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  • How to convert rows returned by a query into columns in oracle?

    - by Piyush Lohana
    I have to display the results of the below query as columns. select to_char(sysdate + 1 - rownum,'MON-YYYY') as d from all_objects where trunc(sysdate + 1 - rownum,'MM') = trunc(to_date(:from_date,'MON-YYYY'),'MM') minus select to_char(sysdate + 1 - rownum,'MON-YYYY') as d from all_objects where trunc(sysdate + 1 - rownum,'MM') trunc(to_date(':to_date','MON-YYYY'),'MM') Please help me in figuring that out.

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  • Need help displaying a table dynamically based on a drop down date selection

    - by Gideon
    I am designing a job rota planner for a company and need help displaying a dynamic table containing the staff details. I have the following tables in MySQL database: Staff, Event, and Job. The staff table holds staff details (staffed, name, address...etc), the Event table (eventide, eventName, Fromdate, Todate...etc) and the Job table holds (Jobid, Jobdate, Eventid(fk), Staffid (fk)). I need to dynamically display the available staff list from the staff table when the user selects the event and the date (3 drop downs: date, month, and year) from a PHP form. I need to display staff members that have not been assigned work on the selected date by checking the Jobdate in the Job table. I have been at this for all day and can't get around it. I am still learning PHP and would surely appreciate any help I can get. My current code displays all staff members when an event is selected: //Create the day pull-down menu. $days = range (1, 31); echo "<Select Name=day Value=''><Option>Day</option>"; foreach ($days as $value) { echo '<option value="'.$value.'">'.$value.'</option>\n'; } echo "</Select>"; echo "</td><td>"; //Create the month pull-down menu echo "<Select Name=month Value=''><Option>Month</option>"; echo "<option value='01'>Jan</option>"; echo "<option value='02'>Feb</option>"; echo "<option value='03'>Mar</option>"; echo "<option value='04'>Apr</option>"; echo "<option value='05'>May</option>"; echo "<option value='06'>Jun</option>"; echo "<option value='07'>Jul</option>"; echo "<option value='08'>Aug</option>"; echo "<option value='09'>Sep</option>"; echo "<option value='10'>Oct</option>"; echo "<option value='11'>Nov</option>"; echo "<option value='12'>Dec</option>"; echo "</select>"; echo "</td><td>"; //Create the year pull-down menu $currentYear = date ("Y"); $years = range ($currentYear, 2020); echo "<Select Name=year Value=''><Option>Year</option>"; foreach ($years as $value) { echo '<option value="'.$value.'">'.$value.'</option>\n'; } echo "</Select>"; echo "</td></tr></table>"; echo "</td><td>"; //echo "<img src='../ETMSimages/etms_staff.png'</img></td><td>"; //construct the available staff list $staffsql = "SELECT StaffId, LastName, FirstName FROM Staff order by StaffId"; $staffResult = mysql_query($staffsql); if ($staffResult){ echo "<p><table cellspacing='1' cellpadding='3'>"; echo "<th colspan=6>List of Available Staff</th>"; echo "</tr><tr><th> Select</th><th>Id</th><th></th><th>Last Name </th><th></th><th>First Name </th></tr>"; while ($staffarray = mysql_fetch_array($staffResult)) { echo "<tr onMouseOver= this.bgColor = 'red' onMouseOut =this.bgColor = 'white' bgcolor= '#FFFFFF'> <td align=center><input type='checkbox' name='selectbox[]' id='selectbox[]' value=".$staffarray['StaffId']."> </td><td align=left>".$staffarray['StaffId']." </td><td>&nbsp&nbsp</td><td align=center>".$staffarray['LastName']." </td><td>&nbsp&nbsp</td><td align=center>".$staffarray['FirstName']." </td></tr>"; } echo "</table>"; } else { echo "<br> The Staff list can not be displayed!"; } echo "</td></tr>"; echo "<tr><td></td>"; echo "<td align=center><input type='submit' name='Submit' value='Assign Staff'>&nbsp&nbsp"; echo "<input type='reset' value='Start Over'>"; echo "</td></tr>"; echo "</table>";

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  • lookahead and group

    - by Istao
    Hi, In Java, on a text like foo <on> bar </on> thing <on> again</on> now, I should want a regex with groups wich give me with a find "foo", "bar", empty string, then "thing", "again", "now". If I do (.*?)<on>(.*?)</on>(?!<on>), I get only two group (foo bar, thing again, and I've not the end "now"). if I do (.*?)<on>(.*?)</on>((?!<on>)) I get foo bar empty string, then thing again and empty string (here I should want "now"). Please what is the magical formula ? Thanks.

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  • Codeigniter view file looping query

    - by user2505513
    Right, I'm unsure about how to code my view file to generate following query results WITHOUT compromising the principles of mvc. Query in model: SELECT * FROM events GROUP BY country, area ORDER BY country, area View: <?php if (isset($query)):?> <?php foreach ($query as $row):?> <h2><?=$row->country?></h2> <h3><?=$row->area?></h3> <?php endforeach;?> <?php endif;?> I want the results to display: England North South West - utilising the GROUP BY parameter As opposed to: England North England South England West Has anybody any advice as to how to achieve this?

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  • Group and count in Rails

    - by alamodey
    I have this bit of code and I get an empty object. @results = PollRoles.find( :all, :select => 'option_id, count(*) count', :group => 'option_id', :conditions => ["poll_id = ?", @poll.id]) Is this the correct way of writing the query? I want a collection of records that have an option id and the number of times that option id is found in the PollRoles model. EDIT: This is how I''m iterating through the results: <% @results.each do |result| %> <% @option = Option.find_by_id(result.option_id) %> <%= @option.question %> <%= result.count %> <% end %>

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  • InfoPath Getting SharePoint Group Information

    - by anon
    I have an InfoPath form embedded in an aspx page on a SharePoint site. How do I bind the SharePoint user groups to a drop-down list on my form? What I've tried so far is to create a data connection to a web service (method GetGroupCollectionFromWeb) to pull the data. Next, I open the list box properties, select "Look up values from an external data source", select the data source, assign the entries, and I get the following error: "You must select a repeating group or field." What I don't understand is that since the method I am calling is called GetGroupCollectionFromWeb, isn't the return value a collection? And aren't collections repeating by definition? What am I missing, and is there a workaround? Thank you.

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  • SQL where clasue to work with Group by clasue after performing a count()

    - by Matt
    Tried my usual references at w3schools and google. No luck I'm trying to produce the following results. QTY is a derived column | Position | QTY -------------------- 1 Clerk 2 2 Mgr 2 Here's what I'm not having luck with: SELECT Position, Count(position) AS 'QTY' FROM tblemployee Where ('QTY' != 1) GROUP BY Position I know that my Position is set up as varchar(255) Count produces a integer data and my where clasue is accurate so that leads me to believe that that Count() is jamming me up. Please throw up an example so I can reference later. Thanks for the help!

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  • After grouping by, can I refer to the elements of the original IEnumerable in a LINQ query?

    - by michielvoo
    Example: from OriginalObject in ListOfOriginalObjects group new CustomObject { X = OriginalObject.A, Y = OriginalObject.B } by OriginalObject.Z into grouping select new GroupOfCustomObjects { Z = grouping.Key, C = OriginalObject.C, group = grouping } In the select part of the query, I'd like to add a property (OriginalObject.C) to the type GroupOfCustomObjects. But it seems that OriginalObject is out of scope in that part of the query. I can sort of understand why, since I am not grouping on that property and I am also not making that property part of CustomObject that I'm grouping. One workaround is to add a property C to CustomObject and the in the GroupOfCustomObjects read the value of the first CustomObject in the grouping. My issue with that is that I'm adding a property to an object that doesn't need it (CustomObject), just to be able to add it to the GroupOfCustomObjects. I hope I have explained this properly! Is there a way to refer to the OriginalObject that the query starts with? Thanks!

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  • join select from multiple row values?

    - by user1869132
    Two tables 1) product -------------------- id | Name | price 1 | p1 | 10 2 | p2 | 20 3 | p3 | 30 2) product_attributes: --------------------------------------------------- id | product_id | attribute_name | attribute_value --------------------------------------------------- 1 | 1 | size | 10 2 | 1 | colour | red 3 | 2 | size | 20 I need to join these two tables. In the where clause I need to match both the two rows attribute values. Is it possible to get the result based on two rows value. Here if size=10 and colour=red. Output should be 1 | p1 | 10 It could be greatly helpful to get a query for this.

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  • Rails group validation with just one error message

    - by Victor
    The following validation code in the model: validates :formatted_address, :zip, :city, :state, :country, :presence => true, :message => "is incomplete. Please enter full address." is displayed when either of the fields are empty. Let's say now :address and country are empty, 2 errors are displayed: Formatted Address is incomplete. Please enter full address. Country is incomplete. Please enter full address. How can I group the error message in the validation to just show one error message if either of the fields validated does not exist? Address is incomplete. Please enter full address. Thanks.

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  • Finding group maxes in SQL join result

    - by Gene
    Two SQL tables. One contestant has many entries: Contestants Entries Id Name Id Contestant_Id Score -- ---- -- ------------- ----- 1 Fred 1 3 100 2 Mary 2 3 22 3 Irving 3 1 888 4 Grizelda 4 4 123 5 1 19 6 3 50 Low score wins. Need to retrieve current best scores of all contestants ordered by score: Best Entries Report Name Entry_Id Score ---- -------- ----- Fred 5 19 Irving 2 22 Grizelda 4 123 I can certainly get this done with many queries. My question is whether there's a way to get the result with one, efficient SQL query. I can almost see how to do it with GROUP BY, but not quite. In case it's relevant, the environment is Rails ActiveRecord and PostgreSQL.

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  • Translate SQL to LINQ query - group/join/filter

    - by Paddy
    I have the following query: SELECT S.[FlowOrder], S.[DESCRIPTION], COUNT(I.ID) FROM WorkFlowStatus AS S INNER JOIN Item AS I ON S.ID = I.StatusID WHERE I.Installation = '1' GROUP BY S.[Description], S.[FlowOrder] ORDER BY S.[FlowOrder] Which gives me the count of an item, grouped by a foreign key to workflow, outputting the descriptive name from my FK table. I've go this far with the LINQ query (using LINQ-to-SQL) in the background: var items = from s in _entities.WorkflowStatus join i in _entities.Items on s.ID equals i.StatusId into Statuses orderby s.FlowOrder select new {s.Description, ItemCount = Statuses.Count() }; How do I get the where clause in the SQL into this LINQ query?

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  • How to SUM columns on multiple conditions in a GROUP BY

    - by David Liddle
    I am trying to return a list of Accounts with their Balances, Outcome and Income Account Transaction ------- ----------- AccountID TransactionID BankName AccountID Locale Amount Status Here is what I currently have. Could someone explain where I am going wrong? select a.ACCOUNT_ID, a.BANK_NAME, a.LOCALE, a.STATUS, sum(t1.AMOUNT) as BALANCE, sum(t2.AMOUNT) as OUTCOME, sum(t3.AMOUNT) as INCOME from ACCOUNT a left join TRANSACTION t1 on t1.ACCOUNT_ID = a.ACCOUNT_ID left join TRANSACTION t2 on t1.ACCOUNT_ID = a.ACCOUNT_ID and t2.AMOUNT < 0 left join TRANSACTION t3 on t3.ACCOUNT_ID = a.ACCOUNT_ID and t3.AMOUNT > 0 group by a.ACCOUNT_ID, a.BANK_NAME, a.LOCALE, a.[STATUS]

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  • I can't Distinct, Sum, or Count from 3 tables with group clauses

    - by Rio Inggit Dharmawangsa
    I'm still learning linq, now i'm getting confused. I need data for report from 3 tables, I get the result, but it's duplicate. I have used distinct but it's not working, n I need data to be sum still not working. Here is my query, can somebody explain what's wrong? var report= (from u in myDb.TBL_TRANSAKSI_MKN_MNMs.AsEnumerable() where u.TGL_TRANSAKSI.Value.Date.Equals(dateTimePicker1.Value.Date) join l in myDb.TBL_DETAIL_TRANSAKSIs.AsEnumerable() on u.ID_NOTA equals l.ID_NOTA join m in myDb.TBL_MKN_MNMs.AsEnumerable() on l.ID_MKN_MNM equals m.ID_MKN_MNM group new { u, l, m } by new { m.NAMA_MKN_MNM, m.HARGA_JUAL, u.TGL_TRANSAKSI, l.ID_MKN_MNM, u.USERNAME, l.Jumlah } into grp select new { MakanMinum = grp.Key.NAMA_MKN_MNM, HargaJual = grp.Key.HARGA_JUAL, Stok = grp.Sum(groupedthing => groupedthing.l.Jumlah), Tanggal = grp.Key.TGL_TRANSAKSI, Jumlah =(grp.Key.HARGA_JUAL * grp.Sum(groupedthing => groupedthing.l.Jumlah)), Total = grp.Sum(grouptotal => grp.Key.HARGA_JUAL * grp.Sum(groupedthing => groupedthing.l.Jumlah)), Username = grp.Key.USERNAME }).Distinct();

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  • Algorithm to Group All the Cycles Together

    - by Ngu Soon Hui
    I have a lot of cycles ( indicated by numeric values, for example, 1-2-3-4 corresponds to a cycle, with 4 edges, edge 1 is {1:2}, edge 2 is {2:3}, edge 3 is {3,4}, edge 4 is {4,1}, and so on). A cycle is said to be connected to another cycle if they share one and only one edge. For example, let's say I have two cycles 1-2-3-4 and 5-6-7-8, then there are two cycle groups because these two cycles are not connecting to each other. If I have two cycles 1-2-3-4 and 3-4-5-6, then I have only one cycle group because these two cycles share the same edge. What is the most efficient way to find all the cycle groups?

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  • selecting and formating text in richtextbox control vb6

    - by Smith
    i need to bold some text as i add them to the richtextbox control, currently here is my code With txtDetails If Not IsNullOrEmpty(title) Then .SelStart = Len(.Text) .Text = .Text & title .SelLength = Len(title) .SelBold = True .SelLength = 0 .Text = .Text & vbNewLine End If If Not IsNullOrEmpty(value) Then .Text = .Text & value & vbNewLine End If .Text = .Text & vbNewLine End With can anyone help me with the fix

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  • Getting the most recent entry per group in a select statement

    - by TheObserver
    I have 3 tables to join to get table1.code, table1.series, table2.entry_date, table3.title1 and I'm trying to get the most recent non null table3.title1 grouped by table1.code and table1.series. select table1.code, table1.series, max(table2.entry_date), table3.Title1 from table3 INNER JOIN table2 ON table3.ID = table2.ID INNER JOIN table1 ON table2.source_code = table1.code where table3.Title1 is not NULL group by table1.code, table1.series, table3.Title1 seems to give me all entries with a non null title1 instead of the most recent one. How should I structure the query to just pick the newest version of Title1 per code & series?

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  • MySQL - Conflicting WHERE and GROUP BY Statements

    - by TaylorPLM
    I have a query returning the counts of some data, but I do NOT want data that has a null value in it... As an example, the code rolls stats from a clicking system into a table. SELECT sh.dropid, ... FROM subscriberhistory sh INNER JOIN subscriberhistory sh2 on sh.subid = sh2.subid WHERE sh.dropid IS NOT NULL AND sh.dropid != "" ... GROUP BY sh.dropid An example of the record set returned would look like this... 400 2 3 4 5 6 401 2 3 6 5 4 NULL 2 3 4 5 1 There are some other where clauses, and a few more selects (as I said, using the count aggregate) that are also within the query. There is also an order by statement. Again, the goal is to keep the NULL data out of the preceding record set. Could someone explain to me why this behavior is occurring and what to do to solve it.

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  • Identifying when there is more than 1 in a group based on grouped field

    - by Brian Cascone
    Sorry for the bad description it is tough to explain in one sentence. I have a dataset that has Cause field (RootCause) and an ID field (GroupID). Both can be many things but I need to identify where a GroupID has a multiple different rootcauses. for example: RootCause GrpId AAA 111 BBB 222 CCC 111 I am looking to be able to identify that GrpId 111 has two different RootCauses. This is what I have so far: Select [RootCause], GrpId, Count(GrpID) as CntGrpId From DB.dbo.Table Where DatatypeField <> '' Group BY [RootCause],GrpId This results set visualy gives me enough information to identify what I am looking for, but i need something better. I am looking to return only the ones that have multiples. Any ideas? Thanks

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  • Group Objects by Common Key

    - by Marshmellow1328
    I have a list of Customers. Each customer has an address and some customers may actually have the same address. My ultimate goal is to group customers based on their address. I figure I could either put the customers in some sort of list-based structure and sort on the addresses, or I could drop the objects into some sort of map that allows multiple values per key. I will now make a pretty picture: List: A1 - C1, A1 - C2, A2 - C3, A3 - C4, A3 - C5 Map: A1 A2 A3 C1 C3 C4 C2 C5 Which option (or any others) do you see as the best solution? Are there any existing classes that will make development easier?

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  • Need help with a sub query/group/order (get latest comment for each ordered topic)

    - by Scarface
    Hey guys I have a query that currently finds the latest comment for each of a user's topics and then orders topics by that comment's timestamp. What I want to do is expand on this query's use and print the latest comment for each topic. The problem with this query is that while it orders the topics correctly, it prints seemingly random comments for each topic. I am trying to implement a sub query but I am not quite sure how to approach it. I was thinking that I just had to somehow use this query to get the comments. If anyone has any ideas I would really appreciate it. Here is what I think I need to add SELECT * FROM comments where topic_id='$topic_id' ORDER BY timestamp DESC LIMIT 1 Here is the query I need to modify SELECT topic.topic_title, topic.content_type, topic.subject_id, topic.creator, topic.description, topic.topic_id,comments.message,comments.user FROM comments JOIN topic ON topic.topic_id = comments.topic_id WHERE topic.creator = '$user' AND comments.timestamp > $week GROUP BY topic_id ORDER BY MAX(comments.timestamp) DESC

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  • MySQL Group Results by day using timestamp

    - by Webnet
    I need to take the following query and pull the total order counts and sum of the orders grouped by day. I'm storing everything using timestamps. SELECT COUNT(id) as order_count, SUM(price + shipping_price) as order_sum, DAY(FROM_UNIXTIME(created)) as day FROM `order` WHERE '.implode(' AND ', $where).' I need to group by DAY but when I do for this past weekend's sales it takes my order_count and makes it 1 instead of 3. How can I pull the above values grouped by day? NOTE: The implode is used ONLY to define the time period (WHERE created = TIMESTAMP AND <= TIMESTAMP)

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  • Any idea why this query always returns duplicate items?

    - by Kardo
    I want to get all Images not used by current ItemID. The this subquery but it also always returns duplicate Images: EDITED select Images.ImageID, Images.ItemStatus, Images.UserName, Images.Url, Image_Item.ItemID, Image_Item.ItemID from Images left join (select ImageID, ItemID, MAX(DateCreated) x from Image_Item where ItemID != '5a0077fe-cf86-434d-9f3b-7ff3030a1b6e' group by ImageID, ItemID having count(*) = 1) image_item on Images.imageid = image_item.imageid where ItemID is not null I guess the problem is with the subquery which I can't avoid duplicate rows: select ImageID, ItemID, MAX(DateCreated) x from Image_Item where ItemID != '5a0077fe-cf86-434d-9f3b-7ff3030a1b6e' group by ImageID, ItemID having count(*) = 1 Result: F2EECBDC-963D-42A7-90B1-4F82F89A64C7 0578AC61-3C32-4A1D-812C-60A09A661E71 F2EECBDC-963D-42A7-90B1-4F82F89A64C7 9A4EC913-5AD6-4F9E-AF6D-CF4455D81C10 42BC8B1A-7430-4915-9CDA-C907CBC76D6A CB298EB9-A105-4797-985E-A370013B684F 16371C34-B861-477C-9A7C-DEB27C8F333D 44E6349B-7EBF-4C7E-B3B0-1C6E2F19992C Table: Images ImageID uniqueidentifier UserName nvarchar(100) DateCreated smalldatetime Url nvarchar(250) ItemStatus char(1) Table: Image_Item ImageID uniqueidentifier ItemID uniqueidentifier UserName nvarchar(100) ItemStatus char(1) DateCreated smalldatetime Any kind help is highly appreciated.

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