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• Openldap/Sasl/GSSAPI on Debian: Key table entry not found

  - by badbishop

  The goal: to make an OpenLDAP server to authenticate using Kerberos V via GSSAPI Setup: several virtual machines running on freshly installed/updated Debian Squeeze A master KDC server kdc.example.com A LDAP server, running OpenLDAP ldap.example.com The problem: tom@ldap:~$ ldapsearch -b 'dc=example,dc=com' SASL/GSSAPI authentication started ldap_sasl_interactive_bind_s: Other (e.g., implementation specific) error (80) additional info: SASL(-1): generic failure: GSSAPI Error: Unspecified GSS failure. Minor code may provide more information (Key table entry not found) One might suggest to add that bloody keytab entry, but here's the real problem: ktutil: rkt /etc/ldap/ldap.keytab ktutil: list slot KVNO Principal ---- ---- --------------------------------------------------------------------- 1 2 ldap/[email protected] 2 2 ldap/[email protected] 3 2 ldap/[email protected] 4 2 ldap/[email protected] So, the entry as suggested by the OpenLDAP manual is there allright. Deleting and re-creating both service principal and the keytab on ldap.example.com didn't help, I get the same error. And before I make the keytab file readable by openldap, I get "Permission denied" error instead of the one in the subject. Which implies, that the right keytab file is being accessed, as set in /etc/default/slapd. I have my doubts about the following part of slapd config: root@ldap:~# cat /etc/ldap/slapd.d/cn\=config.ldif | grep -v "^#" dn: cn=config objectClass: olcGlobal cn: config olcArgsFile: /var/run/slapd/slapd.args olcLogLevel: 256 olcPidFile: /var/run/slapd/slapd.pid olcToolThreads: 1 structuralObjectClass: olcGlobal entryUUID: d6737f5c-d321-1030-9dbe-27d2a7751e11 olcSaslHost: kdc.example.com olcSaslRealm: EXAMPLE.COM olcSaslSecProps: noplain,noactive,noanonymous,minssf=56 olcAuthzRegexp: {0}"uid=([^/]*),cn=EXAMPLE.COM,cn=GSSAPI,cn=auth" "uid=$1,ou=People,dc=example,dc=com" olcAuthzRegexp: {1}"uid=host/([^/]*).example.com,cn=example.com,cn=gssapi,cn=auth" "cn=$1,ou=hosts,dc=example,dc=com" A HOWTO at https://help.ubuntu.com/community/OpenLDAPServer#Kerberos_Authentication mentiones vaguely: Also, it is frequently necessary to map the Distinguished Name (DN) of an authorized Kerberos client to an existing entry in the DIT. I fail to understand where in the tree this should be defined, what schema should be used, etc. After hours of googling, it's official: I'm stuck! Please, help. Other things checked: Kerberos as such works fine (I can ssh without using a password to any machine in this setup). That means there should be no DNS-related problems. ldapsearch -b 'dc=example,dc=com' -x works OK. SASL/GSSAPI has been tested using sasl-sample-server -m GSSAPI -s ldap and sasl-sample-client -s ldap -n ldap.example.com -u tom without errors: root@ldap:~# sasl-sample-server -m GSSAPI -s ldap Forcing use of mechanism GSSAPI Sending list of 1 mechanism(s) S: R1NTQVBJ Waiting for client mechanism... C: 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 'GSSAPI' Sending response... S: YIGZBgkqhkiG9xIBAgICAG+BiTCBhqADAgEFoQMCAQ+iejB4oAMCARKicQRvkxggi9pW+yJ1ExbTwLDclqw/VQ98aPq8mt39hkO6PPfcO2cB+t6vJ01xRKBrT9D2qF2XK0SWD4PQNb5UFbH4RM/bKAxDuCfZ1MHKgIWTLu4bK7VGZTbYydcckU2d910jIdvkkHhaRqUEM4cqp/cR Waiting for client reply... C: got '' Sending response... S: BQQF/wAMAAAAAAAAMBOWqQcACAAlCodrXW66ZObsEd4= Waiting for client reply... C: BQQE/wAMAAAAAAAAFUYbXQQACAB0b20VynB4uGH/iIzoRhw=got '?' Negotiation complete Username: tom Realm: (NULL) SSF: 56 sending encrypted message 'srv message 1' S: AAAASgUEB/8AAAAAAAAAADATlqrqrBW0NRfPMXMdMz+zqY32YakrHqFps3o/vO6yDeyPSaSqprrhI+t7owk7iOsbrZ/idJRxCBm8Wazx Waiting for encrypted message... C: AAAATQUEBv8AAAAAAAAAABVGG17WC1+/kIV9xTMUdq6Y4qYmmTahHVCjidgGchTOOOrBLEwA9IqiTCdRFPVbK1EgJ34P/vxMQpV1v4WZpcztgot '' recieved decoded message 'client message 1' root@ldap:~# sasl-sample-client -s ldap -n ldap.example.com -u tom service=ldap Waiting for mechanism list from server... S: R1NTQVBJrecieved 6 byte message Choosing best mechanism from: GSSAPI returning OK: tom Using mechanism GSSAPI Preparing initial. Sending initial response... C: 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 Waiting for server reply... S: YIGZBgkqhkiG9xIBAgICAG+BiTCBhqADAgEFoQMCAQ+iejB4oAMCARKicQRvkxggi9pW+yJ1ExbTwLDclqw/VQ98aPq8mt39hkO6PPfcO2cB+t6vJ01xRKBrT9D2qF2XK0SWD4PQNb5UFbH4RM/bKAxDuCfZ1MHKgIWTLu4bK7VGZTbYydcckU2d910jIdvkkHhaRqUEM4cqp/cRrecieved 156 byte message C: Waiting for server reply... S: BQQF/wAMAAAAAAAAMBOWqQcACAAlCodrXW66ZObsEd4=recieved 32 byte message Sending response... C: BQQE/wAMAAAAAAAAFUYbXQQACAB0b20VynB4uGH/iIzoRhw= Negotiation complete Username: tom SSF: 56 Waiting for encoded message... S: AAAASgUEB/8AAAAAAAAAADATlqrqrBW0NRfPMXMdMz+zqY32YakrHqFps3o/vO6yDeyPSaSqprrhI+t7owk7iOsbrZ/idJRxCBm8Wazxrecieved 78 byte message recieved decoded message 'srv message 1' sending encrypted message 'client message 1' C: AAAATQUEBv8AAAAAAAAAABVGG17WC1+/kIV9xTMUdq6Y4qYmmTahHVCjidgGchTOOOrBLEwA9IqiTCdRFPVbK1EgJ34P/vxMQpV1v4WZpczt

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• What can tables do that CSS positioning cannot?

  - by Jeremy Lew

  I know there are various good arguments preferring css positioning over table-based layouts. What I'm wondering is whether the CSS model is complete (assuming a relatively modern browser) with respect to ALL of the capabilities of tables. Are there layouts that tables can achieve that are impossible or impractical with CSS?

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• How to add a default value to an already existing column?

  - by Earlz

  I have an existing column in my SQL Server database. I have tried about everything I can think of but can not get a default value to be added to the column. What works in every other database is alter table mytable alter column mycolumn set default(now()) --mycolumn is a datetime How do I do this in SQL Server? The error I get for that exact syntax is incorrect syntax near the keyword 'set'

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• How do I merge cells of the same column in LyX?

  - by brickner

  I have 3 subfigures I want to arrange so that 1 will be in the left and 2 will be in the right (one above the other): Figure 1 | Figure 2 Figure 1 | Figure 3 Figure 1 should appear only once of course - across the entire column. I thought I should use 2x2 table to arrange them, but I can't find a way to merge the two cells in the same column to one cell in order to put figure 1 there. How can I merge the two cells in the same column?

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• How to add 1 to the value of a column of an existing row in mysql

  - by mithun1538

  Hello everyone, I have a table called pollData. It will always contain only 1 row. It has columns option1, option2, option3, option4, option5 each of type int. In the beginning, these columns have 0 as their value. How do I add 1 to any column, say option2? I mean do i retrieve the value of that column first, perform addition, and store back, or is there any auto increment function?

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• Select result in single cell

  - by Ruslan

  How can i select all id's for records in single cell? For example: --example select of all values select id, name, address, phone from table And get all id's where phone like '%555%' and show them in single field like: '111 123 234 321 231 234'

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• How to return children objects?

  - by keruilin

  I have -- what I think -- is a simple question. Here's my code: class Fruit < ActiveRecord::Base end class Apple < Fruit end class Kiwi < Fruit end Assume that I have all the STI setup correctly, and there are multiple types of Apple and Kiwi records in the table. From here... fruits = Fruit.find(:all) ...how do I return an array of just Apples from the fruits array?

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• zend framework 2 autentification using DbTable failure

  - by josepmra

  I have followed the zend instructions for implement my web Authentication using a database table. It's exactly the same code, but when render the page, the following exceptions appears: Zend\Authentication\Adapter\Exception\RuntimeException File: C:\xampp\htdocs\pfc\vendor\ZF2\library\Zend\Authentication\Adapter\DbTable.php Mensaje: The supplied parameters to DbTable failed to produce a valid sql statement, please check table and column names for validity. produced by this other: Zend\Db\Adapter\Exception\InvalidQueryException File: C:\xampp\htdocs\pfc\vendor\ZF2\library\Zend\Db\Adapter\Driver\Mysqli\Statement.php Mensaje: Statement couldn't be produced with sql: SELECT `users`.*, (CASE WHEN `password` = ? THEN 1 ELSE 0 END) AS `zend_auth_credential_match` FROM `users` WHERE `mail` = ? Seems to be that Statement.php can not execute the sql of above, but I send the sql by phpmyadmin replacing the ? for strings and work ok. I am sure that $dbAdapter works ok also because I have tested it and the columns name are "mail" and "password". This in my code, also I put the $dbAdapter test code. $dbAdapter = new DbAdapter(array( //This DbAdapter Work ok sure!! 'driver' => 'Mysqli', 'database' => 'securedraw', 'username' => 'root', 'password' => '' )); $fp = function($name) use ($dbAdapter) { return $dbAdapter->driver->formatParameterName($name);}; $sql = 'SELECT * FROM ' . $qi('users') . ' WHERE id = ' . $fp('id'); $statement = $dbAdapter->query($sql); $parameters = array('id' => 1); $sqlResult = $statement->execute($parameters); $row = $sqlResult->current(); $mail = $row['mail']; $password = $row['password']; //until here test $dbAdapter exitly!! //Start the auth proccess!! $authAdapter = new AuthDbTableAdapter($dbAdapter); $authAdapter->setTableName('users') ->setIdentityColumn('mail') ->setCredentialColumn('password'); $authAdapter->setIdentity('josep') ->setCredential('josep'); $authResult = $authAdapter->authenticate(); //This is the fail method!!!

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• How do you find the row count for all your tables in Postgres

  - by mmrobins

  I'm looking for a way to find the row count for all my tables in Postgres. I know I can do this one table at a time with a select count(*) from table_name; but I'd like to see the row count for all the tables and the order by that to get an idea of how big all my tables are.

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• convert rst to latex, problem with tables

  - by ace

  hi all, I have some .rst files and I convert them to .tex file using standard sphinx converter. but in some .rst I have tables with special width like: .. list-table:: :widths: 50 50 but resulting .tex always contains tables like: \begin{tabulary}{\textwidth}{|L|L|} so, column width is lost. how can I preserve column width when converting rst to latex?

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• MYSQL - Rows to Columns

  - by Bob Rivers

  Hi, I tried to search posts, but I only found solutions for SQL Server/Access. I need a solution to MYSQL (5.X). I have a table with 3 columns: hostid, itemname, itemvalue. If I do a select, it will return 1 A 10 1 B 3 2 A 9 2 C 40 How do I query the database to return something like A B C 1 10 3 2 9 40

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• SQL Server 2005 - query with case statement

  - by user329266

  Trying to put a single query together to be used eventually in a SQL Server 2005 report. I need to: Pull in all distinct records for values in the "eventid" column for a time frame - this seems to work. For each eventid referenced above, I need to search for all instances of the same eventid to see if there is another record with TaskName like 'review1%'. Again, this seems to work. This is where things get complicated: For each record where TaskName is like review1, I need to see if another record exists with the same eventid and where TaskName='End'. Utimately, I need a count of how many records have TaskName like 'review1%', and then how many have TaskName like 'review1%' AND TaskName='End'. I would think this could be accomplished by setting a new value for each record, and for the eventid, if a record exists with TaskName='End', set to 1, and if not, set to 0. The query below seems to accomplish item #1 above: SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000'))) AS T WHERE seq = 1 order by eventid And the query below seems to accomplish #2: SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000')) and TaskName like 'Review1%') AS T WHERE seq = 1 order by eventid This will bring back the eventid's that also have a TaskName='End': SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000')) and TaskName like 'Review1%') AS T WHERE seq = 1 and eventid in (Select eventid from eventrecords where TaskName = 'End') order by eventid So I've tried the following to TRY to accomplish #3: SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000')) and TaskName like 'Review1%') AS T WHERE seq = 1 and case when (eventid in (Select eventid from eventrecords where TaskName = 'End') then 1 else 0) as bit end order by eventid When I try to run this, I get: "Incorrect syntax near the keyword 'then'." Not sure what I'm doing wrong. Haven't seen any examples anywhere quite like this. I should mention that eventrecords has a primary key, but it doesn't seem to help anything when I include it, and I am not permitted to change the table. (ugh) I've received one suggestion to use a cursor and temporary table, but am not sure how badley that would bog down performance when the report is running. Thanks in advance.

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• CSS Cell Margin

  - by Tom

  In my HTML document, I have a table with two columns and multiple rows. How can I increase the space in between the first and second column with css? I've tried applying "margin-right: 10px;" to each of the cells on the left hand side, but to no effect.

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• How to make separator (Single Line) transparent in Tableview?

  - by Mishal

  I have used table view in my application, and within that I have used the single line separator given by tableview. How can I make a transparent separator in a tableview? If anybody has any ideas/code snippets/useful links, I would greatly appreciate it.

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• hiding <div> from vb.net code side

  - by reffe

  i have this code for hiding a table and a cell in aspx, backend vb.net Code - For Each row As HtmlTableRow In tab_a1.Rows If row.ID = "a1" Then For Each cell As HtmlTableCell In row.Cells cell.Visible = (cell.ID = "a1") Next ElseIf row.ID = "b1" Then For Each cell As HtmlTableCell In row.Cells cell.Visible = (cell.ID = "b1") Next Else row.Visible = False End If Next now instead of tables I'm using tags. How can i use similar code and make div's visible and invisible?

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• HTML Tables - How to make IE not break lines at hyphens

  - by Greg

  I have some table cells containing dates formatted like this: 2009-01-01. I.E 7 seems to be breaking these into two lines at the hyphen. Is there any way to turn this off?

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• Add not null DateTime column to SQLite without default value?

  - by acidzombie24

  It looks like i cant add a not null constraint or remove a default constraint. I would like to add a datetime column to a table and have all the values set to anything (perhaps 1970 or year 2000) but it seems like i cant use not null without a default and i cant remove a default once added in. So how can i add this column? (once again just a plain datetime not null)

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• cross referenced tables from multi-dimensional arrays php?

  - by significance

  how do it turn a multidimensional array like: $fruits['apples']['blue'] = 24; $fruits['bananas']['blue'] = 12; $fruits['apple']['red'] = 34; $fruits['gooseberries']['orange'] = 4; $fruits['oranges']['red'] = 12; into a cross referenced table like: Thanks!

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• Can I create my own database from PHP?

  - by Roman

  I have a working PHP server. Now I want to use databases (MySQL or something similar). Is it possible to create a database from PHP? I would like to emphasize that in my case I do not have any user-name and password to which I can use to connect to MySQL server. I also do not have a control-panel where I could create a database or a table in an existing database.

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• Programmatically remove the header of UITableView and automatically resizes the content to fill in the removed area.

  - by code007

  Hello all, I have added a UIButton in the header section of the UITableView via the interface builder and would like to remove the access to the button in certain cases. I have tried to use the '.hidden = TRUE' property but it just hides the button from the view, leaving a white space behind. How do I programmatically remove the header of UITableView and have the table's content automatically resizes to fill in the removed header area?

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• Mysql change column details

  - by Ankur

  I am trying to redefine the number of varchars a column can have (in a MySQL db). I am doing alter table obj_details IMG_SRC IMG_SRC varchar(180); I want to change the number of characters that can be used in the column IMG_SRC to 180 (it is currently 100). But I get an error saying that I should check the syntax near IMG_SRC IMG_SRC varchar(180).

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• [CakePHP] Showing first element of the array

  - by user198003

  How can I find and show Name of first element in a table? I'm guessing that I have to use something like $this->data['lastInvioce'] = $this->Invoice->find('all', array('limit' => 1)); ... in controller to find it... Tnx in adv!!!

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• Select count() max() Date HELP!!! mysql oracle

  - by DAVID

  Hi guys i have a table with shifts history along with emp ids im using this code to retrieve a list of employees and their total shifts by specifying the range to count from: SELECT ope_id, count(ope_id) FROM operator_shift WHERE ope_shift_date >=to_date( '01-MAR-10','dd-mon-yy') and ope_shift_date <= to_date('31-MAR-10','dd-mon-yy') GROUP BY OPE_ID which gives OPE_ID COUNT(OPE_ID) 1 14 2 7 3 6 4 6 5 2 6 5 7 2 8 1 9 2 10 4 10 rows selected. NOW how do i choose the employee with the highest no of shifts under the specified range date, please this is really important

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• make img height 100% of td

  - by kristina childs

  I'm creating an HTML email and since background images can't be used on anything but <body> thought I could get around this by making a border image 100% height within a cell. Perhaps it was wishful thinking? I've searched at the solutions that worked in the past no longer work in modern browsers. Is there any special trick to making this happen without setting a hard height for the cell? Here are the things I've tried so far: <td width="25" style="margin:0; padding:0;"> <img src="http://www.mysite.com/images/side-left.jpg" width="25" height="100%" alt="border" style="margin:0; padding:0; display: block;" /> </td> stretches the image to 100% height of the entire table (even though the table is nested in a <td width="25" height="100%" style="margin:0; padding:0;"> <div style="height:100%; diplay: block;"> <img src="http://www.mysite.com/images/side-left.jpg" width="25" height="100%" alt="border" style="margin:0; padding:0; display: block;" /> </div> </td> ditto <td width="25" height="1" style="margin:0; padding:0;"> <div style="height:100%; diplay: block;"> <img src="http://www.mysite.com/images/side-left.jpg" width="25" height="100%" alt="border" style="margin:0; padding:0; display: block;" /> </div> </td> setting a smaller td size does not force it to strectch as expected. bummer.

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• Looking for a phpmyadmin tool who shows the tables in "design mode" with relations...

  - by Tristan

  Hello, all is in the title one day i saw on phpmyadmin a tool capable of drawing a shcema of the table in the database linked with primary keys / foreign keys together. Where can i find this tools please ? (what's his name ?) thanks

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