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  • Why my events aren't registered after postback?

    - by lucian.jp
    I have a problem where I have a page with a checkbox : <asp:CheckBox runat="server" ID="chkSelectAll" OnCheckedChanged="chkSelectAll_CheckedChanged" EnableViewState="true" Text='<%# CommonFunctions.GetText(Page, "CreateTask", "chkSelectAll.text") %>' AutoPostBack="true" /> First I had the problem that when the event was raised the checkbox wasn't keeping the checked property value. This is still strange because nowhere in the application we set the EnableViewState to false and by default it should be true. Well this behavior was fixed by puting EnableViewState="true". So now, I have a checkbox that when I first load the page, wworks correctly. I check the box, the event is raised Checked property valu is good and the method is executed. Postback completes and renders the page. I check the box back to false, the event is not triggered and the page is reloaded with the previous data but the Checked Property stays at true. So after the first postback I seem to loose behavior of event and ViewState. We suspect the fact that we move dynamically the controls in the page (See answer here) But this suspicion doesn't explain why everything works perfectly after the first load and stops working after first PostBack. EDIT CODE SAMPLE I created a test project where you can experience my problem. At load if you check any checkbox both raise their respective event. After postback only the second raise both events. I seem to have a problem when I register the events after moving control.

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  • Checkbox 'off' value

    - by Richard JP Le Guen
    Does anyone have a no JavaScript way to make HTML checkbox still submit a value? As in if you check it the form submission will include a value A but if it is uncheck it still contains a value B? While I figure there isn't any way, I'm working on a site which needs to still be function when JS is off, and this would be ideal.

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  • heterogeneous comparisons in python3

    - by Matt Anderson
    I'm 99+% still using python 2.x, but I'm trying to think ahead to the day when I switch. So, I know that using comparison operators (less/greater than, or equal to) on heterogeneous types that don't have a natural ordering is no longer supported in python3.x -- instead of some consistent (but arbitrary) result we raise TypeError instead. I see the logic in that, and even mostly think its a good thing. Consistency and refusing to guess is a virtue. But what if you essentially want the python2.x behavior? What's the best way to go about getting it? For fun (more or less) I was recently implementing a Skip List, a data structure that keeps its elements sorted. I wanted to use heterogeneous types as keys in the data structure, and I've got to compare keys to one another as I walk the data structure. The python2.x way of comparing makes this really convenient -- you get an understandable ordering amongst elements that have a natural ordering, and some ordering amongst those that don't. Consistently using a sort/comparison key like (type(obj).__name__, obj) has the disadvantage of not interleaving the objects that do have a natural ordering; you get all your floats clustered together before your ints, and your str-derived class separates from your strs. I came up with the following: import operator def hetero_sort_key(obj): cls = type(obj) return (cls.__name__+'_'+cls.__module__, obj) def make_hetero_comparitor(fn): def comparator(a, b): try: return fn(a, b) except TypeError: return fn(hetero_sort_key(a), hetero_sort_key(b)) return comparator hetero_lt = make_hetero_comparitor(operator.lt) hetero_gt = make_hetero_comparitor(operator.gt) hetero_le = make_hetero_comparitor(operator.le) hetero_ge = make_hetero_comparitor(operator.gt) Is there a better way? I suspect one could construct a corner case that this would screw up -- a situation where you can compare type A to B and type A to C, but where B and C raise TypeError when compared, and you can end up with something illogical like a > b, a < c, and yet b > c (because of how their class names sorted). I don't know how likely it is that you'd run into this in practice.

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  • Browsers disagree about the text of a body element

    - by Charles Anderson
    My HTML looks like this: <html> <head> <title>Test</title> <script type="text/javascript" src="jQuery.js"></script> <script type="text/javascript"> function init() { var text = jQuery('body').text(); alert('length = ' + text.length); } </script> </head> <body onload="init()">0123456789</body> </html> When I load this in Firefox, the length is reported as 10. However, in Chrome it's 11 because it thinks there's a linefeed after the '9'. In IE it's also 11, but the last character is an escape. Meanwhile, Opera thinks there are 12 characters, with the last two being CR LF. If I change the body element to include a span: <body onload="init()"><span>0123456789</span></body> and the jQuery call to: var text = jQuery('body span').text(); then all the browsers agree that the length is 10. Clearly it's the body element that's causing the issue, but can anyone explain exactly why this is happening? I'm particularly surprised because the excellent jQuery is normally browser-independent.

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  • many to many query for ActiveRecord

    - by JP
    I have three data models, Users, Conversations and Lines, where each conversation has many lines and certain participating users, each line has one conversation and one user and each user has many conversations and many lines. I have arranged these in ActiveRecord like this: class Line < ActiveRecord::Base belongs_to :conversation belongs_to :user end class User < ActiveRecord::Base has_and_belongs_to_many :conversations has_many :lines end class Conversation < ActiveRecord::Base has_many :lines has_and_belongs_to_many :users end If I want to create a new conversation with 4 users, where the users are either found or created inside the users table, how would I go about doing this? I thought I could do: c = Conversation.new c.users.find_or_create_by_username('myUsername') c.save But this will create a new username in the Users table even if that username already exists! (ie. running the above code 3 times will result in Users having 3 rows with 'myUsername' as the username, one for each conversation, rather than three conversations all with the same 'myUsername' entry listed in their associated users) I'm not sure how to search for this kind of information with google - can anyone help?

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  • Can't switch on designMode in Internet Explorer

    - by Charles Anderson
    The following code works in Firefox 3.6, but not in Internet Explorer 8: <html> <head> <title>Example</title> <script type="text/javascript"> function init() { alert(document.designMode); document.designMode = "on"; alert(document.designMode); } </script> </head> <body onload="init()"> </body> </html> In FF the alerts show 'off', then 'on'; in IE they're both 'Off'. What am I doing wrong?

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  • PHP Modify the return of a loop over and over.

    - by Joshua Anderson
    Basically I want to do a php loop that base64_encodes its self 5 times. //For example i want to encode "test" which is "dGVzdA==" then we encode "dGVzdA==" which is "ZEdWemRBPT0=" then encode "ZEdWemRBPT0=" which is "WkVkV2VtUkJQVDA9" I can't figure out how to create a loop that modifies its self each time it runs. // this is what i had function enloop($dowork){ for ($i=1; $i&lt;=5; $i++) { returns base64_encode($dowork); } } enloop($code); //THIS SCRIPT DOES THIS Repeats the encode 5 times, lets say your encodign the word test for example the output would be dGVzdA==dGVzdA==dGVzdA==dGVzdA==dGVzdA==

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  • .NET --- Textbox control - wait till user is done typing

    - by Cj Anderson
    Greetings all, Is there a built in way to know when a user is done typing into a textbox? (Before hitting tab, Or moving the mouse) I have a database query that occurs on the textchanged event and everything works perfectly. However, I noticed that there is a bit of lag of course because if a user is quickly typing into the textbox the program is busy doing a query for each character. So what I was hoping for was a way to see if the user has finished typing. So if they type "a" and stop then an event fires. However, if they type "all the way" the event fires after the y keyup. I have some ideas floating around my head but I'm sure they aren't the most efficient. Like measuring the time since the last textchange event and if it was than a certain value then it would proceed to run the rest of my procedures. let me know what you think. Language: VB.NET Framework: .Net 2.0 --Edited to clarify "done typing"

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  • Python File Search Line And Return Specific Number of Lines after Match

    - by Simos Anderson
    I have a text file that has lines representing some data sets. The file itself is fairly long but it contains certain sections of the following format: Series_Name INFO Number of teams : n1 | Team | # | wins | | TeamName1 | x | y | . . . | TeamNamen1 | numn | numn | Some Irrelevant lines Series_Name2 INFO Number of teams : n1 | Team | # | wins | | TeamName1 | num1 | num2 | . where each section has a header that begins with the Series_Name. Each Series_Name is different. The line with the header also includes the number of teams in that series, n1. Following the header line is a set of lines that represents a table of data. For each series there are n1+1 rows in the table, where each row shows an individual team name and associated stats. I have been trying to implement a function that will allow the user to search for a Team name and then print out the line in the table associated with that team. However, certain team names show up under multiple series. To resolve this, I am currently trying to write my code so that the user can search for the header line with series name first and then print out just the following n1+1 lines that represent the data associated with the series. Here's what I have come up with so far: import re print fname = raw_input("Enter filename: ") seriesname = raw_input("Enter series: ") def findcounter(fname, seriesname): logfile = open(fname, "r") pat = 'INFO Number of teams :' for line in logfile: if seriesname in line: if pat in line: s=line pattern = re.compile(r"""(?P<name>.*?) #starting name \s*INFO #whitespace and success \s*Number\s*of\s*teams #whitespace and strings \s*\:\s*(?P<n1>.*)""",re.VERBOSE) match = pattern.match(s) name = match.group("name") n1 = int(match.group("n1")) print name + " has " + str(n1) + " teams" lcount = 0 for line in logfile: if line.startswith(name): if pat in line: while lcount <= n1: s.append(line) lcount += 1 return result The first part of my code works; it matches the header line that the person searches for, parses the line, and then prints out how many teams are in that series. Since the header line basically tells me how many lines are in the table, I thought that I could use that information to construct a loop that would continue printing each line until a set counter reached n1. But I've tried running it, and I realize that the way I've set it up so far isn't correct. So here's my question: How do you return a number of lines after a matched line when given the number of desired lines that follow the match? I'm new to programming, and I apologize if this question seems silly. I have been working on this quite diligently with no luck and would appreciate any help.

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  • Python urllib.urlopen() call doesn't work with a URL that a browser accepts

    - by Charles Anderson
    If I point Firefox at http://bitbucket.org/tortoisehg/stable/wiki/Home/ReleaseNotes, I get a page of HTML. But if I try this in Python: import urllib site = 'http://bitbucket.org/tortoisehg/stable/wiki/Home/ReleaseNotes' req = urllib.urlopen(site) text = req.read() I get the following: 500 Internal Server Error The server encountered an internal error or misconfiguration and was unable to complete your request. What am I doing wrong?

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  • Fixing parent controller's elements after screen orientation

    - by Jonas Anderson
    I have a tab bar application with mixed orientation support for only some views. One of the child view controller shown from one of the tab's navigation controller is displayed only in Landscape mode. In order to accomplish this, I've done the view transformation for the child view as suggested here: Is there a documented way to set the iPhone orientation? The only problem I'm seeing is that after I've performed the orientation adjustment for the child controller and then readjusted orientation back to normal on its dismissal, the contents of the (parent) navigation controller is still shown with Landscape mode dimensions despite the navigation controller reporting the correct value for the interfaceOrientation. How do I ensure that view's size is reset to match the orientation without hardcoding screen dimensions? I have the following in the root navigation controller's viewWillAppear (invoked after the child controller is dismissed): - (void)viewWillAppear:(BOOL)animated { NSLog(@"viewFrame: (%2f, %2f), width: %2f, height: %2f\n", self.view.frame.origin.x, self.view.frame.origin.y, self.view.frame.size.width, self.view.frame.size.height); // Frame values are (0, 0) for (x,y) width: 320, height: 367 before I // displayed child controller. // Frame values are (0,0) width: 480, height: 219 after returning from child // controller -- still has the landscape dimensions NSLog(@"orientation: %d", self.interfaceOrientation); // reports portrait as expected } I've tried to invoke 'layoutIfNeeded' as well as 'setNeedsDisplay' on the view but neither of them bring the view contents into the correct display. Any suggestions would be greatly appreciated.

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  • Trying to not need two separate solutions for x86 and x64 program.

    - by Sean Anderson
    Hi all, I have a program which needs to function in both an x86 and an x64 environment. It is using Oracle's ODBC drivers. I have a reference to Oracle.DataAccess.DLL. This DLL is different depending on whether the system is x64 or x86, though. Currently, I have two separate solutions and I am maintaining the code on both. This is atrocious. I was wondering what the proper solution is? I have my platform set to "Any CPU." and it is my understanding that VS should compile the DLL to an intermediary language such that it should not matter if I use the x86 or x64 version. Yet, if I attempt to use the x64 DLL I receive the error "Could not load file or assembly 'Oracle.DataAccess, Version=2.102.3.2, Culture=neutral, PublicKeyToken=89b483f429c47342' or one of its dependencies. An attempt was made to load a program with an incorrect format." I am running on a 32 bit machine, so the error message makes sense, but it leaves me wondering how I am supposed to efficiently develop this program when it needs to work on x64. Thanks.

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  • Detect similar sounding words in Ruby

    - by JP
    I'm aware of SOUNDEX and (double) Metaphone, but these don't let me test for the similarity of words as a whole - for example "Hi" sounds very similar to "Bye", but both of these methods will mark them as completely different. Are there any libraries in Ruby, or any methods you know of, that are capable of determining the similarity between two words? (Either a boolean is/isn't similar, or numerical 40% similar) edit: Extra bonus points if there is an easy method to 'drop in' a different dialect or language!

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  • Server -> Desktop Push API

    - by Rich Anderson
    Hi I am looking for solution which can push automatically a certain event (let's say RSS message) realtime to a desktop user. A toolbar app or a desktop (growl like) will be super for this push. I have looked at few options but cannot find much info on these kind of apps. I have looked at conduit - it sucks as there is lot of other fancy options which I am not interested in offering to users. Please let me know. Thanks.

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  • QuickTimeX in Applescript / Scripting Bridge

    - by JP
    I'd like to be able to grab the metadata of the currently playing file in Quicktime X using ScriptingBridge and Ruby, so far I have the following code require 'osx/cocoa' OSX.require_framework 'ScriptingBridge' @app = OSX::SBApplication.applicationWithBundleIdentifier("com.apple.QuickTimePlayerX") @app.documents.each do |movie| # What now?! end But I can't find any functions in QuickTime X's applescript dictionary to get the metadata from a document object (the same data you can see in QT's 'Show Movie Inspector' HUD) — does anyone have any ideas?

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  • Accessing parent 'this' inside a jQuery $.getJSON

    - by JP
    I'm going to assume that the overall structure of my code as it currently stands is 'best', otherwise this question gets too long, but if I've made any obvious mistakes (or if I've made life hard for myself) then please correct away! Using jQuery, I have a javascript 'class' set out something like this: function MyClass () { this.noise = "Woof" this.dostuff = function() { $.getJSON("http://cows.go",function(moo) { this.noise = moo.inEnglish; } } } var instance = new MyClass(); instance.doStuff() console.log(instance.noise) I'm expecting some kinda tea drinking moo in the console, but of course I'm getting an error about this.noise not being defined (because $.getJSON doesn't pass this through, right?) Any suggestions as to how to be able to affect instance.squeak for any and all instances of MyClass without interference?

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  • jQuery('body').text() gives different answers in different browsers

    - by Charles Anderson
    My HTML looks like this: <html> <head> <title>Test</title> <script type="text/javascript" src="jQuery.js"></script> <script type="text/javascript"> function init() { var text = jQuery('body').text(); alert('length = ' + text.length); } </script> </head> <body onload="init()">0123456789</body> </html> When I load this in Firefox, the length is reported as 10. However, in Chrome it's 11 because it thinks there's a linefeed after the '9'. In IE it's also 11, but the last character is an escape. Meanwhile, Opera thinks there are 12 characters, with the last two being CR LF. If I change the body element to include a span: <body onload="init()"><span>0123456789</span></body> and the jQuery call to: var text = jQuery('body span').text(); then all the browsers agree that the length is 10. Clearly it's the body element that's causing the issue, but can anyone explain exactly why this is happening? I'm particularly surprised because the excellent jQuery is normally browser-independent.

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  • How can I prevent a ToggleButton from being Toggled without setting IsEnabled=False

    - by Bryan Anderson
    I have a list of ToggleButtons being used as the ItemTemplate in a ListBox similar to this answer using the MultiSelect mode of the Listbox. However I need to make sure at least one item is always selected. I can get the proper behavior from the ListBox by just adding an item back into the ListBox's SelectedItems collection on the ListBox.SelectionChanged event but my ToggleButton still moves out of its toggled state so I think I need to stop it earlier in the process. I would like to do it without setting IsEnabled="False" on the last button Selected because I'd prefer to stay with the Enabled visual style without having to redo my button templates. Any ideas?

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  • Require Integer Value not Memory Address whilst avoiding Invalid receiver type compiler warning

    - by Dave Anderson
    I have the following code; int days = [[SettingsUtils daysToRetainHistory] intValue]; [retainHistory setText:[NSString stringWithFormat:@"Days to retain History: %d", days]]; [daysToRetainHistory setValue:days animated:NO]; where [SettingsUtils daysToRetainHistory] is as follows; + (int) daysToRetainHistory { return (int)[[NSUserDefaults standardUserDefaults] objectForKey:@"CaseBaseDaysToRetainHistory"]; } I get the compiler warning Invalid receiver type 'int' because I call intValue on an int but unless I do this I can't seem to get the integer value out and always end up with the memory address i.e. 98765432 instead of 9 which ruins the UILabel display [retainHistory] and the UISlider [daysToRetainHistory] value. How do I avoid the compiler warning and still get my integer value in the label and the necessary float value for setting the UISlider value?

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  • Sintra app in a gem

    - by JP
    I have a Sinatra application I've created and I'd like to package it as a gem-based binary. I have my gemspec and gem set up to generate a suitable executable that points to the my_sinatra_app.rb (which is executable) but the sinatra server never runs. Any ideas why and how to make it work? my_sinatra_app executable: #!/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/bin/ruby # # This file was generated by RubyGems. require 'rubygems' version = ">= 0" if ARGV.first =~ /^_(.*)_$/ and Gem::Version.correct? $1 then version = $1 ARGV.shift end gem 'my_sinatra_app', version load Gem.bin_path('my_sinatra_app', 'my_sinatra_app', version)

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