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  • how to subtract circle from an arbitrary polygon

    - by George
    Given an arbitary polygon with vertices stored in either clockwise/counterclockwise fashion (depicted as a black rectangle in the diagram), I need to be able to subtract an arbitrary number of circles (in red on the diagram) from that polygon. Removing a circle could possibly split the polygon into two seperate polygons (as depicted by the second line in the diagram). I'm not sure where to start. http://www.freeimagehosting.net/image.php?89a0276d9d.jpg

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  • Great programming quotes

    - by epatel
    There are a lot of great programming quotes out there. Which do you like? Today (Sept 12, 2008) I heard a new one from a friend, Lars-Gunnar, he said "Gud finns i Emacs" (in Swedish). This basically means "God is in Emacs". Still laughing about it here :) What he meant was that a function "gud is grand-unified-debugger" is in Emacs. A great one I think all programmers should know is The Three Great Virtues of a Programmer.

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  • Spinning a circle in J2ME using a Canvas.

    - by JohnQPublic
    Hello all! I have a problem where I need to make a multi-colored wheel spin using a Canvas in J2ME. What I need to do is have the user increase the speed of the spin or slow the spin of the wheel. I have it mostly worked out (I think) but can't think of a way for the wheel to spin without causing my cellphone to crash. Here is what I have so far, it's close but not exactly what I need. class MyCanvas extends Canvas{ //wedgeOne/Two/Three define where this particular section of circle begins to be drawn from int wedgeOne; int wedgeTwo; int wedgeThree; int spinSpeed; MyCanvas(){ wedgeOne = 0; wedgeTwo = 120; wedgeThree = 240; spinSpeed = 0; } //Using the paint method to public void paint(Graphics g){ //Redraw the circle with the current wedge series. g.setColor(255,0,0); g.fillArc(getWidth()/2, getHeight()/2, 100, 100, wedgeOne, 120); g.setColor(0,255,0); g.fillArc(getWidth()/2, getHeight()/2, 100, 100, wedgeTwo, 120); g.setColor(0,0,255); g.fillArc(getWidth()/2, getHeight()/2, 100, 100, wedgeThree, 120); } protected void keyPressed(int keyCode){ switch (keyCode){ //When the 6 button is pressed, the wheel spins forward 5 degrees. case KEY_NUM6: wedgeOne += 5; wedgeTwo += 5; wedgeThree += 5; repaint(); break; //When the 4 button is pressed, the wheel spins backwards 5 degrees. case KEY_NUM4: wedgeOne -= 5; wedgeTwo -= 5; wedgeThree -= 5; repaint(); } } I have tried using a redraw() method that adds the spinSpeed to each of the wedge values while(spinSpeed0) and calls the repaint() method after the addition, but it causes a crash and lockup (I assume due to an infinite loop). Does anyone have any tips or ideas how I could automate the spin so you do not have the press the button every time you want it to spin? (P.S - I have been lurking for a while, but this is my first post. If it's too general or asking for too much info (sorry if it is) and I either remove it or fix it. Thank you!)

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  • How to find 2D grid cells swept by a moving circle?

    - by Nevermind
    I'm making a game based on a 2D grid, with some cells passable and some not. Dynamic objects can move continuously, independent of the grid, but need to collide with impassable cells. I wrote an algorithm to trace a ray against the grid, that gives me all cells that ray intersects. However, actual object are not point-sized; I'm currently representing them as circles. But I can't figure out an effective algorithm to trace a moving circle. Here's a picture of what I need: The numbers show in what order the circle collides with grid cells. Does anybody know the algorithm to find these collisions? Preferably in C#. Update The circle can be bigger than a single grid cell.

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  • Ubuntu - wireless connection works great but wired is totally dead

    - by Dan
    I am running Ubuntu 10.04 on my Acer Aspire One netbook. The wireless connection works great, but the wired is totally dead. When I plug the Ethernet wire, the little led next to the port doesn't blink. If I do ifconfig, this is the output: lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:1659 errors:0 dropped:0 overruns:0 frame:0 TX packets:1659 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:132304 (132.3 KB) TX bytes:132304 (132.3 KB) wlan0 Link encap:Ethernet HWaddr 18:f4:6a:65:48:1f inet addr:192.168.1.7 Bcast:192.168.1.255 Mask:255.255.255.0 inet6 addr: fe80::1af4:6aff:fe65:481f/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:94823 errors:0 dropped:0 overruns:0 frame:0 TX packets:81390 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:93028474 (93.0 MB) TX bytes:18002558 (18.0 MB) There is no eth0. Is that normal? In the "Network Connections" GUI there is an entry "Wired connection 1", its "MAC address" field is blank. How can I make the wired connection work?

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  • Moving a sprite around the circumference of a circle in Cocos2d-iPhone

    - by CircleOfLife
    I am new to Cocos2d. I have taken a look at the documentation at it looks pretty simple compared to what you need to do using basic Iphone classes such as UIAnimation etc. I want to move a Sprite (eg. Bird, Plane or Car) around the center of a circle around its circumference, smoothly so that even the sprite rotates accordingly. How is this possible in Cocos2d? It would be very helpful if someone can post some basic code. Thanks.

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  • Problem trying to move a CCSprite circle in Cocos2d

    - by thyrgle
    Hi, So I am trying to move a CCSprite (which has the picture of a circle and is 32 by 32 pixels) with ccTouchesBegan. I have tried the following: -(void) ccTouchesBegan:(UITouch *)touch withEvent:(UIEvent *)event { CGPoint location = [touch locationInView:touch.view]; if ((location.x <= L1Circle1.position.x + 32 && location.x >= L1Circle2.position.x - 32) && (location.y <= L1Circle1.position.y + 32 || location.y >= L1Circle2.position.y - 32)) { L1Circle1.position = ccp(location.x, location.y); } } But, when I touch the screen in the simulator nothing happens... What am I doing wrong?

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  • Python: writing a program to compute the area of a circle and square

    - by user1672504
    I have a question with an assignment. I'm not sure how to write this program and I really need help! Could someone help me with this? This is the assignment: Write a program that asks the user to enter two values: an integer choice and a real number x. If choice is 1, compute and display the area of a circle of radius x. If choice is 2, compute and display the are of a square with sides of length x. If choice is neither 1, nor 2, will display the text Invalid choice. Sample run: Enter choice: 2 Enter x: 8 The area is: 64.0 Sample run: Enter choice: 1 Enter x: 8 The area is: 201.06176 My attempt: choice = input ('Enter Choice:') choice_1 = int (choice) if (choice_1==1): radius = (int) print('Enter x:',radius) pi = 3.14159 area = ( radius ** 2 ) * pi print ( 'The Area is=' , area )

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  • Find most right and left point of a horizontal circle in 3d Vector environment

    - by Olivier de Jonge
    I'm drawing a 3D pie chart that is rendered with in 3D vectors, projected to 2D vectors and then drawn on a Graphics object. I want to calculate the most left and right point of the circle The method to create a vector, draw and project to a 2d vector are below. Anyone knows the answer? public class Vector3d { public var x:Number; public var y:Number; public var z:Number; //the angle that the 3D is viewed in tele or wide angle. public static var viewDist:Number = 700; function Vector3d(x:Number, y:Number, z:Number){ this.x = x; this.y = y; this.z = z; } public function project2DNew():Vector { var p:Number = getPerspective(); return new Vector(p * x, p * y); } public function getPerspective():Number{ return viewDist / (this.z + viewDist); } }

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  • Collision detection of huge number of circles

    - by Tomek Tarczynski
    What is the best way to check collision of huge number of circles? It's very easy to detect collision between two circles, but if we check every combination then it is O(n^2) which definitely not an optimal solution. We can assume that circle object has following properties: -Coordinates -Radius -Velocity -Direction Velocity is constant, but direction can change. I've come up with two solutions, but maybe there are some better solutions. Solution 1 Divide whole space into overlapping squares and check for collision only with circles that are in the same square. Squares needs to overlap so there won't be a problem when circle moves from one square to another. Solution 2 At the beginning distances between every pair of circles need to be calculated. If the distance is small then these pair is stored in some list, and we need to check for collision in every update. If the distance is big then we store after which update there can be a collision (it can be calculated because we know the distance and velocitites). It needs to be stored in some kind of priority queue. After previously calculated number of updates distance needs to be checked again and then we do the same procedure - put it on the list or again in the priority queue.

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  • How do I know when to increase or decrease angle to get a specific angle?

    - by Thomas
    Hi. I am programming a game and I have come to a very hard spot. Basically I have a circle and I have 2 angles on this circle. Angle 1 (A) is a point I want angle 2 (B) to go to. During my game every frame I need to check weither or not to increase or decrease my angle value by a certain amount (speed) to eventually reach the first angle. My question is how do I do this? I tried doing this but I don't seem to be doing it right. bool increase = false; float B = [self radiansToDegrees:tankAngle]; float A = [self radiansToDegrees:tankDestinationAngle]; float newAngle = B; if(B < A) { float C = B - (360 - A); float D = A - B; if(C < D) increase = false; else increase = true; } else if(B A) { float C = B - A; float D = A - (360 - B); if(C < D) increase = false; else increase = true; } if(increase) { newAngle += 1.0; } else { newAngle -= 1.0; } if(newAngle 360.0) { newAngle = 0 + (newAngle - 360.0); } else if(newAngle < 0.0) { newAngle = 360 + newAngle; } if(newAngle == 0) newAngle = 360; newAngle = [self degreesToRadians:newAngle]; [self setTanksProperPositionRotation:newAngle]; The basic effect I am trying to achieve is when the user makes a new point, which would be angle 1, angle 2 would move towards angle 1 choosing the fastest direction. I think I have spent around 4 hours trying to figure this out.

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  • how to rotate the Circle in DrawRect?

    - by senthilmuthu
    HI, i want to draw a circle in DrawRect through context like pie chart(took from tutorial) thorugh UITouch? i have given the code as follows,how can i rotate ? any help please? define PI 3.14159265358979323846 define snapshot_start 360 define snapshot_finish 360 static inline float radians(double degrees) { return degrees * PI / 180; } - (void)drawRect:(CGRect)rect { // Drawing code CGRect parentViewBounds = self.bounds; CGFloat x = CGRectGetWidth(parentViewBounds)/2; CGFloat y = CGRectGetHeight(parentViewBounds)*0.55; // Get the graphics context and clear it CGContextRef ctx = UIGraphicsGetCurrentContext(); CGContextClearRect(ctx, rect); // define stroke color CGContextSetRGBStrokeColor(ctx, 1, 1, 1, 1.0); // define line width CGContextSetLineWidth(ctx, 4.0); // need some values to draw pie charts double snapshotCapacity =20; double rawCapacity = 100; double systemCapacity = 1; int offset = 5; double pie1_start = 315.0; double pie1_finish = snapshotCapacity *360.0/rawCapacity; double system_finish = systemCapacity*360.0/rawCapacity; CGContextSetFillColor(ctx, CGColorGetComponents( [[UIColor greenColor] CGColor])); CGContextMoveToPoint(ctx, x+2*offset, y); CGContextAddArc(ctx, x+2*offset, y, 100, radians(snapshot_start), radians(snapshot_start+snapshot_finish), 0); CGContextClosePath(ctx); CGContextFillPath(ctx); // system capacity CGContextSetFillColor(ctx, CGColorGetComponents( [[UIColor colorWithRed:15 green:165/255 blue:0 alpha:1 ] CGColor])); CGContextMoveToPoint(ctx, x+offset,y); CGContextAddArc(ctx, x+offset, y, 100, radians(snapshot_start+snapshot_finish+offset), radians(snapshot_start+snapshot_finish+system_finish), 0); CGContextClosePath(ctx); CGContextFillPath(ctx); /* data capacity */ CGContextSetFillColor(ctx, CGColorGetComponents( [[UIColor colorWithRed:99/255 green:184/255 blue:255/255 alpha:1 ] CGColor])); CGContextMoveToPoint(ctx, x, y); CGContextAddArc(ctx, x, y, 100, radians(snapshot_start+snapshot_finish+system_finish+offset), radians(snapshot_start), 0); CGContextClosePath(ctx); CGContextFillPath(ctx); }

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  • rotating a circle in UIView?

    - by senthilmuthu
    HI, i want to draw a circle in DrawRect through context like pie chart(took from tutorial) thorugh UITouch? i have given the code as follows,how can i rotate ? any help please? define PI 3.14159265358979323846 define snapshot_start 360 define snapshot_finish 360 static inline float radians(double degrees) { return degrees * PI / 180; } - (void)drawRect:(CGRect)rect { // Drawing code CGRect parentViewBounds = self.bounds; CGFloat x = CGRectGetWidth(parentViewBounds)/2; CGFloat y = CGRectGetHeight(parentViewBounds)*0.55; // Get the graphics context and clear it CGContextRef ctx = UIGraphicsGetCurrentContext(); CGContextClearRect(ctx, rect); // define stroke color CGContextSetRGBStrokeColor(ctx, 1, 1, 1, 1.0); // define line width CGContextSetLineWidth(ctx, 4.0); // need some values to draw pie charts double snapshotCapacity =20; double rawCapacity = 100; double systemCapacity = 1; int offset = 5; double pie1_start = 315.0; double pie1_finish = snapshotCapacity *360.0/rawCapacity; double system_finish = systemCapacity*360.0/rawCapacity; CGContextSetFillColor(ctx, CGColorGetComponents( [[UIColor greenColor] CGColor])); CGContextMoveToPoint(ctx, x+2*offset, y); CGContextAddArc(ctx, x+2*offset, y, 100, radians(snapshot_start), radians(snapshot_start+snapshot_finish), 0); CGContextClosePath(ctx); CGContextFillPath(ctx); // system capacity CGContextSetFillColor(ctx, CGColorGetComponents( [[UIColor colorWithRed:15 green:165/255 blue:0 alpha:1 ] CGColor])); CGContextMoveToPoint(ctx, x+offset,y); CGContextAddArc(ctx, x+offset, y, 100, radians(snapshot_start+snapshot_finish+offset), radians(snapshot_start+snapshot_finish+system_finish), 0); CGContextClosePath(ctx); CGContextFillPath(ctx); /* data capacity */ CGContextSetFillColor(ctx, CGColorGetComponents( [[UIColor colorWithRed:99/255 green:184/255 blue:255/255 alpha:1 ] CGColor])); CGContextMoveToPoint(ctx, x, y); CGContextAddArc(ctx, x, y, 100, radians(snapshot_start+snapshot_finish+system_finish+offset), radians(snapshot_start), 0); CGContextClosePath(ctx); CGContextFillPath(ctx); }

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  • moving image to bounce or rotate in a circle

    - by BlueMonster
    I found this small application that i've been playing around with for the past little while. I was wondering, if i wanted to simply rotate the image in a circle? or make the entire image just bounce up and down, how would i modify this program to do so? Everything i've tried will just stretch the image - even if i do get it to move to the left or to the right. Any ideas on what i can do? Code is below public partial class Form1 : Form { private int width = 15; private int height = 15; Image pic = Image.FromFile("402.png"); private Button abort = new Button(); Thread t; public Form1() { abort.Text = "Abort"; abort.Location = new Point(190, 230); abort.Click += new EventHandler(Abort_Click); Controls.Add(abort); SetStyle(ControlStyles.DoubleBuffer| ControlStyles.AllPaintingInWmPaint| ControlStyles.UserPaint, true); t = new Thread(new ThreadStart(Run)); t.Start(); } protected void Abort_Click(object sender, EventArgs e) { t.Abort(); } protected override void OnPaint( PaintEventArgs e ) { Graphics g = e.Graphics; g.DrawImage(pic, 10, 10, width, height); base.OnPaint(e); } public void Run() { while (true) { for(int i = 0; i < 200; i++) { width += 5; Invalidate(); Thread.Sleep(30); } } } }

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  • How to get location of sprite placed on rotating circle in cocos2d android?

    - by Real_steel4819
    I am developing a game using cocos2d and i got stuck here when finding location of sprite placed on rotating circle on background, so that when i hit at certain position on circle its not getting hit at wanted position,but its going away from it and placing target there.I tried printing the position of hit on spriteMoveFinished() and ccTouchesEnded(). Its giving initial position and not rotated position. CGPoint location = CCDirector.sharedDirector().convertToGL(CGPoint.ccp(event.getX(), event.getY())); This is what i am using to get location.

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  • If I project a sphere in 3D will it be a circle?

    - by yuumei
    Assuming I have infinite vertices to represent the sphere, if I project the sphere from any position/scale in 3D to 2D, will it be a circle? I know it will not be a circle on the screen, because of scaling and different resolutions. But do field of view and aspect ratio effect the results? Edit: Sorry yes, I am talking about perspective projection. Seems the answer is no then, perspective will distort the sphere. Thanks!

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  • Multiple circles -> One Polygon?

    - by Josh
    Using Google Maps API v3, I was able to create multiple google.maps.Circle objects on my map. However, I now need to "connect" them somehow. I have the following map with multiple circles: I now need to get it to look something like this: I've looked all over the Internet for solutions, but to no avail. Any ideas?

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  • Great GUI for Apache2?

    - by ajsie
    I wonder if there are great GUI management tools for Apache so you dont have to manually edit files in VIM. It would be great if you could manage Apache over internet. Any suggestions of such tools?

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  • QuickBox2D poly behaviour vs box or circle

    - by Ben Kanizay
    Hi I've played a little with Box2D before and have just started using QuickBox2D which makes things heaps easier. I am however getting different behaviour with a specific poly shape than I am with a box. All other properties are the same. I've included 3 simple examples and their source below. What I really want to work is Example 1 with both objects as poly. As you can see, it seems like the 'paddle' poly is the one that's failing - the 'ball' (whether it's a poly or circle) just falls straight through it instead of bouncing off as it does with a box 'paddle' object. Would appreciate some help or insight. As I can only post one line at this stage, the swf previews of the 3 examples can be seen here Example 1 source: package { import com.actionsnippet.qbox.QuickBox2D; import com.actionsnippet.qbox.QuickObject; import flash.display.MovieClip; public class Eg1 extends MovieClip { private var sim:QuickBox2D; private var paddle:QuickObject; private var ball:QuickObject; public function Eg1() { this.sim = new QuickBox2D(this); this.paddle = this.sim.addPoly({ x:13, y:19, angle:0, density:0, draggable:false, isBullet:true, verts:[[-3.84,-0.67,-2.84,-1,-2.17,-0.33,2.17,-0.33,2.84,-1,3.84,-0.67,2.84,1,-2.51,1]] }); this.ball = this.sim.addPoly({ x:13, y:1, restitution:1, friction:1, draggable:false, isBullet:true, verts:[[-0.34,-1,0.34,-1,0.67,-0.33,0.67,0.33,0.34,1,-0.34,1,-0.67,0.33,-0.67,-0.33]] }); this.sim.start(); } }} Example 2 source: package { import com.actionsnippet.qbox.QuickBox2D; import com.actionsnippet.qbox.QuickObject; import flash.display.MovieClip; public class Eg2 extends MovieClip { private var sim:QuickBox2D; private var paddle:QuickObject; private var ball:QuickObject; public function Eg2() { this.sim = new QuickBox2D(this); this.paddle = this.sim.addBox({ x:13, y:19, angle:0, density:0, draggable:false, isBullet:true, width:8 }); this.ball = this.sim.addPoly({ x:13, y:1, restitution:1, friction:1, draggable:false, isBullet:true, verts:[[-0.34,-1,0.34,-1,0.67,-0.33,0.67,0.33,0.34,1,-0.34,1,-0.67,0.33,-0.67,-0.33]] }); this.sim.start(); } }} Example 3 source: package { import com.actionsnippet.qbox.QuickBox2D; import com.actionsnippet.qbox.QuickObject; import flash.display.MovieClip; public class Eg3 extends MovieClip { private var sim:QuickBox2D; private var paddle:QuickObject; private var ball:QuickObject; public function Eg3() { this.sim = new QuickBox2D(this); this.paddle = this.sim.addPoly({ x:13, y:19, angle:0, density:0, draggable:false, isBullet:true, verts:[[-3.84,-0.67,-2.84,-1,-2.17,-0.33,2.17,-0.33,2.84,-1,3.84,-0.67,2.84,1,-2.51,1]] }); this.ball = this.sim.addCircle({ x:13, y:1, restitution:1, friction:1, draggable:false, isBullet:true, radius:1 }); this.sim.start(); } }}

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  • Where can I find great Windows XP themes?

    - by Jon
    For the last couple of years I have used the Zune theme for Windows XP. Once the background picture is removed it is a very classy look for XP. Is there a place on the web where I can find other Windows themes are available to download and try? Do you have any recommendations for individual themes to use?

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  • The great Vanishing Act of INetMgr.exe on my Windows 7 x64 system

    - by marc_s
    I'm facing an odd issue with the IIS Manager on Windows 7 (x64). At home, I have Win7 Professional, and when I check my IIS manager icon in the start menu, I see it links to %windir%\system32\inetsrv\InetMgr.exe When I launch this from the command line, it works like a charm. At work, however, I have Windows 7 Enterprise (x64), and when I check my link in the start menu, the entry is exactly the same. If I click on it - it works like a charm. Now if I'd like to launch it from the command line (cmd.exe or TakeCommand), however - the file just isn't there - a DIR %windir%\system32\inetsrv\*.exe shows a number of files, including a "inetmgr6.exe" - but no "inetmgr.exe" - and of course, I can't launch it either :-( Strangely enough, when I look at the directory %windir%\system32\INetSrv in Windows Explorer or Windows Powershell, I SEE the INetMgr.exe file and I can launch it - no problem. What the **** is going on here? How can I find the INetMgr.exe from my classic command line and launch it from there?? UPDATE: ok, some updates. On my work laptop, the INetMgr.exe file appears to really be located in a directory called c:\windows\syswow64\inetsrv (I'm recalling from memory, so don't quote me on the directory name - something like that). I can see this if I search for it in e.g. Powershell or Windows 7 Explorer. However, from a "classic" command line like cmd.exe, it appears to be in c:\windows\system32\inetsrv ..... hmmm.... trouble is - even though I now know where the file really is, I cannot access that directory from my classic command line - not even if I'm running cmd.exe as admin with elevated privileges....... so I know where the file is, but that still doesn't solve my problem :-(

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