Search Results

Search found 3956 results on 159 pages for 'regex cookbook'.

Page 114/159 | < Previous Page | 110 111 112 113 114 115 116 117 118 119 120 121  | Next Page >

  • negative look ahead to exclude html tags

    - by Remoh
    I'm trying to come up with a validation expression to prevent users from entering html or javascript tags into a comment box on a web page. The following works fine for a single line of text: ^(?!.(<|)).$ ..but it won't allow any newline characters because of the dot(.). If I go with something like this: ^(?!.(<|))(.|\s)$ it will allow multiple lines but the expression only matches '<' and '' on the first line. I need it to match any line. This works fine: ^[-_\s\d\w"'.,:;#/&\$\%\?!@+*\()]{0,4000}$ but it's ugly and I'm concerned that it's going to break for some users because it's a multi-lingual application. Any ideas? Thanks!

    Read the article

  • Pulling international street addresses / phone numbers from free-form text

    - by spitzanator
    Hey, folks. I'm looking for some regular expressions to help grab street addresses and phone numbers from free-form text (a la Gmail). Given some text: "John, I went to the store today, and it was awesome! Did you hear that they moved to 500 Green St.? ... Give me a call at +14252425424 when you get a chance." I'd like to be able to pull out: 500 Green St. (recognized as a street address) +14252425424 (recognized as a phone number) What makes this problem easier is that I don't care about parsing text that gets pulled out. That is, I don't care that Green is the name of the road or that 425 is the area code. I just want to grab strings that "look like" addresses or telephone numbers. Unfortunately, this needs to work internationally, as best as possible. Anyone have any leads? Thanks!

    Read the article

  • How to pull the file name from a url using javascript/jquery?

    - by jim23
    A certain variable might contain a relative path or an absolute path. Either way, I need to be able to pull the filename from the variable: http://www.somesite.com/dir1/dir2/filename.gif /dir1/dir2/filename.gif The directory structure is also arbitrary. So basically given either of the url's above (with arbirtrary directory structure) I need to pull 'filename.gif'. Thanks in advance

    Read the article

  • classic asp comparison of comma seperated lists

    - by Reiwoldt
    Hello, I have two comma seperated lists:- 36,189,47,183,65,50 65, 50, 189, 47 the question is how to compare the two in classic ASP in order to identify and return any values that exist in list 1 but that don't exist in list 2 bearing in mind that associative arrays aren't available. e.g. in the above example I would need the return value to be 36,183 Thanks

    Read the article

  • JavaScript Regex question

    - by Vincent
    All, I have following function to check for invalid symbols entered in a text box and return true or false. How can I modify this function to also check for occurrences like http:// and https:// and ftp:// return false if encountered ? function checkURL(textboxval) { return ! (/[<>()#'"]|""/.test(textboxval)); } Thanks

    Read the article

  • regexp to match string with (comma-separated) number at start and to split into number and rest?

    - by mix
    Given a string such as: 23,234,456 first second third How can I split string this into two parts, where part 1 contains the number at the beginning and part 2 contains the rest---but only if the string STARTS with a number, and the number can be comma-separated or not? In other words, I want two results: 23,234,456 and first second third. If there's a number in that string that isn't part of the first number then it should be in the second result. My best stab at this so far, to grab the number at the beginning, is something like this: ^[0-9]+(,[0-9]{3})* Which seems to grab a comma-separated or non-comma-separated number that starts the line. However, when I run this in the Javascript console I get not only the full number, but also a match on just the last 3 digits with their preceeding ,. (e.g. 23,234,456 and ,456). As for getting the rest into another var I'm having trouble. I tried working with \b, etc., but I think I must be missing something fundamental about grabbing the rest of the line. I'm doing this in Javascript in case it matters. More examples of what to match and what not to match. 2 one two three should return 2 and one two three 2345 one two three should return 2345 and one two three 2 one 2 three should return 2 and one 2 three 2,234 one two 3,000 should return 2,234 and one two 3,000 The space between parts 1 and two could be included in the beginning of part 2.

    Read the article

  • PHP: extract email and name from data file

    - by pi-2r
    I need to extract the name and the e-mail from one data file. the file contains more than 500 lines and I want to extract this two informations almost all the data. I would like to use preg_match_all, but my function doesn't work ... $chaine = " ----------------- 11/21/12 16:06:54 tcp static-qvn-qvt-127041 MAIL [email protected] NAME tata1 ----------------- 11/21/12 16:06:54 tcp static-qvn-qvt-127041 MAIL [email protected] NAME tata2 * ----------------- 11/21/12 16:06:54 tcp static-qvn-qvt-127041 MAIL [email protected] NAME tata3 "; //$chaine =" #76:50#89:1#86:50#49:1#84:22"; $motif="/MAIL([a-z]{2,4}+)NAME([a-z]{2,4}+)/"; preg_match_all($motif,$chaine,$out); $nb=count($out[0]); for($i=0;$i<$nb;$i++) { echo $out[0][$i].'<br/>'; }

    Read the article

  • Regular Expression

    - by equilibrium
    Ohh! this regular expression thing is eating my brain up. I have been reading it from Introduction to Automata Theory, Languages and Computer by Hopcroft, Motwani and Ullman. I have solved a few exercises too but could not solve the following even after trying for almost one hr. The problem is to write a regular expression that defines a language consisting of all strings of 0s and 1s except the substring 011. Is the answer (0+1)* - 011 correct ? If not what should be the correct answer for this?

    Read the article

  • asp.net regular expression not working as expected

    - by Zaps
    Hi, I have a textbox and a regular expression validator applied to it. I want to make sure that the only allowed string inputted into the textbox are "Anything Entered" or "Something Else" or "Another String" otherwise I want an error to be displayed. This is the regular expression I have so far: ValidationExpression="(^Anything Entered)$|(^Something Else)$ |(^Another String)$" However when I enter the supposed valid strings the error is displayed. I cant figure out whats wrong with the expression. Any help would be greatly appreciated. Thanks, Zaps

    Read the article

  • How do I .MatchCase and .WholeWord?

    - by Tanner
    Hello, Ive been making a find, find next function for my richtextbox, so I have these check boxes to let the user search by whole word or case sensitive or both, and I got the first two, to work but I can't get it to work with both case a whole word checked, here's my code: if (isWhole == true && isCase == true) { string searchText = Form2.text; this.Focus(); richTextBox1.Focus(); findPos = richTextBox1.Find(searchText,findPos,richTextBox1.Text.Length, RichTextBoxFinds.WhatGoesHere?); richTextBox1.Select(findPos, searchText.Length); findPos += searchText.Length; } But there's no option for wholeword and matchcase so is there any way to do this with .Find()?

    Read the article

  • A regular expression question

    - by Hellnar
    Hello, I am in dire need of a such regular expression where my alphabet is made up of 0s and 1s. Now I need a language that accepts all words as long as it has three 0s. IE: 000 10001 0001 1000 10000101

    Read the article

  • How to using String.split in this case?

    - by hoang nguyen
    I want to write a fuction like that: - Input: "1" -> return : "1" - Input: "12" -> return : ["1","2"] If I use the function split(): String.valueOf("12").split("") -> ["","1","2"] But, I only want to get the result: ["1","2"]. What the best way to do this? Infact, I can do that: private List<String> decomposeQuantity(final int quantity) { LinkedList<String> list = new LinkedList<String>(); int parsedQuantity = quantity; while (parsedQuantity > 0) { list.push(String.valueOf(parsedQuantity % 10)); parsedQuantity = parsedQuantity / 10; } return list; } But, I want to use split() for having an affective code

    Read the article

  • Split a string by comma, quote and full-stop.. with a few exceptions

    - by dunc
    I've got a lot of text, similar to the following paragraph, which I'd like to split into words without punctuation (', ", ,, ., newline etc).. with a few exceptions. Initially considered endemic to the Chalakudy River system in Kerala state, southern India, but now recognised to have a wider distribution in surrounding drainages including the Periyar, Manimala, and Pamba river though the Manimala data may be questionable given it seems to be the type locality of P. denisonii. In the Achankovil River basin it occurs sympatrically, and sometimes syntopically, with P. denisonii. Wild stocks may have dwindled by as much as 50% in the last 15 years or so with collection for the aquarium trade largely held responsible although habitats are also being degraded by pollution from agricultural and domestic sources, plus destructive fishing methods involving explosives or organic toxins. The text refers to P. denisonii which is a species of fish. It's an abbreviation of Genus species. I would like this reference to be one word. So, for instance, this is the kind of array I'd like to see: Array ( ... [44] given [45] it [46] seems [47] to [48] be [49] the [50] type [51] locality [52] of [53] P. denisonii [54] In [55] the ... ) The only things that distinguish these species references such as P. denisonii from a new sentence like end. New are: The P (for Puntius, as in the P. in the aforementioned example) is only ever one letter, always a capital the d (as in . denisonii) is always either a lower case letter or an apostrophe (') What regexp can I use with preg_split to give me such an array? I've tried a simple explode( " ", $array ) but it doesn't do the job at all. Thanks in advance,

    Read the article

  • mod_rewrite per-dir redirection returning a 400

    - by Eaterrust
    I moved my images directory to a different folder, and now I want to redirect all images requests from that folder to the new one. I do not have access to the main configuraion file, so I'm doing this in a .htaccess. I tried this, and it works:     RewriteCond %{REQUEST_URI} old_dir/.+.(jpg|png|gif)$     RewriteRule old_dir/(.+[^/]+..+)$ $1 [L,PT] But since they have permanently moved, I want to do a proper redirect, so I added the [R] flag, like this:      %{REQUEST_URI} old_dir/.+.(jpg|png|gif)$     RewriteRule old_dir/(.+[^/]+..+)$ $1 [L,PT,R] But the server gets confused, and returns a 400, so I looked at the log file, and this is what happens:     strip per-dir prefix: C:/wamp/www/natrazyle/old_dir/images/banner.jpg - old_dir/images/banner.jpg     applying pattern 'old_dir/(.+[^/]+..+)$' to uri 'old_dir/images/banner.jpg'     rewrite 'old_dir/images/banner.jpg' - 'images/banner.jpg'     add per-dir prefix: images/banner.jpg - C:/wamp/www/natrazyle/images/banner.jpg     explicitly forcing redirect with http://localhost/C:/wamp/www/natrazyle/images/banner.jpg As you can see, the full local path gets added after localhost I know I'm doing something wrong, I just can't figure it out myself. Any help would be greatly appreciated...

    Read the article

  • what is the regular expression for this

    - by bn
    I want to parse this (adv) much (thanks) I want to eliminate the words and the bracket (adv) but not (thanks) the condition is: inside bracket, and word length inside bracket is 1-5 characters I am using preg_match in PHP Thank You

    Read the article

  • PHP preg_match Math Function

    - by Matt
    I'm writing a script that will allow a user to input a string that is a math statement, to then be evaluated. I however have hit a roadblock. I cannot figure out how, using preg_match, to dissallow statements that have variables in them. Using this, $calc = create_function("", "return (" . $string . ");" ); $calc();, allows users to input a string that will be evaluated, but it crashes whenever something like echo 'foo'; is put in place of the variable $string.

    Read the article

  • document.URL Matching in Javascript

    - by streetparade
    I have a url which looks like this https://test.high.com/people/11111111-name-firstname-_custa/deals/new Now i need to match document.URL if im on that Page if so i will alert a message. The important part is /deals/new How can i match that in Javascript?

    Read the article

  • JQuery if/else statement matching a wildcard css name

    - by Neokoenig
    Hi All, I'm trying to write an if/else statement in jQuery which can change an elements class by matching 'IN' or 'OUT' (in this case). I.e, I have several Divs with class='IN-something' OR class='OUT-something'. The below would work if I new the exact CSS class, but all I'll know is whether it contains 'IN' or 'OUT'. So like this, but works: if ($(jRow).hasClass('IN-*')) {jRow.attr( "class", "OUT-foo" );} else {jRow.attr( "class", "IN-foo");} Ideas? Thanks!

    Read the article

  • Is it possible to use a back reference to specify the number of replications in a regular expression

    - by user307894
    Is it possible to use a back reference to specify the number of replications in a regular expression? foo= 'ADCKAL+2AG.+2AG.+2AG.+2AGGG+.+G+3AGGa4.' The substrings that start with '+[0-9]' followed by '[A-z]{n}.' need to be replaced with simply '+' where the variable n is the digit from earlier in the substring. Can that n be back referenced? For example (doesn't work) '+([0-9])[A-z]{/1}.' is the pattern I want replaced with "+" (that last dot can be any character and represents a quality score) so that foo should come out to ADCKAL++++G.G+. foo = 'ADCKAL+2AG.+2AG.+2AG.+2AGGG^+.+G+3AGGa4.' indelpatt = re.compile('\+([0-9])') while indelpatt.search(foo): indelsize=int(indelpatt.search(foo).group(1)) new_regex = '\+%s[ACGTNacgtn]{%s}.' % (indelsize,indelsize) newpatt=re.compile(new_regex) foo = newpatt.sub("+", foo) I'm probably missing an easier way to parse the string.

    Read the article

  • Validate a string

    - by Activist
    I'm not that good with regular expressions... I need a JavaScript regular expression that will do the following: The string can contain letters (upper and lower case), but not punctuations such as éàïç... The string can contain numbers (0..9) anywhere in the string, except on the first position. The string can contain underscores (_). Valid strings: foo foo1 foo_bar fooBar Invalid strings: 1foo -- number as first character foo bar -- space föo -- punctuation ö Many thanks!

    Read the article

< Previous Page | 110 111 112 113 114 115 116 117 118 119 120 121  | Next Page >