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  • SQL Server 2005 - query with case statement

    - by user329266
    Trying to put a single query together to be used eventually in a SQL Server 2005 report. I need to: Pull in all distinct records for values in the "eventid" column for a time frame - this seems to work. For each eventid referenced above, I need to search for all instances of the same eventid to see if there is another record with TaskName like 'review1%'. Again, this seems to work. This is where things get complicated: For each record where TaskName is like review1, I need to see if another record exists with the same eventid and where TaskName='End'. Utimately, I need a count of how many records have TaskName like 'review1%', and then how many have TaskName like 'review1%' AND TaskName='End'. I would think this could be accomplished by setting a new value for each record, and for the eventid, if a record exists with TaskName='End', set to 1, and if not, set to 0. The query below seems to accomplish item #1 above: SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000'))) AS T WHERE seq = 1 order by eventid And the query below seems to accomplish #2: SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000')) and TaskName like 'Review1%') AS T WHERE seq = 1 order by eventid This will bring back the eventid's that also have a TaskName='End': SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000')) and TaskName like 'Review1%') AS T WHERE seq = 1 and eventid in (Select eventid from eventrecords where TaskName = 'End') order by eventid So I've tried the following to TRY to accomplish #3: SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000')) and TaskName like 'Review1%') AS T WHERE seq = 1 and case when (eventid in (Select eventid from eventrecords where TaskName = 'End') then 1 else 0) as bit end order by eventid When I try to run this, I get: "Incorrect syntax near the keyword 'then'." Not sure what I'm doing wrong. Haven't seen any examples anywhere quite like this. I should mention that eventrecords has a primary key, but it doesn't seem to help anything when I include it, and I am not permitted to change the table. (ugh) I've received one suggestion to use a cursor and temporary table, but am not sure how badley that would bog down performance when the report is running. Thanks in advance.

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  • how to put result in the end using jquery

    - by Martty Rox
    my code is : html with the js in section please ch3eck it out i need to prodeuce the result of the form of five questions and display it in the last section of the page where am i going wrong am using innerhtml js thing to produce the result in the last section <div id="section1"> <script type="text/javascript"> function changeText2(){ alert("working"); var count1=0; var a=document.forms["myForm"]["drop1"].value; var b=document.forms["myForm"]["drop2"].value; alert(document.forms["myForm"]["drop2"].value); var c=document.forms["myForm"]["drop3"].value; var d=document.forms["myForm"]["drop4"].value; var e=document.forms["myForm"]["drop5"].value; var f=document.forms["myForm"]["drop6"].value; if(a===2) { count1++; alert(count1); } else { alert("lit"); } if(b===2) { count1++; } else { alert("lit"); } if(c===2) { count1++; } else { alert("lit"); } if(d===2) { count1++; } else { alert("lit"); } if(e===2) { count1++; } else alert("lit"); } alert(count1); document.getElementById('boldStuff2').innerHTML = count1; </script> <form name="myForm"> <p>1)&#x00A0;&#x00A0;Who won the 1993 &#x201C;King of the Ring&#x201D;?</p> <div> <select id="f1" name="drop1"> <option value="0" selected="selected">-- Select -- </option> <option value="1">Owen Hart </option> <option value="2">Bret Hart </option> <option value="3">Edge </option> <option value="4">Mabel </option> </select> </div> <!--que1--> <p>2)&#x00A0;&#x00A0;What NHL goaltender has the most career wins?</p> <div> <select id="f2" name="drop2"> <option value="0" selected="selected">-- Select -- </option> <option value="1">Grant Fuhr </option> <option value="2">Patrick Roy </option> <option value="3">Chris Osgood </option> <option value="4">Mike Vernon</option> </select> </div> <!--que2--> <p>3)&#x00A0;&#x00A0;What Major League Baseball player holds the record for all-time career high batting average?</p> <div> <select id="f3" name="drop3"> <option value="0" selected="selected">-- Select -- </option> <option value="1">Ty Cobb </option> <option value="2">Larry Walker </option> <option value="3">Jeff Bagwell </option> <option value="4">Frank Thomas</option> </select> </div> <!--que3--> <p>4)&#x00A0;&#x00A0;Who among the following is NOT associated with billiards in India?</p> <div> <select id="f4" name="drop4" > <option value="0" selected="selected">-- Select -- </option> <option value="1">Subash Agrawal </option> <option value="2">Ashok Shandilya </option> <option value="3">Manoj Kothari </option> <option value="4">Mihir Sen</option> </select> </div> <!--que4--> <p>5)&#x00A0;&#x00A0;Which cricketer died on the field in Bangladesh while playing for Abahani Club?</p> <div> <select id="f5" name="drop5" > <option value="0" selected="selected">-- Select -- </option> <option value="1">Subhash Gupte</option> <option value="2">M.L.Jaisimha</option> <option value="3">Lala Amarnath</option> <option value="4">Raman Lamba</option> </select> </div> <!--que5--> <a href="#services" class="page_nav_btn next"><input type='button' onclick='changeText2()' value='NEXT'/></a> </form> </div> <div id="section2"> </div> ... <div id="results"> <b id='boldStuff2'>fff ggg</b> </div> need to display the results of each section at the last div as shown in script... js for first section not working plz some help me where am i going wrong....

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  • whats wrong in this LINQ synatx?

    - by Saurabh Kumar
    Hi, I am trying to convert a SQL query to LINQ. Somehow my count(distinct(x)) logic does not seem to be working correctly. The original SQL is quite efficient(or so i think), but the generated SQL is not even returning the correct result. I am trying to fix this LINQ to do what the original SQL is doing, AND in an efficient way as the original query is doing. Help here would be really apreciated as I am stuck here :( SQL which is working and I need to make a comparable LINQ of: SELECT [t1].[PersonID] AS [personid] FROM [dbo].[Code] AS [t0] INNER JOIN [dbo].[phonenumbers] AS [t1] ON [t1].[PhoneCode] = [t0].[Code] INNER JOIN [dbo].[person] ON [t1].[PersonID]= [dbo].[Person].PersonID WHERE ([t0].[codetype] = 'phone') AND ( ([t0].[CodeDescription] = 'Home') AND ([t1].[PhoneNum] = '111') OR ([t0].[CodeDescription] = 'Work') AND ([t1].[PhoneNum] = '222') ) GROUP BY [t1].[PersonID] HAVING COUNT(DISTINCT([t1].[PhoneNum]))=2 The LINQ which I made is approximately as below: var ids = context.Code.Where(predicate); var rs = from r in ids group r by new { r.phonenumbers.person.PersonID} into g let matchcount=g.Select(p => p.phonenumbers.PhoneNum).Distinct().Count() where matchcount ==2 select new { personid = g.Key }; Unfortunately, the above LINQ is NOT generating the correct result, and is actually internally getting generated to the SQL shown below. By the way, this generated query is also reading ALL the rows(about 19592040) around 2 times due to the COUNTS :( Wich is a big performance issue too. Please help/point me to the right direction. Declare @p0 VarChar(10)='phone' Declare @p1 VarChar(10)='Home' Declare @p2 VarChar(10)='111' Declare @p3 VarChar(10)='Work' Declare @p4 VarChar(10)='222' Declare @p5 VarChar(10)='2' SELECT [t9].[PersonID], ( SELECT COUNT(*) FROM ( SELECT DISTINCT [t13].[PhoneNum] FROM [dbo].[Code] AS [t10] INNER JOIN [dbo].[phonenumbers] AS [t11] ON [t11].[PhoneType] = [t10].[Code] INNER JOIN [dbo].[Person] AS [t12] ON [t12].[PersonID] = [t11].[PersonID] INNER JOIN [dbo].[phonenumbers] AS [t13] ON [t13].[PhoneType] = [t10].[Code] WHERE ([t9].[PersonID] = [t12].[PersonID]) AND ([t10].[codetype] = @p0) AND ((([t10].[codetype] = @p1) AND ([t11].[PhoneNum] = @p2)) OR (([t10].[codetype] = @p3) AND ([t11].[PhoneNum] = @p4))) ) AS [t14] ) AS [cnt] FROM ( SELECT [t3].[PersonID], ( SELECT COUNT(*) FROM ( SELECT DISTINCT [t7].[PhoneNum] FROM [dbo].[Code] AS [t4] INNER JOIN [dbo].[phonenumbers] AS [t5] ON [t5].[PhoneType] = [t4].[Code] INNER JOIN [dbo].[Person] AS [t6] ON [t6].[PersonID] = [t5].[PersonID] INNER JOIN [dbo].[phonenumbers] AS [t7] ON [t7].[PhoneType] = [t4].[Code] WHERE ([t3].[PersonID] = [t6].[PersonID]) AND ([t4].[codetype] = @p0) AND ((([t4].[codetype] = @p1) AND ([t5].[PhoneNum] = @p2)) OR (([t4].[codetype] = @p3) AND ([t5].[PhoneNum] = @p4))) ) AS [t8] ) AS [value] FROM ( SELECT [t2].[PersonID] FROM [dbo].[Code] AS [t0] INNER JOIN [dbo].[phonenumbers] AS [t1] ON [t1].[PhoneType] = [t0].[Code] INNER JOIN [dbo].[Person] AS [t2] ON [t2].[PersonID] = [t1].[PersonID] WHERE ([t0].[codetype] = @p0) AND ((([t0].[codetype] = @p1) AND ([t1].[PhoneNum] = @p2)) OR (([t0].[codetype] = @p3) AND ([t1].[PhoneNum] = @p4))) GROUP BY [t2].[PersonID] ) AS [t3] ) AS [t9] WHERE [t9].[value] = @p5 Thanks!

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  • SQL Server: How to call a UDF, if available?

    - by Ian Boyd
    Most systems will have a user-defined function (UDF) available. Some will not. i want to use the UDF if it's there: SELECT Users.*, dbo.UserGroupMembershipNames(Users.UserID) AS MemberOfGroupNames FROM Users Otherwise fallback to the acceptable alternative SELECT Users.*, (SELECT TOP 1 thing FROM Something WHERE Something.ID = Users.UserID) AS MemberGroupNames FROM Users How do? My first attempt, using the obvious solution, of course failed: SELECT Users.*, CASE WHEN (OBJECT_ID('dbo.UserGroupMembershipNames') IS NOT NULL) THEN dbo.UserGroupMembershipNames(Users.UserID) ELSE (SELECT TOP 1 thing FROM Something WHERE Something.ID = Users.UserID) END AS MemberOfGroupNames FROM Users for reasons beyond me

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  • Sql query Error: Operand should contain 1 column(s) in rails

    - by dombesz
    Hi everyone, SELECT * FROM jobs WHERE (SELECT DISTINCT jobs.* FROM jobs, job_requests WHERE (jobs.user_id = 1) OR (job_requests.user_id = 1 AND job_requests.job_id = jobs.id)) This sql gives me Mysql::Error: Operand should contain 1 column(s). If i execute the select from the where clause it works SELECT DISTINCT jobs.* FROM jobs, job_requests WHERE (jobs.user_id = 1) OR (job_requests.user_id = 1 AND job_requests.job_id = jobs.id) Could somebody explain me why? This query is generated by rails activerecord so the main select is needed.

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  • NHibernate - using custom sql query for a column

    - by stacker
    Is there anyway to use custom sql with NHibernate? I want to use custom sql for a specific column. select id, viewsCount, commentsCount, 0.2 * viewsCount / (select top 1 viewsCount from articles where isActive = 1 order by viewsCount DESC) as priorityViews, 0.8 * commentsCount / (select top 1 commentsCount from articles where isActive = 1 order by commentsCount DESC) as priorityComments, round(0.2 * viewsCount / (select top 1 viewsCount from articles where isActive = 1 order by viewsCount DESC) + 0.8 * commentsCount / (select top 1 commentsCount from articles where isActive = 1 order by commentsCount DESC), 1) as priority from articles

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  • How to refactor this MySQL code?

    - by Jader Dias
    SELECT * ( SELECT * FROM `table1` WHERE `id` NOT IN ( SELECT `id` FROM `table2` WHERE `col4` = 5 ) group by `col2` having sum(`col3`) > 0 UNION SELECT * FROM `table1` WHERE `id` NOT IN ( SELECT `id` FROM `table2` WHERE `col4` = 5 ) group by `col2` having sum(`col3`) = 0 ) t1; For readability and performance reasons, I think this code could be refactored. But how?

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  • how to specify literal value in linq union

    - by lowlyintern
    I have the following SQL query, note I want the literal value '0' in the second field in the second SELECT statement from the ItemSale table. How do I express this in LINQ? I get the error message 'Invalid anonymous type member declarator'. SELECT BranchNumber,QuantitySold FROM Department UNION SELECT BranchNumber,0 FROM ItemSale How to express the '0' in LINQ? var unionQuery = (from dept in Department select new { dept.BranchNumber, dept.QuantitySold, }) .Concat(from item in ItemSale select new { item.BranchNumber, 0 });

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  • MySQL count statements error - operand should contain 1 column(s)

    - by jason
    I am trying to do multiple counts everyone was working accept the first sub select (list1) I get an error that reads "Operand should contain 1 column(s)" i'm guessing it has something to do with the AND, but i'm not sure how I would fix this one. Select Count(list0.ustatus) AS finished_count, (Select list1.ustatus, Count(*) From listofupdates list1 Where list1.ustarted != '0000-00-00 00:00:00' AND list1.ustatus != 1) AS start_count, (Select Count(list2.udifficulty) From listofupdates list2 Where list2.udifficulty = 2) AS recheck_count, (Select Count(list3.udifficulty) From listofupdates list3 Where list3.udifficulty = 4) AS question_count From listofupdates list0 Where list0.ustatus = 1

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  • Which of these queries is more efficient?

    - by Brian
    Which of these queries are more efficient? select 1 as newAndClosed from sysibm.sysdummy1 where exists ( select 1 from items where new = 1 ) and not exists ( select 1 from status where open = 1 ) select 1 as newAndClosed from items where new = 1 and not exists ( select 1 from status where open = 1 )

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  • TIME REDUCE(OPTIMISE QUERY)

    - by user2527657
    select a.userid,(select firstName from user where userid=NOTUSED.userid) as z, (select max(login_time) from userLoginTime AS b where userid = a.user_id GROUP BY b.user_id ORDER BY b.user_id) as y From(SELECT DISTINCT a.user_id FROM user AS a LEFT OUTER JOIN (SELECT (userid) FROM userlogintime where serialid=15400012)AS b ON user.user_id = b.user_id where a.Serialid=15400012 AND b.userid IS NULL) NOTUSED, Relation r, user a where r.childuserid = NOTUSED.userid and guarduserid = a.userid

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  • SQL SERVER – Index Created on View not Used Often – Observation of the View

    - by pinaldave
    I always enjoy writing about concepts on Views. Views are frequently used concepts, and so it’s not surprising that I have seen so many misconceptions about this subject. To clear such misconceptions, I have previously written the article SQL SERVER – The Limitations of the Views – Eleven and more…. I also wrote a follow up article wherein I demonstrated that without even creating index on the basic table, the query on the View will not use the View. You can read about this demonstration over here: SQL SERVER – Index Created on View not Used Often – Limitation of the View 12. I promised in that post that I would also write an article where I would demonstrate the condition where the Index will be used. I got many responses suggesting that I can do that with using NOEXPAND; I agree. I have already written about this in my original summary article. Here is a way for you to see how Index created on View can be utilized. We will do the following steps on this exercise: Create a Table Create a View Create Index On View Write SELECT with ORDER BY on View USE tempdb GO IF EXISTS (SELECT * FROM sys.views WHERE OBJECT_ID = OBJECT_ID(N'[dbo].[SampleView]')) DROP VIEW [dbo].[SampleView] GO IF EXISTS (SELECT * FROM sys.objects WHERE OBJECT_ID = OBJECT_ID(N'[dbo].[mySampleTable]') AND TYPE IN (N'U')) DROP TABLE [dbo].[mySampleTable] GO -- Create SampleTable CREATE TABLE mySampleTable (ID1 INT, ID2 INT, SomeData VARCHAR(100)) INSERT INTO mySampleTable (ID1,ID2,SomeData) SELECT TOP 100000 ROW_NUMBER() OVER (ORDER BY o1.name), ROW_NUMBER() OVER (ORDER BY o2.name), o2.name FROM sys.all_objects o1 CROSS JOIN sys.all_objects o2 GO -- Create View CREATE VIEW SampleView WITH SCHEMABINDING AS SELECT ID1,ID2,SomeData FROM dbo.mySampleTable GO -- Create Index on View CREATE UNIQUE CLUSTERED INDEX [IX_ViewSample] ON [dbo].[SampleView] ( ID2 ASC ) GO -- Select from view SELECT ID1,ID2,SomeData FROM SampleView ORDER BY ID2 GO When we check the execution plan for this , we find it clearly that the Index created on the View is utilized. ORDER BY clause uses the Index created on the View. I hope this makes the puzzle simpler on how the Index is used on the View. Again, I strongly recommend reading my earlier series about the limitations of the Views found here: SQL SERVER – The Limitations of the Views – Eleven and more…. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Optimization, SQL Performance, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQL View, T SQL, Technology

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  • SQL SERVER – Saturday Fun Puzzle with SQL Server DATETIME2 and CAST

    - by pinaldave
    Note: I have used SQL Server 2012 for this small fun experiment. Here is what we are going to do. We will run the script one at time instead of running them all together and try to guess the answer. I am confident that many will get it correct but if you do not get correct, you learn something new. Let us create database and sample table. CREATE DATABASE DB2012 GO USE DB2012 GO CREATE TABLE TableDT (DT1 VARCHAR(100), DT2 DATETIME2, DT1C AS DT1, DT2C AS DT2); INSERT INTO TableDT (DT1, DT2) SELECT GETDATE(), GETDATE() GO There are four columns in the table. The first column DT1 is regular VARCHAR and second DT2 is DATETIME2. Both of the column are been populated with the same data as I have used the function GETDATE(). Now let us do the SELECT statement and get the result from both the columns. Before running the query please guess the answer and write it down on the paper or notepad. Question 1: Guess the resultset SELECT DT1, DT2 FROM TableDT GO Now once again run the select statement on the same table but this time retrieve the computed columns only. Once again I suggest you write down the result on the notepad. Question 2: Guess the resultset SELECT DT1C, DT2C FROM TableDT GO Now here is the best part. Let us use the CAST function over the computed columns. Here I do want you to stop and guess the answer for sure. If you have not done it so far, stop do it, believe me you will like it. Question 3: Guess the resultset SELECT CAST(DT1C AS DATETIME2) CDT1C, CAST(DT2C AS DATETIME2) CDT1C FROM TableDT GO Now let us inspect all the answers together and see how many of you got it correct. Answer 1: Answer 2: Answer 3:  If you have not tried to run the script so far, you can execute all the three of the above script together over here and see the result together. SELECT CAST(DT1C AS DATETIME2) CDT1C, CAST(DT2C AS DATETIME2) CDT1C FROM TableDT GO Here is the Saturday Fun question to you – why do we get same result from both of the expressions in Question 3, where as in question 2 both the expression have different answer. I will publish the valid answer with explanation in future blog posts. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL DateTime, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – Solution – 2 T-SQL Puzzles – Display Star and Shortest Code to Display 1

    - by pinaldave
    Earlier on this blog we had asked two puzzles. The response from all of you is nothing but Amazing. I have received 350+ responses. Many are valid and many were indeed something I had not thought about it. I strongly suggest you read all the puzzles and their answers here - trust me if you start reading the comments you will not stop till you read every single comment. Seriously trust me on it. Personally I have learned a lot from it. Let us recap the puzzles here quickly. Puzzle 1: Why following code when executed in SSMS displays result as a * (Star)? SELECT CAST(634 AS VARCHAR(2)) Puzzle 2: Write the shortest code that produces results as 1 without using any numbers in the select statement. Bonus Q: How many different Operating System (OS) NuoDB support? As I mentioned earlier the participation was nothing but Amazing. I will write about the winners and the best answers in short time. Meanwhile I will give to the point answers to above puzzles. Solution 1: When you convert character or binary expressions (char, nchar, nvarchar, varchar,binary, or varbinary) to an expression of a different data type, data can be truncated, only partially displayed, or an error is returned because the result is too short to display. Conversions to char, varchar, nchar, nvarchar, binary, and varbinary are truncated, except for the conversions shown in the following table. Reference of the text and table from MSDN. Solution 2: The shortest code to produce answer 1 : SELECT EXP($) or SELECT COS($) or SELECT DAY($) When SELECT $ it gives us the result as 0.00 and the EXP of the same is 1. I believe it is pretty neat. There were plenty other answers but this was the shortest. Another shorter answer would be PRINT EXP($) but no one has proposed that as in original Question I have explicitly mentioned SELECT in the original question. Bonus Answer: 5 OS: Windows, MacOS, Linux, Solaris, Joyent SmartOS Reference Please do read every single comment here. Do leave a comment which one do you think is the best comment out of all the comments. Meanwhile if there is a better solution and I have missed it do let me know as we still have time to correct it. I will be selecting the winner before the weekend as I am going through each and every of 350 comment. I will be selecting the best comments along with the winning comment. If our selection matches – one of you may still win something cool.  Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology Tagged: NuoDB

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  • SQL SERVER – Introduction to Function SIGN

    - by pinaldave
    Yesterday I received an email from a friend asking how do SIGN function works. Well SIGN Function is very fundamental function. It will return the value 1, -1 or 0. If your value is negative it will return you negative -1 and if it is positive it will return you positive +1. Let us start with a simple small example. DECLARE @IntVal1 INT, @IntVal2 INT,@IntVal3 INT DECLARE @NumVal1 DECIMAL(4,2), @NumVal2 DECIMAL(4,2),@NumVal3 DECIMAL(4,2) SET @IntVal1 = 9; SET @IntVal2 = -9; SET @IntVal3 = 0; SET @NumVal1 = 9.0; SET @NumVal2 = -9.0; SET @NumVal3 = 0.0; SELECT SIGN(@IntVal1) IntVal1,SIGN(@IntVal2) IntVal2,SIGN(@IntVal3) IntVal3 SELECT SIGN(@NumVal1) NumVal1,SIGN(@NumVal2) NumVal2,SIGN(@NumVal2) NumVal3   The above function will give us following result set. You will notice that when there is positive value the function gives positive values and if the values are negative it will return you negative values. Also you will notice that if the data type is  INT the return value is INT and when the value passed to the function is Numeric the result also matches it. Not every datatype is compatible with this function.  Here is the quick look up of the return types. bigint -> bigint int/smallint/tinyint -> int money/smallmoney -> money numeric/decimal -> numeric/decimal everybody else -> float What will be the best example of the usage of this function that you will not have to use the CASE Statement. Here is example of CASE Statement usage and the same replaced with SIGN function. USE tempdb GO CREATE TABLE TestTable (Date1 SMALLDATETIME, Date2 SMALLDATETIME) INSERT INTO TestTable (Date1, Date2) SELECT '2012-06-22 16:15', '2012-06-20 16:15' UNION ALL SELECT '2012-06-24 16:15', '2012-06-22 16:15' UNION ALL SELECT '2012-06-22 16:15', '2012-06-22 16:15' GO -- Using Case Statement SELECT CASE WHEN DATEDIFF(d,Date1,Date2) > 0 THEN 1 WHEN DATEDIFF(d,Date1,Date2) < 0 THEN -1 ELSE 0 END AS Col FROM TestTable GO -- Using SIGN Function SELECT SIGN(DATEDIFF(d,Date1,Date2)) AS Col FROM TestTable GO DROP TABLE TestTable GO This was interesting blog post for me to write. Let me know your opinion. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – A Brief Note on SET TEXTSIZE

    - by pinaldave
    Here is a small conversation I received. I thought though an old topic, indeed a thought provoking for the moment. Question: Is there any difference between LEFT function and SET TEXTSIZE? I really like this small but interesting question. The question does not specify the difference between usage or performance. Anyway we will quickly take a look at how TEXTSIZE works. You can run the following script to see how LEFT and SET TEXTSIZE works. USE TempDB GO -- Create TestTable CREATE TABLE MyTable (ID INT, MyText VARCHAR(MAX)) GO INSERT MyTable (ID, MyText) VALUES(1, REPLICATE('1234567890', 100)) GO -- Select Data SELECT ID, MyText FROM MyTable GO -- Using Left SELECT ID, LEFT(MyText, 10) MyText FROM MyTable GO -- Set TextSize SET TEXTSIZE 10; SELECT ID, MyText FROM MyTable; SET TEXTSIZE 2147483647 GO -- Clean up DROP TABLE MyTable GO Now let us see the usage result which we receive from both of the example. If you are going to ask what you should do – I really do not know. I can tell you where I will use either of the same. LEFT seems to be easy to use but again if you like to do extra work related to SET TEXTSIZE go for it. Here is how I will use SET TEXTSIZE. If I am selecting data from in my SSMS for testing or any other non production related work from a large table which has lots of columns with varchar data, I will consider using this statement to reduce the amount of the data which is retrieved in the result set. In simple word, for testing purpose I will use it. On the production server, there should be a specific reason to use the same. Here is my candid opinion – I do not think they can be directly comparable even though both of them give the exact same result. LEFT is applicable only on the column of a single SELECT statement. where it is used but it SET TEXTSIZE applies to all the columns in the SELECT and follow up SELECT statements till the SET TEXTSIZE is not modified again in the session. Uncomparable! I hope this sample example gives you idea how to use SET TEXTSIZE in your daily use. I would like to know your opinion about how and when do you use this feature. Please leave a comment. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Is there any good hosting for asp.net and MySQL

    - by HAJJAJ
    HI every one ,I have account with one of the hosting company, and i did my project in asp.net and I used MySQL for the database. the hosting company is not giving me the full privileges to create new user or to create new stored procedure!!! this is what they said for me: Due to the shared nature of our environment we had to make some modifications to your procedure (namely the definer). We also had to review your procedure to determine if it would be compatible with our environment. While your procedures will work (via phpMyAdmin or some other interface), it is unlikely they will be accessible via the Connector/.NET (ADO.NET) that your application is likely using. This is due to a security restriction with how that connector works in shared environments. http://dev.mysql.com/doc/refman/5.0/en/connector-net-programming-stored.html "Note When you call a stored procedure, the command object makes an additional SELECT call to determine the parameters of the stored procedure. You must ensure that the user calling the procedure has the SELECT privilege on the mysql.proc table to enable them to verify the parameters. Failure to do this will result in an error when calling the procedure." Unfortunately, giving read privileges on the mysql.proc table will give you access to the data of our other customers and that is not an acceptable risk. If your application can only work using stored procedures, then MSSQL will probably be the better option for your site. I apologize for the inconvenience and the wait to have this ticket completed. So is there any good hosting that any body already used it to publish his asp.net and mysql project ??? this is one of my stored procedure and i think it's sample and it will not harm any other uses!!: -- -------------------------------------------------------------------------------- -- Routine DDL -- Note: comments before and after the routine body will not be stored by the server -- -------------------------------------------------------------------------------- DELIMITER $$ CREATE DEFINER=`root`@`localhost` PROCEDURE `SpcategoriesRead`( IN PaRactioncode VARCHAR(5), IN PaRCatID BIGINT, IN PaRSearchText TEXT ) BEGIN -- CREATING TEMPORARY TABLE TO SAVE DATA FROM THE ACTIONCODE SELECTS -- DROP TEMPORARY TABLE IF EXISTS TEMP; CREATE temporary table tmp ( CatID BIGINT primary key not null, CatTitle TEXT, CatDescription TEXT, CatTitleAr TEXT, CatDescriptionAr TEXT, PictureID BIGINT, Published BOOLEAN, DisplayOrder BIGINT, CreatedOn DATE ); IF PaRactioncode = 1 THEN -- Retrive all DATA from the database -- INSERT INTO tmp SELECT CatID,CatTitle,CatDescription,CatTitleAr,CatDescriptionAr,PictureID,Published,DisplayOrder,CreatedOn FROM tbcategories; ELSEIF PaRactioncode = 2 THEN -- Retrive all from the database By ID -- INSERT INTO tmp SELECT CatID,CatTitle,CatDescription,CatTitleAr,CatDescriptionAr,PictureID,Published,DisplayOrder,CreatedOn FROM tbcategories WHERE CatID=PaRCatID; ELSEIF PaRactioncode = 3 THEN -- NOSET YET -- INSERT INTO tmp SELECT CatID,CatTitle,CatDescription,CatTitleAr,CatDescriptionAr,PictureID,Published,DisplayOrder,CreatedOn FROM tbcategories WHERE Published=1 ORDER BY DisplayOrder; END IF; IF PaRSearchText IS NOT NULL THEN set PaRSearchText=concat('%', PaRSearchText ,'%'); SELECT CatID,CatTitle,CatDescription,CatTitleAr,CatDescriptionAr,PictureID,Published,DisplayOrder,CreatedOn FROM tmp WHERE Concat(CatTitle, CatDescription, CatTitleAr, CatDescriptionAr) LIKE PaRSearchText; ELSE SELECT CatID,CatTitle,CatDescription,CatTitleAr,CatDescriptionAr,PictureID,Published,DisplayOrder,CreatedOn FROM tmp; END IF; DROP TEMPORARY TABLE IF EXISTS tmp; END

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  • SQL??“ALL”,????

    - by Todd Bao
    ALL????????????,>ALL?>=ALL?<ALL?<=ALL?=ALL?!=ALL???????????????????WHERE????TRUE?????????“=ALL”?????:select employee_id,last_name,department_id  from hr.employees   where department_id =ALL (select department_id from hr.employees where salary > 16000);EMPLOYEE_ID + LAST_NAME         + DEPARTMENT_ID----------- + ------------------------- + -------------    100 + King            +         90    101 + Kochhar            +         90    102 + De Haan            +         903 rows selected.??????????SALARY??16000????????????????????(???90),???????????????????????,????????????department_id???,????????????,???16000???8000:select employee_id,last_name   from hr.employees   where department_id =ALL (select department_id from hr.employees where salary > 8000);no rows selected????,ALL???????????????????WHERE????TURE,??????,??????salary > 77777:select employee_id,last_name   from hr.employees   where department_id =ALL (select department_id from hr.employees where salary > 77777)/?????????????77777??,??????“where department_id =ALL (???)”??TRUE,?????????????:EMPLOYEE_ID + LAST_NAME----------- + -------------------------    198 + OConnell    199 + Grant    ...   .....    196 + Walsh    197 + Feeney107 rows selected.?????????????>ALL?<ALL?>=ALL?<=ALL?!=ALL??,??????????????,???????“?”??????????????????,?“?”?????????????????????????????:select * from hr.employees where department_id >=ALL (null)/Todd

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  • SQL SERVER – Server Side Paging in SQL Server 2011 Performance Comparison

    - by pinaldave
    Earlier, I have written about SQL SERVER – Server Side Paging in SQL Server 2011 – A Better Alternative. I got many emails asking for performance analysis of paging. Here is the quick analysis of it. The real challenge of paging is all the unnecessary IO reads from the database. Network traffic was one of the reasons why paging has become a very expensive operation. I have seen many legacy applications where a complete resultset is brought back to the application and paging has been done. As what you have read earlier, SQL Server 2011 offers a better alternative to an age-old solution. This article has been divided into two parts: Test 1: Performance Comparison of the Two Different Pages on SQL Server 2011 Method In this test, we will analyze the performance of the two different pages where one is at the beginning of the table and the other one is at its end. Test 2: Performance Comparison of the Two Different Pages Using CTE (Earlier Solution from SQL Server 2005/2008) and the New Method of SQL Server 2011 We will explore this in the next article. This article will tackle test 1 first. Test 1: Retrieving Page from two different locations of the table. Run the following T-SQL Script and compare the performance. SET STATISTICS IO ON; USE AdventureWorks2008R2 GO DECLARE @RowsPerPage INT = 10, @PageNumber INT = 5 SELECT * FROM Sales.SalesOrderDetail ORDER BY SalesOrderDetailID OFFSET @PageNumber*@RowsPerPage ROWS FETCH NEXT 10 ROWS ONLY GO USE AdventureWorks2008R2 GO DECLARE @RowsPerPage INT = 10, @PageNumber INT = 12100 SELECT * FROM Sales.SalesOrderDetail ORDER BY SalesOrderDetailID OFFSET @PageNumber*@RowsPerPage ROWS FETCH NEXT 10 ROWS ONLY GO You will notice that when we are reading the page from the beginning of the table, the database pages read are much lower than when the page is read from the end of the table. This is very interesting as when the the OFFSET changes, PAGE IO is increased or decreased. In the normal case of the search engine, people usually read it from the first few pages, which means that IO will be increased as we go further in the higher parts of navigation. I am really impressed because using the new method of SQL Server 2011,  PAGE IO will be much lower when the first few pages are searched in the navigation. Test 2: Retrieving Page from two different locations of the table and comparing to earlier versions. In this test, we will compare the queries of the Test 1 with the earlier solution via Common Table Expression (CTE) which we utilized in SQL Server 2005 and SQL Server 2008. Test 2 A : Page early in the table -- Test with pages early in table USE AdventureWorks2008R2 GO DECLARE @RowsPerPage INT = 10, @PageNumber INT = 5 ;WITH CTE_SalesOrderDetail AS ( SELECT *, ROW_NUMBER() OVER( ORDER BY SalesOrderDetailID) AS RowNumber FROM Sales.SalesOrderDetail PC) SELECT * FROM CTE_SalesOrderDetail WHERE RowNumber >= @PageNumber*@RowsPerPage+1 AND RowNumber <= (@PageNumber+1)*@RowsPerPage ORDER BY SalesOrderDetailID GO SET STATISTICS IO ON; USE AdventureWorks2008R2 GO DECLARE @RowsPerPage INT = 10, @PageNumber INT = 5 SELECT * FROM Sales.SalesOrderDetail ORDER BY SalesOrderDetailID OFFSET @PageNumber*@RowsPerPage ROWS FETCH NEXT 10 ROWS ONLY GO Test 2 B : Page later in the table -- Test with pages later in table USE AdventureWorks2008R2 GO DECLARE @RowsPerPage INT = 10, @PageNumber INT = 12100 ;WITH CTE_SalesOrderDetail AS ( SELECT *, ROW_NUMBER() OVER( ORDER BY SalesOrderDetailID) AS RowNumber FROM Sales.SalesOrderDetail PC) SELECT * FROM CTE_SalesOrderDetail WHERE RowNumber >= @PageNumber*@RowsPerPage+1 AND RowNumber <= (@PageNumber+1)*@RowsPerPage ORDER BY SalesOrderDetailID GO SET STATISTICS IO ON; USE AdventureWorks2008R2 GO DECLARE @RowsPerPage INT = 10, @PageNumber INT = 12100 SELECT * FROM Sales.SalesOrderDetail ORDER BY SalesOrderDetailID OFFSET @PageNumber*@RowsPerPage ROWS FETCH NEXT 10 ROWS ONLY GO From the resultset, it is very clear that in the earlier case, the pages read in the solution are always much higher than the new technique introduced in SQL Server 2011 even if we don’t retrieve all the data to the screen. If you carefully look at both the comparisons, the PAGE IO is much lesser in the case of the new technique introduced in SQL Server 2011 when we read the page from the beginning of the table and when we read it from the end. I consider this as a big improvement as paging is one of the most used features for the most part of the application. The solution introduced in SQL Server 2011 is very elegant because it also improves the performance of the query and, at large, the database. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: SQL, SQL Authority, SQL Optimization, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Add Keyboard Input Language to Ubuntu

    - by Matthew Guay
    Want to type in multiple languages in Ubuntu?  Here we’ll show you how you can easily add and switch between multiple keyboard layouts in Ubuntu. Add a Keyboard Language To add a keyboard language, open the System menu, select Preferences, and then select Keyboard. In the Keyboard Preferences dialog, select the Layouts tab, and click Add.   You can select a country and then choose an language and keyboard variant.  Note that some countries, such as the United States, may show several languages.  Once you’ve made your selection, you can preview it on the sample keyboard displayed below the menu. Alternately, on the second tab, select a language and then choose a variant.  Click Add when you’ve made your selection. Now you’ll notice that there are two languages listed in the Keyboard Preferences, and they’re both ready to use immediately.  You can add more if you wish, or close the dialog. Switch Between Languages When you have multiple input languages installed, you’ll notice a new icon in your system tray on the top right.  It will show the abbreviation of the country and/or language name that is currently selected.  Click the icon to change the language. Right-click the dialog to view available languages (listed under Groups), open the Keyboard Preferences dialog again, or show the current layout. If you select Show Current Layout you’ll see a window with the keyboard preview we saw previously when setting the keyboard layout.  You can even print this layout preview out to help you remember a layout if you wish. Change Keyboard Shortcuts to Switch Languages By default, you can switch input languages in Ubuntu from the keyboard by pressing both Alt keys together.  Many users are already used to the default Alt+Switch combination to switch input languages in Windows, and we can add that in Ubuntu.  Open the keyboard preferences dialog, select the Layout tab, and click Options. Click the plus sign beside Key(s) to change layout, and select Alt+Shift.  Click Close, and you can now use this familiar shortcut to switch input languages. The layout options dialog offers many more neat keyboard shortcuts and options.  One especially neat option was the option to use a keyboard led to show when we’re using the alternate keyboard layout.  We selected the ScrollLock light since it’s hardly used today, and now it lights up when we’re using our other input language.   Conclusion Whether you regularly type in multiple languages or only need to enter an occasional character from an alternate keyboard layout, Ubuntu’s keyboard settings make it easy to make your keyboard work the way you want.  And since you can even preview and print a keyboard layout, you can even remember an alternate keyboard’s layout if it’s not printed on your keyboard. Windows users, you’re not left behind, either.  Check out our tutorial on how to Add keyboard languages to XP, Vista, and Windows 7. Similar Articles Productive Geek Tips Add keyboard languages to XP, Vista, and Windows 7Assign a Hotkey to Open a Terminal Window in UbuntuWhat is ctfmon.exe And Why Is It Running?Keyboard Shortcuts for VMware WorkstationInput Director Controls Multiple Windows Machines with One Keyboard and Mouse TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips VMware Workstation 7 Acronis Online Backup DVDFab 6 Revo Uninstaller Pro MELTUP – "The Beginning Of US Currency Crisis And Hyperinflation" Enable or Disable the Task Manager Using TaskMgrED Explorer++ is a Worthy Windows Explorer Alternative Error Goblin Explains Windows Error Codes Twelve must-have Google Chrome plugins Cool Looking Skins for Windows Media Player 12

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  • Convert YouTube Videos to MP3 with YouTube Downloader

    - by DigitalGeekery
    Are you looking for a way to take the music videos you watch on YouTube and convert them to MP3? Today we take a look at an easy way to convert those YouTube videos to MP3 for free with YouTube Downloader. The YouTube Downloader functions in two steps. First, it downloads the video from YouTube in MP4 format, and then allows you to convert that MP4 file to MP3. Note: It also supports conversion conversion to some other formats such as AVI video, MOV, iPhone, PSP, 3GP, and WMV.   Installation and usage Download and Install YouTube Downloader. (See download link below) Open the YouTube Downloader by clicking on the desktop icon. Find a YouTube video you’d like to convert to MP3 and copy the URL. Paste the URL into the “Enter video URL” text box in YouTube Downloader. When you hover your mouse over the text box, the text box will auto-fill with the URL from your clipboard. Select the “Download video from YouTube” radio button and click “Ok.” Choose a folder to location to download your YouTube video and click “Save.” The video is downloaded in MP4 format. Now wait while the video is downloaded to your hard drive.   Select the “Convert video (previously downloaded) from file” radio button. Click the (…) button to the right of the “Select video file” text box to browse for and select the MP4 file you just downloaded. Then select “MPEG Audio Layer (MP3) from the “Convert to” drop down list. Select “OK” to begin the conversion. Choose the conversion quality by moving the slider to the right or left. The options are: Low (96kbps bite rate), Medium (128kbps bit rate), Optimal (192kbps bit rate), and High 256kbps bit rate). Here you can select the output volume as well. Click “OK” when finished. If there is a portion of the beginning or end of the video that you wish to cut out of the MP3, select the “Cut video” check box and choose a Start and End time. Click “OK” when finished. Note: The start and end time represent the audio portion of the MP3 you wish to keep. All portions before and after these times will be cut.   The conversion process will begin and should only take a few moments. Times will vary depending on the size of the video you’re converting. Conversion was successful! The MP3 you converted will be in the same directory you downloaded the video to. Now you’re ready to listen to your MP3 or import it to your Zune, iTunes, or music library. You may also want to delete the MP4 files after the conversion if you will no longer need them. Conclusion YouTube Downloader features a very simple interface that’s user friendly and easy to use. It comes in handy when you watch videos that look horrible, but the sound quality is good. Or if you just need to hear the audio of something posted and don’t need the video. It also allows you to download from Google Video, MySpace, and others. Download YouTube Downloader Similar Articles Productive Geek Tips Download YouTube Videos with Cheetah YouTube DownloaderWatch YouTube Videos in Cinema Style in FirefoxStop YouTube Videos from Automatically Playing in FirefoxRemove Unsuitable Comments from YouTubeImprove YouTube Video Viewing in Google Chrome TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Windows Media Player 12: Tweak Video & Sound with Playback Enhancements Own a cell phone, or does a cell phone own you? Make your Joomla & Drupal Sites Mobile with OSMOBI Integrate Twitter and Delicious and Make Life Easier Design Your Web Pages Using the Golden Ratio Worldwide Growth of the Internet

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  • “Query cost (relative to the batch)” <> Query cost relative to batch

    - by Dave Ballantyne
    OK, so that is quite a contradictory title, but unfortunately it is true that a common misconception is that the query with the highest percentage relative to batch is the worst performing.  Simply put, it is a lie, or more accurately we dont understand what these figures mean. Consider the two below simple queries: SELECT * FROM Person.BusinessEntity JOIN Person.BusinessEntityAddress ON Person.BusinessEntity.BusinessEntityID = Person.BusinessEntityAddress.BusinessEntityID go SELECT * FROM Sales.SalesOrderDetail JOIN Sales.SalesOrderHeader ON Sales.SalesOrderDetail.SalesOrderID = Sales.SalesOrderHeader.SalesOrderID After executing these and looking at the plans, I see this : So, a 13% / 87% split ,  but 13% / 87% of WHAT ? CPU ? Duration ? Reads ? Writes ? or some magical weighted algorithm ?  In a Profiler trace of the two we can find the metrics we are interested in. CPU and duration are well out but what about reads (210 and 1935)? To save you doing the maths, though you are more than welcome to, that’s a 90.2% / 9.8% split.  Close, but no cigar. Lets try a different tact.  Looking at the execution plan the “Estimated Subtree cost” of query 1 is 0.29449 and query 2 its 1.96596.  Again to save you the maths that works out to 13.03% and 86.97%, round those and thats the figures we are after.  But, what is the worrying word there ? “Estimated”.  So these are not “actual”  execution costs,  but what’s the problem in comparing the estimated costs to derive a meaning of “Most Costly”.  Well, in the case of simple queries such as the above , probably not a lot.  In more complicated queries , a fair bit. By modifying the second query to also show the total number of lines on each order SELECT *,COUNT(*) OVER (PARTITION BY Sales.SalesOrderDetail.SalesOrderID) FROM Sales.SalesOrderDetail JOIN Sales.SalesOrderHeader ON Sales.SalesOrderDetail.SalesOrderID = Sales.SalesOrderHeader.SalesOrderID The split in percentages is now 6% / 94% and the profiler metrics are : Even more of a discrepancy. Estimates can be out with actuals for a whole host of reasons,  scalar UDF’s are a particular bug bear of mine and in-fact the cost of a udf call is entirely hidden inside the execution plan.  It always estimates to 0 (well, a very small number). Take for instance the following udf Create Function dbo.udfSumSalesForCustomer(@CustomerId integer) returns money as begin Declare @Sum money Select @Sum= SUM(SalesOrderHeader.TotalDue) from Sales.SalesOrderHeader where CustomerID = @CustomerId return @Sum end If we have two statements , one that fires the udf and another that doesn't: Select CustomerID from Sales.Customer order by CustomerID go Select CustomerID,dbo.udfSumSalesForCustomer(Customer.CustomerID) from Sales.Customer order by CustomerID The costs relative to batch is a 50/50 split, but the has to be an actual cost of firing the udf. Indeed profiler shows us : No where even remotely near 50/50!!!! Moving forward to window framing functionality in SQL Server 2012 the optimizer sees ROWS and RANGE ( see here for their functional differences) as the same ‘cost’ too SELECT SalesOrderDetailID,SalesOrderId, SUM(LineTotal) OVER(PARTITION BY salesorderid ORDER BY Salesorderdetailid RANGE unbounded preceding) from Sales.SalesOrderdetail go SELECT SalesOrderDetailID,SalesOrderId, SUM(LineTotal) OVER(PARTITION BY salesorderid ORDER BY Salesorderdetailid Rows unbounded preceding) from Sales.SalesOrderdetail By now it wont be a great display to show you the Profiler trace reads a *tiny* bit different. So moral of the story, Percentage relative to batch can give a rough ‘finger in the air’ measurement, but dont rely on it as fact.

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