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• Storage servers architectural solution for backup. What is the best way? (pics inside)

  - by Kirzilla

  Hello, What is the best architecture for storage servers array? Needs... a) easy way to add one more server to array b) we don't have single backup server c) we need to have one backup for each "web" part of each server Group #1 : is cross-server-backuping scheme; the main disadvantage that we can't add one more server, we should add 2 servers in one time. Group #2 : is a Group #1, but with three and more servers. It also have a disadvantage - to add one more server we should move existing backup to it. Any suggestions? Thank you. Thank you.

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• preg_match problem

  - by Biroka

  I'm trying to get some stuff from a string in php. In RegexBuddy and Regular expression tester (firefox addon) it works good, but php gives me the following: Warning: preg_match() [function.preg-match]: Compilation failed: unmatched parentheses at offset 34 in D:\path\example.php on line 62 my pattern is "/.{4}_tmp\\([A-Za-z0-9.\\]*)\(([0-9]*)\) : (.*)/i" an example string: C:\Temp\browseide\projects\32\821C_tmp\SourceFiles\main.c(8) : error C2143: syntax error : missing ';' before 'for' what RegexBuddy gets: 821C_tmp\SourceFiles\main.c(8) : error C2143: syntax error : missing ';' before 'for' Group 1: SourceFiles\main.c Group 2: 8 Group 3: error C2143: syntax error : missing ';' before 'for'

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• Umbraco -- controlling access to media by membership

  - by Ryan

  I need to set up access to media files with the following structure: A media folder is designated as belonging to a specific member group. Then, a sub-folder below that needs to be available to a subset of members from the parent's member group. Any thoughts on how this can best be accomplished? I'll render the actual file download links with a user control, but how should I set up this access control on the back end? I need a member-group picker and a multiple member picker. Do these exist anywhere?

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• How to change page author in wordpress?

  - by GaVrA

  Ofc i know how to do that, but the thing is that i am using "User Role Editor" and i have one user group that can read and edit published pages. Now, i will be adding all the pages on that site, and we will have several users that will need to have only one page they can edit, so i need for that page to change "Page author" to that user. In case you didnt know, when user have "Edit published pages" enabled they can edit only pages where they are listed as author. Problem is i can only do that by going in phpmyadmin and changing the page_author field to the id of that user because that user group, like i said, can only read and edit published pages. That is why i can not change page author from "Edit page" page to user from that user group. So my question is: does anyone know any solution to this problem which does not involve me going to phpmyadmin and changing the id for page_author there?

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• Multiple many-to-many JOINs in a single mysql query without Cartesian Product

  - by VWD

  At the moment I can get the results I need with two seperate SELECT statements SELECT COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID GROUP BY bl.biblioID Combining them like this however SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ), COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID causes the author result column to have duplicate names. How can I get the desired results from one SELECT statement without using DISTINCT? With subqueries?

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• Match groups in Python

  - by Curd

  Is there a way in Python to access match groups without explicitely creating a match object (or another way to beautify the example below)? Here is an example to clarify my motivation for the question: Following perl code if ($statement =~ /I love (\w+)/) { print "He loves $1\n"; } elsif ($statement =~ /Ich liebe (\w+)/) { print "Er liebt $1\n"; } elsif ($statement =~ /Je t\'aime (\w+)/) { print "Il aime $1\n"; } translated into Python m = re.match("I love (\w+)", statement) if m: print "He loves",m.group(1) else: m = re.match("Ich liebe (\w+)", statement) if m: print "Er liebt",m.group(1) else: m = re.match("Je t'aime (\w+)", statement) if m: print "Il aime",m.group(1) looks very awkward (if-else-cascade, match object creation).

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• RecursiveIterator: used to explode tree structure, or only flatten?

  - by Stephen J. Fuhry

  There are tons of examples of using the RecursiveIterator to flatten a tree structure.. but what about using it to explode a tree structure? Is there an elegant way to use this, or some other SPL library to recursively build a tree (read: turn a flat array into array of arbitrary depth) given a table like this: SELECT id, parent_id, name FROM my_tree EDIT: You know how you can do this with Directories? $it = new RecursiveDirectoryIterator("/var/www/images"); foreach(new RecursiveIteratorIterator($it) as $file) { echo $file . PHP_EOL; } .. What if you could do something like this: $it = new RecursiveParentChildIterator($result_array); foreach(new RecursiveIteratorIterator($it) as $group) { echo $group->name . PHP_EOL; echo implode(PHP_EOL, $group->getChildren()) . PHP_EOL . PHP_EOL; } :END EDIT

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• Firefox extension dev: observing preferences, avoid multiple notifications

  - by Michael

  Let's say my Firefox extension has multiple preferences, but some of them are grouped, like check interval, fail retry interval, destination url. Those are used in just single function. When I subscribe to preference service and add observer, the observe callback will be called for each changed preference, so if by chance user changed all of the settings in group, then I will have to do the same routine for the same subsystem as many times as I have items in that preferences group. It's a great redundancy! What I want is observe to be called just once for group of preferences. Say extensions.myextension.interval1 extensions.myextension.site extensions.myextension.retry so if one or all of those preferences are changed, I receive only 1 notification about it. In other words, no matter how many preferences changed in branch, I want the observe callback to called once.

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• How do you data drive task dependencies via properties in psake?

  - by Jordan

  In MSBuild you can data drive target dependencies by passing a item group into a target, like so: <ItemGroup> <FullBuildDependsOn Include="Package;CoreFinalize" Condition="@(FullBuildDependsOn) == ''" /> </ItemGroup> <Target Name="FullBuild" DependsOnTargets="@(FullBuildDependsOn)" /> If you don't override the FullBuildDependsOn item group, the FullBuild target defaults to depending on the Package and CoreFinalize targets. However, you can override this by defining your own FullBuildDependsOn item group. I'd like to do the same in psake - for example: properties { $FullBuildDependsOn = "Package", "CoreFinalize" } task default -depends FullBuild # this won't work because $FullBuildDependsOn hasn't been defined yet - the "Task" function will see this as a null depends array task FullBuild -depends $FullBuildDependsOn What do I need to do to data drive the task dependencies in psake?

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• How do I transfer this logic into a LINQ statement?

  - by Geoffrey

  I can't get this bit of logic converted into a Linq statement and it is driving me nuts. I have a list of items that have a category and a createdondate field. I want to group by the category and only return items that have the max date for their category. So for example, the list contains items with categories 1 and 2. The first day (1/1) I post two items to both categories 1 and 2. The second day (1/2) I post three items to category 1. The list should return the second day postings to category 1 and the first day postings to category 2. Right now I have it grouping by the category then running through a foreach loop to compare each item in the group with the max date of the group, if the date is less than the max date it removes the item. There's got to be a way to take the loop out, but I haven't figured it out!

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• PHP Doctrine - YAML syntax help. Default value for many to many relationship?

  - by Dan

  Hi, I have the following YAML schema for organising users in Doctrine: Person: tableName: people columns: id: type: integer primary: true autoincrement: true firstname: type: string notnull: true lastname: type: string notnull: true User: inheritance: extends: Person type: column_aggregation keyField: type keyValue: 1 Userdetails: columns: person_id: type: integer primary: true password: type: string notnull: true relations: User: foreignType: one local: person_id onDelete: CASCADE onUpdate: CASCADE Group: tableName: groups columns: id: type: integer primary: true autoincrement: true name: type: string notnull: true UserGroup: columns: group_id: type: integer primary: true person_id: type: integer primary: true relations: User: foreignType: many local: person_id Group: foreignType: many Basically, any people who are users will belong to one or more groups. Is there any way to add new users to a particular group by default? Any advice appreciated. Thanks

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• Find missing birth days in Apple Addressbook

  - by Felix Ogg

  I am trying to clean the holes out of my Mac address book. As a first step I want to ask all my friends for their birth day, to be able to congratulate them with cheesy Hallmark cards. I need a "group" in my address book, to mailmerge personalized messages from. This is the Applescript I came up with: tell application "Address Book" make new group with properties {name:"No Birthday"} set birthdayPeople to (get every person whose birth date is greater than date "Monday, January 1, 1900 12:00:00 AM") repeat with i from 1 to number of items in people set thePerson to item i of people if not (birthdayPeople contains thePerson) then add thePerson to group "No Birthday" end if end repeat save end tell It breaks, but from the error messages I cannot deduce what is wrong: Result: error "Can’t make «class azf4» id \"05F770BA-7492-436B-9B58-E24F494702F8:ABPerson\" of application \"Address Book\" into type vector." number -1700 from «class azf4» id "05F770BA-7492-436B-9B58-E24F494702F8:ABPerson" to vector (BTW: Did I mention this is my first AppleScript code, EVER? So, if this code can be simplified, or made more elegant, that is welcome too.)

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• Firefox extension dev: observing preferences, avoid multiple notifications

  - by Michael

  Let's say my Firefox extension has multiple preferences, but some of them are grouped, like check interval, fail retry interval, destination url. Those are used in just single function. When I subscribe to preference service and add observer, the observe callback will be called for each changed preference, so if by chance user changed all of the settings in group, then I will have to do the same routine for the same subsystem as many times as I have items in that preferences group. It's a great redundancy! What I want is observe to be called just once for group of preferences. Say extensions.myextension.interval1 extensions.myextension.site extensions.myextension.retry so if one or all of those preferences are changed, I receive only 1 notification about it. In other words, no matter how many preferences changed in branch, I want the observe callback to called once.

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• Why Jmeter is not recoring?

  - by Monika

  I am working with Jmeter2.3.2 version and trying to record a webpage. I have added http proxy server under workbench and added http request default under thread group. using port 9090 and target controller test plan - thread group. grouping - do not group samplers. After this setting i have started proxy server and opened internet browser selected manual proxy setting and added address as localhost with port 9090. the issue is Jmeter is nopt recoring anything. Please suggest it is urgent.

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• AesCryptoServiceProvider not part of SymmetricAlgorithm?

  - by user330006

  I have a quick little app that steps through the possible symmetric encryption methods. I get them with the following line: private static List<Type> GetAlgorithmTypes { get { return Assembly.GetAssembly(typeof(SymmetricAlgorithm)).GetTypes().Where( type => type.IsSubclassOf(typeof(SymmetricAlgorithm))).ToList(); } } As you can see when i run this, AesCryptoServiceProvider is not a member of this group, even though it inherits from AES, which does belong to SymmetricAlgorithm and shows up in my list. This wouldn't be so much of a problem, i can manually add the provider in the group if i have too, but then if i try to retrieve this type by its name: Type t = Type.GetType("System.Security.Cryptography.AesCryptoServiceProvider"); i get a null object for AesCryptoServiceProvider, but not for any of the other items in the group. This is really strange, and i'm wondering if anyone has any ideas. It's kinda making me need to use tripleDES because of this (since my machines are all running the FIPS compliance requirement). Thanks for any help!

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• Have the default security settings changed in Windows 7 that would affect IPrincipal.IsInRole?

  - by adrianbanks

  We use NTLM auth in our application to determine whether a user can perform certain operations. We use the IPrincipal of their current Windows login (in WinForms applications), calling IsInRole to check for specific group memberships. To check that a user is a local administrator on the machine, we use: AppDomain.CurrentDomain.SetPrincipalPolicy(PrincipalPolicy.WindowsPrincipal); ... bool allowed = Thread.CurrentPrincipal.IsInRole(@"Builtin\Administrators") This works if the current user is the Administrator user, or is another user that is a member of the Builtin\Administrators group. In our testing on Windows 7, we have found that this no longer works as expected. The Administrator user still works fine, but any other user that is a member of the Builtin\Administrators group returns false for the IsInRole call. What could be causing this difference? I have a gut feeling that a default setting has changed somewhere (possible in gpedit), but cannot find anything that looks like the culprit.

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• Script to Copy User according to UID

  - by bradlis7

  I'm looking for a way to copy all non-system users from one PC to another. I can get the group and passwd files copied over using this awk -F":" ' $3 > 499 ' etc/passwd >> /etc/passwd awk -F":" ' $3 > 499 ' etc/group >> /etc/group But, how would I go about getting the shadow file copied over since it does not store the UID? Assume that there are over 1000 users, so doing a grep with the usernames, such as egrep '(bob|bill|sarah|sal):' etc/shadow >> /etc/shadow generating the usernames from the awk code above, would be a bit inefficient, but a possible option.

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• Stata output files in surveys

  - by William Shakespeare

  I have some survey data which I'm using Stata to analyze. I want to compute means of one variable by group and save those means to a Stata file. My code looks like this: svyset [iw=wtsupp], sdrweight(repwtp1-repwtp160) vce(sdr) svy: mean x I tried svy: by grp: mean x but that did not work. I could save each mean to a separate file by simply saying svy: mean x if grp==1 but that's inefficient. Is there a better way? Saving results to a file like one can use SAS ODS to capture results is also a need. I am not talking about the log here. I need the means and the associated group. I'm thinking estimates save [path],replace but I'm not sure if that will give me a Stata file or the group if I can figure out how to use by processing.

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• Acts as Tree with Multiple Models

  - by Joe

  I've got several models that I'd like to relate together hierarchically. For simplicity's sake, let's say I've got these three: class Group < ActiveRecord::Base acts_as_tree has_many :users end class User < ActiveRecord::Base acts_as_tree belongs_to :group has_many :posts end class Post < ActiveRecord::Base acts_as_tree belongs_to :user end Under the current acts_as_tree, each node can individually can relate hierarchically to other nodes provided they are of the same type. What I'd like is to remove this restriction on type identity, so that SomePost.parent could have a User or a Post as its' parent, and that SomeUser.parent could have another user or a group as its parent. Any thoughts?

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• How to Sum calulated fields

  - by Nazero Jerry

  I‘d like to ask I question that here that I think would be easy to some people. Ok I have query that return records of two related tables. (One to many) In this query I have about 3 to 4 calculated fields that are based on the fields from the 2 tables. Now I want to have a group by clause for names and sum clause to sum the calculated fields but it ends up in error message saying: “You tried to execute a query that is not part of aggregate function” So I decided to just run the query without the totals *(ie no group by , sum etc,,,) : And then I created another query that totals my previous query. ( i.e. using group by clause for names and sum for calculated fields… no calculation here) This is fine ( I use to do this) but I don’t like having two queries just to get summary total. Is their any other way of doing this in the design view and create only one query?. I would very much appreciate. Thankyou: JM

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• Placement of service methods

  - by mhp

  Let's assume I have two service classes with the following methods: GroupService createGroup() deleteGroup() updateGroup() findGroup() UserService createUser() deleteUser() updateUser() findUser() Now, I am thinking about the aesthetics of theses classes. Imagine we want to implement a method which search for all user of a specific group. Which service class is responsible for such a method? I mean, the return value is a user (or maybe a collection of users) but the parameter (which means the name of the group) is a group. So which service class is the better place to put this method in?

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• administrator permission are recommended for running visual studio sp1 on windows 7 rc

  - by vinayakg

  I get this annoying message everytime I try to run visual studio 2005(even using "Run as Administrator" gives same message). I have VS 2005 Professional with all the latest service packs installed including vs2005 SP1 and vs 2005 update for Vista. I am part of the administrators group on my machine. Still I have this problem. Some read on the web suggests that Running program in Compatibility mode solves the problem. Others also recommend turning off the message forever. Well my question is how do I turn off this warning which seems to bother me even if I am part of administrators group. Does Visual Studio does not run in administrator mode even when I am an administrator or even I use "Run as adminsitrator". Also it would be greate if someone out there can highlight what features of Visual Studio wont be available if Visual Studio is launched as a normal user (User is not an administrator/part of the administrator group) on Windows 7.

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• IGrouping and Casting in Linq

  - by FiveTools

  I have the following query: var groupCats = from g in groups group g by g.Value into grouped select new { GroupCategory = grouped.Key, Categories = GetCategories(grouped.Key, child) }; This works fine. In the anonymous type returned GroupCategory is a string, and Categories are an Enumerable - what is the proper way to declare this instead of using 'var'? I tried: IGrouping<string,string> groupCats = from g in groups group g by g.Value into grouped select new { GroupCategory = grouped.Key, Categories = GetCategories(grouped.Key, child) }; and IGrouping<string,Enumerable<string>> groupCats = from g in groups group g by g.Value into grouped select new { GroupCategory = grouped.Key, Categories = GetCategories(grouped.Key, child) }; In both instances I get: Cannot implicity convert type....An explicit conversion exists (are you missing a cast) How do I cast this?

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• How should I implement items that are normalized in the Database, in Object Oriented Design?

  - by Jonas

  How should I implement items that are normalized in the Database, in Object Oriented classes? In the database I have a big table of items and a smaller of groups. Each item belong to one group. This is how my database design look like: +----------------------------------------+ | Inventory | +----+------+-------+----------+---------+ | Id | Name | Price | Quantity | GroupId | +----+------+-------+----------+---------+ | 43 | Box | 34.00 | 456 | 4 | | 56 | Ball | 56.50 | 3 | 6 | | 66 | Tin | 23.00 | 14 | 4 | +----+------+-------+----------+---------+ Totally 3000 lines +----------------------+ | Groups | +---------+------+-----+ | GroupId | Name | VAT | +---------+------+-----+ | 4 | Mini | 0.2 | | 6 | Big | 0.3 | +---------+------+-----+ Totally 10 lines I will use the OOP classes in a GUI, where the user can edit Items and Groups in the inventory. It should also be easy to do calculations with a bunch of items. The group information like VAT are needed for the calculations. I will write an Item class, but do I need a Group class? and if I need it, should I keep them in a global location or how do I access it when I need it for Item-calculations? Is there any design pattern for this case?

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• Core Data - Relationship to dissimilar entities

  - by carotene

  Suppose I have the following data model: Entity Person Attribute name String Attribute personType String Attribute dailyRecords Entity CarpenterDailyRecord Attribute numberOfNailsHammered Int Attribute picNameOfFinishedCabinet String Entity WindowWasherDailyRecord Attribute nameOfBuildingWashed String Attribute numberOfWindowsWashed Int I would like to establish a to-many relationship between the Person.dailyRecords and 1 of the daily record entities (which changes depending on the person type). Of course, i could create a CarpenterPerson and WindowWasher entity which each points to it's unique daily record structure, but i have to group people together in my app somehow. so if i do a Group Entity: Entity Group Attribute people array i'm still stuck. how do i point to multiple & different Person entities? There must be an obvious answer, it's just i'm so new to all of this. thanks!

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