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  • [solved] IE6 PNG-transparency CSS hack not working

    - by John
    I looked around and decided to use a CSS approach rather than rely on JS... I figure the kind of corporate users stuck with IE6 might also have JS disabled by IT departments. So In my HTML I have: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html;charset=utf-8" /> <title>My Page</title> <link rel="stylesheet" type="text/css" href="default.css" /> <!--[if IE 6]><link rel="stylesheet" type="text/css" href="ie6.css"><![endif]--> </head> <body> <img src="media/logo.png"/> </body> Then my ie6.css consists simply of: img { filter: progid:DXImageTransform.Microsoft.AlphaImageLoader(...); } However none of this makes the slightest difference, no transparency. I commented out all the rest of the page so it is literally that one and still no luck. I removed the default.css stylesheet and still no difference. EDIT: I now got it working, using the .htc method, loading that file in a conditional IE6 test block. It turned out the problem I was having was that Windows 7 had 'locked' the file (I don't even know what this means) and this blocked IE from loading/using it.

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  • how to preform an activity at the android lock screen?

    - by John
    I would like to perform an activity at the key guard screen, but the only way I can find to do so is to disable the key guard, do my activity, then re enable the key guard. This would be ok if it didn't cause the key guard screen to flash off and on (disable makes it disappear then re enable brings it back). I am wondering how I can perform an activity with it still being displayed? Kinda like how when the alarm goes off it shows a pop-up which is displayed over the key-guard screen?

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  • in Python find number of same elements in 2 lists

    - by John
    Hi, In Python if I have 2 lists say: l1 = ['a', 'b', 'c', 'd'] l2 = ['c', 'd', 'e'] is there a way to find out how many elements they have the same. In the case about it would be 2 (c and d) I know I could just do a nested loop but is there not a built in function like in php with the array_intersect function Thanks

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  • MySQL Math - Is it possible to calculate a correlation in a query?

    - by John M
    In a MySQL (5.1) database table there is data that represents: how long a user takes to perform a task and how many items the user handled during the task. Would MySQL support correlating the data or do I need to use PHP/C# to calcuate? Where would I find a good formula to calculate correlation (it's been a long time since I last did this)?

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  • HTML not appearing in Emails

    - by John
    My website sends out html emails but most of my recipients are receiving them as HTML marked up source pages instead of the nice table layouts. The problem doesn't appear to be an email client issue since the emails display properly in web mail clients like gmail, yahoo, hotmail etc... They also display properly when viewed through outlook or thunderbird that are connected to gmail, yahoo, hotmail etc... However, I have one domain name that I registered with a shared hosting provider called 1and1.com. I tried viewing my emails through their webmail client, thunderbird and outlook, but in all three cases, only the html mark up showed up. Also, I assume most of my recipients use MS Outlook with MS Exchange Server because they are business/finance people. Unfortunately, I don't know how to get an email that's managed by an MS Exchange Server. I made sure I'm sending my emails with the following headers: MIME-Version: 1.0 Content-type: text/html; charset=iso-8859-1 Does anyone know what might be wrong? can anyone recommend a solution?

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  • jquery: how to append elements to emtpy object

    - by John
    I want to create a set of options, that will be appended to every select in grid column <option> option 1 </option> <option> option 2 </option> ... <option> option N </option> but I don't know how to create a set of elements without parent element. appending to an empty jquery object doesn't work var options = $(''); options.append('<option></option>')

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  • whats wrong with this peace of code for saving contacts

    - by Shadow
    Hi, i am using the latest Nokia Qt SDK. i have tried to add the contacts, its not getting added.. what is missing here.. // Construct contact manager for default contact backend QContactManager* cm = new QContactManager("simulator"); // QContactManager* cm = new QContactManager("memory"); // i tried this, its also not working // Create example contact QContact example; // Add contact name QContactName name; name.setFirstName("John"); name.setLastName("Doe"); example.saveDetail(&name); // Add contact email address //QContactEmailAddress email; // email.setContexts(QContactDetail::ContextHome); //email.setEmailAddress(“[email protected]”); // example.saveDetail(&email); // Finally, save the contact details cm->saveContact(&example); delete cm; Thanks

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  • Is this a bug? Or is it a setting in ASP.NET 4 (or MVC 2)?

    - by John Gietzen
    I just recently started trying out T4MVC and I like the idea of eliminating magic strings. However, when trying to use it on my master page for my stylesheets, I get this: <link href="<%: Links.Content.site_css %>" rel="stylesheet" type="text/css" /> rending like this: <link href="&lt;%: Links.Content.site_css %>" rel="stylesheet" type="text/css" /> Whereas these render correctly: <link href="<%: Url.Content("~/Content/Site.css") %>" rel="stylesheet" type="text/css" /> <link href="<%: Links.Content.site_css + "" %>" rel="stylesheet" type="text/css" /> It appears that, as long as I have double quotes inside of the code segment, it works. But when I put anything else in there, it escapes the leading "less than". Is this something I can turn off? Is this a bug? Edit: This does not happen for <script src="..." ... />, nor does it happen for <a href="...">. Edit 2: Minimal case: <link href="<%: string.Empty %>" /> vs <link href="<%: "" %>" />

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  • MySQL LEFT OUTER JOIN virtual table

    - by user1707323
    I am working on a pretty complicated query let me try to explain it to you. Here is the tables that I have in my MySQL database: students Table --- `students` --- student_id first_name last_name current_status status_change_date ------------ ------------ ----------- ---------------- -------------------- 1 John Doe Active NULL 2 Jane Doe Retread 2012-02-01 students_have_courses Table --- `students_have_courses` --- students_student_id courses_course_id s_date e_date int_date --------------------- ------------------- ---------- ---------- ----------- 1 1 2012-01-01 2012-01-04 2012-01-05 1 2 2012-01-05 NULL NULL 2 1 2012-01-10 2012-01-11 NULL students_have_optional_courses Table --- `students_have_optional_courses` --- students_student_id optional_courses_opcourse_id s_date e_date --------------------- ------------------------------ ---------- ---------- 1 1 2012-01-02 2012-01-03 1 1 2012-01-06 NULL 1 5 2012-01-07 NULL Here is my query so far SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_have_optional_courses`.optional_courses_opcourse_id, `students_have_optional_courses`.s_date, `students_have_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN `students_have_optional_courses` ON ( `students_have_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_have_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_have_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id; What I want to be returned is the student_id, first_name, and last_name for all Active or Retread students and then LEFT JOIN the highest course_id, s_date, e_date, and int_date for the those students where the s_date is since the status_change_date if status is 'Retread'. Then LEFT JOIN the highest optional_courses_opcourse_id, s_date, and e_date from the students_have_optional_courses TABLE where the students_have_optional_courses.s_date is greater or equal to the students_have_courses.s_date and the students_have_optional_courses.e_date IS NULL Here is what is being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 1 2012-01-06 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Here is what I want being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 5 2012-01-07 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Everything is working except one thing, I cannot seem to get the highest students_have_optional_courses.optional_courses_opcourse_id no matter how I form the query Sorry, I just solved this myself after writing this all out I think it helped me think of the solution. Here is the solution query: SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_optional_courses`.optional_courses_opcourse_id, `students_optional_courses`.s_date, `students_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN ( SELECT * FROM `students_have_optional_courses` ORDER BY `students_have_optional_courses`.optional_courses_opcourse_id DESC ) `students_optional_courses` ON ( `students_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id;

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  • How to get file path using FileUpload to be read by FileStream?

    - by john ryan
    I have a Method that open excel file and read it through exceldatareaderClass that i have downloaded in codeplex by using filestream. Currently I just declared the exact directory where the filestream open an excel file.And it works fine. Stream stream = new FileStream("C:\\" + FileUpload.PostedFile.FileName, FileMode.Open, FileAccess.Read, FileShare.Read); Now i need to read the excel file wherever location the user place it like on windows forms fileupload.FileStream needs the exact location where the file is located. How to do this.? Example: Sample.xls is located on My Documents the file path should be like : C:\Documents and Settings\user\My Documents\ string openpath ="" ;//filepath Stream stream = new FileStream(openpath+ FileUpload.PostedFile.FileName, FileMode.Open, FileAccess.Read, FileShare.Read); Thanks in Regards

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  • Planning and coping with deadlines in SCRUM

    - by John
    From wikipedia: During each “sprint”, typically a two to four week period (with the length being decided by the team), the team creates a potentially shippable product increment (for example, working and tested software). The set of features that go into a sprint come from the product “backlog,” which is a prioritized set of high level requirements of work to be done. Which backlog items go into the sprint is determined during the sprint planning meeting. During this meeting, the Product Owner informs the team of the items in the product backlog that he or she wants completed. The team then determines how much of this they can commit to complete during the next sprint. During a sprint, no one is allowed to change the sprint backlog, which means that the requirements are frozen for that sprint. After a sprint is completed, the team demonstrates the use of the software. I was reading this and two questions immediately popped into my head: 1)If a sprint is only a couple of weeks, decided in a single meeting, how can you accurately plan what can be achieved? High-level tasks can't be estimated accurately in my experience, and can easily double what seems reasonable. As a developer, I hate being pushed into committing what I can deliver in the next month based on a set of customer requirements, this goes against everything I know about generating reliable estimates rather than having to roughly estimate and then double it! 2)Since the requirements are supposed to be locked and a deliverable product available at the end, what happens when something does take twice as long? What if this feature is only 1/2 done at the end of the sprint? The wiki article goes on to talk about Sprint planning, where things are broken down into much smaller tasks for estimation (<1 day) but this is after the Sprint features are already planned and the release agreed, isn't it? kind of like a salesman promising something without consulting the developers.

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  • MySQL developer here -- Nesting with select * finicky in Oracle 10g?

    - by John Sullivan
    I'm writing a simple diagnostic query then attempting to execute it in the Oracle 10g SQL Scratchpad. EDIT: It will not be used in code. I'm nesting a simple "Select *" and it's giving me errors. In the SQL Scratchpad for Oracle 10g Enterprise Manager Console, this statement runs fine. SELECT * FROM v$session sess, v$sql sql WHERE sql.sql_id(+) = sess.sql_id and sql.sql_text <> ' ' If I try to wrap that up in Select * from () tb2 I get an error, "ORA-00918: Column Ambiguously Defined". I didn't think that could ever happen with this kind of statement so I am a bit confused. select * from (SELECT * FROM v$session sess, v$sql sql WHERE sql.sql_id(+) = sess.sql_id and sql.sql_text <> ' ') tb2 You should always be able to select * from the result set of another select * statement using this structure as far as I'm aware... right? Is Oracle/10g/the scratchpad trying to force me to accept a certain syntactic structure to prevent excessive nesting? Is this a bug in scratchpad or something about how oracle works?

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  • X-Domain Cookies in iFrames

    - by John
    Hi Guys, I have a domain A.com which is my website. I want to allow the user to login and then I have embedded an iframe into domain B.com which attempts to grab the cookie from A.com to allow the user to be continued to be signed in. I can't seem to get this working in IE ? A new session gets set instead and the cookie is never retrieved. I have set a P3P policy ? Any ideas what I am doing wrong.

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  • Include a unique URL in EXE

    - by John Grey
    Hi :) I want to give users of my site the ability to upload their software/hardware configuration automatically on Windows. So I'm thinking of having an EXE file download, and somehow put in that EXE a unique URL for each user. When the data is collected, the program would just posts some JSON to that URL. How can I do it? I'm most familiar with .NET platform. Tools like this do exist, for example Blizzard uses this approach for their beta test enroll. Each user downloads a slightly different EXE. TIA

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  • Why does C++ linking use virtually no CPU?

    - by John
    On a native C++ project, linking right now can take a minute or two, yet during this time CPU drops from 100% during compilation to virtually zero. Does this mean linking is primarily a disk activity? If so, is this the main area an SSD would make big changes? But, why aren't all my OBJ files (or as many as possible) kept in RAM after compilation to avoid this? With 4Gb of RAM I should be able to save a lot of disk access and make it CPU-bound again, no?

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  • `php -v` segmentation fault

    - by John
    I'm getting an odd segmentation fault in PHP. Every few times, when I run: php -v I see: PHP 5.2.6 (cli) (built: Aug 19 2009 16:59:56) Copyright (c) 1997-2008 The PHP Group Zend Engine v2.2.0, Copyright (c) 1998-2008 Zend Technologies Segmentation fault (core dumped) Analyzing the core dump (backtrace with gdb): #0 0x00002ba6412f6c6c in ?? () #1 0x0000003f90c06367 in start_thread () from /lib64/libpthread.so.0 #2 0x0000003f904d2f7d in clone () from /lib64/libc.so.6 #3 0x0000000000000000 in ?? () Any ideas? OS: Linux version 2.6.18-92.el5 ([email protected]) (gcc version 4.1.2 20071124 (Red Hat 4.1.2-42)) #1 SMP Tue Jun 10 18:51:06 EDT 2008

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  • Which XML library for what purposes?

    - by John Mee
    A search for "python" and "xml" returns a variety of libraries for combining the two. This list probably faulty: xml.dom xml.etree xml.sax xml.parsers.expat PyXML beautifulsoup? HTMLParser htmllib sgmllib Be nice if someone can offer a quick summary of when to use which, and why.

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  • Paginating data, has to be a better way

    - by John Tyler
    I've read like 10 or so "tutorials", and they all involve the same thing: Pull a count of the data set Pull the relevant data set (LIMIT, OFFSET) IE: SELECT COUNT(*) FROM table WHERE something = ? SELECT * FROM table WHERE something =? LIMIT ? offset ?` Two very similar queries, no? There has to be a better way to do this, my dataset is 600,000+ rows and already sluggish (results are determined by over 30 where clauses, and vary from user to user, but are properly indexed of course).

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  • C# = assigning custom objects to array with a for loop?

    - by John M
    Given this example: // Create an arary of car objects. car[] arrayOfCars= new car[] { new car("Ford",1992), new car("Fiat",1988), new car("Buick",1932), new car("Ford",1932), new car("Dodge",1999), new car("Honda",1977) }; I tried something like this: for (int i = 0; i < dtable.Rows.Count; i++) { DataRow drow = dtable.Rows[i]; arrayOfCars[] = new car(drow["make"].ToString(), drow["year"].ToString()); } How do I add additional data to the array while looping through a datatable?

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  • Controlling the print options of a pdf

    - by John Nolan
    I am producing a number of PDFs using either SSRS or using an HTML to PDF component. What I want to do for each document is to set the first page to print to tray 1 and subsequent pages. Is there anyway to do this? System.Drawing.Printing and System.Printing seem like good candidates but they don't seem to be useful for PDFs (i may be wrong). The Adobe sdk doesn't at first glance seem to have that level of granularity either.

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  • Left Join works with table but fails with query

    - by Frank Martin
    The following left join query in MS Access 2007 SELECT Table1.Field_A, Table1.Field_B, qry_Table2_Combined.Field_A, qry_Table2_Combined.Field_B, qry_Table2_Combined.Combined_Field FROM Table1 LEFT JOIN qry_Table2_Combined ON (Table1.Field_A = qry_Table2_Combined.Field_A) AND (Table1.Field_B = qry_Table2_Combined.Field_B); is expected by me to return this result: +--------+---------+---------+---------+----------------+ |Field_A | Field_B | Field_A | Field_B | Combined_Field | +--------+---------+---------+---------+----------------+ |1 | | | | | +--------+---------+---------+---------+----------------+ |1 | | | | | +--------+---------+---------+---------+----------------+ |2 |1 |2 |1 |John, Doe | +--------+---------+---------+---------+----------------+ |2 |2 | | | | +--------+---------+---------+---------+----------------+ [Table1] has 4 records, [qry_Table2_Combined] has 1 record. But it gives me this: +--------+---------+---------+---------+----------------+ |Field_A | Field_B | Field_A | Field_B | Combined_Field | +--------+---------+---------+---------+----------------+ |2 |1 |2 |1 |John, Doe | +--------+---------+---------+---------+----------------+ |2 |2 |2 | |, | +--------+---------+---------+---------+----------------+ Really weird is that the [Combined_Field] has a comma in the second row. I use a comma to concatenate two fields in [qry_Table2_Combined]. If the left join query uses a table created from the query [qry_Table2_Combined] it works as expected. Why does this left join query not give the same result for a query and a table? And how can i get the right results using a query in the left join?

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