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  • Exclude one or more elements from being connected (using connectWith) in jQuery's sortable lists

    - by Lev
    I have two lists, one with an ID of "vlist" and one with an ID of "hlist". The "vlist" holds elements which should be visible, while the "hlist" holds items that should remain hidden. The idea here is to allow the administrator of the system to specify which elements/fields should be shown on a sign-up page, and which shouldn't. The two lists are connected using "connectWith", so the administrator can drag items from the visible list to the hidden list (or vice versa). My dilemma is that there are a few fields I want locked into the visible list, but still sortable within that one list. For example, the "username", "email" and "password" fields should be locked within the visible list (as they always need to be used for registration). Is this even possible? Perhaps it is a no-brainer that I simply haven't discovered yet. I've looked around through jQuery's documentation for a while and can't seem to find anything related to this scenario. I have found how you can "cancel" specific elements in the list from being sortable altogether or even disabled from being a dropable target, but this doesn't do it. The user should still have the ability to drag these items within the "visible" list, in case they want to adjust the ordering of the locked fields. I'm also aware that you can contain sortable elements within a specific element or DOM object, but this also can't be used as this only seems to apply to the whole sortable list, and not specific elements of that list. I've even tried to see if something like this would work after I built the sortable listing(s): $('#vlist > #slist-li-username').sortable('option', 'containment', '#vlist'); Obviously, that didn't work either or I wouldn't be posting this. In case it might help, I thought I'd throw in the code I'm using now; here is the jQuery code: $(function() { $('#vlist, #hlist').sortable ({ connectWith: '.signup-set_flist', forcePlaceholderSize: true, receive: function (event, ui) { var itemID = ui.item.attr('id'); var fID = itemID.replace(/slist-li-/g, ''); var hID = 'slist-' + fID; if (ui.sender.attr('id') == 'vlist') { $('#'+hID).val(''); } else { $('#'+hID).val(fID); } } }).disableSelection(); $('#vlist > #slist-li-username').sortable('option', 'containment', '#vlist'); }); And as for the HTML, I'll upload it to here (since StackOverflow seems to break when I paste it in here - even in code mode): http://sikosoft.net/jquery-sort-connect.html Any help would greatly be appreciated! :) Oh, and be gentle as this is my first question here. ;)

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  • scala currying by nested functions or by multiple parameter lists

    - by Morgan Creighton
    In Scala, I can define a function with two parameter lists. def myAdd(x :Int)(y :Int) = x + y This makes it easy to define a partially applied function. val plusFive = myAdd(5) _ But, I can accomplish something similar by defining and returning a nested function. def myOtherAdd(x :Int) = { def f(y :Int) = x + y f _ } Cosmetically, I've moved the underscore, but this still feels like currying. val otherPlusFive = myOtherAdd(5) What criteria should I use to prefer one approach over the other?

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  • PHP Trasnlate HTML page using google translate

    - by John Jones
    Afternoon, Bit of a tricky question this one, I have a website and need to translate the pages into french, I am using google translate API to do the translation. What I am doing is loading in the HTML templates into a string using PHP and then need to translate the text copy on the pages and then save as for example: fr_master_header.html de_master_header.html The problem I have is identifying the text copy on the page ignoring the HTML, replacing the copy in the extact place and then saving the file with the HTML tags and trasnlated text copy. Cheers in advanced.

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  • Algorithm to retrieve every possible combination of sublists of a two lists

    - by sgmoore
    Suppose I have two lists, how do I iterate through every possible combination of every sublist, such that each item appears once and only once. I guess an example could be if you have employees and jobs and you want split them into teams, where each employee can only be in one team and each job can only be in one team. Eg List<string> employees = new List<string>() { "Adam", "Bob"} ; List<string> jobs = new List<string>() { "1", "2", "3"}; I want Adam : 1 Bob : 2 , 3 Adam : 1 , 2 Bob : 3 Adam : 1 , 3 Bob : 2 Adam : 2 Bob : 1 , 3 Adam : 2 , 3 Bob : 1 Adam : 3 Bob : 1 , 2 Adam, Bob : 1, 2, 3 I tried using the answer to this stackoverflow question to generate a list of every possible combination of employees and every possible combination of jobs and then select one item from each from each list, but that's about as far as I got. I don't know the maximum size of the lists, but it would be certainly be less than 100 and there may be other limiting factors (such as each team can have no more than 5 employees) Update Not sure whether this can be tidied up more and/or simplified, but this is what I have ended up with so far. It uses the Group algorithm supplied by Yorye (see his answer below), but I removed the orderby which I don't need and caused problems if the keys are not comparable. var employees = new List<string>() { "Adam", "Bob" } ; var jobs = new List<string>() { "1", "2", "3" }; int c= 0; foreach (int noOfTeams in Enumerable.Range(1, employees.Count)) { var hs = new HashSet<string>(); foreach( var grouping in Group(Enumerable.Range(1, noOfTeams).ToList(), employees)) { // Generate a unique key for each group to detect duplicates. var key = string.Join(":" , grouping.Select(sub => string.Join(",", sub))); if (!hs.Add(key)) continue; List<List<string>> teams = (from r in grouping select r.ToList()).ToList(); foreach (var group in Group(teams, jobs)) { foreach (var sub in group) { Console.WriteLine(String.Join(", " , sub.Key ) + " : " + string.Join(", ", sub)); } Console.WriteLine(); c++; } } } Console.WriteLine(String.Format("{0:n0} combinations for {1} employees and {2} jobs" , c , employees.Count, jobs.Count)); Since I'm not worried about the order of the results, this seems to give me what I need.

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  • Html.RadioButtonListFor problem

    - by ognjenb
    <%using (Html.BeginForm("Numbers", "Numbers", FormMethod.Post)) { %> <table id="numbers"> <tr> <th> prvi_br </th> <th> drugi_br </th> <th> treci_br </th> </tr> <%int rb =1; %>" <% foreach (var item in Model) { %> <tr> <td> <%= Html.Encode(item.prvi_br) %> <input type="radio" name="<%= Html.Encode(rb) %>" value="<%= Html.Encode(rb) %>" /> </td> <td> <%= Html.Encode(item.drugi_br) %> <input type="radio" name="<%= Html.Encode(rb) %>" value="<%= Html.Encode(rb) %>"/> </td> <td> <%= Html.Encode(item.treci_br) %> <input type="radio" name="<%= Html.Encode(rb) %>" value="<%= Html.Encode(rb) %>"/> </td> </tr> <% rb++; %> <% } %> </table> <p> <input type="submit" value="Save" /> </p> <%} %> How post this form with only one checked radio button? In my case all of 3 radio buttons is possible to check. How to restrict so that it is possible check only one radio. In this article I found good solutions but it can not be applied because I have a table.

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  • Using PyLab to create a 2D graph from two separate lists

    - by user324333
    Hey Guys, This seems like a basic problem with an easy answer but I simply cannot figure it out no matter how much I try. I am trying to create a line graph based on two lists. For my x-axis, I want my list to be a set of strings. x_axis_list = ["Jan-06","Jul-06","Jan-07","Jul-07","Jan-08"] y_axis_list = [5,7,6,8,9] Any suggestions on how to best graph these items?

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  • Reading lists from a file in Ruby

    - by Gjorgji
    Hi, I have a txt file which contains data in the following format: X1 Y1 X2 Y2 etc.. I want to read the data from this file and create two lists in ruby (X containing X1, X2 and Y containing Y1, Y2). How can I do this in Ruby? Thanks.

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  • Under what circumstances are linked lists useful?

    - by Jerry Coffin
    Most times I see people try to use linked lists, it seems to me like a poor (or very poor) choice. Perhaps it would be useful to explore the circumstances under which a linked list is or is not a good choice of data structure. Ideally, answers would expound on the criteria to use in selecting a data structure, and which data structures are likely to work best under specified circumstances.

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  • Vim - Activiting html snippets on php files

    - by Alfredo Palhares
    Hello i am using vim and snipMate i very times i need to name the html files to php, just because 1 or 2 lines of code. I every time i create an php file no introduce html and i have to activate the html snippets manually with the command set ft=php.html I intend to activate it automatically in this this line on my vimrc autocmd BufREad, BufNewFile *.php set ft=php.html Is this correct? I am missing anything or is something wrong? Thanks already.

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  • YAML front matter for Jekyll and nested lists

    - by motleydev
    I have a set of nested yaml lists with something like the following: title: the example image: link.jpg products: - top-level: Product One arbitrary: Value nested-products: - nested: Associated Product sub-arbitrary: Associated Value - top-level: Product Two arbitrary: Value - top-level: Product Three arbitrary: Value I can loop through the products with no problem using for item in page.products and I can use a logic operator to determine if nested products exist - what I CAN'T do is loop through multiple nested-products per iteration of top-level I have tried using for subitem in item and other options - but I can't get it to work - any ideas?

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  • Use .js files for caching large dropdown lists.

    - by ProfK
    I would like to keep the contents of large UI lists cached on the client, and updated according to criterial or regularly. Client side code can then just fill the dropdowns locally, avoiding long page download times. How can I go about this? I mean, what patterns and strategies would be suitable for this?

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  • Classic asp comparison of comma separated lists

    - by Reiwoldt
    Hello, I have two comma separated lists:- 36,189,47,183,65,50 65,50,189,47 The question is how to compare the two in classic ASP in order to identify and return any values that exist in list 1 but that don't exist in list 2 bearing in mind that associative arrays aren't available. E.g., in the above example I would need the return value to be 36,183 Thanks

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  • Doctype, HTML 5

    - by MB1
    Hi, i have two questions: 1) was HTML released and if yes, when? 2) is doctype HTML 5 in use? or is it better to use one of these: - HTML 4.01 Strict, - HTML 4.01 Transitional, - HTML 4.01 Frameset, - XHTML 1.0 Strict, - XHTML 1.0 Transitional, - XHTML 1.0 Frameset, - XHTML 1.1

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  • Append to list of lists

    - by Joel
    Hello, I am trying to build a list of lists using the following code: list=3*[[]] Now I am trying to append a string to the list in position 0: list[0].append("hello") However, instead of receiving the list [ ["hello"] , [], [] ] I am receiving the list: [ ["hello"] ,["hello"] , ["hello"] ] Am I missing something? Thanks, Joel

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  • create a dict of lists from a string

    - by Chris Card
    I want to convert a string such as 'a=b,a=c,a=d,b=e' into a dict of lists {'a': ['b', 'c', 'd'], 'b': ['e']} in Python 2.6. My current solution is this: def merge(d1, d2): for k, v in d2.items(): if k in d1: if type(d1[k]) != type(list()): d1[k] = list(d1[k]) d1[k].append(v) else: d1[k] = list(v) return d1 record = 'a=b,a=c,a=d,b=e' print reduce(merge, map(dict,[[x.split('=')] for x in record.split(',')])) which I'm sure is unnecessarily complicated. Any better solutions?

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  • in Python find number of same elements in 2 lists

    - by John
    Hi, In Python if I have 2 lists say: l1 = ['a', 'b', 'c', 'd'] l2 = ['c', 'd', 'e'] is there a way to find out how many elements they have the same. In the case about it would be 2 (c and d) I know I could just do a nested loop but is there not a built in function like in php with the array_intersect function Thanks

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  • Convert codes to HTML with CSS style

    - by David.Chu.ca
    I normally use VIM to edit my codes and convert them to HTML by using TOhtml command. The only thing I don't like is that the converted HTML does not have css class style definitions. I am not sure if there is tool to convert codes to HTML with css, or I can use additional tool or command to convert HTML HTML with css?

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  • Join a list of lists together into 1 list in Python

    - by dotty
    Hay All. I have a list which consists of many lists, here is an example [ [Obj, Obj, Obj, Obj], [Obj], [Obj], [ [Obj,Obj], [Obj,Obj,Obj] ] ] Is there a way to join all these items together as 1 list, so the output will be something like [Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj] Thanks

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  • Need to try and count repeated lists within a list

    - by user1828603
    Im trying to count how many repeated lists there are inside a list. But it doesnt work the same way I could count repeated elements in just a list. Im fairly new to python, so apologies if it sounds too easy. this is what i did x= [["coffee", "cola", "juice" "tea" ],["coffee", "cola", "juice" "tea"] ["cola", "coffee", "juice" "tea" ]] dictt= {} for item in x: dictt[item]= dictt.get(item, 0) +1 return(dictt)

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  • Web Programming language for very large lists?

    - by behrk2
    Hello, In your experience, what is the best web programming language used to handle sorting and comparison of very large lists (ie tens of thousands of email addresses)? I am most familiar with PHP. I think that it could get the job done, but I'm unsure of other languages and if there might be a bettor suitor. Thanks!

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  • python: html writer?

    - by Bin Chen
    With jquery it's very easy to insert some element inside another element using the selector technology, I am wondering if there is any python library that can do things similar with jquery, the reason is I want server side python program to produce the static pages, which needs to parse the html and insert something into it. Or other alternative, not in python language at all? EDIT: To be clear, I want to use python to write below program: h = html.parse('temp.html') h.find('#idnum').html('<b>my html generated</b>') h.close()

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