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  • why resubmit after refresh php page

    - by user2719452
    why resubmit after refresh php page? try it, go to: http://qass.im/message-envelope/ and upload any image now try click F5, after refresh page "resubmit" Why? I don't want resubmit after refresh page What is the solution? See this is my form code: <form id="uploadedfile" name="uploadedfile" enctype="multipart/form-data" action="upload.php" method="POST"> <input name="uploadedfile" type="file" /> <input type="submit" value="upload" /> </form> See this is php code upload.php file: <?php $allowedExts = array("gif", "jpeg", "jpg", "png", "zip", "pdf", "docx", "rar", "txt", "doc"); $temp = explode(".", $_FILES["uploadedfile"]["name"]); $extension = end($temp); $newname = $extension.'_'.substr(str_shuffle(str_repeat("0123456789abcdefghijklmnopqrstuvwxyz", 7)), 4, 7); $imglink = 'attachment/attachment_file_'; $uploaded = $imglink .$newname.'.'.$extension; if ((($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpg") || ($_FILES["uploadedfile"]["type"] == "image/pjpeg") || ($_FILES["uploadedfile"]["type"] == "image/x-png") || ($_FILES["uploadedfile"]["type"] == "image/gif") || ($_FILES["uploadedfile"]["type"] == "image/png") || ($_FILES["uploadedfile"]["type"] == "application/msword") || ($_FILES["uploadedfile"]["type"] == "text/plain") || ($_FILES["uploadedfile"]["type"] == "application/vnd.openxmlformats-officedocument.wordprocessingml.document") || ($_FILES["uploadedfile"]["type"] == "application/pdf") || ($_FILES["uploadedfile"]["type"] == "application/x-rar-compressed") || ($_FILES["uploadedfile"]["type"] == "application/x-zip-compressed") || ($_FILES["uploadedfile"]["type"] == "application/zip") || ($_FILES["uploadedfile"]["type"] == "multipart/x-zip") || ($_FILES["uploadedfile"]["type"] == "application/x-compressed") || ($_FILES["uploadedfile"]["type"] == "application/octet-stream")) && ($_FILES["uploadedfile"]["size"] < 5242880) // Max size is 5MB && in_array($extension, $allowedExts)) { move_uploaded_file($_FILES["uploadedfile"]["tmp_name"], $uploaded ); echo '<a target="_blank" href="'.$uploaded.'">click</a>'; // If has been uploaded file echo '<h3>'.$uploaded.'</h3>'; } if($_FILES["uploadedfile"]["error"] > 0){ echo '<h3>Please choose file to upload it!</h3>'; // If you don't choose file } elseif(!in_array($extension, $allowedExts)){ echo '<h3>This extension is not allowed!</h3>'; // If you choose file not allowed } elseif($_FILES["uploadedfile"]["size"] > 5242880){ echo "Big size!"; // If you choose big file } ?> if you have solution, please edit my php code and paste your solution code! Thanks.

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  • how to use alert in php and js combined

    - by user295189
    have a need to alert through php, I have the code below. Problem is that it works as long as I dont use header redirect. But as soon as I use it..I loose alert. echo "I will do some functions here in php"; if($value == 1){ alert('ok working'); } header(location: 'someOtherpagethanthis.php');

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  • JQuery post to php

    - by RussP
    Why is it that I can never get JQuery serialize to work properly. I guess I must be missing something. I can serialize a form data and it shows in an alert: var forminfo = $j('#frmuserinfo').serialize(); alert(forminfo); I then post to my PHP page thus: $j.ajax({ type: "POST", url: "cv-user-process.php", data: "forminfo="+forminfo, cache: false, complete: function(data) { } }); But WHENEVER (not the first time) I try to insert/update the data in the DB I only ever get 1 varaible passed: Here is my PHP script: $testit = mysql_query("UPDATE cv_usersmeta SET inputtest='".$_POST['forminfo']."' WHERE user='X'"); the data passed only ever gets the first variable. why? I think it is more the way I deal with the php but it drives me nuts and always takes me far too long to find where I am going wrong.

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  • php to translate GET request to POST request

    - by DennyHalim
    i have a hosted script somewhere that only accept POST request. example, some.hosted/script.php how can i setup another simple php that can accept GET request and then POST it to the hosted script. so that i can put up a link like this: other.site/post2hostedscript.php?postthis=data and then it POST postthis=data to the hosted script. tnx

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  • Gmail,Yahoo, Facebook, Twitter contacts importer in PHP

    - by Arjun
    Which is the greatest, cheapest application in PHP that I can buy to import Gmail, Yahoo, MSN, Facebook, Twitter contacts from my user's accounts if they wish to invite their friends? I have gone through: http://www.improsys.com/importer.htm http://www.octazen.com/demo.php and http://www.iplussoft.com/product/iplusinvite_pricing Octazen looks awesome but wants excess of $320 for an all in solution. I don't want to spend that much. All you PHP programmers out there you may have needed to build of integrate a similar app, I need to know which is the best PHP readymade app for this? Any help would be appreciated and I'll smile with each answer - this should be your biggest incentive to find me something amazing :)

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  • Ajax progress with PHP session

    - by FFish
    I have an app that processes images and use jQuery to display progress to the user. I done this with writing to a textfile each time and image is processed and than read this status with a setInterval. Because no images are actually written in the processing (I do it in PHP's memory) I thought a log.txt would be a solution, but I am not sure about all the fopen and fread's. Is this prone to issues? I tried also with PHP sessions, but can't seem to get it to work, I don't get why.. HTML: <a class="download" href="#">request download</a> <p class="message"></p> JS: $('a.download').click(function() { var queryData = {images : ["001.jpg", "002.jpg", "003.jpg"]}; $("p.message").html("initializing..."); var progressCheck = function() { $.get("dynamic-session-progress.php", function(data) { $("p.message").html(data); } ); }; $.post('dynamic-session-process.php', queryData, function(intvalId) { return function(data) { $("p.message").html(data); clearInterval(intvalId); } } (setInterval(progressCheck, 1000)) ); return false; }); process.php: // session_start(); $arr = $_POST['images']; $arr_cnt = count($arr); $filename = "log.txt"; for ($i = 1; $i <= $arr_cnt; $i++) { $content = "processing $val ($i/$arr_cnt)"; $handle = fopen($filename, 'w'); fwrite($handle, $content); fclose($handle); // $_SESSION['counter'] = $content; sleep(3); // to mimic image processing } echo "<a href='#'>download zip</a>"; progress.php: // session_start(); $filename = "log.txt"; $handle = fopen($filename, "r"); $contents = fread($handle, filesize($filename)); fclose($handle); echo $contents; // echo $_SESSION['counter'];

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  • PHP Download File with Include

    - by arik-so
    How can I use PHP's include function to include a file and then modify the headers so it forces - at least that's how it's called - browsers to download ITSELF (the PHP file). Is it possible to also modify the preset save name, in order to change the extension from *.php to something else? Thanks in advance!

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  • PHP CURL sending POST to Django app issue

    - by Felipe Pelá
    This code in PHP sends a HTTP POST to a Django app using CURL lib. I need that this code sends POST but redirect to the page in the same submit. Like a simple form does. The PHP Code: $c = curl_init(); curl_setopt($c, CURLOPT_FOLLOWLOCATION, true); curl_setopt($c, CURLOPT_URL, "http://www.xxx.com"); curl_setopt($c, CURLOPT_POST, true); curl_setopt($c, CURLOPT_POSTFIELDS, 'Var='.$var); curl_exec($c); curl_close ($c); In this case, the PHP is sending the HTTP POST, but is not redirecting to the page. He is printing the result. My URL still .php and not a django/url/ I need be redirected to the django URL with the Post like a simple form in HTML does. Any Idea? Thanks.

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  • Write to the second line of a PHP file

    - by Woz
    I have a php file that I want to add an include path to on the second line. I need to open the file and inset a line of code on line 2. I have tried a few techniques none of which are working but I think it has something to do with the text I am trying to write and possibly not escaping character correctly as I am not too familiar with file writing. So here is the file I want to write to: $file = $_SERVER['DOCUMENT_ROOT'].'/'.$domaindir.'/test.php'; Here is the piece of text I want to insert into the file: $dbfile = "include('".$_SERVER['DOCUMENT_ROOT']."/".$domaindir."/web_".$dbname.".inc.php');"; Then what I was doing was a string replace but all it did was bump the "session_start();" bit to a newline! Can anyone point me in the direction of a tutorial that might tell me how to insert this into the second line of my php file or indeed if anyone has any ideas? I can say for sure that the path to the PHP file is fully tested so i know its not that the file is not being open or written to. Any ideas would be much appreciated. Thanks in advance.

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  • htaccess to not show index.php in sub directory

    - by Jamesaa
    I have a simple page structure like below /directory/subdir_1/index.php /directory/subdir_2/index.php .... (there are no other files in these directories) is it possible to have 'fake/pretty' urls for the above files as below? /directory/subdir_1 /directory/subdir_2 ... so this path would show whether the visitor typed that,/directory/subdir_2/ or /directory/subdir_2/index.php. Many thanks

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  • Undefined index: email in C:\wamp\www\emailvalidate.php on line 4

    - by klari
    I am new to Ajax. In my Ajax I get the following error message : Notice: Undefined index: address in C:\wamp\www\test\sample.php on line 11 I googled but I didn't get a solution for my specified issue. Here is what I did. HTML Form with Ajax (test1.php) <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <script> function loadXMLDoc() { var xmlhttp; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("mydiv").innerHTML=xmlhttp.responseText; } } xmlhttp.open("POST","test2.php",true); xmlhttp.send(); } </script> </head> <body> <form id="form1" name="form1" method="post" action="sample.php"> <p> <label for="mail"></label> <input type="text" name="mail" id="mail" onblur="loadXMLDoc()" /> <input type="submit" name="submit" id="submit" value="Submit" /> </p> <p><div id = 'mydiv'></div></p> </form> </body> </html> test2.php <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <?php echo "Your Address is ".$_POST['address']; ?> </body> </html> I am sure it is very simple issue but I don't know how to solve it. Any help ?

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  • Creating a session user login php

    - by user2419393
    I'm stuck on how to create a session for a user who logs in. I got the part of checking to make sure the log in information corresponds with the database information, but is stuck on how to take the email address and store into a session. Here is my php code below. <?php include '../View/header.php'; session_start(); require('../model/database.php'); $email = $_POST['username']; $password = $_POST['password']; $sql = "SELECT emailAddress FROM customers WHERE emailAddress ='$email' AND password = '$password'"; $result = mysql_query($sql, $db); if (!$result) { echo "DB Error, could not query the database\n"; echo 'MySQL Error: ' . mysql_error(); exit; } while ($row = mysql_fetch_assoc($result)) { echo $row['emailAddress']; } mysql_free_result($result); ?>

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  • Passing $_GET or $_POST data to PHP script that is run with wget

    - by Matt
    Hello, I have the following line of PHP code which works great: exec( 'wget http://www.mydomain.com/u1.php /dev/null &' ); u1.php acts to do various types of maintenance on my server and the above command makes it happen in the background. No problems there. But I need to pass variable data to u1.php before it's executed. I'd like to pass POST data preferably, but could accommodate GET or SESSION data if POST isn't an option. Basically the type of data being passed is user-specific and will vary depending on who is logged in to the site and triggering the above code. I've tried adding the GET data to the end of the URL and that didn't work. So how else might I be able to send the data to u1.php? POST data preferred, SESSION data would work as well (but I tried this and it didn't pick up the logged in user's session data). GET would be a last resort. Thanks!

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  • where is wrong in my php code ????

    - by user318068
    hi all, <td align="center" bgcolor="#FFFFFF"><?php echo '<label onclick="window.open('profilephp.php?member=$row['MemberID']','mywindow')">'.{$row['MemberName']}.'</label>';?><br /> <?php echo "<p align='center'><img width='100' height='100' src={$row['MemberImg']} alt='' /></p>";?></td></tr> Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in C:\xampp\htdocs\home - Copy\membercopy.php on line 141 I really don't know where it went wrong. Please help,

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  • showing error on uploading a big file using php

    - by user1489969
    I have created a php code to display the upload option to upload multiple files as below: <?php $f_id= $_GET["id"]; ?> <title>Upload File</title> <form enctype="multipart/form-data" method="post" action="upload_hal_mult.php?id=<?php echo $f_id;?>" > <input type="hidden" name="MAX_FILE_SIZE" value="10000000"> <input id="infile" type="file" name="infile[]" multiple="true" /> <input type="submit" value="upload" name="file_uploaded" / > <br> <br> </form> So this will call "upload_hal_mult.php" when "upload" button is clicked. And the code for that is as follows: <title>Upload Results</title> <?php define("MAX_SIZE",10000000); $f_id= $_GET["id"]; $dir_name="dir_hal_".$f_id; $u=0; if (!is_dir($dir_name)) mkdir($dir_name); $dir=$dir_name."/"; $file_realname = $_FILES['infile']['name']; for ($i = 0; $i < count($_FILES['infile']['name']); $i++) { $ext = substr(strrchr($_FILES['infile']['name'][$i], "."), 1); $fname = substr($_FILES['infile']['name'][$i],0,strpos($_FILES['infile']['name'][$i], ".")); $fPath = $fname."_(".substr(md5(rand() * time()),0,4).")".".$ext"; echo "files size=".$_FILES["infile"]["size"][$i]."\n"; if($_FILES["infile"]["size"][$i]>MAX_SIZE) echo('File uploaded exceeds maximum upload size.'); if(($_FILES['infile']['error'][i]==0) && move_uploaded_file($_FILES['infile']['tmp_name'][$i], $dir . $fPath)) { $u=$u+1; ?> <!--<script type="text/javascript">setTimeout("window.close();", 1300);</script>--> <?php echo "Upload is successful\n"; } else echo "if stmt failed so error \n"; } if($u!=count($_FILES['infile']['name'])) echo "Error"; else echo "count is correct"; ?> This upload works correctly for files of size<10MB. But for files of size10MB, it's not echoing 'File uploaded exceeds maximum upload size.' as expected. Its also not uploading the file of size10MB. But the $u gets incremented. But none of the statements like "Upload is successful" or "if stmt failed so error" are being echoed as well. However the statement "count is correct" is being displayed, and this shows the $u got incremented somehow even though the echo statements didnt work! Can someone please point out the error I am doing here? I thought its simply a matter of 'if/else' statements but it seems more than that to me. Please help me out if you have any clue. Thanks

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  • HttpWebRequest POST and retrieve data from php script after login

    - by KenaGT
    Hello guys i am newbie to this stuff so i'll try to explain my problem.I am building application that retrieve data after login to php script that looks like this: https://zamger.etf.unsa.ba/getrssid.php (see the page source for php scirpt definition) and definition(source) here: Korisnicko ime (UID): Šifra: After i login it shows me data that i must collect like this: RSSID: 1321B312 (this is only data that it shows and nothing else) I must do this with httpwebrequest but don't know how i tried to do it with POST(data) but it always give me the defnition of php script as response.But i need response to be like "RSSID: 1321B312" not as script definition mentioned above...please heeelp ASAP....

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  • undefined offset error in php

    - by user225269
    I don't know why but the code below is working when I have a different query: $result = mysql_query("SELECT * FROM student WHERE IDNO='".$_GET['id']."'") ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <?php list($year,$month,$day)=explode("-", $row['BIRTHDAY']); ?> <tr> <td width="30" height="35"><font size="2">Month:</td> <td width="30"><input name="mm" type="text" id="mm" onkeypress="return handleEnter(this, event)" value="<?php echo $month;?>"> <td width="30" height="35"><font size="2">Day:</td> <td width="30"><input name="dd" type="text" id="dd" maxlength="25" onkeypress="return handleEnter(this, event)" value="<?php echo $day;?>"> <td width="30" height="35"><font size="2">Year:</td> <td width="30"><input name="yyyy" type="text" id="yyyy" maxlength="25" onkeypress="return handleEnter(this, event)" value="<?php echo $year;?>"> And it works when this is my query: $idnum = mysql_real_escape_string($_POST['idnum']); mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); Please help, why do I get the undefined offset error when I use this query: $result = mysql_query("SELECT * FROM student WHERE IDNO='".$_GET['id']."'") I assume that the query is the problem because its the only thing that's different between the two.

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  • php regular expression assistance bold a filename

    - by jason
    I am not very good, with regular expression in php I am trying to get a reg_expression to find all file names such as /file-name-here.php and make it bold. This expression works in Flash but not in php it also doesn't accept the '-' i'm not sure why i can't get it to work with preg_replace /(https?://)?(www\.)?([a-zA-Z0-9_%]*)\b\.[a-z]{2,4}(\.[a-z]{2})?((/[a-zA-Z0-9_%]*)+)?(\.[a-z]*)?/g

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  • PHP Ajax not working

    - by Kostis
    I have 3 buttons on my page and depending on which one the user is clickingi want to run through ajax call a delete query in my database. When the user clicks on a button the javascript function seems to work but it doesn't run the query in php script. The html page: <?php session_start(); ?> <!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-7"> <script> function myFunction(name) { var r=confirm("Are you sure? This action cannot be undone!"); if (r==true) { alert(name); // check if is getting in if statement and confirm the parameter's value var xmlhttp; if (str.length==0) { document.getElementById("clearMessage").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("clearMessage").innerHTML= responseText; } } xmlhttp.open("GET","clearDatabase.php?q="+name,true); xmlhttp.send(); } else alert('pff'); } </script> </head> <body> <div id="wrapper"> <div id="header"></div> <div id="main"> <?php if (session_is_registered("username")){ ?> <!--<a href="#">???a????s? pa?a??? µ???µ?t??</a><br /> <a href="#">???a????s? pa?a??? s??ed????</a><br /> <a href="#">???a????s? push notifications</a><br />--> <input type="button" value="???a????s? pa?a??? µ???µ?t??" onclick="myFunction('messages')" /> <input type="button" value="???a????s? pa?a??? s??ed????" onclick="myFunction('conferences')" /> <input type="button" value="???a????s? push notifications" onclick="myFunction('notifications')" /> <div id="clearMessage"></div> <?php } else echo "Login first."; ?> </div> <div id="footer"></div> </div> </body> </html> and the php script: <?php if (isset($_GET["q"])) $q=$_GET["q"]; $host = "localhost"; $database = "dbname"; $user = "dbuser"; $pass = "dbpass"; $con = mysql_connect($host,$user,$pass) or die(mysql_error()); mysql_select_db($database,$con) or die(mysql_error()); if ($q=="messages") $query = "DELETE FROM push_message WHERE time_sent IS NOT NULL"; else if ($q=="conferences") $query = "DELETE FROM push_message WHERE time_sent IS NOT NULL"; else if ($q=="notifications") { $query = "DELETE FROM push_friend WHERE time_sent IS NOT NULL"; } $res = mysql_query($query,$con) or die(mysql_error()); if ($res) echo "success"; else echo "failed"; mysql_close($con); ?>

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  • header problem in php refresh

    - by basma
    hello i have this code : <?php session_start(); echo "".$_SESSION['eventnum'].""; $urlRefresh = "testremot.php"; header("Refresh: 5; URL=\"" . $urlRefresh . "\""); ?> but the header doesnt work and this warning appear when i try to run this code : Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\remot\testremot.php:3) in C:\xampp\htdocs\remot\testremot.php on line 5 can you please help me ?

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  • Pass a variable from javascript to php in the same session OnClickFunction

    - by MickyScion
    I was seeing through stackoverflow the solutions for this kind of problems but any of them are executing the code of javascript in the same session...please i want some help with this...i have this in my session <script> function show_alert() { var ProdAntes = document.getElementById("productoseleccionado").value; var CantAntes = document.getElementById("cantidadantes").value; var PrecAntes = document.getElementById("precioantes").value; var FecAntes = document.getElementById("fechaantes").value; var ProdAhora = document.getElementById("SoyaProductorProduccionProducto").value; var CantAhora = document.getElementById("SoyaProductorProduccionCantidadtm").value; var PrecAhora = document.getElementById("SoyaProductorProduccionPreciodolar").value; var FecAhora = document.getElementById("select_date").value; } </script> and in my html stuff i have this <?php echo $this->Form->create('SoyaProductorProduccion');?> <fieldset> <?php echo $this->Form->hidden('id', array('value' => $this->data['SoyaProductorProduccion']['id'])); echo $this->Form->input('operacion', array('type' => 'hidden', 'value'=>'Produccion')); //-------------------------------------------------------------- $productoseleccionado = $this->data['SoyaProductorProduccion']['producto']; echo $this->Form->input('productoseleccionado', array('type' => 'hidden','style'=>'width:500px; height:30px;','id' => 'productoseleccionado' , 'value' => $productoseleccionado)); echo $this->Form->input('producto', array( 'options' => array( $productoseleccionado => $productoseleccionado, 'Torta solvente de soya' => 'Torta solvente de soya', 'Torta solvente de girasol' => 'Torta solvente de girasol', 'Harina integral de soya' => 'Harina integral de soya', 'Harina de girasol' => 'Harina de girasol', 'Cascarilla de soya' => 'Cascarilla de soya', 'Cascarilla de girasol' => 'Cascarilla de girasol', 'Aceite de soya refinado' => 'Aceite de soya refinado', 'Aceite de soya crudo' => 'Aceite de soya crudo', 'Aceite de girasol refinado' => 'Aceite de girasol refinado', 'Aceite de girasol crudo' => 'Aceite de girasol crudo', ),'label'=>'Tipo de Producto' )); foreach ($soyacambiodolares as $soyacambiodolar): $dolar=$soyacambiodolar['SoyaCambioDolar']['cambio']; endforeach; echo $this->Form->input('cambio', array('type' => 'hidden','value' => $dolar)); //----------------------------------------------------------------------------- $cantidadantes = $this->data['SoyaProductorProduccion']['cantidadtm']; echo $this->Form->input('cantidadantes', array('type' => 'hidden','style'=>'width:500px; height:30px;', 'value' => $cantidadantes,'id' => 'cantidadantes')); echo $this->Form->input('cantidadtm', array('label' => 'Cantidad en tonelada(s) métrica(s) del producto (TM)','style'=>'width:500px; height:30px;')); //----------------------------------------------------------------------------- $precioantes = $this->data['SoyaProductorProduccion']['preciodolar']; echo $this->Form->input('precioantes', array('type' => 'hidden','style'=>'width:500px; height:30px;', 'value' => $precioantes,'id' => 'precioantes')); echo $this->Form->input('preciodolar', array('label' => 'Precio en Dolares Americanos por tonelada métrica (TM / $us)','style'=>'width:500px; height:30px;')); //----------------------------------------------------------------------------- ?> <table style="width: 600px"> <tr> <td > <?php //---------------------------------------------------------------- $fechaantes = $this->data['SoyaProductorProduccion']['fecharegistro']; echo $this->Form->input('fechaantes', array('type' => 'hidden','style'=>'width:500px; height:30px;', 'value' => $fechaantes, 'id' => 'fechaantes')); //---------------------------------------------------------------- echo $this->Form->input("fecharegistro", array( 'label' => '<strong>Periodo al que corresponde la declaración</strong>', 'type' => 'text', 'style' => 'width: 110px', 'class' => 'fl tal vat w300p', 'error' => false , 'id' => 'select_date')); ?> <?php echo $this->Html->div('datepicker_img w100p fl pl460p pa', $this->Html->image('datepicker_calendar_icon.gif'),array('id' => 'datepicker_img')); ?> <?php echo $this->Html->div('datepicker fl pl460p pa', ' ' ,array('id' => 'datepicker')); ?> </td> </tr> </table> <?php echo $this->Form->submit('Modificar Existencia', array('class' => 'form-submit', 'title' => 'Presione aqui para agregar datos', 'onclick' => 'return show_alert();')); ?> </fieldset> <?php echo $this->Form->end(); ?> my function is ok but i want these: when i click the submit button i want to compare wich field had been changed, and i want to create a chain of detailed changes like "change in the field 1, change in the fiel 2.--" and so on...and this has to be saved in my database so i have to pass to a variable in my php before saving...thanks!

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  • PHP+MYSQL Server Config

    - by Matias
    Hi guys, I am parsing an XML file with PHP and inserting the rows in a MYSQL database. I am using PHP simplexml_load_files to load the XML and a foreach to loop through the array and insert the rows into my database. It works perfectly fine with small files i am testing, but it comes to reality I need to parse a large 500mb XML file and nothing happens. I was wondering what was the right Php.ini config for this case ? I have a VPS Linux Cent OS, with 256 mb of dedicated Memory and MYSQL 5.0.5. I have also set php memory_limit = 256M (maximum of my server) Any suggestions, similar experiences will be greatly appreciated Thanks

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