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  • The sign of zero with float2

    - by JackOLantern
    Consider the following code performing operations on complex numbers with C/C++'s float: float real_part = log(3.f); float imag_part = 0.f; float real_part2 = (imag_part)*(imag_part)-(real_part*real_part); float imag_part2 = (imag_part)*(real_part)+(real_part*imag_part); The result will be real_part2= -1.20695 imag_part2= 0 angle= 3.14159 where angle is the phase of the complex number and, in this case, is pi. Now consider the following code: float real_part = log(3.f); float imag_part = 0.f; float real_part2 = (-imag_part)*(-imag_part)-(real_part)*(real_part); float imag_part2 = (-imag_part)*(real_part)+(real_part)*(-imag_part); The result will be real_part2= -1.20695 imag_part2= 0 angle= -3.14159 The imaginary part of the result is -0 which makes the phase of the result be -pi. Although still accomplishing with the principal argument of a complex number and with the signed property of floating point's 0, this changes is a problem when one is defining functions of complex numbers. For example, if one is defining sqrt of a complex number by the de Moivre formula, this will change the sign of the imaginary part of the result to a wrong value. How to deal with this effect?

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  • Prolog Beginner: How to unify with arithmentic cmparison operators or how to get a set var to range

    - by sixtyfootersdude
    I am new to prolog. I need to write an integer adder that will add numbers between 0-9 to other numbers 0-9 and produce a solution 0-18. This is what I want to do: add(in1, in2, out) :- in1 < 10, in2 < 10, out < 18. I would like to be able to call it like this: To Check if it is a valid addition: ?- add(1,2,3). true ?- add(1,2,4). false With one missing variable: ?- add(X,2,3). 1 ?- add(1,4,X). 5 With multiple missing variables: ?-add(X,Y,Z). % Some output that would make sense. Some examples could be: X=1, Y=1, Z=2 ; X=2, Y=1, Z=3 ...... I realize that this is probably a pretty simplistic question and it is probably very straightforward. However cording to the prolog tutorial I am using: "Unlike unification Arithmetic Comparison Operators operators cannot be used to give values to a variable. The can only be evaluated when every term on each side have been instantiated."

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  • Complexity of subset product

    - by threenplusone
    I have a set of numbers produced using the following formula with integers 0 < x < a. f(x) = f(x-1)^2 % a For example starting at 2 with a = 649. {2, 4, 16, 256, 636, 169, 5, 25, 649, 576, 137, ...} I am after a subset of these numbers that when multiplied together equals 1 mod N. I believe this problem by itself to be NP-complete (based on similaries to Subset-Sum problem). However starting with any integer (x) gives the same solution pattern. Eg. a = 649 {2, 4, 16, 256, 636, 169, 5, 25, 649, 576, 137, ...} = 16 * 5 * 576 = 1 % 649 {3, 9, 81, 71, 498, 86, 257, 500, 135, 53, 213, ...} = 81 * 257 * 53 = 1 % 649 {4, 16, 256, 636, 169, 5, 25, 649, 576, 137, 597, ...} = 256 * 25 * 137 = 1 % 649 I am wondering if this additional fact makes this problem solvable faster? Or if anyone has run into this problem previously or has any advice?

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  • Solving problems with near infinite potential solutions

    - by Zonda333
    Today I read the following problem: Use the digits 2, 0, 1, 1 and the operations +, -, x, ÷, sqrt, ^ , !, (), combinations, and permutations to write equations for the counting numbers 1 through 100. All four digits must be used in each expression. Only the digits 2, 0, 1, 1 may be used, and each must be used exactly once. Decimals may be used, as in .1, .02, etc. Digits may be combined; numbers such as 20 or 101 may be used. Example: 60 = 10*(2+1)!, 54 = ¹¹C2 - 0! Though I was able to quickly find around 50 solutions quite easily in my head, I thought programming it would be a far superior solution. However, I then realized I had no clue how to go about solving a problem like this. I am not asking for complete code for me to copy and paste, but for ideas about how I would solve this problems, and others like it that have nearly infinite potential solutions. As I will be writing it in python, where I have the most experience, I would prefer if the answers were more python based, but general ideas are great too.

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  • Using functions and arrays

    - by Ordo
    Hello! My little program below shall take 5 numbers from the user, store them into an array of integers and use a function to print them out. Sincerly it doesn't work and my output is always "00000". I can't find a mistake, so i would be glad about any advice. Thanks. #include <stdio.h> void printarray(int intarray[], int n) { int i; for(i = 0; i < n; i ++) { printf("%d", intarray[i]); } } int main () { const int n = 5; int temp = 0; int i; int intarray [n]; char check; printf("Please type in your numbers!\n"); for(i = 0; i < n; i ++) { printf(""); scanf("&d", &temp); intarray[i] = temp; getchar(); getchar(); } printf("Do you want to print them out? (yes/no): "); scanf("%c", &check); if (check == 'y') printarray(intarray, n); getchar(); getchar(); return 0; }

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  • SQL Server 2008 Prior String Extract

    - by Saidur Rahman
    I have strings like the ones below in a SQL column. I want to extract them as a Gigabyte amount in aggregate. Example: Original Column ---------> Expected Output from a TSQL function ------------------------------------------- $15 / 1GB 24m + Intern 120MB ----------> 1.12 GB $19.95 / 500MB + $49.95 / 9GB Blackberry -----> 9.5GB $174.95 Blackberry 24GB + $10 / 1GB Datapack ----> 25GB $79 / 6GB --> 6GB Null --> Null $20 Plan --> 0GB Note: for our purpose, 1000MB = 1 GB (not 1024). The pattern is numbers followed by GB/MB, usually they are combined like 1GB (without any space but may sometimes may contain a space, it is not particularly important if hard to implement for this exception). Sometimes there are up to three or four instances of GB/MB occurring in the same string which are usually separated by a + sign (see row 2 and 3 of my example above). I have seen how we extract the dollar values in one of the answers where numbers were followed by $ or extract all integers in a string but I don't want to extract the dollar values or all the integers in a string. I just want the sum of GB/MB in the string.

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  • game currency convert: math efficient

    - by Comradsky
    For variables:4 text views named diamondText, goldText, silverText, and bronzeText;money variable unsigned int money;and an NSTimer, every .1 sec,runs function: -(void)updateMoney{ money++; bronzeText.text = [NSString stringWithFormat:@"%d",money]; silverText.text = [NSString stringWithFormat:@"%d",money%10]; goldText.text = [NSString stringWithFormat:@"%d",money%100]; diamondText.text= [NSString stringWithFormat:@"%d",money%1000]; } Given that my currency is diamond = 10 gold = 10 silver = 10 bronze = 1; What would be most efficient way to calculate and display the money labels? How would you store this variable, with GameCenter and NSDictionary or GameCenter and something else? More details are below if you don't understand. To clarify: bronze has the last 2 numbers, silver has the next 2 numbers, and so on. I understand I could use 4 ints or an array, but i would rather try to use this method, unless theres a much more efficient way. Example: When money = 1000;bronzeText = nothing, silverText = 10,goldText = nothing, diamondText = nothing; What other ways would you do this that you think would be more efficient? I will be calling a function (void)collisionDetector that detects if my player.frame crosses with a flyingObject.frame, and if that object is a coin it gives an added value to money and then calls (void)updateMoney. Im just using the timer to test this and spawn these flying objects.

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  • C++ - my loop keeps on adding up to 0

    - by user1756913
    so far here's my code #include <iostream> using namespace std; int main () { int num1 = 0; int num2 = 0; int sum = 0; for(num2 = num1; num1 <= num2; num1 +=2) sum += num1; num1 = num1 / 2 == 0? num1 : num1 + 1; num2 = num2 / 2 == 0? num2 : num2 - 1; cout << "Enter the First Number:" << endl; cin >> num1; cout << "Enter the Second Number:" << endl; cin >> num2; cout << "Total Sum: " << sum << endl; } //end for but the sum keeps on adding up to 0 :/ here's the problem. Create a program that displays the sum of the even numbers between and including two numbers entered by the user. In other words, if the user enters an even number, that number should be included in the sum. For example, if the user enters the integers 2 and 7, the sum is 12 (2 + 4 + 6). If the user enters the integers 2 and 8, the sum is 20 (2 + 4 + 6 + 8 ). Display an error message if the first integer entered by the user is greater than the second integer.

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  • What is the best way to add two strings together?

    - by Pim Jager
    I read somewehere (I thought on codinghorror) that it is bad practice to add strings together as if they are numbers, since like numbers, strings cannot be changed. Thus, adding them together creates a new string. So, I was wondering, what is the best way to add two strings together, when focusing on performance? Which of these four is better, or is there another way which is better? //Note that normally at least one of these two strings is variable $str1 = 'Hello '; $str2 = 'World!'; $output1 = $str1.$str2; //This is said to be bad $str1 = 'Hello '; $output2 = $str1.'World!'; //Also bad $str1 = 'Hello'; $str2 = 'World!'; $output3 = sprintf('%s %s', $str1, $str2); //Good? //This last one is probaply more common as: //$output = sprintf('%s %s', 'Hello', 'World!'); $str1 = 'Hello '; $str2 = '{a}World!'; $output4 = str_replace('{a}', $str1, $str2); Does it even matter?

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  • Problem with running totals in jquery

    - by rshivers
    I'm having an issue trying to get an accurate running total for my calculations. When you enter numbers into the input field I get an accurate total for that line item, but the grand total comes out to a higher number. Note that this is a dynamic form and that the id's will change depending on how many form fields I have added to the form. Also, I have it set to make the calculations onKeyUp for each input field instead of a calculate button. The code that calculates a single item is this: function calcLineItem(id) { var id = $(id).attr("id"); var Item1 = $("#Item1" + id).val(); var Item2 = $("#Item2" + id).val(); var Item3 = $("#Item3" + id).val(); function calcTotal(Item1, Item2, Item3){ var total; total = Math.round((Item1 * Item2) * Item3); return total; } $("#total" + id).text(calcTotal(Item1, Item2, Item3)); calcAllFields(); } This will give me the total of this particular input field. The function at the end, calcAllFields(), is supposed to do the calculations for all items in my form to give me the grand total of all input fields: function calcAllFields(id) { var id = $(id).attr("id"); $('#target1').text($("#total" + id).map(function() { var currentValue = parseFloat(document.getElementById("currentTotal").value); var newValue = parseFloat($("#total" + id).text()); var newTotal = currentValue + newValue; document.getElementById("currentTotal").value = newTotal; return newTotal; }).get().join()); } The variable currentTotal is getting its value from a hidden field on my form: <input type="hidden" id="currentTotal" value="0"> As I enter numbers a field the calculation for that line will be accurate, but the grand total will be inaccurate because the value for currentTotal will continue to increment with every key stroke I make in the input field. Any ideas on how to avoid this from happening?

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  • Regex preg_match issue with commas

    - by Serge Sf
    This is my code to pre_match when an amount looks like this: $ 99.00 and it works if (preg_match_all('/[$]\s\d+(\.\d+)?/', $tout, $matches)) { $tot2 = $matches[0]; $tot2 = preg_replace("/\\\$/", '', $tot2);} I need to do the same thing for a amount that looks like this (with a comma): $ 99,00 Thank you for your help (changing dot for comma do not help, there is an "escape" thing I do not understand... Idealy I need to preg_match any number that looks like an amount with dot or commas and with or without dollar sign before or after (I know, it's a lot to ask :) since on the result form I want to scan there are phone and street numbers... UPDATE (For some reason I cannot comment on replies) : To test properly, I need to preg_replace the comma by a dot (since we are dealings with sums, I don't think calculations can be done on numbers with commas in it). So to clarify my question, I should say : I need to transform, let's say "$ 200,24" to "200.24". (could be amounts bettween 0.10 to 1000.99) : $tot2 = preg_replace("/\\\$/", '', $tot2);} (this code just deals with the $ (it works), I need adaptation to deal also with the change of (,) for (.))

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  • What is a more "ruby way" to write this code?

    - by steadfastbuck
    This was a homework assignment for my students (I am a teaching assistant) in c and I am trying to learn Ruby, so I thought I would code it up. The goal is to read integers from a redirected file and print some simple information. The first line in the file is the number of elements, and then each integer resides on its own line. This code works (although perhaps inefficiently), but how can I make the code more Ruby-like? #!/usr/bin/ruby -w # first line is number of inputs (Don't need it) num_inputs = STDIN.gets.to_i # read inputs as ints h = Hash.new STDIN.each do |n| n = n.to_i h[n] = 1 unless h[n] and h[n] += 1 end # find smallest mode h.sort.each do |k,v| break puts "Mode is: #{k}", "\n" if v == h.values.max end # mode unique? v = h.values.sort print "Mode is unique: " puts v.pop == v.pop, "\n" # print number of singleton odds, # odd elems repeated odd number times in desc order # even singletons in desc order odd_once = 0 odd = Array.new even = Array.new h.each_pair do |k, v| odd_once += 1 if v == 1 and k.odd? odd << k if v.odd? even << k if v == 1 and k.even? end puts "Number of elements with an odd value that appear only once: #{odd_once}", "\n" puts "Elements repeated an odd number of times:" puts odd.sort.reverse, "\n" puts "Elements with an even value that appear exactly once:" puts even.sort.reverse, "\n" # print fib numbers in the hash class Fixnum def is_fib? l, h = 0, 1 while h <= self return true if h == self l, h = h, l+h end end end puts "Fibonacci numbers:" h.keys.sort.each do |n| puts n if n.is_fib? end

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  • Finding the Largest and Smallest Integers In A Set- Basic

    - by Ka112324
    I'm kind of on the right track, however my output is not quite right. The program asks for the number of integers you have and then it asks for those numbers. For an example is says please enter the number of integers, you can put 3. And then you enter 3 numbers. I can't use arrays because I am a beginner student and we have not learned those yet. Using count is the only way that allows me to input integers. What do I need to add to my program? Again I am a general computer science student so I can't use anything advanced. I used include iostream, namespace int main and all that you just cant see it int data; int num; int count=0; int max=0; do { cout<<"Enter the number of intergers"<<endl; cin>>num; while (count<num) { cout<<"Please enter a number"<<endl; cin>>data; count++; if (data<min) { min=data; } if (data>max) { max=data; } } cout<<"Smallest integer:"<<min<<endl; cout<<"Largest integer:"<<max<<endl; cout<<"Would you like to continue?"<<endl; cin>>ans; } while ((ans=='y')||(ans=='Y')); return 0; }

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  • Weird send() problem (with Wireshark log)

    - by Meta
    I had another question about this issue, but I didn't ask properly, so here I go again! I'm sending a file by sending it in chunks. Right now, I'm playing around with different numbers for the size of that chunk, to see what size is the most efficient. When testing on the localhost, any chunk size seems to work fine. But when I tested it over the network, it seems like the maximum chunk size is 8191 bytes. If I try anything higher, the transfer becomes extremely, painfully, slow. To show what happens, here are the first 100 lines of Wireshark logs when I use a chunk size of 8191 bytes, and when I use a chunk size of 8192 bytes: (the sender is 192.168.0.102, and the receiver is 192.168.0.100) 8191: http://pastebin.com/E7jFFY4p 8192: http://pastebin.com/9P2rYa1p Notice how in the 8192 log, on line 33, the receiver takes a long time to ACK the data. This happens again on line 103 and line 132. I believe this delay is the root of the problem. Note that I have not modified the SO_SNDBUF option nor the TCP_NODELAY option. So my question is, why am I getting delayed ACKs when sending files in chunks of 8192 bytes, when everything works fine when using chunks of 8191 bytes? Edit: As an experiment, I tried to do the file transfer in the other direction (from 192.168.0.100 to 192.168.0.102), and surprisingly, any number worked! (Although numbers around 8000 seemed to perform the smoothest). So then the problem is with my computer! But I'm really not sure what to check for. Edit 2: Here is the pseudocode I use to send and receive data.

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  • Define a positive number to be isolated if none of the digits in its square are in its cube [closed]

    - by proglaxmi
    Define a positive number to be isolated if none of the digits in its square are in its cube. For example 163 is n isolated number because 69*69 = 26569 and 69*69*69 = 4330747 and the square does not contain any of the digits 0, 3, 4 and 7 which are the digits used in the cube. On the other hand 162 is not an isolated number because 162*162=26244 and 162*162*162 = 4251528 and the digits 2 and 4 which appear in the square are also in the cube. Write a function named isIsolated that returns 1 if its argument is an isolated number, it returns 0 if its not an isolated number and it returns -1 if it cannot determine whether it is isolated or not (see the note below). The function signature is: int isIsolated(long n) Note that the type of the input parameter is long. The maximum positive number that can be represented as a long is 63 bits long. This allows us to test numbers up to 2,097,151 because the cube of 2,097,151 can be represented as a long. However, the cube of 2,097,152 requires more than 63 bits to represent it and hence cannot be computed without extra effort. Therefore, your function should test if n is larger than 2,097,151 and return -1 if it is. If n is less than 1 your function should also return -1. Hint: n % 10 is the rightmost digit of n, n = n/10 shifts the digits of n one place to the right. The first 10 isolated numbers are N n*n n*n*n 2 4 8 3 9 27 8 64 512 9 81 729 14 196 2744 24 576 13824 28 784 21952 34 1156 39304 58 3364 195112 63 3969 250047

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  • multiplying all elements in an array by an outside number?

    - by prodo
    I need to multiple all the values in an array by 3000 which in turn would create a new array that I will use to subtract from another array. I've tried to create a separate method that would do that for me but all I got back in the multiplied array was a bunch of numbers and symbols strangely? here is the code that I wrote public static void main(String[] args) { int numberOfTaxpayers = Integer.parseInt(JOptionPane.showInputDialog("Enter how many users you would like to calculate taxes for: "); int[] usernumChild = new int[numberOfTaxPayers]; for (int i = 0; i < usernumChild.length; i++) { usernumChild[i] = Integer.parseInt(JOptionPane.showInputDialog("Enter number of children for user "+ (i+1) +": ")); }//this for loop finds out the number of children per user so we can later multiply each input by 3000 to create an array that determine dependency exemption for each user int[] depndExemp = multiply(usernumChild, 3000);//this was the calling of the multiply method... somewhere here is the error!! }//end main method public static int[] multiply(int[] children, int number) { int array[] = new int[children.length]; for( int i = 0; i < children.length; i++) { children[i] = children[i] * number; }//end for return array; }//this is the method that I was shown in a previous post on how to create return an array in this the dependency exemption array but when I tested this by printing out the dependency array all I received were a jumble of wrong numbers.

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  • get random password with puppet function

    - by ninja-2
    I have a function that allow me to generate random password. My function is working well without a puppetmaster. When i tried with a master an error appear when I called the function : Error 400 on SERVER: bad value for range Here is my function module Puppet::Parser::Functions newfunction(:get_random_password, :type => :rvalue, :doc => <<-EOS Returns a random password. EOS ) do |args| raise(Puppet::ParseError, "get_random_password(): Wrong number of arguments " + "given (#{args.size} for 1)") if args.size != 1 specials = ((33..33).to_a + (35..38).to_a + (40..47).to_a + (58..64).to_a + (91..93).to_a + (95..96).to_a + (123..125).to_a).pack('U*').chars.to_a numbers = (0..9).to_a alphal = ('a'..'z').to_a alphau = ('A'..'Z').to_a length = args[0] CHARS = (alphal + specials + numbers + alphau) pwd = CHARS.sort_by { rand }.join[0...length] return pwd end end The function is called in both case with $pwd = get_random_password(10). When I specified the length directly in the function to 10 for example. the password is well generated in master mode. Have you any idea why i can't specify the lentgth value ? Thanks for any help.

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  • Transfering data from Excel to dataGridView

    - by Panecillo
    I have a problem when I want to transfer data from Excel to dataGridView in C#. My Excel's column has numeric and alphanumeric values. But for example, if the column has 3 numbers and 2 alphanumeric values then only the numbers are shown in the dataGridView, and vice versa. Why aren't all the values shown? The next is what happen: Excel's Column: DataGridView's Column: 45654 45654 P745K 31233 31233 23111 23111 45X2Y Here is my code to load the dataGridView: string connectionString = @"Provider=Microsoft.Jet.OLEDB.4.0;Data Source=D:\test.xls;Extended Properties=""Excel 8.0;HDR=YES;"""; DbProviderFactory factory = DbProviderFactories.GetFactory("System.Data.OleDb"); DbDataAdapter adapter = factory.CreateDataAdapter(); DbCommand selectCommand = factory.CreateCommand(); selectCommand.CommandText = "SELECT * FROM [sheet1$]"; DbConnection connection = factory.CreateConnection(); connection.ConnectionString = connectionString; selectCommand.Connection = connection; adapter.SelectCommand = selectCommand; data = new DataSet(); adapter.Fill(data); dataGridView1.DataSource = data.Tables[0].DefaultView; I hope I explained it well. Sorry my bad english. Thanks.

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  • PHP function: find argument's variable name, and function calls line number

    - by Majid
    I want to do something like this for simplifying logging operations. Any idea what I should put in for ?[1]? and ?[2]?? function log_var($var) { $line = ?[1]?; $var_name = ?[2]?; $line--; $filepath = 'log-' . date('Y-m-d'). '.txt'; $message = "$line, $var_name = $var\n"; $fp = fopen($filepath, "a"); fwrite($fp, $message); fclose($fp); @chmod($filepath, 0666); return TRUE; } This how I'd use the function in code (numbers are assumed to be line numbers in actual code): 23 $a = 'hello'; 24 log_var($a); 25 $b = 'bye'; 26 log_var($b); And this is what I want to be written to the log file: 23, a = hello 25, b = bye

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  • getline with ints C++

    - by Mdjon26
    I have a file 0 3 2 1 2 3 4 5 6 6 8 1 Where the first number for each line is the row, the second number is the column, and the third number is the data contained in that row, column. This will be a given [8][8] array so I have already initialized everything to 0, but how can I store each of these data values? For example, I want [0][3] =2 and [1][2] = 3. I would like to keep track of the line on which I found that row, col, and data value. So, how can I correctly insert these values into my 2-D array? int rowcol[8][8]; for (int i=0; i < 9; i++) for (int j=0; j < 9; j++) { rowcol[i][j] =0; } ifstream myfile; int nums; myfile.open(text.c_str()); while (!myfile.eof()) { myfile >> nums; numbers.push_back(nums); } for (int i=0; i < numbers.size(); i++) { //Not sure what the best approach here would be and I'm not even sure if I should have done a vector... }

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  • not a proper naming convention but it's working fine, How and what is need of naming conventions if it works?

    - by Pravallika69
    I'm new to javascript programming. I have found below example while practicing javascript. <html> <head> <script type="text/javascript"> function changeTabIndex() { document.getElementById('1').tabIndex="3" document.getElementById('2').tabIndex="2" document.getElementById('3').tabIndex="1" } </script> </head> <body> <p><a id="1" href="http://www.w3schools.com">1</a></p> <p><a id="2" href="http://www.w3schools.com">2</a></p> <p><a id="3" href="http://www.w3schools.com">3</a></p> <input type="button" onclick="changeTabIndex()" value="Change TabIndex" /> </body> </html> What's my doubt is, naming conventions for id attribute must start with an alphabet followed by numbers and underscore. But in this example even though they used numbers as id's the code working fine.Then what is the need of following naming conventions. It seems to be simple but anyone please clarify it.

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  • Convert binary unsigned vector to dec list

    - by Juan
    This code convert a unsigned long vector variable cR1 to NB_ERRORS numbers (in 'a' variable I print these numbers). for (l = 0; l < NB_ERRORS; ++l) { k = (l * EXT_DEGREE) / BIT_SIZE_OF_LONG; j = (l * EXT_DEGREE) % BIT_SIZE_OF_LONG; a = cR1[k] >> j; if(j + EXT_DEGREE > BIT_SIZE_OF_LONG) a ^= cR1[k + 1] << (BIT_SIZE_OF_LONG - j); a &= ((1 << EXT_DEGREE) - 1); printf("\na=%d\n",a); } For example I am have a cR1 with two elements that follow: 0,0,1,1,0,1,0,0,0,0,1,0,0,1,1,1,1,1,0,0,1,1,1,1,0,0,0,1,1,0,0,0,1,0,1,1,0,0,1,0,1,1,1,0,0,1,0,0,1,0,1,0,1,1,1,0,1,0,0,1,1,1,1,0, executing that code I get (44), (228, (243), (24), (77), (39), (117), (121). This code convert from right to left, I want modify to convert from right to left, Where I will be able to modify this? pdta: In the example case EXT_DEGREE = 8, BIT_SIZE_OF_LONG = 32

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  • EDIT: I need to generate a string of 7 chars that is based on the id of the row.

    - by Totty
    EDIT: I need to generate a string of 7 chars that is based on the id of the row. So knowing the id of the image and a secret key, i should get the generated string. the string must contain chars from "a" to "z" and numbers from 0 to 9. I have a dir that contains photos like this dir/p3/i2/s21/thumb.jpg the generated string is p3i2s21, then is used to calculate the path of the image. EDIT: currently im using the id of the image: id = 55 then i modify and i get path = 000000055 then path = "000/000/055" then path = "000/000/055/thumb.jpg" ready to use! now i want something more clever because is easy to track down all the images from a server, because ids are sequencial: 1, 2, 3, 4, 5, 6... so i must think of creating from 55 a string that is 7 char length and will not overlap with other numbers. I can even transform the 55 to 0000055 and from this convert to a 7 char length string using a secret string. then when i got the secret string and the id i want to get back that 7 char length string. Is this possible? i was thinking about hases but they only uses 0-9 and a-e and are more chars.. :s

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  • Working with PivotTables in Excel

    - by Mark Virtue
    PivotTables are one of the most powerful features of Microsoft Excel.  They allow large amounts of data to be analyzed and summarized in just a few mouse clicks. In this article, we explore PivotTables, understand what they are, and learn how to create and customize them. Note:  This article is written using Excel 2010 (Beta).  The concept of a PivotTable has changed little over the years, but the method of creating one has changed in nearly every iteration of Excel.  If you are using a version of Excel that is not 2010, expect different screens from the ones you see in this article. A Little History In the early days of spreadsheet programs, Lotus 1-2-3 ruled the roost.  Its dominance was so complete that people thought it was a waste of time for Microsoft to bother developing their own spreadsheet software (Excel) to compete with Lotus.  Flash-forward to 2010, and Excel’s dominance of the spreadsheet market is greater than Lotus’s ever was, while the number of users still running Lotus 1-2-3 is approaching zero.  How did this happen?  What caused such a dramatic reversal of fortunes? Industry analysts put it down to two factors:  Firstly, Lotus decided that this fancy new GUI platform called “Windows” was a passing fad that would never take off.  They declined to create a Windows version of Lotus 1-2-3 (for a few years, anyway), predicting that their DOS version of the software was all anyone would ever need.  Microsoft, naturally, developed Excel exclusively for Windows.  Secondly, Microsoft developed a feature for Excel that Lotus didn’t provide in 1-2-3, namely PivotTables.  The PivotTables feature, exclusive to Excel, was deemed so staggeringly useful that people were willing to learn an entire new software package (Excel) rather than stick with a program (1-2-3) that didn’t have it.  This one feature, along with the misjudgment of the success of Windows, was the death-knell for Lotus 1-2-3, and the beginning of the success of Microsoft Excel. Understanding PivotTables So what is a PivotTable, exactly? Put simply, a PivotTable is a summary of some data, created to allow easy analysis of said data.  But unlike a manually created summary, Excel PivotTables are interactive.  Once you have created one, you can easily change it if it doesn’t offer the exact insights into your data that you were hoping for.  In a couple of clicks the summary can be “pivoted” – rotated in such a way that the column headings become row headings, and vice versa.  There’s a lot more that can be done, too.  Rather than try to describe all the features of PivotTables, we’ll simply demonstrate them… The data that you analyze using a PivotTable can’t be just any data – it has to be raw data, previously unprocessed (unsummarized) – typically a list of some sort.  An example of this might be the list of sales transactions in a company for the past six months. Examine the data shown below: Notice that this is not raw data.  In fact, it is already a summary of some sort.  In cell B3 we can see $30,000, which apparently is the total of James Cook’s sales for the month of January.  So where is the raw data?  How did we arrive at the figure of $30,000?  Where is the original list of sales transactions that this figure was generated from?  It’s clear that somewhere, someone must have gone to the trouble of collating all of the sales transactions for the past six months into the summary we see above.  How long do you suppose this took?  An hour?  Ten?  Probably. If we were to track down the original list of sales transactions, it might look something like this: You may be surprised to learn that, using the PivotTable feature of Excel, we can create a monthly sales summary similar to the one above in a few seconds, with only a few mouse clicks.  We can do this – and a lot more too! How to Create a PivotTable First, ensure that you have some raw data in a worksheet in Excel.  A list of financial transactions is typical, but it can be a list of just about anything:  Employee contact details, your CD collection, or fuel consumption figures for your company’s fleet of cars. So we start Excel… …and we load such a list… Once we have the list open in Excel, we’re ready to start creating the PivotTable. Click on any one single cell within the list: Then, from the Insert tab, click the PivotTable icon: The Create PivotTable box appears, asking you two questions:  What data should your new PivotTable be based on, and where should it be created?  Because we already clicked on a cell within the list (in the step above), the entire list surrounding that cell is already selected for us ($A$1:$G$88 on the Payments sheet, in this example).  Note that we could select a list in any other region of any other worksheet, or even some external data source, such as an Access database table, or even a MS-SQL Server database table.  We also need to select whether we want our new PivotTable to be created on a new worksheet, or on an existing one.  In this example we will select a new one: The new worksheet is created for us, and a blank PivotTable is created on that worksheet: Another box also appears:  The PivotTable Field List.  This field list will be shown whenever we click on any cell within the PivotTable (above): The list of fields in the top part of the box is actually the collection of column headings from the original raw data worksheet.  The four blank boxes in the lower part of the screen allow us to choose the way we would like our PivotTable to summarize the raw data.  So far, there is nothing in those boxes, so the PivotTable is blank.  All we need to do is drag fields down from the list above and drop them in the lower boxes.  A PivotTable is then automatically created to match our instructions.  If we get it wrong, we only need to drag the fields back to where they came from and/or drag new fields down to replace them. The Values box is arguably the most important of the four.  The field that is dragged into this box represents the data that needs to be summarized in some way (by summing, averaging, finding the maximum, minimum, etc).  It is almost always numerical data.  A perfect candidate for this box in our sample data is the “Amount” field/column.  Let’s drag that field into the Values box: Notice that (a) the “Amount” field in the list of fields is now ticked, and “Sum of Amount” has been added to the Values box, indicating that the amount column has been summed. If we examine the PivotTable itself, we indeed find the sum of all the “Amount” values from the raw data worksheet: We’ve created our first PivotTable!  Handy, but not particularly impressive.  It’s likely that we need a little more insight into our data than that. Referring to our sample data, we need to identify one or more column headings that we could conceivably use to split this total.  For example, we may decide that we would like to see a summary of our data where we have a row heading for each of the different salespersons in our company, and a total for each.  To achieve this, all we need to do is to drag the “Salesperson” field into the Row Labels box: Now, finally, things start to get interesting!  Our PivotTable starts to take shape….   With a couple of clicks we have created a table that would have taken a long time to do manually. So what else can we do?  Well, in one sense our PivotTable is complete.  We’ve created a useful summary of our source data.  The important stuff is already learned!  For the rest of the article, we will examine some ways that more complex PivotTables can be created, and ways that those PivotTables can be customized. First, we can create a two-dimensional table.  Let’s do that by using “Payment Method” as a column heading.  Simply drag the “Payment Method” heading to the Column Labels box: Which looks like this: Starting to get very cool! Let’s make it a three-dimensional table.  What could such a table possibly look like?  Well, let’s see… Drag the “Package” column/heading to the Report Filter box: Notice where it ends up…. This allows us to filter our report based on which “holiday package” was being purchased.  For example, we can see the breakdown of salesperson vs payment method for all packages, or, with a couple of clicks, change it to show the same breakdown for the “Sunseekers” package: And so, if you think about it the right way, our PivotTable is now three-dimensional.  Let’s keep customizing… If it turns out, say, that we only want to see cheque and credit card transactions (i.e. no cash transactions), then we can deselect the “Cash” item from the column headings.  Click the drop-down arrow next to Column Labels, and untick “Cash”: Let’s see what that looks like…As you can see, “Cash” is gone. Formatting This is obviously a very powerful system, but so far the results look very plain and boring.  For a start, the numbers that we’re summing do not look like dollar amounts – just plain old numbers.  Let’s rectify that. A temptation might be to do what we’re used to doing in such circumstances and simply select the whole table (or the whole worksheet) and use the standard number formatting buttons on the toolbar to complete the formatting.  The problem with that approach is that if you ever change the structure of the PivotTable in the future (which is 99% likely), then those number formats will be lost.  We need a way that will make them (semi-)permanent. First, we locate the “Sum of Amount” entry in the Values box, and click on it.  A menu appears.  We select Value Field Settings… from the menu: The Value Field Settings box appears. Click the Number Format button, and the standard Format Cells box appears: From the Category list, select (say) Accounting, and drop the number of decimal places to 0.  Click OK a few times to get back to the PivotTable… As you can see, the numbers have been correctly formatted as dollar amounts. While we’re on the subject of formatting, let’s format the entire PivotTable.  There are a few ways to do this.  Let’s use a simple one… Click the PivotTable Tools/Design tab: Then drop down the arrow in the bottom-right of the PivotTable Styles list to see a vast collection of built-in styles: Choose any one that appeals, and look at the result in your PivotTable:   Other Options We can work with dates as well.  Now usually, there are many, many dates in a transaction list such as the one we started with.  But Excel provides the option to group data items together by day, week, month, year, etc.  Let’s see how this is done. First, let’s remove the “Payment Method” column from the Column Labels box (simply drag it back up to the field list), and replace it with the “Date Booked” column: As you can see, this makes our PivotTable instantly useless, giving us one column for each date that a transaction occurred on – a very wide table! To fix this, right-click on any date and select Group… from the context-menu: The grouping box appears.  We select Months and click OK: Voila!  A much more useful table: (Incidentally, this table is virtually identical to the one shown at the beginning of this article – the original sales summary that was created manually.) Another cool thing to be aware of is that you can have more than one set of row headings (or column headings): …which looks like this…. You can do a similar thing with column headings (or even report filters). Keeping things simple again, let’s see how to plot averaged values, rather than summed values. First, click on “Sum of Amount”, and select Value Field Settings… from the context-menu that appears: In the Summarize value field by list in the Value Field Settings box, select Average: While we’re here, let’s change the Custom Name, from “Average of Amount” to something a little more concise.  Type in something like “Avg”: Click OK, and see what it looks like.  Notice that all the values change from summed totals to averages, and the table title (top-left cell) has changed to “Avg”: If we like, we can even have sums, averages and counts (counts = how many sales there were) all on the same PivotTable! Here are the steps to get something like that in place (starting from a blank PivotTable): Drag “Salesperson” into the Column Labels Drag “Amount” field down into the Values box three times For the first “Amount” field, change its custom name to “Total” and it’s number format to Accounting (0 decimal places) For the second “Amount” field, change its custom name to “Average”, its function to Average and it’s number format to Accounting (0 decimal places) For the third “Amount” field, change its name to “Count” and its function to Count Drag the automatically created field from Column Labels to Row Labels Here’s what we end up with: Total, average and count on the same PivotTable! Conclusion There are many, many more features and options for PivotTables created by Microsoft Excel – far too many to list in an article like this.  To fully cover the potential of PivotTables, a small book (or a large website) would be required.  Brave and/or geeky readers can explore PivotTables further quite easily:  Simply right-click on just about everything, and see what options become available to you.  There are also the two ribbon-tabs: PivotTable Tools/Options and Design.  It doesn’t matter if you make a mistake – it’s easy to delete the PivotTable and start again – a possibility old DOS users of Lotus 1-2-3 never had. We’ve included an Excel that should work with most versions of Excel, so you can download to practice your PivotTable skills. Download Our Practice Excel File Similar Articles Productive Geek Tips Magnify Selected Cells In Excel 2007Share Access Data with Excel in Office 2010Make Excel 2007 Print Gridlines In Workbook FileMake Excel 2007 Always Save in Excel 2003 FormatConvert Older Excel Documents to Excel 2007 Format TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Ben & Jerry’s Free Cone Day, 3/23/10 New Stinger from McAfee Helps Remove ‘FakeAlert’ Threats Google Apps Marketplace: Tools & Services For Google Apps Users Get News Quick and Precise With Newser Scan for Viruses in Ubuntu using ClamAV Replace Your Windows Task Manager With System Explorer

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  • Simple MSBuild Configuration: Updating Assemblies With A Version Number

    - by srkirkland
    When distributing a library you often run up against versioning problems, once facet of which is simply determining which version of that library your client is running.  Of course, each project in your solution has an AssemblyInfo.cs file which provides, among other things, the ability to set the Assembly name and version number.  Unfortunately, setting the assembly version here would require not only changing the version manually for each build (depending on your schedule), but keeping it in sync across all projects.  There are many ways to solve this versioning problem, and in this blog post I’m going to try to explain what I think is the easiest and most flexible solution.  I will walk you through using MSBuild to create a simple build script, and I’ll even show how to (optionally) integrate with a Team City build server.  All of the code from this post can be found at https://github.com/srkirkland/BuildVersion. Create CommonAssemblyInfo.cs The first step is to create a common location for the repeated assembly info that is spread across all of your projects.  Create a new solution-level file (I usually create a Build/ folder in the solution root, but anywhere reachable by all your projects will do) called CommonAssemblyInfo.cs.  In here you can put any information common to all your assemblies, including the version number.  An example CommonAssemblyInfo.cs is as follows: using System.Reflection; using System.Resources; using System.Runtime.InteropServices;   [assembly: AssemblyCompany("University of California, Davis")] [assembly: AssemblyProduct("BuildVersionTest")] [assembly: AssemblyCopyright("Scott Kirkland & UC Regents")] [assembly: AssemblyConfiguration("")] [assembly: AssemblyTrademark("")]   [assembly: ComVisible(false)]   [assembly: AssemblyVersion("1.2.3.4")] //Will be replaced   [assembly: NeutralResourcesLanguage("en-US")] .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }   Cleanup AssemblyInfo.cs & Link CommonAssemblyInfo.cs For each of your projects, you’ll want to clean up your assembly info to contain only information that is unique to that assembly – everything else will go in the CommonAssemblyInfo.cs file.  For most of my projects, that just means setting the AssemblyTitle, though you may feel AssemblyDescription is warranted.  An example AssemblyInfo.cs file is as follows: using System.Reflection;   [assembly: AssemblyTitle("BuildVersionTest")] .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } Next, you need to “link” the CommonAssemblyinfo.cs file into your projects right beside your newly lean AssemblyInfo.cs file.  To do this, right click on your project and choose Add | Existing Item from the context menu.  Navigate to your CommonAssemblyinfo.cs file but instead of clicking Add, click the little down-arrow next to add and choose “Add as Link.”  You should see a little link graphic similar to this: We’ve actually reduced complexity a lot already, because if you build all of your assemblies will have the same common info, including the product name and our static (fake) assembly version.  Let’s take this one step further and introduce a build script. Create an MSBuild file What we want from the build script (for now) is basically just to have the common assembly version number changed via a parameter (eventually to be passed in by the build server) and then for the project to build.  Also we’d like to have a flexibility to define what build configuration to use (debug, release, etc). In order to find/replace the version number, we are going to use a Regular Expression to find and replace the text within your CommonAssemblyInfo.cs file.  There are many other ways to do this using community build task add-ins, but since we want to keep it simple let’s just define the Regular Expression task manually in a new file, Build.tasks (this example taken from the NuGet build.tasks file). <?xml version="1.0" encoding="utf-8"?> <Project ToolsVersion="4.0" DefaultTargets="Go" xmlns="http://schemas.microsoft.com/developer/msbuild/2003"> <UsingTask TaskName="RegexTransform" TaskFactory="CodeTaskFactory" AssemblyFile="$(MSBuildToolsPath)\Microsoft.Build.Tasks.v4.0.dll"> <ParameterGroup> <Items ParameterType="Microsoft.Build.Framework.ITaskItem[]" /> </ParameterGroup> <Task> <Using Namespace="System.IO" /> <Using Namespace="System.Text.RegularExpressions" /> <Using Namespace="Microsoft.Build.Framework" /> <Code Type="Fragment" Language="cs"> <![CDATA[ foreach(ITaskItem item in Items) { string fileName = item.GetMetadata("FullPath"); string find = item.GetMetadata("Find"); string replaceWith = item.GetMetadata("ReplaceWith"); if(!File.Exists(fileName)) { Log.LogError(null, null, null, null, 0, 0, 0, 0, String.Format("Could not find version file: {0}", fileName), new object[0]); } string content = File.ReadAllText(fileName); File.WriteAllText( fileName, Regex.Replace( content, find, replaceWith ) ); } ]]> </Code> </Task> </UsingTask> </Project> .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } If you glance at the code, you’ll see it’s really just going a Regex.Replace() on a given file, which is exactly what we need. Now we are ready to write our build file, called (by convention) Build.proj. <?xml version="1.0" encoding="utf-8"?> <Project ToolsVersion="4.0" DefaultTargets="Go" xmlns="http://schemas.microsoft.com/developer/msbuild/2003"> <Import Project="$(MSBuildProjectDirectory)\Build.tasks" /> <PropertyGroup> <Configuration Condition="'$(Configuration)' == ''">Debug</Configuration> <SolutionRoot>$(MSBuildProjectDirectory)</SolutionRoot> </PropertyGroup>   <ItemGroup> <RegexTransform Include="$(SolutionRoot)\CommonAssemblyInfo.cs"> <Find>(?&lt;major&gt;\d+)\.(?&lt;minor&gt;\d+)\.\d+\.(?&lt;revision&gt;\d+)</Find> <ReplaceWith>$(BUILD_NUMBER)</ReplaceWith> </RegexTransform> </ItemGroup>   <Target Name="Go" DependsOnTargets="UpdateAssemblyVersion; Build"> </Target>   <Target Name="UpdateAssemblyVersion" Condition="'$(BUILD_NUMBER)' != ''"> <RegexTransform Items="@(RegexTransform)" /> </Target>   <Target Name="Build"> <MSBuild Projects="$(SolutionRoot)\BuildVersionTest.sln" Targets="Build" /> </Target>   </Project> Reviewing this MSBuild file, we see that by default the “Go” target will be called, which in turn depends on “UpdateAssemblyVersion” and then “Build.”  We go ahead and import the Bulid.tasks file and then setup some handy properties for setting the build configuration and solution root (in this case, my build files are in the solution root, but we might want to create a Build/ directory later).  The rest of the file flows logically, we setup the RegexTransform to match version numbers such as <major>.<minor>.1.<revision> (1.2.3.4 in our example) and replace it with a $(BUILD_NUMBER) parameter which will be supplied externally.  The first target, “UpdateAssemblyVersion” just runs the RegexTransform, and the second target, “Build” just runs the default MSBuild on our solution. Testing the MSBuild file locally Now we have a build file which can replace assembly version numbers and build, so let’s setup a quick batch file to be able to build locally.  To do this you simply create a file called Build.cmd and have it call MSBuild on your Build.proj file.  I’ve added a bit more flexibility so you can specify build configuration and version number, which makes your Build.cmd look as follows: set config=%1 if "%config%" == "" ( set config=debug ) set version=%2 if "%version%" == "" ( set version=2.3.4.5 ) %WINDIR%\Microsoft.NET\Framework\v4.0.30319\msbuild Build.proj /p:Configuration="%config%" /p:build_number="%version%" .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } Now if you click on the Build.cmd file, you will get a default debug build using the version 2.3.4.5.  Let’s run it in a command window with the parameters set for a release build version 2.0.1.453.   Excellent!  We can now run one simple command and govern the build configuration and version number of our entire solution.  Each DLL produced will have the same version number, making determining which version of a library you are running very simple and accurate. Configure the build server (TeamCity) Of course you are not really going to want to run a build command manually every time, and typing in incrementing version numbers will also not be ideal.  A good solution is to have a computer (or set of computers) act as a build server and build your code for you, providing you a consistent environment, excellent reporting, and much more.  One of the most popular Build Servers is JetBrains’ TeamCity, and this last section will show you the few configuration parameters to use when setting up a build using your MSBuild file created earlier.  If you are using a different build server, the same principals should apply. First, when setting up the project you want to specify the “Build Number Format,” often given in the form <major>.<minor>.<revision>.<build>.  In this case you will set major/minor manually, and optionally revision (or you can use your VCS revision number with %build.vcs.number%), and then build using the {0} wildcard.  Thus your build number format might look like this: 2.0.1.{0}.  During each build, this value will be created and passed into the $BUILD_NUMBER variable of our Build.proj file, which then uses it to decorate your assemblies with the proper version. After setting up the build number, you must choose MSBuild as the Build Runner, then provide a path to your build file (Build.proj).  After specifying your MSBuild Version (equivalent to your .NET Framework Version), you have the option to specify targets (the default being “Go”) and additional MSBuild parameters.  The one parameter that is often useful is manually setting the configuration property (/p:Configuration="Release") if you want something other than the default (which is Debug in our example).  Your resulting configuration will look something like this: [Under General Settings] [Build Runner Settings]   Now every time your build is run, a newly incremented build version number will be generated and passed to MSBuild, which will then version your assemblies and build your solution.   A Quick Review Our goal was to version our output assemblies in an automated way, and we accomplished it by performing a few quick steps: Move the common assembly information, including version, into a linked CommonAssemblyInfo.cs file Create a simple MSBuild script to replace the common assembly version number and build your solution Direct your build server to use the created MSBuild script That’s really all there is to it.  You can find all of the code from this post at https://github.com/srkirkland/BuildVersion. Enjoy!

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