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  • Numbered paragraphs in Word 2007

    - by Kit
    I have the following styles defined in Word 2007. They all have outline levels 1-6. They also correctly show up in the Table of Contents (not all, I only set the TOC up to Level 3). 1 Heading 1 1.1 Heading 2 1.1.1 Heading 3 1.1.1.1 Heading 4 1.1.1.1.1 Heading 5 1.1.1.1.1.1 Heading 6 This is what I want 1 Heading 1 1.1 Body text under Heading Level 1 1.2 Body text under Heading Level 1 2 Heading 1 2.1 Heading 2 2.1.1 Body text under Heading Level 2 2.1.2 Body text under Heading Level 2 2.1.3 Body text under Heading Level 2 2.2 Heading 2 2.2.1 Body text under Heading Level 2 2.2.2 Body text under Heading Level 2 How do I make two list sequences link to each other? Here's a {fill in the blanks} illustration: {section number} Heading 1 {section number}.{clause number} Body text under Heading Level 1 {section number}.{clause number} Body text under Heading Level 1 The example above should expand to: 1 Heading 1 1.1 Body text under Heading Level 1 1.2 Body text under Heading Level 1 Another example: {section number} Heading 1 {section number}.{subsection number} Heading 2 {section number}.{subsection number}.{clause number} Body text under Heading Level 2 {section number}.{subsection number}.{clause number} Body text under Heading Level 2 should expand to: 2 Heading 1 2.1 Heading 2 2.1.1 Body text under Heading Level 2 2.1.2 Body text under Heading Level 2 2.1.3 Body text under Heading Level 2 The numbered body text paragraphs shouldn't show up the Table of Contents. I couldn't find the right way to do that, whether in multilevel lists, fields, styles, etc. How do I do it right?

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  • Take the intersection of an arbitrary number of lists in python

    - by thepandaatemyface
    Suppose I have a list of lists of elements which are all the same (i'll use ints in this example) [range(100)[::4], range(100)[::3], range(100)[::2], range(100)[::1]] What would be a nice and/or efficient way to take the intersection of these lists (so you would get every element that is in each of the lists)? For the example that would be: [0, 12, 24, 36, 48, 60, 72, 84, 96]

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  • ruby number to human-readable string conversion

    - by yaya3
    I need to have a list with id's for each list item being #one, #two etc. Is this the most efficient way or am I missing an in built ruby function here? -num_array = ["one", "two", "three", "four", "five", "six", "seven"] -navigation[:primary_level].each_with_index do |primary_item, idx| %li{ :id => "#{num_array[idx]}"}

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  • Auto generate varchar Ticket number via DB...

    - by Rusty
    Hello, I'm looking for suggestion on how to get the DB to auto generate Ticket numbers (preferably via the SQL DB) for a varchar column. I have the following tables in the DB: Activities & Cases and would prefer the format to be "Act000001" or "Cse000001". This would be something similar to the identity column property. Any suggestion would be highly appreciated. Thanks. Rusty

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  • How to catch specific exception without error number?

    - by CJ7
    I need to catch the following specific exception: System.Data.OleDb.OleDbException was caught ErrorCode=-2147467259 Message="The changes you requested to the table were not successful because they would create duplicate values in the index, primary key, or relationship. Change the data in the field or fields that contain duplicate data, remove the index, or redefine the index to permit duplicate entries and try again." Source="Microsoft JET Database Engine" I'm not sure what ErrorCode is but it looks unreliable. Can I rely on Message being identical across platforms? Is the only solution to do a text search of Message for words like duplicate and primary key? Note: see my question here for why I need to catch this exception.

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  • Internet Explorer not incrementing number for non-sibling <li> elements

    - by biagidp
    I've got some html that looks like this: <ol> <div> <li>one</li> </div> <div> <li>two</li> </div> <div> <li>three</li> </div> </ol> Which looks like this in Chrome/Firefox: 1. one 2. two 3. three But looks like this in IE: 1. one 1. two 1. three If I change the code so that the li element is the parent of the div element instead of the other way around (so that all the li elements are siblings) IE renders it correctly. Anyone know what causes this or if this is the intended working behavior of IE? Furthermore is one way technically more correct than the other? <div><li></li></div> VS. <li><div></div></li> Thanks, David

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  • Limit Annotation number in Mapkit

    - by teddafan
    Hi all, I want to stop my app from loading more annotations after they are all added ( they are added by the user one by one). How would you do that? the following code is what i think is important (void) loadAndSortPOIs { [poiArray release]; nextPoiIndex = 0; NSString *poiPath = [[NSBundle mainBundle] pathForResource:@"pois" ofType:@"plist"]; poiArray = [[NSMutableArray alloc] initWithContentsOfFile:poiPath]; CLLocation *homeLocation = [[CLLocation alloc] initWithLatitude:homeCoordinate.latitude longitude:homeCoordinate.longitude]; for (int i = 0; i < [poiArray count]; i++) { NSDictionary *dict = (NSDictionary*) [poiArray objectAtIndex: i]; CLLocationDegrees storeLatitude = [[dict objectForKey:@"workingCoordinate.latitude"] doubleValue]; CLLocationDegrees storeLongitude = [[dict objectForKey:@"workingCoordinate.longitude"] doubleValue]; CLLocation *storeLocation = [[CLLocation alloc] initWithLatitude:storeLatitude longitude:storeLongitude]; CLLocationDistance distanceFromHome = [storeLocation getDistanceFrom: homeLocation]; NSMutableDictionary *mutableDict = [[NSMutableDictionary alloc] initWithDictionary:dict]; [mutableDict setValue:[NSNumber numberWithDouble:distanceFromHome] forKey:@"distanceFromHome"]; [poiArray replaceObjectAtIndex:i withObject:mutableDict]; [mutableDict release]; } [homeLocation release]; // now sort by distanceFromHome NSArray *sortDescriptors = [NSArray arrayWithObject: [[NSSortDescriptor alloc] initWithKey: @"distanceFromHome" ascending: YES]]; [poiArray sortUsingDescriptors:sortDescriptors]; NSLog (@"poiArray: %@", poiArray); } Thank you for your help. Best regards,

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  • PHP and MS Access: Number of Records returned by SELECT query

    - by VarunGupta
    I am running following PHP code to interact with a MS Access database. $odbc_con = new COM("ADODB.Connection"); $constr = "DRIVER={Microsoft Access Driver (*.mdb)}; DBQ=" . $db_path . ";"; $odbc_con -> open($constr); $rs_select = $odbc_con -> execute ("SELECT * FROM Main"); Using ($rs_select - RecordCount) gives -1 though the query is returning non-zero records. (a) What can be the reason? (b) Is there any way out? I have also tried using count($rs_select -> GetRows()). This satisfies the need but looks inefficient as it will involve copying of all the records into an array first.

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  • How to use R-Tree for plotting large number of map markers on google maps

    - by Eeyore
    After searching SO and multiple articles I haven't found a solution to my problem. What I am trying to achieve is to load 20,000 markers on Google Maps. R-Tree seems like a good approach but it's only helpful when searching for points within the visible part of the map. When the map is zoomed out it will return all of the points and...crash the browser. There is also the problem with dragging the map and at the end of dragging re-running the query. I would like to know how I can use R-Tree and be able to achieve the all of the above.

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  • Objective-c Method to get a number then countdown in 1 every second

    - by Sami
    Hi, i need a little help i have a method which gets value such as 50, it then assigns that value to trackDuration, so NSNumber *trackDuration = 50, i want the method to every second minus 1 from the value of trackDuration and update a label, the label being called duration. Here's what i have so far; - (void) countDown { iTunesApplication *iTunes = [SBApplication applicationWithBundleIdentifier:@"com.apple.iTunes"]; NSNumber *trackDuration = [NSNumber numberWithDouble:[[iTunes currentTrack] duration]]; while (trackDuration > 0) { trackDuration - 1; int inputSeconds = [trackDuration intValue]; int hours = inputSeconds / 3600; int minutes = ( inputSeconds - hours * 3600 ) / 60; int seconds = inputSeconds - hours * 3600 - minutes * 60; NSString *trackDurationString = [NSString stringWithFormat:@"%.2d:%.2d:%.2d", hours, minutes, seconds]; [duration setStringValue:trackDurationString]; sleep(1); }} Any help would be much appreciated, thanks in advanced, Sami.

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  • C# : Number Conversion Problem

    - by Sayem Ahmed
    Today I faced a strange problem in C#. I have an ASP.NET page where user can enter certain price, quantity etc. I get the price value, convert it to double, then multiply it with 100 and then typecast it to an integer. When the price is "33.30", after converting it to double it remains 33.3 (obviously...), but after multiplying it with 100, it becomes 3329.9999999999995, and when I cast it to integer by applying simple cast operator "(int) (price * 100) ", it becomes 3329. Right now I have no idea why this is happening. So I thought may be you guys can help :) .

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  • Stack trace with incorrect line number

    - by adrianbanks
    Why would a stack trace show "line 0", but only for one frame in the stack trace? eg. ... at System.Data.SqlClient.SqlCommand.ExecuteDbDataReader(CommandBehavior behavior) at System.Data.Common.DbCommand.System.Data.IDbCommand.ExecuteReader() at My.LibraryA.Some.Method():line 16 at My.LibraryB.Some.OtherMethod():line 0 at My.LibraryB.Some.Method():line 22 at My.LibraryA.Some.Method():line 10 Background: I have an application that is failing with an exception, and is logging a stack trace to its log file. When the applciation was built, all assemblies were compiled with full debug info (Project Properties - Build - Advanced - Debug Info - Full), and so PDB files were generated. To help me diagnose where the error is coming from, I dropped the PDB files into the application's bin directory, and reproduced the exception. All line numbers for each stack frame look correct, with the exception of one which displays "line 0" as its source.

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  • jQuery - After number of elements add html!

    - by Florescu Adrian
    Hello. I need to know if I can count the elements inside a div and after 3 elements to add an html object. <div id="wrapper"> <a href="#">1</a> <a href="#">1</a> <a href="#">1</a> //insert html with jQuery here <a href="#">1</a> <a href="#">1</a> <a href="#">1</a> //insert html with jQuery here <a href="#">1</a> <a href="#">1</a> <a href="#">1</a> //insert html with jQuery here </div>

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  • Phone Number Recognition in Javascript

    - by samer
    Hi Guys, Is there a javascript library the can recognize phone numbers in a web page? Just like what skype did on their firefox plugin. Or do you know a way on how to do it? Websites or any tutorial that do the same would be very helpful. Your reply is greatly appreciated. Best,

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  • Rails - Format number as currency format in the Getter

    - by daemonsy
    I am making a simple retail commerce solution, where there are prices in a few different models. These prices contribute to a total price. Imagine paying $0.30 more for selecting a topping for your yogurt. When I set the price field to t.decimal :price, precision:8, scale:2 The database stores 6.50 as 6.5. I know in the standard rails way, you call number_to_currency(price) to get the formatted value in the Views. I need to programmatically call the price field as well formatted string, i.e. $6.50 a few places that are not directly part of the View. Also, my needs are simple (no currency conversion etc), I prefer to have the price formatted universally in the model without repeated calling number_to_currency in views. Is there a good way I can modify my getter for price such that it always returns two decimal place with a dollar sign, i.e. $6.50 when it's called? Thanks in advance.

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  • inserting large number of dates

    - by Radhe
    How can I insert all dates in an year(or more) in a table using sql My dates table has following structure dates(date1 date); Suppose I want to insert dates between "2009-01-01" to "2010-12-31" inclusive. Is there any sql query for the above?

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