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  • Is this a correct json format....

    - by chandru_cp
    I want to get a fair idea about json format... I am using php in which i have converted my result array to json like this $result = mysql_query("select dStud_id,dMarkObtained1,dMarkObtained2, dMarkObtained3,dMarkTotal from tbl_internalmarkallot"); $JsonVar = json_encode($res); echo "<input type='text' name='json' id='json' value ='$JsonVar'>"; And the text box shows {"0":"101","dStud_id":"101","1":"60","dMarkObtained1":"60","2":"80", "dMarkObtained2":"80","3":"80","dMarkObtained3":"80","4":"220","dMarkTotal":"220"} Is this a correct json format....

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  • Extract a portion of a Qt .ui file into its own .ui file

    - by Grant Limberg
    We have a designer creating a user interface for an application. The main window has several QStackedWidgets used for in place panel switching. What I'd like to be able to do is extract each individual panel that makes up each page of the QStackedWidget into it its own .ui file. Is there an easy way to accomplish this from within Qt Designer, or are there any other tools to help accomplish this task short of redesigning all of the panels in their own .ui files?

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  • C# DateTime.ParseExact throwing format exception

    - by Rob
    I'm developing an .NET4 webapplication using MVC3. Let's say i'm getting the following DateTime as string from an XML-feed. The xml feed is being read by my application and i'm looping through all it's descendants. The DateTime i'm receiving is begin returned in the following format (as string); var myDateTime = "Sun Dec 19 11:45:45 +0000 2010" I'm using the piece of code below to try and parse the DateTime string i mentioned above to a valid DateTime format (preferably dutch) var CorrectDateTime = DateTime.ParseExact(myDateTime , "dd MMM yyyy HH:mm:ss", CultureInfo.InvariantCulture); When trying to execute this code i'm facing an formatexception. Somebody has got any ideas?

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  • Writing Strings to files in python

    - by Leif Andersen
    I'm getting the following error when trying to write a string to a file in pythion: Traceback (most recent call last): File "export_off.py", line 264, in execute save_off(self.properties.path, context) File "export_off.py", line 244, in save_off primary.write(file) File "export_off.py", line 181, in write variable.write(file) File "export_off.py", line 118, in write file.write(self.value) TypeError: must be bytes or buffer, not str I basically have a string class, which contains a string: class _off_str(object): __slots__ = 'value' def __init__(self, val=""): self.value=val def get_size(self): return SZ_SHORT def write(self,file): file.write(self.value) def __str__(self): return str(self.value) Furthermore, I'm calling that class like this: def write(self, file): for variable in self.variables: variable.write(file) I have no idea what is going on. I've seen other python programs writing strings to files, so why can't this one? Thank you very much for your help.

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  • Rails rabl json format

    - by brabertaser1992
    I'm displaying data from my db in json format using rabl to parse it for android... My json looks like so: [ { "bank":{ "central_office_address":"ololo", "license":"12312312", "location_id":3, "name":"Pbank", "tax_number":"12312312", "year_of_foundation":1987 } }, { "bank":{ "central_office_address":"sdfsdf sdf", "license":"321312", "location_id":3, "name":"Bbank", "tax_number":"321321", "year_of_foundation":1999 } } ] I need my json in a format like: { "contacts": [ { "id": "c200", "name": "Ravi Tamada", "email": "[email protected]", "address": "xx-xx-xxxx,x - street, x - country", "gender" : "male", "phone": { "mobile": "+91 0000000000", "home": "00 000000", "office": "00 000000" } }, { "id": "c201", "name": "Johnny Depp", "email": "[email protected]", "address": "xx-xx-xxxx,x - street, x - country", "gender" : "male", "phone": { "mobile": "+91 0000000000", "home": "00 000000", "office": "00 000000" } } ] } Such data is normally parsed in java.... My rabl view: object @banks attributes :central_office_address, :license, :location_id, :name, :tax_number, :year_of_foundation How do I change its output to match the second example?

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  • f# string.Format

    - by mamu
    I am writing my first f# library i am trying to use string.Format and it complains that no such function Is it not available or am i doing something wrong

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  • Description format for an embedded structure

    - by praetorian20
    Hi, I have a C structure that allow users to configure options in an embedded system. Currently the GUI we use for this is custom written for every different version of this configuration structure. What I'd like for is to be able to describe the structure members in some format that can be read by the client configuration application, making it universal across all of our systems. I've experimented with describing the structure in XML and having the client read the file; this works in most cases except those where some of the fields have inter-dependencies. So the format that I use needs to have a way to specify these; for instance, member A must always be less than or equal to half of member B. Thanks in advance for your thoughts and suggestions.

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  • C# Timer counter in xx.xx.xx format

    - by Darkshadw
    I have a counter that counts up every 1 second and add 1 to an int. Question How can I format my string so the counter would look like this: 00:01:23 Instead of: 123 Things I've tried Things I've tried so far: for (int i = 0; i < 1; i++) { _Counter += 1; labelUpTime.Text = _Counter.ToString(); } My timer's interval is set to: 1000 (so it adds 1 every second). I did read something about string.Format(""), but I don't know if it is applicable. Thanks if you can guide me through this :D!

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  • String.Format with NumberGroupSeparator outputting 0xa0 not comma

    - by andrevdm
    I'm seeing strange results when doing a string.Format( "C" ); E.g. double val = 123456.78; Console.WriteLine( val.ToString( "C" ) ); This prints the thousand separator as 0xa0 rather than a comma (0x2c). I get the same result if I use string.Format( "{0:0,0.00}", 1234567.12D ); Here is the full output R 123ÿ456,78 52333A333233 201230456C78 My regional settings are English (South African) and I'm getting the same result on multiple machines. Any ideas? Thanks.

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  • dropdownlist format and then convert

    - by dinra
    i need a dropdownlist to show current month and year (January 2010) till January 2011, and an additional record of January 2011 +. But I want to save this in the database as 01/01/2010 format. also if the user selects current month then the record should be getdate() to go in database, else for any other month it should be 02/01/2010 (date = 01, first day of month). how do i do this in aspx.vb .net. i wrote a function to populate the dorpdownlist - Public Sub Load_dates(ByRef DDL As System.Web.UI.WebControls.DropDownList) Try Dim i As Integer Dim j As Integer For i = Now.Year To Now.Year For j = Now.Month To Now.Month + 11 DDL.Items.Add((j.ToString) + " " + (i.ToString)) Next Next Catch ex As Exception ReportError(ex) End Try End Sub this function only shows number like 01 2010 and 02 2010. how can i format this to show january 2010 and february 2010 and so on. please advice

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  • PHP strtotime() setting date to default

    - by Paddyd
    I have a script which is reading values from an excel sheet and inserting them into an sql table. My problem is when the script reads in some of the date fields it is setting them to a default value : 1970-01-01 01:00:00 I have noticed that this is happening when it comes across a date where the 'day' is greater than 12 : 13/05/2012 18:52:33 (dd-mm-yyyy hh-mm-ss) I thought this may be due to the script thinking that this is the month field (i.e american format) and it sees it as an invalid value, so I set the default timezone to my own hoping it may resolve the problem but it made no difference. date_default_timezone_set('Europe/Dublin'); Here is an example of what my code is doing: Excel field value : 01/05/2012 18:32:45 Script: $start_time = $data->val($x,5); echo $start_time = date("Y-m-d H:i:s", strtotime($start_time)); Output: 2012-01-05 18:32:45 This is the exact format I am looking for (except for the fact that the day and month fields are switched around i.e american date format) but it doesnt work for the type of dates I mentioned above.

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  • How to write a list to a text file in the correct format

    - by lia1000
    I've got this piece of code that I want to write the output to a text file but with the correct format i.e. no brackets, single quotes so it appears as a formatted list. This is the code: file = open("env5.txt", "w"); for key in os.environ.keys(): env = os.environ[key]; key1 = key; list = str([key, env]).replace("'","").replace('[]', ''); list2 = list[1:-1]; print(list2); file.writelines(list2); file.close(); This is the original code: for key in os.environ.keys(): print(key, os.environ[key]); Many thanks

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  • Error when selecting content from ADDTIME(CURTIME(), '14400 hour') format

    - by Blahwhore
    So apparently i've stumbled upon a coding error when trying to select the time from my database. SELECT * FROM `videos` WHERE `added_time` > AddTime( CurTime(), '14400 hour' ) is the code, i'm trying to select all the videos posted 10 days (14400 hours) ago using the "added_time" format, because it worked for my previous coding but in this one it work work. Shown below is a link to the image showing how my database structure for videos are shown. http://i.imm.io/NURT.png Edit: Previously i had this problem for retrieving and deleting bulletins posted 10 days ago, and this code worked, however this code apparently won't work when trying to retrieve the videos :/ I don't know why, they're using the same format. See: http://i.imm.io/NUSW.png

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  • printf("... %c ...",'\0') and family - what will happen?

    - by SF.
    How will various functions that take printf format string behave upon encountering the %c format given value of \0/NULL? How should they behave? Is it safe? Is it defined? Is it compiler-specific? e.g. sprintf() - will it crop the result string at the NULL? What length will it return? Will printf() output the whole format string or just up to the new NULL? Will va_args + vsprintf/vprintf be affected somehow? If so, how? Do I risk memory leaks or other problems if I e.g. shoot this NULL at a point in std::string.c_str()? What are the best ways to avoid this caveat (sanitize input?)

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  • SSIS Technique to Remove/Skip Trailer and/or Bad Data Row in a Flat File

    - by Compudicted
    I noticed that the question on how to skip or bypass a trailer record or a badly formatted/empty row in a SSIS package keeps coming back on the MSDN SSIS Forum. I tried to figure out the reason why and after an extensive search inside the forum and outside it on the entire Web (using several search engines) I indeed found that it seems even thought there is a number of posts and articles on the topic none of them are employing the simplest and the most efficient technique. When I say efficient I mean the shortest time to solution for the fellow developers. OK, enough talk. Let’s face the problem: Typically a flat file (e.g. a comma delimited/CSV) needs to be processed (loaded into a database in most cases really). Oftentimes, such an input file is produced by some sort of an out of control, 3-rd party solution and would come in with some garbage characters and/or even malformed/miss-formatted rows. One such example could be this imaginary file: As you can see several rows have no data and there is an occasional garbage character (1, in this example on row #7). Our task is to produce a clean file that will only capture the meaningful data rows. As an aside, our output/target may be a database table, but for the purpose of this exercise we will simply re-format the source. Let’s outline our course of action to start off: Will use SSIS 2005 to create a DFT; The DFT will use a Flat File Source to our input [bad] flat file; We will use a Conditional Split to process the bad input file; and finally Dump the resulting data to a new [clean] file. Well, only four steps, let’s see if it is too much of work. 1: Start the BIDS and add a DFT to the Control Flow designer (I named it Process Dirty File DFT): 2, and 3: I had added the data viewer to just see what I am getting, alas, surprisingly the data issues were not seen it:   What really is the key in the approach it is to properly set the Conditional Split Transformation. Visually it is: and specifically its SSIS Expression LEN([After CS Column 0]) > 1 The point is to employ the right Boolean expression (yes, the Conditional Split accepts only Boolean conditions). For the sake of this post I re-named the Output Name “No Empty Rows”, but by default it will be named Case 1 (remember to drag your first column into the expression area)! You can close your Conditional Split now. The next part will be crucial – consuming the output of our Conditional Split. Last step - #4: Add a Flat File Destination or any other one you need. Click on the Conditional Split and choose the green arrow to drop onto the target. When you do so make sure you choose the No Empty Rows output and NOT the Conditional Split Default Output. Make the necessary mappings. At this point your package must look like: As the last step will run our package to examine the produced output file. F5: and… it looks great!

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  • sort surname in alphabet from file to file JAVA

    - by user577939
    hello all. I need some help. I have wrote this code and dont now how to sort surnames in alphabet from my file to other file. import java.io.; import java.util.; class Asmuo { String pavarde; String vardas; long buvLaikas; int atv1; int atv2; int atv3; } class Irasas { Asmuo duom; Irasas kitas; } class Sarasas { private Irasas p; Sarasas() { p = null; } Irasas itrauktiElementa(String pv, String v, long laikas, int d0, int d1, int d2) { String pvrd, vrd; int data0; int data1; int data2; long lks; lks = laikas; pvrd = pv; vrd = v; data0 = d0; data1 = d1; data2 = d2; Irasas r = new Irasas(); r.duom = new Asmuo(); uzpildymasDuomenimis(r, pvrd, vrd, lks, d0, d1, d2); r.kitas = p; p = r; return r; } void uzpildymasDuomenimis(Irasas r, String pv, String v, long laik, int d0, int d1, int d2) { r.duom.pavarde = pv; r.duom.vardas = v; r.duom.atv1 = d0; r.duom.buvLaikas = laik; r.duom.atv2 = d1; r.duom.atv3 = d2; } void spausdinti() { Irasas d = p; int i = 0; try { FileWriter fstream = new FileWriter("rez.txt"); BufferedWriter rez = new BufferedWriter(fstream); while (d != null) { System.out.println(d.duom.pavarde + " " + d.duom.vardas + " " + d.duom.buvLaikas + " " + d.duom.atv1 + " " + d.duom.atv2 + " " + d.duom.atv3); rez.write(d.duom.pavarde + " " + d.duom.vardas + " " + d.duom.buvLaikas + " " + d.duom.atv1 + " " + d.duom.atv2 + " " + d.duom.atv3 + "\n"); d = d.kitas; i++; } rez.close(); } catch (Exception e) { System.err.println("Error: " + e.getMessage()); } } } public class Gyventojai { public static void main(String args[]) { Sarasas sar = new Sarasas(); Calendar atv = Calendar.getInstance(); Calendar isv = Calendar.getInstance(); try { FileInputStream fstream = new FileInputStream("duom.txt"); DataInputStream in = new DataInputStream(fstream); BufferedReader br = new BufferedReader(new InputStreamReader(in)); String eil; while ((eil = br.readLine()) != null) { String[] cells = eil.split(" "); String pvrd = cells[0]; String vrd = cells[1]; atv.set(Integer.parseInt(cells[2]), Integer.parseInt(cells[3]), Integer.parseInt(cells[4])); isv.set(Integer.parseInt(cells[5]), Integer.parseInt(cells[6]), Integer.parseInt(cells[7])); long laik = (isv.getTimeInMillis() - atv.getTimeInMillis()) / (24 * 60 * 60 * 1000); int d0 = Integer.parseInt(cells[2]); int d1 = Integer.parseInt(cells[3]); int d2 = Integer.parseInt(cells[4]); sar.itrauktiElementa(pvrd, vrd, laik, d0, d1, d2); } in.close(); } catch (Exception e) { System.err.println("Error: " + e.getMessage()); } sar.spausdinti(); } }

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  • File Segmentation when trying to write in a file

    - by user1286390
    I am trying in C language to use the method of bisection to find the roots of some equation, however when I try to write every step of this process in a file I get the problem "Segmentation fault". This might be an idiot fault that I did, however I have been trying to solve this for a long time. I am compiling using gcc and that is the code: #include <stdio.h> #include <stdlib.h> #include <math.h> #define R 1.0 #define h 1.0 double function(double a); void attractor(double *a1, double *a2, double *epsilon); void attractor(double *a1, double *a2, double *epsilon) { FILE* bisection; double a2_copia, a3, fa1, fa2; bisection = fopen("bisection-part1.txt", "w"); fa1 = function(*a1); fa2 = function(*a2); if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); fprintf(bisection, "a1 a2 fa1 fa2 epsilon\n"); a2_copia = 0.0; if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { a3 = *a2 - (*a2 - *a1); a2_copia = *a2; *a2 = a3; if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", *a1, *a2, function(*a1), function(*a1), *epsilon); attractor(a1, a2, epsilon); } else { *a2 = a2_copia; *a1 = a3; if(function(*a1) - function(*a2) > 0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", *a1, *a2, function(*a1), function(*a1), *epsilon); attractor(a1, a2, epsilon); } } } fa1 = function(*a1); fa2 = function(*a2); if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", a1, a2, fa1, fa2, epsilon); } double function(double a) { double fa; fa = (a * cosh(h / (2 * a))) - R; return fa; } int main() { double a1, a2, fa1, fa2, epsilon; a1 = 0.1; a2 = 0.5; fa1 = function(a1); fa2 = function(a2); if(fa1 - fa2 > 0.0) epsilon = fa1 - fa2; else epsilon = fa2 - fa1; if(epsilon >= 0.00001) { fa1 = function(a1); fa2 = function(a2); attractor(&a1, &a2, &epsilon); fa1 = function(a1); fa2 = function(a2); if(fa1 - fa2 > 0.0) epsilon = fa1 - fa2; else epsilon = fa2 - fa1; } if(epsilon < 0.0001) printf("Vanish at %f", a2); else printf("ERROR"); return 0; } Thanks anyway and sorry if this question is not suitable.

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  • Fixing corrupt files or corrupt file table on a USB drive?

    - by Kelsey
    I was doing a virus scan on an external USB drive while copying data over to it. While AVG was scanning my system got locked up I think due to the USB drive running out of space and it required a reboot. Since that time all data on the external drive is no longer accessible. I can see all the files in the root and directories but I cannot browse into any of them as Windows 7 gives an error stating they are corrupt. I think the file table or whatever it uses to store the index of what exists on the drive has been corrupted since it still shows the the drive as being almost full but everything I do a properties check on says it is 0 bytes. Does anyone know how to 'unlock' or recover this data? Is there a way to rebuild the file table somehow? Luckily I can recover this data from other sources as a last resort but I would like to fix this if possible. Any help would be appreciated. Thanks.

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  • Why Does DreamWeaver CS5 Discriminate between File Extensions, Even After Modding Mime Types!?

    - by Sam
    Hi folks, Even After I forced DreamWeaver CS5 to allow opening of .ast extensions as a MIME type of php5, which DreamWeaver now opens and colors correctly as described here, I still have trouble figuring out why it still discriminates between the two file extensions! Symptoms: External Files & Design View I have a file foo.php which php includes other files (e.g. the php-combined css.php and js.php). Now, when opening foo.php all functions work perfectly: the external (included) php files are all recognised correctly. However, when I change foo.php foo.ast, and open it again, It does not recognise the files extensions anymore in the top bar. Also, I lose the Design / Live View functionality.** When I change foo.ast to foo.php, all works again! Anyone any clues of why there remains a a difference between one and other extension? Note1: I have added the .ast extension to these four files, next to .php: 1 C:\Users\Sam\AppData\Local\VirtualStore\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\DocumentTypes\MMDocumentTypes.xml 2 C:\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\DocumentTypes\MMDocumentTypes.xml 3 C:\Users\Sam\AppData\Roaming\Adobe\Dreamweaver CS5\en_US\Configuration\Extensions.txt 4 C:\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\Extensions.txt Note2: sometimes, even .php files do not want to show in design view or live view. Could this be caused by a corrupted installation?

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  • Is there a POSIX pathname that can't name a file?

    - by Charles Stewart
    Are there any legal paths in POSIX that cannot be associated with a file, regular or irregular? That is, for which test -e "$LEGITIMATEPOSIXPATHNAME" cannot succeed? Clarification #1: pathnames By "legal paths in POSIX", I mean ones that POSIX says are allowed, not ones that POSIX doesn't explicitly forbid. I've looked this up, and the are POSIX specification calls them character strings that: Use only characters from the portable filename character set [a-zA-Z0-9._-] (cf. http://www.opengroup.org/onlinepubs/009695399/basedefs/xbd_chap03.html#tag_03_276); Do not begin with -; and Have length between 1 and NAME_MAX, a number unspecified for POSIX that is not less than 14. POSIX also allows that filesystems will probably be more relaxed than this, but it forbids the characters NUL and / from appearing in filenames. Note that such a paradigmatically UNIX filename as lost+found isn't FPF, according to this def. There's another constant PATH_MAX, whose use needs no further explanation. The ideal answer will use FPFs, but I'm interested in any example with filenames that POSIX doesn't expressly forbid. Clarification #2: impossibility Obviously, pathnames normally could be bound to a file. But UNIX semantics will tell you that there are special places that couldn't normally have arbitrary files created, like in the /dev directory. Are any such special places stipulated in POSIX? That is what the question is getting after.

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  • Everyone can access my Windows 7 Homegroup file shares - Even Windows XP computers.

    - by adriangrigore
    Hi, I have 3 computers in my network, two running Windows 7 and one running Windows XP. I've set up a homegroup on both Windows 7 computers. Also, all computers are in the same Workgroup. The problem is that one of the Windows 7 computers makes all shares accessible to the entire Workgroup instead of just sharing to the Homegroup as it should be. I created the file share in Windows 7 via right-click in the explorer, then click on "Share For" - "Homegroup (Read/Write)" (translated from German, so the actual wording may be different). Also, when I look at the file sharing properties of that folder, Windows Explorer informs me that Users must have a valid account and password for this Computer to access drive shares. Unfortunately this is not true. Being in the same Workgroup is enough to get access. Homegroup restrictions work as expected on my other Windows 7 computer. When trying to browse those shares from the XP computer, I get a dialog asking for a login and password. What might cause homegroup restrictions to fail and how can I fix this?

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