Search Results

Search found 39999 results on 1600 pages for 'php session'.

Page 109/1600 | < Previous Page | 105 106 107 108 109 110 111 112 113 114 115 116  | Next Page >

  • Pass a variable from the source file to an included file in PHP

    - by Alpha1
    For my website I want to store the general format of the site in a single PHP file in a single location, and each of the different pages content in the local location of the page. I then want to pass the title and content address to the included file via a variable. However I can't get the included format file to read the variables storing the title and content data. AKA, the called file for the individual page would be: <?php $title = 'Some Title'; $source_file = 'content.php'; readfile('http:...../format.php'); ?> The format file would be: <html> ... <title> <?php echo $title; ?> </title> ... <?php include($source_file); ?> ... I recall reading somewhere I need to include something to get the variables at the start of the format file, however I can't remember what it is or find where I found that information.

    Read the article

  • How to automatically open a session after a Windows 2003 SP2 reboot ?

    - by Fredv
    Hi, i'm using a Windows 2003 Server. I have a session with my username on it and i have a windows application (not service) opened on it. I want this application to always be running. The problem is, when Security updates force Windows to reboot, my session is closed and i need to reconnect to the session to get my application working again .. How can i do to automaticaly force the opening of my user's session upon server's reboot ? (application launch is in the startup of my session) Thanks

    Read the article

  • How to avoid notice in php when one of the conditions is not true

    - by user225269
    I've notice that when one of the two conditions in a php if statement is not true. You get an undefined index notice for the statement that is not true. And the result in my case is a distorted web page. For example, this code: <?php session_start(); if (!isset($_SESSION['loginAdmin']) && ($_SESSION['loginAdmin'] != '')) { header ("Location: loginam.php"); } else { include('head2.php'); } if (!isset($_SESSION['login']) && ($_SESSION['login'] != '')) { header ("Location: login.php"); } else { include('head3.php'); } ?> If one of the if statements is not true. The one that is not true will give you a notice that it is undefined. In my case it says that the session 'login' is not defined. If session 'LoginAdmin' is used. What can you recommend that I would do in order to avoid these undefined index notice.

    Read the article

  • Unable to Get values from Web Form to a PHP Class to Display

    - by kentrenholm
    I am having troubles getting the value from my variables submitted via a web form using a PHP class file. Here is my structure of the web page: Order Form Page Process.php Page Book.php Page I can easily get the user data entered (on Order Form Page), process, and display it on the Process.php page. The issue is that I must create a Book class and print the details of the data using the Book class. I have an empty constructor printing out "created" so I know my constructor is being called. I also am able to print the word "title" so I know I can print to the screen by using the Book class. My issue is that I can't get values in my variables in the Book class. Here is my variable declaration: private $title; Here is my printDetails function: public function printDetails () { echo "Title: " . $this->title . "<br />"; } Here is my new instance of the book class: $bookNow = new book; Here are my get and set functions: function __getTitle($title) { return $this->$title; } function __setTitle($title,$value) { $this->$title = $value; } I do have four other variables that I'm looking to display as well. Each of those have their own variable declaration, a line in printDetails, and their own setter and getter. Lastly, I also have a call to the Book class in my process PHP. It looks like this: function __autoload($book) { include $book . '.php'; } $bookNow = new book(); Any help, much appreciated. It must be something so very small (I'm hoping).

    Read the article

  • JQuery to PHP function and back Ajaxed

    - by Xaris
    Hi all, i have a set of php function that i want to call on different events mostly onclick with jquery async (ajax). The first function is called on load $(document).ready(function() { $("#div2").hide('slow'); $("#div1").empty().html('<img src="ajax-loader.gif" />'); $.ajax( { type: "POST", url: "WebFunctions.php", data: {'func':'1'}, success: function(html) { $("#div1").show('slow').html(html) } }); The Data: {'func':'1'} -- is a switch statement on the php side switch($_POST['func']) { case '1': getParents(); break; case '2': getChilds(params); break; case '3': getChildObjects(params); break; default: } "This functions are calls to a soap server" <-- irrelevant. So when that function finishes i get an array which contains IDs and Names. I echo the names but i want the ID for reference so when i click on the echoed name i can call an other php function with parameter the ID of the name... How do i get rid of the switch statement?? How do i call properly php functions and pass params to it??? How can i save this IDs so when i click on an item with that id an other php function is called?? Plz feel free to ask any question, any answer is welcome :)

    Read the article

  • How to load data on option box in php

    - by user225269
    I'm having trouble loading the mysql data on the html form option box using php. Here's my code: <?php $con = mysql_connect("localhost","myuname","mypassword"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $idnum= mysql_real_escape_string($_POST['idnum']); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" type="text" maxlength="5" value="<?php echo $row["IDNO"]; ?>" readonly="readonly"></td> </tr> My problem is loading it here: <td><font size="2">Gender</td> <td> <select name="gender" id="gender"> <font size="2"> <option value="<?php echo $line['IDNO']; ?> "><?php $line['GENDER'] ; ?></option> </select></td></td> The table looks like this: IDNO | GENDER 123 | M 321 | F What am I supposed to do?To load the exact gender corresponding to the IDNO?

    Read the article

  • Include php code within echo from a random text

    - by lisa
    I want to display a php code at random and so for I have <?php // load the file that contain thecode $adfile = "code.txt"; $ads = array(); // one line per code $fh = fopen($adfile, "r"); while(!feof($fh)) { $line = fgets($fh, 10240); $line = trim($line); if($line != "") { $ads[] = $line; } } // randomly pick an code $num = count($ads); $idx = rand(0, $num-1); echo $ads[$idx]; ?> The code.txt has lines like <?php print insert_proplayer( array( "width" => "600", "height" => "400" ), "http://www.youtube.com/watch?v=xnPCpCVepCg"); ?> Proplayer is a wordpress plugin that displays a video. The codes in code.txt work well, but not when I use the pick line from code.txt. Instead of the full php line I get: "width" => "600", "height" => "400" ), "http://www.youtube.com/watch?v=xnPCpCVepCg"); ?> How can I make the echo show the php code, rather than a txt version of the php code?

    Read the article

  • creating new instance fails PHP

    - by as3isolib
    I am relatively new to PHP and having some decent success however I am running into this issue: If I try to create a new instance of the class GenericEntryVO, I get a 500 error with little to no helpful error information. However, if I use a generic object as the result, I get no errors. I'd like to be able to cast this object as a GenericEntryVO as I am using AMFPHP to communicate serialize data with a Flex client. I've read a few different ways to create constructors in PHP but the typical 'public function Foo()' for a class Foo was recommended for PHP 5.4.4 //in my EntryService.php class public function getEntryByID($id) { $link = mysqli_connect("localhost", "root", "root", "BabyTrackingAppDB"); if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } $query = "SELECT * FROM Entries WHERE id = '$id' LIMIT 1"; if ($result = mysqli_query($link, $query)) { // $entry = new GenericEntryVO(); this is where the problem lies! while ($row = mysqli_fetch_row($result)) { $entry->id = $row[0]; $entry->entryType = $row[1]; $entry->title = $row[2]; $entry->description = $row[3]; $entry->value = $row[4]; $entry->created = $row[5]; $entry->updated = $row[6]; } } mysqli_free_result($result); mysqli_close($link); return $entry; } //my GenericEntryVO.php class <?php class GenericEntryVO { public function __construct() { } public $id; public $title; public $entryType; public $description; public $value; public $created; public $updated; // public $properties; } ?>

    Read the article

  • php search database for row

    - by Brenden Morley
    Okay I got code the code to pull data based on a users account number well here is what im using (And yes I know it isnt safe now that is the reason for my post) <?php include('config.php'); $user_info = fetch_user_info($_GET['AccountNumber']); ?> <html> <body> <div> <?php if ($user_info === false){ $Output = 'http://www.MyDomain.Com/'; echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL='.$Output.'">'; }else{ ?> <center> <title><?php echo $user_info['FirstName'], ' ', $user_info['LastName'], ' - ', $user_info['City'], ', ', $user_info['State']; ?> - Name of site</title> So basically what this code is allowing me to do is have a file called Profile.php And when a user visits this this page it will return the data Like this http://MyDomain.com/Profile.php?AccountNumber=50b9c965b7c3b How can I do this securely cause right now its using a get method really unsafe to retive the account number from the url bar.

    Read the article

  • PHP setting cookies in a child class

    - by steve
    I am writing a custom session handler and for the life of me I cannot get a cookie to set in it. I'm not outputting anything to the browser before I set the cookie but it still doesn't work. Its killing me. The cookie will set if I set it in the script I define and call on the session handler with. If necessary I will post code. Any ideas people? <?php /* require the needed classes comment out what is not needed */ require_once("classes/sessionmanager.php"); require_once("classes/template.php"); require_once("classes/database.php"); $title=" "; //titlebar of the web browser $description=" "; $keywords=" "; //meta keywords $menutype="default"; //default or customer, customer is elevated $pagetitle="dflsfsf "; //title of the webpage $pagebody=" "; //body of the webpage $template=template::def_instance(); $database=database::def_instance(); $session=sessionmanager::def_instance(); $session->sessions(); session_start(); ?> and this is the one that actually sets the cookie for the session function write($session_id,$session_data) { $session_id = mysql_real_escape_string($session_id); $session_data = mysql_real_escape_string(serialize($session_data)); $expires = time() + 3600; $user_ip = $_SERVER['REMOTE_ADDR']; $bol = FALSE; $time = time(); $newsession = FALSE; $auth = FALSE; $query = "SELECT * FROM 'sessions' WHERE 'expires' > '$time'"; $sessions_result = $this->query($query); $newsession = $this->newsession_check($session_id,$sessions_result); while($sessions_array = mysql_fetch_array($sessions_result) AND $auth = FALSE) { $session_array = $this->strip($session_array); $auth = $this->auth_check($session_array,$session_id); } /* this is an authentic session. build queries and update it */ if($auth = TRUE AND $newsession = FALSE) { $session_data = mysql_real_escape_string($session_data); $update_query1 = "UPDATE 'sessions' SET 'user_ip' = '$user_ip' WHERE 'session_id' = '$session_id'"; $update_query2 = "UPDATE 'sessions' SET 'data' = '$session_data' WHERE 'session_id = '$session_id'"; $update_query3 = "UPDATE 'sessions' SET 'expires' = '$expires' WHERE 'session_id' = '$session_id'"; $this->query($update_query1); $this->query($update_query2); $this->query($update_query3); $bol = TRUE; } elseif($newsession = TRUE) { /* this is a new session, build and create it */ $random_number = $this->obtain_random(); $cookieval = hash("sha512",$random_number); setcookie("rndn",$cookieval); $query = "INSERT INTO sessions VALUES('$session_id','0','$user_ip','$random_number','$session_data','$expires')"; $this->query($query); //echo $cookieval."this is the cookie <<"; $bol = TRUE; } return $bol; }

    Read the article

  • php session_start() error

    - by tooepic
    Hi, i've used a sample found on online and applied it to my code: <?php session_start(); if (isset($_REQUEST["email"])) { $_SESSION["name"] = true; $host = $_SERVER["HTTP_HOST"]; $path = dirname($_SERVER["PHP_SELF"]); $sid = session_name() . "=" . session_id(); header("Location: index.php?$sid"); exit; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> ... ... and rest of the html code When I open this page, I got an error: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 I looked around to resolve this issue and saw few posts about this in this site also, but I just can't get a good grip on this...can't find the answer. Please help. Thanks.

    Read the article

  • PHP object help -> unexpected T_OBJECT_OPERATOR

    - by php-b-grader
    Please help me understand: print gettype(new CustomerObject()) prints: "object" (so it is an object) BUT print gettype((new CustomerObject())->get_customer()); prints: unexpected T_OBJECT_OPERATOR If I do it over two lines it works fine $object = new Customer($order->customer_id); print gettype($object); prints: object $customer = $object->get_customer(); print gettype($customer); prints: array It appears that the lines cannot be joined into a single call. Is this correct? and what is the logic behind that?

    Read the article

  • Strange bug with PHP on Windows 7

    - by chessweb
    This is the configuration: Windows 7 Home Premium, XAMPP 1.7.3 (Apache 2.2.14 , PHP 5.3.1), Firefox 3.6 This is the PHP-code in a file named 'test.php' in htdocs: <?php echo('04556-8978765'); ?> On http://localhost/test.php I would expect to see the string 04556-8978765 in the browser. This is not what happens, though. The string appears for a short time and then it disappears altogether. Firebug shows an empty body-tag. However, when I look at page source, the string is there alright. When I change the string in the echo-statement to e.g. 4556-8978765, everything is fine. Internet Explorer 8 does not show this strange behavior. I could not reproduce this with the same Apache/PHP/Firefox configuration on Windows XP. '04556-8978765' is by no means unique. The couple '02065-96047' and '02065-9604' behave exactly the same. Can anybody reproduce this and offer an explanation as to what is going on? PS: If you can not see the string '04556-8978765' in the echo-statement above, look at this post with IE8.

    Read the article

  • extract associative array within an array in php

    - by I Like PHP
    i have an array like this Array ( [0] => Array ( [s_id] => 4 [si_id] => sec_1 [d_id] => dep_4 [s_name] => sec1 [s_location] => LA [s_visibility] => yes [s_created_date] => 1273639343 [s_last_updated_date] => 1273639343 [s_created_by] => someone [s_last_updated_by] => everyone ) ) now i want to extract array[0] into an array... means i want this Array ( [s_id] => 4 [si_id] => sec_1 [d_id] => dep_4 [s_name] => sec1 [s_location] => LA [s_visibility] => yes [s_created_date] => 1273639343 [s_last_updated_date] => 1273639343 [s_created_by] => someone [s_last_updated_by] => everyone ) how do i get above results?

    Read the article

  • please suggest good variable names that represent theirself ( php)

    - by I Like PHP
    Hi all, it may be wrong place to ask this question, but i hope u all programmer must have the interesting naming convention of variables. i have seen many places that some variable names are very good n effective like common variable names $link $db $connect $query $stmt $sql $qry $output $result $list so please suggest me some good names for variable , bcoz all time i have to write $x, $y etc.. if i want to save something instantly on page...that are even not relevant, so please suggest me good variable names

    Read the article

  • curl multiple request session issue

    - by embedded
    I'm using curl multi API for multiple curl requests. first I'm using a single request to login to a site and save the cookie file. then I'm using the curl multi API to get some data from that site. The problem I'm facing is that from some reason the cookie file does not get read and I'm redirecting to the main login page. I must say that this work once in awhile so I can't point what went wrong. Any help would be much appreciated. Thanks

    Read the article

  • Dynamic URL to Stay the Same on all Pages

    - by JCBiggar
    so when my url looks like this: http://mywebsitehere.com/?kw=1 I am using this code below to do stuff with it: <?php if( isset($_GET['kw'] )){ //my div here } ?> It works great, and I am getting exactly what I want on the page. However, any link I click on that page will change the url structure and remove the ?kw=1 . Is there anyway to add the ?kw=1 to every link for that session? I have no clue how to do this? Any ideas or answers would be great! Thanks! Let me know if I need to give more to my question.

    Read the article

  • (php) regexto remove comments but ignore occurances within strings

    - by David
    Hi there, I am writing a comment-stripper and trying to accommodate for all needs here. I have the below stack of code which removes pretty much all comments, but it actually goes too far. A lot of time was spent trying and testing and researching the regex patterns to match, but I don't claim that they are the best at each. My problem is that I also have situation where I have 'PHP comments' (that aren't really comments' in standard code, or even in PHP strings, that I don't actually want to have removed. Example: <?php $Var = "Blah blah //this must not comment"; // this must comment. ?> What ends up happening is that it strips out religiously, which is fine, but it leaves certain problems: <?php $Var = "Blah blah ?> Also: will also cause problems, as the comment removes the rest of the line, including the ending ? See the problem? So this is what I need... Comment characters within '' or "" need to be ignored PHP Comments on the same line, that use double-slashes, should remove perhaps only the comment itself, or should remove the entire php codeblock. Here's the patterns I use at the moment, feel free to tell me if there's improvement I can make in my existing patterns? :) $CompressedData = $OriginalData; $CompressedData = preg_replace('!/\*.*?\*/!s', '', $CompressedData); // removes /* comments */ $CompressedData = preg_replace('!//.*?\n!', '', $CompressedData); // removes //comments $CompressedData = preg_replace('!#.*?\n!', '', $CompressedData); // removes # comments $CompressedData = preg_replace('/<!--(.*?)-->/', '', $CompressedData); // removes HTML comments Any help that you can give me would be greatly appreciated! :)

    Read the article

  • How can I secure my $_GETs in PHP?

    - by ggfan
    My profile.php displays all the user's postings,comments,pictures. If the user wants to delete, it sends the posting's id to the remove.php so it's like remove.php?action=removeposting&posting_id=2. If they want to remove a picture, it's remove.php?action=removepicture&picture_id=1. Using the get data, I do a query to the database to display the info they want to delete and if they want to delete it, they click "yes". So the data is deleted via $POST NOT $GET to prevent cross-site request forgery. My question is how do I make sure the GETs are not some javascript code, sql injection that will mess me up. here is my remove.php //how do I make $action safe? //should I use mysqli_real_escape_string? //use strip_tags()? $action=trim($_GET['action']); if (($action != 'removeposting') && ($action != 'removefriend') && ($action != 'removecomment')) { echo "please don't change the action. go back and refresh"; header("Location: index.php"); exit(); } if ($action == 'removeposting') { //get the info and display it in a form. if user clicks "yes", deletes } if ($action =='removepicture') { //remove pic } I know I can't be 100% safe, but what are some common defenses I can use. EDIT Do this to prevent xss $action=trim($_GET['action']); htmlspecialchars(strip_tags($action)); Then when I am 'recalling' the data back via POST, I would use $posting_id = mysqli_real_escape_string($dbc, trim($_POST['posting_id']));

    Read the article

  • JavaScript two-dimensional Array to PHP

    - by vi
    Hi I have to send a two-dimensional JavaScript Array to a PHP page. Indeed, I'm working on a form-builder, in which the user can add or remove fields. These fields are added (or removed) using JavaScript (jQuery). When the user is done and hit a 'publish' button, I have to get all the fields concerned and send them to a PHP page which would build a real form with it. I found a way to do it but I'm pretty sure it's not very clean : addedFields = new Array(); $("#add-info .field").each(function() { addedFields.push(new Array($(this).find('.name').val(), $(this).find('.type').val(), $(this).find('.size').val())); }); Basically, the ".field" class objects are <tr> and the ".name", ".type" and ".size" objects are inputs. So I get an array of [name, type, size], then I convert it into a string using addedFields = addedFields.join(";"); Finally, I go to the PHP form that way ; document.location.href = "create.php?addedfields=" + addedFields; Concerning the PHP code, I create a PHP array using the explode() function: $addedFields = explode(";", $_GET['addedfields']); and then I use it again for each element in the array: foreach ($addedFields as $field) { $field = explode(",", $field); echo "<li>Field with name : '$field[0]', of '$field[1]' type and with a size of $field[2]"; }

    Read the article

  • IE Kills Session After Exporting CSV [CakePHP]

    - by OneBlueMidnight
    i have a web application that export CSV and i logged in as admin but what happened during the exportation the IE opens a new tab and export the CSV but what happens next when you click any of the link on the web app you will automatically logout! This only happen on IE. here is the header i used: header("Content-type:application/vnd.ms-excel"); header("Content-disposition:attachment;filename=".$this->filename); I am using cakephp 1.3.x.x TIA :D

    Read the article

< Previous Page | 105 106 107 108 109 110 111 112 113 114 115 116  | Next Page >