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  • How can I add similar functionality to a number of methods in java?

    - by Roman
    I have a lot of methods for logging, like logSomeAction, logAnotherAction etc. Now I want all these methods make a small pause after printing messages (Thread.sleep). If I do it manually, I would do something like this: //before: public static void logSomeAction () { System.out.println (msg(SOME_ACTION)); } //after: public static void logSomeAction () { System.out.println (msg(SOME_ACTION)); try { Thread.sleep (2000); } catch (InterruptedException ignored) { } } I remember that Java has proxy classes and some other magic-making tools. Is there any way avoid copy-n-pasting N sleep-blocks to N logging methods?

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  • How to raise an error, if the parsed number of a C++ stdlib stream is immediatly followed by a non whitespace character?

    - by Micha Wiedenmann
    In the following example, I didn't expect, that 1.2345foo would be parsed. Since I am reading data files, it is probably better to raise an error and notify the user. Is peek() the correct thing to do here? #include <iostream> #include <sstream> int main() { std::stringstream in("1.2345foo"); double x; in >> x; if (in) { std::cout << "good\n"; } else { std::cout << "bad\n"; } } Output good

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  • How to limit the number of post values on UpdatePanel ?

    - by Aristos
    I have notice that the UpdatePanel post every field included on the form on every trigger. But in most of my cases I use 2-3 UpdatePanels at the same page, and each one is independent. When I click for update the one panel, then my page receive all the input data of the page (ok this is logical) but I won to read only this UpdatePanels data and act according, and not the other panels data. So I see that a lot of traffic is happened this way. So is there a way to say to one UpdatePanel - send only my input data, and not everything found on the page. ? Thank you in advanced.

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  • Using excel, how can I count the number of cells in a column containing the text "true" or "false"?

    - by Jay Elston
    I have a spreadsheet that has a column of cells where each cell contains a single work. I would like to count the occurrences of some words. I can use the COUNTIF function for most words, but if the word is "true" or "false", I get 0. A B 1 apples 2 2 true 0 3 false 0 4 oranges 1 5 apples In the above spreadsheet table, I have these formulas in cells B1, B2, B3 and B4: =COUNTIF(A1:A5,"apples") =COUNTIF(A1:A5,"true") =COUNTIF(A1:A5,"false") =COUNTIF(A1:A5,"oranges) As you can see, I can count apples, but not true or false. I have also tried this: =COUNTIF(A1:A5,TRUE) But that does not work either. Note -- I am using Excel 2007.

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  • How could I pass the float number by value in obj-c?

    - by user313439
    - (void)applicationDidFinishLaunching:(UIApplication *)application{ // Override point for customization after application launch [window makeKeyAndVisible]; [self printFloat:1.3f]; } - (void)printFloat:(float)f { NSLog(@"%f",f); } I passed the "1.3f" to printFloat, but it was the wrong value (in this case, -2.000000) after "f" received. And there is a warning that "AppDelegate may not respond to -printFloat:" Where did I get it wrong? Thanks.

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  • Is there a single query that can update a "sequence number" across multiple groups?

    - by Drarok
    Given a table like below, is there a single-query way to update the table from this: | id | type_id | created_at | sequence | |----|---------|------------|----------| | 1 | 1 | 2010-04-26 | NULL | | 2 | 1 | 2010-04-27 | NULL | | 3 | 2 | 2010-04-28 | NULL | | 4 | 3 | 2010-04-28 | NULL | To this (note that created_at is used for ordering, and sequence is "grouped" by type_id): | id | type_id | created_at | sequence | |----|---------|------------|----------| | 1 | 1 | 2010-04-26 | 1 | | 2 | 1 | 2010-04-27 | 2 | | 3 | 2 | 2010-04-28 | 1 | | 4 | 3 | 2010-04-28 | 1 | I've seen some code before that used an @ variable like the following, that I thought might work: SET @seq = 0; UPDATE `log` SET `sequence` = @seq := @seq + 1 ORDER BY `created_at`; But that obviously doesn't reset the sequence to 1 for each type_id. If there's no single-query way to do this, what's the most efficient way? Data in this table may be deleted, so I'm planning to run a stored procedure after the user is done editing to re-sequence the table.

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  • Write a function int mystrlen(char *s) that returns the number of characters in a string wuthout str

    - by henry
    heres what i did, i just have ne error that i cant figure out. int mystrlen(char string[]) { char string1[LENGHT], string2[LENGHT]; int len1, len2; char newstring[LENGHT*2]; printf("enter first string:\n"); len1 = mystrlen(string1); printf("enter second string:\n"); len2 = mystrlen(string2); if(len1 == EOF || len2 == EOF) exit(1); strcpy(newstring, string1); strcat(newstring, string2); printf("%s\n", newstring); return 0;

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  • linq to xml selection/update

    - by gleasonomicon
    If I have the following xml, how would I use linq to xml blank out the date fields in each video node? I wanted to do it for the purpose of a comparison in a unit test. <?xml version="1.0" encoding="utf-8" standalone="yes" ?> <main> <videos> <video> <id>00000000-0000-0000-0000-000000000000</id> <title>Video Title</title> <videourl>http://sample.com</videourl> <thumbnail>http://sample.com</thumbnail> <dateCreated>2011-01-12T18:54:56.7318386-05:00</dateCreated> <dateModified>2011-02-12T18:54:56.7318386-05:00</dateModified> <Numbers> <Number>28</Number> <Number>78</Number> </Numbers> </video> <video> <id>00000000-0000-0000-0000-000000000000</id> <title>Video Title</title> <videourl>http://sample.com</videourl> <thumbnail>http://sample.com</thumbnail> <dateCreated>2011-01-12T18:54:56.7318386-05:00</dateCreated> <dateModified>2011-02-12T18:54:56.7318386-05:00</dateModified> <Numbers> <Number>28</Number> <Number>78</Number> </Numbers> </video> </videos>

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  • finding the total number of distinct shortest paths between 2 nodes in undirected weighted graph in linear time?

    - by logan
    I was wondering, that if there is a weighted graph G(V,E), and I need to find a single shortest path between any two vertices S and T in it then I could have used the Dijkstras algorithm. but I am not sure how this can be done when we need to find all the distinct shortest paths from S to T. Is it solvable on O(n) time? I had one more question like if we assume that the weights of the edges in the graph can assume values only in certain range lets say 1 <=w(e)<=2 will this effect the time complexity?

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  • How do I use a MySQL subquery to count the number of rows in a foreign table?

    - by James Skidmore
    I have two tables, users and reports. Each user has no, one, or multiple reports associated with it, and the reports table has a user_id field. I have the following query, and I need to add to each row a count of how many reports the user has: SELECT * FROM users LIMIT 1, 10 Do I need to use a subquery, and if so, how can I use it efficently? The reports table has thousands and thousands of rows.

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  • If a Matlab function returns a variable number of values, how can I get all of them as a cellarray,

    - by kaleidomedallion
    I am writing a function to remove some values from a cellarray, like so: function left = remove(cells, item); left = cells{cellfun(@(i) ~isequal(item, i), cells)}; But when I run this, left has only the first value, as the call to cells{} with a logical array returns all of the matching cells as separate values. How do I group these separate return values into a single cellarray? Also, perhaps there is already a way to remove a given item from a cellarray? I could not find it in the documentation.

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  • Is it faster to loop through a Python set of number or a set of letters?

    - by Scott Bartell
    Is it faster to loop through a Python set of numbers or a Python set of letters given that each set is the exact same length and each item within each set is the same length? Why? I would think that there would be a difference because letters have more possible characters [a-zA-Z] than numbers [0-9] and therefor would be more 'random' and likely affect the hashing to some extent. numbers = set([00000,00001,00002,00003,00004,00005, ... 99999]) letters = set(['aaaaa','aaaab','aaaac','aaaad', ... 'aaabZZ']) # this is just an example, it does not actually end here for item in numbers: do_something() for item in letters: do_something() where len(numbers) == len(letters) Update: I am interested in Python's specific hashing algorithm and what happens behind the scenes with this implementation.

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  • Modify a given number to find the required sum?

    - by Gaurav
    A friend of mine sent me this question. I haven't really been able to come up with any kind of algorithm to solve this problem. You are provided with a no. say 123456789 and two operators * and +. Now without changing the sequence of the provided no. and using these operators as many times as you wish, evaluate the given value: eg: given value 2097 Solution: 1+2+345*6+7+8+9 Any ideas on how to approach problems like these?

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  • Should I Use GUID or IDENTITY as Thread Number?

    - by user311509
    offerID is the thread # which represents the thread posted. I see in forums posts are represented by random numbers. Is this achieved by IDENTITY? If not, please advice. nvarchar(max) will carry all kind of texts along with HTML tags. CREATE TABLE Offer ( offerID int IDENTITY (4382,15) PRIMARY KEY, memberID int NOT NULL REFERENCES Member(memberID), title nvarchar(200) NOT NULL, thread nvarchar(max) NOT NULL, . . . );

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  • Grouping date periods (by number of days) but exclude the weekends?

    - by tonyyeb
    I have a table with start and end dates in. My goal is to have a table that has grouped these dates into how many days the period spans. I thought I had the solution with a simple SQL statement (MS SQL Server 2005) but I want to exclude weekends. SELECT DATEDIFF(D, StartDate, EndDate)+1 AS Days, COUNT(ID) as Count FROM myDateTable GROUP BY DATEDIFF(D, StartDate, EndDate) This gives a record set of: Days Count 1 4 2 2 4 1 7 2 Is this possible to exclude the weekends in the SQL statement and if not can it be done using ASP and a array perhaps?

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  • What's a good way to add a large number of small floats together?

    - by splicer
    Say you have 100000000 32-bit floating point values in an array, and each of these floats has a value between 0.0 and 1.0. If you tried to sum them all up like this result = 0.0; for (i = 0; i < 100000000; i++) { result += array[i]; } you'd run into problems as result gets much larger than 1.0. So what are some of the ways to more accurately perform the summation?

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  • how to represent negative number to array of integers ?

    - by stdnoit
    I must convert string of 1324312321 to array of integers in java this is fine. I could use integer parseint and string substring method but how do I repesent -12312312 to my original array of integer.. the fact that - is a char / string and convert to array of integer would alter the value ( even though I convert - to integer-equivalent , it would change the rest of 12312312) it must be an array of integers and how should I convert negative numbers and still keeep the same value somehow reminding me of two complements trick but i dont think i need to go down to binary level in my program.. any other trick for doing this? thanks!

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  • jQuery memory game: if $('.opened').length; == number run function.

    - by Carl Papworth
    So I'm trying to change the a.heart when there is td.opened == 24. I'm not sure what's going wrong though since nothings happening. HTML: <body> <header> <div id="headerTitle"><a href="index.html">&lt;html<span class="heart">&hearts;</span>ve&gt;</a> </div> <div id="help"> <h2>?</h2> <div id="helpInfo"> <p>How many tiles are there? Let's see [calculating] 25...</p> </div> </div> </header> <div id="reward"> <div id="rewardContainer"> <div id="rewardBG" class="heart">&hearts; </div> <p>OMG, this must be luv<br><a href="index.html" class="exit">x</a></p> </div> </div> <div id="pageWrap"> <div id="mainContent"> <!-- DON'T BE A CHEATER !--> <table id="memory"> <tr> <td class="pair1"><a>&Psi;</a></td> <td class="pair2"><a>&para;</a></td> <td class="pair3"><a>&Xi;</a></td> <td class="pair1"><a>&Psi;</a></td> <td class="pair4"><a >&otimes;</a></td> </tr> <tr> <td class="pair5"><a>&spades;</a></td> <td class="pair6"><a >&Phi;</a></td> <td class="pair7"><a>&sect;</a></td> <td class="pair8"><a>&clubs;</a></td> <td class="pair4"><a>&otimes;</a></td> </tr> <tr> <td class="pair9"><a>&Omega;</a></td> <td class="pair2"><a>&para;</a></td> <td id="goal"> <a href="#reward" class="heart">&hearts;</a> </td> <td class="pair10"><a>&copy;</a></td> <td class="pair9"><a>&Omega;</a></td> </tr> <tr> <td class="pair11"><a>&there4;</a></td> <td class="pair8"><a>&clubs;</a></td> <td class="pair12"><a>&dagger;</a></td> <td class="pair6"><a>&Phi;</a></td> <td class="pair11"><a>&there4;</a></td> </tr> <tr> <td><a class="pair12">&dagger;</a></td> <td><a class="pair5">&spades;</a></td> <td><a class="pair10">&copy;</a></td> <td><a class="pair3">&Xi;</a></td> <td><a class="pair7">&sect;</a></td> </tr> </table> <!-- DON'T BE A CHEATER !--> </div> </div> <!-- END Page Wrap --> <footer> <div class="heartCollection"> <p>collect us if u need luv:<p> <ul> <li><a id="collection1">&hearts;</a></li> <li><a id="collection2">&hearts;</a></li> <li><a id="collection3">&hearts;</a></li> <li><a id="collection4">&hearts;</a></li> <li><a id="collection5">&hearts;</a></li> <li><a id="collection6">&hearts;</a></li> </ul> </div> <div class="credits">with love from Popm0uth ©2012</div> </footer> </body> </html> Javascript: var thisCard = $(this).text(); var activeCard = $('.active').text(); var openedCards = $('.opened').length; $(document).ready(function() { $('a.heart').css('color', '#CCCCCC'); $('a.heart').off('click'); function reset(){ $('td').removeClass('opened'); $('a').removeClass('visible'); $('td').removeClass('active'); }; $('td').click(openCard); function openCard(){ $(this).addClass('opened'); $(this).find('a').addClass('visible'); if ($(".active")[0]){ if ($(this).text() != $('.active').text()) { setTimeout(function(){ reset(); }, 1000); } else { $('.active').removeClass('active'); } } else { $(this).addClass("active"); } if (openedCards == 24){ $(".active").removeClass("active"); $("a.heart").css('color', '#ff63ff'); $("a.heart").off('click'); } } });

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