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  • How to teach Django to non-web programmers? [closed]

    - by Greg
    I've been tasked with providing a workshop for my co-workers to teach them Django. They're all good programmers but they've never done any web programming. I was thinking to just go through the Django tutorial with them, but are there things in there that wouldn't make sense to non-web programmers? Do they need any kind of webdev background first? Any thoughts on a good way to provide the basics so that Django will make sense?

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  • Using Django.test.client to check template vars

    - by scott
    I've got a view that I'm trying to test with the Client object. Can I get to the variables I injected into the render_to_response of my view? Example View: def myView(request): if request.method == "POST": # do the search return render_to_response('search.html',{'results':results},context_instance=RequestContext(request)) else: return render_to_response('search.html',context_instance=RequestContext(request) Test: c = Client() response = c.post('/school/search/', {'keyword':'beagles'}) # how do I get to the 'results' variable??

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  • django join querysets from multiple tables

    - by dana
    if i have queries on multiple tables like: d = Relations.objects.filter(follow = request.user).filter(date_follow__lt = last_checked) r = Reply.objects.filter(reply_to = request.user).filter(date_reply__lt = last_checked) article = New.objects.filter(created_by = request.user) vote = Vote.objects.filter(voted = article).filter(date__lt = last_checked) and i want to display the results from all of them ordered by date (i mean not listing all the replies, then all the votes, etc ). Somehow, i want to 'join all these results', in a single queryset. Is there possible?

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  • How to make my view better to save Django

    - by user558251
    Hy guys sorry for this post but i need help with my application, i need optimize my view. I have 5 models, how i can do this? def save(request): # get the request.POST in content if request.POST: content = request.POST dicionario = {} # create a dict to get the values in content for key,value in content.items(): # get my fk Course.objects if key == 'curso' : busca_curso = Curso.objects.get(id=value) dicionario.update({key:busca_curso}) else: dicionario.update({key:value}) #create the new teacher Professor.objects.create(**dicionario) my questions are? 1 - How i can do this function in a generic way? Can I pass a variable in a %s to create and get? like this way ? foo = "Teacher" , bar = "Course" def save(request, bar, foo): if request post: ... if key == 'course' : get_course = (%s.objects.get=id=value) %bar ... (%s.objects.create(**dict)) %foo ??? i tried do this in my view but don't work =/, can somebody help me to make this work ? Thanks

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  • Best way Implement "refferal links" in Django

    - by Murkin
    Intro I am working on an e-commerce website. And we want to add a feature where a user can refer others via a custom link e.g.: http://mysite.com/a1t2312 or http://mysite.com/?ref=a1t2312 (a1t231 being the referral code). A user following such a link, will navigate a few pages on the site. And if he reached the 'buy' page and purchases something - the original referrer will get a discount. The question is: What is the best method to track the referral code ? Put it in the user's cookies ? Stick it somehow into the session ? Other method ? Thanks

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  • Django: How to write the reverse function for the following

    - by ninja123
    The urlconf and view is as follows: url(r'^register/$', register, { 'backend': 'registration.backends.default.DefaultBackend' }, name='registration_register'), def register(request, backend, success_url=None, form_class=None, disallowed_url='registration_disallowed', template_name='registration/registration_form.html', extra_context=None): What i want to do is redirect users to the register page and specify a success_url. I tried reverse('registration.views.register', kwargs={'success_url':'/test/' }) but that doesn't seem to work. I've been trying for hours and can't get my mind around getting it right. Thanks

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  • Django: auto minifying css/js files before release

    - by Dzida
    Hi, I have following case: I want to use uncompressed js/css files during development (to debug js for example) but on production I want to switch automatically to minified versions of that files. some simple solution is to put in your template: <script src="some_js.{% if not debug %}min.{% endif %}js".... but this require manully providing that such file exist and to do minifaction manullay after original file change. How do you accomplish this in your projects? Is there any tool for this?

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  • Django populate select field based on model query

    - by Mike
    I have the following model class DNS(models.Model): domain = models.ForeignKey(Domain) host_start = models.CharField(max_length=150, blank=True, null=True) type = models.SmallIntegerField(max_length=1, default=0, choices=DNS_CHOICE) value = models.SmallIntegerField(max_length=3, default=0, blank=True, null=True) ip = models.IPAddressField(blank=True, null=True) host_end = models.ForeignKey("DNS", blank=True, null=True) other_end = HostnameField(max_length=150, blank=True, null=True) created = models.DateTimeField(auto_now_add=True) sticky = models.BooleanField(default=0) other = models.BooleanField(default=0) When I try to init a form with just foreignkeys on host_end.. it always shows all entries in the DNS table domain = Domain.objects.get(id=request.GET['domain'], user=request.user, active=1) form = DNSFormCNAME(initial={'ip': settings.MAIN_IP, 'type': request.GET['type'], 'host_end': DNS.objects.filter(domain=domain)}) I just want the zones that match that domain.. not all domains.

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  • Need help optimizing this Django aggregate query

    - by Chris Lawlor
    I have the following model class Plugin(models.Model): name = models.CharField(max_length=50) # more fields which represents a plugin that can be downloaded from my site. To track downloads, I have class Download(models.Model): plugin = models.ForiegnKey(Plugin) timestamp = models.DateTimeField(auto_now=True) So to build a view showing plugins sorted by downloads, I have the following query: # pbd is plugins by download - commented here to prevent scrolling pbd = Plugin.objects.annotate(dl_total=Count('download')).order_by('-dl_total') Which works, but is very slow. With only 1,000 plugins, the avg. response is 3.6 - 3.9 seconds (devserver with local PostgreSQL db), where a similar view with a much simpler query (sorting by plugin release date) takes 160 ms or so. I'm looking for suggestions on how to optimize this query. I'd really prefer that the query return Plugin objects (as opposed to using values) since I'm sharing the same template for the other views (Plugins by rating, Plugins by release date, etc.), so the template is expecting Plugin objects - plus I'm not sure how I would get things like the absolute_url without a reference to the plugin object. Or, is my whole approach doomed to failure? Is there a better way to track downloads? I ultimately want to provide users some nice download statistics for the plugins they've uploaded - like downloads per day/week/month. Will I have to calculate and cache Downloads at some point? EDIT: In my test dataset, there are somewhere between 10-20 Download instances per Plugin - in production I expect this number would be much higher for many of the plugins.

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  • Is there a way to ignore Cache errors in Django?

    - by Josh Smeaton
    I've just set our development Django site to use redis for a cache backend and it was all working fine. I brought down redis to see what would happen, and sure enough Django 404's due to cache backend behaviour. Either the Connection was refused, or various other errors. Is there any way to instruct Django to ignore Cache errors, and continue processing the normal way? It seems weird that caching is a performance optimization, but can bring down an entire site if it fails. I tried to write a wrapper around the backend like so: class CacheClass(redis_backend.CacheClass): """ Wraps the desired Cache, and falls back to global_settings default on init failure """ def __init__(self, server, params): try: super(CacheClass, self).__init__(server, params) except Exception: from django.core import cache as _ _.cache = _.get_cache('locmem://') But that won't work, since I'm trying to set the cache type in the call that sets the cache type. It's all a very big mess. So, is there any easy way to swallow cache errors? Or to set the default cache backend on failure?

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  • Django: ordering numerical value with order_by

    - by h3
    I'm in a situation where I must output a quite large list of objects by a CharField used to store street addresses. My problem is, that obviously the data is ordered by ASCII codes since it's a Charfield, with the predictable results .. it sort the numbers like this; 1, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 2, 20, 21.... Now the obvious step would be to change the Charfield the proper field type (IntegerField let's say), however it cannot work since some address might have apartments .. like "128A". I really don't know how I can order this properly ..

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  • Django display notifications by day

    - by dana
    hi guys, i have a notification list, and i want to order them by day, meaning, that i want to have in my notification list every day a title like 'Monday 16th od September' and the notifications for that day. I did not find anywhere how it should be done thanks a lot!

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  • Django | How to pass form values to an redirected page

    - by MMRUser
    Here's my function: def check_form(request): if request.method == 'POST': form = UsersForm(request.POST) if form.is_valid(): cd = form.cleaned_data try: newUser = form.save() return HttpResponseRedirect('/testproject/summery/) except Exception, ex: # sys.stderr.write('Value error: %s\n' % str(ex) return HttpResponse("Error %s" % str(ex)) else: return render_to_response('index.html', {'form': form}, context_instance=RequestContext(request)) else: form = CiviguardUsersForm() return render_to_response('index.html',context_instance=RequestContext(request)) I want to pass each and every field in to a page call summery and display all the fields when user submits the form, so then users can view it before confirming the registration. Thanks..

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  • Customizing Django Form: Required and InputId?

    - by Mark
    I'm trying to customize how my form is displayed by using a form_snippet as suggested in the docs. Here's what I've come up with so far: {% for field in form %} <tr> <th><label for="{{ field.html_name }}">{{ field.label }}:</label></th> <td> {{ field }} {% if field.help_text %}<br/><small class="help_text">{{ field.help_text }}</small>{% endif %} {{ field.errors }} </td> </tr> {% endfor %} Of course, field.html_name is not what I'm looking for. I need the id of the input field. How can I get that? Also, is there a way I can determine if the field is required, so that I can display an asterisk beside the label?

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  • django accessing class variables in a view

    - by dana
    hello, i want to make a notification function, and i need fields from 2 different models. how can i access those fields? in my notification view i wrote this data = Notices.objects.filter(last_login<date_follow) where last_login belongs to the model class User , and date_follow to Follow but it is not a proper and correct way of accessing those variables. How can i access them? I need to compare the two dates for realising the notifications that one did not see since his last login. Thanks!

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  • Adding fields to Django form dynamically (and cleanly)

    - by scott
    Hey guys, I know this question has been brought up numerous times, but I'm not quite getting the full implementation. As you can see below, I've got a form that I can dynamically tell how many rows to create. How can I create an "Add Row" link that tells the view how many rows to create? I would really like to do it without augmenting the url... # views.py def myView(request): if request.method == "POST": form = MyForm(request.POST, num_rows=1) if form.is_valid(): return render_to_response('myform_result.html', context_instance=RequestContext(request)) else: form = MyForm(num_rows=1) return render_to_response('myform.html', {'form':form}, context_instance=RequestContext(request)) # forms.py class MyForm(forms.Form): def __init__(self, *args, **kwargs): num_rows = kwargs.pop('num_rows',1) super(MyForm, self).__init__(*args, **kwargs) for row in range(0, num_rows): field = forms.CharField(label="Row") self.fields[str(row)] = field # myform.html http://example.com/myform <form action="." method="POST" accept-charset="utf-8"> <ul> {% for field in form %} <li style="margin-top:.25em"> <span class="normal">{{ field.label }}</span> {{ field }} <span class="formError">{{ field.errors }}</span> </li> {% endfor %} </ul> <input type="submit" value="Save"> </form> <a href="ADD_ANOTHER_ROW?">+ Add Row</a>

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  • is it safe to refactor my django models?

    - by Johnd
    My model is similar to this. Is this ok or should I make the common base class abstract? What are the differcenes between this or makeing it abstract and not having an extra table? It seems odd that there is only one primary key now that I have factored stuff out. class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) pub_date = models.DateTimeField('date published') rating = models.IntegerField() def __unicode__(self): return self.details class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() is this ok to factor stuff out intpu Input? I noticed Cases and Arguments share a primary Key. like this: CREATE TABLE "cases_input" ( "id" integer NOT NULL PRIMARY KEY, "details" varchar(1000) NOT NULL, "user_id" integer NOT NULL REFERENCES "auth_user" ("id"), "pub_date" datetime NOT NULL, "rating" integer NOT NULL ) ; CREATE TABLE "cases_case" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "title" varchar(200) NOT NULL, "views" integer NOT NULL ) ; CREATE TABLE "cases_argument" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "case_id" integer NOT NULL REFERENCES "cases_case" ("input_ptr_id"), "side" bool NOT NULL )

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  • Django: HTTPS for just login page?

    - by Mark
    I just added this SSL middleware to my site http://www.djangosnippets.org/snippets/85/ which I used to secure only my login page so that passwords aren't sent in clear-text. Of course, when the user navigates away from that page he's suddenly logged out. I understand why this happens, but is there a way to pass the cookie over to HTTP so that users can stay logged in? If not, is there an easy way I can use HTTPS for the login page (and maybe the registration page), and then have it stay on HTTPS if the user is logged in, but switch back to HTTP if the user doesn't log in? There are a lot of pages that are visible to both logged in users and not, so I can't just designate certain pages as HTTP or HTTPS.

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