 0.4, 0.5, 0.9, 0.8, 1, 0.8, 0.5, 0.3, 0.9, 0.2, 1, 0.8, 0.1, 1, 0.8, 0.5, 0.2, 0.7, 0.8, 1, 0.9, 0.6, 0.8, 0.2, 1), twelve = c(0.666666666666667, NA, 0.133333333333333, 1, 1, 0.8, 0.4, 0.733333333333333, NA, 0.933333333333333, NA, NA, 0.6, 0.533333333333333, NA, 0.533333333333333, NA, 0, 0.6, 0.533333333333333, 0.733333333333333, 0.6, 0.733333333333333, 0.666666666666667, 0.533333333333333, 0.733333333333333, 0.466666666666667, 0.733333333333333, 1, 0.733333333333333, 0.666666666666667, 0.533333333333333, NA, 0.533333333333333, 0.6, 0.866666666666667, 0.466666666666667, 0.533333333333333, 0.333333333333333, 0.6, 0.6, 0.866666666666667, 0.666666666666667, 0.6, 0.6, 0.533333333333333)), .Names = c("id", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "elleven", "twelve"), class = "data.frame", row.names = c(NA, -46L)) iqr <- function(x, ...) { qs <- quantile(as.numeric(x), c(0.25, 0.5, 0.75), na.rm = T) names(qs) <- c("ymin", "y", "ymax") qs } magic <- function(y, ...) { high <- median(SOdata[[y]], na.rm=T)+1.5*sd(SOdata[[y]],na.rm=T) low <- median(SOdata[[y]], na.rm=T)-1.5*sd(SOdata[[y]],na.rm=T) ggplot(SOdata, aes_string(x="six", y=y))+ stat_summary(fun.data="iqr", geom="crossbar", fill="grey", alpha=0.3)+ geom_point(data = SOdata[SOdata[[y]] > high,], position=position_jitter(w=0.1, h=0),col="green", alpha=0.5)+ geom_point(data = SOdata[SOdata[[y]] < low,], position=position_jitter(w=0.1, h=0),col="red", alpha=0.5)+ stat_summary(fun.y=median, geom="point",shape=18 ,size=4, col="orange") } for (i in names(SOdata)[-c(1,7)]) { p<- magic(i) ggsave(paste("magig_plot_",i,".png",sep=""), plot=p, height=3.5, width=5.5) }

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• Given the full path to a file, how do I get just the path without the filename?

  - by Zerobu

  Hello, Suppose I have a path in a string called '/home/user/directory/HelloWorld.txt'. I would like to remove the HelloWorld.txt, and end up with '/home/user/directory'. What regex would I need.

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• Receiving a JSON string & saving one of the array paramaters to the database as a full string

  - by ElTren

  Hi I have a JSON string that looks like this (Usingt Rails and a REST service) { person: { name:"Pepe", last:"Smith" hats:[ { team:"lakers", color:"purple"}, { team:"heats", color:"red" }] } } I want to be able to able to get that JSON, and save the Person to the database, but I want to save the "hats".. as a string to the database; without parsing it or anything like that i.e. I want to save this to SQL: hats = "[ { team:"lakers", color:"purple"}, { team:"heats", color:"red" }] }" Is there a way to do this in rails?

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• C++ non-member functions for nested template classes

  - by beldaz

  I have been writing several class templates that contain nested iterator classes, for which an equality comparison is required. As I believe is fairly typical, the comparison is performed with a non-member (and non-friend) operator== function. In doing so, my compiler (I'm using Mingw32 GCC 4.4 with flags -O3 -g -Wall) fails to find the function and I have run out of possible reasons. In the rather large block of code below there are three classes: a Base class, a Composed class that holds a Base object, and a Nested class identical to the Composed class except that it is nested within an Outer class. Non-member operator== functions are supplied for each. These classes are in templated and untemplated forms (in their own respective namespaces), with the latter equivalent to the former specialised for unsigned integers. In main, two identical objects for each class are compared. For the untemplated case there is no problem, but for the templated case the compiler fails to find operator==. What's going on? #include <iostream> namespace templated { template<typename T> class Base { T t_; public: explicit Base(const T& t) : t_(t) {} bool equal(const Base& x) const { return x.t_==t_; } }; template<typename T> bool operator==(const Base<T> &x, const Base<T> &y) { return x.equal(y); } template<typename T> class Composed { typedef Base<T> Base_; Base_ base_; public: explicit Composed(const T& t) : base_(t) {} bool equal(const Composed& x) const {return x.base_==base_;} }; template<typename T> bool operator==(const Composed<T> &x, const Composed<T> &y) { return x.equal(y); } template<typename T> class Outer { public: class Nested { typedef Base<T> Base_; Base_ base_; public: explicit Nested(const T& t) : base_(t) {} bool equal(const Nested& x) const {return x.base_==base_;} }; }; template<typename T> bool operator==(const typename Outer<T>::Nested &x, const typename Outer<T>::Nested &y) { return x.equal(y); } } // namespace templated namespace untemplated { class Base { unsigned int t_; public: explicit Base(const unsigned int& t) : t_(t) {} bool equal(const Base& x) const { return x.t_==t_; } }; bool operator==(const Base &x, const Base &y) { return x.equal(y); } class Composed { typedef Base Base_; Base_ base_; public: explicit Composed(const unsigned int& t) : base_(t) {} bool equal(const Composed& x) const {return x.base_==base_;} }; bool operator==(const Composed &x, const Composed &y) { return x.equal(y); } class Outer { public: class Nested { typedef Base Base_; Base_ base_; public: explicit Nested(const unsigned int& t) : base_(t) {} bool equal(const Nested& x) const {return x.base_==base_;} }; }; bool operator==(const Outer::Nested &x, const Outer::Nested &y) { return x.equal(y); } } // namespace untemplated int main() { using std::cout; unsigned int testVal=3; { // No templates first typedef untemplated::Base Base_t; Base_t a(testVal); Base_t b(testVal); cout << "a=b=" << testVal << "\n"; cout << "a==b ? " << (a==b ? "TRUE" : "FALSE") << "\n"; typedef untemplated::Composed Composed_t; Composed_t c(testVal); Composed_t d(testVal); cout << "c=d=" << testVal << "\n"; cout << "c==d ? " << (c==d ? "TRUE" : "FALSE") << "\n"; typedef untemplated::Outer::Nested Nested_t; Nested_t e(testVal); Nested_t f(testVal); cout << "e=f=" << testVal << "\n"; cout << "e==f ? " << (e==f ? "TRUE" : "FALSE") << "\n"; } { // Now with templates typedef templated::Base<unsigned int> Base_t; Base_t a(testVal); Base_t b(testVal); cout << "a=b=" << testVal << "\n"; cout << "a==b ? " << (a==b ? "TRUE" : "FALSE") << "\n"; typedef templated::Composed<unsigned int> Composed_t; Composed_t c(testVal); Composed_t d(testVal); cout << "c=d=" << testVal << "\n"; cout << "d==c ? " << (c==d ? "TRUE" : "FALSE") << "\n"; typedef templated::Outer<unsigned int>::Nested Nested_t; Nested_t e(testVal); Nested_t f(testVal); cout << "e=f=" << testVal << "\n"; cout << "e==f ? " << (e==f ? "TRUE" : "FALSE") << "\n"; // Above line causes compiler error: // error: no match for 'operator==' in 'e == f' } cout << std::endl; return 0; }

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• EF4. Add a object with relationship causes full table select

  - by Fujiy

  Ex 1: "autor.ComentariosWorkItens.Add(comentarioWorkItem);" autor.ComentariosWorkItens makes EF4 load all ComentariosWorkItens. Ex 2: comentarioWorkItem.Usuario = autor; Fixup make EF load all ComentariosWorkItens too: private void FixupUsuario(Usuario previousValue) { if (previousValue != null && previousValue.ComentariosWorkItens.Contains(this)) { previousValue.ComentariosWorkItens.Remove(this); } if (Usuario != null) { if (!Usuario.ComentariosWorkItens.Contains(this)) { Usuario.ComentariosWorkItens.Add(this); } } } How can I prevent this?

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• CSS - postion: absolute; - auto height

  - by superUntitled

  I am having a problem with some div's The outer div has a min-height, but the inner divs are all varying heights. Because the inner divs are absolute positioned, they do not affect the outer divs height. Is there a way to make these inner divs affect the height of the outer div? The reason I am styling these divs with position:absolute is so that they all start at the top of the container div.

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• How do I join three tables with SQLalchemy and keeping all of the columns in one of the tables?

  - by jimka

  So, I have three tables: The class defenitions: engine = create_engine('sqlite://test.db', echo=False) SQLSession = sessionmaker(bind=engine) Base = declarative_base() class Channel(Base): __tablename__ = 'channel' id = Column(Integer, primary_key = True) title = Column(String) description = Column(String) link = Column(String) pubDate = Column(DateTime) class User(Base): __tablename__ = 'user' id = Column(Integer, primary_key = True) username = Column(String) password = Column(String) sessionId = Column(String) class Subscription(Base): __tablename__ = 'subscription' userId = Column(Integer, ForeignKey('user.id'), primary_key=True) channelId = Column(Integer, ForeignKey('channel.id'), primary_key=True) And the SQL commands that are executed to create them: CREATE TABLE subscription ( "userId" INTEGER NOT NULL, "channelId" INTEGER NOT NULL, PRIMARY KEY ("userId", "channelId"), FOREIGN KEY("userId") REFERENCES user (id), FOREIGN KEY("channelId") REFERENCES channel (id) ); CREATE TABLE user ( id INTEGER NOT NULL, username VARCHAR, password VARCHAR, "sessionId" VARCHAR, PRIMARY KEY (id) ); CREATE TABLE channel ( id INTEGER NOT NULL, title VARCHAR, description VARCHAR, link VARCHAR, "pubDate" TIMESTAMP, PRIMARY KEY (id) ); NOTE: I know user.username should be unique, need to fix that, and I'm not sure why SQLalchemy creates some row names with the double-quotes. And I'm trying to come up with a way to retrieve all of the channels, as well as an indication on what channels one particular user (identified by user.sessionId together with user.id) has a subscription on. For example, say we have four channels: channel1, channel2, channel3, channel4; a user: user1; who has a subscription on channel1 and channel4. The query for user1 would return something like: channel.id | channel.title | subscribed --------------------------------------- 1 channel1 True 2 channel2 False 3 channel3 False 4 channel4 True This is a best-case result, but since I have absolutely no clue as how to accomplish the subscribed column, I've been instead trying to get the particular users id in the rows where the user has a subscription and where a subscription is missing, just leave it blank. The database engine that I'm using together with SQLalchemy atm. is sqlite3 I've been scratching my head over this for two days now, I've no problem joining together all three by way of the subscription table but then all of the channels where the user does not have a subscription gets omitted. I hope I've managed to describe my problem sufficiently, thanks in advance.

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• How to do a Postgresql subquery in select clause with join in from clause like SQL Server?

  - by Ricardo

  I am trying to write the following query on postgresql: select name, author_id, count(1), (select count(1) from names as n2 where n2.id = n1.id and t2.author_id = t1.author_id ) from names as n1 group by name, author_id This would certainly work on Microsft SQL Server but it does not at all on postegresql. I read its documentation a bit and it seems I could rewrite it as: select name, author_id, count(1), total from names as n1, (select count(1) as total from names as n2 where n2.id = n1.id and n2.author_id = t1.author_id ) as total group by name, author_id But that returns the following error on postegresql: "subquery in FROM cannot refer to other relations of same query level". So I'm stuck. Does anyone know how I can achieve that? Thanks

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• Is there a Cart/Catalog app out there that isnt a full site?

  - by prodigitalson

  Every solution i come across seems to be a complete store with far too many options and too much functionality. I can write my own cart to get the minimal functionality i need out of the frontend, im just trying to cut out the time writing a complex backend. What im really looking for is something that offers the backend functionality for a product catalog, order management, etc. while providing a smooth and consistent API to access the data for my completely custom frontend application. The frontend will be in PHP so the API would have to be native PHP or some kind of web service interface i can create my own php models around. It would need to run on a LAMP stack and would preferably be written in PHP, Python, or Ruby just in case i need to customize the backend (she curently has ZenCart and hates it - says its far too complicated and sophisticated for her needs). Does such a thing exist? Or what would be the next best thing?

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• How do I join two git repos without a common root, where all modified files are the same?

  - by Evan Carroll

  I have a git-cpan-init of a repo which yielded a different root node from another already established git repo I found on github C:A:S:DBI. I've developed quite a bit on my repo, and I'd like to merge or replay my edits on a fork of the more authoritative repository. Does anyone know how to do this? I think it is safe to assume none of the file-contents of the modified files are different -- the code base hasn't been since Nov 08'. For clarity the git hub repo is the authoritative one. My local repo is the one I want to go up to git hub shown as a real git fork.

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• Can I create a standalone (not ran in browser, having full trust) application with Moonlight?

  - by Ivan

  I look forward to develop a WPF MVVC application which is to be ran both on Windows with .Net Framework and Mac/Linux with Mono. As far as I understand the only part of of WPF implemented in Mono is Silverlight as Moonlight. As far as I've read it is possible to develop a standalone application with Silverlight 3, but is it possible with Moonlight 2?

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• Integrating lesser known e-payment gateways full of surprises?

  - by John

  I've integrated about half a dozen e-payment gateways, from popular ones (like paypal) to not-so popular ones. It seems every time I try to integrate a non-popular epayment gateway, I exceed my original time-estimation. I think I'm a decent programmer, but my time estimations probably needs work. Do other programmers run into many "surprises" when integrating e-payment gateways they've never heard of? Any advice will help. thanks

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• Getting error 400 / 404 - HttpUtility.UrlEncode not encoding full string?

  - by Justin808

  Why do the following URLs give me the IIS errors below: A) http://192.168.1.96/cms/View.aspx/Show/Small+test' A2) http://192.168.1.96/cms/View.aspx/Show/Small%20test' <-- this works, but is not the result from HttpUtility.UrlEncode() B) http://192.168.1.96/cms/View.aspx/Show/'%26$%23funky**!!~''+page Error for A: HTTP Error 404.11 - Not Found The request filtering module is configured to deny a request that contains a double escape sequence. Error for B: HTTP Error 400.0 - Bad Request ASP.NET detected invalid characters in the URL. The last part of the URL after /Show/ is the result after the text is being sent through HttpUtility.UrlEncode() so, according to Microsoft it is URL Encoded correctly. If I user HttpUtility.UrlPathEncode() rather than HttpUtility.UrlEncode() I get the A2 results. But B ends up looking like: http://192.168.1.96/TVCMS-CVJZ/cms/View.aspx/Show/'&$#funky**!!~''%20page which is still wrong. Does Microsoft know how to URL Encode at all? Is there a function someone has written up to do it the correct way?

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• vector<vector<largeObject>> vs. vector<vector<largeObject>*> in c++

  - by Leif Andersen

  Obviously it will vary depending on the compiler you use, but I'm curious as to the performance issues when doing vector<vector<largeObject>> vs. vector<vector<largeObject>*>, especially in c++. In specific: let's say that you have the outer vector full, and you want to start inserting elements into first inner vector. How will that be stored in memory if the outer vector is just storing pointers, as apposed to storing the whole inner vector. Will the whole outer vector have to be moved to gain more space, or will the inner vector be moved (assuming that space wasn't pre-allocated), causing problems with the outer vector? Thank you

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• Does `throw` cause stack variables (full types) to be freed from memory in C++?

  - by nbolton

  I'm pondering a question on Brainbench. I actually realised that I could answer my question easily by compiling the code, but it's an interesting question nonetheless, so I'll ask the question anyway and answer it myself shortly. Take a look at this snippet: The question considers what happens when we throw from a destructor (which causes terminate() to be called). It's become clear to me by asking the question that the memory is indeed freed and the destructor is called, but, is this before or after throw is called from foo? Perhaps the issue here is that throw is used while the stack is unwinding that is the problem... Actually this is slightly confusing.

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• Doing a join across two databases with different collations on SQL Server and getting an error.

  - by Andrew G. Johnson

  I know, I know with what I wrote in the question I shouldn't be surprised. But my situation is slowly working on an inherited POS system and my predecessor apparently wasn't aware of JOINs so when I looked into one of the internal pages that loads for 60 seconds I see that it's a fairly quick, rewrite these 8 queries as one query with JOINs situation. Problem is that besides not knowing about JOINs he also seems to have had a fetish for multiple databases and surprise, surprise they use different collations. Fact of the matter is we use all "normal" latin characters that English speaking people would consider the entire alphabet and this whole thing will be out of use in a few months so a bandaid is all I need. Long story short is I need some kind of method to cast to a single collation so I can compare two fields from two databases. Exact error is: Cannot resolve the collation conflict between "SQL_Latin1_General_CP850_CI_AI" and "SQL_Latin1_General_CP1_CI_AS" in the equal to operation.

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• Is it possible to join these two regex expressions into one?

  - by Pure.Krome

  Hi folks, i have the following two regular expressions (in order btw). 1. ^~/buying/(.*)\?(.*) => foo= group 1 baa= group 2. 2. ^~/buying/(.*) => foo= group 1 baa= nothing/empty/null/baibai What's i'm trying to do is, if the url has a questionmark, then split it into two groups. Otherwise, just throw all the stuff into the first group. the reason why the order is important for me, is that if i switch them round, the '?' regex will never get fired because the #2 expression (above) will catch all. So .. can this be re-fixed? NOTE: I have tried using this website** to help me debug/tweak .. but I can't figure it out. ** I have no affiliation with that site.

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• How do I use Criteria to make a join on a date field (in DB2) based on the year.

  - by HtmlTableGuru

  I have a java.util.Date field in my Object. I would like to use Criteria to select all rows that have a date field with a given year. The SQL would look like the following: SELECT * FROM GAME GM WHERE YEAR(GM.GAME_DATE) = 2010 How can I use Criteria to accomplish this? Thanks in advance. public Collection<Game> getGamesByDate(Date date){ Collection<Game> games = null; try { session.beginTransaction(); Criteria criteria = session.createCriteria(Game.class); criteria .... ... ... games = criteria.list(); } catch (HibernateException e) { e.printStackTrace(); } return games; }

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• SQLAlchemy Expression Language problem

  - by Torkel

  I'm trying to convert this to something sqlalchemy expression language compatible, I don't know if it's possible out of box and are hoping someone more experienced can help me along. The backend is PostgreSQL and if I can't make it as an expression I'll create a string instead. SELECT DISTINCT date_trunc('month', x.x) as date, COALESCE(b.res1, 0) AS res1, COALESCE(b.res2, 0) AS res2 FROM generate_series( date_trunc('year', now() - interval '1 years'), date_trunc('year', now() + interval '1 years'), interval '1 months' ) AS x LEFT OUTER JOIN( SELECT date_trunc('month', access_datetime) AS when, count(NULLIF(resource_id != 1, TRUE)) AS res1, count(NULLIF(resource_id != 2, TRUE)) AS res2 FROM tracking_entries GROUP BY date_trunc('month', access_datetime) ) AS b ON (date_trunc('month', x.x) = b.when) First of all I got a class TrackingEntry mapped to tracking_entries, the select statement within the outer joined can be converted to something like (pseudocode):: from sqlalchemy.sql import func, select from datetime import datetime, timedelta stmt = select([ func.date_trunc('month', TrackingEntry.resource_id).label('when'), func.count(func.nullif(TrackingEntry.resource_id != 1, True)).label('res1'), func.count(func.nullif(TrackingEntry.resource_id != 2, True)).label('res2') ], group_by=[func.date_trunc('month', TrackingEntry.access_datetime), ]) Considering the outer select statement I have no idea how to build it, my guess is something like: outer = select([ func.distinct(func.date_trunc('month', ?)).label('date'), func.coalesce(?.res1, 0).label('res1'), func.coalesce(?.res2, 0).label('res2') ], from_obj=[ func.generate_series( datetime.now(), datetime.now() + timedelta(days=365), timedelta(days=1) ).label(x) ]) Then I suppose I have to link those statements together without using foreign keys: outer.outerjoin(stmt???).??(func.date_trunc('month', ?.?), ?.when) Anyone got any suggestions or even better a solution?

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• How to order by last name on a full name column?

  - by GateKiller

  I have a SQL Table with a column called FullName which contains, for example, "John Smith". How can order the data by the last name that appears in the FullName column? For a long name like "Laurence John Fishburne", I would like to order the data by the word "Fishburne". Thus, names are stored in the order First Name Middle Names Last Name I am using Microsoft SQL Server 2005.

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• How do I view the full content of a text or varchar(MAX) column in SQL Server 2008 Management Studio

  - by adamjford

  In this live SQL Server 2008 (build 10.0.1600) database, there's an Events table, which contains a text column named Details. (Yes, I realize this should actually be a varchar(MAX) column, but whoever set this database up did not do it that way.) This column contains very large logs of exceptions and associated JSON data that I'm trying to access through SQL Server Management Studio, but whenever I copy the results from the grid to a text editor, it truncates it at 43679 characters. I've read on various locations on the Internet that you can set your Maximum Characters Retrieved for XML Data in Tools > Options > Query Results > SQL Server > Results To Grid to Unlimited, and then perform a query such as this: select Convert(xml, Details) from Events where EventID = 13920 (Note that the data is column is not XML at all. CONVERTing the column to XML is merely a workaround I found from Googling that someone else has used to get around the limit SSMS has from retrieving data from a text or varchar(MAX) column.) However, after setting the option above, running the query, and clicking on the link in the result, I still get the following error: Unable to show XML. The following error happened: Unexpected end of file has occurred. Line 5, position 220160. One solution is to increase the number of characters retrieved from the server for XML data. To change this setting, on the Tools menu, click Options. So, any idea on how to access this data? Would converting the column to varchar(MAX) fix my woes?

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• Which will be the best query OR there is an another one?

  - by serhan

  SELECT k.id,k.adsoyad, COUNT(DISTINCT(e.id)) as iletisimbilgisisay, COUNT(DISTINCT(f.id)) AS ilangonderensay, COUNT(DISTINCT(g.id)) AS emlaksahibisay, isNULL(MAX(eb.yonetici_kisi),0) AS yoneticiid FROM dbo.kisiler k LEFT OUTER JOIN dbo.emlaklar e ON e.iletisimbilgisi=k.id LEFT OUTER JOIN dbo.emlaklar f ON f.ilangonderen=k.id LEFT OUTER JOIN dbo.emlaklar g ON g.emlaksahibi=k.id LEFT OUTER JOIN dbo.emlakcibilgileri eb ON eb.yonetici_kisi=k.id GROUP BY k.id,k.adsoyad ORDER BY yoneticiid DESC, iletisimbilgisisay DESC, ilangonderensay DESC total execution time (above) 28 SELECT id,adsoyad, (select COUNT(id) FROM dbo.emlaklar WHERE iletisimbilgisi=k.id) AS iletisimbilgisisay, (select COUNT(id) FROM dbo.emlaklar WHERE emlaksahibi=k.id) AS emlaksahibisay, (select COUNT(id) FROM dbo.emlaklar WHERE ilangonderen=k.id) AS ilangonderensay, (Select isNULL(MAX(id),0) FROM dbo.emlakcibilgileri WHERE yonetici_kisi=k.id) AS yoneticiid FROM dbo.kisiler k total execution time 4 my tables are emlaklar: id int, ilangonderen int,iletisimbilgisi int,emlaksahibi int kisiler: id int,kisiadi emlakcibilgileri: id int,yonetici_kisi int,firma and ilangonderen,iletisimbilgisi,emlaksahibi,yonetici_kisi => kisiler.id

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• How to get the full pathname of the current shell script?

  - by Dan

  Is there a less brute-force way to do this? #!/bin/ksh THIS_SCRIPT=$(/usr/bin/readlink -f $(echo $0 | /bin/sed "s,^[^/],$PWD/&,")) echo $THIS_SCRIPT I'm stuck using ksh but would prefer a solution that works in bash too (which I think this does).

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