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  • Stop browser from filling textboxes with details

    - by TenaciousImpy
    Hi, I've run into a really annoying problem, and I'm hoping it's just a setting I've missed. I've got an ASP.NET application which allows users to enter their username/password in various places (e.g. login, change password, change username etc..). When I logged in, the browser asked if I would like to store the user details. Usually, I click 'no', but this time I decided to click 'yes'. Now, certain textboxes in my form are prefilled with the username or password. Is it possible to remove these, as they sometimes appear in textboxes which shouldn't be prefilled. I tried setting AutoCompleteType=none and Text='' but it still gets prefilled. The textboxes don't have much in common, except the same CssClass and, for password boxes, TextMode=password. The names are different, although sometimes they include the word name (e.g. fullName, userName). Is there a way to stop the browser from filling certain textboxes? Thanks

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  • How can I set controls for a web page ??

    - by Rami Jarrar
    I have this login page with https, and i reach to this approach:: import ClientForm import urllib2 request = urllib2.Request("http://ritaj.birzeit.edu") response = urllib2.urlopen(request) forms = ClientForms.ParseResponseEx(response) response.close() f = forms[0] username = str(raw_input("Username: ")) password = str(raw_input("Password: ")) ## Here What To Do request2 = form.click() i get the controls of that page >>> f = forms[0] >>> [c.name for c in f.controls] ['q', 'sitesearch', 'sa', 'domains', 'form:mode', 'form:id', '__confirmed_p', '__refreshing_p', 'return_url', 'time', 'token_id', 'hash', 'username', 'password', 'persistent_p', 'formbutton:ok'] so how can i set the username and password controls of the "non-form form" f ??? and i have another problem,, how to know if its the right username and password ??

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  • Cookbook: SES and UCM setup

    - by George Maggessy
    The purpose of this post is to guide you setting up the integration between UCM and SES. On my next post I’ll show different approaches to integrate WebCenter Portal, UCM and SES based on some common scenarios. Let’s get started. WebCenter Content Configuration WebCenter Content has a component that adds functionality to the content server to allow it to be searched via the Oracle SES. To enable the component installation, go to Administration -&gt; Admin Server and select SESCrawlerExport. Click the update button and restart UCM_server1 managed server. Once the managed server is back, we’ll configure the component. In the menu, under Administration you should see SESCrawlerExport. Click on the link. You’ll see the window below. Click on Configure SESCrawlerExport. Configure the values below: Hostname: SES hostname. Feed Location: Directory where data feeds will be saved. Metadata List: List of metadata that will be searchable by SES. After updating the values click on the Update button. Come back to the SESCrawlerExport Administration UI and click on Take Snapshot button. It will create the data feeds in the specified Feed Location. To check if the correct configuration was done, please access the following URL http://&lt;ucm_server&gt;:&lt;port&gt;/cs/idcplg?IdcService=SES_CRAWLER_DOWLOAD_CONFIG&amp;source=default. It should download config file in the format below: &lt;?xml version="1.0" encoding="UTF-8"?&gt; &lt;rsscrawler xmlns="http://xmlns.oracle.com/search/rsscrawlerconfig"&gt; &lt;feedLocation&gt;&lt;![CDATA[http://adc6160699.us.oracle.com:16200/cs/idcplg?IdcService=SES_CRAWLER_DOWNLOAD_CONTROL&amp;source=default]]&gt;&lt;/feedLocation&gt; &lt;errorFileLocation&gt;&lt;![CDATA[http://adc6160699.us.oracle.com:16200/cs/idcplg?IdcService=SES_CRAWLER_STATUS&amp;IsJava=1&amp;source=default&amp;StatusFeed=]]&gt;&lt;/errorFileLocation&gt; &lt;feedType&gt;controlFeed&lt;/feedType&gt; &lt;sourceName&gt;default&lt;/sourceName&gt; &lt;securityType&gt;attributeBased&lt;/securityType&gt; &lt;securityAttribute name="Account" grant="true"/&gt; &lt;securityAttribute name="DocSecurityGroup" grant="true"/&gt; &lt;securityAttribute name="Collab" grant="true"/&gt; &lt;/rsscrawler&gt; Make sure Account and DocSecurityGroup values are true. SES Configuration Let’s start by configuring the Identity Plug-ins in SES. Go to Global Settings -&gt; System -&gt; Identity Management Setup. Select Oracle Content Server and click the Activate button. We’ll populate the following values: HTTP endpoint for authentication: URL to WebCenter Content. Notice that /cs/idcplg was added at the end of the URL. Admin User: UCM Admin user. This user must have access to all CPOE content. Password: Password to Admin user. Authentication Type: NATIVE. Go back to the Home tab and click on Sources on the top left. Select Oracle Content Server on the right and click the Create button. Configuration URL: URL that point to the configuration file. Example: http://&lt;ucm_hostname&gt;:&lt;port&gt;/cs/idcplg?IdcService=SES_CRAWLER_DOWNLOAD_CONFIG&amp;source=default. User ID: UCM Admin user. Password: Password to Admin user. Click on the Authorization tab and add the appropriate values to the fields below. Make sure you see the ACCOUNT and DOCSECURITYGROUP security attributes at the end of the page. HTTP endpoint for authorization: http://&lt;ucm_hostname&gt;:&lt;port&gt;/cs/idcplg. Display URL prefix: http://&lt;ucm_hostname&gt;:&lt;port&gt;/cs. Administrator user: UCM Admin user. Administrator password. On the Document Types tab, add the documents that should be indexed by SES. As our last step, we’ll configure the Federation Trusted Entities under Global Settings. Entity Name: The user must be present in both the identity management server configured for your WebCenter application and the identity management server configured for Oracle SES. For instance, I used weblogic in my sample. Password: Entity user password.\ Now you are ready to test the integration on the SES UI: http://&lt;ses hostname&gt;:&lt;port&gt;/search/query/.

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  • Encryption using rijndael

    - by user363295
    Hi all. I'm quite new in programming .I wrote the below code in order to prompt the user for a password to encrypting a file, But it just work when the length of password is 8, What can I do on order to accepting any number of characters for the password? string pass = textBox2.Text.ToString(); string password = @"" + pass + ""; UnicodeEncoding UE = new UnicodeEncoding(); byte[] key = UE.GetBytes(password); FileStream fsCrypt = new FileStream(@"c:\\users\\new", FileMode.Create); name = fsCrypt.Name; RijndaelManaged RMCrypto = new RijndaelManaged(); CryptoStream cs = new CryptoStream(fsCrypt, RMCrypto.CreateEncryptor(key, key), CryptoStreamMode.Write); FileStream fsIn = new FileStream(filename, FileMode.Open); int data; while ((data = fsIn.ReadByte()) != -1) cs.WriteByte((byte)data);

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  • SQL Encryption - Asymmetric Key - 2nd Server

    - by Jason Heine
    Hello, I created an asymmetric key on one of my SQL servers (2008). I encrypted a password field and I am able to retrieve that password just fine on my development server. The issue comes into play where I need to move this data to a production server. Here is the code for the key that was created: CREATE MASTER KEY ENCRYPTION BY PASSWORD='#########' CREATE ASYMMETRIC KEY UserEncryptionKey WITH ALGORITHM = RSA_2048 Now, when I run this on the production server, it creates the key just fine. However, when I run my sproc to get the password, it returns NULL. SQL: SELECT EncryptByAsymKey(AsymKey_ID('UserEncryptionKey'), Password ) FROM Users WHERE UserName = '######' Any thoughts on what I need to do to get the encrypted field to work on multiple SQL Servers? Please let me know if I need to clarify something. Thanks

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  • Why does this regular expression fail?

    - by Stephen
    I have a password validation script in PHP that checks a few different regular expressions, and throws a unique error message depending on which one fails. Here is an array of the regular expressions and the error messages that are thrown if the match fails: array( 'rule1' => array( '/^.*[\d].*$/i', 'Password must contain at least one number.' ), 'rule2' => array( '/^.*[a-z].*$/i', 'Password must contain at least one lowercase letter' ), 'rule3' => array( '/^.*[A-Z].*$/i', 'Password must contain at least one uppercase letter' ), 'rule4' => array( '/^.*[~!@#$%^&*()_+=].*$/i', 'Password must contain at least one special character [~!@#$%^&*()_+=]' ) ); For some reason, no matter what I pass through the validation, the "Special Characters" rule fails. I'm guessing it's a problem with the expression. If there's a better (or correct) way to write these expressions, I'm all ears!

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  • How can I login in a website with Pyhon?

    - by Shady
    How can I do it? I was trying to enter some specified link (with urllib), but to do it, I need to log. I have this source from the site <form id="login-form" action="auth/login" method="post"> <div> <!--label for="rememberme">Remember me</label><input type="checkbox" class="remember" checked="checked" name="remember me" /--> <label for="email" id="email-label" class="no-js">Email</label> <input id="email-email" type="text" name="handle" value="" autocomplete="off" /> <label for="combination" id="combo-label" class="no-js">Combination</label> <input id="password-clear" type="text" value="Combination" autocomplete="off" /> <input id="password-password" type="password" name="password" value="" autocomplete="off" /> <input id="sumbitLogin" class="signin" type="submit" value="Sign In" /> It's possible?

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  • How secure is a PostgreSQL database if my server is stolen?

    - by orokusaki
    If I have a server with a database if top secret data in PostgreSQL and my password is practically impossible to crack (128 character string of all sorts of weird chars, generated by hand). The server password is also uncrackable in theory (basically, ignore the possibility of a password crack on the DB). Aside from a password crack, how easy is it to get the data out of this database? Assumptions: Only the DB exists on the server. There is no password in a PHP script or anything like that The person who has the server is a computer / DB / hard-drive recovery expert I'm not using any hard-drive encryption or anything out of the norm for protection I'm trying to understand the risks involved with somebody gaining physical access to my server's hard-drives.

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  • Why is django.test.client.Client not keeping me logged in.

    - by Mystic
    I'm using django.test.client.Client to test whether some text shows up when a user is logged in. However, I the Client object doesn't seem to be keeping me logged in. This test passes if done manually with Firefox but not when done with the Client object. class Test(TestCase): def test_view(self): user.set_password(password) user.save() client = self.client # I thought a more manual way would work, but no luck # client.post('/login', {'username':user.username, 'password':password}) login_successful = client.login(username=user.username, password=password) # this assert passes self.assertTrue(login_successful) response = client.get("/path", follow=True) #whether follow=True or not doesn't seem to work self.assertContains(response, "needle" ) When I print response it returns the login form that is hidden by: {% if not request.user.is_authenticated %} ... form ... {% endif %} This is confirmed when I run ipython manage.py shell. The problem seems to be that the Client object is not keeping the session authenticated.

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  • How do I get phpMyAdmin to connect to a local mysql server?

    - by bryan
    Hi everyone, I have my config.inc.php file, and have set my host name to localhost. Unfortunately, I have no idea what my username/password should be. Is that something I need to configure on the MySql side? I tried creating an arbitrary username/password (admin/password), but when I try to log into phpMyAdmin with those credentials, I get an error: (#1045 - Access denied for user 'admin'@'localhost' (using password: YES)) Can anyone point me in the right direction? (Sorry for the dumb question; I just haven't had to install mysql before. I've always had a host name / username / password given to me.) Thanks!

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  • Encryption-Decryption in Rails

    - by Salil
    Hi All, I am using require 'digest/sha1' to encrypt my password and save into database. During login I authenticate by matching the encrypted password saved in database and again encrypted the one use enter in password field. As of now everything works fine but now I want to do 'Forgot Password' functionality. To do this I need to decrypt the password which is saved in database to find original one. How to decrypt using digest/sha1? Or does anyone know any algorithm which supports encryption & decryption as well? I am using ruby on rails so I need Ruby way to accomplish it.

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  • I want to design a html form in python

    - by VaIbHaV-JaIn
    when user will enter details in the text box on the html from <h1>Please enter new password</h1> <form method="POST" enctype="application/json action="uid"> Password<input name="passwd"type="password" /><br> Retype Password<input name="repasswd" type="password" /><br> <input type="Submit" /> </form> </body> i want to post the data in json format through http post request and also i want to set content-type = application/json

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  • How to manually verify a user against the asp.net memberhip database

    - by Ekk
    I would like to know how I can verify a user's credential against an existing asp.net membership database. The short story is that we want provide single sign on access. So what I've done is to connect directly to the membership database and tried to run a sql query against the aspnet_Membership table: private bool CanLogin(string userName, string password) { // Check DB to see if the credential is correct try { string passwordHash = FormsAuthentication.HashPasswordForStoringInConfigFile(password, "SHA1"); string sql = string.Format("select 1 from aspnet_Users a inner join aspnet_Membership b on a.UserId = b.UserId and a.applicationid = b.applicationid where a.username = '{0}' and b.password='{1}'", userName.ToLowerInvariant(), passwordHash); using (SqlConnection sqlConn = new SqlConnection(ConfigurationManager.ConnectionStrings["LocalSqlServer"].ConnectionString)) using (SqlCommand sqlCmd = new SqlCommand(sql, sqlConn)) { sqlConn.Open(); int count = sqlCmd.ExecuteNonQuery(); sqlConn.Close(); return count == 1; } } catch (Exception ex) { return false; } } The problem is the password value, does anyone know how the password it is hashed?

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  • How to login with python and save cookie, then use that info to view page for member only

    - by patcsong
    I am quite new in python and trying to write a script to login to the page at http://ryushare.com/login.python. I have try many attempt, but it fails to login and i have no idea why. After login to the page, I wish to get the return of http://ryushare.com/file-manager.python Here's the code I try to attempt by reading the example from others. import urllib, urllib2, cookielib username = 'myusername' password = 'mypassword' cj = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) login_data = urllib.urlencode({'login' : username, 'password' : password}) opener.open('http://www.ryushare.com/login.python', login_data) resp = opener.open('http://ryushare.com/file-manager.python') print resp.read() I check the source code of the login page, it said the username and password value is "login and password" so i change it. I have try some other example which can be found here like google news feed, It also can not able to login : (

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  • How do I handle user authorization the safest way?

    - by Irro
    I'm developing a small website where I'm going to allow user to create accounts but I'm quite clueless when it comes to safety around authorizations. I have built my project in PHP with codeigniter and found a library (Tank Auth) that could handle authorization for me. It stores password in a safe way but I'm still worried about the part when the user sends their password to my server. One easy way to do it would be to send the password in a post-request but I would guess that it's quite easy to sniff such a password. Should I do something with the password on the client side before sending it to my server? And is there any good javascript libraries for this?

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  • jQuery event binding does not work properly or i can't make it properly working

    - by Saiful
    HTML: <input id="email" name="email" type=text /> <input id="password name="password" type="password" /> JavaScript: var fields = ["email","password"]; for (var i in fields) { var field = $("#"+fields[i]); field.bind({ focus: function() { field.css("border-color","#f00"); }, blur: function() { field.css("border-color","#000"); } }); } My desire action will be as follows: When I place cursor on any of the above fields the input field's border will be red. When I take away the cursor from the field it's border will be black. But the event is occurs only for the password filed whether I place and take away cursor form any of the above fields.

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  • built in Soap extension php5 passing in params as associative array

    - by Ageis
    I have this xml I'm wanting to pass to this web service function <UserName>myuser</UserName> <Password>password</Password> <User> <AddCoverCode /> <title>sdadasdsa</title> </User> </CreateNewUser>','',array(),'document', 'literal'); I'm using the soap extension buit in php5. Is this what I'm supposed to be passing in the soapcall function as parameters? array('CreateNewUser' => array( 'UserName' => 'sc', 'Password' => 'i82372', 'Registration' => array('username' =>'new','password' =>'ss'));

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  • Which Java library lets me initialize an object's properties from a properties file?

    - by Kjetil Ødegaard
    Is there a Java library that lets you "deserialize" a properties file directly into an object instance? Example: say you have a file called init.properties: username=fisk password=frosk and a Java class with some properties: class Connection { private String username; private String password; public void setUsername(String username) { this.username = username; } public void setPassword(String password) { this.password = password; } } I want to do this: Connection c = MagicConfigurator.configure("init.properties", new Connection()) and have MagicConfigurator apply all the values from the properties file to the Connection instance. Is there a library with a class like this?

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  • git, SSH_ASKPASS on windows

    - by Martin Schreiber
    I am writing a graphical git frontend for Linux and Windows (MSEgit) based on MSEide+MSEgui. MSEgit has an internal console window which communicates with git by pipes. On Linux it uses a PTY so SSH asks for key unlocking passwords on the PTY. On Windows I wrote a small password entry application and set the SSH_ASKPASS environment variable accordingly. SSH calls the password application if git is started with CreateProcess() dwCreationFlags DETACHED_PROCESS set but the password entry window will not be focused, its taskbar icon flashes instead. SSH does not run the password application if FreeConsole() is called to be sure that there is no attached console to MSEgit and git is started without DETACHED_PROCESS but CREATE_NO_WINDOW instead. I assume a Windows equivalent of POSIX setsid() should be called. How can I force SSH to use SSH_ASKPASS without the DETACHED_PROCESS flag? If this is not possible, how can I ensure that the password entry window is focused?

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  • Should default passwords always be empty?

    - by mafutrct
    I'm currently designing a system that requires an admin to log in using a password. For certain reasons, it is difficult to set this password during installation, but it can be changed later. My idea is this: If I leave the default password empty, it is so horridly insecure that every admin is going to fix this as soon as possible. If I were to use some kind of predefined password instead, admins may think "ah.. nobody would think I've got 'defaultpassword' as my password so it's not very important to change." So the basic thought is to make it so terrible that even the most lazy people are going to do something about it.

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  • How can I login to a website with Python?

    - by Shady
    How can I do it? I was trying to enter some specified link (with urllib), but to do it, I need to log in. I have this source from the site: <form id="login-form" action="auth/login" method="post"> <div> <!--label for="rememberme">Remember me</label><input type="checkbox" class="remember" checked="checked" name="remember me" /--> <label for="email" id="email-label" class="no-js">Email</label> <input id="email-email" type="text" name="handle" value="" autocomplete="off" /> <label for="combination" id="combo-label" class="no-js">Combination</label> <input id="password-clear" type="text" value="Combination" autocomplete="off" /> <input id="password-password" type="password" name="password" value="" autocomplete="off" /> <input id="sumbitLogin" class="signin" type="submit" value="Sign In" /> Is this possible?

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  • Developed android application cannot connect to phpmyadmin

    - by user1850936
    I am developing an app with eclipse. I tried to store the data that key in by user into database in phpmyadmin. Unfortunately, after the user has clicked on submit button, there is no response and data is not stored in my database. Here is my java file: import java.util.ArrayList; import java.util.List; import org.apache.http.NameValuePair; import org.apache.http.message.BasicNameValuePair; import org.json.JSONObject; import android.app.Activity; import android.app.AlertDialog; import android.content.DialogInterface; import android.content.Intent; import android.os.Bundle; import android.util.Log; import android.view.View; import android.widget.Button; import android.widget.EditText; import android.widget.RadioButton; import android.content.res.Configuration; public class UserRegister extends Activity { JSONParser jsonParser = new JSONParser(); EditText inputName; EditText inputUsername; EditText inputEmail; EditText inputPassword; RadioButton button1; RadioButton button2; Button button3; int success = 0; private static String url_register_user = "http://10.20.92.81/database/add_user.php"; private static final String TAG_SUCCESS = "success"; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_user_register); inputName = (EditText) findViewById(R.id.nameTextBox); inputUsername = (EditText) findViewById(R.id.usernameTextBox); inputEmail = (EditText) findViewById(R.id.emailTextBox); inputPassword = (EditText) findViewById(R.id.pwTextBox); Button button3 = (Button) findViewById(R.id.regSubmitButton); button3.setOnClickListener(new View.OnClickListener() { public void onClick(View view) { String name = inputName.getText().toString(); String username = inputUsername.getText().toString(); String email = inputEmail.getText().toString(); String password = inputPassword.getText().toString(); if (name.contentEquals("")||username.contentEquals("")||email.contentEquals("")||password.contentEquals("")) { AlertDialog.Builder builder = new AlertDialog.Builder(UserRegister.this); builder.setMessage(R.string.nullAlert) .setTitle(R.string.alertTitle); builder.setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int id) { } }); AlertDialog dialog = builder.show(); } // creating new product in background thread RegisterNewUser(); } }); } public void RegisterNewUser() { try { String name = inputName.getText().toString(); String username = inputUsername.getText().toString(); String email = inputEmail.getText().toString(); String password = inputPassword.getText().toString(); // Building Parameters List<NameValuePair> params = new ArrayList<NameValuePair>(); params.add(new BasicNameValuePair("name", name)); params.add(new BasicNameValuePair("username", username)); params.add(new BasicNameValuePair("email", email)); params.add(new BasicNameValuePair("password", password)); // getting JSON Object // Note that create product url accepts POST method JSONObject json = jsonParser.makeHttpRequest(url_register_user, "GET", params); // check log cat for response Log.d("Send Notification", json.toString()); success = json.getInt(TAG_SUCCESS); if (success == 1) { // successfully created product Intent i = new Intent(getApplicationContext(), StudentLogin.class); startActivity(i); finish(); } else { // failed to register } } catch (Exception e) { e.printStackTrace(); } } @Override public void onConfigurationChanged(Configuration newConfig) { super.onConfigurationChanged(newConfig); } } my php file: <?php $response = array(); require_once __DIR__ . '/db_connect.php'; $db = new DB_CONNECT(); if (isset($_GET['name']) && isset($_GET['username']) && isset($_GET['email']) && isset($_GET['password'])) { $name = $_GET['name']; $username = $_GET['username']; $email = $_GET['email']; $password = $_GET['password']; // mysql inserting a new row $result = mysql_query("INSERT INTO register(name, username, email, password) VALUES('$name', '$username', '$email', '$password')"); // check if row inserted or not if ($result) { // successfully inserted into database $response["success"] = 1; $response["message"] = "You are successfully registered to MEMS."; // echoing JSON response echo json_encode($response); } else { // failed to insert row $response["success"] = 0; $response["message"] = "Oops! An error occurred."; // echoing JSON response echo json_encode($response); } } else { // required field is missing $response["success"] = 0; $response["message"] = "Required field(s) is missing"; // echoing JSON response echo json_encode($response); } ?> the log cat is as follows: 11-25 10:37:46.772: I/Choreographer(638): Skipped 30 frames! The application may be doing too much work on its main thread.

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  • Check If Stored Procedure Returns Value

    - by Eric
    Hello all, I am using Linq 2 Sql in VS 2010, and I have the following stored procedure to check a username and password ALTER PROCEDURE dbo.CheckUser ( @username varchar(50), @password varchar(50) ) AS SELECT * FROM Users Where UserName=@username AND Password=@password The problem I'm having is that it throws an exception if the username and password are incorrect. I'd like to perform a check to see if there is a return value, rather than using try/catch to determine whether the procedure returned a value. Should I do this check in code (C#)? Or is there a way to do it in SQL? Thanks.

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  • can this code be shortened or improved?

    - by user2816683
    Can this be shortened/improved? I'm trying to make a password checker in python. Could the if's be put into a for loop? And if so, how? pw = input("Enter password to test: ") caps = sum(1 for c in pw if c.isupper()) lower = sum(1 for c in pw if c.islower()) nums = sum(1 for c in pw if c.isnumeric()) scr = ['weak', 'medium', 'strong'] r = [caps, lower, nums] if len(pw) < 6: print("too short") elif len(pw) > 12: print("too long") if caps >= 1: if lower >= 1: if nums >= 1: print(scr[2]) elif nums < 1: print("your password is " + scr[1]) elif lower < 1: print("your password strength is " + scr[0]) elif caps < 1: print("your password strength is " + scr[1]) Thanks for any suggestions :D

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  • How to Install Oracle Software on Remote Linux Server

    - by James Taylor
    It is becoming more common these days to install Oracle software on remote Linux servers. This issue has always existed but was generally resolved either by silent installs or by someone physically going to the server to install the software. This is becoming more difficult with the popular virtualisation and cloud deployment strategies. This post provides the steps involved to install Oracle Software using the GUI interface on a remote Linux server. There are many ways to achieve this, the way I resolve this issue is via Virtual Network Computing (VNC) as it is shipped with RedHat and OEL out of the box. For this post I’m using OEL 5 deployed on a OVM guest. If not already done so download and install a client version of VNC so you can connect to the server. There are many out there, for the purpose of this post I use UltraVNC. You can download a free version from http://www.uvnc.com/download/index.html By default VNC Server is installed in your RedHat and OEL OS, but it is not configured. The way VNC works is when started it creates a client instance for the user and binds it to a specific port. So if have an account on the Linux box you can setup a VNC Server session for that user, you don’t need to be root. For the purpose of this document I’m going to use oracle as the user to setup a VNC Session as this is the user I want use to install the software. However to start the VNC Service you must be root. As the root user run the following command: service vncserver start Starting VNC server: no displays configured                [  OK  ] Login to the Linux box as the user  you wan to install the Oracle software [oracle@lisa ~]$ Run the command to create a new VNC server instance for the oracle user: vncserver You will be ask to supply password information. This is what you will enter when connecting from your desktop client. This password is also independent of the actual Linux user password. The VNC Server is acting as a proxy to this instance. You will require a password to access your desktops. Password: Verify: xauth:  creating new authority file /home/oracle/.Xauthority New 'lisa.nz.oracle.com:1 (oracle)' desktop is lisa.nz.oracle.com:1 Creating default startup script /home/oracle/.vnc/xstartup Starting applications specified in /home/oracle/.vnc/xstartup Log file is /home/oracle/.vnc/lisa.nz.oracle.com:1.log As you can see a new instance lisa.nz.oracle.com:1 has been created. If you were to run the vncserver command again another instance lisa.nz.oracle.com:2 will be created. If you are going through a firewall you will need to ensure that the port 5901 (port 1) is open between your client desktop and the Linux Server. Depending on the options chosen at install time a firewall could be in place. The simplest way to disable this is using the command. You will need to be root. service iptables stop This will stop the firewall while you install. If you just want to add a port to the accepted lists use the firewall UI. You will need to be root. system-config-security-level Now you are ready to connect to the server via the VNC. Using the software installed in step one start the VNC Client. You should be prompted for the server and port. If connectivity is established, you will be prompted for the password entered in step 5. You should now be presented with a terminal screen ready to install software Go to the location of the oracle install software and start the Oracle Universal Installer

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