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  • Transmission-daemon not picking up on watch directory

    - by Mild Fuzz
    Trying to get my transmission-daemon to pick up files from a dropbox folder, to make remote starting easier (it's a headless system). As far as I can tell, the settings.json file is as expected, but none of the files I place in the folder get picked up. I have checked that dropbox is syncing correctly. Here is the whole settings.json file, but the relevant lines are included below: "watch-dir": "/home/john/Dropbox/torrents", "watch-dir-enabled": true Update It appears to be a permissions issue. From /var/log/syslog: Unable to watch "/home/john/Dropbox/torrents": Permission denied (watch.c:79) I have tried stopping the daemon - sudo service transmission-daemon stop - changing permissions of folder using chown - sudo chown -R john /home/john/Dropbox/torrents - restarting daemon - sudo service transmission-daemon start Same result, however Update 2 Permissions for the folder are: drwsrwsrwx 2 john debian-transmission 4096 2012-04-09 19:40

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  • How to calculate running totals of subsets of data in a table

    - by John
    I have 4 columns: Name, Week, Batch and Units Produced (Cols, A,B,C,D). In column E, I need to keep running totals based on name and week. When the week changes for the same person, restart the total. Fred, 12, 4001, 129.0 Answer in e: 129.0 Fred, 12, 4012, 234.0 Answer in e: 363.0 Fred, 13, 4023, 12.0 Answer in e: 12.0 John, 12, 4003, 420.0 Answer in e: 420.0 John, 13, 4021, 1200.0 Answer in e: 1200.0 John, 13, 4029, 120.0 Answer in e: 1320.0 I need to be able to copy the formula to over 1000 rows.

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  • SQL Joining on a one-to-many relationship

    - by Harley
    Ok, here was my original question; Table one contains ID|Name 1 Mary 2 John Table two contains ID|Color 1 Red 1 Blue 2 Blue 2 Green 2 Black I want to end up with is ID|Name|Red|Blue|Green|Black 1 Mary Y Y 2 John Y Y Y It seems that because there are 11 unique values for color and 1000's upon 1000's of records in table one that there is no 'good' way to do this. So, two other questions. Is there an efficient way to query to get this result? I can then create a crosstab in my application to get the desired result. ID|Name|Color 1 Mary Red 1 Mary Blue 2 John Blue 2 John Green 2 John Black If I wanted to limit the number of records returned how could I do a query to do something like this? Where ((color='blue') AND (color<>'red' OR color<>'green')) So using the above example I would then get back ID|Name|Color 1 Mary Blue 2 John Blue 2 John Black I connect to Visual FoxPro tables via ADODB to use SQL. Thanks!

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  • Simple Select Statement on MySQL Database Hanging

    - by AlishahNovin
    I have a very simple sql select statement on a very large table, that is non-normalized. (Not my design at all, I'm just trying to optimize while simultaneously trying to convince the owners of a redesign) Basically, the statement is like this: SELECT FirstName, LastName, FullName, State FROM Activity Where (FirstName=@name OR LastName=@name OR FullName=@name) AND State=@state; Now, FirstName, LastName, FullName and State are all indexed as BTrees, but without prefix - the whole column is indexed. State column is a 2 letter state code. What I'm finding is this: When @name = 'John Smith', and @state = '%' the search is really fast and yields results immediately. When @name = 'John Smith', and @state = 'FL' the search takes 5 minutes (and usually this means the web service times out...) When I remove the FirstName and LastName comparisons, and only use the FullName and State, both cases above work very quickly. When I replace FirstName, LastName, FullName, and State searches, but use LIKE for each search, it works fast for @name='John Smith%' and @state='%', but slow for @name='John Smith%' and @state='FL' When I search against 'John Sm%' and @state='FL' the search finds results immediately When I search against 'John Smi%' and @state='FL' the search takes 5 minutes. Now, just to reiterate - the table is not normalized. The John Smith appears many many times, as do many other users, because there is no reference to some form of users/people table. I'm not sure how many times a single user may appear, but the table itself has 90 Million records. Again, not my design... What I'm wondering is - though there are many many problems with this design, what is causing this specific problem. My guess is that the index trees are just too large that it just takes a very long time traversing the them. (FirstName, LastName, FullName) Anyway, I appreciate anyone's help with this. Like I said, I'm working on convincing them of a redesign, but in the meantime, if I someone could help me figure out what the exact problem is, that'd be fantastic.

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  • Chinese footwear retailer Daphne on choosing Oracle Retail solutions

    - by user801960
    In January, leading Chinese footwear brand Daphne announced that they had chosen Oracle Retail as a solution provider for its expansion strategy. We were delighted to host Michael Hu, Chief Operations Officer of Daphne, at our exclusive Retail Exchange event in New York in January. We interviewed Michael about Daphne, Daphne's plans for the future and how Oracle's solutions will play a role in that future. The video is below. We are very grateful to Michael for taking the time to speak to us. To find out more about how Daphne is using Oracle, see the full press release HERE. To find out more about Oracle Retail solutions and how Oracle Retail can help your business, visit http://www.oracle.com/oms/retail/index.html

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  • Is adding users to the group www-data safe on Debian?

    - by John
    Many PHP applications do self-configuration and self-updating. This requires apache to have write access to the PHP files. While chgrp'ing them all to www-data appears like a good practice to avoid making them world writable, I also wish to allow users to create new files and edit existing one. Is adding users to the group www-data safe on Debian? For example: 775 root www-data /var/www 644 john www-data /var/www/johns_php_application.php 660 john www-data /var/www/johns_php_applications_configuration_file

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  • Handwritten linked list is segfaulting and I don't understand why

    - by Born2Smile
    Hi I was working on a bit of fun, making an interface to run gnuplot from within c++, and for some reason the my linked list implementation fails. The code below fails on the line plots-append(&plot). Stepping through the code I discovered that for some reason the destructor ~John() is called immediately after the constructor John(), and I cannot seem to figure out why. The code included below is a stripped down version operating only on Plot*. Originally I made the linked list as a template class. And it worked fine as ll<int and ll<char* but for some reason it fails as ll<Plot*. Could youp please help me figure out why it fails? and perhaps help me understand how to make it work? In advance: Thanks a heap! //B2S #include <string.h class Plot{ char title[80]; public: Plot(){ } }; class Link{ Plot* element; Link* next; Link* prev; friend class ll; }; class ll{ Link* head; Link* tail; public: ll(){ head = tail = new Link(); head-prev = tail-prev = head-next = tail-next = head; } ~ll(){ while (head!=tail){ tail = tail-prev; delete tail-next; } delete head; } void append(Plot* element){ tail-element = element; tail-next = new Link(); tail-next-prev = tail; tail-next = tail; } }; class John{ ll* plots; public: John(){ plots= new ll(); } ~John(){ delete plots; } John(Plot* plot){ John(); plots-append(plot); } }; int main(){ Plot p; John k(&p); }

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  • SQL Server Distinct Question

    - by RPS
    I need to be able to select only the first row for each name that has the greatest value. I have a table with the following: id name value 0 JOHN 123 1 STEVE 125 2 JOHN 127 3 JOHN 126 So I am looking to return: id name value 1 STEVE 125 2 JOHN 127 Any idea on the MSSQL Syntax on how to perform this operation?

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  • string.Replace does not work for quote

    - by Azhar
    ((string)dt.Rows[i][1]).Replace("'", "\'") I want the result that if any string have quote it change it into slash quote e.g John's - John\'s but the above replace function is not working fine. it results like John\'s but if we change the code to ((string)dt.Rows[i][1]).Replace("'", "\'") it gives the Result like John's does change it anyway.

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  • PHP Find and replace after in a string?

    - by TheBlackBenzKid
    I have some strings which contain the words LIMIT 3, 199 or LIMIT 0, 100. Basically I want to replace the word LIMIT and everything after it in my string. How do I do this in PHP? str_replace only replaces an item and the LIMIT text after is dynamic/ So it could be WHEN JOHN WAS TRYING HIS SQL QUERY, HE FOUND THAT LIMIT, 121 // RETURN WOULD BE WHEN JOHN WAS TRYING HIS SQL QUERY, HE FOUND THAT WHEN JOHN TRIED LIMIT 343, 333 HE FOUND // RETURN WOULD BE WHEN JOHN TRIED

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  • Can't add any PPA's after reinstalling Ubuntu 13.10

    - by Michael Clare
    I can't add any PPA's at all after reinstalling Ubuntu 13.10. Here is what it says: michael@MikesKomputer:~$ sudo add-apt-repository ppa:atareao/atareao Cannot add PPA: 'ppa:atareao/atareao'. Please check that the PPA name or format is correct. This repository is working as far as I know. The problem is that I can't add any new repositories. Even if I can use the Software Center, I can't have my system with the add-apt-repository command broken.

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  • Virtualization of the human race interactivity and beyond. [on hold]

    - by J Michael Caldwell
    We are in the processes of attempting this lofty goal. It requires multidiscipline advancements over long periods of time. Achieving this requires a great deal of science advancement including major programming and algorithm developments. These requirements are going to be ongoing and will be required well into the next century. Does anyone know of individuals or feel themselves that they might be knowledgable or interested in this endeavor? Details upon request. Thanks Michael

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  • Exchange 2010 OWA - a few questions about using multiple mailboxes

    - by Alexey Smolik
    We have an Exchange 2010 SP2 deployment and we need that our users could access multiple mailboxes in OWA. The problem is that a user (eg John Smith) needs to access not just somebody else's (eg Tom Anderson) mailboxes, but his OWN mailboxes, e.g. in different domains: john[email protected], john[email protected], john[email protected], etc. Of course it is preferable for the user to work with all of his mailboxes from a single window. Such mailboxes can be added as multiple Exchange accounts in Outlook, that works almost fine. But in OWA, there are problems: 1) In the left pane - as I've learned - we can open only Inbox folders from other mailboxes. No way to view all folders like in Outlook? 2) With Send-As permissions set, when trying to send a message from another address, that message is saved in the Sent Items folder of the mailbox that is opened in OWA, and not in the mailbox the message is sent from. The same thing with the trash can. Is there a way to fix that? Also, this problem exists in desktop Outlook when mailboxes are added automatically via the Auto Mapping feature, so that we need to turn it off and add the accounts manually. Is there a simpler workaround? 3) Okay, suppose we only open Inbox folders in the left pane. The problem is that the mailbox names shown there are formed from Display Name attributes. But those names are all identical! All the mailboxes are owned by John Smith, so they should be all named John Smith - so that letter recepient sees "John Smith" in the "from" field, no matter what mailbox it is sent from. Also, the user knows what's his name - no need to tell him. He wants to know what mailbox he works with. So we need a way to either: a) customize OWA to show mailbox email address instead of user Display Name, or b) make Exchange use another attribute to put in the "from" field when sending letters 4) Okay, we can switch between mailboxes using "Open Other Mailbox" in the upper-right corner menu. But: a) To select a mailbox we need to enter its name (or first letters). It there a way to show a list of links to mailboxes the user has full access to? Eg in the page header... b) If we start entering the first letters, we see a popup list with possible mailboxes to be opened. But there are all mailboxes (apparently from GAL), not only mailboxes the user has permission to open! How to filter that popup list? c) The same problem as in (3) with mailbox naming. We can see the opened mailbox email address ONLY in the page URL, which is insufficient for many users. In the left pane we see "John Smith" which is useless. 5) Each mailbox is tied with a separate user in AD. If one has several mailboxes, we need to have additional dummy AD accounts, create additional OUs to store them, etc. That's not very nice, is there any standartized, optimal way to build such a structure? We would really appreciate any answers or additional info for any of these questions. Thank you in advance.

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  • Rhythmbox 2.99.1 crashes when playing any song on Ubuntu 13.10

    - by John H
    Yesterday rhythmbox was running smoothly but today it crashes only a few seconds after I hit the play button, regardless of track. I've tried disabling plugins, re-installing rhythmbox via synaptics, clearing the library and the rhythmdb.xml-file and just adding one album. Still, it crashes. If I run the rhythmbox from the command line i get the following before I have to force quit: :~$ rhythmbox Failed to create secure directory (/run/user/1000/pulse): Permission denied Killed :~$ However, if i run rhythmbox via the command line as superuser it does work. But i get the following errors: sudo rhythmbox (rhythmbox:8335): Gtk-WARNING **: Failed to register client: GDBus.Error:org.freedesktop.DBus.Error.ServiceUnknown: The name org.gnome.SessionManager was not provided by any .service files (rhythmbox:8335): IBUS-WARNING **: The owner of /home/john/.config/ibus/bus is not root! (rhythmbox:8335): Rhythmbox-WARNING **: Unable to grab media player keys: GDBus.Error:org.freedesktop.DBus.Error.ServiceUnknown: The name org.gnome.SettingsDaemon was not provided by any .service files Traceback (most recent call last): File "/usr/lib/rhythmbox/plugins/rb/Loader.py", line 47, in _contents_cb (ok, contents, etag) = file.load_contents_finish(result) gi._glib.GError: Operation not supported Traceback (most recent call last): File "/usr/lib/python2.7/dist-packages/gi/overrides/GLib.py", line 634, in return (lambda data: callback(*data), user_data) […] I'm running rhythmbox on a Lenovo e335 thikpad edge. I hope I've supplied enough information. Cheers -John

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  • Mexico leading in Business Transformation Strategies:

    - by [email protected]
    By john[email protected] on April 15, 2010 8:31 AM By John Burke Group Vice President Oracle Applications Business Unit I recently completed a business tour in Mexico, and was surprised by both the economic vibrancy of the country and the thought leadership expressed by many of the customers I met. An example of the economic vibrancy of the country: across the street from my hotel was the local Bentley dealership, Coach Store, Yves Saint Laurent and of course a Starbucks. I only made it to Starbucks. Both the Coach Store and YSL had a line of folks waiting to get in... As for thought leadership, there were several illustrations only on the first day. I had the opportunity to meet with a branch of the Mexican Federal Government. Their questions were not about clerical task automation, far from it! We discussed citizen on-line access to fees and services - for example looking up the duty on an international goods shipment, or tracking that my taxes have been received, or the status of my request for a certain service. Eligibility, policies and status. Having an integrated rules or policy automation system that would allow businesses and citizens to access accurate information and ensure the proper collection of fees and payment for 3rd party provided services. Then in the afternoon, I met with the owner of a roofing company (note: most roofs in Mexico are flat and made of cement). This CEO started discussing how he wanted to transform his business from a cement products company to a service company and market 5-10-15 year service contracts which would guarantee the structural integrity of the roof and of course that the roof would remain waterproof. Although his products were guaranteed, they required an annual inspection and most home owners never schedule that inspection until it is too late and water damage has occurred. These emergency calls reduce his margin and reduce customer satisfaction. This lead to a discussion of business models in general and why long term differentiation can only come from service, not just for the music or news industries, but also for roofing companies! I completely agreed with the transformational concepts described in both meetings and quickly understood why there is a Bentley dealership near my hotel.

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  • Ubuntu 12.10 unmet dependencies

    - by John
    I have Ubuntu 12.10 with 3.2.0.24-generic #39-Ubuntu running on a Dell Inspiron 700m laptop. I have unmet dependencies as follows: root@John-700m:/home/John# sudo apt-get remove --purge linux-image-3.5.0-{18,27,31,34}-generic Reading package lists... Done Building dependency tree Reading state information... Done Package 'linux-image-3.5.0-18-generic' is not installed, so not removed Package 'linux-image-3.5.0-27-generic' is not installed, so not removed Package 'linux-image-3.5.0-31-generic' is not installed, so not removed Package 'linux-image-3.5.0-34-generic' is not installed, so not removed You might want to run 'apt-get -f install' to correct these: The following packages have unmet dependencies: linux-generic : Depends: linux-image-generic but it is not going to be installed linux-image-extra-3.5.0-18-generic : Depends: linux-image-3.5.0-18-generic but it is not going to be installed linux-image-extra-3.5.0-27-generic : Depends: linux-image-3.5.0-27-generic but it is not going to be installed linux-image-extra-3.5.0-31-generic : Depends: linux-image-3.5.0-31-generic but it is not going to be installed linux-image-extra-3.5.0-34-generic : Depends: linux-image-3.5.0-34-generic but it is not going to be installed E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). I tried to remove the packages, but I still get the same error message. Any help would certainly be appreciated. @Eric, well noted. Here is the reults: model name : Intel(R) Pentium(R) M processor 1.60GHz flags : fpu vme de pse tsc msr mce cx8 mtrr pge mca cmov clflush dts acpi mmx fxsr sse sse2 ss tm pbe up bts est tm2 Thanks again. @Eric, If I need to downgrade to Ubuntu 12.04 from 12.10, can I do it without having to mess my current partition or files? I also have Windows XP running on the machine. Best. @Eric, if you are online, I could use your help (or anybody's else). I installed the package for non-pae unit and I still get the same error. Any suggestions? Thanks

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  • Merge\Combine two datatables

    - by madlan
    I'm trying to merge\combine two datatables. I've looked at various examples and answers but they seem to create duplicate rows or require indexes (merge on datatable etc) I can't do this via SQL as one source is from a linked Oracle server accessed via MSSQL and the other from a different MSSQL Server that does not have linked access. The data is currently very simple: Name, Email, Phone DataTable1: "John Clark", "", "01522 55231" "Alex King", "[email protected]", "01522 55266" "Marcus Jones", "[email protected]", "01522 55461" DataTable2: "John Clark", "john[email protected]", "01522 55231" "Alex King", "[email protected]", "" "Marcus Jones", "[email protected]", "01522 55461" "Warren bean", "[email protected]", "01522 522311" Giving a datatable with the following: "John Clark", "john[email protected]", "01522 55231" "Alex King", "[email protected]", "01522 55266" "Marcus Jones", "[email protected]", "01522 55461" "Warren bean", "[email protected]", "01522 522311" Name is the field to match records on, with the first datatable taking priority.

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  • To ref or not to ref

    - by nmarun
    So the question is what is the point of passing a reference type along with the ref keyword? I have an Employee class as below: 1: public class Employee 2: { 3: public string FirstName { get; set; } 4: public string LastName { get; set; } 5:  6: public override string ToString() 7: { 8: return string.Format("{0}-{1}", FirstName, LastName); 9: } 10: } In my calling class, I say: 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(Employee employee) 16: { 17: employee.FirstName = "Smith"; 18: employee.LastName = "Doe"; 19: } 20: }   After having a look at the code, you’ll probably say, Well, an instance of a class gets passed as a reference, so any changes to the instance inside the CallSomeMethod, actually modifies the original object. Hence the output will be ‘John-Doe’ on the first call and ‘Smith-Doe’ on the second. And you’re right: So the question is what’s the use of passing this Employee parameter as a ref? 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(ref employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(ref Employee employee) 16: { 17: employee.FirstName = "Smith"; 18: employee.LastName = "Doe"; 19: } 20: } The output is still the same: Ok, so is there really a need to pass a reference type using the ref keyword? I’ll remove the ‘ref’ keyword and make one more change to the CallSomeMethod method. 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(Employee employee) 16: { 17: employee = new Employee 18: { 19: FirstName = "Smith", 20: LastName = "John" 21: }; 22: } 23: } In line 17 you’ll see I’ve ‘new’d up the incoming Employee parameter and then set its properties to new values. The output tells me that the original instance of the Employee class does not change. Huh? But an instance of a class gets passed by reference, so why did the values not change on the original instance or how do I keep the two instances in-sync all the times? Aah, now here’s the answer. In order to keep the objects in sync, you pass them using the ‘ref’ keyword. 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(ref employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(ref Employee employee) 16: { 17: employee = new Employee 18: { 19: FirstName = "Smith", 20: LastName = "John" 21: }; 22: } 23: } Viola! Now, to prove it beyond doubt, I said, let me try with another reference type: string. 1: class Program 2: { 3: static void Main() 4: { 5: string name = "abc"; 6: Console.WriteLine(name); 7: CallSomeMethod(ref name); 8: Console.WriteLine(name); 9: } 10:  11: private static void CallSomeMethod(ref string name) 12: { 13: name = "def"; 14: } 15: } The output was as expected, first ‘abc’ and then ‘def’ - proves the 'ref' keyword works here as well. Now, what if I remove the ‘ref’ keyword? The output should still be the same as the above right, since string is a reference type? 1: class Program 2: { 3: static void Main() 4: { 5: string name = "abc"; 6: Console.WriteLine(name); 7: CallSomeMethod(name); 8: Console.WriteLine(name); 9: } 10:  11: private static void CallSomeMethod(string name) 12: { 13: name = "def"; 14: } 15: } Wrong, the output shows ‘abc’ printed twice. Wait a minute… now how could this be? This is because string is an immutable type. This means that any time you modify an instance of string, new memory address is allocated to the instance. The effect is similar to ‘new’ing up the Employee instance inside the CallSomeMethod in the absence of the ‘ref’ keyword. Verdict: ref key came to the rescue and saved the planet… again!

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  • SQL group and order

    - by John Lambert
    I have multiple users with multiple entries recording times they arrive at destinations Somehow, with my select query I would like to only show the most recent entries for each unique user name. Here is the code that doesn't work: SELECT * FROM $dbTable GROUP BY xNAME ORDER BY xDATETIME DESC This does the name grouping fine, but as far as showing ONLY their most recent entry, is just shows the first entry it sees in the SQL table. I guess my question is, is this possible? Here is my data sample: john 7:00 chris 7:30 greg 8:00 john 8:15 greg 8:30 chris 9:00 and my desired result should only be john 8:15 chris 9:00 greg 8:30

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  • C# - Determine if class initializaion causes infinite recursion?

    - by John M
    I am working on porting a VB6 application to C# (Winforms 3.5) and while doing so I'm trying to break up the functionality into various classes (ie database class, data validation class, string manipulation class). Right now when I attempt to run the program in Debug mode the program pauses and then crashes with a StackOverFlowException. VS 2008 suggests a infinite recursion cause. I have been trying to trace what might be causing this recursion and right now my only hypothesis is that class initializations (which I do in the header(?) of each class). My thought is this: mainForm initializes classA classA initializes classB classB initializes classA .... Does this make sense or should I be looking elsewhere? UPDATE1 (a code sample): mainForm namespace john { public partial class frmLogin : Form { stringCustom sc = new sc(); stringCustom namespace john { class stringCustom { retrieveValues rv = new retrieveValues(); retrieveValues namespace john { class retrieveValues { stringCustom sc = new stringCustom();

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  • struct assignment operator on arrays

    - by Django fan
    Suppose I defined a structure like this: struct person { char name [10]; int age; }; and declared two person variables: person Bob; person John; where Bob.name = "Bob", Bob.age = 30 and John.name = "John",John.age = 25. and I called Bob = John; struct person would do a Memberwise assignment and assign Johns's member values to Bob's. But arrays can't assign to arrays, so how does the assignment of the "name" array work?

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  • In Clojure - How do I access keys in a vector of structs

    - by Nick
    I have the following vector of structs: (defstruct #^{:doc "Basic structure for book information."} book :title :authors :price) (def #^{:doc "The top ten Amazon best sellers on 16 Mar 2010."} best-sellers [(struct book "The Big Short" ["Michael Lewis"] 15.09) (struct book "The Help" ["Kathryn Stockett"] 9.50) (struct book "Change Your Prain, Change Your Body" ["Daniel G. Amen M.D."] 14.29) (struct book "Food Rules" ["Michael Pollan"] 5.00) (struct book "Courage and Consequence" ["Karl Rove"] 16.50) (struct book "A Patriot's History of the United States" ["Larry Schweikart","Michael Allen"] 12.00) (struct book "The 48 Laws of Power" ["Robert Greene"] 11.00) (struct book "The Five Thousand Year Leap" ["W. Cleon Skousen","James Michael Pratt","Carlos L Packard","Evan Frederickson"] 10.97) (struct book "Chelsea Chelsea Bang Bang" ["Chelsea Handler"] 14.03) (struct book "The Kind Diet" ["Alicia Silverstone","Neal D. Barnard M.D."] 16.00)]) I would like to sum the prices of all the books in the vector. What I have is the following: (defn get-price "Same as print-book but handling multiple authors on a single book" [ {:keys [title authors price]} ] price) Then I: (reduce + (map get-price best-sellers)) Is there a way of doing this without mapping the "get-price" function over the vector? Or is there an idiomatic way of approaching this problem?

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