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  • How to count NULL values in MySQL?

    - by abbr
    I want to know how can i find all the values that are NULL in the MySQL database for example I'm trying to display all the users who don't have an average yet. Here is the MySQL code. SELECT COUNT(average) as num FROM users WHERE user_id = '$user_id' AND average IS_NULL

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  • Load huge sql dump to mySql

    - by jonathan
    Hi I have a huge mysql dump file generated from phpmyAdmin (150 000 lines of create table, inserts....) The mySql query tool fails to open such a big file. As a result i can't insert all the records. Is there a way to do this ? Thanks John

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  • Updating multiple rows with an array

    - by Copephobia
    I have a table that holds user information. One of the columns holds the position of the user in the game they are in. When a game is being created, I need to update the positions of the users of each team. Here is an example: Game id : 7 Team 1 users : 1,2 Team 2 users : 3,4 team1_position : array(1,2) team2_position : array(13,14) What I want to do is update the user table using the array of positions in the SET area. My goal is to be able to update the users without the need for their id (I have different size game boards, so I have multiple position arrays for each board size) How can I do something like this: UPDATE user SET position='(team1_position)' WHERE game = '7' AND team = '1' I feel like it would be a waste of resources to select all the id's of each team and update them separately.

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  • MySql LINK to SQL Server

    - by XkiD
    I have a host with php+mysql and i need to run a script here to register accounts to another host that has SQL Server and i also have php+mysql here also , but i need the accounts to be in SQL Server. how can i do this?

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  • Why am I getting a MySQL error?

    - by John Hoffman
    Here is my query. Its intention is allow access to properties of the animals that constitute a match of two animals. The match table contains columns for animal1ID and animal2ID to store which animals constitute the match. SELECT id, (SELECT * FROM animals WHERE animals.id=matches.animal1ID) AS animal1, (SELECT * FROM users WHERE animals.id=matches.animalID) AS animal2 FROM matches WHERE id=5 However, MySQl returns this error: Operand should contain 1 column(s). Why? Is there an alternative way to do this, perhaps with a JOIN statement?

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  • iPhone to host server to mySQL and back?

    - by ronbowalker
    Can someone please direct me to process for doing this? I have already done the Login verification exercise using mySQL for the dbase on my host server (thanks to kiksy). Now I am trying to move forward and "Query" from the iPhone a list of "users" that currently occupy the table (iphoneusers) in MySQL. And of course get it back to the iPhone via the php connection. Any help would be very much appreciated. ronbowalker

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  • How to dynamically insert a keyword in an Amazon Search Widget

    - by ElHaix
    Through Amazon Associates, you can create search widgets that have a place for a search term. In the admin, you can set the default search term, but that seems to be tied to the widget ID. I would like to be able to dynamically set the search term for the widget when it is displayed. How can I accomplish this? Note: I am referring to the following banner script: <SCRIPT charset="utf-8" type="text/javascript" src="http://ws-na.amazon-adsystem.com/widgets/q?rt=tf_sw&ServiceVersion=20070822&MarketPlace=CA&ID=V20070822%2FCA%2F[PARTNER-ID]%2F8002%2F84cb1754-d9ab-48de-b96b-574927fa9599"> </SCRIPT> <NOSCRIPT><A HREF="http://ws-na.amazon-adsystem.com/widgets/q?rt=tf_sw&ServiceVersion=20070822&MarketPlace=CA&ID=V20070822%2FCA%2F[PARTNER-ID]%2F8002%2F84cb1754-d9ab-48de-b96b-574927fa9599&Operation=NoScript">Amazon.ca Widgets</A></NOSCRIPT>

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  • Default User Id at Login different from User Name in Terminal Shell

    - by Bill
    During the Ubuntu 12.04 LTS installation, I was prompted to enter a user name and password, so that a corresponding account could be created and set up for login. I replaced the one that was provided by default (i.e. '70319', which is the Windows 7 admin id) with a user name/id of my choosing. Now, when I turn on the computer, and choose to enter the Ubuntu operating system, the login id that is displayed is 70319 - that is, the one provided by Windows 7. However, when I open up a Unix/Terminal shell, the user id that is displayed at the prompt is the one I entered during installation. Otherwise, the installation of Ubuntu was a success! Is there some way of changing the user id that is displayed at the Login screen, so that it is consistent with the one I entered during installation? If it's any help, I installed Ubuntu using wubi on an ASUS Eee PC 1011PX running Windows 7, and ASUS Express Gate Cloud. Further details regarding the setup/installation can be found at the following link: Installing Ubuntu on an Eee PC 1011PX

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  • Selecting Dynamic ID JQuery [migrated]

    - by Vedran Wex Maricevic
    I need to select dynamic id using JQuery, and once I select it then I need to do some action on it. This is the HTML that I have: <input id="content_photos_attributes_1355755712119_image" name="content[photos_attributes][1355755712119][image]" size="30" type="file"> Please note the id value, text is always the same however the number changes (I do not have control over that change). What I need to do is to create on click for that element. This is what I got so far, and it is not working. <script type="text/javascript"> jQuery.noConflict(); jQuery("input[id *= 'content_photos_attributes_']").click(function() { alert("Image deletion is clicked"); }); </script> It really makes no difference whether I select that element by ID or by its name.

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  • When tracking which elements were clicked e.target.id is sometimes empty [migrated]

    - by Ivan
    I am trying to test the following JavaScript code, which is meant to keep track of the timing of user responses on a multiple choice survey: document.onclick = function(e) { var event = e || window.event; var target = e.target || e.srcElement; //time tracking var ClickTrackDate = new Date; var ClickData = ""; ClickData = target.id + "=" + ClickTrackDate.getUTCHours() + ":" + ClickTrackDate.getUTCMinutes() + ":" + ClickTrackDate.getUTCSeconds() +";"; document.getElementById("txtTest").value += ClickData; alert(target.id); // for testing } Usually target.id equals to the the id of the clicked element, as you would expect, but sometimes target.id is empty, seemingly at random, any ideas?

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  • How to set permalink of your blog post according to date and title of post?

    - by Amit
    I am having this website http://www.finalyearondesk.com . My blogs post link are set like this.. http://www.finalyearondesk.com/index.php?id=28 . I want it to set like this ... finalyearondesk.com/2011/09/22/how-to-recover-ubuntu-after-it-is-crashed/ . I am using the following function to get these posts... function get_content($id = '') { if($id != ""): $id = mysql_real_escape_string($id); $sql = "SELECT * from blog WHERE id = '$id'"; $return = '<p><a href="http://www.finalyearondesk.com/">Go back to Home page</a></p>'; echo $return; else: $sql = "select * from blog ORDER BY id DESC"; endif; $res = mysql_query($sql) or die(mysql_error()); if(mysql_num_rows($res) != 0): while($row = mysql_fetch_assoc($res)) { echo '<h1><a href="index.php?id=' . $row['id'] . '">' . $row['title'] . '</a></h1>'; echo '<p>' . "By: " . '<font color="orange">' . $row['author'] . '</font>' . ", Posted on: " . $row['date'] . '<p>'; echo '<p>' . $row['body'] . '</p><br />'; } else: echo '<p>We are really very sorry, this page does not exist!</p>'; endif; } Any suggestions how to do this? And can we do this by using .htaccess?

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  • C#/.Net Error: MySql.Data Object reference not set to an instance of an object.

    - by Simon
    Hello, I get this exception on my Windows 7 64bit in application running in VS 2008 express. I am using Connector/Net 6.2.2.0: Message: Object reference not set to an instance of an object. Source: MySql.Data in MySql.Data.MySqlClient.NativeDriver.GetResult(Int32& affectedRow, Int32& insertedId) Stack trace: in MySql.Data.MySqlClient.Driver.GetResult(Int32 statementId, Int32& affectedRows, Int32& insertedId) in MySql.Data.MySqlClient.Driver.NextResult(Int32 statementId) in MySql.Data.MySqlClient.MySqlDataReader.NextResult() in MySql.Data.MySqlClient.MySqlDataReader.Close() in MySql.Data.MySqlClient.MySqlConnection.Close() in MySql.Data.MySqlClient.MySqlConnection.Dispose(Boolean disposing) in System.ComponentModel.Component.Finalize() No inner exception. This exception is unhalted and the debugger dont point on any code line. It just say "Object reference not set to an instance of an object. MySql.Data" This error is really hard to repeat. On my Windows XP 32bit is all ok. Could it be error in 64bit Windows 7? Thank you very much for your answers. Regards, simon

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  • Query design in SQL - ORDER BY SUM() of field in rows which meet a certain condition

    - by Christian Mann
    OK, so I have two tables I'm working with - project and service, simplified thus: project ------- id PK name str service ------- project_id FK for project time_start int (timestamp) time_stop int (timestamp) One-to-Many relationship. Now, I want to return (preferably with one query) a list of an arbitrary number of projects, sorted by the total amount of time spent at them, which is found by SUM(time_stop) - SUM(time_start) WHERE project_id = something. So far, I have SELECT project.name FROM service LEFT JOIN project ON project.id = service.project_id LIMIT 100 but I cannot figure out how what to ORDER BY.

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  • Why does this PHP script interfere with my CSS layout?

    - by CT
    This page uses $_GET to grab an asset id and query a mysql database and return some information. If 'id' does not match anything, no results are displayed but the page looks fine. If 'id' is null an error would occur at $id = $_GET["id"] or die(mysql_error()); When this occurs, they page layout is not displayed correctly. How do I fix this? Bonus question: How would I get a message like "No matching results found" or something when the id does not match any id in the database or is null. Thank you. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link rel="stylesheet" type="text/css" href="style.css" /> <title>Wagman IT Asset</title> </head> <body> <div id="page"> <div id="header"> <img src="images/logo.png" /> </div> </div> <div id="content"> <div id="container"> <div id="main"> <div id="menu"> <ul> <table width="100%" border="0"> <tr> <td><li><a href="index.php">Search Assets</a></li></td> <td><li><a href="browse.php">Browse Assets</a></li></td> <td><li><a href="add_asset.php">Add Asset</a></li></td> <td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td> </tr> </table> </ul> </div> <div id="text"> <ul> <li> <h1>View Asset</h1> </li> </ul> <table width="100%" border="0" cellpadding="2"> <?php //make database connect mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); //get asset $id = $_GET["id"] or die(mysql_error()); //get type of asset $sql = "SELECT asset.type From asset WHERE asset.id = $id"; $result = mysql_query($sql) or die(mysql_error()); $row = mysql_fetch_assoc($result); $type = $row['type']; switch ($type){ case "Server": $sql = " SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serial_number ,server.esc ,server.user ,server.prev_user ,server.warranty FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = $id "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Asset ID:</td><td>"; $id = $row['id']; setcookie('id', $id); echo "$id</td></tr>"; echo "<tr<td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Company:</td><td>"; $company = $row['company']; setcookie('company', $company); echo "$company</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Location:</td><td>"; $location = $row['location']; setcookie('location', $location); echo "$location</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Date:</td><td>"; $purchase_date = $row['purchase_date']; setcookie('purchase_date', $purchase_date); echo "$purchase_date</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Order:</td><td>"; $purchase_order = $row['purchase_order']; setcookie('purchase_order', $purchase_order); echo "$purchase_order</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Value:</td><td>"; $value = $row['value']; setcookie('value', $value); echo "$value</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Type:</td><td>"; $type = $row['type']; setcookie('type', $type); echo "$type</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Notes:</td><td>"; $notes = $row['notes']; setcookie('notes', $notes); echo "$notes</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Manufacturer:</td><td>"; $manufacturer = $row['manufacturer']; setcookie('manufacturer', $manufacturer); echo "$manufacturer</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Model / Description:</td><td>"; $model = $row['model']; setcookie('model', $model); echo "$model</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Serial Number / Service Tag:</td><td>"; $serial_number = $row['serial_number']; setcookie('serial_number', $serial_number); echo "$serial_number</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Express Service Code:</td><td>"; $esc = $row['esc']; setcookie('esc', $esc); echo "$esc</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>User:</td><td>"; $user = $row['user']; setcookie('user', $user); echo "$user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Previous User:</td><td>"; $prev_user = $row['prev_user']; setcookie('prev_user', $prev_user); echo "$prev_user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Warranty:</td><td>"; $warranty = $row['warranty']; setcookie('warranty', $warranty); echo "$warranty</td></tr>"; } break; case "Laptop": $sql = " SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,laptop.manufacturer ,laptop.model ,laptop.serial_number ,laptop.esc ,laptop.user ,laptop.prev_user ,laptop.warranty FROM asset LEFT JOIN laptop ON laptop.id = asset.id WHERE asset.id = $id "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Asset ID:</td><td>"; $id = $row['id']; setcookie('id', $id); echo "$id</td></tr>"; echo "<tr<td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Company:</td><td>"; $company = $row['company']; setcookie('company', $company); echo "$company</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Location:</td><td>"; $location = $row['location']; setcookie('location', $location); echo "$location</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Date:</td><td>"; $purchase_date = $row['purchase_date']; setcookie('purchase_date', $purchase_date); echo "$purchase_date</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Order:</td><td>"; $purchase_order = $row['purchase_order']; setcookie('purchase_order', $purchase_order); echo "$purchase_order</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Value:</td><td>"; $value = $row['value']; setcookie('value', $value); echo "$value</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Type:</td><td>"; $type = $row['type']; setcookie('type', $type); echo "$type</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Notes:</td><td>"; $notes = $row['notes']; setcookie('notes', $notes); echo "$notes</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Manufacturer:</td><td>"; $manufacturer = $row['manufacturer']; setcookie('manufacturer', $manufacturer); echo "$manufacturer</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Model / Description:</td><td>"; $model = $row['model']; setcookie('model', $model); echo "$model</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Serial Number / Service Tag:</td><td>"; $serial_number = $row['serial_number']; setcookie('serial_number', $serial_number); echo "$serial_number</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Express Service Code:</td><td>"; $esc = $row['esc']; setcookie('esc', $esc); echo "$esc</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>User:</td><td>"; $user = $row['user']; setcookie('user', $user); echo "$user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Previous User:</td><td>"; $prev_user = $row['prev_user']; setcookie('prev_user', $prev_user); echo "$prev_user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Warranty:</td><td>"; $warranty = $row['warranty']; setcookie('warranty', $warranty); echo "$warranty</td></tr>"; } break; case "Desktop": $sql = " SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,desktop.manufacturer ,desktop.model ,desktop.serial_number ,desktop.esc ,desktop.user ,desktop.prev_user ,desktop.warranty FROM asset LEFT JOIN desktop ON desktop.id = asset.id WHERE asset.id = $id "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Asset ID:</td><td>"; $id = $row['id']; setcookie('id', $id); echo "$id</td></tr>"; echo "<tr<td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Company:</td><td>"; $company = $row['company']; setcookie('company', $company); echo "$company</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Location:</td><td>"; $location = $row['location']; setcookie('location', $location); echo "$location</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Date:</td><td>"; $purchase_date = $row['purchase_date']; setcookie('purchase_date', $purchase_date); echo "$purchase_date</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Purchase Order:</td><td>"; $purchase_order = $row['purchase_order']; setcookie('purchase_order', $purchase_order); echo "$purchase_order</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Value:</td><td>"; $value = $row['value']; setcookie('value', $value); echo "$value</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Type:</td><td>"; $type = $row['type']; setcookie('type', $type); echo "$type</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Notes:</td><td>"; $notes = $row['notes']; setcookie('notes', $notes); echo "$notes</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Manufacturer:</td><td>"; $manufacturer = $row['manufacturer']; setcookie('manufacturer', $manufacturer); echo "$manufacturer</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Model / Description:</td><td>"; $model = $row['model']; setcookie('model', $model); echo "$model</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Serial Number / Service Tag:</td><td>"; $serial_number = $row['serial_number']; setcookie('serial_number', $serial_number); echo "$serial_number</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Express Service Code:</td><td>"; $esc = $row['esc']; setcookie('esc', $esc); echo "$esc</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>User:</td><td>"; $user = $row['user']; setcookie('user', $user); echo "$user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Previous User:</td><td>"; $prev_user = $row['prev_user']; setcookie('prev_user', $prev_user); echo "$prev_user</td></tr>"; echo "<tr><td>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>Warranty:</td><td>"; $warranty = $row['warranty']; setcookie('warranty', $warranty); echo "$warranty</td></tr>"; } break; } ?> </table> <br /> <br /> <table width="100%" border="0"> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td>&nbsp;</td> <td><a href="#">Add Software</a></td> <td><a href="#">Edit Asset</a></td> <td><a href="#">Delete Asset</a></td> </tr> </table> </div> </div> </div> <div class="clear"></div> <div id="footer" align="center"> <p>&nbsp;</p> </div> </div> <div id="tagline"> Wagman Construction - Bridging Generations since 1902 </div> </body> </html>

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  • Any disadvantages to this tagging approach

    - by donpal
    I have a table of tags ID tag --- ------ 1 tagt 2 tagb 3 tagz 4 tagn In my items table, I'm using those tags in serialized format, comma delimited ID field1 tags ---- ------ ----- 1 value1 tagt,tagb 2 value2 tagb 3 value3 tagb,tagn 4 value4 When I need to find items that have this tag, I plan to deserialize the tags. But I'm not actually sure how to do it, and if it's better to have a third table for associations instead between the tags and the items.

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  • Unique Alpha numeric generator

    - by AAA
    Hi, I want to give our users in the database a unique alpha-numeric id. I am using the code below, will this always generate a unique id? Below is the updated version of the code: old php: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid(rand(),true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; New PHP: // Generate Guid function NewGuid() { $s = strtoupper(uniqid("something",true)); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Will the second (new php) code guarantee 100% uniqueness. Final code: PHP // Generate Guid function NewGuid() { $s = strtoupper(uniqid(rand(),true)); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; $alphabet = '123456789abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNPQRSTUVWXYZ'; function base_encode($num, $alphabet) { $base_count = strlen($alphabet); $encoded = ''; while ($num >= $base_count) { $div = $num/$base_count; $mod = ($num-($base_count*intval($div))); $encoded = $alphabet[$mod] . $encoded; $num = intval($div); } if ($num) $encoded = $alphabet[$num] . $encoded; return $encoded; } function base_decode($num, $alphabet) { $decoded = 0; $multi = 1; while (strlen($num) > 0) { $digit = $num[strlen($num)-1]; $decoded += $multi * strpos($alphabet, $digit); $multi = $multi * strlen($alphabet); $num = substr($num, 0, -1); } return $decoded; } echo base_encode($Guid, $alphabet); } So for more stronger uniqueness, i am using the $Guid as the key generator. That should be ok right?

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  • How can you access two identically-named columns in a MySQL LEFT JOIN query?

    - by George Edison
    I have two tables. table_x: id INT(11) tag INT(11) table_tags: id INT(11) name VARCHAR(255) Then I use PHP to perform the following query: SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id The only problem is: how do I access table_x.id and table_tags.id in the results? Here is the PHP code: $query = "SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id"; $results = mysql_query($query); while($row = mysql_fetch_array($results)) { // how do I now access table_x.id and table_tags.id ??? }

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  • Need help with a SELECT statement

    - by Travis
    I express the relationship between records and searchtags that can be attached to records like so: TABLE RECORDS id name TABLE SEARCHTAGS id recordid name I want to be able to SELECT records based on the searchtags that they have. For example, I want to be able to SELECT all records that have searchtags: (1 OR 2 OR 5) AND (6 OR 7) AND (10) Using the above data structure, I am uncertain how to structure the SQL to accomplish this. Any suggestions? Thanks!

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  • howto have condition in a nested SQL query?

    - by fenec
    here is my SQL statement , i would like to find all the games that have the status 0 and names of teams that are like key_word or the sport's name that are like the key word. The problem is that all the games that are displayed don't have status 0 . What am i doing wrong? sql="select * from games where games.status=0 and games.team_2_id IN (select id from teams where name like '"+key_word+"') or games.team_1_id IN (select id from teams where name like '"+key_word+"') or games.sport like '"+key_word+"' "

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  • how to access mysql table from wamp database using this php code? [migrated]

    - by user3909877
    how to access tables from database by using php in wamp server.i have done the following code but its not working for some reason.is there anything to put in 'action=""'.it is not giving any error but displaying the same page.i want to display table from database on any different entry in dropdown menu and pressing search button.. <p class="h2">Quick Search</p> <div class="sb2_opts"> <p> </p> <form method="post" action="" > <p>Enter your source and destination.</p> <p> From:</p> <select name="from"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <p> To:</p> <select name="To"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <input type="submit" value="search" /> </form> </form> </table> <?php if(isset($_POST['from']) and isset($_POST['To'])) { $from = $_POST['from'] ; $to = $_POST['To'] ; $table = array($from, $to); $con=mysqli_connect("localhost"); $mydb=mysql_select_db("homedb"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } switch ($table) { case array ("Islamabad", "Lahore") : $result = mysqli_query($con,"SELECT * FROM flights"); echo "</flights>"; //table name is flights break; case array ("Islamabad", "Murree") : $result = mysqli_query($con,"SELECT * FROM `isb to murree`"); echo "</`isb to murree`>"; //table name isb to murree ; break; case array ("Islamabad", "Muzaffarabad") : $result = mysqli_query($con,"SELECT * FROM `isb to muzz`"); echo "</`isb to muzz`>"; break; //..... //...... default: echo "Your choice is nor valid !!"; } } mysqli_close($con); ?>

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  • MySQL Relational Database Foreign Key

    - by user623879
    To learn databasing, I am creating a movie database. To associate multiple directors with a movie, I have the following schema: movie(m_ID, ....) m_director(dirID, dirName)//dirID is a autoincrement primary key m_directs(dirID, m_ID) //dirID, m_ID are set as foreign Keys in the mysql database(InnoDB engine) I have a program that connects to the db that needs to add a movie to the database. I can easily add a new entry to the movie table and the m_director table, but I am having trouble adding a entry in the m_directs table. INSERT INTO m_director (dirName) VALUES("Jason Reitman"); INSERT INTO m_directs (dirID, m_ID) VALUES(LAST_INSERT_ID(), "tt0467406"); I am using this sql statement to insert a new director and add the association to the movie. I know the primary key of the movie, but I don't know the dirID, so I use LAST_INSERT_ID() to get the last id of the director just inserted. The problem I am having is that I get the following error: MySql.Data.MySqlClient.MySqlException (0x80004005): Cannot add or update a child row: a foreign key constraint fails (`siteproducts`. `m_directs`, CONSTRAINT `m_directs_ibfk_2` FOREIGN KEY (`dirID`) REFERENCES `m_directs` (`dirID`) ON DELETE CASCADE ON UPDATE CASCADE) Any ideas?

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