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  • Get current user from View

    - by gosu kiwi
    So what I want to do is, in my main layout, have a menu for logged in users, and a different for anon users. THe layout will be used on every page, so I'm not sure how to do this, as I've seen, the Auth Component can only be used in the controller, this would be nice if I had to do this in only one view, but for every view, how can I do this? Do I have to do something on AppController? What I want to do is basically // layout <?php if(logged): ?> Welcome <?php echo $user; ?> <?php else: ?> Welcom anon, Log in? <?php endif; ?>

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  • iPhone - At user event create objects in the view

    - by insaneshow
    Hello, I am new to iPhone programming, so I think part of the problem is that I don't know what I really want to google to find my answer. I am looking for a method that allows a user to draw a line on the screen. There is no guarantee that it will be straight, it can be curved or whatever. I was thinking that I could create some small square image, and then as they draw, place them into a NSset. But I am not really sure how to communicate each new object up to the view. Up to this point, I've just been messing around with objects I put on the view and then assign movement to those, this is my first jump into on-the-fly object creation. It might be that I just need to jump into a class/object type or even a tutorial, any guidance would be great. Thanks!

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  • How to release my view from stack ?

    - by aman-gupta
    Hi, In my application I m using following coding convention to open my default screen :-- AppDelegate *ptrDefaultScreen = (AppDelegate *)[[UIApplication sharedApplication]delegate]; [self.navigationController presentModalViewController:ptrDefaultScreen.FrmFlashScreenLink animated:YES]; but when I move to other screen after default screen ,my default screen is still exists even i used [self dismissModelViewController:YES]; to dimiss default screen from view. where I m wrong I want my default screen will be completely removed from view. Is any other way to call default screen before actual application. Please help me out.Thanks in advance

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  • How to move to another view without using a button

    - by Will
    My first view displays an image and action indicator while web-servers and database function are run in that background. I want the application to go to my tab view when the functions have been completed. How do I do this? Here is what the views look like. What I have tried: TabBarViewController *tab = [[TabBarViewController alloc]init]; [self presentViewController:tab animated:NO completion:nil]; and [self performSegueWithIdentifier:@"first" sender:self]; Please can you help my to understand how to do this. I have spent many hours googling this problem and couldn't work out how to do it. Thanks EDIT: Added Code

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  • ERROR: there is no parameter $1 when creating view

    - by idlemoments
    When we try to create a view within a funcion we get ERROR: there is no parameter $1. This is the sample code. Begin CREATE VIEW artikelnr AS SELECT datum, 'uitgifte' as "type", CASE WHEN 'test'='test' THEN 0 END as "aantal ontvangen", aantal as "aantal uitgegeven" FROM uitgifteregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN uitgifte ON uitgifte.uitgiftenr = uitgifteregel.uitgiftenr UNION SELECT datum, 'ontvangst' as "type", aantal as "aantal ontvangen" , CASE WHEN 'test'='test' THEN 0 END as "aantal uitgegeven" FROM ontvangstregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN ontvangst ON ontvangst.ontvangstnr = ontvangstregel.ontvangstnr; Return new; end; When we replace new.artikelnr on line 7 with value 1 it works like it should, but the function needs to work with different artikelnr's. example line 7: JOIN artikel ON artikel.artikelnr = new.artikelnr Please point us in the right direction.

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  • A Map of View instances?

    - by user291701
    Is it possible to keep references to views keyed off of their hashCode? Something like: Map<Integer, View> views; views.put(view1.hashCode(), view1); views.put(view2.hashCode(), view2); views.put(viewN.hashCode(), viewN); I have a few in my view hierarchy and am downloading images for each. I want to be able to iterate over them quickly, or see if I've already previously added one (hence the map).

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  • Asp.net with MVC multiple model in one view (create, update)

    - by Abdalmohaymen
    I have problem in asp.ne Mvc with multiple model in one view on create and update I 'm work on exams system class Questions and class Answers Question is aparent class and Answers is a child class [Bind(exclude("id"))] class Quesions { public string question{get; set;} public Datetime Timepostquestion{get; set;} } [Bind(exclude("id"))] class Answers { public string answer{get; set;} public Datetime Timepostanswer{get; set;} public questionId {get; set;} } in a view I use two classes how to use classes in insert and update what a way which I have to solve my problem

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  • Android refresh StateListDrawable problem

    - by Max
    Hi all, I have a strange problem with StateListDrawable or maybe (probably) I'm missing something. I created a test application for it and the same problem occurs. So, this is my StateListDrawable resourse in file test_selection.xml <?xml version="1.0" encoding="utf-8"?> <selector xmlns:android="http://schemas.android.com/apk/res/android"> <item android:state_selected="true"> <shape android:shape="rectangle" android:background="#ff0000"> <corners android:radius="10dp" /> <gradient android:startColor="#ff5555" android:endColor="#ff5555" android:angle="0" /> </shape> </item> <item android:state_selected="false"> <shape android:shape="rectangle" android:background="#eeeeee"> <corners android:radius="10dp" /> <gradient android:startColor="#eeeeee" android:endColor="#eeeeee" android:angle="0" /> </shape> </item> </selector> It's a very simple selector that draw a red color for selected state and a white rect for the unselected one. My main.xml template is very simple. I simply use a TextView that uses the selection as background. <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="@string/hello" android:textSize="30dp" android:id="@+id/test_view_example" android:background="@drawable/test_selection"/> <Button android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/refresh" android:onClick="updateView" android:text="refresh"></Button> </LinearLayout> My Activity code is also very simple. public class TestDrawableStateActivity extends Activity { private final static int[] SELECTED_STATE = { android.R.attr.state_selected }; private final static int[] UNSELECTED_STATE = {}; private TextView textView; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); textView = (TextView) findViewById(R.id.test_view_example); } @Override protected void onResume() { super.onResume(); // Carichiamo la Drawable if(textView.getBackground().setState(SELECTED_STATE)){ textView.invalidate(); } } public void updateView(View view) { if(textView.getBackground().setState(SELECTED_STATE)){ textView.invalidate(); }; } } When Activity starts I try to set the state of my Drawable (the StateListDrawable) with the value SELECTED. It seems all very simple.... but the problem is that the state is not shown. If, later, I click a button and execute the method updateView() the state changes. Where is my problem? Where am I wrong? Thankx a lot Max

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  • Building a system that allows users to see a video only once

    - by Bart van Heukelom
    My client wants to distribute a video to some people, specifically car dealers, but he doesn't want the video to end up on Youtube or something like that. Therefore he wants the recipients of the video to be able to see it only once. My idea to implement this is: Generate a unique key per viewer Send each viewer a link to a page with a Flash based video player, with their key in the URL Have Flash get the video from the server. On the server the key is checked and the file sent (using php's readfile or something equivalent). Then the key is invalidated. I was thinking this wouldn't take more than a day to build. I know that if you want somebody to be able to play something, you implicitly give them the power to record it as well, but the client just wants me to make it as hard as possible. Do you think this is secure enough for the intended audience? Anything else I can do to add some security without exceeding the development time of 1 day? I'm also interested in ready made solutions, if they exist.

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  • Looking into ASP.Net MVC 4.0 Mobile Development - part 1

    - by nikolaosk
    In this post I will be looking how ASP.Net MVC 4.0 helps us to create web solutions that target mobile devices.We all experience the magic that is the World Wide Web through mobile devices. Millions of people around the world, use tablets and smartphones to view the contents of websites,e-shops and portals.ASP.Net MVC 4.0 includes a new mobile project template and the ability to render a different set of views for different types of devices.There is a new feature that is called browser overriding which allows us to control exactly what a user is going to see from your web application regardless of what type of device he is using.In order to follow along this post you must have Visual Studio 2012 and .Net Framework 4.5 installed in your machine.Download and install VS 2012 using this link.My machine runs on Windows 8 and Visual Studio 2012 works just fine.It will work fine in Windows 7 as well so do not worry if you do not have the latest Microsoft operating system.1) Launch VS 2012 and create a new Web Forms application by going to File - >New Project - > ASP.Net MVC 4 Web Application and then click OKHave a look at the picture below  2) From the available templates select Mobile Application and then click OK.Have a look at the picture below 3) When I run the application I get the mobile view of the page. I would like to show you what a typical ASP.Net MVC 4.0 application looks like. So I will create a new simple ASP.Net MVC 4.0 Web Application. When I run the application I get the normal page view.Have a look at the picture below.On the left is the mobile view and on the right the normal view. As you can see we have more or less the same content in our mobile application (log in,register) compared with the normal ASP.Net MVC 4.0 application but it is optimised for mobile devices. 4) Let me explain how and when the mobile view is selected and finally rendered.There is a feature in MVC 4.0 that is called Display Modes and with this feature the runtime will select a view.If we have 2 views e.g contact.mobile.cshtml and contact.cshtml in our application the Controller at some point will instruct the runtime to select and render a view named contact.The runtime will look at the browser making the request and will determine if it is a mobile browser or a desktop browser. So if there is a request from my IPhone Safari browser for a particular site, if there is a mobile view the MVC 4.0 will select it and render it. If there is not a mobile view, the normal view will be rendered.5) In the  ASP.Net MVC 4.0 (Internet application) I created earlier (not the first project which was a mobile one) I can run it once more and see how it looks on the browser. If I want to view it with a mobile browser I must download one emulator like Opera Mobile.You can download Opera Mobile hereWhen I run the application I get the same view in both the desktop and the mobile browser. That was to be expected. Have a look at the picture below 6) Then I create another version of the _Layout.mobile.cshtml view in the Shared folder.I simply copy and paste the _Layout.cshtml  into the same folder and then rename it to _Layout.mobile.cshtml and then just alter the contents of the _Layout.mobile.cshtml.When I run again the application I get a different view on the desktop browser and a different one on the Opera mobile browser.Have a look at the picture below ?he Controller will instruct the ASP.Net runtime to select and render a view named _Layout.mobile.cshtml when the request will come from a mobile browser.?he runtime knows that a browser is a mobile one through the ASP.Net browser capability provider. Hope it helps!!!

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  • Tab Sweep: Arquillian, Power Mac, PowerPC, JSP Performance, JMX Connection, ...

    - by arungupta
    Recent Tips and News on Java, Java EE 6, GlassFish & more : • Extreme Portability: OpenJDK 7 and GlassFish 3.1.1 on Power Mac G5! (Mark Heckler) • Using GlassFish domain templates to easily create several customized domains (Masoud Kalali) • OpenJDK 7 on Apple G5 PowerPC on Mac OS X 10.5.8 (John Yeary) • ENABLING REMOTE ADMINISTRATION FOR GLASSFISH (Adam Bien) • The Java EE 7 Feature List: Cloud Focused Upgrades (devx) • Improve JavaServer Pages Performance with Caching (distributedcaching) • Interactive Glassfish configuration and application deployment (mpashworth) • Allow JMX connection on JVM 1.6.x (Martin Muller) • Arquillian 1.0.0.Final released! Ready for GlassFish and WebLogic! Death to all bugs! (Markus Eisele) • Using GlassFish and APEXListener as backend for Apache so server APEX (Ronald Rod) • Installing and running Eclipse, Glassfish and Ubuntu 12.04 Precise for Web Applications (Connected Web) • Java EE 6 and modular JAX-RS services (Parijat) • ARQUILLIAN CONFIGURATION FOR EMBEDDED GLASSFISH 3.1.2 AND MAVEN 3 (Adam Bien) • Atmosphere .9 released (JeanFrancois Arcand) • Make JSF your friend again (Daniel Pfeifer)

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  • What causes a WPF ListCollectionView that uses custom sorting to re-sort its items?

    - by Drew Noakes
    Consider this code (type names genericised for the purposes of example): // Bound to ListBox.ItemsSource _items = new ObservableCollection<Item>(); // ...Items are added here ... // Specify custom IComparer for this collection view _itemsView = CollectionViewSource.GetDefaultView(_items) ((ListCollectionView)_itemsView).CustomSort = new ItemComparer(); When I set CustomSort, the collection is sorted as I expect. However I require the data to re-sort itself at runtime in response to the changing of the properties on Item. The Item class derives from INotifyPropertyChanged and I know that the property fires correctly as my data template updates the values on screen, only the sorting logic is not being called. I have also tried raising INotifyPropertyChanged.PropertyChanged passing an empty string, to see if a generic notification would cause the sorting to be initiated. No bananas. EDIT In response to Kent's suggestion I thought I'd point out that sorting the items using this has the same result, namely that the collection sorts once but does not re-sort as the data changes: _itemsView.SortDescriptions.Add( new SortDescription("PropertyName", ListSortDirection.Ascending));

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  • web2py server-side comments

    - by MikeWyatt
    In a web2py view, how do I comment out server-side code? In ASP.NET, I can surround any HTML or code tags with <%-- and --% and that block will not be compiled or sent to the client. Velocity does the same thing with #* and *#. Is there an equivalent in web2py? ASP.NET <div> <p><%=foo.bar%></p> <%-- don't print twice! <p><%=foo.bar%></p> --%> </div> web2py <div> <p><%=foo.bar%></p> ??? don't print twice! <p><%=foo.bar%></p> ??? </div>

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  • Extreme Portability: OpenJDK 7 and GlassFish 3.1.1 on Power Mac G5!

    - by MarkH
    Occasionally you hear someone grumble about platform support for some portion or combination of the Java product "stack". As you're about to see, this really is not as much of a problem as you might think. Our friend John Yeary was able to pull off a pretty slick feat with his vintage Power Mac G5. In his words: Using a build script sent to me by Kurt Miller, build recommendations from Kelly O'Hair, and the great work of the BSD Port team... I created a new build of OpenJDK 7 for my PPC based system using the Zero VM. The results are fantastic. I can run GlassFish 3.1.1 along with all my enterprise applications. I recently had the opportunity to pick up an old G5 for little money and passed on it. What would I do with it? At the time, I didn't think it would be more than a space-consuming novelty. Turns out...I could have had some fun and a useful piece of hardware at the same time. Maybe it's time to go bargain-hunting again. For more information about repurposing classic Apple hardware and learning a few JDK-related tricks in the process, visit John's site for the full article, available here. All the best,Mark

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  • In MVC framworks (such as Ruby on Rails), does usually Model spell as singular and controller and vi

    - by Jian Lin
    I usually see Ruby on Rails books using script/generate model Story name:string link:string which is a singular Story, while when it is controller script/generate controller Stories index then the Story now is Stories, which is plural. Is this a standard on Ruby on Rails? Is it true in other MVC frameworks too, like CakePHP, Symfony, Django, or TurboGears? I see that in the book Rails Space, the controller is also called User, which is the same as the model name, and it is the only exception I see. Update: also, when scaffold is done on Ruby on Rails, then automatically, the model is singular and the controller and view are both plural.

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  • Zend Framework: how to remove rendered views in the controller?

    - by takpar
    i want to render one of these sets of views: head body-$id1 foot OR head body-$id2 foot which set exsists. i do it like this: try { $this->render("head"); $this->render("body-$id1"); $this->render("foot"); } catch (Exception $e) { $this->render("head"); $this->render("body-$id2"); $this->render("foot"); } but it causes the head view be rendered twice if body-$id1 does not exists. do you have a better solution? in another saying, may i check the existance of body-$id1 before rendering it?

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  • General approach for posting business logic status messages to UI?

    - by generalt
    Hello all. I have been struggling with this question for awhile now, and I haven't reached a conclusion. I'm not typically a UI programmer, so forgive the noobishness. I'm writing a typical application with a UI layer (WPF) and a business layer. I want to post status messages to the UI from the business layer (perhaps deep within the business layer), but I don't want the business layer to have any knowledge of the UI. Is there a generally accepted pattern for this? I was thinking to have a message queue of some sort to which the business layer posts status messages, and have the view model of the UI subscribe to that queue and intercept messages from the queue and route them to the UI. Is that a good approach? Is there somewhere else I should start? Thank you.

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  • producing a typewriter-like effect

    - by Tony Ennis
    Android newb here. Please use small words :-) I'd like to simulate typewriter output on my Android. The output being displayed is generated by a game and is somewhat freeform. The effect I want to see individual characters appear at a rate of about 6 characters a second. When a 'carriage return' is seen, I'd like to insert a delay then resume typing on the left. What are some suggestions on views? Would the view of choice for this be a TextView? Even that seems like overkill for this read-only coarsely scrolling output. I saw something on this thread about an AsyncTask. That looks useful. Perhaps my game will write to some manner of buffer, and a subclass of AsyncTask will pull characters out every .15 seconds or so, add them to the TextView, then invalidate() the TextView? Sound like a plan?

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  • Rails: textfield list to array of strings

    - by poseid
    I want to take input from a textfield and turn it into an array of strings. After having submitted the "post", I want to display again the textfield, but with the array showed below. I have a view that would look like: <% form_tag "/list2array" do -%> <%= text_area_tag "mylist" %> <div><%= submit_tag 'save' %></div> <% end -%> <% @myArray.each do |item| %> <%= item %> <% end %> And as a start for the controller: class List2ArrayController < ApplicationController def index end def save @myArray = params[:mylist].split("\r\n") end end However, after the post, I only get an empty textfield without values in the array from the previous POST. Do I need to use the model layer for my experiment? How? Or do I need to modify my controller?

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  • HTML5 - Does it have the power to handle a large 2D game with a huge world?

    - by user15858
    I have been using XNA game studio, but due to private reasons (as well as the ability to publish anywhere & my heavy interest in isogenic engine), I would like to switch to HTML5. However, I have very high 2D graphic demands for my game. The game itself will have a HDD size of anywhere between 6GB (min) to 12GB (max) which would be a full game deployed offline. The size of the images aren't significantly large, so streaming would be entirely possible if only those assets required were streamed as needed. The game has a massive file size because of the sheer amount of content. For some images or spritesheets, they would be quite massive. (ex. a very large Dragon, which if animated in a spritesheet would be split into two 4096x4096 sheets or one 8192x8192 sheet). Most assets would be very small, and about 7MB for a full character with 15 animations in every direction (all animations not required immediately) so in the size of a few hundred KB to download before the game loads. My question, however, is if the graphical power of HTML5 is enough to animate several characters on screen at once, when it flips through frames quite rapidly. All my sprites have about 25 frames per animation, 5 directions (a spritesheet for each direction & animation), and run at 30fps. Upon changing direction, animation, or a new character entering, spritesheets would change and be constantly loading/unloading. If I pack all directions in a single sheet, it would be about 2048x2048 per sheet. Most frameworks have no problem with this, but I am afraid from what I read that HTML5's graphical capabilities will limit me. Since it takes significant time simply to animate characters in any language, I'd like a quick answer.

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  • Client Id for Property (ASP.Net MVC)

    - by Felipe
    Hi guys... I'm begginer in asp.net mvc, and i have a doubs: I'm trying to do a label for a TextBox in my View and I'd like to know, how can I take a Id that will be render in client to generete scripts... for example: <label for="<%=x.Name.?ClientId?%>"> Name: </label> <%=Html.TextBoxFor(x=>x.Name) %> What need I put in "?ClientId?" to make sure that correct Id will be render to the corresponding control ? Thanks Cheers

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  • Maxtor 500GB external hard drive not being detected but power is going to it?

    - by ClarkeyBoy
    I have 2 * Maxtor Onetouch 4 Lite 500GB external hard drives (part no. 9NT2A4-500). They both used to work fine on my old laptop (an Acer) but I have not used them for about a year, since my laptop was stolen and I got this one (also an Acer [Aspire 7738G]). I have one plugged into the mains with one of the leads I believe was supplied with them. It appears to be receiving power as it is warm and the power light (on the unit itself) is on; also the mains adapter is fairly warm. I also have it plugged into my laptop with a USB lead which I have tested on my mp3 player (so I know it works). However my hard drive is not showing on my computer. I have tried checking for new hardware, installing the software that was supplied with it, checking drive letters in case it is registered as C: or something stupid, checking for problems etc... I can't find any cause for it to do this. It does appear to be starting up and, possibly, shutting down and restarting constantly (that's what it sounds like altho I can't be certain). I have had both hard drives stored in different places for the last year and they're both doing the same thing.. if it was only one then I'd guess it had got damaged or corrupted or something but since it is both I doubt this is it. The only things in common with both of them are the leads and the laptop, however I know the USB lead works and guess the mains lead works as there is power going to the unit. Has anyone come across this before or does anyone have any idea what the cause / solution to the problem is? Any help would be greatly appreciated. Regards, Richard

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  • MVC 3 ModelView passing parameters between view & controller

    - by Tobias Vandenbempt
    I've been playing with MVC 3 in a test project and have the following issue. I have Group & Subscriber entities and those are coupled through a SubscriberGroup table. Using the DetailView of Group I open a view of SubscriberGroup containing all subscribers. This list has the option to filter. So far it all works, however when I call the AddToGroup method on the controller it fails. Specifically it goes into the method but doesn't pass the subscriberCheckedModels list. Am I doing something wrong? View: SubscriberGroup Index.aspx <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.master" Inherits="System.Web.Mvc.ViewPage<Mail.Models.SubscriberCheckedListViewModel>" %> … <h2 class="common-box-title"> Add Subscribers to Group</h2> <p> <% using (Html.BeginForm("Index", "SubscriberGroup")) { %> <input name="filter" id="filter" type="text" /> <input type="submit" value="Search" /> <%} %> </p> <% using (Html.BeginForm("AddToGroup", "SubscriberGroup", Model,FormMethod.Get, null)) { %> <fieldset> <div style="display: inline-block; width: 70%; vertical-align: top;"> <% if (Model.subscribers.Count() != 0) { %> <table class="hor-minimalist-b"> <tr> <th> Add To Group </th> <th> Full Name </th> <th> Email </th> <th> Customer </th> </tr> <% foreach (var item in Model.subscribers) { %> <tr> <td> <%= Html.CheckBoxFor(modelItem => item.AddToGroup)%> </td> <td> <%= Html.DisplayFor(modelItem => item.subscriber.LastName)%> <%= Html.ActionLink(item.subscriber.FirstName + " " + item.subscriber.LastName, "Details", new { id = item.subscriber.SubscriberID })%> </td> <td> <%: Html.DisplayFor(modelItem => item.subscriber.Email)%> </td> <td> <%: Html.DisplayFor(modelItem => item.subscriber.Customer.Company)%> <%= Html.HiddenFor(modelItem => item.subscriber) %> </td> </tr> <% } %> <% ViewBag.subscribers = Model.subscribers; %> probeersel <%= Html.HiddenFor(model => model.subscribers) %> probeersel </table> <%} %> <%else { %> <p> No subscribers found.</p> <%} %> <input type="submit" value="Add Subscribers" /> </div> </fieldset> <%} %> Controller: SubscriberGroupController using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Mvc; using System.Web.Security; using Mail.Models; namespace Mail.Controllers { public class SubscriberGroupController : Controller { private int groupID; private MailDBEntities db = new MailDBEntities(); // // GET: /SubscriberGroup/ public ActionResult Index(int id) { groupID = id; MembershipUser myObject = Membership.GetUser(); Guid UserID = Guid.Parse(myObject.ProviderUserKey.ToString()); UserCustomer usercustomer = db.UserCustomers.Single(s => s.UserID == UserID); var subscribers = from subscriber in db.Subscribers where (subscriber.CustomerID == usercustomer.CustomerID) | (subscriber.CustomerID == 0) select new SubscriberCheckedModel { subscriber = subscriber, AddToGroup = false }; SubscriberCheckedListViewModel test = new SubscriberCheckedListViewModel(); test.subscribers = subscribers; return View(test); } [HttpPost] public ActionResult Index(string filter) { MembershipUser myObject = Membership.GetUser(); Guid UserID = Guid.Parse(myObject.ProviderUserKey.ToString()); UserCustomer usercustomer = db.UserCustomers.Single(s => s.UserID == UserID); var subscribers2 = from subscriber in db.Subscribers where ((subscriber.FirstName.Contains(filter)|| subscriber.LastName.Contains(filter)) && (subscriber.CustomerID == usercustomer.CustomerID || subscriber.CustomerID == 0)) select new SubscriberCheckedModel { subscriber = subscriber, AddToGroup = false }; SubscriberCheckedListViewModel test = new SubscriberCheckedListViewModel(); test.subscribers = subscribers2.ToList(); return View(test); } [HttpPost] public ActionResult AddToGroup(SubscriberCheckedListViewModel test) { //test is null return RedirectToAction("Details", "Group", new { id = groupID }); } } } ViewModel: SubscriberGroupModel using System.Collections.Generic; using Mail; namespace Mail.Models { public class SubscriberCheckedModel { public Subscriber subscriber { get; set; } public bool AddToGroup { get; set; } } public class SubscriberCheckedListViewModel { public IEnumerable<SubscriberCheckedModel> subscribers { get; set; } } }

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