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  • Microsoft SQL Count problem

    - by Matt
    Hey smarties. I'm having trouble with the following SQL statement. I know that I can't do a GROUP BY on the OnlineStatus column, and it makes sense because it's a function call, not an actual column in my table. How would I modify this so that I can get a count of how many users are online? SELECT CASE dbo.fnGetWebUserOnlineStatus(W.Id) WHEN 1 THEN 'Online' WHEN 2 THEN 'Ingame' ELSE 'Offline' END AS OnlineStatus FROM dbo.WebUsers W WHERE W.[Status]=1 GROUP BY OnlineStatus

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  • T-SQL String Functions: difference between using Left/Right and Substring and strange behaviour

    - by TheObserver
    I am using SQL Server 2008 & 2005 (Express). I'm trying to extract part of an alpha numeric string from a varchar field. RIGHT(str_field,3) yields null values but substring(str_field, len(str_field)-2, len(str_field)) gives the right value. left(str_field,7) gives the expected values. What gives? I would have thought that RIGHT(str_field,3) and substring(str_field, len(str_field)-2, len(str_field)) are equivalent expressions.

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  • Dynamic SQL to query an Adventureworks table

    - by salvationishere
    I am trying to see a list of tables from Adventureworks DB from "Person" schema in Sql Server 2008. I developed teh following SP, but after running it as follows it gives me error "Incorrect syntax near ')'". Do you know how I can revise this SP or exec statement? CREATE PROCEDURE [getTableNames] @SchemaName VARCHAR(50) AS BEGIN SET NOCOUNT ON; SET @SchemaName = 'PERSON' DECLARE @cmd AS VARCHAR(max) SET @SchemaName = RTRIM(@SchemaName) SET @cmd = N'SELECT TABLE_NAME ' + 'FROM information_schema.Tables ' + 'WHERE TABLE_TYPE = ''BASE TABLE'' AND TABLE_SCHEMA = @SchemaName' END exec sp_executesql getTableNames, N'@SchemaName NVARCHAR(50), @SchemaName'

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  • Program execution stop at scanf???

    - by Mohit Deshpande
    main.c (with all the headers like stdio, stdlib, etc): int main() { int input; while(1) { printf("\n"); printf("\n1. Add new node"); printf("\n2. Delete existing node"); printf("\n3. Print all data"); printf("\n4. Exit"); printf("Enter your option -> "); scanf("%d", &input); string key = ""; string tempKey = ""; string tempValue = ""; Node newNode; Node temp; switch (input) { case 1: printf("\nEnter a key: "); scanf("%s", tempKey); printf("\nEnter a value: "); scanf("%s", tempValue); //execution ternimates here newNode.key = tempKey; newNode.value = tempValue; AddNode(newNode); break; case 2: printf("\nEnter the key of the node: "); scanf("%s", key); temp = GetNode(key); DeleteNode(temp); break; case 3: printf("\n"); PrintAllNodes(); break; case 4: exit(0); break; default: printf("\nWrong option chosen!\n"); break; } } return 0; } storage.h: #ifndef DATABASEIO_H_ #define DATABASEIO_H_ //typedefs typedef char *string; /* * main struct with key, value, * and pointer to next struct * Also typedefs Node and NodePtr */ typedef struct Node { string key; string value; struct Node *next; } Node, *NodePtr; //Function Prototypes void AddNode(Node node); void DeleteNode(Node node); Node GetNode(string key); void PrintAllNodes(); #endif /* DATABASEIO_H_ */ I am using Eclipse CDT, and when I enter 1, then I enter a key. Then the console says . I used gdb and got this error: Program received signal SIGSEGV, Segmentation fault. 0x00177024 in _IO_vfscanf () from /lib/tls/i686/cmov/libc.so.6 Any ideas why?

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  • Grouping SQL results by continous time intervals (oracle sql)

    - by Kamil Zadora
    Hi I have following data in the table: ID-----startDate----endDate 5549 2008-05-01 4712-12-31 5567 2008-04-17 2008-04-30 1 5567 2008-05-01 2008-07-31 1 5567 2008-09-01 4712-12-31 2 5569 2008-05-01 2008-08-31 5569 2008-09-01 4712-12-31 5589 2008-04-18 2008-04-30 5589 2008-05-01 4712-12-31 5667 2008-05-01 4712-12-31 5828 2008-06-03 4712-12-31 5867 2008-06-03 4712-12-31 6167 2008-11-01 4712-12-31 6207 2008-07-01 4712-12-31 6228 2008-07-01 4712-12-31 6267 2008-07-14 4712-12-31 I am looking for I way to group the continuous time intervals for each id to return: ID, min(startDate), max(endDate), to have something like this in result for the bolded ID 5567 5567 2008-04-17 2008-07-31 5567 2008-09-01 4712-12-31 PL/SQL is also an option here :) Thanks,

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  • Performance in SQL Mobile with one big column that's not being selected

    - by Anthony Mastrean
    I have a SQL Mobile database with one table. It has several columns with useful, often queried data and one column that stores a relatively large string per record (1000+ characters) that is not queried often. Imagine this fake schema, the "lifeStory" field is the large one. table1 String firstName String lastName String address String lifeStory A representative query would be SELECT firstName, lastName, address FROM table1 WHERE firstName = :p1 Does anyone know of any performance concerns leaving that large, infrequently queried column in this table?

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  • Changing default logical filename in SQL 2005

    - by Andrew
    I have a issue about creating databases in SQL 2005. I want to be able to change the default logical filename for the mdf file. At the moment the log logical filename ends in _log by default. I want the data logical filename to automatically end with _data for consistency. Is there a way i can set this? Andrew

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  • How to Configure and run DataBase Mail in SQL Server

    - by Nasser Hajloo
    How to enable and run Database Mail in SQL Server 2008 . I know that it need Enabling Service Broker Configuring SMTP (a Mail server is needed) Using Configuration Storeprocedure. I don't know what's the relation between application and dataBase mail. Actually How to enable Database mail for a RollBack and Commit Transaction ? (not for all SP , just for some of them)

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  • sql server modify error

    - by Jaspal
    hi, i m not able to modify table in SQL server. i m new to databases. use work go alter table employee modify id varchar(20) error message is- Msg 102, Level 15, State 1, Line 1 Incorrect syntax near 'modify' here is an screenshot thanks

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  • SQL Server Select Distinct

    - by homam
    I want to write a query like this: For a table that has these columns: ColA ColB ColC, ColD select first(ColA, ColB, ColC, ColD) distinct(ColB, ColC) from table order by ColD The query is supposed to order the table by ColD, then group the results by the combination of ColB and ColC (they may have different data types) and returns the first rows (with all the columns of the table) in the groups. How is it possible in MS SQL Server 2005?

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  • How to order by column with non-null values first in sql

    - by devlife
    I need to write a sql statement to select all users ordered by lastname, firstname. This is the part I know how to do :) What I don't know how to do is to order by non-null values first. Right now I get this: null, null null, null p1Last, p1First p2Last, p2First etc I need to get: p1Last, p1First p2Last, p2First null, null null, null Any thoughts?

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  • Modify xml element name in SQL Server

    - by sesame
    I want to change element name with following statement: SET @myDoc.modify('replace value of (/CustomerInfo)[1] with "Customer"') from <CustomerInfo>     <ID1</ID> </CustomerInfo> to <Customer>     <ID1</ID> </Customer> But failed. So how can i change it just in sql ?

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  • Storing JSON in an SQL Server database?

    - by JKirchartz
    I'm developing a form generator, and wondering if it would be bad mojo to store JSON in an SQL Server database? I want to keep my database & tables simple, so I was going to have `pKey, formTitle, formJSON` on a table, and then store {["firstName":{"required":"true","type":"text"},"lastName":{"required":"true","type":"text"}} in formJSON. would this slow down the DB server too much to set live? Any input is appreciated.

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  • Case Order by using Null

    - by molgan
    Hello I have the following test-code: CREATE TABLE #Foo (Foo int) INSERT INTO #Foo SELECT 4 INSERT INTO #Foo SELECT NULL INSERT INTO #Foo SELECT 2 INSERT INTO #Foo SELECT 5 INSERT INTO #Foo SELECT 1 SELECT * FROM #Foo ORDER BY CASE WHEN Foo IS NULL THEN Foo DESC ELSE Foo END DROP TABLE #Foo I'm trying to produce the following output: 1 2 3 4 5 NULL "If null then put it last" How is that done using Sql 2005 /M

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  • help translate this week query from Oracle PL/SQL to SQL Server 2008

    - by Sarah Vessels
    I have the following query that runs in my Oracle database and I want to have the equivalent for a SQL Server 2008 database: SELECT TRUNC( /* Midnight Sunday */ NEXT_DAY(SYSDATE, 'SUN') - (7*LEVEL) ) AS week_start, TRUNC( /* 23:59:59 Saturday */ NEXT_DAY(NEXT_DAY(SYSDATE, 'SUN') - (7*LEVEL), 'SAT') + 1 ) - (1/(60*24)) + (59/(60*60*24)) AS week_end FROM DUAL CONNECT BY LEVEL <= 4 /* Get the past 4 weeks */ What the query does is get the start of the week and the end of the week for the last 4 weeks. It generates data like the following: WEEK_START WEEK_END 2010-03-07 00:00:00 2010-03-13 23:59:59 2010-02-28 00:00:00 2010-03-06 23:59:59 ...

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  • SQL Server 2005 red herring error "The user does not have permission to perform this action"

    - by Sylvia
    We're getting the error "The user does not have permission to perform this action" during times of heavy load (regularly, when a trim job occurs). The error clears up when the service accessing sql server is restarted, so it's obviously not a real permissions problems. What kind of situations could cause an error like this, when it's not really a permissions problem? Any ideas of good places to start looking? thanks for any insights...

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