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  • A more elegant way to parse a string with ruby regular expression using variable grouping?

    - by i0n
    At the moment I have a regular expression that looks like this: ^(cat|dog|bird){1}(cat|dog|bird)?(cat|dog|bird)?$ It matches at least 1, and at most 3 instances of a long list of words and makes the matching words for each group available via the corresponding variable. Is there a way to revise this so that I can return the result for each word in the string without specifying the number of groups beforehand? ^(cat|dog|bird)+$ works but only returns the last match separately , because there is only one group.

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  • Passing parameter to base class constructor or using instance variable?

    - by deamon
    All classes derived from a certain base class have to define an attribute called "path". In the sense of duck typing I could rely upon definition in the subclasses: class Base: pass # no "path" variable here def Sub(Base): def __init__(self): self.path = "something/" Another possiblity would be to use the base class constructor: class Base: def __init__(self, path): self.path = path def Sub(Base): def __init__(self): super().__init__("something/") What would you prefer and why? Is there a better way?

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  • Python parsing error message functions

    - by user1716168
    The code below was created by me with the help of many SO veterans: The code takes an entered math expression and splits it into operators and operands for later use. I have created two functions, the parsing function that splits, and the error function. I am having problems with the error function because it won't display my error messages and I feel the function is being ignored when the code runs. An error should print if an expression such as this is entered: 3//3+4,etc. where there are two operators together, or there are more than two operators in the expression overall, but the error messages dont print. My code is below: def errors(): numExtrapolation,opExtrapolation=parse(expression) if (len(numExtrapolation) == 3) and (len(opExtrapolation) !=2): print("Bad1") if (len(numExtrapolation) ==2) and (len(opExtrapolation) !=1): print("Bad2") def parse(expression): operators= set("*/+-") opExtrapolate= [] numExtrapolate= [] buff=[] for i in expression: if i in operators: numExtrapolate.append(''.join(buff)) buff= [] opExtrapolate.append(i) opExtrapolation=opExtrapolate else: buff.append(i) numExtrapolate.append(''.join(buff)) numExtrapolation=numExtrapolate #just some debugging print statements print(numExtrapolation) print("z:", len(opExtrapolation)) return numExtrapolation, opExtrapolation errors() Any help would be appreciated. Please don't introduce new code that is any more advanced than the code already here. I am looking for a solution to my problem... not large new code segments. Thanks.

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  • How to store the hostname in a variable in a .bat file?

    - by eqbridges
    I would like to convert this /bin/sh syntax into a widely compatible Windows batch script: host=`hostname` echo ${host} How to do this so that it'll work on any Windows Vista, Windows XP, and Windows 2000 machine? To clarify: I would then like to go on in the program and use the hostname as stored in the variable host. In other words, the larger goal of the program is not to simply echo the hostname.

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  • In C++, what happens when you return a variable?

    - by wowus
    What happens, step by step, when a variable is returned. I know that if it's a built-in and fits, it's thrown into rax/eax/ax. What happens when it doesn't fit, and/or isn't built-in? More importantly, is there a guaranteed copy constructor call? edit: What about the destructor? Is that called "sometimes", "always", or "never"?

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  • Why does 'url' not work as a variable here?

    - by kryptobs2000
    I originally had the variable cpanel named url and the code would not return anything. Any idea why? It doesn't seem to be used by anything else, but there's gotta be something I'm overlooking. import urllib2 cpanel = 'http://www.tas-tech.com/cpanel' req = urllib2.Request(cpanel) try: handle = urllib2.urlopen(req) except IOError, e: if hasattr(e, 'code'): if e.code != 401: print 'We got another error' print e.code else: print e.headers print e.headers['www-authenticate']

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  • How can I save shell output to a variable in LaTeX?

    - by Frank
    I need to be able to execute a shell command through LaTeX [*] and have the resulting output available for use later on in the form of a LaTeX 'variable' (e.g., via a subsequent \newcommand command). If necessary a temporary file could be used to hold the output, although I would like to avoid this. I have been able to use \immediate\write18 to invoke a bash command before, but this was only used to write to a temporary file. [*] I realise that the -shell-escape flag must be set for this to be allowed

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  • is it correct to unset the session variable for a particular index as the vay whole session is made

    - by OM The Eternity
    is it correct to unset the session variable for a particular index as the vay whole session is made unset in PHP? I know this works: unset($_SESSION['bannersize']) But does this works ? : unset($_SESSION['bannersize'][3]) or is there any other way to unset any particular desired index of the session and then again rearrange the values inside it to remove the empty index..?

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  • Why can't i define recursive variable in code block?

    - by senia
    Why can't i define a variable recursively in a code block? scala> { | val fibs: Stream[Int] = 1 #:: fibs.scanLeft(1){_ + _} | } <console>:9: error: forward reference extends over definition of value fibs val fibs: Stream[Int] = 1 #:: fibs.scanLeft(1){_ + _} ^ scala> val fibs: Stream[Int] = 1 #:: fibs.scanLeft(1){_ + _} fibs: Stream[Int] = Stream(1, ?) lazy keyword solves this problem, but i can't understand why it works without a code block but throws a compilation error in a code block.

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