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  • Rails, Apache2 on Ubuntu (karmic) deployment

    - by Steve
    I just need some clarification on a couple of files. My site has an admin subdomain and SSL in addition to the normal *:80 details found in the virtual hosts. My question(s): Do I need to specify a 1) ServerName and 2) DocumentRoot in: /etc/apache2/apache2.conf? I currently enable my site from this directory: /etc/apache2/sites-available/site Here are the contents of my site file in the above directory (/etc/apache2/sites-available/site): <VirtualHost *:80> ServerName www.site.com ServerAlias www.site.com DocumentRoot /home/user/public_html/site/current/public RailsAllowModRewrite off <directory "/home/user/public_html/site/current/public"> Order allow,deny Allow from all </directory> </VirtualHost> <VirtualHost *:80> ServerName www.site.com ServerAlias admin.site.com DocumentRoot /home/user/public_html/site/current/public RailsAllowModRewrite off <directory "/home/user/public_html/site/current/public"> Order allow,deny Allow from all </directory> </VirtualHost> <VirtualHost *:443> ServerName www.site.com ServerAlias www.site.com # SSL releated SSLEngine on SSLOptions +FakeBasicAuth +ExportCertData +StrictRequire SSLCertificateFile /path/to/site.com.crt SSLCertificateChainFile /path/to/bundle.crt SSLCertificateKeyFile /path/to/site.key # Used by rails RequestHeader set X_FORWARDED_PROTO "https" </VirtualHost> Do you see anything wrong?

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  • Django + Apache wsgi = paths problem

    - by Shamanu4
    Hello. I have this view which generates interface language options menu def lang_menu(request,language): lang_choices = [] import os.path for lang in settings.LANGUAGES: if os.path.isfile("gui/%s.py" % lang) or os.path.isfile("gui/%s.pyc" % lang): langimport = "from gui.%s import menu" % lang try: exec(langimport) except ImportError: lang_choices.append({'error':'invalid language file'}) else: lang_choices.append(menu) else: lang_choices.append({'error':'lang file not found'}) t = loader.get_template('gui/blocks/lang_menu_options.html') data = '' for lang in lang_choices: if not 'error' in lang: data = "%s\n%s" % (data,t.render(Context(lang))) if not data: data = "Error! No languages configured or incorrect language files!" return Context({'content':data}) When I'am using development server (python manage.py runserver ...) it works fine. But when I ported my app to apache wsgi server I've got error "No languages configured or incorrect language files!" Here is my Apache config <VirtualHost *:9999> WSGIScriptAlias / "/usr/local/etc/django/terminal/django.wsgi" <Directory "/usr/local/etc/django/terminal"> Options +ExecCGI Allow From All </Directory> Alias /media/ "/usr/local/lib/python2.5/site-packages/django/contrib/admin/media/" <Location /media/> SetHandler None </Location> <Directory "/usr/local/lib/python2.5/site-packages/django/contrib/admin/media/> Allow from all </Directory> Alias /static/ "/usr/local/etc/django/terminal/media/" <Location /static/> SetHandler None </Location> ServerName ******* ServerAlias ******* ErrorLog /var/log/django.error.log TransferLog /var/log/django.access.log </VirtualHost> django.wsgi: import os, sys sys.path.append('/usr/local/etc/django') sys.path.append('/usr/local/etc/django/terminal') os.environ['DJANGO_SETTINGS_MODULE'] = 'terminal.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() It's look like as problem with path configuration but I'm stuck here ...

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  • Enter ID instead of name on submit (form)

    - by Derek
    In my activities table, I have a user ID and a project ID. When a user (of admin level) creates an activity they select from a drop down menu a project. Here is the select query to draw up appropriate values: $sql = "SELECT usersprojects_tb.projectid, projects.projectname FROM projects INNER JOIN usersprojects on projects.projectid = usersprojects.projectid WHERE usersprojects.userid = '".$_SESSION['SESS_USERID']."'"; And for the tag with the dropdown menu, I have this: <?php echo $row['projectname']?> I have tried submitting the form with 'projectid' here instead and the project ID is stored successfully in my activies table. However, the user needs to see the project names (IDs arent exactly user-friendly!) And with 'projectname' as displayed, they can select the names of the available projects (to associate an activity with) but the project ID is not stored, how I link this up, so that when the project name is sent, the ID for this project is stored properly in my activities table. I'm also having the exact same problem with the users drop down. As the admin user selects a user from the drop down to assign the task to. I exactly what I want, but I think I may be using the wrong syntax! Any help is much appreciated. Thanks.

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  • Form not sending full data

    - by gAMBOOKa
    I have a form with over 50 input fields. The input fields are divided into 5 jquery jabs within the form container. Here's a sample of what it looks like: <form action="admin/save" method="post" enctype="multipart/form-data"> <input type="hidden" name="type" value="department" /> <input type="hidden" name="id" value="21" /> <div id="tabs"> <ul> <li><a href="#tab-1">Tab 1</a><li> <li><a href="#tab-2">Tab 2</a><li> <li><a href="#tab-3">Tab 3</a><li> </ul> <div id="tab-1"> <label>Name</label> <input type="text" name="user-name" /> </div> <div id="tab-2"> <label>Address</label> <input type="text" name="user-address" /> </div> <div id="tab-3"> <label>Phone</label> <input type="text" name="user-phone" /> </div> </div> <input type="submit" value="Send" /> </form> I'm using PHP's Kohana framework, so admin maps to a controller, and save maps to the method action_save. When I output the $_POST variables in action_save, only 'type' and 'id' show up, all the other fields don't seem to submit their data. What could I be doing wrong?

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  • form layout in drupal from a module

    - by EricP
    I created my own module called "cssswitch". I'm trying to create my own html layout to display the admin form portion of the module. I understand how to use the hook_form_alter() to modify form elements, but I need to create the entire form layout to make some fields appear next to each other. It seems I need something like the way I have the frontend view of the node displayed with theme_cssswitch_display(), but for the admin part of the node. function cssswitch_form_alter(&$form, $form_state, $form_id) { switch($form_id) { case 'cssswitch_node_form': $form['hour_start']['#prefix'] = '<div class="start-box">'; $form['ampm_start']['#suffix'] = '</div>'; $form['ampm_start']['#attributes'] = array("style" => "border-width:2px;"); break; } } function cssswitch_theme() { return array( 'cssswitch_display' => array( 'arguments' => array('node'), ), ); } // to display the view of the node function theme_cssswitch_display($node) { $output = '<div class="cssswitch-cssfilename">Filename: '. check_plain($node->cssfilename). '</div>'; $output .= '<div class="cssswitch-time_start">Start: '. check_plain($node->hour_start). ':'.check_plain($node->minute_start).' '.check_plain($node->ampm_start).'</div>'; $output .= '<div class="cssswitch-time_end">End: '. check_plain($node->hour_end). ':'.check_plain($node->minute_end).' '.check_plain($node->ampm_end).'</div>'; return $output; } thanks for any help

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  • Record Disappeared from Mysql Table, How Can I Find Out What Happened?

    - by Jascha
    I got the fire alarm phone call, AIM messages and email today from a client stating "The site is down!, WTF happened?!" Well, after a little digging, it turns out one of the records in a table had been wiped clean, but without removing the row itself. So, I had the representation of data, but a bunch of empty fields. (needless to day I need to write into my code a catch for this.) What my real question is, where can I figure out what happened? I've got access to phpmyadmin and that's about it. I found some access logs on in the root directory of my server, but that just tells me the client was in the admin area I built editing that record, I'd like to know specifically what they did that made all of the data go away. (what query was run etc...) is it possible without real server admin access? is there a neat little php to mysql class that returns data like this? Thanks in advance. -Jascha

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  • eclipse django using wrong settings.py in pythonpath

    - by user1290264
    I have pydev/django installed in eclipse, and it runs fine. However, after adding a second django project to eclipse and running the server ('http://127.0.0.1:8000') the pythonpath seems to be stuck on project2 even when I run project1. As a summary, I have two django projects: project1, project2. When I run the django server for project1 I get: Validating models... 0 errors found Django version 1.5, using settings 'project1.settings' Development server is running at 'http://127.0.0.1:8000/' Quit the server with CTRL-BREAK. The above seems to suggest that django is using the correct settings file; however, when I go to 'http://127.0.0.1:8000/' it displays the urls from project2. Also, if I go to 'http://127.0.0.1:8000/admin' the models are getting pulled from the sqlite.db file in project2 as well. I've even tried removing project2 from eclipse entirely and now at 'http://127.0.0.1:8000/admin' I get this error: Python Path: ['C:\Users\Brad\workspaces\In Progress\project2', 'C:\Users\Brad\workspaces\In Progress\project2', 'C:\Python27\DLLs', 'C:\Python27\lib', 'C:\Python27\lib\plat-win', 'C:\Python27\lib\lib-tk', 'C:\Python27', 'C:\Python27\lib\site-packages', 'C:\Windows\system32\python27.zip'] If I run the server on a different port with project1 the path seems to be fine: runserver 7000 --noreload Then 'http://127.0.0.1:7000/' uses project1's paths, but it doesn't seem like I should have to do this. Note: I have setup the run configurations as correctly as I know how. In the main tab, the project and main module both point to the correct project (project1), and the "PYTHONPATH that will be used in the run:" includes project1. Also, I have cleared my browser history, cookies, and everything that chrome would let me delete.

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  • Django error - no module named

    - by Shreyas
    Here is my relevant directory structure (Windows 7, Python 2.7, virtualenv) -userProf - - manage.py - -UserProfile - sampleapp_db - urls.py - views.py - wsgi.py - __init__.py - -libs - - __init__.py - -allauth - - app_settings.py - - models.py - - tests.py - - urls.py - - utils.py - - - -account - - - admin.py - - - context_processors.py - - - models.py - - - urls.py - - - __init__.py - -socialaccount - - - admin.py - - - context_processors.py - - - models.py - - - urls.py - - - views.py - - - __init__.py - - - - -templates - -account - - - base.html - - - email.html -settings - base_settings.py - dev.py - __init__.py - -static -css I get the following error when I try to run this dango app Error: No module named account I have read other posts on SO that refer to the syspath being the issue or that the appname matches the project name Django Shell No module named settings ...as a result of this, I added the following statements in the base_settings.py file import sys base = os.path.abspath(os.path.dirname(os.path.dirname(__file__))) base_parent = os.path.dirname(base) sys.path.append(base) sys.path.append(base_parent) sys.path.append(os.path.join(base,'libs')) sys.path.append(os.path.join(base,'libs','allauth','account')) I verified that the sys.path is correct by putting a break in PyCharm and evaluating sys.path Should I be putting this in manage.py? Some other SO postings referred to not being able to import the module but I can launch the python console and import UserProfile.libs.allauth.account without any exceptions being thrown! My base_setings.py has the following relevant section INSTALLED_APPS = ( 'UserProfile.libs.allauth.account', )

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  • PHP DOMDocument getElementsByTagname??

    - by FFish
    This is driving me bonkers... I just want to add another img node. $xml = <<<XML <?xml version="1.0" encoding="UTF-8"?> <gallery> <album tnPath="tn/" lgPath="imm/" fsPath="iml/" > <img src="004.jpg" caption="4th caption" /> <img src="005.jpg" caption="5th caption" /> <img src="006.jpg" caption="6th caption" /> </album> </gallery> XML; $xmlDoc = new DOMDocument(); $xmlDoc->loadXML($xml); $album = $xmlDoc->getElementsByTagname('album')[0]; // Parse error: syntax error, unexpected '[' in /Applications/XAMPP/xamppfiles/htdocs/admin/tests/DOMDoc.php on line 17 $album = $xmlDoc->getElementsByTagname('album'); // Fatal error: Call to undefined method DOMNodeList::appendChild() in /Applications/XAMPP/xamppfiles/htdocs/admin/tests/DOMDoc.php on line 19 $newImg = $xmlDoc->createElement("img"); $album->appendChild($newImg); print $xmlDoc->saveXML(); Error:

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  • Authentification-None for one folder(page) when the project is under FormsAuthentifications

    - by Sirius Lampochkin
    I have a WebApplication on asp.net 2.0 with namespace Admin. I have Form Authentification mode for the project. <authentication mode="Forms"> <forms name="ASP_XML_Form" loginUrl="Login.aspx" protection="All" timeout="30" path="/" requireSSL="false" slidingExpiration="true" cookieless="AutoDetect"> </forms> </authentication> Now, I try to share one folder (one inside page) for not Authentificatied users: <location path="Recovery"> <system.web> <roleManager enabled="false" > </roleManager> <authentication mode="None"> </authentication> <authorization> <allow users="*" /> </authorization> <httpHandlers> <remove verb="GET" path="image.aspx" /> <remove verb="GET" path="css.aspx" /> </httpHandlers> </system.web> </location> But when I create the page inside the shared folder, it can't get access to the assembly. And I see the error like this: Could not load file or assembly 'Admin' or one of its dependencies. The system cannot find the file specified. It also shows me the error: ASP.NET runtime error: It is an error to use a section registered as allowDefinition='MachineToApplication' beyond application level. This error can be caused by a virtual directory not being configured as an application in IIS. Does anybody know how to share (Authentification None) one folder(page) when the project is under FormsAuthentifications?

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  • jscript1.js error in webforms when applying routing

    - by Sean N
    Hello I have a project using webforms. I applied routing on one of the page. My route is structure like this : http://localhost:3576/Request/Admin/Rejected/ = http://localhost:3576/Request/{role}/{action}/{id} Everything works great but i have a javascript error: Webpage error details User Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; .NET CLR 1.1.4322; .NET CLR 2.0.50727; .NET CLR 3.0.04506.30; .NET CLR 3.0.04506.648; .NET CLR 3.5.21022; InfoPath.2; .NET CLR 3.0.4506.2152; .NET CLR 3.5.30729) Timestamp: Fri, 7 May 2010 13:35:54 UTC Message: Syntax error Line: 3 Char: 1 Code: 0 URI: http://localhost:3576/Request/Admin/Rejected/JScript1.js I think it's trying to route to the file where i stored my javascript functions. Any suggestion?

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  • Using Doctrine to abstract CRUD operations

    - by TomWilsonFL
    This has bothered me for quite a while, but now it is necessity that I find the answer. We are working on quite a large project using CodeIgniter plus Doctrine. Our application has a front end and also an admin area for the company to check/change/delete data. When we designed the front end, we simply consumed most of the Doctrine code right in the controller: //In semi-pseudocode function register() { $data = get_post_data(); if (count($data) && isValid($data)) { $U = new User(); $U->fromArray($data); $U->save(); $C = new Customer(); $C->fromArray($data); $C->user_id = $U->id; $C->save(); redirect_to_next_step(); } } Obviously when we went to do the admin views code duplication began and considering we were in a "get it DONE" mode so it now stinks with code bloat. I have moved a lot of functionality (business logic) into the model using model methods, but the basic CRUD does not fit there. I was going to attempt to place the CRUD into static methods, i.e. Customer::save($array) [would perform both insert and update depending on if prikey is present in array], Customer::delete($id), Customer::getObj($id = false) [if false, get all data]. This is going to become painful though for 32 model objects (and growing). Also, at times models need to interact (as the interaction above between user data and customer data), which can't be done in a static method without breaking encapsulation. I envision adding another layer to this (exposing web services), so knowing there are going to be 3 "controllers" at some point I need to encapsulate this CRUD somewhere (obviously), but are static methods the way to go, or is there another road? Your input is much appreciated.

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  • SQL Server database change workflow best practices

    - by kubi
    The Background My group has 4 SQL Server Databases: Production UAT Test Dev I work in the Dev environment. When the time comes to promote the objects I've been working on (tables, views, functions, stored procs) I make a request of my manager, who promotes to Test. After testing, she submits a request to an Admin who promotes to UAT. After successful user testing, the same Admin promotes to Production. The Problem The entire process is awkward for a few reasons. Each person must manually track their changes. If I update, add, remove any objects I need to track them so that my promotion request contains everything I've done. In theory, if I miss something testing or UAT should catch it, but this isn't certain and it's a waste of the tester's time, anyway. Lots of changes I make are iterative and done in a GUI, which means there's no record of what changes I made, only the end result (at least as far as I know). We're in the fairly early stages of building out a data mart, so the majority of the changes made, at least count-wise, are minor things: changing the data type for a column, altering the names of tables as we crystallize what they'll be used for, tweaking functions and stored procs, etc. The Question People have been doing this kind of work for decades, so I imagine there have got to be a much better way to manage the process. What I would love is if I could run a diff between two databases to see how the structure was different, use that diff to generate a change script, use that change script as my promotion request. Is this possible? If not, are there any other ways to organize this process? For the record, we're a 100% Microsoft shop, just now updating everything to SQL Server 2008, so any tools available in that package would be fair game.

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  • Create xml file to be used in wordpress post import

    - by adedoy
    Alright here is the thing, I have this site that was once wordpress but have been converted into 70+ static pages, the admin is deleted and the whole site is static(which means every page is in index.html), I want to create a script that makes an xml so that I will just have to import it in the new wordpress install. So far, I am able to create an XML but it only imports one post. The data source is the URL of a page and I use jquery $get to filter only to gather the post of a given archive. //html <input type="text" class="full_path"> <input type="button" value="Get Data" class="getdata"> //script $('.getdata').click(function(){ $.get($('.full_path').val(), function(data) { post = $(data).find('div [style*="width:530px;"]'); $('.result').html(post.html()); }); });//get Data Through AJAX I send the cleaned data into a php below that creates the XML: $file = 'newpost.xml'; $post_data = $_REQUEST['post_data']; // Open the file to get existing content $current = file_get_contents($file); // Append a new post to the file $catStr = ''; if(isset($post_data['categories']) && count($post_data['categories']) > 0){ foreach($post_data['categories'] as $category) { $catStr .= '<category domain="category" nicename="'.$category.'"><![CDATA['.$category.']]></category>'; } } $tagStr = ''; if(isset($post_data['tags']) && count($post_data['tags']) > 0){ foreach($post_data['tags'] as $tag) { $tagStr = '<category domain="post_tag" nicename="'.$tag.'"><![CDATA['.$tag.']]></category>'; } } $post_name = str_replace(' ','-',$post_data["title"]); $post_name = str_replace(array('"','/',':','.',',','[',']','“','”'),'',strtolower($post_name)); $post_date = '2011-4-0'.rand(1, 29).''.rand(1, 12).':'.rand(1, 59).':'.rand(1, 59); $pubTime = rand(1, 12).':'.rand(1, 59).':'.rand(1, 59).' +0000'; $post = ' <item> <title>'.$post_data["title"].'</title> <link>'.$post_data["link"].'</link> <pubDate>'.$post_data["date"].' '.$pubTime.'</pubDate> <dc:creator>admin</dc:creator> <guid isPermaLink="false">http://localhost/saunders/?p=1</guid> <description></description> <content:encoded><![CDATA['.$post_data["content"].']]></content:encoded> <excerpt:encoded><![CDATA[]]></excerpt:encoded> <wp:post_id>1</wp:post_id> <wp:post_date>'.$post_date.'</wp:post_date> <wp:post_date_gmt>'.$post_date.'</wp:post_date_gmt> <wp:comment_status>open</wp:comment_status> <wp:ping_status>open</wp:ping_status> <wp:post_name>'.$post_name.'</wp:post_name> <wp:status>publish</wp:status> <wp:post_parent>0</wp:post_parent> <wp:menu_order>0</wp:menu_order> <wp:post_type>post</wp:post_type> <wp:post_password></wp:post_password> <wp:is_sticky>0</wp:is_sticky> '.$catStr.' '.$tagStr.' <wp:postmeta> <wp:meta_key>_edit_last</wp:meta_key> <wp:meta_value><![CDATA[1]]></wp:meta_value> </wp:postmeta> </item> '; // Write the contents back to the file with the appended post file_put_contents($file, $current.$post); After being appended I add the code below to complete the xml rss tag </channel> </rss> If I look and compare the xml file of one that is exported from a wordpress site, I see little difference. Please HELP!! here is a sample of a generated xml: <?xml version="1.0" encoding="UTF-8" ?> <rss version="2.0" xmlns:excerpt="http://wordpress.org/export/1.2/excerpt/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:wp="http://wordpress.org/export/1.2/" > <channel> <title>lols why</title> <link>http://localhost/lols</link> <description>Just another WordPress site</description> <pubDate>Wed, 03 Oct 2012 04:24:04 +0000</pubDate> <language>en-US</language> <wp:wxr_version>1.2</wp:wxr_version> <wp:base_site_url>http://localhost/lols</wp:base_site_url> <wp:base_blog_url>http://localhost/lols</wp:base_blog_url> <wp:author><wp:author_id>1</wp:author_id><wp:author_login>adedoy</wp:author_login><wp:author_email>[email protected]</wp:author_email><wp:author_display_name><![CDATA[adedoy]]></wp:author_display_name><wp:author_first_name><![CDATA[]]></wp:author_first_name><wp:author_last_name><![CDATA[]]></wp:author_last_name></wp:author> <generator>http://wordpress.org/?v=3.4.1</generator> <item> <title>Sample lift?</title> <link>../../breast-lift/delaware-breast-surgery-do-i-need-a-breast-lift/</link> <pubDate>Wed, 03 Oct 2012 9:29:16 +0000</pubDate> <dc:creator>admin</dc:creator> <guid isPermaLink="false">http://localhost/lols/?p=1</guid> <description></description> <content:encoded><![CDATA[<p>sample</p>]]></content:encoded> <excerpt:encoded><![CDATA[]]></excerpt:encoded> <wp:post_id>1</wp:post_id> <wp:post_date>2011-4-0132:45:4</wp:post_date> <wp:post_date_gmt>2011-4-0132:45:4</wp:post_date_gmt> <wp:comment_status>open</wp:comment_status> <wp:ping_status>open</wp:ping_status> <wp:post_name>sample-lift?</wp:post_name> <wp:status>publish</wp:status> <wp:post_parent>0</wp:post_parent> <wp:menu_order>0</wp:menu_order> <wp:post_type>post</wp:post_type> <wp:post_password></wp:post_password> <wp:is_sticky>0</wp:is_sticky> <category domain="category" nicename="Sample Lift"><![CDATA[Sample Lift]]></category><category domain="category" nicename="Sample Procedures"><![CDATA[Yeah Procedures]]></category> <category domain="post_tag" nicename="delaware"><![CDATA[delaware]]></category> <wp:postmeta> <wp:meta_key>_edit_last</wp:meta_key> <wp:meta_value><![CDATA[1]]></wp:meta_value> </wp:postmeta> </item> <item> <title>lalalalalala</title> <link>../../administrative-tips-for-surgery/delaware-cosmetic-surgery-a-better-experience/</link> <pubDate>Wed, 03 Oct 2012 3:20:43 +0000</pubDate> <dc:creator>admin</dc:creator> <guid isPermaLink="false">http://localhost/lols/?p=1</guid> <description></description> <content:encoded><![CDATA[ lalalalalala ]]></content:encoded> <excerpt:encoded><![CDATA[]]></excerpt:encoded> <wp:post_id>1</wp:post_id> <wp:post_date>2011-4-0124:39:30</wp:post_date> <wp:post_date_gmt>2011-4-0124:39:30</wp:post_date_gmt> <wp:comment_status>open</wp:comment_status> <wp:ping_status>open</wp:ping_status> <wp:post_name>lalalalalala</wp:post_name> <wp:status>publish</wp:status> <wp:post_parent>0</wp:post_parent> <wp:menu_order>0</wp:menu_order> <wp:post_type>post</wp:post_type> <wp:post_password></wp:post_password> <wp:is_sticky>0</wp:is_sticky> <category domain="category" nicename="lalalalalala"><![CDATA[lalalalalala]]></category> <category domain="post_tag" nicename="oink"><![CDATA[oink]]></category> <wp:postmeta> <wp:meta_key>_edit_last</wp:meta_key> <wp:meta_value><![CDATA[1]]></wp:meta_value> </wp:postmeta> </item> </channel> </rss> Please tell me what am I missing....

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  • Is there a way to customize how the value for a custom Model Field is displayed in a template?

    - by Jordan Reiter
    I am storing dates as an integer field in the format YYYYMMDD, where month or day is optional. I have the following function for formatting the number: def flexibledateformat(value): import datetime, re try: value = str(int(value)) except: return None match = re.match(r'(\d{4})(\d\d)(\d\d)$',str(value)) if match: year_val, month_val, day_val = [int(v) for v in match.groups()] if day_val: return datetime.datetime.strftime(datetime.date(year_val,month_val,day_val),'%b %e, %Y') elif month_val: return datetime.datetime.strftime(datetime.date(year_val,month_val,1),'%B %Y') else: return str(year_val) Which results in the following outputs: >>> flexibledateformat(20100415) 'Apr 15, 2010' >>> flexibledateformat(20100400) 'April 2010' >>> flexibledateformat(20100000) '2010' So I'm wondering if there's a function I can add under the model field class that would automatically call flexibledateformat. So if there's a record r = DataRecord(name='foo',date=20100400) when processed in the form the value would be 20100400 but when output in a template using {{ r.date }} it shows up as "April 2010". Further clarification I do normally use datetime for storing date/time values. In this specific case, I need to record non-specific dates: "x happened in 2009", "y happened sometime in June 1996". The easiest way to do this while still preserving most of the functionality of a date field, including sorting and filtering, is by using an integer in the format of yyyymmdd. That is why I am using an IntegerField instead of a DateTimeField. This is what I would like to happen: I store what I call a "Flexible Date" in a FlexibleDateField as an integer with the format yyyymmdd. I render a form that includes a FlexibleDateField, and the value remains an integer so that functions necessary for validating it and rendering it in widgets work correctly. I call it in a template, as in {{ object.flexibledate }} and it is formatted according to the flexibledateformat rules: 20100416 - April 16, 2010; 20100400 - April 2010; 20100000 - 2010. This also applies when I'm not calling it directly, such as when it's used as a header in admin (http://example.org/admin/app_name/model_name/). I'm not aware if these specific things are possible.

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  • A dropdownlist list in ASP.NET MVC although not [required] field shows up as required and Model Sta

    - by VJ
    I have the following code- View- <% Html.BeginForm(); %> <div> <%= Html.DropDownList("DropDownSelectList", new SelectList( Model.DropDownSelectList, "Value", "Text"))%> Controller- public ActionResult Admin(string apiKey, string userId) { ChallengesAdminViewModel vm = new ChallengesAdminViewModel(); vm.ApiKey = apiKey; vm.UserId = userId; vm.DropDownSelectList = new List<SelectListItem>(); vm.DropDownSelectList.Add(listItem1); vm.DropDownSelectList.Add(listItem2); vm.DropDownSelectList.Add(listItem3); vm.DropDownSelectList.Add(listItem4); vm.DropDownSelectList.Add(listItem5); vm.DropDownSelectList.Add(listItem6); vm.DropDownSelectList.Add(listItem7); } [HttpPost] public ActionResult Admin(ChallengesAdminViewModel vm) { if (ModelState.IsValid)//Due to the null dropdownlist gives model state invalid { } } ViewModel- public class ChallengesAdminViewModel { [Required] public string ApiKey { get; set; } [Required] public string UserId { get; set; } public List<SelectListItem> DropDownSelectList { get; set; } } I dont know why it still requires the list although not required. I want to have only two attributes as required. So I wanted to know how do i declare or change that list to be not required and have my Model State Valid.

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  • ACL architechture for a Software As a service in Sprgin 3.0

    - by geoaxis
    I am making a software as a service using Spring 3.0 (Spring MVC, Spring Security, Spring Roo, Hibernate) I have to come up with a flexible access control list mechanism.I have three different kinds of users System (who can do any thing to the system, includes admin and internal daemons) Operations (who can add and delete users, organizations, and do maintenance work on behalf of users and organizations) End Users (they belong to one or more organization, for each organization, the user can have one or more roles, like being organization admin, or organization read-only member) (role like orgadmin can also add users for that organization) Now my question is, how should i model the entity of User? If I just take the End User, it can belong to one or more organizations, so each user can contain a set of references to its organizations. But how do we model the users role for each organization, So for example User UX belongs to organizations og1, og2 and og3, and for og1 he is both orgadmin, and org-read-only-user, where as for og2 he is only orgadmin and for og3 he is only org-read-only-user I have the possibility of making each user belong to one organization alone, but that's making the system bounded and I don't like that idea (although i would still satisfy the requirement) If you have a better extensible ACL architecture, please suggest it. Since its a software as a service, one would expect that alot of different organizations would be part if the same system. I had one concern that it is not a good idea to keep og1 and og2 data on the same DB (if og1 decides to spawn a 100 reports on the system, og2 should not suffer) But that is some thing advanced for now and is not directly related to ACL but to the physical distribution of data and setup of services based on those ACLs This is a community Wiki question, please correct any thing which you wish to do so. Thanks

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  • starting oracle 10g on ubuntu, Listener failed to start.

    - by tsegay
    I have installed oracle 10g on a ubuntu 10.x, This is my first time installation. After installing I tried to start it with the command below. tsegay@server-name:/u01/app/oracle/product/10.2.0/db_1/bin$ lsnrctl LSNRCTL for Linux: Version 10.2.0.1.0 - Production on 29-DEC-2010 22:46:51 Copyright (c) 1991, 2005, Oracle. All rights reserved. Welcome to LSNRCTL, type "help" for information. LSNRCTL> start Starting /u01/app/oracle/product/10.2.0/db_1/bin/tnslsnr: please wait... TNSLSNR for Linux: Version 10.2.0.1.0 - Production System parameter file is /u01/app/oracle/product/10.2.0/db_1/network/admin/listener.ora Log messages written to /u01/app/oracle/product/10.2.0/db_1/network/log/listener.log Error listening on: (DESCRIPTION=(ADDRESS=(PROTOCOL=IPC)(KEY=EXTPROC1))) TNS-12555: TNS:permission denied TNS-12560: TNS:protocol adapter error TNS-00525: Insufficient privilege for operation Linux Error: 1: Operation not permitted Listener failed to start. See the error message(s) above... my listener.ora file looks like this: # listener.ora Network Configuration File: /u01/app/oracle/product/10.2.0/db_1/network/admin/listener.ora # Generated by Oracle configuration tools. SID_LIST_LISTENER = (SID_LIST = (SID_DESC = (SID_NAME = PLSExtProc) (ORACLE_HOME = /u01/app/oracle/product/10.2.0/db_1) (PROGRAM = extproc) ) ) LISTENER = (DESCRIPTION_LIST = (DESCRIPTION = (ADDRESS = (PROTOCOL = IPC)(KEY = EXTPROC1)) (ADDRESS = (PROTOCOL = TCP)(HOST = acct-vmserver)(PORT = 1521)) ) ) I can guess the problem is with permission issue, But i dont know where I have to do the change on permission. Any help is appreciated ...

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  • I can not use Session In Page_Load and I got error bellow

    - by LostLord
    hi my dear friends .... why i got this error : Object reference not set to an instance of an object. when i put this code in my page_load.: protected void Page_Load(object sender, EventArgs e) { BackEndUtils.OverallLoader(); string Teststr = Session["Co_ID"].ToString(); } ========================================================================== this session is made when user logins to my web site and this session works in other areas... thanks for your attention ========================================================================== thanks for your answers i removed BackEndUtils.OverallLoader(); but error still exists i tried Teststr = Convert.ToString(Session["Co_ID"]); and error disappeared - but i don't know why that session is null in other areas that session works perfectly = such as a button in that form what is the matter? my web page markup is like this : <%@ Page Title="" Language="C#" MasterPageFile="~/Admin/AdminBackend.Master" AutoEventWireup="true" CodeBehind="Personel.aspx.cs" Inherits="Darman.Admin.Personel" Theme="DefaultTheme" %> ================================================================================= i put this code in a button like this : string Teststr = Convert.ToString(Session["Co_ID"]); when i press that button THIS code in page Load(POSTBACK) + IN Button_Click works perfectly and shows me 23 (my Co_ID) But when i run my page in browser (first time) this code in page load shows me null. why? thanks a lot

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  • need advice on Zend framework Application architecture, or say approach dealing with modules

    - by simple
    Let me start with the things that I did and how am I using some things to get results I have set up modular structure as: application/ /configs /layouts /models /modules /users /profile /frontend /backend /controllers /views .... I write a plugin that does addes changes with FrontController-setModuleControllerDirectoryName() FrontController-addModuleDirectory() and It is all good I have a changed all the directories according weather admin page is requested in the url or not (it is some thing like /admin/some/some) Let's say I have a single layout for anything that is related to Profile viewing , in this case the "Profile" module. The Profile layout is divided into three parts In the layout I was pulling out the Profile/PhotoController 's index action with a action() $this->action('index', 'photo', 'profile'); Then I have faced few issues 1. Can get passed Params inside the Photo Controller when calling ( profile/profile/index); 2. found out that helper Action() is evil cause it starts another dispatching loop =) --- and now I am thinking that my approach on plugging in controllers modules into layout also evil =). anyhow how Should I deal with plugging in some controllers (another module controllers) into the layout ?

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  • How do I create a selection list in ASP.NET MVC?

    - by Gary McGill
    I have a database table that records what publications a user is allowed to access. The table is very simple - it simply stores user ID/publication ID pairs: CREATE TABLE UserPublication (UserId INTEGER, PublicationID INTEGER) The presence of a record for a given user & publication means that the user has access; absence of a record implies no access. I want to present my admin users with a simple screen that allows them to configure which publications a user can access. I would like to show one checkbox for each of the possible publications, and check the ones that the user can currently access. The admin user can then check or un-check any number of publications and submit the form. There are various publication types, and I want to group the similarly-typed publications together - so I do need control over how the publications are presented (I don't want to just have a flat list). My view model obviously needs to have a list of all the publications (since I need to display them all regardless of the current selection), and I also need a list of the publications that the user currently has access to. (I'm not sure whether I'd be better off with a single list where each item includes the publication ID and a yes/no field?). But that's as far as I've got. I've really no idea how to go about binding this to some checkboxes. Where do I start?

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  • Although not [required] List field shows up as required and Model State is not Valid due to it bein

    - by VJ
    I have the following code- View- <% Html.BeginForm(); %> <div> <%= Html.DropDownList("DropDownSelectList", new SelectList( Model.DropDownSelectList, "Value", "Text"))%> Controller- public ActionResult Admin(string apiKey, string userId) { ChallengesAdminViewModel vm = new ChallengesAdminViewModel(); vm.ApiKey = apiKey; vm.UserId = userId; vm.DropDownSelectList = new List<SelectListItem>(); vm.DropDownSelectList.Add(listItem1); vm.DropDownSelectList.Add(listItem2); vm.DropDownSelectList.Add(listItem3); vm.DropDownSelectList.Add(listItem4); vm.DropDownSelectList.Add(listItem5); vm.DropDownSelectList.Add(listItem6); vm.DropDownSelectList.Add(listItem7); } [HttpPost] public ActionResult Admin(ChallengesAdminViewModel vm) { if (ModelState.IsValid)//Due to the null dropdownlist gives model state invalid { } } ViewModel- public class ChallengesAdminViewModel { [Required] public string ApiKey { get; set; } [Required] public string UserId { get; set; } public List<SelectListItem> DropDownSelectList { get; set; } } I dont know why it still requires the list although not required. I want to have only two attributes as required. So I wanted to know how do i declare or change that list to be not required and have my Model State Valid.

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  • User Management: Managing users in user-defined "groups", database schema and logistics

    - by Kevin Brown
    I'm a noob, development wise and logistically-wise. I'm developing a site that lets people take a test... My client wants the ability for a user with the roll/privledge "admin" (a step below a super-admin) to be allowed to create users and only see/edit the users that they create... The users created in that "category" or group need some information that their superior provides. For example, I log in as a "manager", I have the ability to invite people to take the test, and manage those people. Before adding those people, I will have filled out a short survey about myself... Right now, the users that are invited will be asked some of the same questions as the manager. I'd like to cut down the redundancy by using the information put into the database by the manager and apply it to the invited users. How do I set up my database to work with this criterion? I'm a little confused about how to do this! Let me know if I can add more details... (This is a mysql and php app)

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  • How should i organize authority code?

    - by acidzombie24
    I have users that fall into the following Not logged in Not Verified Verified Moderator Admin All code that only admin and moderators can access (like banning) is in ModeratorUser which inherits from verified which inherits from BaseUser. Some pages are accessible to all users such as public profiles. If a user is logged in he can leave a comment. To check this i use if (IsVerifiedUser). Now here is the problem. To avoid problems if a user is banned he is not recognized as a verified user. However in the rare case i need to know if he is verified i can use usertype & Verified. Should i not be doing this? I have a bunch of code in my VerifiedUser class and find i am moving tons of it to BaseUser. Is this something i help because a not logged in user can access the page? Should i handle the ban user in a different way and allow IsVerifiedUser to be true even if the user is banned?

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  • Action Mailer: How do I render dynamic data in an email body that is stored in the database?

    - by Brandon Toone
    I have Action Mailer setup to render an email using the body attribute of my Email model (in the database). I want to be able to use erb in the body but I can't figure out how to get it to render in the sent email message. I'm able to get the body as a string with this code # models/user_mailer.rb def custom_email(user, email_id) email = Email.find(email_id) recipients user.email from "Mail It Example <[email protected]>" subject "Hello From Mail It" sent_on Time.now # pulls the email body and passes a string to the template views/user_mailer/customer_email.text.html.erb body :msg => email.body end I came across this article http://rails-nutshell.labs.oreilly.com/ch05.html which says I can use render but I'm only able to get render :text to work and not render :inline # models/user_mailer.rb def custom_email(user, email_id) email = Email.find(email_id) recipients user.email from "Mail It Example <[email protected]>" subject "Hello From Mail It" sent_on Time.now # body :msg => email.body body :msg => (render :text => "Thanks for your order") # renders text and passes as a variable to the template # body :msg => (render :inline => "We shipped <%= Time.now %>") # throws a NoMethodError end

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