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  • Yahoo! passe en open source Mojito, son framework JavaScript MVC pour les applications Web multiplateformes

    Yahoo! vient de rendre Open Source son framework web Mojito. L'open source attire de plus en plus les entreprises IT. Après Microsoft et Facebook qui ont rendu certains de leurs projets open source en l'espace de quelques semaines, c'est au tour de Yahoo! de suivre le même chemin. La firme a rendu public sous une licence open source Mojito, un framework Web qui rend plus rapide le développement d'applications Web multiplateforme, et notamment mobiles (tout OS). Mojito fait partie d'une série de "cadres applicatifs" JavaScript développé et utilisé en interne,

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  • La croissance du marché de l'open source devrait-elle alarmer les éditeurs de logiciels propriétaires ? En France le marché pèse 2,5 milliards d'Euro

    La montée en popularité de l'open source devrait-elle alarmer les éditeurs de logiciels propriétaires ? En France le marché pèse 2,5 milliards Depuis quelque temps déjà l'open source fait couler beaucoup d'encre dans l'actualité technologique. En France par exemple l'open source a déjà investi tous les grands domaines du système d'information des administrations : environnements serveurs, domaines applicatifs, outils d'ingénierie, solutions de réseaux et sécurité. Des services publiques comme...

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  • Oracle Coding Standards Feature Implementation

    - by Mike Hofer
    Okay, I have reached a sort of an impasse. In my open source project, a .NET-based Oracle database browser, I've implemented a bunch of refactoring tools. So far, so good. The one feature I was really hoping to implement was a big "Global Reformat" that would make the code (scripts, functions, procedures, packages, views, etc.) standards compliant. (I've always been saddened by the lack of decent SQL refactoring tools, and wanted to do something about it.) Unfortunatey, I am discovering, much to my chagrin, that there doesn't seem to be any one widely-used or even "generally accepted" standard for PL-SQL. That kind of puts a crimp on my implementation plans. My search has been fairly exhaustive. I've found lots of conflicting documents, threads and articles and the opinions are fairly diverse. (Comma placement, of all things, seems to generate quite a bit of debate.) So I'm faced with a couple of options: Add a feature that lets the user customize the standard and then reformat the code according to that standard. —OR— Add a feature that lets the user customize the standard and simply generate a violations list like StyleCop does, leaving the SQL untouched. In my mind, the first option saves the end-users a lot of work, but runs the risk of modifying SQL in potentially unwanted ways. The second option runs the risk of generating lots of warnings and doing no work whatsoever. (It'd just be generally annoying.) In either scenario, I still have no standard to go by. What I'd need to know from you guys is kind of poll-ish, but kind of not. If you were going to use a tool of this nature, what parts of your SQL code would you want it to warn you about or fix? Again, I'm just at a loss due to a lack of a cohesive standard. And given that there isn't anything out there that's officially published by Oracle, I think this is something the community could weigh in on. Also, given the way that voting works on SO, the votes would help to establish the popularity of a given "refactoring." P.S. The engine parses SQL into an expression tree so it can robustly analyze the SQL and reformat it. There should be quite a bit that we can do to correct the format of the SQL. But I am thinking that for the first release of the thing, layout is the primary concern. Though it is worth noting that the thing already has refactorings for converting keywords to upper case, and identifiers to lower case.

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  • Can I make Windows to open Excel XML files with Excel without opening Explorer?

    - by Sorin Sbarnea
    I want to be able to open Excel XML files in Excel but without assigning XML directly to Excel. There are lots of XML files that are not Excel files and I don't want to open all of them in Excel. The file has proper header for opening in Excel but currently it does open Internet Explorer that asks me if I want to open the file with Excel, save or cancel. I just want to open it without two another annoying windows.

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  • error: unable to open database file, SQLiteException was unhandled

    - by rose
    My project has a reference to SQLite.Interop.066.dll and even after putting in the correct path to the SQLite database, the application is still unable to find it. A SQLiteException was unhandled is returned. SQLiteConnection conn = new SQLiteConnection(); //SQLiteDataAdapter da; SQLiteCommandBuilder cb; DataTable dt=new DataTable(); int row = 0; conn.ConnectionString = "Data Source=C:\\database\\info"; conn.Open(); DataRow dr = dt.NewRow(); dr["name"] = txtName.Text; dr["address"] = txtAddress.Text; dr["phone"] = txtPhone.Text; dr["position"] = txtPosition.Text; dt.Rows.Add(dr); da.Update(dt); row = dt.Rows.Count - 1; txtName.Text = dt.Rows[row]["name"].ToString(); txtAddress.Text = dt.Rows[row]["address"].ToString(); txtPhone.Text = dt.Rows[row]["phone"].ToString(); txtPosition.Text = dt.Rows[row]["position"].ToString(); da.Fill(dt); cb = new SQLiteCommandBuilder(da); conn.Dispose(); conn.Close(); The exception occur at line: conn.Open(); sorry for the mistake title error before...

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  • Open source Java CMS for Google App Engine?

    - by markvgti
    I am looking for an open source Java CMS (Web CMS, actually) to run on Google App Engine. I have looked at related older questions on this topic (What CMS runs on Google AppEngine?, CMS over Google App Engine, with SEO etc.) but the problem is that they all largely list Python-based CMSes. Plus these questions are pretty old, and since GAE is a fast-moving target, I thought it might be worthwhile to ask again. I want a CMS for creating some websites (for myself and for others), but would rather not start writing one from scratch. A "good" (very subjective, I know) open source WCMS allows me to start using a product, while still being able to add to/extend the product/project. On the one hand I am looking for a somewhat mature product/project, on the other hand it's easier to start contributing to the development cycle of a young product/project (conflicting, I know :-). Here are some features that would be preferable: [X]HTML/XML/CSS based templating Ability to create multiple blogs Galleries Ability to create a "Downloads" section (is this pretty much standard?) Separate management for digital assets (images, PDFs, binary files etc.) Roles like "Administrator", "Editor", "Contributor" etc. (or their equivalents) Ability to move/reorganize pages Export to PDF Reformat content for printing Is the CMS you are about to suggest especially well-suited to publishing an online book? My idea is that while the book may be offered as a downloadable eBook, the latest, most current version will be the one available on the website.

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  • Android - How to Use SQLiteDatabase.open?

    - by Edwin Lee
    Hi all, i'm trying to use SQLiteDatabase.openDatabase( "/data/data/edwin11.myapp/databases/myapp.db", null, (SQLiteDatabase.CREATE_IF_NECESSARY | SQLiteDatabase.NO_LOCALIZED_COLLATORS)); to create/open a database instead of making use of the SQLiteOpenHelper (because i want to pass in the flag SQLiteDatabase.NO_LOCALIZED_COLLATORS. However, i am getting this exception for that line of code: 04-18 09:50:03.585: ERROR/Database(3471): sqlite3_open_v2("/data/data/edwin11.myapp/databases/myapp.db", &handle, 6, NULL) failed 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): java.lang.RuntimeException: An error occured while executing doInBackground() 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): at android.os.AsyncTask$3.done(AsyncTask.java:200) 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:234) 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:258) 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): at java.util.concurrent.FutureTask.run(FutureTask.java:122) 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:648) 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:673) 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): at java.lang.Thread.run(Thread.java:1060) 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): Caused by: android.database.sqlite.SQLiteException: unable to open database file 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): at android.database.sqlite.SQLiteDatabase.dbopen(Native Method) 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): at android.database.sqlite.SQLiteDatabase.<init>(SQLiteDatabase.java:1584) 04-18 09:50:03.665: ERROR/AndroidRuntime(3471): at android.database.sqlite.SQLiteDatabase.openDatabase(SQLiteDatabase.java:638) ... Doing some testing just before that line of code (using File.isExists) shows that the file /data/data/edwin11.myapp/databases/myapp.db does not exist. Would that be the cause of the error? (Or am i just using SQLiteDatabase.openDatabase the wrong way?) Would it help if i create the file beforehand? (Shouldn't that be taken care of by the SQLiteDatabase.CREATE_IF_NECESSARY flag that i passed in?) If creating the file manually is the way to go, is it just an empty file, or do i have to write something to it? Thanks and Regards.

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  • GenerateDSYMFile warning: unable to open object file

    - by regulus6633
    The background: I have a project that I last built on 10.5 on a PPC computer using xcode v3.1. It builds against the 10.4 SDK. I now have a MacBook with 10.6 on it and Xcode v3.2.1. I installed the 10.4 SDK with xcode. So now I want to build the project on an intel chip on 10.6. I first get a build error because I have the wrong version of gcc setup so I change the build settings to use gcc 4.0. The problem: Now when I build the project I get the following warning: GenerateDSYMFile "build/Release/What's Keeping Me?.app.dSYM" "build/Release/What's Keeping Me?.app/Contents/MacOS/What's Keeping Me?" cd "/Users/hmcshane/Development/ Cocoa Projects/What's Keeping Me?" /Developer/usr/bin/dsymutil "/Users/hmcshane/Development/ Cocoa Projects/What's Keeping Me?/build/Release/What's Keeping Me?.app/Contents/MacOS/What's Keeping Me?" -o "/Users/hmcshane/Development/ Cocoa Projects/What's Keeping Me?/build/Release/What's Keeping Me?.app.dSYM" warning: (i386) /Users/hmcshane/Downloads/Csu-71/crt.dynamic_no_pic.o unable to open object file warning: (ppc7400) /Users/hmcshane/Downloads/Csu-71/crt.dynamic_no_pic.o unable to open object file Any idea what this is? And why is the path for the problem files rooted in my downloads folder? The project certainly doesn't reside there.

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  • .net c# cannot find img resources when open with exe

    - by okuryazar
    Hello, My exe processes text documents and I want to be able to right click on documents, select open with and point to my exe file. I can double click on my exe and choose a file to process with OpenFileDialog and it works fine. However, when I do open with, I get FileNotFound error. Here is the error log: System.IO.FileNotFoundException: attention.jpg at System.Drawing.Image.FromFile(String filename, Boolean useEmbeddedColorManagement) at System.Drawing.Image.FromFile(String filename) at ImzaDogrulamaUygulamasi.frmCertificate.FillTreeView() in D:\VSS\SOURCE\VS2008\EGA\ImzaDogrulamaUygulamasi\ImzaDogrulamaUygulamasi\frmCertificate.cs:line 76 at ImzaDogrulamaUygulamasi.frmCertificate.Form2_Load(Object sender, EventArgs e) in D:\VSS\SOURCE\VS2008\EGA\ImzaDogrulamaUygulamasi\ImzaDogrulamaUygulamasi\frmCertificate.cs:line 244 at System.Windows.Forms.Form.OnLoad(EventArgs e) at System.Windows.Forms.Form.OnCreateControl() at System.Windows.Forms.Control.CreateControl(Boolean fIgnoreVisible) at System.Windows.Forms.Control.CreateControl() at System.Windows.Forms.Control.WmShowWindow(Message& m) at System.Windows.Forms.Control.WndProc(Message& m) at System.Windows.Forms.ScrollableControl.WndProc(Message& m) at System.Windows.Forms.ContainerControl.WndProc(Message& m) at System.Windows.Forms.Form.WmShowWindow(Message& m) at System.Windows.Forms.Form.WndProc(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m) and this is how I add my images in my code, all resources are in the same directory with the exe file: ImageList myImageList = new ImageList(); myImageList.Images.Add(Image.FromFile("attention.jpg")); myImageList.Images.Add(Image.FromFile("sandglass.jpg")); myImageList.Images.Add(Image.FromFile("11.JPG")); myImageList.Images.Add(Image.FromFile("checkGif.jpg")); treeView1.ImageList = myImageList; Any help is much appreciated. Thanks

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  • Open XML document ContentControls problem with signed id's

    - by willvv
    I have an application that generates Open XML documents with Content Controls. To create a new Content Control I use Interop and the method ContentControls.Add. This method returns an instance of the added Content Control. I have some logic that saves the id of the Content Control to reference it later, but in some computers I've been having a weird problem. When I access the ID property of the Content Control I just created, it returns a string with the numeric id, the problem is that when this value is too big, after I save the document, if I look through the document.xml in the generated document, the <w:id/> element of the <w:sdtPr/> element has a negative value, that is the signed equivalent of the value I got from the Id property of the generated control. For example: var contentControl = ContentControls.Add(...); var contentControlId = contentControl.ID; // the value of contentControlId is "3440157266" If I save the document and open it in the Package Explorer, the Id of the Content Control is "-854810030" instead of "3440157266". What have I figured out is this: ((int)uint.Parse("3440157266")).ToString() returns "-854810030" Any idea of why this happens? This issue is hard to replicate because I don't control the Id of the generated controls, the Id is automatically generated by the Interop libraries.

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  • MS Access 2003 - Save button enabling on form open on different tabs

    - by Justin
    I have a tab control on a form, and a couple different tabs have save buttons on them. Once the user saves data (via SQL statements in VBA), I set the .enabled = false so that they cannot use this button again until moving to a brand new record (which is a button click on the overall form). so when my form open i was going to reference a sub that enabled all these save buttons because the open event would mean new record. though i get an error that says it either does not exist, or is closed. any ideas? thanks EDIT: Sub Example() error handling Dim db as dao.database dim rs as dao.recordset dim sql as string SQL = "INSERT INTO tblMain (Name, Address, CITY) VALUES (" if not isnull (me.name) then sql = sql & """" & me.name & """," else sql = sql & " NULL," end if if not insull(me.adress) then sql = sql & " """ & me.address & """," else sql = sql & " NULL," end if if not isnull(me.city) then sql = sql & " """ & me.city & """," else sql = sql & " NULL," end if 'debug.print(sql) set db = currentdb db.execute (sql) MsgBox "Changes were successfully saved" me.MyTabCtl.Pages.Item("SecondPage").setfocus me.cmdSaveInfo.enabled = false and then on then the cmdSave needs to get re enabled on a new record (which by the way, this form is unbound), so it all happens when the form is re-opened. I tried this: Sub Form_Open() me.cmdSaveInfo.enabled = true End Sub and this is where I get the error stated above. So this is also not the tab that has focus when the form opens. Is that why I get this error? I cannot enable or disable a control when the tab is not showing?

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  • XMLHttpRequest open() returning access denied

    - by rjovic
    Hi! I have problem with xhr open() method. My code follows : var xmlhttp=false; if(!xmlhttp) try { xmlhttp=new XMLHttpRequest(); } catch(e) { xmlhttp=false; } function returnPage(url) { if(!xmlhttp) return alert("Your browser doesn't seem to support XMLHttpRequests."); xmlhttp.open("GET",url,true); xmlhttp.onreadystatechange=function() { if(xmlhttp.readyState!=4) return; if(!xmlhttp.status||xmlhttp.status==200) alert(xmlhttp.responseText); else alert("Request failed!"); }; //onreadystatechange xmlhttp.send(null); } Call : <a href='#' onclick="returnPage('http://www.something.com'); return false;">Link 1</a></p> I'm using IE8 (because I'm building web slice) and I received error "Access denied". I found on the Internet that problem is that XHR isn't working across different domains, but I used code from Firefox Add-on which is working OK. And that add-on and "my" code (which are the same) are calling the same page. How that add-on have access and my code not?

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  • Reading data from an open HTTP stream

    - by allenjones
    Hi, I am trying to use the .NET WebRequest/WebResponse classes to access the Twitter streaming API here "http://stream.twitter.com/spritzer.json". I need to be able to open the connection and read data incrementally from the open connection. Currently, when I call WebRequest.GetResponse method, it blocks until the entire response is downloaded. I know there is a BeginGetResponse method, but this will just do the same thing on a background thread. I need to get access to the response stream while the download is still happening. This just does not seem possible to me with these classes. There is a specific comment about this in the Twitter documentation: "Please note that some HTTP client libraries only return the response body after the connection has been closed by the server. These clients will not work for accessing the Streaming API. You must use an HTTP client that will return response data incrementally. Most robust HTTP client libraries will provide this functionality. The Apache HttpClient will handle this use case, for example." They point to the Appache HttpClient, but that doesn't help much because I need to use .NET. Any ideas whether this is possible with WebRequest/WebResponse, or do I have to go for lower level networking classes? Maybe there are other libraries that will allow me to do this? Thx Allen

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  • Creating an application that can open files of a given format

    - by Brian Postow
    I've got an app, written in Obj-C. The info.plist has a list of file types that the app can open. I'm pretty sure that this is working because when I try to drag a file of an unacceptable type, the app doesn't highlight, but when I drag a file of an acceptable type, it does highlight, and lets me drop. When I drop, the app starts up, correctly, however, then I get a dialog saying: The document "foo.tiff" could not be opened. DocView cannot open files in the "TIFF File" format. I DO have this in my info.plist <key>CFBundleTypeExtensions</key> <array> <string>tif</string> <string>tiff</string> </array> <key>CFBundleTypeIconFile</key> <string>TIFFFile.icns</string> <key>CFBundleTypeName</key> <string>TIFF File</string> <key>CFBundleTypeOSTypes</key> <array> <string>TIFF</string> </array> <key>CFBundleTypeRole</key> <string>Viewer</string> <key>LSHandlerRank</key> <string>Documents/</string> Thanks.

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  • C system calls open / read / write / close problem.

    - by Andrei Ciobanu
    Hello, given the following code (it's supposed to write "hellowolrd" in a "helloworld" file, and then read the text): #include <fcntl.h> #include <sys/types.h> #include <sys/stat.h> #define FNAME "helloworld" int main(){ int filedes, nbytes; char buf[128]; /* Creates a file */ if((filedes=open(FNAME, O_CREAT | O_EXCL | O_WRONLY | O_APPEND, S_IRUSR | S_IWUSR)) == -1){ write(2, "Error1\n", 7); } /* Writes hellow world to file */ if(write(filedes, FNAME, 10) != 10) write(2, "Error2\n", 7); /* Close file */ close(filedes); if((filedes = open(FNAME, O_RDONLY))==-1) write(2, "Error3\n", 7); /* Prints file contents on screen */ if((nbytes=read(filedes, buf, 128)) == -1) write(2, "Error4\n", 7); if(write(1, buf, nbytes) != nbytes) write(2, "Error5\n", 7); /* Close rile afte read */ close(filedes); return (0); } The first time i run the program, the output is: helloworld After that every time I to run the program, the output is: Error1 Error2 helloworld I don't understand why the text isn't appended, as I've specified the O_APPEND file. Is it because I've included O_CREAT ? It the file is already created, shouldn't O_CREAT be ignored ?

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  • Passing a parameter in a Report's Open Event to a parameter query (Access 2007)

    - by JPM
    Hi there, I would like to know if there is a way to set the parameters in an Access 2007 query using VBA. I am new to using VBA in Access, and I have been tasked with adding a little piece of functionality to an existing app. The issue I am having is that the same report can be called in two different places in the application. The first being on a command button on a data entry form, the other from a switchboard button. The report itself is based on a parameter query that has requires the user to enter a Supplier ID. The user would like to not have to enter the Supplier ID on the data entry form (since the form displays the Supplier ID already), but from the switchboard, they would like to be prompted to enter a Supplier ID. Where I am stuck is how to call the report's query (in the report's open event) and pass the SupplierID from the form as the parameter. I have been trying for a while, and I can't get anything to work correctly. Here is my code so far, but I am obviously stumped. Private Sub Report_Open(Cancel As Integer) Dim intSupplierCode As Integer 'Check to see if the data entry form is open If CurrentProject.AllForms("frmExample").IsLoaded = True Then 'Retrieve the SupplierID from the data entry form intSupplierCode = Forms![frmExample]![SupplierID] 'Call the parameter query passing the SupplierID???? DoCmd.OpenQuery "qryParams" Else 'Execute the parameter query as normal DoCmd.OpenQuery "qryParams"????? End If End Sub I've tried Me.SupplierID = intSupplierCode, and although it compiles, it bombs when I run it. And here is my SQL code for the parameter query: PARAMETERS [Enter Supplier] Long; SELECT Suppliers.SupplierID, Suppliers.CompanyName, Suppliers.ContactName, Suppliers.ContactTitle FROM Suppliers WHERE (((Suppliers.SupplierID)=[Enter Supplier])); I know there are ways around this problem (and probably an easy way as well) but like I said, my lack of experience using Access and VBA makes things difficult. If any of you could help, that would be great!

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  • jquery ui dialog in asp.net mvc3 doesn't open on second time

    - by giri
    when i click the New Trade button in the form it opens jquery ui dialog. but, i have link button in the gridview when i click the link button it should open jquery ui dialog, it opens jquery ui dialog before clicking the new trade button. but, after clicking the new trade button, if i click link button in the gridview it invoke "ViewTradeDialog(id)" function, the dialog doesn't open, it shows error message "$vwdia.html(data).dialog is not a function". my code follows: @using (Html.BeginForm("NewTrade", "Trade", FormMethod.Post, new { id = "searchForm" })) { <div id="searchbtn"> <input id="btn_newtrade" type="submit" value="New Trade" /> </div> } jquery code <script type="text/javascript"> $(function () { var $loading = $('<img src="../../loading.gif" alt="loading">'); var $dialog = $('<div></div>').append($loading); $('#searchForm').submit(function (e) { var url = this.action; $.ajax({ autoOpen: false, url: url, success: function (data) { $dialog.html(data).dialog({ zIndex:1, width: 1400, height: 600, resizable: false, title: 'New Trade Details', modal: true, buttons: { "close": function () { $dialog.dialog('close'); }, "Add Trade": function () { $dialog.dialog('close'); $.ajax({ type: 'POST', url: url }); } } }); } }); return false; }); }); function ViewTradeDialog(id) { alert(id); var $vwdia = $('<div></div>'); var url = '/Trade/ViewTrades?tradeid=' + id; $.ajax({ url: url, success: function (data) { $vwdia.html(data).dialog({ width: 600, height: 600, resizable: false, title: 'View Trade Details', modal: false, buttons: { "close": function () { $vwdia.dialog('close'); } } }); } }); return false; }

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  • open current page in new window including query string

    - by Hatch
    First of all, I am a total dud at all things related to web developement, so please bear with me here. I suspect this question is laughable for the web guys, but unfortunately I can't figure this out. Here goes: I have an application, that does some processing, writes some result files and then displays the results in an embedded IE browser control. This is done by navigating the browser control to a local html file together with a query string containing the generated result files to display it all. The link target would look something like: c:\SomeFolder\results.htm?results=file%201.xml;file%202.xml;file%203.xml So far, everything's fine. However, in the html page is a href that is suppossed to open up the exact same just in a normal browser window. What I thought would work is: <a href="#" target="_blank">Show in browser</a> Since it is a link in an html page displayed in an IE control, the link will open up in IE no matter what the default browser might be. This works for IE7 and 8, but not for IE6. With IE6 the query string gets cut off and the browser opens file://c:/results/results.htm# without the query string. I am sure there must be a much better way to do this without the # and which would work in all IEs. How would the pros solve this?

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  • Open + Save .exe file in notepad makes it corrupted

    - by Jacob Kofoed
    Hi, I just published this simple console application that is supposed to show a textbox with the value of a setting called "userID" with value 1001. This works like a charm. Now what I need is to change this value outside the editor, from notepad etc. When I open the application a lot in there is non-sence (& o! -å Þþþ,o" Ü+) etc. but with a quick (ctrl + F) I found the value 1001, and changed this to some other integer. I ran the application again, and it failed, didn't even give any userful error-message. At a point I tried just opening a newly published non-corrupted version of the application, didn't change anything, then saved from notepad, and it were also corrupted. It seems like notepad can't open some characters or something. Do I need to publish the application in some specific text-unicode language or something? Help much appreciated :) I know it sounds like a stupid application, but it is just a test of concept :) I use vb.net for this

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  • Javascript document.open asynchronous?

    - by Alex Schneider
    So on my site there is a Javascript function that will load a new site from the server via XMLHttpRequest. After that it replaces the current page with the new one: var post = new XMLHttpRequest(); post.open('POST', data); post.onload = function() { var do = document.open("text/html", "replace"); do.write(post.responseText); do.close(); goOn(); } function goOn() { console.log($('img:visible')); } Some could assume that after do.close() the document has changed and is ready. But it is not, e.g. if i load very much/big data/responseText the function goOn() only logs an empty result. Obviously goOn() gets in that case called before the DOM is ready to be read! Unfortunately the is no "ready" event fired after write() finished.... How can i be sure it is finished? /EDIT: goOn() logs this to Chrome Console: [prevObject: p.fn.p.init[1], context: #document, selector: "img:visible"] context: #document length: 0 prevObject: p.fn.p.init[1] selector: "img:visible" __proto__: Object[0] But if i right after that type $('img:visible') into console manually it shows me all images....

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  • fopen() fails to open stream: permission denied, yet permissions should be valid

    - by about blank
    So, I have this error: Warning: fopen(/path/to/test-in.txt) [function.fopen]: failed to open stream: Permission denied Performing ls -l in the directory where test-in.txt is produces the following output: -rw-r--r-- 1 $USER $USER 1921 Sep 6 20:09 test-in.txt -rw-r--r-- 1 $USER $USER 0 Sep 6 20:08 test-out.txt In order to get past this, I decided to perform the following: chgrp -R www-data /path/to/php/webroot And then did: chmod g+rw /path/to/php/webroot Yet, I still get this error when I run my php5 script to open the file. Why is this happening? I've tried this using LAMP as well as cherokee through CGI, so it can't be this. Is there a solution of some sort? Edit I'll also add that I'm just developing via localhost right now. Update - PHP fopen() line $fullpath = $this->fileRoot . $this->fileInData['fileName']; $file_ptr = fopen( $fullpath, 'r+' ); I should also mention I'd like to stick with Cherokee if possible. What's this deal about setting file permissions for Apache/Cherokee?

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  • accordion tab open at different times

    - by user3279193
    I am using an asp classic and on the page I have a J-Query accordion. I want one tab to be open if the value that the asp prints out is greater than zero, if not , I want them all to be closed, this is an example of what I've got: J-Query: $(function() { $( "#accordion" ).accordion({ heightStyle: "content", collapsible: true, active: false }); }); HTML/ASP: <div id="accordion"> <h3>Tab1</h3> <div> <p>Hello World</p> </div> <h3>Tab2</h3> <div> <p>Hello World</p> </div> <h3>Tab3</h3> <div> <p>Hello World</p> </div> <h3>Results (<%=number%>)</h3> <!--if number > 0 then open tab else close all tabs--> <div> <p>Hello World</p> </div> </div>

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  • Response Redirect - Open Link in New Window

    - by bacis09
    First, I've taken the time to review this question which seems to be the most similar, however, the solution that seems to have been selected will not work in my scenario.Not to mention I worry about some of the comments claiming it to be brittle or an inadequate solution. http://stackoverflow.com/questions/104601/asp-net-response-redirect-to-new-window -We have an XML document which basically contains all of the information for a Side menu. -We have numerous URLS which are stored in a constants class. -One of the elements in a string of XML (well call it label) is used to determine if the menu item is created as a LinkButton or a Label. -Links use a custom user control that is used standard for all links across the application (why suggestion on similar thread doesn't work - I don't want all links to open in a new window - just one) -One of the elements in a string of XML (well call it function) is used in a Switch statement to generate our links using Response Redirect. It may look something like this. switch (function) { case goto 1: string url; if (user_group == 1) { url = Constants.CONSTANT1 } else { url = Constants.CONSTANT2 } Response.Redirect(url) case goto 2: ...... default: ...... break; } Given this scenario, I'm trying to find the best way to quickly open a New Window, when a specific case in this switch statement is met. Can it be done with Response Redirect (this seems to be arguable - people say no it can't, yet other people say they have made it work)? If not, what alternative can work here?

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  • Changing/Adding controls to the windows Open/Save common dialog

    - by ajp
    Is there a way of changing/adding to the windows Open/Save common dialog to add extra functionality? At work we have an area on a server with hundreds of 'jobfolders'- just ordinary windows folders created/managed automatically by the database application to house information about a job (emails/scanned faxes/Word docs/Spreadsheets/Photos etc) The folders are named by the job Number. I would like to expand the standard open/save dialog with a combobox which searches for jobfolders based on tags from the database, so that whatever my users are doing they can easily find their way to the correct jobfolder to find/save their work Connecting to the database and providing the functionality to search is no problem, but is there a way to add a combobox control (ideally with a keypress/keydown event) to the dialog? Or Create my own dialog and have it called/used in place of the standard one? i.e. from ANY app my dialog would be called allowing easy access to the jobfolders. If they are in outlook they can find a jobfolder quickly, if there are using Notepad they can still find the folder easily. This would mean a new unified way of finding jobfolders from any app. Ideally someone would know a way using VB/VB.net/C# but I'm guessing, if its possible, its probably going to be C++.

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  • Python server open all ports

    - by user1670178
    I am trying to open all ports using this code, why can I not create a loop to perform this function? http://www.kellbot.com/2010/02/tutorial-writing-a-tcp-server-in-python/ #!/usr/bin/python # This is server.py file ##server.py from socket import * #import the socket library n=1025 while n<1050: ##let's set up some constants HOST = '' #we are the host PORT = n #arbitrary port not currently in use ADDR = (HOST,PORT) #we need a tuple for the address BUFSIZE = 4096 #reasonably sized buffer for data ## now we create a new socket object (serv) ## see the python docs for more information on the socket types/flags serv = socket( AF_INET,SOCK_STREAM) ##bind our socket to the address serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow serv = socket( AF_INET,SOCK_STREAM) ##bind our socket to the address serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow print 'listening...' n=n+1 conn,addr = serv.accept() #accept the connection print '...connected!' conn.send('TEST') conn.close() How do I make this work so that I can specify input range and have the server open all ports up to 65535? #!/usr/bin/python # This is server.py file from socket import * #import the socket library startingPort=input("\nPlease enter starting port: ") startingPort=int(startingPort) #print startingPort def connection(): ## let's set up some constants HOST = '' #we are the host PORT = startingPort #arbitrary port not currently in use ADDR = (HOST,PORT) #we need a tuple for the address BUFSIZE = 4096 #reasonably sized buffer for data def socketObject(): ## now we create a new socket object (serv) serv = socket( AF_INET,SOCK_STREAM) def bind(): ## bind our socket to the address serv = socket( AF_INET,SOCK_STREAM) serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow serv = socket( AF_INET,SOCK_STREAM) print 'listening...' def accept(): conn,addr = serv.accept() #accept the connection print '...connected!' conn.send('TEST') def close(): conn.close() ## Main while startingPort<65535: connection() socketObject() bind() accept() startingPort=startingPort+1

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