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  • Symfony 1.4 - Don't save a blank password on a executeUpdate action.

    - by Twelve47
    I have a form to edit a UserProfile which is stored in mysql db. Which includes the following custom configuration: public function configure() { $this->widgetSchema['password']=new sfWidgetFormInputPassword(); $this->validatorSchema['password']->setOption('required', false); // you don't need to specify a new password if you are editing a user. } When the user tries to save the executeUpdate method is called to commit the changes. If the password is left blank, the password field is set to '', but I want it to retain the old password instead of overwriting it. What is the best (/most in the symfony ethos) way of doing this? My solution was to override the setter method on the model (which i had done anyway for password encryption), and ignore blank values. public function setPassword( $password ) { if ($password=='') return false; // if password is blank don't save it. return $this->_set('password', UserProfile ::encryptPassword( $password )); } It seems to work fine like this, but is there a better way? If you're wondering I cannot use sfDoctrineGuard for this project as I am dealing with a legacy database, and cannot change the schema.

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  • from svn to git (+ LDAP + password-less updates + passworded access control)

    - by Jayen
    We have an SVN setup and there are some things we dislike about it and some things we like about it. We want to move to git, but we're not sure exactly what setup will work for us. We're currently using SVN (w/ Authz) + Apache (w/ WebDAV & LDAP). Hook to update the live site [like] Live site update requires no additional interaction [like] Live site update uses stored password [dislike] Commits require centralized-password authentication [like] Commit from live site changes stored credentials [dislike] Access control (per repository) for commits [like] Point 5 above is the one that keeps stuffing us up. Someone makes a commit from the live site and then the hook breaks. We're thinking to use gitosis/gitolite to get access control, but as they use ssh keys, we won't be requiring passwords. We're also thinking to use git-http-backend, and use Apache for authentication, but then do we lose access control? Can the live site be automatically updated from a hook if Apache requires authentication? Can we combine git-http-backend and gitosis/gitolite somehow? Can we store http credentials with git?

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  • MySQL password changed every other day in windows?

    - by PHP
    Every morning when I check server status,I will find MySQL's password is changed: mysql -uuser -ppassword will report ERROR 1045 (28000): Access denied for user 'user'@'localhost' (using password: YES) And then I restart server,and when it's up,MySQL will be back to normal. It has now become a routinely job. What can be the cause for this? How can I know what's exactly happening to MySQL? Here is the error log: 100122 10:11:16 [Note] D:\MySQL\MySQL Server 5.0\bin\mysqld-nt: Normal shutdown 100122 10:11:16 InnoDB: Starting shutdown... 100122 10:11:18 InnoDB: Shutdown completed; log sequence number 0 22939338 100122 10:11:18 [Note] D:\MySQL\MySQL Server 5.0\bin\mysqld-nt: Shutdown complete 100122 10:12:40 InnoDB: Started; log sequence number 0 22939338 100122 10:12:42 [Note] D:\MySQL\MySQL Server 5.0\bin\mysqld-nt: ready for connections. Version: '5.0.24-community-nt' socket: '' port: 3306 MySQL Community Edition (GPL) 100123 16:20:44 [Note] D:\MySQL\MySQL Server 5.0\bin\mysqld-nt: Normal shutdown 100123 16:20:44 InnoDB: Starting shutdown... 100123 16:20:46 InnoDB: Shutdown completed; log sequence number 0 22939832 100123 16:20:46 [Note] D:\MySQL\MySQL Server 5.0\bin\mysqld-nt: Shutdown complete 100123 16:22:09 InnoDB: Started; log sequence number 0 22939832 100123 16:22:11 [Note] D:\MySQL\MySQL Server 5.0\bin\mysqld-nt: ready for connections. Version: '5.0.24-community-nt' socket: '' port: 3306 MySQL Community Edition (GPL) 100125 9:18:59 [Note] D:\MySQL\MySQL Server 5.0\bin\mysqld-nt: Normal shutdown 100125 9:18:59 InnoDB: Starting shutdown... 100125 9:19:00 InnoDB: Shutdown completed; log sequence number 0 22941001 100125 9:19:00 [Note] D:\MySQL\MySQL Server 5.0\bin\mysqld-nt: Shutdown complete 100125 9:20:22 InnoDB: Started; log sequence number 0 22941001 100125 9:20:25 [Note] D:\MySQL\MySQL Server 5.0\bin\mysqld-nt: ready for connections. Version: '5.0.24-community-nt' socket: '' port: 3306 MySQL Community Edition (GPL)

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  • The Network folder specified is currently mapped using a different user name and password

    - by Frank Thornton
    I have a NAS device, it has 3 shares. On one computer I have access to all 3 of the shares. On another computer I keep getting this error when try and add a 2nd one. The Network folder specified is currently mapped using a different user name and password [...] That is the message I keep getting. What causes that? EDIT: Every share has it's own username and password. EDIT: NET USE on the one running 3 from the same NAS device New connections will be remembered. Status Local Remote Network ------------------------------------------------------------------------------- OK T: \\192.168.2.5\SHARE1 Microsoft Windows Network OK X: \\Nas-1dsho-abc\SHARE2 Microsoft Windows Network Disconnected Y: \\192.168.2.9\backups Microsoft Windows Network OK Z: \\Nas-1dsho-abc\cbackups Microsoft Windows Network The command completed successfully. NET USE on the other: New connections will be remembered. Status Local Remote Network ------------------------------------------------------------------------------- OK Y: \\192.168.2.5\SHARE1 Microsoft Windows Network Unavailable Z: \\192.168.2.5\SHARE2 Microsoft Windows Network The command completed successfully.

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  • apache using mod_auth_kerb always asks for the password twice

    - by DrStalker
    (Debian Squeeze) I'm trying to set apache up to use Kerberos authentication to allow AD users to log in. It is working, but prompts the user twice for a username and password, with the first time being ignored (no matter what is put it in.) Only the second prompt includes the AuthName string from the config (i.e.: the first windows is a generic username/password one, the second includes the title "Kerberos Login") I'm not worried about integrated windows authentication working at this stage, I just want users to be able to login with their AD account so we don't need to set up a second repository of user accounts. How do I fix this to eliminate that first useless prompt? The directives in the apache2.conf file: <Directory /var/www/kerberos> AuthType Kerberos AuthName "Kerberos Login" KrbMethodNegotiate On KrbMethodK5Passwd On KrbAuthRealms ONEVUE.COM.AU.LOCAL Krb5KeyTab /etc/krb5.keytab KrbServiceName HTTP/[email protected] require valid-user </Directory> krb5.conf: [libdefaults] default_realm = ONEVUE.COM.AU.LOCAL [realms] ONEVUE.COM.AU.LOCAL = { kdc = SYD01PWDC01.ONEVUE.COM.AU.LOCAL master_kdc = SYD01PWDC01.ONEVUE.COM.AU.LOCAL admin_server = SYD01PWDC01.ONEVUE.COM.AU.LOCAL default_domain = ONEVUE.COM.AU.LOCAL } [login] krb4_convert = true krb4_get_tickets = false The access log when accessing the secured directory (note the two seperate 401's) 192.168.10.115 - - [24/Aug/2012:15:52:01 +1000] "GET /kerberos/ HTTP/1.1" 401 710 "-" "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.83 Safari/537.1" 192.168.10.115 - - [24/Aug/2012:15:52:06 +1000] "GET /kerberos/ HTTP/1.1" 401 680 "-" "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.83 Safari/537.1" 192.168.10.115 - [email protected] [24/Aug/2012:15:52:10 +1000] "GET /kerberos/ HTTP/1.1" 200 375 "-" "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.83 Safari/537.1" And one line in error.log [Fri Aug 24 15:52:06 2012] [error] [client 192.168.0.115] gss_accept_sec_context(2) failed: An unsupported mechanism was requested (, Unknown error)

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  • Shut Out of XP - No Admin Password or CDR

    - by ashes999
    I inherited an old WinXP/Linux dual-boot machine from the stoneage. Because it has Linux, the regular boot process is replaced with the Fedora boot loader; I cannot, therefore, press F8 strategically to tell my PC to boot from CD. Even if I could, it's a moot point; the CDR doesn't seem to recognize any CDs. To make things worse, there's no option to network boot. The original user is probably long gone; I don't know the password for any of the Administrator group users. I can login using my corp account, but that's unprivileged on this machine. Since I'm not an admin, I can't do crazy things, like looking at boot.ini. Or deleting files. I only have 500MB free on my C drive. I'm pretty sure I can't boot from a USB, since I didn't see any settings for this in my BIOS. How can I get admin access for my user? Edit: Things I've tried: Boot from CD (CD not recognized) Launch CD from XP (CD not recognized) Install Daemon Tools Lite so I can install from an ISO -- don't have admin privileges XP password recovery tool -- requires admin privileges Adding an admin user -- no access to Control Panel Users since I'm not an admin Logging in as both the admin users on the system (trying some standard passwords) Using Fedora to chntpw (the Fedora version installed is ancient -- 2.7)

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  • Hadoop initscript askes password

    - by Ramesh
    I have installed hadoop on my ubuntu 12.04 single node .I am trying to execute an init script to make the hadoop run on start up but it asks password every time i execute. #!/bin/sh ### BEGIN INIT INFO # Provides: hadoop services # Required-Start: $network # Required-Stop: $network # Default-Start: 2 3 4 5 # Default-Stop: 0 1 6 # Description: Hadoop services # Short-Description: Enable Hadoop services including hdfs ### END INIT INFO PATH=/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin HADOOP_BIN=/home/naveen/softwares/hadoop-1.0.3/bin NAME=hadoop DESC=hadoop USER=naveen ROTATE_SUFFIX= test -x $HADOOP_BIN || exit 0 RETVAL=0 set -e cd / start_hadoop () { set +e su $USER -s /bin/sh -c $HADOOP_BIN/start-all.sh > /var/log/hadoop/startup_log case "$?" in 0) echo SUCCESS RETVAL=0 ;; 1) echo TIMEOUT - check /var/log/hadoop/startup_log RETVAL=1 ;; *) echo FAILED - check /var/log/hadoop/startup_log RETVAL=1 ;; esac set -e } stop_hadoop () { set +e if [ $RETVAL = 0 ] ; then su $USER -s /bin/sh -c $HADOOP_BIN/stop-all.sh > /var/log/hadoop/shutdown_log RETVAL=$? if [ $RETVAL != 0 ] ; then echo FAILED - check /var/log/hadoop/shutdown_log fi else echo No nodes running RETVAL=0 fi set -e } restart_hadoop() { stop_hadoop start_hadoop } case "$1" in start) echo -n "Starting $DESC: " start_hadoop echo "$NAME." ;; stop) echo -n "Stopping $DESC: " stop_hadoop echo "$NAME." ;; force-reload|restart) echo -n "Restarting $DESC: " restart_hadoop echo "$NAME." ;; *) echo "Usage: $0 {start|stop|restart|force-reload}" >&2 RETVAL=1 ;; esac exit $RETVAL Please tell me how to run hadoop without entering password.

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  • Windows 7 Professional Cannot Connect to Share - Wrong password

    - by henryford
    I know that this question has actually been asked a few times before, but every solution I found didn't yield any results on my end, I can't get my head around it: When I am trying to connect to a share on the network, I always get the response "The specified network password is incorrect". However, the password is definetly correct and it works if I connect from another machine. I changed the LAN Manager authentication level to "Send LM & NTLM - use NTLMv2 session security if negiotated", I configured Kerberos encryption types to include all suites, rebooted (several times), but still - no luck. I can connect if I use my regular account with which I am logged in, but I need to connect with a different user since my log-in user has not enough privileges on the share. When I do that, the error above comes up. I'm really frustrated at the moment, this problem is driving me crazy. I'd be gladful for any possible solution to this. At the moment I'm using a workaround: I connect to a different machine via RDP, login with the user I have to use for the network-share connection and then I can map the drive and copy/paste from the RDP session to my local workstation. This is also working when I am connecting via RDP with my current login user and map the drive with the other user who has sufficent privileges. Tanks in advance, Thomas

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  • Permission denied (publickey,gssapi-with-mic,password) ssh error

    - by zentenk
    Heads up I'm a noob with linux and networking. I set up a ubuntu server and I have a static ip for my network. When I try to connect to the server at home (external), it prompts me to log in. I supply the correct password (or incorrect pw), I get the error Permission denied, please try again. and after 3 times I get Permission denied (publickey,gssapi-with-mic,password) I am however able to connect with SSH from another computer in the same network with ssh < internal ip of server > I'm connecting with mac os x and my config file is vanilla. Note: During installation of ubuntu it says I don't have a default route or something while doing auto network configuration, but I ignored it and continued the installation, could this be the problem? EDIT: I have tried the below, I have nothing in hosts.allow and also iptables shows the ports that I have allowed, which is 22. I checked the auth.log, and there is nothing when I connect to it remotely (even when it says permission denied). I have tried connecting to it internally and the correct authentication logs show. Any idea whats wrong?

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  • SSH Keys Authentication keeps asking for password

    - by Rhyuk
    Im trying to set access from ServerA(SunOS) to ServerB(Some custom Linux with Keyboard Interactive login) with SSH Keys. As a proof of concept I was able to do it between 2 virtual machines. Now in my real life scenario it isnt working. I created the keys in ServerA, copied them to ServerB, chmod'd .ssh folders to 700 on both ServerA,B. Here is the log of what I get. debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: Peer sent proposed langtags, ctos: debug1: Peer sent proposed langtags, stoc: debug1: We proposed langtags, ctos: en-US debug1: We proposed langtags, stoc: en-US debug1: SSH2_MSG_KEX_DH_GEX_REQUEST sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: dh_gen_key: priv key bits set: 125/256 debug1: bits set: 1039/2048 debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'XXX.XXX.XXX.XXX' is known and matches the RSA host key. debug1: Found key in /XXX/.ssh/known_hosts:1 debug1: bits set: 1061/2048 debug1: ssh_rsa_verify: signature correct debug1: newkeys: mode 1 debug1: set_newkeys: setting new keys for 'out' mode debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: newkeys: mode 0 debug1: set_newkeys: setting new keys for 'in' mode debug1: SSH2_MSG_NEWKEYS received debug1: done: ssh_kex2. debug1: send SSH2_MSG_SERVICE_REQUEST debug1: got SSH2_MSG_SERVICE_ACCEPT debug1: Authentications that can continue: publickey,keyboard-interactive debug1: Next authentication method: publickey debug1: Trying private key: /XXXX/.ssh/identity debug1: Trying public key: /xxx/.ssh/id_rsa debug1: Authentications that can continue: publickey,keyboard-interactive debug1: Trying private key: /xxx/.ssh/id_dsa debug1: Next authentication method: keyboard-interactive Password: Password: ServerB has pretty limited actions since its a custom propietary linux. What could be happening? EDIT WITH ANSWER: Problem was that I didnt have those settings enabled in the sshd_config (Refer to accepted answer) AND that while pasting the key from ServerA to ServerB it would interpret the key as 3 separate lines. What I did was, in case you cant use ssh-copy-id like I couldnt. Paste the first line of your key in your "ServerB" authorized_keys file WITHOUT the last 2 characters, then type yourself the missing characters from line 1 and the first one from line 2, this will prevent adding a "new line" between the first and second line of the key. Repeat with the 3d line.

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  • Unique Alpha numeric generator

    - by AAA
    Hi, I want to give our users in the database a unique alpha-numeric id. I am using the code below, will this always generate a unique id? Below is the updated version of the code: old php: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid(rand(),true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; New PHP: // Generate Guid function NewGuid() { $s = strtoupper(uniqid("something",true)); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Will the second (new php) code guarantee 100% uniqueness. Final code: PHP // Generate Guid function NewGuid() { $s = strtoupper(uniqid(rand(),true)); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; $alphabet = '123456789abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNPQRSTUVWXYZ'; function base_encode($num, $alphabet) { $base_count = strlen($alphabet); $encoded = ''; while ($num >= $base_count) { $div = $num/$base_count; $mod = ($num-($base_count*intval($div))); $encoded = $alphabet[$mod] . $encoded; $num = intval($div); } if ($num) $encoded = $alphabet[$num] . $encoded; return $encoded; } function base_decode($num, $alphabet) { $decoded = 0; $multi = 1; while (strlen($num) > 0) { $digit = $num[strlen($num)-1]; $decoded += $multi * strpos($alphabet, $digit); $multi = $multi * strlen($alphabet); $num = substr($num, 0, -1); } return $decoded; } echo base_encode($Guid, $alphabet); } So for more stronger uniqueness, i am using the $Guid as the key generator. That should be ok right?

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  • Fail to load NPAPI plugin in Google Chrome on Mac OS X

    - by Roman
    I have been trying to get Google Chrome (6.0.401.1 dev) on Mac OS X to load an NPAPI plugin without success so far. I have been working around the npsimple example from here: http://git.webvm.net/?p=npsimple. Using gcc on Mac and VC++ 2008 on Windows I managed to get it running on Safari and Firefox on Mac OS X and Firefox and Google Chrome on Windows, but not on Google Chrome on Mac OS X. When trying to debug Google Chrome on Mac OS X it seemed Google Chrome was briefly dyld-loading (and immediately dyld-unloading) the plugin on startup, but without actually looking-up any symbols within the plugin or calling any of the functions. It seemed to be doing that for every plugin, though. Also, when loading a page with the embed-tag for the plugin, Google Chrome did not seem to even dyld-load the plugin and no functions were called (not even NP_GetEntryPoints). Google Chrome also does not output any error message, it just simply does not load the plugin. I am not sure I caught everything with gdb because of Google Chrome using different processes, but I have also tried all the switches like --no-sandbox, --single-process and --plugin-startup-dialog (which incidentally does not seem to work at all on Mac OS X). I also made sure the architecture of the binary matches (i.e. 32-bit for Google Chrome). Has anybody had similar problems before? Is there anything I am missing here, like a gcc switch when compiling or something? Any help would be greatly appreciated.

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  • File Format DOS/Unix/MAC code sample

    - by mac
    I have written the following method to detemine whether file in question is formatted with DOS/ MAC, or UNIX line endings. I see at least 1 obvious issue: 1. i am hoping that i will get the EOL on the first run, say within first 1000 bytes. This may or may not happen. I ask you to review this and suggest improvements which will lead to hardening the code and making it more generic. THANK YOU. new FileFormat().discover(fileName, 0, 1000); and then public void discover(String fileName, int offset, int depth) throws IOException { BufferedInputStream in = new BufferedInputStream(new FileInputStream(fileName)); FileReader a = new FileReader(new File(fileName)); byte[] bytes = new byte[(int) depth]; in.read(bytes, offset, depth); a.close(); in.close(); int thisByte; int nextByte; boolean isDos = false; boolean isUnix = false; boolean isMac = false; for (int i = 0; i < (bytes.length - 1); i++) { thisByte = bytes[i]; nextByte = bytes[i + 1]; if (thisByte == 10 && nextByte != 13) { isDos = true; break; } else if (thisByte == 13) { isUnix = true; break; } else if (thisByte == 10) { isMac = true; break; } } if (!(isDos || isMac || isUnix)) { discover(fileName, offset + depth, depth + 1000); } else { // do something clever } }

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  • PRNG test suite: bitstream and stream length

    - by Martin Trigaux
    On the NIST website, there is a tool called sts (Statistical Test Suite) that allow us to rest the validity of a pseudo-random number generator based on a stream of bits in input. When running the program, there is two variables I am not sure to understand : the stream length and number of bitstream. Is the stream length the size of the file ? The number of bit inside ? The size of a bitstream ? Are the bitstreams subset of the whole file ? Chosen how ? Let say I have a text file containing 1,000,000 bits in ascii. What should be my arguments ? You can find the user manual here if needed (I didn't find explanation about what are these variables in it). Thank you

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  • Issues with Rails 3.1 API with Query String to Create action on Mac OSX Mountain Lion

    - by hjaved
    Hi I've been stuck on this problem for a while and would appreciate your help. I'm writing an API to allow an external source like a Browser Query String or a smartphone to enter some model User info in a form and hit the User create action to write the data to the db. Please tell me what I'm doing wrong with the code below. I've also observed that if I have code like @user = User.new(params[:user]), that this approach only works when a user enters their data within the form. And that if I have code such as @user = User.new( name: params[:name], location: params[:location], password = params[:password], email: params[:email]), that this code ONLY works for a Query string entry, but NOT both Query string AND regular form submission. Why is that and how can I write the code above in the Users Controller Create action, so that it takes care of both situations? URL used: localhost:3000/users/create?name=John&&[email protected]&&password=secret&&location=SanFrancisco&date=06122012 The date is of type string but it doesn't show up in the database. Why? Everything else does. UsersController.rb def create @user = User.new(params[:user]) if @user.save session[:uid] = @user.id redirect_to thanks_path, notice: "Welcome #{@user.name}!" else redirect_to root_path end end New User Form: <%=u.text_field :name, placeholder: "Name"%><br> <%=u.text_field :email, placeholder: "Email"%><br> <%=u.password_field :password, placeholder: "Password"%><br> <%=u.text_field :location, placeholder: "City"%><br> <%=u.text_field :date, placeholder: "Date"%><br> <%if params[:partner_id]%> <%=u.hidden_field :partner_id, value: params[:partner_id]%> <%end%> <button class="btn btn-large btn-primary">Enter</button> I also tried to create a separate method called remotecreate for User creation for something other than a regular web form. I entered remotecreate in the Query string but it didn't work. def remotecreate @user = User.create(name: params[:name], email: params[:email], password: params[:password], location: params[:location], date: params[:date]) if @user.save session[:uid] = @user.id redirect_to thanks_path, notice: "Welcome #{@user.name}" else redirect_to root_path end end Thanks!

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  • SQL Server 2005 Express: upgrading to SP3 in mixed-mode installations

    - by Jeroen Pluimers
    I'm having trouble upgrading SQL Server 2005 Express SP1 to SP3. The SP1 install uses mixed mode authentication (so there is an sa password). This is the message I get: TITLE: Microsoft SQL Server Setup ------------------------------ None of the selected features can be installed or upgraded. Setup cannot proceed since no effective change is being made to the machine. To continue, click Back and then select features to install. To exit SQL Server Setup, click Cancel. For help, click: http://go.microsoft.com/fwlink?LinkID=20476&ProdName=Microsoft+SQL+Server&ProdVer=9.00.4035.00&EvtSrc=setup.rll&EvtID=SQLSetup90&EvtType=28108 ------------------------------ BUTTONS: OK ------------------------------ The link then tells me To continue you must provide a strong sa password. I tried some searching, and found something about BPAClient.dll, but this batch-file does not fix it: mkdir "%ProgramFiles%\Microsoft SQL Server\90\Setup Bootstrap\BPA\BPAClient" copy "%ProgramFiles%\Microsoft SQL Server\90\Setup Bootstrap\BPA\bin\BPAClient.dll" "%ProgramFiles%\Microsoft SQL Server\90\Setup Bootstrap\BPA\BPAClient\" So I think the clue is the strong in the link above. Am I on the right track? Where do I find more information on the strongness of an sa password? --jeroen (who will adjust the question when he has dug further)

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  • WD my cloud 4th is Super Slow

    - by Saduser
    I am using a WD my cloud 4Tb and I have read other posts about users complaining about getting only 10Mb per second. My problem is that I am getting about 100kb/s to transfer a 125gb iPhoto library. Estimated time is 11 days to transfer this file. This is unacceptable. On the back of the WD cloud I am getting a solid green light and from what I read this means that I am on a gigabyte network. I have mac book pro running Mac OS Mavericks. I have tried 4 different cables and turned off my router firewall. I don't run anti-virus nor any firewall on the mac. Other things I have checked: direct connection to both router and WD cloud device. Tried wireless but it is even slower. Previously I was able to transfer a 55Gb iPhoto library in 14 hours which I felt was acceptable. I figured it would take approximately double the time to transfer the 125gb file but 11 days is ridiculous. Any other suggestions? Anything else I can check (how to check it) what is the bottle neck?

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  • Font for Wine that supports the entire character set of the Win32 Console?

    - by Brian Campbell
    I would like to be able to display in the Wine console all characters that the Win32 console can display. I've written a small test program to print out all 8-bit characters: #include <stdio.h> int main(int argc, char *argv[]) { int i, j; for (i = 0; i <= 0xF0; i+=0x10) { for (j = i; j <= i + 0x0F; ++j) printf("%2x:%c", j, (char)j); printf("\n"); } getchar(); return 0; } Under Wine, the best I can do so far is using Andale Mono: While this is what I see on Windows Server 2008: Is there anywhere I can legally download a font that will allow me to view all of those characters under Wine? edit I've found a set of DOS fonts that includes a CP437 font, which should cover the character set I'm interested in. However, even if I install this font, wineconsole doesn't seem to recognize it. Is there any way I can get wineconsole to use this font, or convert this font to a format that wineconsole can use? Or is there any way I can extract fonts from DOSEMU for use in Wine? Oh, and I should probably mention that I'm on Mac OS X 10.6.2, installing Wine via MacPorts, using the wine-devel package. more information I have tried installing some console fonts that should cover the full character set as Mac OS X fonts (such as the NewDOS font listed above, and a font I tried converting from the fonts supplied by DOSEMU). Wine does not seem to pick up on new fonts installed in Mac OS X. Is there a way to register new fonts I've installed with Wine? Would manually editing the system.reg file that seems to contain font mappings work, or is there something else I'd need to do? bump Bounty ends soon, I'm still looking for an answer for this. Does anyone use the Wine console for complex text user interfaces?

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  • OSX root user keeps re-enabling itself on reboot

    - by geodave
    Running Snow Leopard. Completely inexplicably, I seem to have enabled the OSX root user by accident. I honestly have no idea how it happened, but if memory serves I was looking at the login pane (with my two user accounts) when I must have hit something, and suddenly the two accounts were replaced by one that just said "Other..." Clicking the "Other..." account allows me to type a username and password, but neither of the normal two accounts would work. Since I never set a root password, it wouldn't let me in that way either. So I booted into Single User mode and ran these commands: /sbin/mount -uw / fsck -fy launchctl load /System/Library/LaunchDaemons/com.apple.DirectoryServices.plist dscl . -passwd /Users/root newpassword and that let me login as root. Then, I went to System Preferences, Accounts, Login Options, clicked Join, Open Directory Utility, and lastly in the Edit menu I clicked "Disable Root User" Great, I thought, back to normal. Except rebooting, I still only have the Other... account visible, and the root password I set beforehand doesn't work anymore! I have to reboot into Single User Mode and go through the whole process again just to get back into the system (as root) How on Earth did I accidentally enable this? I didn't even know about the Directory Utility before now. And most importantly, why the heck would it be re-enabling the root user on boot? Thanks in advance to any help!

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  • Remote desktop type software that the client need not install anything...

    - by allentown
    I am primarily a Macintosh user, and can usually walk a client though any troubles they may have because I have a Macintosh in front of me. If they are on a different OS, things are close enough, or I cam remember, that I can get by. When trying to help clients on Windows, I get stuck. I do not have access to windows, and even if I did, there are far too many versions of Outlook, all with their various esoteric settings and checkboxes, that I could never see exactly what they are seeing. I mostly need to just help them with email setup. Something like copilot.com may do the trick. What is the simplest remote control software out there, ideally, it would accomplish these: No software needed on remote end, or, a single .exe that they can toss when done. I need Mac based software on my end. I do have ARD, which support VNC Free :) If possible, it would be really nice Needs a port forwarding proxy run by the company. There is no way I can get the user to alter their router, or to even plug directly into their WAN for a short time. On the Mac, I just have them open iChat, and this is all built in, proxying through AIM, looking for the same for Windows and Mac.

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  • Ping server NETBIOS name returns wrong IP and "Destination host unreachable"

    - by music2myear
    Problem server is Windows 2008 R2 VM running on VMWare ESXi 4 host. Single network adapter manually assigned single IP address (192.168.1.11). When I ping the server from any other network computer, it returns 192.168.1.124 and "Destination host unreachable". Yesterday I found a second network adapter assigned to this server with an IP of 169.254... indicating it had no real valid IP. Using the MAC addresses I determined which adapter was not needed/not wanted, and removed it using VMWare systems. This is the network Printer Server and, understandably, nothing is printing right now. I've looked at the solutions here Why was my ping answered by a different IP address than the one pinged? and they aren't applicable to my situation for the following reasons: Output of arp -a on another computer returns the correct IP address (.1.11) assigned to the correct MAC address, the incorrect IP .1.124 is not listed, and the MAC of the network adapter I removed yesterday is not listed at all. I checked out the Microsoft KB article which listed pretty much my exact symptoms ( http://support.microsoft.com/kb/981953 ) and it says to check binding orders and look for hidden adapters. But there are no hidden adapters, and there is only one Network Adapter listed in the Binding Order list. Essentially, I can communicate from the server TO any other network device, but I cannot communicate from any other network device TO the server. Help! UPDATE: Solution found, see this solution for the details.

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  • How to Re-install an App that Shows up in the Appstore as 'Update' Instead of 'Buy App'

    - by Craig Reville
    So long story short: I dropped the wrong app into 'clean my mac' and I hit 'cancel' but it was too late by that point. I rebooted and appstore said it had an update, when I opened appstore it was showing an update for the app I just uninstalled. I tried clicking 'update' but it gives me an error saying it's unable to install after 'downloading'. When I try to go into 'purchased apps' it shows the app as uninstalled so I click 'install' and I get an error saying it's already installed. I'm running Lion OS X, latest version, updated, mac book pro is only a few months old. I tried searching through the entire system to remove all traces of the app, after rebooting appstore no longer shows the app and no longer shows the update but on the apps page it still says 'Update'. I tried reinstalling the app from desktop OUT of the appstore and again says the app is 'already installed'. So after reading more about lion I found an article that spoke about 'BundleID' being the thing that tells appstore what's installed and needing updating however I can't find the location of where the BundleID would be. Any thoughts? I've tried CCleaner, AppCleaner etc and none of them show the app, mainly because it is uninstalled. Update I've spoken to Apple Support who confirmed that there is a file in the system that connects separately to tell the system if there are updates available however they declined to inform me of any further details. Apple also referred me from technical support to iTunes App Store opposed to Mac App Store support and from there I have been referred to AppleCare who are currently 'investigating' this issue. Hopefully there will be a fix that's simple to implement for people having similar issues, this appears to be a more common issue than I previously thought.

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  • Cannot log into Windows XP Embedded after changing computer name

    - by bignis
    Hi everyone, I purchased a tablet pc running Windows XP Embedded. The tablet was used in a medical clinic on a domain. For illustrative purposes, say the computer name was "COMPLEXCOMPUTERNAME". There was an administrator account, so I changed the password on account "COMPLEXCOMPUTERNAME\Administrator" to a blank password. I logged out and logged in successfully with the blank administrator password when the log-in dialog said "Log in to COMPLEXCOMPUTERNAME (this computer)". Next I renamed the computer from COMPLEXCOMPUTERNAME to SIMPLECOMPUTERNAME, which required a reboot. I did so, and I can't log in anymore. The log in screen still just says "Log in to COMPLEXCOMPUTERNAME (this computer)", but the account "COMPLEXCOMPUTERNAME\Administrator" no longer works. I suspect that this is because the computer has been renamed to SIMPLECOMPUTERNAME and it can no longer find the account. The "Log in to" dropdown can't be typed in, so I can't change the computer name Windows is trying to log into. I fear that I'm stuck. Is there a way I can get Windows to log into the computer name that I chose? Thanks! -Mike

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  • General name for Macs' operating system

    - by andy124
    First of all, I hope that my question is fairly suitable for this site. I have a website where I would like to write articles about some operating systems. Therefore, I have created a main category called "Operating systems". Within a subcategory, I would like to write articles about Apple's operating system that is running on Macs. However, I do not know what to name this category. I have always thought the name was just OS X, but come to think about it, the "X" is actually part of the version (10). Therefore I cannot exactly call my category OS X, because what about when OS 11 is released in a few years? And since Apple has gone from Mac OS X to just OS X, then I cannot use "Mac OS". And, if I remove the X from OS X, then I only have "OS" left, which does not seem so proper. I am really looking for a meaningful all-round name for the Macs' operating system that does not involve the versioning. I was thinking about just calling the category "Mac", but that is not precise either - but perhaps the closest I can get?

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  • Get Safari to use different autocompletion on different URLs on same hostname

    - by Luke404
    I have a webserver publishing different services over the same SSL VirtualHost, the two most commonly used being PhpMyAdmin and Cacti. These (and others) use 'cookie' style authentication, asking user and password in an HTML form (thus not using HTTP Authentication). Being on the same hostname, the Safari browser didn't manage too well stored passwords: if I login to one app with user foo, and then go to app two it would propose me user foo and its password in the login form. Changing just the username to bar used to be sufficient to let Safari autocomplete the correct password in its form field. Annoying, but I could live with it - usernames are short and easy to remember when compared to the passwords we use. After the update to safari5 this seems to be no longer true: if I store in safari (actually user keychain on OSX) credentials for https://www.foobarbaz.com/app1 AND credentials for https://www.foobarbaz.com/app2 there seem to be no way for it to autocomplete both based on the url. Even editing the keychain to add the path (it will store only the hostname by default) does not help. Is there anything I can do to let it work the way I want while still keeping everything on one hostname? Modifying anything server side is of course possible, but I can't switch apps to HTTP Auth (and not every one will support it anyway) to use different 'realms'.

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