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• How to make strtotime parse dates in Australian (i.e. UK) format: dd/mm/yyyy?

  - by Iain Fraser

  I can't beleive I've never come across this one before. Basically, I'm parsing the text in human-created text documents and one of the fields I need to parse is a date and time. Because I'm in Australia, dates are formatted like dd/mm/yyyy but strtotime only wants to parse it as a US formatted date. Also, exploding by / isn't going to work because, as I mentioned, these documents are hand-typed and some of them take the form of d M yy. I've tried multiple combinations of setlocale but no matter what I try, the language is always set to US English. I'm fairly sure setlocale is the key here, but I don't seem to be able to strike upon the right code. Tried these: au au-en en_AU australia aus Anything else I can try? Thanks so much :) Iain Example: $mydatetime = strtotime("9/02/10 2.00PM"); echo date('j F Y H:i', $mydatetime); Produces 2 September 2010 14:00 I want it to produce: 9 February 2010 14:00

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• MYSQL query to get all entries with specific time, from PHP?

  - by meds

  I'm trying to query a mysql table which places its date in the following format: yyyy-mm-dd hh:mm:ss So it's date and time, and that's all in a single field. Now from php I want to get the time and query the table to only return entries where the date field is less than 24 hours old. I'm having issues with the system because PHPs get time seems to return the values seperately and I'm struggling to figure out how to make it work with mysql queries. This seems fairly simple but I'm quite new to php so sorry if I'm completely missing something..

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• basic boost date_time input format question

  - by Chris H

  I've got a pointer to a string, (char *) as input. The date/time looks like this: Sat, 10 Apr 2010 19:30:00 I'm only interested in the date, not the time. I created an "input_facet" with the format I want: boost::date_time::date_input_facet inFmt("%a %d %b %Y"); but I'm not sure what to do with it. Ultimately I'd like to create a date object from the string. I'm pretty sure I'm on the right track with that input facet and format, but I have no idea how to use it. Thanks.

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• StremReader.ReadToEnd() returning an empty string

  - by axk

  I have a method private static String DecompressAndDecode(byte[] data) { GZipStream decompressor = new GZipStream(new MemoryStream(data), CompressionMode.Decompress); StreamReader decompressed = new StreamReader(decompressor, Encoding.UTF8); String result = decompressed.ReadToEnd(); return result; } I have some GZipped text as input and the result is supposed to be a String representation of this text. The problem is that the method returns an empty string. What is puzzling me is that when I step trough the method in debug mode and reach the return statement the result variable is an empty string but if I create a watch for the decompressed.ReadToEnd() expression it returns me the text. What I would expect at this point is the result variable to contain the text and the decompressed.ReadToEnd() expression evaluating to an empty string. (Reevaluating the decompressed.ReadToEnd() expression returns an empty string as expected). There must be something obvious I'm missing here.

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• Write a program that allows the user to enter a string and then prints the letters of the String sep

  - by WM

  The output is always a String, for example H,E,L,L,O,. How could I limit the commas? I want the commas only between letters, for example H,E,L,L,O. import java.util.Scanner; import java.lang.String; public class forLoop { public static void main(String[] args) { Scanner Scan = new Scanner(System.in); System.out.print("Enter a string: "); String Str1 = Scan.next(); String newString=""; String Str2 =""; for (int i=0; i < Str1.length(); i++) { newString = Str1.charAt(i) + ","; Str2 = Str2 + newString; } System.out.print(Str2); } }

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• ls output changing when used through exec()

  - by user359650

  I'm using the ls command via PHP and exec() and I get a different output than when I run the same command via the shell. When running ls through PHP the year and month of the date get changed into the month name: Running the command through the shell: $ ls -lh /path/to/file -rw-r--r-- 1 sysadmin sysadmin 36M 2011-05-18 13:25 file Running the command via PHP: <?php exec("ls -lh /path/to/file", $output); print_r($output); /* Array ( [0] => -rw-r--r-- 1 sysadmin sysadmin 36M May 18 13:25 file ) */ Please note that: -the issue doesn't occur when I run the PHP script via the cli (it only occurs when run through apache) -I checked the source code of the page to make sure that what I was seeing was what I was getting (and I do get the month name instead of the proper date) -I also run the ls command through the shell as the www-data user to see if ls was giving different output depending on the user (the output is the always the same from the shell, that is I get the date in yyyy-mm-dd instead of the month name)

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• How can I clip strings in Java2D and add ... in the end?

  - by Jonas

  I'm trying to print Invoices in a Java Swing applications. I do that by extending Printable and implement the method public int print(Graphics g, PageFormat pf, int page). I would like to draw strings in columns, and when the string is to long I want to clip it and let it end with "...". How can I measure the string and clip it at the right position? Some of my code: Font headline = new Font("Times New Roman", Font.BOLD, 14); g2d.setFont(headline); FontMetrics metrics = g2d.getFontMetrics(headline); g2d.drawString(myString, 0, 20); I.e How can I limit myString to be max 120px? I could use metrics.stringWidth(myString), but I don't get the position where I have to clip the string. Expected results could be: A longer string that exc... A shorter string. Another long string, but OK

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• php - comparing timestamp dates to make sure user is of minimum age

  - by Micheal Ken

  When a user signs up the system has to check that they are old enough to do so, in this example they have to be atleast 8 years old $minAge = strtotime(date("d")."-".date("m")."-".(date("Y")-8)); $dob = strtotime($day."-".$month."-".$year); $minAge = 01-03-2004, $dob = 01-02-2011 I basically need to make sure this person was born before 2004 but I want to know whether I have to convert the timestamps to do a comparison or whether there is a more efficient way. Any help is appreciated, thank you

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• Scaffolding A model with an attribute of type datetime creates a 10 years range in the form

  - by b_ayan

  For a simple rails application ( 1.86 /2.3.5) , lets say I run a simple scaffold script/generate scaffold blog title:string content:text published:date When I open up the new / edit view for the blog controller in index/new.html.erb , I see that the drop down enabler for date select has a date range of 2005 - 2015 , i.e 5 years +/- I tried to change this default behavior by introducing this code f.date_select :entered, :start_year => 1970, :end_year => 2020 Apparently this has no impact to the behavior mentioned above. How do I increase the date_select range which seems to be default?

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• What is the MM/DD/YYYY regular expression and how do I use it in php?

  - by zeckdude

  I found the regular expression for MM/DD/YYYY at http://www.regular-expressions.info/regexbuddy/datemmddyyyy.html but I don't think I am using it correctly. Here's my code: $date_regex = '(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d'; $test_date = '03/22/2010'; if(preg_match($date_regex, $test_date)) { echo 'this date is formatted correctly'; } else { echo 'this date is not formatted correctly'; } When I run this, it still echoes 'this date is not formatted correctly', when it should be saying the opposite. How do I set this regular expression up in php?

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• How to set the time for a specific local in javascript

  - by Joao

  Hi, i have a problem, and maybe someone can help me, i will explain... i have the in javascript "var date= new date();" and its give me the local time (browser time) but i want force this data/time for a especific local... for example... Spain. i want everytime that someone enter in the page (from others country) the date need be the spanish hour. i found some soluction but the problem is the summer time and winter time... we have offset variations because some time is +1 hours and others is +2.... someone can help me in one soluction? thanks [email protected]

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• String handle in C#

  - by Chelsea_cole

  I don't understand the use of "get" and "set" command, how to add a list of the accounts using the code below and someone give me some example to fix the error? Thanks! :( public class Account { public string UserName {get rerurn textBox1.Test; // error set UserName = textBox1.Text;} // error public string Password { get; set; } public string RePassword { get; set; } public string Name { get; set; } public string bd { get; set; } public string dt { get; set; } public string dc { get; set; } } public class ListAcc { static void Data() { List<Account> UserList = new List<Account>(); } }

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• mySQL query : working with INTERVAL and CURDATE

  - by Tristan

  Hello, i'm building a chart and i want to recieve data for each months Here's my first request which is working : SELECT s.GSP_nom AS nom, timestamp, AVG( v.vote + v.prix ) /2 AS avg FROM votes_serveur AS v INNER JOIN serveur AS s ON v.idServ = s.idServ WHERE s.valide =1 AND v.date > CURDATE() -30 GROUP BY s.GSP_nom ORDER BY avg DESC But, in my case i've to write 12 request to recieve datas for the 12 previous months, is there any trick to avoid writing : // example for the previous month AND v.date > CURDATE() -60 AND v.date < CURDATE () -30 I heard about INTERVAL, i went to the mySQL doc but i didn't manage to implement it. Any ideas / example of using INTERVAL please ? Thank you

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• How to select the most recent set of dated records from a mysql table

  - by Ken

  I am storing the response to various rpc calls in a mysql table with the following fields: Table: rpc_responses timestamp (date) method (varchar) id (varchar) response (mediumtext) PRIMARY KEY(timestamp,method,id) What is the best method of selecting the most recent responses for all existing combinations of method and id? For each date there can only be one response for a given method/id. Not all call combinations are necessarily present for a given date. There are dozens of methods, thousands of ids and at least 356 different dates Sample data: timestamp method id response 2009-01-10 getThud 16 "....." 2009-01-10 getFoo 12 "....." 2009-01-10 getBar 12 "....." 2009-01-11 getFoo 12 "....." 2009-01-11 getBar 16 "....." Desired result: 2009-01-10 getThud 16 "....." 2009-01-10 getBar 12 "....." 2009-01-11 getFoo 12 "....." 2009-01-11 getBar 16 "....." (I don't think this is the same question - it won't give me the most recent response)

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• Function for averages of tuples in a dictionary

  - by Billy Mann

  I have a string, dictionary in the form: ('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) Each parentheses is a tuple which corresponds to (score, standard deviation). I'm taking the average of just the first integer in each tuple. I've tried this: def score(string, d): for word in d: (score, std) = d[word] d[word]=float(score),float(std) if word in string: word = string.lower() number = len(string) return sum([v[0] for v in d.values()]) / float(len(d)) if len(string) == 0: return 0 When I run: print score('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) I should get 5.5 but instead I'm getting 5.875. Can't figure out what in my function is not allowing me to get the correct answer.

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• Convert Java String to Array

  - by Bruce

  This is a weird problem. Here is my code String reply = listen.executeUrl("http://localhost:8080/JavaBridge/reply.php); executeUrl returns as String object whatever is returned by the reply.php file. Now comes the problem. In reply.php I am returning an PHP array and reply is a String. When I do System.out.println("Reply = "+reply); I get Reply = array(2) { [0]=> string(14) "Dushyant Arora" [1]=> string(19 ) "@dushyantarora13 hi"} But reply is still a String. How do I convert it into a String array or an Array.

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• Passing variable string to create arrays (Android)

  - by dweebsonduty

  Hello all, I am a newb to Android and Java and want to write a funtion that will display a list based on a varable that I pass to the function. The function is below and the code below creates an array out of a string called type, but what I want to do is pass it a variable string and have it build a list based on that string. So if I wanted the type list I would say list_it("type") But if I try something like getResources().getStringArray(R.array.thelist); it doesn't work. Can someone point me in the right direction? public void list_it(String thelist){ String[] types = getResources().getStringArray(R.array.type); ArrayAdapter<String> mAdapter = new ArrayAdapter<String>(this, R.layout.list_item1, types); setListAdapter(mAdapter); ListView lv = getListView(); lv.setTextFilterEnabled(true); }

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• SharePoint - Auto-increment dates in new records?

  - by ACal

  Hello, I have a list that's going to be updated with relatively static data weekly, and I wanted to create a workflow to do this automatically. The only field I'm having trouble with is Start Date. I want the new Start Date to be exactly one week after the previous week's (row's) Start Date, but I can't figure out how to capture this. I can't seem to find an easy way to get the value of the previous row. Now, theoretically, I could just have the workflow run once a week on a given day and use [Today] as the value for the field; however, a requirement is that the list can be populated a few weeks in advance if needed. Thanks in advance for any help you can provide!

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• Java: Extend SimpleDateFormat with new pattern letters

  - by Adam Matan

  Java's SimpleDateFormat is used to format a Date object to a string. The formatter supports various pattern letters, which denote textual representation of a Date field. For example, yy is two-letter year, yyyy is four-letter year, and E is day of week. For example, A SimpleDateFormat initialized with yyyy.MM.dd G 'at' HH:mm:ss z will format a date to something like 2001.07.04 AD at 12:08:56 PDT. I would like to add some pattern letters to SimpleDateFormat. For example, want C to denote Hebrew weekday (??? ?????, ??? ???, ...). What's the right way to extend SimpleDateFormat with these new pattern letters? The only online example I could find seems somewhat complicated. I can live with formatting only, without parsing.

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• C# sqlite query results to list<string>

  - by jakesankey

  Guys, I'm struggling. I have query against my db that returns a single column of data and I need to set it as List. Here is what I am working with and I am getting an error about converting void to string. public static void GetImportedFileList() { using (SQLiteConnection connect = new SQLiteConnection(@"Data Source=C:\Documents and Settings\js91162\Desktop\CMMData.db3")) { connect.Open(); using (SQLiteCommand fmd = connect.CreateCommand()) { SQLiteCommand sqlComm = new SQLiteCommand(@"SELECT DISTINCT FileName FROM Import"); SQLiteDataReader r = sqlComm.ExecuteReader(); while (r.Read()) { string FileNames = (string)r["FileName"]; List<string> ImportedFiles = new List<string>(); } connect.Close(); } } } THEN LATER IN THE APPLICATION List<string> ImportedFiles = GetImportedFileList() // Method that gets the list of files from the db foreach (string file in files.Where(fl => !ImportedFiles.Contains(fl)))

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• Casting Class into String and Vice Versa in JAVA

  - by topgun_ivard

  I have a program in which I need to store a Class object into memory by casting it into String. Is it possible to convert the String back into the original Class so that I can use that class variables? I am doing this in JAVA. Example: test.java class hello{ public String h1; public String h2; } public class test { public static void main(String[] args) { hello h = new hello(); h.h1 = "hello"; h.h2 = "world"; String s = h.toString(); System.out.println("Print s : "+s); // Now I need to convert String s into type hello so that // I can do this: // (hello)s.h1; // (hello)s.h2; } } NOTE: this is not a homework, this is a personal project and I would be grateful if anyone can help! Thanks! Ivar

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• how to calculate the beginning of a day given milliseconds?

  - by conman

  i want to figure out the time from the beginning of the day given a days milliseconds. so say i'm given this: 1340323100024 which is like mid day of 6/21/2012. now i want the milliseconds from the beginning of the day, which would be 1340262000000 (at least i think that's what it's supposed to be.) how do i get 1340262000000 from 1340323100024? i tried doing Math.floor(1340323100024/86400000) * 86400000 but that gives me 1340236800000, which if i create a date object out of it, says its the 20th. i know i can create a date object from 1340323100024, then get the month, year, and date, to create a new object which would give me 1340262000000, but i find it ridiculous i can't figure out something so simple. any help would be appreciated. btw, i'm doing this in javascript if it makes any difference.

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• Fortran - String with unknown characters into substrings

  - by Masoud

  I am trying to put an input string into sub-string arrays. The number of data in the input file are less than 10 but unknown. The number of spaces between each data is also unclear. Example: Asd B Cwqe21 Ddsw Eww I am quite novice to Fortran, so I do not know which format I should use. My problem is that I do not know the number of data (here I assumed that there are 5), so how can I make the code work? I tried the following which did not work: CHARACTER (LEN=100), DIMENSION(10) :: string READ (1,*) (string,I=1,10) It seems that the error I got was because there was no 6th string to read and put into string(6). I tried using the "Index" to find the space, but since I do not know how many spaces are in the string, it did not help me.

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• Splitting html string after so many words

  - by jimbo

  Hi all, I have a string that if it is longer than lets say 10 words, I want to split it into two parts. The second part will be included else-where after a 'more' link. The string will hold html tags too though. For an example the string could be: <p>This is just a test string with more words than the <strong>amount allow</strong> before split, blah blah blah</p> So in the case I would want: $string[0] // <p>This is just a test string with more words than</p>; $string[1] // <p>the <strong>amount allow</strong> before split, blah blah blah</p>; Thanks in advance

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• Python : How to add month to December 2012 and get January 2013?

  - by daydreamer

  >>> start_date = date(1983, 11, 23) >>> start_date.replace(month=start_date.month+1) datetime.date(1983, 12, 23) This works until the month is <=11, as soon as I do >>> start_date = date(1983, 12, 23) >>> start_date.replace(month=start_date.month+1) Traceback (most recent call last): File "<stdin>", line 1, in <module> ValueError: month must be in 1..12 How can I keep adding months which increments the year when new month is added to December?

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