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  • ISAPI_Rewrite: Zend PHP Framework project setup

    - by Yaw Reuben
    How do I go about getting the isapi_rewrite working on IIS 6.0? My shared hosting account supports ISAPI_Rewrite - I've run the provided tests to confirm. I'm only able to access the index page of my Zend PHP project, but get the 404 error for other actions in my index controller class definition. I've basically placed the code: [ISAPI_Rewrite] RepeatLimit 20 RewriteRule (?!\.(js|ico|gif|jpg|png|css|swf))$ index.php in an httpd.ini access file in my wwwroot directory. Is there anything I'm missing?

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  • Why isnt php reading my cookie?

    - by Jason94
    at index.php i have a form to fill out some settings. the form posts to setsettings.php at setsettings.php it uses the form data and sets some cookies and redirect back to index.php. if i print_r($_COOKIE) at setsettings.php all is well. but nothing comes up at index.php, the $_COOKIE array is empty :( Does somebody know how i go about solving this? I set det setting by (setsettings.php): /* Write new cookie */ $expire = 60 * 60 * 24 * 60 + time(); // ~2 months setcookie("user_var_001", $_POST['selection'], $expire); and in index.php print_r($_COOKIE) turns up blank;

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  • How to have multiple paths display URL as root

    - by Verdi Erel Ergün
    I want users#new and tasks#index to display as the root path URL, i.e. / When a user logs in on the path users#new (set as root) they are redirected to tasks#index and URL does not change. Can this be done in the routes.rb file? This is my routes.rb file: Todo::Application.routes.draw do resources :sessions resources :subscriptions resources :users resources :tasks do collection do post :sort end end root :to => "users#new" match "sessions#new" => "tasks#index" match "sessions#" => "tasks#index"

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  • function and class to show image not working in php

    - by Gully
    i am trying to get get the following working nothing is happen when i use the function i am trying to get it to display images class ItemRes { //items DB var $img=""; } function ShowItemImage($index,$res_a){ if(sizeof($res_a) > $index){ if($res_a[$index] != NULL) { $cimg = $res_a[$index]->img; return "<img src='$cimg' width='70' height='70' style='cursor:pointer'></img>"; } }else{ return "<center class='whitetxt'><strong>Empty</strong></center>"; } } $res_array = array(); $idx=0; $result21 = mysql_query("SELECT * FROM photos WHERE eid='$eid' ORDER BY id DESC") or die (mysql_error()); while ($row21 = mysql_fetch_array($result21)) { $img_path = $row21['path']; $obj = new ItemRes(); $obj->img = $img_path; $res_array[$idx] = $obj; $idx++; } ShowItemImage(0,$res_array) ShowItemImage(1,$res_array)

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  • Find next lower item in a sorted list

    - by Sebastian
    Hey guys, let's say I have a sorted list of Floats. Now I'd like to get the index of the next lower item of a given value. The usual for-loop aprroach has a complexity of O(n). Since the list is sorted there must be a way to get the index with O(log n). My O(n) approach: index=0 for i,value in enumerate(mylist): if value>compareValue: index=i-1 Is there a datatype for solving that problem in O(log n)? best regards Sebastian

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  • RewriteRule being greedy

    - by lardlad
    I have been looking for an answer for a few hours now, so sorry if this was asked a ton of times, I missed it. I basically want to make a rewrite to ignore the first directory. That first dir in the path will be different so I thought I could use a regex. But my regex is matching all the way to the file name: RewriteRule ^([a-z]+)?/(.+)$ $2 [L] this works if I am one level deep: http://test.domain.com/one/index.php I get the actual index page of the root. Which is what I want. but if I were to go deeper: http://test.domain.com/one/two/index.php I get a message saying /index.php was not found. So it seems my regex is not stopping after the last [a-z]. I appreciate any help. This is Apache2 if that matters at all.

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  • virtual directory for php app

    - by Tom
    I created a virtual directory for my php app. Now I get the "Directory Listing Denied This Virtual Directory does not allow contents to be listed." Do I need to make some kind of dummy index.asp file that redirects (OR PREFERRED: just displays index.php) or how to solve this? I have restricted access to webserver, but index.php is set to be default

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  • Ruby: Why is Array.sort slow for large objects?

    - by David Waller
    A colleague needed to sort an array of ActiveRecord objects in a Rails app. He tried the obvious Array.sort! but it seemed surprisingly slow, taking 32s for an array of 3700 objects. So just in case it was these big fat objects slowing things down, he reimplemented the sort by sorting an array of small objects, then reordering the original array of ActiveRecord objects to match - as shown in the code below. Tada! The sort now takes 700ms. That really surprised me. Does Ruby's sort method end up copying objects about the place rather than just references? He's using Ruby 1.8.6/7. def self.sort_events(events) event_sorters = Array.new(events.length) {|i| EventSorter.new(i, events[i])} event_sorters.sort! event_sorters.collect {|es| events[es.index]} end private # Class used by sort_events class EventSorter attr_reader :sqn attr_reader :time attr_reader :index def initialize(index, event) @index = index @sqn = event.sqn @time = event.time end def <=>(b) @time != b.time ? @time <=> b.time : @sqn <=> b.sqn end end

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  • How to get methods list in scala

    - by skyde
    In language like python and ruby to ask the language what index-related methods its string class supports (which methods’ names contain the word “index”) you can do “”.methods.sort.grep /index/i And in java List results = new ArrayList(); Method[] methods = String.class.getMethods(); for (int i = 0; i < methods.length; i++) { Method m = methods[i]; if (m.getName().toLowerCase().indexOf(“index”) != -1) { results.add(m.getName()); } } String[] names = (String[]) results.toArray(); Arrays.sort(names); return names; How would you do the same thing in Scala?

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  • ASP.NET MVC Default URL View

    - by Moose Factory
    I'm trying to set the Default URL of my MVC application to a view within an area of my application. The area is called "Common", the controller "Home" and the view "Index". I've tried setting the defaultUrl in the forms section of web.config to "~/Common/Home/Index" with no success. I've also tried mapping a new route in global.asax, thus: routes.MapRoute( "Area", "{area}/{controller}/{action}/{id}", new { area = "Common", controller = "Home", action = "Index", id = "" } ); Again, to no avail.

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  • Java method help

    - by dalton conley
    Ok, so I'm working on a project for a class I'm taking.. simple music library. Now I'm having some issues, the main issue is I'm getting "non-static method cannot be referenced from a static context" Here is a function I have public void addSong() { Scanner scan = new Scanner(System.in); Song temp = new Song(); int index = countFileLines(Main.databaseFile); index = index + 2; temp.index = index; System.out.print("Enter the artist name: "); temp.artist.append(scan.next()); } Now thats in a class file called LibraryFunctions. So I can access it with LibraryFunctions.addSong(); Now I'm trying to run this in my main java file and its giving me the error, I know why the error is happening, but what do I do about it? If I make addSong() a static function then it throws errors at me with the Song temp = new Song() being static. Kind of ironic. Much help is appreciated on this!

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  • CSS layout changes in Internet explorer

    - by user1784103
    My problem: I just coded a website that is styled just fine in chrome and firefox. However in internet explorer(9) it breaks. the gray header background is supposed to be pushed up to the right of the logo block, and the buttons are supposed to be in the dark grey area. I posted my code. I'm no expert at css, any tips would be greatly appreciated. (the second image is displaying the desired result) the html: Website </head> <body> <div class="wrap_overall"> <div class="header"> <a href="http://localhost"> <img class="logo" src="http://localhost/images/logo.png" width="175" height="24" alt="weblogo" /> </a> </div> <div class="headerbg"></div> <!-- nav top highlight --> <div style="background-color:#6c6c6c;margin:9px0px0px;height:1px;width:1020px;z-index:1;"></div> <!-- nav bar --> <div style="background-color:#5a5a5a;height:53px;width:1020px;z-index:1;"></div> <!-- nav bottom frame --> <div style="background-color:#d4e6b6;height:13px;width:1020px;z-index:1;border-top:4px solid #9de629; margin:0px 0px 10px;"></div> <div class="nav_main"> <ul> <li> <a href="http://localhost/button1"> <img src="http://localhost/images/button1.png" width="63" height="18" alt="button1" /> </a> </li> <li> <a href="http://localhost/index.php?page=button2"> <img src="http://localhost/images/button2.png" width="59" height="18" alt="button2" /> </a> </li> <li> <a href="http://localhost/index.php?page=button3"> <img src="http://localhost/images/button3.png" width="62" height="18" alt="button3" /> </a> </li> <li> <a href="http://localhost/index.php?page=button4"> <img src="http://localhost/images/button4.png" width="41" height="18" alt="button4" /> </a> </li> <li> <a href="http://localhost/index.php?page=button5"> <img src="http://localhost/images/button5.png" width="73" height="18" alt="button5" /> </a> </li> </ul> </div> </div> </body> </html> the css: .logo { padding:60px 20px 50px 20px; } body { background-color:#282828; color:#FFFFFF; font-family: Arial, Helvetica, sans-serif; } body a, img{ border-style:none; color:#9de629; text-decoration:none;} body a:visited {color:#9de629;} body a:hover{ color:#FFFFFF; text-decoration:underline;} .wrap_overall { position:relative; width: 1020px; margin:0px auto; } .header { width:216px; height:148px; margin:0px 0px; padding:0px 0px; background-color:#252525; float:left; display:inline; } .headerbg { margin:0px 0px 0px; padding:0px 0px; width:1020px; height:148px; background-color:#c7c7c7; } .nav_main/*holds the buttons*/ { margin:0px 0px 1px 0px; padding:0px 0px 0px 0px; position:absolute; top:148px; left:363px; z-index:2; overflow: hidden; } .nav_main ul { margin:0px 0px 0px 0px; padding:0px 0px 0px 0px; overflow: hidden; } .nav_main ul li { margin:0px 0px 0px 0px; display: inline; float: left; } .nav_main ul li a { outline: none; border:none; margin:0px 0px 0px 0px; margin-right:-10px; height:54px; width:125px; color:#FFFFFF; background-image:url(../images/button.png); text-align:center; display:table-cell; vertical-align:middle; } .nav_main ul li a:hover { background-image:url(../images/buttonlight.png); }

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  • How can I shared controller logic in ASP.NET MVC for 2 controllers, where they are overriden

    - by AbeP
    Hello, I am trying to implement user-friendly URLS, while keeping the existing routes, and was able to do so using the ActionName tag on top of my controller (http://stackoverflow.com/questions/436866/can-you-overload-controller-methods-in-asp-net-mvc) I have 2 controllers: ActionName("UserFriendlyProjectIndex")] public ActionResult Index(string projectName) { ... } public ActionResult Index(long id) { ... } Basically, what I am trying to do is I store the user-friendly URL in the database for each project. If the user enters the URL /Project/TopSecretProject/, the action UserFriendlyProjectIndex gets called. I do a database lookup and if everything checks out, I want to apply the exact same logic that is used in the Index action. I am basically trying to avoid writing duplicate code. I know I can separate the common logic into another method, but I wanted to see if there is a built-in way of doing this in ASP.NET MVC. Any suggestions? I tried the following and I go the View could not be found error message: [ActionName("UserFriendlyProjectIndex")] public ActionResult Index(string projectName) { var filteredProjectName = projectName.EscapeString().Trim(); if (string.IsNullOrEmpty(filteredProjectName)) return RedirectToAction("PageNotFound", "Error"); using (var db = new PIMPEntities()) { var project = db.Project.Where(p => p.UserFriendlyUrl == filteredProjectName).FirstOrDefault(); if (project == null) return RedirectToAction("PageNotFound", "Error"); return View(Index(project.ProjectId)); } } Here's the error message: The view 'UserFriendlyProjectIndex' or its master could not be found. The following locations were searched: ~/Views/Project/UserFriendlyProjectIndex.aspx ~/Views/Project/UserFriendlyProjectIndex.ascx ~/Views/Shared/UserFriendlyProjectIndex.aspx ~/Views/Shared/UserFriendlyProjectIndex.ascx Project\UserFriendlyProjectIndex.spark Shared\UserFriendlyProjectIndex.spark I am using the SparkViewEngine as the view engine and LINQ-to-Entities, if that helps. thank you!

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  • Optimizing an embedded SELECT query in mySQL

    - by Crazy Serb
    Ok, here's a query that I am running right now on a table that has 45,000 records and is 65MB in size... and is just about to get bigger and bigger (so I gotta think of the future performance as well here): SELECT count(payment_id) as signup_count, sum(amount) as signup_amount FROM payments p WHERE tm_completed BETWEEN '2009-05-01' AND '2009-05-30' AND completed > 0 AND tm_completed IS NOT NULL AND member_id NOT IN (SELECT p2.member_id FROM payments p2 WHERE p2.completed=1 AND p2.tm_completed < '2009-05-01' AND p2.tm_completed IS NOT NULL GROUP BY p2.member_id) And as you might or might not imagine - it chokes the mysql server to a standstill... What it does is - it simply pulls the number of new users who signed up, have at least one "completed" payment, tm_completed is not empty (as it is only populated for completed payments), and (the embedded Select) that member has never had a "completed" payment before - meaning he's a new member (just because the system does rebills and whatnot, and this is the only way to sort of differentiate between an existing member who just got rebilled and a new member who got billed for the first time). Now, is there any possible way to optimize this query to use less resources or something, and to stop taking my mysql resources down on their knees...? Am I missing any info to clarify this any further? Let me know... EDIT: Here are the indexes already on that table: PRIMARY PRIMARY 46757 payment_id member_id INDEX 23378 member_id payer_id INDEX 11689 payer_id coupon_id INDEX 1 coupon_id tm_added INDEX 46757 tm_added, product_id tm_completed INDEX 46757 tm_completed, product_id

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  • where do i put html files in my web-app folder for a lift project with maven?

    - by egervari
    I'm new to Lift framework for scala. For some reason, index.html resides in the web-app directory, and when I start up jetty, http://localhost:8080/ will point to that index.html file just fine. However, if I put a login.html file in the same folder as the index.html, and then go http://localhost:8080/login, Lift does not serve the file. Where do I need to put the files to get them register? I am a little lost because the behaviour only seems to work for index.html and nothing else. This is what happens when I view source in Chrome: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html> <body>The Requested URL /login was not found on this server</body> </html>

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  • Rewriterule end slash

    - by Maxime
    Hi, I'm working on a Rewriterule in order to have URLs like these: http://www.myhost.com/var1/var2/ RewriteRule ^(.*)\/(.*)\/$ index.php?var1=$1&var2=$2 [L] What I would like to add is that when someone types myhost.com/var1/var2 (without the end slash), it still goes to the same page. Is there a better way to do it than this? RewriteRule ^(.*)\/(.*)\/$ index.php?band=$1&song=$2 [L] RewriteRule ^(.*)\/(.*)$ index.php?band=$1&song=$2 [L]

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  • Passing get values mangles my urls

    - by SibLiant
    Just upgraded from 1.3 to 2.0.3 and I'm trying to migrate all the changes. I'm noticing that the following line echo $this->Html->link('Quote', array('controller'=>'crm_quotes', 'action'=>'index', $lead['id'].'/'.$crmContact['CrmContact']['id']), null); builds the url "/crm_quotes/index/15/21". When I click the link I'm taken to url: "/crm_quotes/index/15%2F212 so it's replacing the characters with the html # but it's ultimately breaking the link. When I manually edit the URL to the correct one: "/crm_quotes/index/15/21" the page loads. Can someone enlighten me? Should I be using the url function rather than link? I have a lot of pages that need multiple parameters passed in the url. I was using named parameters but after reading some comments by Mark Story I decided to stop the named parameters as he hinted at their possible removal from future versions.

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  • iphone indexed table view problem

    - by steveY
    I have a table view in which I'm using sectionIndexTitlesForTableView to display an index. However, when I scroll the table, the index scrolls with it. This also results in very slow refreshing of the table. Is there something obvious I could be doing wrong? I want the index to remain in place on the right while the table scrolls. This is the code I'm using for the index titles: - (NSArray *)sectionIndexTitlesForTableView:(UITableView *)tableView { NSMutableArray *tempArray = [[NSMutableArray alloc] init]; [tempArray addObject:@"A"]; [tempArray addObject:@"B"]; [tempArray addObject:@"C"]; [tempArray addObject:@"D"]; ... return tempArray; }

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  • asp:SqlDataSource binded to asp:DropDownList

    - by _simon_
    I have a asp:SqlDataSource and asp:DropDownList components on my page. On normal page it works ok. Now I'd like to put this on new page with url like ...mypage.aspx?transactionID=2. In Page_Load I would like to set Transaction drop down selected index to 2. But it always binds to 1. I assume, that things happen in this order: in Page_Load I set selected index to 2. Then asp:SqlDataSource's select statement executes and binds to DropDownList. That's why selected index of my DropDownList is always 1, no matter what I set it in Page_Load. So, how can I bind asp:SqlDataSource to asp:DropDownList and also set it's selected index parameter to some integer?

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  • Retriving data from ListView control

    - by Josh
    I have a ListView control set up in details mode with 5 columns. It is populated by code using the following subroutine: For j = 0 To 14 cmd = New OleDbCommand("SELECT TeacherName, ClassSubject, BookingDate, BookingPeriod FROM " & SchemaTable.Rows(i)!TABLE_NAME.ToString() & " WHERE (((BookingDate)=" & Chr(34) & Date.Today.AddDays(j) & Chr(34) & ") AND ((UserName)=" & Chr(34) & user & Chr(34) & "));", cn) dr = cmd.ExecuteReader Dim itm As ListViewItem Dim itms(4) As String While dr.Read() itms(0) = dr(0) itms(1) = SchemaTable.Rows(i)!TABLE_NAME.ToString() itms(2) = dr(1) itms(3) = dr(2) itms(4) = dr(3) itm = New ListViewItem(itms) Manage.ManageList.Items.Add(itm) End While Next Note that this is not the full routine, just the bit that populated the grid. Now I need to retrieve data from the ListView control in order to delete a booking in my database. I used the following code to retrieve the content of each column: ManageList.SelectedItems(0).Text But it only seems to work on index 0. If I do: ManageList.SelectedItems(3).Text I get this error: InvalidArgument=Value of '3' is not valid for 'index'. Parameter name: index I'm pretty much stumped, it seems logical to me that index 1 will point to the 2nd column, index 2 to the 3rd etc, as it's 0 based? Any help would be appreciated, thanks.

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  • ASP.NET MVC URL Routing problem

    - by Sadegh
    hi, i have defined a route as below: context.MapRoute("SearchEngineWebSearch", "search/web/{query}/{index}/{size}", new { controller = "search", action = "web", query = "", index = 0, size = 5 }); and action method to handle request match with that: public System.Web.Mvc.ActionResult Web(string query = "", int index = 0, int size = 5) { if (string.IsNullOrEmpty(query)) return RedirectToRoute("SearchEngineBasicSearch"); var search = new Search(); var results = search.PerformSearch(query, index, size); ViewData["Query"] = query; if (results != null && results.Count() > 0) { ViewData["Results"]= results; return View("Web"); } else return View("Not-Found"); } and form to sent parameter to action method: <% using (Html.BeginForm("Web", "Search", FormMethod.Post)) { %> <input name="query" type="text" value="<%: ViewData["Query"]%>" class="search-field" /> <input type="submit" value="Search" class="search-button" /> <input type="hidden" name="index" value="2" /> <input type="hidden" name="size" value="2" /> <%} %> now after click on submit and sending value to action method all route values updated but url values still is equals to first time of sending parameter. for example if i sent for first time request such as http://localhost/search/web/google and for next time http://localhost/search/web/yahoo, query parameter which passed to action method is yahoo but url after postback is http://localhost/search/web/google still! can anybody help me plz? ;)

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  • Array::include? on ActiveRecord collection not calling op== ?

    - by tribalvibes
    Given a collection of named Foos from ActiveRecord, why does Array.include? not seem to call Foo.== but yet index does? class Foo < ActiveRecord::Base def ==(s) self.name == s end end class Bar < ActiveRecord::Base has_many :foos end bar.foos << Foo.new( :name = 'hmm' ) bar.foos.all.include?('hmm') # does select all from db every time = true bar.foos.include?('hmm') # does not go to db, but does not find the Foo! = false bar.foos.index('hmm') # does not go to db, but does find the Foo[0] ! = 0 bar.foos.index('eh') # no such object = nil I understand shallow about the proxies, but (without a detour into the AR source) why is index seemingly behaving correctly but include? is not !? Is this a bug in the proxy behavior, and/or is this behavior documented somewhere ? Thanks.

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  • Python opening a file and putting list of names on separate lines

    - by Jeremy Borton
    I am trying to write a python program using Python 3 I have to open a text file and read a list of names, print the list, sort the list in alphabetical order and then finally re-print the list. There's a little more to it than that BUT the problem I am having is that I'm supposed to print the list of names with each name on a separate line Instead of printing each name on a separate line, it prints the list all on one line. How can I fix this? def main(): #create control loop keep_going = 'y' #Open name file name_file = open('names.txt', 'r') names = name_file.readlines() name_file.close() #Open outfile outfile = open('sorted_names.txt', 'w') index = 0 while index < len(names): names[index] = names[index].rstrip('\n') index += 1 #sort names print('original order:', names) names.sort() print('sorted order:', names) #write names to outfile for item in names: outfile.write(item + '\n') #close outfile outfile.close() #search names while keep_going == 'y' or keep_going == 'Y': search = input('Enter a name to search: ') if search in names: print(search, 'was found in the list.') keep_going = input('Would you like to do another search Y for yes: ') else: print(search, 'was not found.') keep_going = input('Would you like to do another search Y for yes: ') main()

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  • Address String Split in javscript

    - by Arasoi
    Ok folks I have bombed around for a few days trying to find a good solution for this one. What I have is two possible address formats. 28 Main St Somecity, NY 12345-6789 or Main St Somecity, Ny 12345-6789 What I need to do Is split both strings down into an array structured as such address[0] = HousNumber address[1] = Street address[2] = City address[3] = State address[4] = ZipCode My major problem is how to account for the lack of a house number. with out having the whole array shift the data up one. address[0] = Street address[1] = City address[2] = State address[3] = ZipCode [Edit] For those that are wondering this is what i am doing atm . (cleaner version) place = response.Placemark[0]; point = new GLatLng(place.Point.coordinates[1],place.Point.coordinates[0]); FCmap.setCenter(point,12); var a = place.address.split(','); var e = a[2].split(" "); var x = a[0].split(" "); var hn = x.filter(function(item,index){ return index == 0; }); var st = x.filter(function(item,index){ return index != 0; }); var street = ''; st.each(function(item,index){street += item + ' ';}); results[0] = new Hash({ FullAddie: place.address, HouseNum: hn[0], Dir: '', Street: street, City: a[1], State: e[1], ZipCode: e[2], GPoint: new GMarker(point), Lat: place.Point.coordinates[1], Lng: place.Point.coordinates[0] }); // End Address Splitting

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  • jQuery : how to manipulate indexes?

    - by Gabriel Theron
    Should not be such a hard question... I'm just having a hard time figuring out how to make operations on some jquery elements, particularly their indexes. Teh codez: $( "#docSlider" ).css("background-image", "url(../../bundles/mypath/images/maquette/img" + $( "#selectable li" ).index( this ) + (".jpg)")); I want to make the name of the picture I load depend on the index of a jQuery selectable. So I grab the index and try to add 1... but it can't work because "+" is also a concatenator. I've tried to parseInt as well, but it was always worth 0. How do I simply transform the index to an integer and then concatenate it with the rest of the string? Thank you in advance! Edit : I'm using a function that already exists, so I can hardly change the parameters (well, I guess I can't...)

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