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  • How to get a nicely formatted PHP Web Service response?

    - by Bruno
    I called an API like this: $service = new Class_Service(); $parameters = new GetClasses(); $parameters->Request = new GetClassesRequest(); $parameters->Request->SourceCredentials = new SourceCredentials(); $parameters->Request->SourceCredentials->SourceName = "Name"; $parameters->Request->SourceCredentials->Password = "Pass"; $parameters->Request->SourceCredentials->SiteIDs = array( 12 ); $classes = $service->GetClasses($parameters); var_dump($classes); And received a response like this: object(GetClassesResponse)#7 (1) { ["GetClassesResult"]=> object(GetClassesResult)#8 (6 { ["Classes"]=> object(stdClass)#9 (1) { ["Class"]=> array(25) { [0]=> object(Mi_Class)#10 (21) { ["ClassScheduleID"]=> int(15) ["Visits"]=> NULL ["Clients"]=> NULL ["Location"]=> object(Location)#11 (30) { ["BusinessID"]=> NULL ["SiteID"]=> int(12) ["BusinessDescription"]=> NULL ["AdditionalImageURLs"]=> object(stdClass)#12 (0) { } ["FacilitySquareFeet"]=> NULL Does a response normally look like this? How do I go about getting the data in a formatted manner?

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  • help configuring a mail server for use with mail.jar and activation.jar

    - by bobbyblue
    im trying to work with the below code: import javax.servlet.*; import javax.servlet.http.*; import java.io.*; import javax.mail.*; import javax.mail.internet.*; // important import javax.mail.event.*; // important import java.net.*; import java.util.*; public class servletmail extends HttpServlet { public void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException, IOException { PrintWriter out=response.getWriter(); response.setContentType("text/html"); try { Properties props=new Properties(); props.put("mail.smtp.host","localhost"); // 'localhost' for testing Session session1 = Session.getDefaultInstance(props,null); String s1 = request.getParameter("text1"); //sender (from) String s2 = request.getParameter("text2"); String s3 = request.getParameter("text3"); String s4 = request.getParameter("area1"); Message message =new MimeMessage(session1); message.setFrom(new InternetAddress(s1)); message.setRecipients (Message.RecipientType.TO,InternetAddress.parse(s2,false)); message.setSubject(s3); message.setText(s4); Transport.send(message); out.println("mail has been sent"); } catch(Exception ex) { System.out.println("ERROR....."+ex); } } } im using mail.jar and activation.jar but i cant understand how shouls i configure it with a mail server which mail server should i use will i be able to send an email using above what are the requirements a mail server? how should i configure it

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  • Spring Controller redirect to another page

    - by user1386375
    Hey I got the following problem. This is the content of the jspx file: function postSMTH() { $.ajax({ type: "POST", url: document.getElementById("urltxt").value, data: parameters, }); } <input type="hidden" value="${pageContext.request.contextPath}/foo/foo2/foodat" name="urltxt" id="urltxt"/> <div class="foodat"><a href="javascript:postSMTH();"><spring:message code="foo_foo2_foodat_text" text="FOODAT"/></a></div> So if I push the submit button, the postSMTH function is called and the ajax object is paste to the Controller which look like this: @Controller @RequestMapping(value="/foo") public class FooController { .............. @RequestMapping(value="/foo2", method=RequestMethod.POST) public String homePOST(HttpServletRequest request) { ........ } @RequestMapping(value="/foo2", method=RequestMethod.GET) public String homeGET(HttpServletRequest request) { ........ } @RequestMapping(value="/foo2/foodat", method=RequestMethod.POST) public String doTHAT(HttpServletRequest request) { // check authorization Map fooMap = request.getParameterMap(); // do something in the Database, depending on the paramMap return "redirect:/foo/foo1"; } } Everything is working fine regarding the Database, but the Problem is, that the redirect at the end DOESN'T work. It just stays at the page foo2. I'm new to Spring, maybe its a little mistake somewhere. I just cant make it out by myself. Would be nice if someone would have some hint. Thanks

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  • Adding fields to Django form dynamically (and cleanly)

    - by scott
    Hey guys, I know this question has been brought up numerous times, but I'm not quite getting the full implementation. As you can see below, I've got a form that I can dynamically tell how many rows to create. How can I create an "Add Row" link that tells the view how many rows to create? I would really like to do it without augmenting the url... # views.py def myView(request): if request.method == "POST": form = MyForm(request.POST, num_rows=1) if form.is_valid(): return render_to_response('myform_result.html', context_instance=RequestContext(request)) else: form = MyForm(num_rows=1) return render_to_response('myform.html', {'form':form}, context_instance=RequestContext(request)) # forms.py class MyForm(forms.Form): def __init__(self, *args, **kwargs): num_rows = kwargs.pop('num_rows',1) super(MyForm, self).__init__(*args, **kwargs) for row in range(0, num_rows): field = forms.CharField(label="Row") self.fields[str(row)] = field # myform.html http://example.com/myform <form action="." method="POST" accept-charset="utf-8"> <ul> {% for field in form %} <li style="margin-top:.25em"> <span class="normal">{{ field.label }}</span> {{ field }} <span class="formError">{{ field.errors }}</span> </li> {% endfor %} </ul> <input type="submit" value="Save"> </form> <a href="ADD_ANOTHER_ROW?">+ Add Row</a>

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  • Mapping restful ajax requests to spring

    - by Diones
    I have this piece of code: @RequestMapping(value = "/test.json", method = RequestMethod.GET) @ResponseStatus(HttpStatus.OK) public @ResponseBody Object[] generateFile(@RequestParam String tipo) { Object[] variaveis = Variavel.getListVariavelByTipo(tipo); return variaveis; } As far as I know it should take a request to test.json?tipo=H and return the JSON representation of Variavel[], however when I make such request I get: HTTP Status 406 - type Status report message descriptionThe resource identified by this request is only capable of generating responses with characteristics not acceptable according to the request "accept" headers () By using the following function I can get the expected json: @RequestMapping(value = "/teste.json") public void testeJson(Model model, @RequestParam String tipo) { model.addAttribute("data", Variavel.getListVariavelByTipo("H")); } What I'm doing wrong?

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  • Get Url Parameters In Django

    - by picomon
    I want to get current transaction id in url. it should be like this www.example.com/final_result/53432e1dd34b3 . I wrote the below codes, but after successful payment, I'm redirected to Page 404. (www.example.com/final_result//) Views.py @csrf_exempt def pay_notif(request, v_transaction_id): if request.method=='POST': v_transaction_id=request.POST.get('transaction_id') endpoint='https://testpay.com/?v_transaction_id={0}&type=json' req=endpoint.format(v_transaction_id) last_result=urlopen(req).read() if 'Approved' in last_result: session=Pay.objects.filter(session=request.session.session_key).latest('id') else: return HttpResponse(status=204) return render_to_response('final.html',{'session':session},context_instance=RequestContext(request)) Urls.py url(r'^final_result/(?P<v_transaction_id>[-A-Za-z0-9_]+)/$', 'digiapp.views.pay_notif', name="pay_notif"), Template: <input type='hidden' name='v_merchant_id' value='{{newpayy.v_merchant_id}}' /> <input type='hidden' name='item_1' value='{{ newpayy.esell.up_name }}' /> <input type='hidden' name='description_1' value='{{ newpayy.esell.up_description }}' /> <input type='hidden' name='price_1' value='{{ newpayy.esell.up_price }}' /> #page to be redirected to after successful payment <input type='hidden' name='success_url' value='http://127.0.0.1:8000/final_result/{{newpayy.v_transaction_id}}/' /> How can I go about this?

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  • urllib open - how to control the number of retries

    - by user1641071
    how can i control the number of retries of the "opener.open"? for example, in the following code, it will send about 6 "GET" HTTP requests (i saw it in the Wireshark sniffer) before it goes to the " except urllib.error.URLError" success/no-success lines. password_mgr = urllib.request.HTTPPasswordMgrWithDefaultRealm() password_mgr.add_password(None,url, username, password) handler = urllib.request.HTTPBasicAuthHandler(password_mgr) opener = urllib.request.build_opener(handler) try: resp = opener.open(url,None,1) except urllib.error.URLError as e: print ("no success") else: print ("success!")

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  • How do I configure a mail server for use with JavaMail?

    - by bobby
    I'm trying to work with the below code: import javax.servlet.*; import javax.servlet.http.*; import java.io.*; import javax.mail.*; import javax.mail.internet.*; // important import javax.mail.event.*; // important import java.net.*; import java.util.*; public class servletmail extends HttpServlet { public void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException, IOException { PrintWriter out=response.getWriter(); response.setContentType("text/html"); try { Properties props=new Properties(); props.put("mail.smtp.host","localhost"); // 'localhost' for testing Session session1 = Session.getDefaultInstance(props,null); String s1 = request.getParameter("text1"); //sender (from) String s2 = request.getParameter("text2"); String s3 = request.getParameter("text3"); String s4 = request.getParameter("area1"); Message message =new MimeMessage(session1); message.setFrom(new InternetAddress(s1)); message.setRecipients(Message.RecipientType.TO,InternetAddress.parse(s2,false)); message.setSubject(s3); message.setText(s4); Transport.send(message); out.println("mail has been sent"); } catch(Exception ex) { System.out.println("ERROR....."+ex); } } } I'm using mail.jar and activation.jar. But I can't understand how I should configure it with a mail server. Which mail server should I use? Will I be able to send an email using above code? What are the requirements a mail server? How should I configure it?

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  • My MYSQL & PHP while code is out of memory, when there is only one row

    - by Sam
    Hey all, why is this code throwing an out of memory error, when there is only 1 row in the database.. $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); $request = mysql_fetch_array( $request_db ); echo "<table border=\"1\" align=\"center\">"; while ( $request['haveplayed'] == "0" ) { echo "<tr><td>"; echo $request['SongName']; echo "</td><td>"; echo "<tr><td>"; echo $request['Artist']; echo "</td><td>"; echo "<tr><td>"; echo $request['DedicatedTo']; echo "</td><td>"; } echo "</table>"; Thanks.

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  • Android:HttpClient does not run in Android 4.0 API

    - by user1635564
    I have written the code it works on Android 2.2 API but it does not work on Android 4.0 String url = textUrl.getText().toString(); HttpClient client = new DefaultHttpClient(); HttpGet request = new HttpGet(url); try { HttpResponse response = client.execute(request); textResult.setText(HttpHelper.request(response)); } catch (Exception e) { // TODO: handle exception textResult.setText("Failed"); }

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  • How to drop/restart a client connection to a flaky socket server

    - by Steve Prior
    I've got Java code which makes requests via sockets from a server written in C++. The communication is simply that the java code writes a line for a request and the server then writes a line in response, but sometimes it seems that the server doesn't respond, so I've implemented an ExecutorService based timeout which tries to drop and restart the connection. To work with the connection I keep: Socket server; PrintWriter out; BufferedReader in; so setting up the connection is a matter of: server = new Socket(hostname, port); out = new PrintWriter(new OutputStreamWriter(server.getOutputStream())); in = new BufferedReader(new InputStreamReader(socket.getInputStream())); If it weren't for the timeout code the request/receive steps are simply: String request="some request"; out.println(request); out.flush(); String response = in.readLine(); When I received a timeout I was trying to close the connection with: in.close(); out.close(); socket.close(); but one of these closes seems to block and never return. Can anyone give me a clue why one of these would block and what would be the proper way to abandon the connection and not end up with resource leak issues?

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  • Django: Why Doesn't the Current URL Match any Patterns in urls.py

    - by austin_sherron
    I've found a few questions here related to my issue, but I haven't found anything that has helped me resolve my issue. I'm using Python 2.7.5 and Django 1.8.dev20140627143448. I have a view that's interacting with my database to delete objects, and it takes two arguments in addition to a request: def delete_data_item(request, dataclass_id, dataitem_id): form = AddDataItemForm(request.POST) data_set = get_object_or_404(DataClass, pk=dataclass_id) context = {'data_set': data_set, 'form': form} data_item = get_object_or_404(DataItem, pk=dataitem_id) data_item.delete() data_set.save() return HttpResponseRedirect(reverse('detail', args=(dataclass_id,))) The URL in myapp.urls.py looks something like this: url(r'^(?P<dataclass_id>[0-9]+)/(?P<dataitem_id>[0-9]+)/delete_data_item/$', views.delete_data_item, name='delete_data_item') and the portion of my template relevant to the view is: <a href="{% url 'delete_data_item' data_set.id data_item.id %}">DELETE</a> Whenever I click on the DELETE link, django tells me that the request URL: http://127.0.0.1:8000/myapp/5/%7B%%20url%20'delete_data_item'%20data_set.id%20data_item.id%20%%7D doesn't match any of my URL patterns. What am I missing? The URL on which the DELETE links exist is myapp/(<dataclass_id>[0-9]+)/

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  • GAE app.yaml appears to be inconsistently routing requests

    - by kamens
    I have the following in app.yaml: - url: /gae_mini_profiler/static static_dir: gae_mini_profiler/static - url: /gae_mini_profiler/.* script: gae_mini_profiler/main.py - url: .* script: main.py and the following in gae_mini_profiler/main.py: def main(): logging.critical("gae_mini_profiler request!") run_wsgi_app(application) However, when I fire requests to, say, /gae_mini_profiler/request?request=ABC, and repeatedly reload the page, sometimes I will get the proper response (as well as a "gae_mini_profiler request!" log entry, and sometimes I get a blank response and nothing in the App Engine logs other than a 200 with an empty response body. This is completely reproducible, only happens in the live environment, and I'd say ~50% of the refreshes work while 50% do not. This only happens in production. Any ideas?

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  • Need help with simple NHibernate mapping...

    - by mplarsen
    Need help with a simple NHibernate relationship... Tables/Classes Request ------- RequestId Title … Keywords ------- RequestID (key) Keyword (key) Request mapping file <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" namespace="CR.Model" assembly="CR"> <class name="CR.Model.Request, CR table="[dbo].[Request]" lazy="true"> <id name="Id" column="[RequestID]"> <generator class="native" /> </id> <property name="RequestorID" column="[RequestorID]" /> <property name="RequestorOther" column="[RequestorOther]" /> … Keyword?? </class> </hibernate-mapping> How do I simply map multiple keywords to a request? I don't need another mapping file for the keyword class, do I? It's be great if I could not only get the associated keywords, but add them too...

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  • json call with C#

    - by Vaccano
    I am trying to make a json call using C#. I made a stab at creating a call, but it did not work: public bool SendAnSMSMessage(string message) { HttpWebRequest request = (HttpWebRequest) WebRequest.Create("http://api.pennysms.com/jsonrpc"); request.Method = "POST"; request.ContentType = "application/json"; string json = "{ \"method\": \"send\", "+ " \"params\": [ "+ " \"IPutAGuidHere\", "+ " \"[email protected]\", "+ " \"MyTenDigitNumberWasHere\", "+ " \""+message+"\" " + " ] "+ "}"; StreamWriter writer = new StreamWriter(request.GetRequestStream()); writer.Write(json); writer.Close(); return true; } Any advice on how to make this work would be appreciated.

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  • Mystery in Ruby sinatra

    - by JVK
    I have the following Sinatra code: post '/bucket' do # determine if this call is coming from filling out web form is_html = request.content_type.to_s.downcase.eql?('application/x-www-form-urlencoded') # If this is a curl call, then get the params differently unless is_html params = JSON.parse(request.env["rack.input"].read) end p params[:name] end If I call this using Curl, params has values, but when this is called via a web form, then params is nil and params[:name] has nothing. I spent several hours figuring out why it happens and asked help from other people, but no one could really find out what is going on. One thing to note is, if I comment out this line: params = JSON.parse(request.env["rack.input"].read) then params has the correct value for "web-form" posting. Actually, the goal is to get the params value if this code is being called by CURL call, so I used: params = JSON.parse(request.env["rack.input"].read) but it messed up the web-form posting. Can anyone solve this mystery?

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  • Authenticating model - best practices

    - by zerkms
    I come into ASP.NET from php so the reason why i ask my question is because it's totally different nature of how application works and handles requests. well, i have an exists table with user creditians, such as: id, login, password (sha hashed), email, phone, room i have built custom membership provider so it can handle my own database authentication schema. and now i'm confused, because User.Identity.Name contains only user's login, but not the complete object (i'm using linq2sql to communicate with database and i need in it's User object to work). at php applications i just store user object at some static method at Auth class (or some another), but here at ASP.NET MVC i cannot do this, because static member is shared across all requests and permanent, and not lives within only current request (as it was at php). so my question is: how and where should i retrieve and store linq2sql user object to work with it within current and only current request? (after request processed successfully i expect it will be disposed from memory and on next request will be created again). or i'm following totally wrong way?

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  • Django: Save an uploaded file to a FileField

    - by David Wolever
    I feel a little stupid for having to ask this… But I can't seem find it documented anywhere. If I've got a Model with FileField, how can I stuff an uploaded FILE into that FileField? For example, I'd like to do something like this: class MyModel(Model): file = FileField(...) def handle_post(request, ...): mymodel = MyModel.objects.get(...) if request.FILES.get("newfile"): mymodel.file = request.FILES["newfile"] But that doesn't appear to work.

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  • JDBC with JSP fails to insert

    - by StrykeR
    I am having some issues right now with JDBC in JSP. I am trying to insert username/pass ext into my MySQL DB. I am not getting any error or exception, however nothing is being inserted into my DB either. Below is my code, any help would be greatly appreciated. <% String uname=request.getParameter("userName"); String pword=request.getParameter("passWord"); String fname=request.getParameter("firstName"); String lname=request.getParameter("lastName"); String email=request.getParameter("emailAddress"); %> <% try{ String dbURL = "jdbc:mysql:localhost:3306/assi1"; String user = "root"; String pwd = "password"; String driver = "com.mysql.jdbc.Driver"; String query = "USE Users"+"INSERT INTO User (UserName, UserPass, FirstName, LastName, EmailAddress) " + "VALUES ('"+uname+"','"+pword+"','"+fname+"','"+lname+"','"+email+"')"; Class.forName(driver); Connection conn = DriverManager.getConnection(dbURL, user, pwd); Statement statement = conn.createStatement(); statement.executeUpdate(query); out.println("Data is successfully inserted!"); } catch(SQLException e){ for (Throwable t : e) t.printStackTrace(); } %> DB script here: CREATE DATABASE Users; use Users; CREATE TABLE User ( UserID INT NOT NULL AUTO_INCREMENT, UserName VARCHAR(20), UserPass VARCHAR(20), FirstName VARCHAR(30), LastName VARCHAR(35), EmailAddress VARCHAR(50), PRIMARY KEY (UserID) );

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  • reverse many to many fields in Django + count them

    - by cleliodpaula
    I'm trying to figure out how to solve this class Item(models.Model): type = models.ForeignKey(Type) name = models.CharField(max_lenght = 10) ... class List(models.Model): items = models.ManyToManyField(Item) ... I want to count how many an Item appears in another Lists, and show on template. view def items_by_list(request, id_): list = List.objects.get(id = id_) qr = list.items.all() #NOT TESTED num = [] i = 0 for item in qr: num[i] = List.objects.filter(items__id = item__id ).count() #FINISH NOT TESTED c = {} c.update(csrf(request)) c = {'request':request, 'list' : qr, 'num' : num} return render_to_response('items_by_list.html', c, context_instance=RequestContext(request)) template {% for dia in list %} <div class="span4" > <div> <h6 style="color: #9937d8">{{item.type.description}}</h6> <small style="color: #b2e300">{{ item.name }}</small> <small style="color: #b2e300">{{COUNT HOW MANY TIMES THE ITEM APPEAR ON OTHER LISTS}}</small> </div> {% endfor %} This seems to be easy, but I could not implement yet. If anyone has some glue to me, please help me. Thanks in advance.

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  • Why can't these generic type parameters be inferred?

    - by Jon M
    Given the following interfaces/classes: public interface IRequest<TResponse> { } public interface IHandler<TRequest, TResponse> where TRequest : IRequest<TResponse> { TResponse Handle(TRequest request); } public class HandlingService { public TResponse Handle<TRequest, TResponse>(TRequest request) where TRequest : IRequest<TResponse> { var handler = container.GetInstance<IHandler<TRequest, TResponse>>(); return handler.Handle(request); } } public class CustomerResponse { public Customer Customer { get; set; } } public class GetCustomerByIdRequest : IRequest<CustomerResponse> { public int CustomerId { get; set; } } Why can't the compiler infer the correct types, if I try and write something like the following: var service = new HandlingService(); var request = new GetCustomerByIdRequest { CustomerId = 1234 }; var response = service.Handle(request); // Shouldn't this know that response is going to be CustomerResponse? I just get the 'type arguments cannot be inferred' message. Is this a limitation with generic type inference in general, or is there a way to make this work?

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  • Filter---after setting attribute--->Servlet---after getting and setting the attribute---->Jsp How do I do this?

    - by Y.E.P
    This is what I want to do : A servlet is called.Before a servlet is called , the request is intercepted by a filter. Filter gets some details out from the request,sets them as an attribute and the forwards it to a servlet via chain.doFilter(request,response). Request finally reaches the servlet. Servlet gets the attribute set by the filter before and sets a new attribute by another name. Then it forwards it to some jsp page where the page gets the attribute and processes it. How do I do this ? I know how to write a filter and a servlet but how do I forward it to a jsp page from the servlet or is there any other way to achieve this ?

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  • JAAS : on Callback ( Interesting based on HTTP headers )

    - by VJS
    I am using NameCallback and PasswordCallback for username and password.For username and password, popup comes on browser and when i enter username ans password, JAAS authenticates my request. On the wireshark, I have seen that 401 Unauthorized message (WWW-Authenticate header)comes and when i enter username/password HTTP request with credentials generate ( with Authorization header) and goes to server. My requirement : I don't want pop up to come.My application on other server having username / password, so once it received 401 then based on some logic it will generate HTTP request with Authorization header / credentials and sent it back. FLow : User - Other Server - My Tomcat5.5 Here on Other Server, nobody is available to enter username/password manually.Application is deployed and it will only generate HTTP request with credential and sent it back to tomcat. Can we have any other callback which behave like this.Need your help.Please provide me feedback as well related to approach.

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  • How to change Session for only one route in asp.net mvc?

    - by denis_n
    How to handle Application_BeginRequest using a custom filter in asp.net mvc? I want to restore session only for one route (~/my-url). It would be cool, if I could create a custom filter and handle that. protected void Application_BeginRequest(object sender, EventArgs e) { var context = HttpContext.Current; if (string.Equals("~/my-url", context.Request.AppRelativeCurrentExecutionFilePath, StringComparison.OrdinalIgnoreCase)) { string sessionId = context.Request.Form["sessionId"]; if (sessionId != null) { HttpCookie cookie = context.Request.Cookies.Get("ASP.NET_SessionId"); if (cookie == null) { cookie = new HttpCookie("ASP.NET_SessionId"); } cookie.Value = sessionId; context.Request.Cookies.Set(cookie); } }

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