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• IDC and Becham Research: New analyst reports and webcast

  - by terrencebarr

  Embedded Java is getting a lot of attention in the analyst community these days. Check out these new analyst reports and a webcast by IDC as well as Beecham Research. IDC published a White Paper titled “Ghost in the Machine: Java for Embedded Development”, and an accompanying webcast recording. Highlights of the White Paper: The embedded systems industry is projected to continue to expand rapidly, reaching $2.1 trillion in 2015 The market for intelligent systems, where Java’s rich set of services are most needed, is projected to grow to 78% of all embedded systems in 2015  Java is widely used in embedded systems and is expected to continue to gain traction in areas where devices present an application platform for developers The free IDC webcast and White Paper can be accessed here. Beecham Research published a report titled “Designing an M2M Platform for the Connected World”. Highlights of the report: The total revenue for M2M Services is projected to double, from almost $15 billion in 2012 to over $30 billion in 2016 The primary driver for M2M solutions is now enabling new services Important trends that are developing are: Enterprise integration – more data and using the data more strategically, new markets in the Internet of Things (IoT), processing large amounts of data in real time (complex event processing) Using the same software development environment for all parts of an M2M solution is a major advantage if the software can be optimized for each part of the solution The free Beecham Research report can be accessed here. Cheers, – Terrence Filed under: Mobile & Embedded Tagged: iot, Java Embedded, M2M, research, webcast

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• IDC and Becham Research: New analyst reports and webcast

  - by terrencebarr

  Embedded Java is getting a lot of attention in the analyst community these days. Check out these new analyst reports and a webcast by IDC as well as Beecham Research. IDC published a White Paper titled “Ghost in the Machine: Java for Embedded Development”, and an accompanying webcast recording. Highlights of the White Paper: The embedded systems industry is projected to continue to expand rapidly, reaching $2.1 trillion in 2015 The market for intelligent systems, where Java’s rich set of services are most needed, is projected to grow to 78% of all embedded systems in 2015  Java is widely used in embedded systems and is expected to continue to gain traction in areas where devices present an application platform for developers The free IDC webcast and White Paper can be accessed here. Beecham Research published a report titled “Designing an M2M Platform for the Connected World”. Highlights of the report: The total revenue for M2M Services is projected to double, from almost $15 billion in 2012 to over $30 billion in 2016 The primary driver for M2M solutions is now enabling new services Important trends that are developing are: Enterprise integration – more data and using the data more strategically, new markets in the Internet of Things (IoT), processing large amounts of data in real time (complex event processing) Using the same software development environment for all parts of an M2M solution is a major advantage if the software can be optimized for each part of the solution The free Beecham Research report can be accessed here. Cheers, – Terrence Filed under: Mobile & Embedded Tagged: iot, Java Embedded, M2M, research, webcast

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• The Oldest Big Data Problem: Parsing Human Language

  - by dan.mcclary

  There's a new whitepaper up on Oracle Technology Network which details the use of Digital Reasoning Systems' Synthesys software on Oracle Big Data Appliance.  Digital Reasoning's approach is inherently "big data friendly," as it leverages multiple components of the Hadoop ecosystem.  Moreover, the paper addresses the oldest big data problem of them all: extracting knowledge from human text.   You can find the paper here.   From the Executive Summary: There is a wealth of information to be extracted from natural language, but that extraction is challenging. The volume of human language we generate constitutes a natural Big Data problem, while its complexity and nuance requires a particular expertise to model and mine. In this paper we illustrate the impressive combination of Oracle Big Data Appliance and Digital Reasoning Synthesys software. The combination of Synthesys and Big Data Appliance makes it possible to analyze tens of millions of documents in a matter of hours. Moreover, this powerful combination achieves four times greater throughput than conducting the equivalent analysis on a much larger cloud-deployed Hadoop cluster.

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• Visual Studio 2010 Keyboard Shortcut Posters Available

  - by Jim Duffy

  I’m a firm believer in the productivity gains you experience when using keyboard shortcuts in Visual Studio. If you’re not using keyboard shortcuts while coding then your productivity is suffering. Some of my favorites (omitting the obvious ones like F5 to start debugging) as are: Ctrl+K, C – Comment section of code Ctrl+K, U – Uncomment section of code Ctrl+K, D – Format the current document (indentation, etc.) Shift+Alt+C – Add new class to a project Shift+Alt+A – Add existing item to a project Ctrl+Shift+A – Add new item to a project The good news is all of these and a TON of others are all documented in the Visual Studio Keyboard Shortcut Posters (available as PDFs). The only problem is there are so many you need a printer capable of printing on larger paper because while you can read them all on 8 1/2 x 11 paper in landscape mode, for them to be a valuable quick reference on your cubicle wall you’re going to need to print them on large paper. If you don’t have a printer capable of producing large sized printouts head down to Office Depot, Staples, FedEx Office, or your favorite print shop and have them print one for you. Oh and one last thing, I’d really like Microsoft to take those people’s picture off them. Really? Do we need to look at these people when trying to improve our productivity? Have a day. :-|

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• OpenWorld Suggest-a-Session Voting on Oracle Mix now OPEN!

  - by keith.laker

  Last year the Oracle OpenWorld team decided to use Oracle Mix as a way to select some of the papers for OpenWorld and this year we are following the same process. The majority of papers for this year's conference have already been selected, however, there are some presentation slots still available so the OpenWorld team are giving you the chance to vote on which papers you want to see at this year's OpenWorld conference.The voting process has just opened and will close on June 20. I did a quick search on the list of sessions one paper really caught my eye: Case Study: Real-Time data warehousing and fraud detection with Oracle 11gR2 by Dr. Holger Friedrich. As a data warehouse product manager I would love to see this paper selected. I have attended a number of presentations over the years given by Holger and he is an excellent, knowledgeable and entertaining presenter. The subject area is, for me, very interesting as it covers topics that I know are important to our customers and this case study highlights the innovative use of key database features. I would strongly encourage everyone to please vote for this paper. You can vote for Holger's presentation by going here:https://mix.oracle.com/oow10/proposals/10566-case-study-real-time-data-warehousing-and-fraud-detection-with-oracle-11gr2There are some rules relating to the voting process and these are all explained here: https://mix.oracle.com/oow10/faqA Quick Overview of the voting rules?1) You have to a member of the Oracle Mix communityBut membership is free! To sign up for a Mix account and you are one your way. You can sign-up by clicking on the "Create an Account" link in the top right corner of the Oracle Mix home page: https://mix.oracle.com/2) You have to vote for 3 different papersBased on last year’s voting pattern, the Mix team found that a number of participants were only voting for their own sessions. This year voters are required to vote on at least three sessions. How do I find the list of presentations? The full list of all available presentations is here: https://mix.oracle.com/oow10/proposalsGood luck and happy voting. Look forward to seeing you all at OpenWorld.

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• Why CFOs Should Care About Big Data

  - by jmorourke

  The topic of “big data” clearly has reached a tipping point in 2012.  With plenty of coverage over the past few years in the IT press, we are now starting to see the topic of “big data” covered in mainstream business press, including a cover story in the October 2012 issue of the Harvard Business Review.  To help customers understand the challenges of managing “big data” as well as the opportunities that can be created by leveraging “big data”, Oracle has recently run and published the results of a customer survey, as well as white papers and articles on this topic.  Most recently, we commissioned a white paper titled “Mastering Big Data: CFO Strategies to Transform Insight into Opportunity”. The premise here is that “big data” is not just a topic that CIOs should pay attention to, but one that CFOs should understand and take advantage of as well.  Clearly, whoever masters the art and science of big data will be positioned for competitive advantage in their industries or markets.  That’s why smart CFOs are taking control of big data and business analytics projects, not just to uncover new ways to drive growth in a slowing global economy, but also to be a catalyst for change in the enterprise.  With an increasing number of CFOs now responsible for overseeing IT investments and providing strategic insight to the board, CFOs will be increasingly called upon to take a leadership role in assessing the value of “big data” initiatives, building on their traditional skills in reporting and helping managers analyze data to support decision making. Here’s a link to the white paper referenced above, which is posted on the Oracle C-Central/CFO web site, as well as some other resources that can help CFOs master the topic of “big data”: White Paper “Mastering Big Data:  CFO Strategies to Transform Insight into Opportunity CFO Market Watch article:  “Does Big Data Affect the CFO?” Oracle Survey Report:  “From Overload to Impact – An Industry Scorecard on Big Data Industry Challenges” Upcoming Big Data Webcast with Andrew McAfee Here’s a general link to Oracle C-Central/CFO in case you want to start there: www.oracle.com/c-central/cfo Feel free to contact me if you have any questions or need additional information:  [email protected]

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• Proper updating of GeoClipMaps

  - by thr

  I have been working on an implementation of gpu-based geo clip maps, but there is a section of the GPU Gems 2 article that i just can't seem to understand, specifically this paragraph and more precisely the bolded part: The choice of grid size n = 2k-1 has the further advantage that the finer level is never exactly centered with respect to its parent next-coarser level. In other words, it is always offset by 1 grid unit either left or right, as well as either top or bottom (see Figure 2-4), depending on the position of the viewpoint. In fact, it is necessary to allow a finer level to shift while its next-coarser level stays fixed, and therefore the finer level must sometimes be off-center with respect to the next-coarser level. An alternative choice of grid size, such as n = 2k-3, would provide the possibility for exact centering Let's take an example image from the article: My "understanding" of the way the clip maps were update was that you floor the position of the viewpoint to an int, and such get the center vertex point if this is not the same as the previous center point, you update the entire map. Now, this obviously is not the case - but what I am failing to understand is this: If you look at the image above, if the viewpoint was to move one unit to the right, then the inner ring (the one just around the view point + white center square) would end up getting a 1 unit space on both the left and right side of itself. But there is nothing in the paper that deals with this, what i mean is that it would end up looking like this (excuse my crummy cut-and-paste editing of the above image): This is obviously not a valid state of the. So, would the solution be that a clip ring (layer) can only move in increments of the ring/layer it's contained within? Wouldn't this end up being very restrictive? I feel like I am missing some crucial understanding of parts of the algorithm, but I have been over both this paper and the original paper from 2004 and I just can't see what I am not getting.

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• Virtual Networks in Oracle Solaris - Part 5

  - by user12616590

             A         long         time      ago in a    blogosphere   far, far away... I wrote four blog entries to describe the new network virtualization features that were in Solaris 11 Express: Part 1 introduced the concept of network virtualization and listed the basic virtual network elements. Part 2 expanded on the concepts and discussed the resource management features. Part 3 demonstrated the creation of some of these virtual network elements. Part 4 demonstrated the network resource controls. I had planned a final entry that added virtual routers to the list of virtual network elements, but Jeff McMeekin wrote a paper that discuses the same features. That paper is available at OTN. And this Jeff can't write any better than that Jeff... All of the features described in those blog entries and that paper are also available in Solaris 11. It is possible that some details have changed, but the vast majority of the content is unchanged.

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• What is an appropriate language for expressing initial stages of algorithm refinement?

  - by hydroparadise

  First, this is not a homework assignment, but you can treat it as such ;). I found the following question in the published paper The Camel Has Two Humps. I was not a CS major going to college (I majored in MIS/Management), but I have a job where I find myself coding quite often. For a non-trivial programming problem, which one of the following is an appropriate language for expressing the initial stages of algorithm refinement? (a) A high-level programming language. (b) English. (c) Byte code. (d) The native machine code for the processor on which the program will run. (e) Structured English (pseudocode). What I do know is that you usually want to start your design implementation by writing down pseuducode and then moving/writing in the desired technology (because we all do that, right?) But I never thought about it in terms of refinement. I mean, if you were the original designer, then you might have access to the original pseudocode. But realisticly, when I have to maintain/refactor/refine somebody elses code, I just keep trucking with the language it currently resides in. Anybody have a definitive answer to this? As a side note, I did a quick scan of the paper as I havn't read every single detail. It presents various score statistics, can't find where the answers are with the paper.

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• Ububtu server 12.04 auto installation freezes at kickseeding running if ks.cfg has post scripts

  - by john206

  I'm trying to make a custom Ubuntu Server iso file. Kickstart file (ks.cfg) runs smooth when there is no %post in the file and Ubuntu installs correctly with ks configuration. Installation finishes installing base, apt, grub and It echos: Kickseed Running... and it freezes @ 0% I thought may be apt-get update doesnt work in ks file, I tried to install other apps like apache2 but no luck I have created dozen iso images and installed them in Virtual Box.I have been googling for 3 days and checked out ubuntu forums but haven't figured out the issue. I appreciate your help. This is how I made the iso image. My ks.file and txt.cfg files located in isolinux directory: root@ubuntu:/home/work mount -o loop ubuntu-12.04-amd64.iso original-iso/ rsync -a original-iso/ custom-iso/ cp ks.cfg custom-iso/isolinux/ cp txt.cfg custom-iso/isolinux/ chmod -R 777 custom-iso/ #Creating Iso image mkisofs -D -r -V “$IMAGE_NAME” -cache-inodes -J -l -b isolinux/isolinux.bin -c isolinux/boot.cat -no-emul-boot -boot-load-size 4 -boot-info-table -o ~/ubuntu-12.04-alternate-custom-amd64.iso custom-iso/ ks.cfg #Generated by Kickstart Configurator #platform=AMD64 or Intel EM64T #System language lang en_US #Language modules to install langsupport en_US #System keyboard keyboard us #System mouse mouse #System timezone timezone America/Los_Angeles #Root password rootpw --iscrypted somethingsomething #Initial user user ubuntu --fullname "ubuntu" --iscrypted --password somethingsomething. #Reboot after installation reboot #Use text mode install text #Install OS instead of upgrade install #Use CDROM installation media cdrom #System bootloader configuration bootloader --location=mbr #Clear the Master Boot Record zerombr yes #Partition clearing information clearpart --all --initlabel #Disk partitioning information part /boot --size 128 --fstype=ext3 --asprimary part / --size 512 --fstype=ext3 --asprimary part swap --size 512 part /tmp --size 512 --fstype=ext3 part /var --size 512 --fstype=ext3 part /usr --size 4096 --fstype=ext3 part /home --size 2048 --fstype=ext3 #System authorization infomation auth --useshadow --enablemd5 #Network information network --bootproto=dhcp --device=eth0 #Firewall configuration firewall --disabled --http --ftp --ssh #X Window System configuration information xconfig --depth=32 --resolution=1024x768 --defaultdesktop=GNOME %post apt-get update mkdir /home/user txt.cfg default autoinstall label autoinstall menu label ^Install Custom Ubuntu Server kernel /install/vmlinuz append file=/cdrom/preseed/ubuntu-server.seed initrd=/install/initrd.gz quiet ks=cdrom:/isolinux/ks.cfg -- label install menu label ^Install Ubuntu Server kernel /install/vmlinuz append file=/cdrom/preseed/ubuntu-server.seed vga=788 initrd=/install/initrd.gz quiet -- label cloud menu label ^Multiple server install with MAAS kernel /install/vmlinuz append modules=maas-enlist-udeb vga=788 initrd=/install/initrd.gz quiet -- label check menu label ^Check disc for defects kernel /install/vmlinuz append MENU=/bin/cdrom-checker-menu vga=788 initrd=/install/initrd.gz quiet -- label memtest menu label Test ^memory kernel /install/mt86plus label hd menu label ^Boot from first hard disk localboot 0x80

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• Using Windows 8 with Bootcamp?

  - by Farhad Yusufali

  I am trying to install Windows 8 using Bootcamp on OSX Mountain Lion. I need a bootable CD. Does the bootable CD have to be the size of the ISO image or can it be smaller (since it only contains the installer)? If it does not in fact have to be the size of the ISO image, what's the minimum required size of the CD I insert into my drive to create a bootable CD? (i.e. the minimum size of a bootable USB is 8GB)

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• RHEL5: Can't create sparse file bigger than 256GB in tmpfs

  - by John Kugelman

  /var/log/lastlog gets written to when you log in. The size of this file is based off of the largest UID in the system. The larger the maximum UID, the larger this file is. Thankfully it's a sparse file so the size on disk is much smaller than the size ls reports (ls -s reports the size on disk). On our system we're authenticating against an Active Directory server, and the UIDs users are assigned end up being really, really large. Like, say, UID 900,000,000 for the first AD user, 900,000,001 for the second, etc. That's strange but should be okay. It results in /var/log/lastlog being huuuuuge, though--once an AD user logs in lastlog shows up as 280GB. Its real size is still small, thankfully. This works fine when /var/log/lastlog is stored on the hard drive on an ext3 filesystem. It breaks, however, if lastlog is stored in a tmpfs filesystem. Then it appears that the max file size for any file on the tmpfs is 256GB, so the sessreg program errors out trying to write to lastlog. Where is this 256GB limit coming from, and how can I increase it? As a simple test for creating large sparse files I've been doing: dd if=/dev/zero of=sparse-file bs=1 count=1 seek=300GB I've tried Googling for "tmpfs max file size", "256GB filesystem limit", "linux max file size", things like that. I haven't been able to find much. The only mention of 256GB I can find is that ext3 filesystems with 2KB blocks are limited to 256GB files. But our hard drives are formatted with 4K blocks so that doesn't seem to be it--not to mention this is happening in a tmpfs mounted ON TOP of the hard drive so the ext3 partition shouldn't be a factor. This is all happening on a 64-bit Red Hat Enterprise Linux 5.4 system. Interestingly, on my personal development machine, which is a 32-bit Fedora Core 6 box, I can create 300GB+ files in tmpfs filesystems no problem. On the RHEL5.4 systems it is no go.

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• Exchange 2007 Standard Edition

  - by Phrontiste

  We Have : Exchange 2007 Standard Edition IBM System X3650 2 x Intel Xeon 5430 2.66 GHz Version 8.1 Build 240.6 Mailbox, Hub Transport, Client Access Role Installed on One Box Total Number of Mailboxes : 110 - 130 6 Physical Disks Disk 0,1 (68 GB) = Raid-1, OS Partition ( C: Partition) Disk 2,3 (279GB) = Raid-1, Exchange Database (First and Second Storage Groups) ( D: Partition ) Disk 4,5 (68 GB) = Raid-1, Exchange Transaction Logs ( E: Partition ) Setup: Storage Groups : D:\First Storage group\Mailbox database.edb Storage Groups : D:\Second Storage Group\Public Folder Database.edb Transaction Logs : E Partition Problem 1: On our D Partition (Mailbox Database Partition), total size is 279 GB, free space remaining is 64.7 GB, when I select the first storage group and second storage group folders and right click properties they report a size of 165 GB. Mailbox database reports a size of 157GB when right clicked Properties. where as the size displayed in the folder is 164,893,456 KB So, we are missing around 50-54 GB, there is nothing else on these drives, no page file, nothing at all. The partition housing the Transaction logs is reporting the sizes accurately. Any suggestions / fixes on the above ? Problem 2: As you may have already read in Problem 1, the size of the mailbox database is 157GB or 164GB reported; which is not recommended, a) What would you suggest we should do to divide mailboxes in storage groups on this same server ? b) How would we move mailboxes into different storage groups ? c) This is the information store size ? (Am I right in thinking that this is not recommended) d) Having multiple storage groups with one Mailbox DB in each, would that reduce the size of the Information Store? e) Any suggestions / how-to reduce the size of information store ? We didn't install this, we have inherited this - what other recommendations you can make in order to keep ourselves better prepared for any server disaster? We are backing up with Yosemite Backup on RD1000 (320GB) at the moment, which is backing up successfully, flushing the logs daily. We haven't done a test restore YET. I have tried to provide as much info as possible, please let me know if you need further info. Also, we haven't yet faced any problems in mailflow, access speeds, everything is working fine, we have two to five people accessing OWA or Outlook via vpn only. Thanks for your time to read the above - will look forward to your expert suggestions.

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• dmidecode showing more ram slots than available?

  - by Jestep

  I have some failing RAM in a server and I ran dmidecode to figure out what tyoe of RAM I needed to replace it with. The server has 6 RAM slots, 4 of which are in use. When I run dmidecode this is what I get. dmidecode 2.10 SMBIOS 2.4 present. Handle 0x001F, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: 72 bits Data Width: 64 bits Size: 2048 MB Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 00 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0020, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: 72 bits Data Width: 64 bits Size: 2048 MB Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 01 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0021, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: Unknown Data Width: Unknown Size: No Module Installed Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 02 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0022, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: Unknown Data Width: Unknown Size: No Module Installed Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 03 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0023, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: 72 bits Data Width: 64 bits Size: 2048 MB Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 10 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0024, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: 72 bits Data Width: 64 bits Size: 2048 MB Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 11 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0025, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: Unknown Data Width: Unknown Size: No Module Installed Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 12 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0026, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: Unknown Data Width: Unknown Size: No Module Installed Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 13 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Does anyone know why it would show 8 slots, with 4 empty instead of 6 slots with 2 empty? Also, but my records and by other tools, the server has 16Gb and not 8Gb in it currently. grep MemTotal /proc/meminfo MemTotal: 16435808 kB The board is a Tyan S5372-LC, running CentOS 5.4 x64. Also, my error log is showing errors in bank 6. Is there any way to determine which slot bank 6 is in via: dmidecode?

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• Cannot install grub to RAID1 (md0)

  - by Andrew Answer

  I have a RAID1 array on my Ubuntu 12.04 LTS and my /sda HDD has been replaced several days ago. I use this commands to replace: # go to superuser sudo bash # see RAID state mdadm -Q -D /dev/md0 # State should be "clean, degraded" # remove broken disk from RAID mdadm /dev/md0 --fail /dev/sda1 mdadm /dev/md0 --remove /dev/sda1 # see partitions fdisk -l # shutdown computer shutdown now # physically replace old disk by new # start system again # see partitions fdisk -l # copy partitions from sdb to sda sfdisk -d /dev/sdb | sfdisk /dev/sda # recreate id for sda sfdisk --change-id /dev/sda 1 fd # add sda1 to RAID mdadm /dev/md0 --add /dev/sda1 # see RAID state mdadm -Q -D /dev/md0 # State should be "clean, degraded, recovering" # to see status you can use cat /proc/mdstat This is the my mdadm output after sync: /dev/md0: Version : 0.90 Creation Time : Wed Feb 17 16:18:25 2010 Raid Level : raid1 Array Size : 470455360 (448.66 GiB 481.75 GB) Used Dev Size : 470455360 (448.66 GiB 481.75 GB) Raid Devices : 2 Total Devices : 2 Preferred Minor : 0 Persistence : Superblock is persistent Update Time : Thu Nov 1 15:19:31 2012 State : clean Active Devices : 2 Working Devices : 2 Failed Devices : 0 Spare Devices : 0 UUID : 92e6ff4e:ed3ab4bf:fee5eb6c:d9b9cb11 Events : 0.11049560 Number Major Minor RaidDevice State 0 8 1 0 active sync /dev/sda1 1 8 17 1 active sync /dev/sdb1 After bebuilding completion "fdisk -l" says what I have not valid partition table /dev/md0. This is my fdisk -l output: Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders, total 976773168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00057d19 Device Boot Start End Blocks Id System /dev/sda1 * 63 940910984 470455461 fd Linux raid autodetect /dev/sda2 940910985 976768064 17928540 5 Extended /dev/sda5 940911048 976768064 17928508+ 82 Linux swap / Solaris Disk /dev/sdb: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders, total 976773168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000667ca Device Boot Start End Blocks Id System /dev/sdb1 * 63 940910984 470455461 fd Linux raid autodetect /dev/sdb2 940910985 976768064 17928540 5 Extended /dev/sdb5 940911048 976768064 17928508+ 82 Linux swap / Solaris Disk /dev/md0: 481.7 GB, 481746288640 bytes 2 heads, 4 sectors/track, 117613840 cylinders, total 940910720 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md0 doesn't contain a valid partition table This is my grub install output: root@answe:~# grub-install /dev/sda /usr/sbin/grub-setup: warn: Attempting to install GRUB to a disk with multiple partition labels or both partition label and filesystem. This is not supported yet.. /usr/sbin/grub-setup: error: embedding is not possible, but this is required for cross-disk install. root@answe:~# grub-install /dev/sdb Installation finished. No error reported. So 1) "update-grub" find only /sda and /sdb Linux, not /md0 2) "dpkg-reconfigure grub-pc" says "GRUB failed to install the following devices /dev/md0" I cannot load my system except from /sdb1 and /sda1, but in DEGRADED mode... Anybody can resolve this issue? I have big headache with this.

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• Mac OS X missing disk

  - by leo

  In boot camp, it only see partition size to be 149G while disk utility shows only one partition with size 320G. Why diskutil and df gives me different sizes? Also how can i fix it? thanks df -h Filesystem Size Used Avail Capacity Mounted on /dev/disk0s2 **149Gi 20Gi 129Gi 14% /** devfs 110Ki 110Ki 0Bi 100% /dev map -hosts 0Bi 0Bi 0Bi 100% /net map auto_home 0Bi 0Bi 0Bi 100% /home and diskutil list /dev/disk0 #: TYPE NAME SIZE IDENTIFIER 0: GUID_partition_scheme ***320.1 GB disk0** 1: EFI 209.7 MB disk0s1 2: Apple_HFS Mac HD 319.6 GB disk0s2

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• Error 5 partition table invalid or corrupt

  - by Clodoaldo

  I'm trying to add a second SSD to a Centos 6 system. But I get the Error 5 partition table invalid or corrupt at boot. The system already has a single SSD (sdb) and a pair of HDDs (sd{a,c}) in a RAID 1 array from where it boots. It is as if the new SSD assumes one of the devices of the RAID array. Is it? How to avoid that or rearrange the setup? # cat fstab UUID=967b4035-782d-4c66-b22f-50244fe970ca / ext4 defaults 1 1 UUID=86fd06e9-cdc9-4166-ba9f-c237cfc43e02 /boot ext4 defaults 1 2 UUID=72552a7a-d8ae-4f0a-8917-b75a6239ce9f /ssd ext4 discard,relatime 1 2 UUID=8000e5e6-caa2-4765-94f8-9caeb2bda26e swap swap defaults 0 0 tmpfs /dev/shm tmpfs defaults 0 0 devpts /dev/pts devpts gid=5,mode=620 0 0 sysfs /sys sysfs defaults 0 0 proc /proc proc defaults 0 0 # ll /dev/disk/by-id/ total 0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX-part1 -> ../../sdb1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-ST3500413AS_5VMT49E3 -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:0 -> ../../md0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:1 -> ../../md1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:2 -> ../../md2 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-a04d7241:8da6023e:f9004352:107a923a -> ../../md1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-a22c43b9:f1954990:d3ddda5e:f9aff3c9 -> ../../md0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-f403a2d0:447803b5:66edba73:569f8305 -> ../../md2 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX-part1 -> ../../sdb1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3 -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5000c500383621ff -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5000c5003838b2e7 -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5e83a97f592139d6 -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5e83a97f592139d6-part1 -> ../../sdb1 # fdisk -l Disk /dev/sdb: 120.0 GB, 120034123776 bytes 255 heads, 63 sectors/track, 14593 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x79298ec9 Device Boot Start End Blocks Id System /dev/sdb1 1 14594 117219328 83 Linux Disk /dev/sdc: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000d99de Device Boot Start End Blocks Id System /dev/sdc1 1 1275 10240000 fd Linux raid autodetect /dev/sdc2 * 1275 1339 512000 fd Linux raid autodetect /dev/sdc3 1339 60802 477633536 fd Linux raid autodetect Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000b3327 Device Boot Start End Blocks Id System /dev/sda1 1 1275 10240000 fd Linux raid autodetect /dev/sda2 * 1275 1339 512000 fd Linux raid autodetect /dev/sda3 1339 60802 477633536 fd Linux raid autodetect Disk /dev/md0: 10.5 GB, 10484641792 bytes 2 heads, 4 sectors/track, 2559727 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md0 doesn't contain a valid partition table Disk /dev/md2: 489.1 GB, 489095557120 bytes 2 heads, 4 sectors/track, 119408095 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md2 doesn't contain a valid partition table Disk /dev/md1: 524 MB, 524275712 bytes 2 heads, 4 sectors/track, 127997 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md1 doesn't contain a valid partition table # cat /etc/grub.conf default=0 timeout=5 splashimage=(hd2,1)/grub/splash.xpm.gz hiddenmenu title CentOS (2.6.32-220.17.1.el6.x86_64) root (hd2,1) kernel /vmlinuz-2.6.32-220.17.1.el6.x86_64 ro root=UUID=967b4035-782d-4c66-b22f-50244fe970ca rd_MD_UUID=f403a2d0:447803b5:66edba73:569f8305 rd_MD_UUID=a22c43b9:f1954990:d3ddda5e:f9aff3c9 rd_NO_LUKS rd_NO_LVM rd_NO_DM LANG=en_US.UTF-8 SYSFONT=latarcyrheb-sun16 KEYBOARDTYPE=pc KEYTABLE=br-abnt2 crashkernel=auto rhgb quiet initrd /initramfs-2.6.32-220.17.1.el6.x86_64.img

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• How much memory do I need for innodb buffer pool?

  - by Shirko

  I read here that You need buffer pool a bit (say 10%) larger than your data (total size of Innodb TableSpaces) On the other hand I've read elswher that innodb_buffer_pool_size must be up to %80 of the memory. So I'm really confused how should I choose the best size for the pool. My database size is about 6GB and my total memory 64GB. Also I'm wondering if I increase the buffer pool size, I should shrink the number of maximum connections to make room for extra buffer, or these parameters are independent. Thanks

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• Error 22 no such partition on adding a SSD

  - by Clodoaldo

  I'm trying to add a second SSD to a Centos 6 system. But I get the error 22 no such partition at boot. The system already has a single SSD (sdb) and a pair of HDDs (sd{a,c}) in a RAID 1 array from where it boots. It is as if the new SSD assumes one of the devices of the RAID array. Is it? How to avoid that or rearrange the setup? # cat fstab UUID=967b4035-782d-4c66-b22f-50244fe970ca / ext4 defaults 1 1 UUID=86fd06e9-cdc9-4166-ba9f-c237cfc43e02 /boot ext4 defaults 1 2 UUID=72552a7a-d8ae-4f0a-8917-b75a6239ce9f /ssd ext4 discard,relatime 1 2 UUID=8000e5e6-caa2-4765-94f8-9caeb2bda26e swap swap defaults 0 0 tmpfs /dev/shm tmpfs defaults 0 0 devpts /dev/pts devpts gid=5,mode=620 0 0 sysfs /sys sysfs defaults 0 0 proc /proc proc defaults 0 0 # ll /dev/disk/by-id/ total 0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX-part1 -> ../../sdb1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-ST3500413AS_5VMT49E3 -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:0 -> ../../md0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:1 -> ../../md1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:2 -> ../../md2 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-a04d7241:8da6023e:f9004352:107a923a -> ../../md1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-a22c43b9:f1954990:d3ddda5e:f9aff3c9 -> ../../md0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-f403a2d0:447803b5:66edba73:569f8305 -> ../../md2 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX-part1 -> ../../sdb1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3 -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5000c500383621ff -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5000c5003838b2e7 -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5e83a97f592139d6 -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5e83a97f592139d6-part1 -> ../../sdb1 # fdisk -l Disk /dev/sdb: 120.0 GB, 120034123776 bytes 255 heads, 63 sectors/track, 14593 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x79298ec9 Device Boot Start End Blocks Id System /dev/sdb1 1 14594 117219328 83 Linux Disk /dev/sdc: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000d99de Device Boot Start End Blocks Id System /dev/sdc1 1 1275 10240000 fd Linux raid autodetect /dev/sdc2 * 1275 1339 512000 fd Linux raid autodetect /dev/sdc3 1339 60802 477633536 fd Linux raid autodetect Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000b3327 Device Boot Start End Blocks Id System /dev/sda1 1 1275 10240000 fd Linux raid autodetect /dev/sda2 * 1275 1339 512000 fd Linux raid autodetect /dev/sda3 1339 60802 477633536 fd Linux raid autodetect Disk /dev/md0: 10.5 GB, 10484641792 bytes 2 heads, 4 sectors/track, 2559727 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md0 doesn't contain a valid partition table Disk /dev/md2: 489.1 GB, 489095557120 bytes 2 heads, 4 sectors/track, 119408095 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md2 doesn't contain a valid partition table Disk /dev/md1: 524 MB, 524275712 bytes 2 heads, 4 sectors/track, 127997 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md1 doesn't contain a valid partition table # cat /etc/grub.conf default=0 timeout=5 splashimage=(hd2,1)/grub/splash.xpm.gz hiddenmenu title CentOS (2.6.32-220.17.1.el6.x86_64) root (hd2,1) kernel /vmlinuz-2.6.32-220.17.1.el6.x86_64 ro root=UUID=967b4035-782d-4c66-b22f-50244fe970ca rd_MD_UUID=f403a2d0:447803b5:66edba73:569f8305 rd_MD_UUID=a22c43b9:f1954990:d3ddda5e:f9aff3c9 rd_NO_LUKS rd_NO_LVM rd_NO_DM LANG=en_US.UTF-8 SYSFONT=latarcyrheb-sun16 KEYBOARDTYPE=pc KEYTABLE=br-abnt2 crashkernel=auto rhgb quiet initrd /initramfs-2.6.32-220.17.1.el6.x86_64.img

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• Problem with bluetooth on android 2.1 (samsung spica i5700) where pairing works but connection does

  - by user319634

  I have a Samsung Spica i5700 which I already have updated to Android 2.1. I am using the phone with an application called Run.GPS (http://www.rungps.net). This application logs data such as GPS position, route, speed, bearing etc. It can also log heartrate provided the user has a Zephyr HxM bluetooth heart rate monitor ("HxM"), which I do have. I can pair the HxM to the phone through the standard bluetooth utility. I'm prompted for the PIN, which I enter and the device is shown as 'Paired but not connected'. In the Run.GPS application itself, I click on 'Connect Heartrate Monitor'. This times out after about 30 seconds and the error message is 'Could not connect to heartrate monitor. Please try other settings'. I used a friend's HTC Windows Mobile as a control device to see if the HxM works there. It does. The Run.GPS application automatically sets the baud rate (initially to 9600 IIRC, though the connection also worked with higher baud rates) and it is possible to choose between various COM ports as well as a .Net COM port. I did some testing on my Spica Android, to try to find out why the bluetooth connection doesn't work. Below are some log files that I connected over adb when I clicked on 'Connect to Heartrate Monitor' in the Run.GPS application. I would be interested in any tips (including if I'm posting to the wrong forum here ;-)) - whether or not it's possible to experiment with the baud rate in Android etc. I still don't know if the problem is with the Run.GPS application (I've posted already on the development forum there) or with Android 2.1. I checked out another application - Endomondo - which is also a sport tracking application which supports heartrate monitor only with the HxM. There, what looked like exactly the same error occurred - I clicked on 'Connect Zephyr HxM'. For a few seconds I was shown the 'Connecting...' status, but then it timed out into 'Not Connected'. I'm thus tending towards looking at Android for the problem. Here's the output of adb logcat while trying to connect ./adb logcat | grep Run.GPS D/WYNEX> (11551): Excute :: Run.GPS Trainer UV, (null) E/Run.GPS (11997): Cannot connect to BT device E/Run.GPS (11997): java.io.IOException: Service discovery failed E/Run.GPS (11997): at android.bluetooth.BluetoothSocket$SdpHelper.doSdp(BluetoothSocket.java:374) E/Run.GPS (11997): at android.bluetooth.BluetoothSocket.connect(BluetoothSocket.java:184) E/Run.GPS (11997): at ju.a(Unknown Source) E/Run.GPS (11997): at qk.j(Unknown Source) E/Run.GPS (11997): at fs.c(Unknown Source) E/Run.GPS (11997): at le.a(Unknown Source) E/Run.GPS (11997): at s.b(Unknown Source) E/Run.GPS (11997): at pb.a(Unknown Source) E/Run.GPS (11997): at as.a(Unknown Source) E/Run.GPS (11997): at am.b(Unknown Source) E/Run.GPS (11997): at gf.onTouchEvent(Unknown Source) E/Run.GPS (11997): at android.view.View.dispatchTouchEvent(View.java:3709) E/Run.GPS (11997): at android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:884) E/Run.GPS (11997): at android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:884) E/Run.GPS (11997): at com.android.internal.policy.impl.PhoneWindow$DecorView.superDispatchTouchEvent(PhoneWindow.java:1665) E/Run.GPS (11997): at com.android.internal.policy.impl.PhoneWindow.superDispatchTouchEvent(PhoneWindow.java:1107) E/Run.GPS (11997): at android.app.Activity.dispatchTouchEvent(Activity.java:2061) E/Run.GPS (11997): at com.android.internal.policy.impl.PhoneWindow$DecorView.dispatchTouchEvent(PhoneWindow.java:1649) E/Run.GPS (11997): at android.view.ViewRoot.handleMessage(ViewRoot.java:1694) E/Run.GPS (11997): at android.os.Handler.dispatchMessage(Handler.java:99) E/Run.GPS (11997): at android.os.Looper.loop(Looper.java:123) E/Run.GPS (11997): at android.app.ActivityThread.main(ActivityThread.java:4363) E/Run.GPS (11997): at java.lang.reflect.Method.invokeNative(Native Method) E/Run.GPS (11997): at java.lang.reflect.Method.invoke(Method.java:521) E/Run.GPS (11997): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:860) E/Run.GPS (11997): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:618) E/Run.GPS (11997): at dalvik.system.NativeStart.main(Native Method) E/Run.GPS (11997): Cannot connect to BT device E/Run.GPS (11997): java.io.IOException: Service discovery failed Here's the output of dmesg while trying to connect the heartrate monitor <4>[74726.239833] select 11691 (.serviceModeApp), adj 15, size 3205, to kill <4>[74726.240741] select 11739 (com.wssnps), adj 15, size 3207, to kill <4>[74726.246870] select 11750 (id.partnersetup), adj 15, size 3219, to kill <4>[74726.253390] select 11857 (p.bluetoothicon), adj 15, size 3299, to kill <4>[74726.259879] select 13131 (ndroid.settings), adj 15, size 4586, to kill <4>[74726.266372] send sigkill to 13131 (ndroid.settings), adj 15, size 4586 <7>[74733.945097] [BT] GPIO_BT_WAKE = 1 <7>[74733.945121] [BT] wake_lock(bt_wake_lock) <7>[74733.951799] [BT] GPIO_BT_HOST_WAKE = 1 <7>[74733.951822] [BT] wake_lock timeout = 5 sec <7>[74735.890196] [BT] GPIO_BT_HOST_WAKE = 0 <7>[74736.150987] [BT] GPIO_BT_HOST_WAKE = 1 <7>[74736.151009] [BT] wake_lock timeout = 5 sec <7>[74737.490185] [BT] GPIO_BT_HOST_WAKE = 0 <7>[74740.073913] [BT] GPIO_BT_HOST_WAKE = 1 <7>[74740.073948] [BT] wake_lock timeout = 5 sec <7>[74741.315336] [BT] GPIO_BT_HOST_WAKE = 0 <7>[74743.249747] [BT] GPIO_BT_HOST_WAKE = 1 <7>[74743.249768] [BT] wake_lock timeout = 5 sec <7>[74744.865099] [BT] GPIO_BT_HOST_WAKE = 0 <7>[74745.154487] [BT] GPIO_BT_HOST_WAKE = 1 <7>[74745.154509] [BT] wake_lock timeout = 5 sec <7>[74748.852534] [BT] GPIO_BT_HOST_WAKE = 0 <7>[74749.156256] [BT] GPIO_BT_HOST_WAKE = 1 <7>[74749.156278] [BT] wake_lock timeout = 5 sec <7>[74750.490018] [BT] GPIO_BT_HOST_WAKE = 0 <4>[74754.230424] select 11691 (.serviceModeApp), adj 15, size 3191, to kill <4>[74754.231326] select 11739 (com.wssnps), adj 15, size 3193, to kill <4>[74754.237473] select 11750 (id.partnersetup), adj 15, size 3205, to kill <4>[74754.243950] select 11857 (p.bluetoothicon), adj 15, size 3283, to kill <4>[74754.250452] select 13140 (com.svox.pico), adj 15, size 3465, to kill <4>[74754.256787] send sigkill to 13140 (com.svox.pico), adj 15, size 3465

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• CUDA linking error - Visual Express 2008 - nvcc fatal due to (null) configuration file

  - by Josh

  Hi, I've been searching extensively for a possible solution to my error for the past 2 weeks. I have successfully installed the Cuda 64-bit compiler (tools) and SDK as well as the 64-bit version of Visual Studio Express 2008 and Windows 7 SDK with Framework 3.5. I'm using windows XP 64-bit. I have confirmed that VSE is able to compile in 64-bit as I have all of the 64-bit options available to me using the steps on the following website: (since Visual Express does not inherently include the 64-bit packages) http://jenshuebel.wordpress.com/2009/02/12/visual-c-2008-express-edition-and-64-bit-targets/ I have confirmed the 64-bit compile ability since the "x64" is available from the pull-down menu under "Tools-Options-VC++ Directories" and compiling in 64-bit does not result in the entire project being "skipped". I have included all the needed directories for 64-bit cuda tools, 64 SDK and Visual Express (\VC\bin\amd64). Here's the error message I receive when trying to compile in 64-bit: 1>------ Build started: Project: New, Configuration: Release x64 ------ 1>Compiling with CUDA Build Rule... 1>"C:\CUDA\bin64\nvcc.exe" -arch sm_10 -ccbin "C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\bin" -Xcompiler "/EHsc /W3 /nologo /O2 /Zi /MT " -maxrregcount=32 --compile -o "x64\Release\template.cu.obj" "c:\Documents and Settings\All Users\Application Data\NVIDIA Corporation\NVIDIA GPU Computing SDK\C\src\CUDA_Walkthrough_DeviceKernels\template.cu" 1>nvcc fatal : Visual Studio configuration file '(null)' could not be found for installation at 'C:/Program Files (x86)/Microsoft Visual Studio 9.0/VC/bin/../..' 1>Linking... 1>LINK : fatal error LNK1181: cannot open input file '.\x64\Release\template.cu.obj' 1>Build log was saved at "file://c:\Documents and Settings\Administrator\My Documents\Visual Studio 2008\Projects\New\New\x64\Release\BuildLog.htm" 1>New - 1 error(s), 0 warning(s) ========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ========== Here's the simple code I'm trying to compile/run in 64-bit: #include <stdlib.h> #include <stdio.h> #include <string.h> #include <math.h> #include <cuda.h> void mypause () { printf ( "Press [Enter] to continue . . ." ); fflush ( stdout ); getchar(); } __global__ void VecAdd1_Kernel(float* A, float* B, float* C, int N) { int i = blockDim.x*blockIdx.x+threadIdx.x; if (i<N) C[i] = A[i] + B[i]; //result should be a 16x1 array of 250s } __global__ void VecAdd2_Kernel(float* B, float* C, int N) { int i = blockDim.x*blockIdx.x+threadIdx.x; if (i<N) C[i] = C[i] + B[i]; //result should be a 16x1 array of 400s } int main() { int N = 16; float A[16];float B[16]; size_t size = N*sizeof(float); for(int i=0; i<N; i++) { A[i] = 100.0; B[i] = 150.0; } // Allocate input vectors h_A and h_B in host memory float* h_A = (float*)malloc(size); float* h_B = (float*)malloc(size); float* h_C = (float*)malloc(size); //Initialize Input Vectors memset(h_A,0,size);memset(h_B,0,size); h_A = A;h_B = B; printf("SUM = %f\n",A[1]+B[1]); //simple check for initialization //Allocate vectors in device memory float* d_A; cudaMalloc((void**)&d_A,size); float* d_B; cudaMalloc((void**)&d_B,size); float* d_C; cudaMalloc((void**)&d_C,size); //Copy vectors from host memory to device memory cudaMemcpy(d_A,h_A,size,cudaMemcpyHostToDevice); cudaMemcpy(d_B,h_B,size,cudaMemcpyHostToDevice); //Invoke kernel int threadsPerBlock = 256; int blocksPerGrid = (N+threadsPerBlock-1)/threadsPerBlock; VecAdd1(blocksPerGrid, threadsPerBlock,d_A,d_B,d_C,N); VecAdd2(blocksPerGrid, threadsPerBlock,d_B,d_C,N); //Copy results from device memory to host memory //h_C contains the result in host memory cudaMemcpy(h_C,d_C,size,cudaMemcpyDeviceToHost); for(int i=0; i<N; i++) //output result from the kernel "VecAdd" { printf("%f ", h_C[i] ); printf("\n"); } printf("\n"); cudaFree(d_A); cudaFree(d_B); cudaFree(d_C); free(h_A); free(h_B); free(h_C); mypause(); return 0; }

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• GetWindowPlacement/SetWindowPlacement not working in WinForms for high DPI

  - by RandomEngy

  I've got a legacy WinForms app and I want to save the window position and size across sessions. I've been using GetWindowPlacement and SetWindowPlacement during the FormClosing and Load events. The problem I'm getting is that at higher DPI settings (Such as Medium, size at 125%) the sizes keep inflating. I'll call SetWindowPlacement on it with a certain size, but when GetWindowPlacement is called, those numbers come back 25% bigger, even though the window was the same size all along. The same sort of problem exists when saving the size of a resizable element within the form. Now this works fine if I create a new WinForms project: The size stays stable even when running at the higher DPI. I'm guessing there's some legacy setting in the bowels of the project or some arcane Form setting that's messing it up, but I can't find out where. I've called IsProcessDPIAware on both projects and both are true. Does anyone know what might be causing this?

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• UIToolbar above UIWebView inside UIScrollView

  - by Nick VanderPyle

  I'd like to display a toolbar above a UIWebView but hide the toolbar until the person "pulls it down". The same functionality can be seen in Safari on the iPhone. When the page loads, the toolbar containing the address is hidden. You must pull it down. In Safari it's possible to scroll up and eventually see the toolbar or scroll down through the page contents. I've tried placing a UIToolbar and UIWebView inside a UIScrollView but it didn't work. I've tried setting the UIScrollView to the size of the toolbar and webview combined, but that didn't work. - (void)viewDidLoad{ CGSize size = CGSizeMake(webView.frame.size.width, toolBar.frame.size.height + webView.frame.size.height); [scrollView setContentSize:size]; } How should I go about doing this?

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• How to get rid of previous reflection when reflecting a UIImageView (with changing pictures)?

  - by epale

  Hi everyone, I have managed to use the reflection sample app from apple to create a reflection from a UIImageView. But the problem is that when I change the picture inside the UIImageView, the reflection from the previous displayed picture remains on the screen. The new reflection on the next picture then overlaps the previous reflection. How do I ensure that the previous reflection is removed when I change to the next picture? Thank you so much. I hope my question is not too basic. Here is the codes which i used so far: //reflection self.view.autoresizesSubviews = YES; self.view.userInteractionEnabled = YES; // create the reflection view CGRect reflectionRect = currentView.frame; // the reflection is a fraction of the size of the view being reflected reflectionRect.size.height = reflectionRect.size.height * kDefaultReflectionFraction; // and is offset to be at the bottom of the view being reflected reflectionRect = CGRectOffset(reflectionRect, 0, currentView.frame.size.height); reflectionView = [[UIImageView alloc] initWithFrame:reflectionRect]; // determine the size of the reflection to create NSUInteger reflectionHeight = currentView.bounds.size.height * kDefaultReflectionFraction; // create the reflection image, assign it to the UIImageView and add the image view to the containerView reflectionView.image = [self reflectedImage:currentView withHeight:reflectionHeight]; reflectionView.alpha = kDefaultReflectionOpacity; [self.view addSubview:reflectionView]; //reflection */ Then the codes below are used to form the reflection: CGImageRef CreateGradientImage(int pixelsWide, int pixelsHigh) { CGImageRef theCGImage = NULL; // gradient is always black-white and the mask must be in the gray colorspace CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceGray(); // create the bitmap context CGContextRef gradientBitmapContext = CGBitmapContextCreate(nil, pixelsWide, pixelsHigh, 8, 0, colorSpace, kCGImageAlphaNone); // define the start and end grayscale values (with the alpha, even though // our bitmap context doesn't support alpha the gradient requires it) CGFloat colors[] = {0.0, 1.0, 1.0, 1.0}; // create the CGGradient and then release the gray color space CGGradientRef grayScaleGradient = CGGradientCreateWithColorComponents(colorSpace, colors, NULL, 2); CGColorSpaceRelease(colorSpace); // create the start and end points for the gradient vector (straight down) CGPoint gradientStartPoint = CGPointZero; CGPoint gradientEndPoint = CGPointMake(0, pixelsHigh); // draw the gradient into the gray bitmap context CGContextDrawLinearGradient(gradientBitmapContext, grayScaleGradient, gradientStartPoint, gradientEndPoint, kCGGradientDrawsAfterEndLocation); CGGradientRelease(grayScaleGradient); // convert the context into a CGImageRef and release the context theCGImage = CGBitmapContextCreateImage(gradientBitmapContext); CGContextRelease(gradientBitmapContext); // return the imageref containing the gradient return theCGImage; } CGContextRef MyCreateBitmapContext(int pixelsWide, int pixelsHigh) { CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); // create the bitmap context CGContextRef bitmapContext = CGBitmapContextCreate (nil, pixelsWide, pixelsHigh, 8, 0, colorSpace, // this will give us an optimal BGRA format for the device: (kCGBitmapByteOrder32Little | kCGImageAlphaPremultipliedFirst)); CGColorSpaceRelease(colorSpace); return bitmapContext; } (UIImage *)reflectedImage:(UIImageView *)fromImage withHeight:(NSUInteger)height { if (!height) return nil; // create a bitmap graphics context the size of the image CGContextRef mainViewContentContext = MyCreateBitmapContext(fromImage.bounds.size.width, height); // offset the context - // This is necessary because, by default, the layer created by a view for caching its content is flipped. // But when you actually access the layer content and have it rendered it is inverted. Since we're only creating // a context the size of our reflection view (a fraction of the size of the main view) we have to translate the // context the delta in size, and render it. // CGFloat translateVertical= fromImage.bounds.size.height - height; CGContextTranslateCTM(mainViewContentContext, 0, -translateVertical); // render the layer into the bitmap context CALayer *layer = fromImage.layer; [layer renderInContext:mainViewContentContext]; // create CGImageRef of the main view bitmap content, and then release that bitmap context CGImageRef mainViewContentBitmapContext = CGBitmapContextCreateImage(mainViewContentContext); CGContextRelease(mainViewContentContext); // create a 2 bit CGImage containing a gradient that will be used for masking the // main view content to create the 'fade' of the reflection. The CGImageCreateWithMask // function will stretch the bitmap image as required, so we can create a 1 pixel wide gradient CGImageRef gradientMaskImage = CreateGradientImage(1, height); // create an image by masking the bitmap of the mainView content with the gradient view // then release the pre-masked content bitmap and the gradient bitmap CGImageRef reflectionImage = CGImageCreateWithMask(mainViewContentBitmapContext, gradientMaskImage); CGImageRelease(mainViewContentBitmapContext); CGImageRelease(gradientMaskImage); // convert the finished reflection image to a UIImage UIImage *theImage = [UIImage imageWithCGImage:reflectionImage]; // image is retained by the property setting above, so we can release the original CGImageRelease(reflectionImage); return theImage; } */

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• Is it possible to shorten my main function in this code?

  - by AjiPorter

  Is it possible for me to shorten my main() by creating a class? If so, what part of my code would most likely be inside the class? Thanks again to those who'll answer. :) #include <iostream> #include <fstream> #include <string> #include <ctime> #include <cstdlib> #define SIZE 20 using namespace std; struct textFile { string word; struct textFile *next; }; textFile *head, *body, *tail, *temp; int main() { ifstream wordFile("WORDS.txt", ios::in); // file object constructor /* stores words in the file into an array */ string words[SIZE]; char pointer; int i; for(i = 0; i < SIZE; i++) { while(wordFile >> pointer) { if(!isalpha(pointer)) { pointer++; break; } words[i] = words[i] + pointer; } } /* stores the words in the array to a randomized linked list */ srand(time(NULL)); int index[SIZE] = {0}; // temporary array of index that will contain randomized indexes of array words int j = 0, ctr; // assigns indexes to array index while(j < SIZE) { i = rand() % SIZE; ctr = 0; for(int k = 0; k < SIZE; k++) { if(!i) break; else if(i == index[k]) { // checks if the random number has previously been stored as index ctr = 1; break; } } if(!ctr) { index[j] = i; // assigns the random number to the current index of array index j++; } } /* makes sure that there are no double zeros on the array */ ctr = 0; for(i = 0; i < SIZE; i++) { if(!index[i]) ctr++; } if(ctr > 1) { int temp[ctr-1]; for(j = 0; j < ctr-1; j++) { for(i = 0; i < SIZE; i++) { if(!index[i]) { int ctr2 = 0; for(int k = 0; k < ctr-1; k++) { if(i == temp[k]) ctr2 = 1; } if(!ctr2) temp[j] = i; } } } j = ctr - 1; while(j > 0) { i = rand() % SIZE; ctr = 0; for(int k = 0; k < SIZE; k++) { if(!i || i == index[k]) { ctr = 1; break; } } if(!ctr) { index[temp[j-1]] = i; j--; } } } head = tail = body = temp = NULL; for(j = 0; j < SIZE; j++) { body = (textFile*) malloc (sizeof(textFile)); body->word = words[index[j]]; if(head == NULL) { head = tail = body; } else { tail->next = body; tail = body; cout << tail->word << endl; } } temp = head; while(temp != NULL) { cout << temp->word << endl; temp = temp->next; } return 0; }

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