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  • Sharepoint Lists.GetListItems Method rowLimit problem

    - by Linda
    In SharePoint I am using the default view of a list. When I use GetListItems method I can pass into it the following: public XmlNode GetListItems ( string listName, string viewName, XmlNode query, XmlNode viewFields, string rowLimit, XmlNode queryOptions, string webID ) I am passing in "" for the viewName and am passing a rowLimit of 1000. By Default view only returns 100 items. 100 Items are still being returned not 1000. Can you use the rowLimit when not specifying a view? Is it possible to bring back 1000 items using the query instead? I do not really want to use a GUID for the viewName as I would have to look it up for each list and perform a big refactor. Update I am now using the guid of the view and my list still returns the incorrect number of items. I know the guid is being used as I sued an incorrect one and it errord out. Any ideas what could be wrong? The code that is being sent to the service is as follows: <GetListItems xmlns='http://schemas.microsoft.com/sharepoint/soap/'> <listName>Media Outlet</listName> <viewName>{2822F0D9-A905-44B5-8913-34E6497F1AAF}</viewName> <query><Query><Where><Eq><FieldRef Name='Outlet_x0020_Type' /><Value Type='Lookup'></Value></Eq></Where><OrderBy><FieldRef Name='Title' /></OrderBy></Query></query> <ViewFields></ViewFields> <RowLimit>10000</RowLimit> <QueryOptions></QueryOptions> <webID></webID> </GetListItems>

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  • Sharepoint GetListItems using rowLimit parameter is not limiting the results returned

    - by Linda
    In SharePoint I am using the default view of a list. When I use GetListItems method I can pass into it the following: public XmlNode GetListItems ( string listName, string viewName, XmlNode query, XmlNode viewFields, string rowLimit, XmlNode queryOptions, string webID ) I am passing in "" for the viewName and am passing a rowLimit of 1000. By Default view only returns 100 items. 100 Items are still being returned not 1000. Can you use the rowLimit when not specifying a view? Is it possible to bring back 1000 items using the query instead? I do not really want to use a GUID for the viewName as I would have to look it up for each list and perform a big refactor. Update I am now using the guid of the view and my list still returns the incorrect number of items. I know the guid is being used as I sued an incorrect one and it errord out. Any ideas what could be wrong? The code that is being sent to the service is as follows: <GetListItems xmlns='http://schemas.microsoft.com/sharepoint/soap/'> <listName>Media Outlet</listName> <viewName>{2822F0D9-A905-44B5-8913-34E6497F1AAF}</viewName> <query><Query><Where><Eq><FieldRef Name='Outlet_x0020_Type' /><Value Type='Lookup'></Value></Eq></Where><OrderBy><FieldRef Name='Title' /></OrderBy></Query></query> <ViewFields></ViewFields> <RowLimit>10000</RowLimit> <QueryOptions></QueryOptions> <webID></webID> </GetListItems>

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  • Suggested Web Application Framework and Database for Enterprise, “Big-Data” App?

    - by willOEM
    I have a web application that I have been developing for a small group within my company over the past few years, using Pipeline Pilot (plus jQuery and Python scripting) for web development and back-end computation, and Oracle 10g for my RDBMS. Users upload experimental genomic data, which is parsed into a database, and made available for querying, transformation, and reporting. Experimental data sets are large and have many layers of metadata. A given experimental data record might have a foreign key relationship with a table that describes this data point's assay. Assays can cover multiple genes, which can have multiple transcript, which can have multiple mutations, which can affect multiple signaling pathways, etc. Users need to approach this data from any point in those layers in the metadata. Since all data sets for a given data type can run over a billion rows, this results in some large, dynamic queries that are hard to predict. New data sets are added on a weekly basis (~1GB per set). Experimental data is never updated, but the associated metadata can be updated weekly for a few records and yearly for most others. For every data set insert the system sees, there will be between 10 and 100 selects run against it and associated data. It is okay for updates and inserts to run slow, so long as queries run quick and are as up-to-date as possible. The application continues to grow in size and scope and is already starting to run slower than I like. I am worried that we have about outgrown Pipeline Pilot, and perhaps Oracle (as the sole database). Would a NoSQL database or an OLAP system be appropriate here? What web application frameworks work well with systems like this? I'd like the solution to be something scalable, portable and supportable X-years down the road. Here is the current state of the application: Web Server/Data Processing: Pipeline Pilot on Windows Server + IIS Database: Oracle 10g, ~1TB of data, ~180 tables with several billion-plus row tables Network Storage: Isilon, ~50TB of low-priority raw data

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  • Big numbers in C

    - by teehoo
    I need help working with very big numbers. According to Windows calc, the exponent 174^55 = 1.6990597648061509725749329578093e+123. How would I store this using C (c99 standard). int main(){ long long int x = 174^55; //result is 153 printf("%lld\n", x); } For those curious, it is for a school project where we are implementing the RSA cryptographic algorithm, which deals with exponentiating large numbers with large powers for encryption/decryption.

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  • Big O, how do you calculate/approximate it?

    - by Sven
    Most people with a degree in CS will certainly know what Big O stands for. It helps us to measure how (in)efficient an algorithm really is and if you know in what category the problem you are trying to solve lays in you can figure out if it is still possible to squeeze out that little extra performance.* But I'm curious, how do you calculate or approximate the complexity of your algorithms? *: but as they say, don't overdo it, premature optimization is the root of all evil, and optimization without a justified cause should deserve that name as well.

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  • How big is too big (for NTFS)

    - by BCS
    I have a program and as it's done now, it has a data directory with something like 10-30K files in it and it's starting to cause problems. Should I expect that to cause problems and my only solution to tweak my file structure or does that indicate other problems?

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  • Big O and Little o

    - by hyperdude
    If algorithm A has complexity O(n) and algorithm B has complexity o(n^2), what, if anything, can we say about the relationship between A and B? Note: the complexity of A is expressed using big-Oh, and the complexity of B is expressed using little-Oh.

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  • BIG DATA eBook - Now Available

    - by Javier Puerta
    The Big Data interactive e-book “Meeting the Challenge of Big Data: Part One” has just been released. It’s your “one-stop shop” for info about Big Data and the Oracle offering around it.The new e-book (available on your computer or iPad) is packed with multi-media resources to educate Oracle staff, customers, prospects and partners on the value of Big Data. It features videos, tutorials, podcasts, reports, white papers, datasheets, blogs, web links, a 3-D demo, and more. Go and get it here!

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  • Big Data Sessions at Openworld 2012

    - by Jean-Pierre Dijcks
    If you are coming to San Francisco, and you are interested in all the aspects to big data, this Focus On Big Data is a must have document.  Some (other) highlights: A performance demo of a full rack Big Data Appliance in the engineered systems showcase A set of handson labs on how to go from a NoSQL DB to an effective analytics play on big data Much, much more See you all in a few weeks in SF!

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  • Big Oh Notation - formal definition.

    - by aloh
    I'm reading a textbook right now for my Java III class. We're reading about Big-Oh and I'm a little confused by its formal definition. Formal Definition: "A function f(n) is of order at most g(n) - that is, f(n) = O(g(n)) - if a positive real number c and positive integer N exist such that f(n) <= c g(n) for all n = N. That is, c g(n) is an upper bound on f(n) when n is sufficiently large." Ok, that makes sense. But hold on, keep reading...the book gave me this example: "In segment 9.14, we said that an algorithm that uses 5n + 3 operations is O(n). We now can show that 5n + 3 = O(n) by using the formal definition of Big Oh. When n = 3, 5n + 3 <= 5n + n = 6n. Thus, if we let f(n) = 5n + 3, g(n) = n, c = 6, N = 3, we have shown that f(n) <= 6 g(n) for n = 3, or 5n + 3 = O(n). That is, if an algorithm requires time directly proportional to 5n + 3, it is O(n)." Ok, this kind of makes sense to me. They're saying that if n = 3 or greater, 5n + 3 takes less time than if n was less than 3 - thus 5n + n = 6n - right? Makes sense, since if n was 2, 5n + 3 = 13 while 6n = 12 but when n is 3 or greater 5n + 3 will always be less than or equal to 6n. Here's where I get confused. They give me another example: Example 2: "Let's show that 4n^2 + 50n - 10 = O(n^2). It is easy to see that: 4n^2 + 50n - 10 <= 4n^2 + 50n for any n. Since 50n <= 50n^2 for n = 50, 4n^2 + 50n - 10 <= 4n^2 + 50n^2 = 54n^2 for n = 50. Thus, with c = 54 and N = 50, we have shown that 4n^2 + 50n - 10 = O(n^2)." This statement doesn't make sense: 50n <= 50n^2 for n = 50. Isn't any n going to make the 50n less than 50n^2? Not just greater than or equal to 50? Why did they even mention that 50n <= 50n^2? What does that have to do with the problem? Also, 4n^2 + 50n - 10 <= 4n^2 + 50n^2 = 54n^2 for n = 50 is going to be true no matter what n is. And how in the world does picking numbers show that f(n) = O(g(n))? Please help me understand! :(

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  • Big O Complexity of a method

    - by timeNomad
    I have this method: public static int what(String str, char start, char end) { int count=0; for(int i=0;i<str.length(); i++) { if(str.charAt(i) == start) { for(int j=i+1;j<str.length(); j++) { if(str.charAt(j) == end) count++; } } } return count; } What I need to find is: 1) What is it doing? Answer: counting the total number of end occurrences after EACH (or is it? Not specified in the assignment, point 3 depends on this) start. 2) What is its complexity? Answer: the first loops iterates over the string completely, so it's at least O(n), the second loop executes only if start char is found and even then partially (index at which start was found + 1). Although, big O is all about worst case no? So in the worst case, start is the 1st char & the inner iteration iterates over the string n-1 times, the -1 is a constant so it's n. But, the inner loop won't be executed every outer iteration pass, statistically, but since big O is about worst case, is it correct to say the complexity of it is O(n^2)? Ignoring any constants and the fact that in 99.99% of times the inner loop won't execute every outer loop pass. 3) Rewrite it so that complexity is lower. What I'm not sure of is whether start occurs at most once or more, if once at most, then method can be rewritten using one loop (having a flag indicating whether start has been encountered and from there on incrementing count at each end occurrence), yielding a complexity of O(n). In case though, that start can appear multiple times, which most likely it is, because assignment is of a Java course and I don't think they would make such ambiguity. Solving, in this case, is not possible using one loop... WAIT! Yes it is..! Just have a variable, say, inc to be incremented each time start is encountered & used to increment count each time end is encountered after the 1st start was found: inc = 0, count = 0 if (current char == start) inc++ if (inc > 0 && current char == end) count += inc This would also yield a complexity of O(n)? Because there is only 1 loop. Yes I realize I wrote a lot hehe, but what I also realized is that I understand a lot better by forming my thoughts into words...

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  • big O notation algorithm

    - by niggersak
    Use big-O notation to classify the traditional grade school algorithms for addition and multiplication. That is, if asked to add two numbers each having N digits, how many individual additions must be performed? If asked to multiply two N-digit numbers, how many individual multiplications are required? . Suppose f is a function that returns the result of reversing the string of symbols given as its input, and g is a function that returns the concatenation of the two strings given as its input. If x is the string hrwa, what is returned by g(f(x),x)? Explain your answer - don't just provide the result!

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  • Tricky Big-O complexity

    - by timeNomad
    public void foo (int n, int m) { int i = m; while (i > 100) i = i/3; for (int k=i ; k>=0; k--) { for (int j=1; j<n; j*=2) System.out.print(k + "\t" + j); System.out.println(); } } I figured the complexity would be O(logn). That is as a product of the inner loop, the outer loop -- will never be executed more than 100 times, so it can be omitted. What I'm not sure about is the while clause, should it be incorporated into the Big-O complexity? For very large i values it could make an impact, or arithmetic operations, doesn't matter on what scale, count as basic operations and can be omitted?

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  • Database indexes and their Big-O notation

    - by miket2e
    I'm trying to understand the performance of database indexes in terms of Big-O notation. Without knowing much about it, I would guess that: Querying on a primary key or unique index will give you a O(1) lookup time. Querying on a non-unique index will also give a O(1) time, albeit maybe the '1' is slower than for the unique index (?) Querying on a column without an index will give a O(N) lookup time (full table scan). Is this generally correct ? Will querying on a primary key ever give worse performance than O(1) ? My specific concern is for SQLite, but I'd be interested in knowing to what extent this varies between different databases too.

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  • Can someone help with big O notation?

    - by Dann
    void printScientificNotation(double value, int powerOfTen) { if (value >= 1.0 && value < 10.0) { System.out.println(value + " x 10^" + powerOfTen); } else if (value < 1.0) { printScientificNotation(value * 10, powerOfTen - 1); } else // value >= 10.0 { printScientificNotation(value / 10, powerOfTen + 1); } } I understand how the method goes but I cannot figure out a way to represent the method. For example, if value was 0.00000009 or 9e-8, the method will call on printScientificNotation(value * 10, powerOfTen - 1); eight times and System.out.println(value + " x 10^" + powerOfTen); once. So the it is called recursively by the exponent for e. But how do I represent this by big O notation? Thanks!

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  • Z600 Workstation ACPI Fan Noise

    - by dpb
    Hi -- I have an HP z600 workstation that has the FAN running full when idle. In fact, after the boot, the fan never slows down or varies. I looked in dmesg, and noticed this: [ 1.516778] ACPI Error (dsfield-0143): [CAPD] Namespace lookup failure, AE_ALREADY_EXISTS [ 1.516781] ACPI Error (psparse-0537): Method parse/execution failed [\_SB_.PCI0._OSC] (Node ffff8801b8c4e3e0), AE_ALREADY_EXISTS [ 1.516786] ACPI: Marking method _OSC as Serialized because of AE_ALREADY_EXISTS error [ 1.519868] ACPI Error (dsfield-0143): [CAPD] Namespace lookup failure, AE_ALREADY_EXISTS [ 1.519872] ACPI Error (psparse-0537): Method parse/execution failed [\_SB_.PCI0._OSC] (Node ffff8801b8c4e3e0), AE_ALREADY_EXISTS [ 1.624638] ACPI Error (dsfield-0143): [CAPD] Namespace lookup failure, AE_ALREADY_EXISTS [ 1.624642] ACPI Error (psparse-0537): Method parse/execution failed [\_SB_.PCI0._OSC] (Node ffff8801b8c4e3e0), AE_ALREADY_EXISTS [ 1.624726] ACPI Error (dsfield-0143): [CAPD] Namespace lookup failure, AE_ALREADY_EXISTS [ 1.624729] ACPI Error (psparse-0537): Method parse/execution failed [\_SB_.PCI0._OSC] (Node ffff8801b8c4e3e0), AE_ALREADY_EXISTS [ 1.624802] ACPI Error (dsfield-0143): [CAPD] Namespace lookup failure, AE_ALREADY_EXISTS [ 1.624805] ACPI Error (psparse-0537): Method parse/execution failed [\_SB_.PCI0._OSC] (Node ffff8801b8c4e3e0), AE_ALREADY_EXISTS [ 1.624895] ACPI Error (dsfield-0143): [CAPD] Namespace lookup failure, AE_ALREADY_EXISTS [ 1.624898] ACPI Error (psparse-0537): Method parse/execution failed [\_SB_.PCI0._OSC] (Node ffff8801b8c4e3e0), AE_ALREADY_EXISTS [ 1.624977] ACPI Error (dsfield-0143): [CAPD] Namespace lookup failure, AE_ALREADY_EXISTS [ 1.624981] ACPI Error (psparse-0537): Method parse/execution failed [\_SB_.PCI0._OSC] (Node ffff8801b8c4e3e0), AE_ALREADY_EXISTS [ 1.625070] ACPI Error (dsfield-0143): [CAPD] Namespace lookup failure, AE_ALREADY_EXISTS [ 1.625074] ACPI Error (psparse-0537): Method parse/execution failed [\_SB_.PCI0._OSC] (Node ffff8801b8c4e3e0), AE_ALREADY_EXISTS [ 1.625153] ACPI Error (dsfield-0143): [CAPD] Namespace lookup failure, AE_ALREADY_EXISTS [ 1.625157] ACPI Error (psparse-0537): Method parse/execution failed [\_SB_.PCI0._OSC] (Node ffff8801b8c4e3e0), AE_ALREADY_EXISTS Anyone know what could be done to fix this?

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  • Red Sand – An Awesome Fan Made Mass Effect Prequel [Short Movie]

    - by Asian Angel
    Welcome to Mars where humanity has just discovered the Prothean Ruins and Element Zero, but danger abounds as the Red Sand terrorist group seeks to claim Mars for themselves! If you love the Mass Effect game series, then you will definitely want to watch this awesome fan made prequel set 35 years before the events of the first game. Synopsis From YouTube: Serving as a prequel to the MASS EFFECT game series,”Red Sand” is set 35 years before the time of Commander Shepard and tells the story of the discovery of ancient ruins on Mars. Left behind by the mysterious alien race known as the Protheans, the ruins are a treasure trove of advanced technology and the powerful Element Zero, an energy source beyond humanity’s wildest dreams. As the Alliance research team led by Dr. Averroes (Ayman Samman) seeks to unlock the secrets of the ruins, a band of marauders living in the deserts of Mars wants the ruins for themselves. Addicted to refined Element Zero in the form of a narcotic nicknamed “Red Sand” which gives them telekinetic “biotic” powers, these desert-dwelling terrorists will stop at nothing to control the ruins and the rich vein of Element Zero at its core. Standing between them and their goal are Colonel Jon Grissom (Mark Meer), Colonel Lily Sandhurst (Amy Searcy), and a team of Alliance soldiers tasked with defending the ruins at all costs. At stake – the future of humanity’s exploration of the galaxy, and the set up for the MASS EFFECT storyline loved by millions of gamers worldwide. RED SAND: a Mass Effect fan film – starring MARK MEER [via Geeks are Sexy] 7 Ways To Free Up Hard Disk Space On Windows HTG Explains: How System Restore Works in Windows HTG Explains: How Antivirus Software Works

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  • Fan always on and overheating problems on HP G62

    - by Dave
    I have a HP G62 with i5 processor, 4G Ram and ATI HD 5470. Started using Ubuntu 4 months ago, first was 11.10 and after 12.04. Everything worked perfectly until some weeks ago when my cpu fan became "crazy" and I mean by this always on, noise and overheating problems, for sure if I put a glass with water in some minutes will boil (and I mean it). There can be a bug in the last kernel or any other Ubuntu's official update? And by the way CPU fan is cleaned like a new born baby; Used jupiter and all those stuff (lm-sensor, psensor...) - same problem; Don't ask me to install ATI drivers because will work like sh#t (interface laggy as HD 5470 isn't supported by Ubuntu) and I can't even open ATI Catalyst (error when I try to open it), more than this I always used open source drivers and as I said, worked perfectly (3d, effects). Right now I'm back to Windows and everything is working perfectly but my main problem is that I get used with Ubuntu and kinda weird to use windows again. I want back my nice and almost perfect Ubuntu. Thanks, Dave

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  • Installing MOSS 2007 on Windows 2008 R2

    - by Manesh Karunakaran
    When you try to install MOSS 2007 on Windows 2008 R2, if you are using an installation media that is older than SP2, you would get the following error, saying that “This program is blocked due to compatibility issues”    All is not lost though, all you need to do is to slip stream the SP2 updates to the MOSS 2007 Setup. Here’s a nice how to on how to do that. http://blogs.technet.com/seanearp/archive/2009/05/20/slipstreaming-sp2-into-sharepoint-server-2007.aspx Once you slipstream the SP2 updates, you would be able to continue with the installation with out the above error. HTH.   You may already read from blogs about April Cumulative Update for separate components in SharePoint. Now, the server-packages (also known as “Uber” packages) of April Cumulative Update for Microsoft Office SharePoint Server 2007 and Windows SharePoint Services 3.0 are ready for download. Download Information Windows SharePoint Services 3.0 April cumulative update package http://support.microsoft.com/hotfix/KBHotfix.aspx?kbnum=968850 Office SharePoint Server 2007 April cumulative update package http://support.microsoft.com/hotfix/KBHotfix.aspx?kbnum=968851 Detail Description Description of the Windows SharePoint Services 3.0 April cumulative update package http://support.microsoft.com/kb/968850 Description of the Office SharePoint Server 2007 April cumulative update package http://support.microsoft.com/kb/968851 Installation Recommendation for a fresh SharePoint Server To keep all files in a SharePoint installation up-to-date, the following sequence is recommended. Service Pack 2 for Windows SharePoint Services 3.0 Service Pack 2 for Office SharePoint Server 2007 April Cumulative Update package for Windows SharePoint Services 3.0 April Cumulative Update package for Office SharePoint Server 2007 Please note: Start from April Cumulative Update, the packages will no longer install on a farm without a service pack installed. You must have installed either Service Pack 1 (SP1) or SP2 prior to the installation of the cumulative updates. After applying the preceding updates, run the SharePoint Products and Technologies Configuration Wizard or “psconfig –cmd upgrade –inplace b2b -wait” in command line. This needs to be done on every server in the farm with SharePoint installed.  The version of content databases should be 12.0.6504.5000 after successfully applying these updates. For more in-depth guidance for the update process, we recommend that customers refer to the following articles. These articles provide a correct way to deploy updates, identify known issues (and resolutions), and provide information about creating slipstream builds. Deploy software updates for Windows SharePoint Services 3.0 http://technet.microsoft.com/en-us/library/cc288269.aspx Deploy software updates for Office SharePoint Server 2007 http://technet.microsoft.com/en-us/library/cc263467.aspx Create an installation source that includes software updates (Windows SharePoint Services 3.0) http://technet.microsoft.com/en-us/library/cc287882.aspx Create an installation source that includes software updates (Office SharePoint Server 2007) http://technet.microsoft.com/en-us/library/cc261890.aspx

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  • SharePoint - Unable to complete this operation. Please contact your administrator

    - by Linda
    When I try and save something to my list in SharePoint I get the following error: Unable to complete this operation. Please contact your administrator. at Microsoft.SharePoint.Library.SPRequestInternalClass.PutFile(String bstrUrl, String bstrWebRelativeUrl, Object varFile, PutFileOpt PutFileOpt, String bstrCreatedBy, String bstrModifiedBy, Int32 iCreatedByID, Int32 iModifiedByID, Object varTimeCreated, Object varTimeLastModified, Object varProperties, String bstrCheckinComment, UInt32& pdwVirusCheckStatus, String& pVirusCheckMessage) at Microsoft.SharePoint.Library.SPRequest.PutFile(String bstrUrl, String bstrWebRelativeUrl, Object varFile, PutFileOpt PutFileOpt, String bstrCreatedBy, String bstrModifiedBy, Int32 iCreatedByID, Int32 iModifiedByID, Object varTimeCreated, Object varTimeLastModified, Object varProperties, String bstrCheckinComment, UInt32& pdwVirusCheckStatus, String& pVirusCheckMessage) A quick google says it may be a problem with disk space on the Database. I have checked my server and the smallest amount of space left on any of the drives is ~4GB. The file size is 1MB. I have checked the database and the data file is on unrestricted growth. Any ideas?

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