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  • Javascript - Text Input Attributes

    - by bobrusha
    I need to create a form element <input disabled type="text" value="smth" /> which is disabled by default. It enables when onmouseover occures. onmouseover="this.disabled=false;" And is disabled by onmouseout onmouseout="this.disabled=true;" What I need is to check the following. If the <input> is focused then it shouldn't be disabled. And if the form element loses focus it disables. Please help me to complete the events. <input disabled type="text" value="smth" onmouseover="this.disabled=false;" onfocus="???" onblur="???" onmouseout="if(???){this.disabled=true;}" />

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  • form validation with jquery and livevalidation

    - by ImpY
    I'm trying to do some form validation with livevaldation & jquery. I've a formular with an input field like that: <div id="prenameDiv" class="control-group"> `<input id="prename" name="prename" class="input-large" placeholder="Max" >` </div> So if there's an error on validation 'livevalidaton' adds the class 'LV_invalid_field' to the input - it looks like that: <div id="prenameDiv" class="control-group"> <input id="prename" name="prename" class="input-large LV_invalid_field" placeholder="Max" > </div> That's ok, but now I'll add another class 'error' to the div 'prenameDiv' when the DOM changes that it looks like that: <div id="prenameDiv" class="control-group error"> `<input id="prename" name="prename" class="input-large LV_invalid_field" placeholder="Max" ` </div> I tried it that way: if ($("#prenameDiv").bind("DOMSubtreeModified")){ `if ($("#prename").hasClass("LV_invalid_field")) {` $("#prenameDiv").addClass("error"); } } But nothing changes? Do you have some ideas?

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  • How to set title and class in the HTML for the options of a ModelChoiceField?

    - by celopes
    I have a model class MyModel(models.Model): name = models.CharField(max_length=80, unique=True) parent = models.ForeignKey('self', null=True, blank=True) I want to render a ModelChoiceField for that model that looks like: <select name="mymodel" id="id_mymodel"> <option value="1" title="Value 1" class="">Value 1</option> <option value="2" title="Value 2" class="Value 1">Value 2</option> </select> The differences between this output and the default output for a ModelChoiceField are the title and class elements in the OPTION tag. They don't exist in ModelChoiceField's default output. For my purposes: The title element is supposed to be the Option Name. The class element is supposed to be self.parent.name. (this is my problem) So, in the HTML snippet above, Value 1 has no parent and Value 2 has a parent of Value 1. What is the best mechanism to change ModelChoiceField's default HTML output? EDIT: I understand how to create a new Widget for rendering HTML. The problem is how to render a value from the underlying model in each of the options.

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  • How to get the right row in a sorted DataView?

    - by ZeissS
    Hi, I have a DataGrid containing a small table. Until now, I had a double click handler on this grid which iterated over all rows to find the selected one: DataTable table = (DataTable)this.dataGrid.DataSource; int selectedRow = -1; for (int i=0; i<table.Rows.Count; i++) if (this.dataGrid.IsSelected(i)) selectedRow = i; break; } if ( selectedRow != -1 ) { DataRow row = table.Rows[selectedRow]; // More code ... } Problem: When the user clicks on a column header and sort the table, table.Rows does not return the right rows. It still contains the unsorted rows. How can I get the right column?

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  • create php form, show message depending user choice

    - by user1056615
    I want to create a php form with checkbox, like this: < form method="post> <input type="checkbox" name="formpractise[]" value="A" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="B" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="C" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="D" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="E" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="F" /> <br/> <br/> <input type="submit" name="formsubmit" value="Submit" /> </form> When the user select checkbox I want to print a message according user choice. Not the choice he made, a message depending his choice.

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  • set an input value from jquery function

    - by user1499220
    I'm simply trying to set a value for an input but it doesn't work. Here is my jquery function : function display_form() { try { $('#start_date').val('2012/08/21'); }catch (e){ alert('error'); } window.alert( $('[name=start_date]').val() ); } This shows "undefined". Here is my form : <input id="start_date" name="start_date" type="text" size="6" /> Should I put somewhere the id of the form that I want to use? I just followed what is said in the documentation of jquery but it doesn't seem to work. Could anyone help me ?

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  • submit button on html to output result on same page

    - by amateur
    Hi, Although this seems like something very basic, but no matter what I tried I couldn't get my head around it. Basically I want a html form where a user types in their ID number in an input text box and when they hit the submit button it displays their email address which is their company ID number @ company.com, such as below <form action=""> ID Number: <input type="text" name="idnumber" /><br/> <input type="submit" value="Whats my email address" /> </form> <p>Your email address is 'idnumber'@email.com</p> Can this even be done using html or would I need to use Javascript or PHP for it? Thanks

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  • Setting variable to value of form [drupal 6]

    - by N Schleder
    I have this form $form['title'] = array( '#type' => 'textfield', '#title' => t('Title of Notice'), '#description' => t('Use_underscores_as_spaces'), '#size' => 30, // '#required' => TRUE ); and I want whatever the user types in to be the value of $test I've tried $test = $form['title']; which gives me $test = array also I've tried $test = current($form['title']); which gives me $test = textfield $form['values']['title'] doesn't work dont know what else to try

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  • how to don't store a repeated field of a Symfony form?

    - by user454760
    Hello everybody, I am working with Symfony 1.4 and Doctrine. I have a model A with a email field. The form of A, display an input in which the user should insert the email correctly. But as everybody know sometiemes they don't do it. To fix this i have insert an extra field in the model (and in the form), called *repeat_email* to prevent the misspellings. Then, in the validation process, after validates all the fields, i use a global validator to compare the data of the two fields. This works, but i don't want to have the email stored two times in the database (i don't want the *repeat_email*). Is there any mechanism to use it in the validation process, but not to store it in the database? Thanks,

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  • How to take value from radio selection and pass that value into a hidden inputs value attribute?

    - by Matthew
    Hello guys, I need to know if this can be done and if so can someone push me in the right direction. Okay I have a series of radio buttons: <input type="radio" name="level_id" id="radio1" value="XXXX" class="radio1" /> <label for="radio1">choice 1</label> <input type="radio" name="level_id" id="radio2" value="XXXX" class="radio2" /> <label for="radio2">choice 2</label> <input type="radio" name="level_id" id="radio3" value="XXXX" class="radio3" /> <label for="radio3">choice 3</label> <label for="radio4">second choice1</label> <input type="radio" name="level_id" id="radio4" value="1" class="radio4" /> <label for="radio5">second choice2</label> <input type="radio" name="level_id" id="radio5" value="2" class="radio5" /> <label for="radio6">second choice3</label> <input type="radio" name="level_id" id="radio6" value="3" class="radio6" /> Now what I am looking to do is if someone selects CHOICE 1 and then selects SECOND CHOICE1 I would like to pass the value of SECOND CHOICE1 into the value of a hidden input. <input type="hidden" name="sub_source" id="sub_source" value="" /> So that when the form is ready to submit the value that gets passed would be: <input type="hidden" name="sub_source" id="sub_source" value="1" />

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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • encode data in get request

    - by user902395
    <!DOCTYPE html> <html> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <body onload="searchForPrograms.submit();"> <form id="searchForPrograms" name="searchForPrograms" enctype="application/x-www-form-urlencoded" method="get" action="searchingEngine.php"> <input type="text" id="query" name="query" value="MyProgram" /><br> <input type="submit" value="Search" /> </form> </body> The get request should have the form like "searchingEngine.php?query=%22MyProgram%22". How can I encode the value of the query input correctly?

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  • submitting a form inside a modalbox with jquery

    - by birdy
    submitting form with jQuery works $('#testform').submit(); doesn't work $('#testform').submit(function () { alert('test1'); return true; }); This is just an exmaple but at times i'd like to do stuff before submission of the form. Like for example submit the form using $.POST Update: If I keep both then the $.POST has no value because the form still gets submitted the traditional way, without ajax... $("#testform").submit(function() { $.post('/myajaxcontroller', function(data) { $('#result').html(data); }); }); $("#testform").submit();

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  • Change Image in Resources at Runtime

    - by zaidwaqi
    Hi, My understanding of Resources is that I can combine resources i.e. images and my program into single executable. Let's say I have image pic1.png and I put it into Resource of my project, and is accessible with Properties.Resource.pic1. For example, PictureBox pb = new PictureBox(); pb.Image = Properties.Resource.pic1; What I want to do is for that my program will be able to replace this image at runtime. For example, my program runs, and locate newPicture.png, and use this new image to replace pic1.png that was originally used. Maybe my question is better reworded as "Can I include new image into Resources at runtime?" Please help. Thanks.

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  • form_for called in a loop overloads IDs and associates fields and labels incorrectly

    - by Katy Levinson
    Rails likes giving all of my fields the same IDs when they are generated in a loop, and this causes trouble. <% current_user.subscriptions.each do |s| %> <div class="subscription_listing"> <%= link_to_function s.product.name, "toggle_delay(this)"%> in <%= s.calc_time_to_next_arrival %> days. <div class="modify_subscription"> <%= form_for s, :url => change_subscription_path(s) do |f| %> <%= label_tag(:q, "Days to delay:") %> <%= text_field_tag(:query) %> <%= check_box_tag(:always) %> <%= label_tag(:always, "Apply delay to all future orders") %> <%= submit_tag("Change") %> <% end %> <%= link_to 'Destroy', s, :confirm => 'Are you sure?', :method => :delete %> </div> </div> <% end %> Produces <div class="subscription_listing"> <a href="#" onclick="toggle_delay(this); return false;">Pasta</a> in 57 days. <div class="modify_subscription"> <form accept-charset="UTF-8" action="/subscriptions/7/change" class="edit_subscription" id="edit_subscription_7" method="post"><div style="margin:0;padding:0;display:inline"><input name="utf8" type="hidden" value="&#x2713;" /><input name="_method" type="hidden" value="put" /><input name="authenticity_token" type="hidden" value="s5LJffuzmbEMkSrez8b3KLVmDWN/PGmDryXhp25+qc4=" /></div> <label for="q">Days to delay:</label> <input id="query" name="query" type="text" /> <input id="always" name="always" type="checkbox" value="1" /> <label for="always">Apply delay to all future orders</label> <input name="commit" type="submit" value="Change" /> </form> <a href="/subscriptions/7" data-confirm="Are you sure?" data-method="delete" rel="nofollow">Destroy</a> </div> </div> <div class="subscription_listing"> <a href="#" onclick="toggle_delay(this); return false;">Gummy Bears</a> in 57 days. <div class="modify_subscription"> <form accept-charset="UTF-8" action="/subscriptions/8/change" class="edit_subscription" id="edit_subscription_8" method="post"><div style="margin:0;padding:0;display:inline"><input name="utf8" type="hidden" value="&#x2713;" /><input name="_method" type="hidden" value="put" /><input name="authenticity_token" type="hidden" value="s5LJffuzmbEMkSrez8b3KLVmDWN/PGmDryXhp25+qc4=" /></div> <label for="q">Days to delay:</label> <input id="query" name="query" type="text" /> <input id="always" name="always" type="checkbox" value="1" /> <label for="always">Apply delay to all future orders</label> <input name="commit" type="submit" value="Change" /> </form> <a href="/subscriptions/8" data-confirm="Are you sure?" data-method="delete" rel="nofollow">Destroy</a> </div> </div> And that's a problem because now no matter which "Apply delay to all future orders" I select it always very helpfully checks the first box for me. How can I override the ID without doing something ugly and un-rails-like?

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  • Drop down selection not registered when form submitted quickly?!

    - by Abs
    Hello all, I have noticed a strange thing that happens on my web app when the server is under heavy loads (I am remoting on to the Windows Server). I have a drop down box which is generated dynamically (server side). When I make a selection and quickly press the submit button to indicate my selection the next page does not register my selection but if I do it a bit more slowly it will. I have not come across this before, has anyone? I know its a small issue but there are a lot of "trigger happy", including me... should I put a delay before the form is submitted? If I do, I can only guess the right amount of time. Or is there an underlying problem with my web app? Thanks all

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  • form element not showing up after adding in through jquery

    - by ooo
    inside a jquery method (on a click event of a button) i have the following code: $(selector).html("<form action='/Tracker/CopyFood' method='post'><input type='hidden' name='Id' value=" + id + "><input class='very-small-input' type='text' name='Quantity' value='1' /> for <select name='Date'><option value='Today'>Today</option><option value='Yesterday'>Yesterday</option></select><select name='Meal'><option value='Breakfast'>Breakfast</option><option value='Lunch'>Lunch</option><option value='Dinner'>Dinner</option><option value='Evening Snack'>Evening Snack</option></select><input type='button' class='submitCopyFood' value='Add'> or <div style='display:inline' class='CancelCopy'>Cancel</div></form> "); it seems to work on the screen, but the button click "submitCopyFood" wasn't firing. When i click "View Selection Source" in firefox, i see the issue. All i see is this: <input name="Id" value="128" type="hidden"><input class="very-small-input" name="Quantity" value="1" type="text"> for <select name="Date"><option value="Today">Today</option><option value="Yesterday">Yesterday</option></select><select name="Meal"><option value="Breakfast">Breakfast</option><option value="Lunch">Lunch</option><option value="Dinner">Dinner</option><option value="Evening Snack">Evening Snack</option></select><input class="submitCopyFood" value="Add" type="button"> or <div style="display: inline;" class="CancelCopy">Cancel</div> Its like i never added the form anywhere. Is there any reason why i dont see the: <form action='/Tracker/CopyFood' method='post'> or the </form> in the source code inside the selected source. Is there something special that i need to do here?

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  • Jquery Mobile is adding text above my "<input type=submit"> automatically, how do i prevent this?

    - by Jack Dalton
    I've just begin work on a mobile version for one of my sites. I've set up my sign up form for my users. It worked fine and the CSS styled it correctly. @using (Html.BeginForm("XXX", "Registration", FormMethod.Post, new { @class = "twitter-sign-in-container" })) { <input type="submit" name="twitter-button" value="Sign in with Twitter" id="twitter-button" /> } Once I added Jquery mobile to the project if found that random unstyled text started to show up. On inspection I found that all input submits where being wrapped in new tags and adding un tagged text == to the inputs "Value": <form action="/registration/xxx" class="twitter-sign-in-container" method="post"> <div class="ui-btn ui-input-btn ui-corner-all ui-shadow"> "Sign in with Twitter" <input type="submit" name="twitter-button" value="Sign in with Twitter" id="twitter-button"> </div> </form> Does anyone have any clue as to why the "sign up with twitter" text is being added, and how i stop it? P.S Less important but I'd also like to know why Jquery wraps form contents in the bellow div.

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  • Send form with jQuery using keypress()

    - by kexxcream
    What I have so far: I have a form in PHP that contain the following: <input type="submit" id="0" name="0" value="This button"> <input type="submit" id="1" name="1" value="This button"> <input type="hidden" id="response" name="response" value="150"> The problem: I would like to send the response value together with either name=1 or name=0, depending on which button the user submit. However, this should be done using the keyboard letters A and S. If a user press the letter A then the value 0 should be submitted, and if S is pressed then the value 1 should be sent. The jQuery code: $(document).ready(function() { // listens for any navigation keypress activity $(document).keypress(function(e) { switch(e.which) { // user presses the "a" case 97: submitViaKeypress("0"); break; // user presses the "s" key case 115: submitViaKeypress("1"); break; } }); }); // shows a given element and hides all others function submitViaKeypress(element_id) { var response = $('#response').attr('value'); $.ajax({ type: "POST", url: "initiate.php", data: "response=" + response + "&" + element_id + "=" + element_id }); } Goal: That "initiate.php receive two POST variables (response and either 0 or 1).

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  • How can I make my password fields always empty?

    - by ggfan
    I have a form field where users can change their passwords, but if they set their settings to remember passwords, their password shows up. Is there a way to make the field always empty? So that they always have to type their password. <label for="oldpassword" class="styled">Old password:</label> <input type="password" id="oldpassword" name="oldpassword"/><br />

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