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  • How to get current datetime on windows command line, in a suitable format for using in a filename?

    - by Rory
    What's a windows command line statement(s) I can use to get the current datetime in a format that I can put into a filename? I want to have a .bat file that zips up a directory into an archive with the current date & time as part of the name, eg "Code_2008-10-14_2257.zip". Is there any easy way I can do this, independent of the regional settings of the machine? I don't really mind about the date format, ideally it'd be yyyy-mm-dd but anything simple is fine. So far I've got this, which on my machine gives me "Tue_10_14_2008_230050_91" rem Get the datetime in a format that can go in a filename. set _my_datetime=%date%_%time% set _my_datetime=%_my_datetime: =_% set _my_datetime=%_my_datetime::=% set _my_datetime=%_my_datetime:/=_% set _my_datetime=%_my_datetime:.=_% rem now use the timestamp by in a new zip file name "d:\Program Files\7-Zip\7z.exe" a -r Code_%_my_datetime%.zip Code I can live with this but it seems a bit clunky. Ideally it'd be briefer and have the format mentioned earlier. I'm using Windows Server 2003 and Win XP Pro. I don't want to install additional utilities to achieve this (although I realise there are some that will do nice date formatting).

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  • drupal themes: .info file: how do I add more than 1 css file / js file to my theme?

    - by egarcia
    I'm creating a new Drupal theme. Until now, I only needed to include a single css file and a single js file. So my theme.info file had something like this: stylesheets[all][] = css/style.css scripts[] = js/script.js Now I must include jquery and jquery-ui in order to use a calendar date. These come with 2 new javascript files, and 1 additonal css file that I must add to the site. The calendar input form is going to be used in all pages (on a side block) so it is ok for me to load the extra css/javascript on all pages. I think the easiest thing would be to reference them on the .info file itself. At first I tried to just put them there with separate spaces: stylesheets[all][] = css/style.css css/ui-lightness/jquery-ui-1.8.1.custom.css scripts[] = js/jquery-1.4.2.min.js js/jquery-ui-1.8.1.custom.min.js js/reservations.js I emptied drupal's cache and... none of them loaded. I then tried separating each file with a comma, and flushing the cache again. Same result. I've browsed some drupal pages, but could not find how to add several javascript/css files on one theme (they always seem to add just 1 of each). So, how do I include several css/javascript files on the .info file?

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  • Unable to parse variable length string separated by delimiter

    - by Technext
    Hi, I have a problem with parsing a string, which consists only of directory path. For ex. My input string is Abc\Program Files\sample\ My output should be Abc//Program Files//sample The script should work for input path of any length i.e., it can contain any no. of subdirectories. (For ex., abc\temp\sample\folder\joe) I have looked for help in many links but to no avail. Looks like FOR command extracts only one whole line or a string (when we use ‘token’ keyword in FOR syntax) but my problem is that I am not aware of the input path length and hence, the no. of tokens. My idea was to use \ as a delimiter and then extract each word before and after it (), and put the words to an output file along with // till we reach the end of the string. I tried implementing the following but it did not work: @echo off FOR /F "delims=\" %%x in (orig.txt) do ( IF NOT %%x == "" echo.%%x//output.txt ) The file orig.txt contains only one line i.e, Abc\Program Files\sample\ The output that I get contains only: Abc// The above output contains blank spaces as well after ‘Abc//’ My desired output should be: Abc//program Files//sample// Can anyone please help me with this? Regards, Technext

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  • PHP: parse $_FILES[] data in multidimesional array

    - by superUntitled
    Example form here: http://jsfiddle.net/superuntitled/uaTtx/1/ I have a form that allows for dynamic duplication of the form fields. The form allows for file uploads and text input, so the data is sent in both $_POST and $_FILES arrays. The the initial set of inputs look like this: <input type="text" name="question[1][text]" /> <input type="file" name="question[1][file]" /> <input type="text" class="a" name="answer[1][text][]" /> <input type="file" name="answer[1][file][]" /> When duplicated the fields are incremented, they look like this: <input type="text" name="question[2][text]" /> <input type="file" name="question[2][file]" /> <input type="text" class="a" name="answer[2][text][]" /> <input type="file" name="answer[2][file][]" /> To complicate matters, the "answer" form fields can also be duplicated (thus the [] at the end of the 'answer' name array. How can I parse the posted $_FILES array? I have tried something like this: foreach ($_FILES['question'] as $p_num) { echo $p_num['file']['name']; foreach ($_FILES['answer'] as $a_num) { echo $a_num['file']['name']; } } but I get an "Undefined index: file... " error. How can I parse out the posted values.

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  • Reading and writing to files simultaneously?

    - by vipersnake005
    Moved the question here. Suppose, I want to store 1,000,000,000 integers and cannot use my memory. I would use a file(which can easily handle so much data ). How can I let it read and write and the same time. Using fstream file("file.txt', ios::out | ios::in ); doesn't create a file, in the first place. But supposing the file exists, I am unable to use to do reading and writing simultaneously. WHat I mean is this : Let the contents of the file be 111111 Then if I run : - #include <fstream> #include <iostream> using namespace std; int main() { fstream file("file.txt",ios:in|ios::out); char x; while( file>>x) { file<<'0'; } return 0; } Shouldn't the file's contents now be 101010 ? Read one character and then overwrite the next one with 0 ? Or incase the entire contents were read at once into some buffer, should there not be atleast one 0 in the file ? 1111110 ? But the contents remain unaltered. Please explain. Thank you.

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  • Windows 7: Can't see ISO file in C:\

    - by cbp
    I used DVD shrink to create an ISO file and saved it into C:\ The ISO file is visible with some programs but not with others. The file is not hidden as far as I am aware. But it cannot be seen by Windows Explorer, DVD Decrypter or a bunch of other programs. If I search for the file using Windows 7's Start Menu search tool, I can see the file and I can right click and select Properties. The Properties window appears OK, but if I try to change tabs on the property window, I receive an error message as though the file is not there. DVD Shrink can still open the file OK. I can also find the file using Agent Ransack (a file searching tool), but then I cannot open it. What gives?

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  • optimizing file share performance on Win2k8?

    - by Kirk Marple
    We have a case where we're accessing a RAID array (drive E:) on a Windows Server 2008 SP2 x86 box. (Recently installed, nothing other than SQL Server 2005 on the server.) In one scenario, when directly accessing it (E:\folder\file.xxx) we get 45MBps throughput to a video file. If we access the same file on the same array, but through UNC path (\server\folder\file.xxx) we get about 23MBps throughput with the exact same test. Obviously the second test is going through more layers of the stack, but that's a major performance hit. What tuning should we be looking at for making the UNC path be closer in performance to the direct access case? Thanks, Kirk (corrected: it is CIFS not SMB, but generalized title to 'file share'.) (additional info: this happens during the read from a single file, not an issue across multiple connections. the file is on the local machine, but exposed via file share. so client and file server are both same Windows 2008 server.)

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  • undelete big files - mission impossible?

    - by johnrembo
    Hi, I've accidentaly deleted outlook.pst (6.7GB) file, while there was only 400MB free space left on primary NTFS partition (winxp). I've tried several recovery tools to get this file back. "Ontrack Easy Recovery Pro" found 0 pst files (complete scan mode), while "Recover My Files" in sector scan mode found 5 pst's, but 4 of them of sizes from 3 to 28 KB, while the 5th one - 1Gb. I've managed to succesfuly recover 1Gb pst file, which was 1 year old copy (the one used after the latest windows reinstall). Now, I'm frustrated and confused Why 1 year old file was succesfuly recovered if there were only 400MB left on primary partition? Where's 6.7GB file gone? I did some reading (i.e. here), and it seems that there's almost no probability to retrieve the file I'm looking for, but wait - none of recovery tools i've used found zero-sized pst file, moreover - if due to fragmentation a file might be corrupted - we could use scanpst.exe to fix some errors and survive with 10 or 100 emails missing - whatever. Could you please recommend some more sophisticated recovery tools for this particular task? Appretiate your help - thanks in advance

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  • Is it possible to download extremely large files intelligently or in parts via SSH from Linux to Windows?

    - by Andrew
    I have a ~35 GB file on a remote Linux Ubuntu server. Locally, I am running Windows XP, so I am connecting to the remote Linux server using SSH (specifically, I am using a Windows program called SSH Secure Shell Client version 3.3.2). Although my broadband internet connection is quite good, my download of the large file often fails with a Connection Lost error message. I am not sure, but I think that it fails because perhaps my internet connection goes out for a second or two every several hours. Since the file is so large, downloading it may take 4.5 to 5 hours, and perhaps the internet connection goes out for a second or two during that long time. I think this because I have successfully downloaded files of this size using the same internet connection and the same SSH software on the same computer. In other words, sometimes I get lucky and the download finishes before the internet connection drops for a second. Is there any way that I can download the file in an intelligent way -- whereby the operating system or software "knows" where it left off and can resume from the last point if a break in the internet connection occurs? Perhaps it is possible to download the file in sections? Although I do not know if I can conveniently split my file into multiple files -- I think this would be very difficult, since the file is binary and is not human-readable. As it is now, if the entire ~35 GB file download doesn't finish before the break in the connection, then I have to start the download over and overwrite the ~5-20 GB chunk that was downloaded locally so far. Do you have any advice? Thanks.

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  • how to write or what is the concept behind the file unlocker program

    - by Jach Many
    Recently i was trying to delete a file thinking that i had closed the program which is manipulating the file but it did not delete because the program was still running. I misunderstood that file as an unwanted file. So i used the file unlocker program to find which process is manipulating that file. That program really worked well by showing the process which was handling that file. and that file was http://download.cnet.com/Unlocker/3000-2248_4-10493998.html. What i want to know is i would like to write a program in win32 C or .net to mimic the same process. Just to find which process is handling which file. and if possible to close it. Or i want to know the concept behind that. I know this cannot be explained in a few paragraphs yet if i could get some references or external links to references then that could be nice.

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  • Pass string between two threads in java

    - by geeta
    I have to search a string in a file and write the matched lines to another file. I have a thread to read a file and a thread to write a file. I want to send the stringBuffer from read thread to write thread. Please help me to pass this. I amm getting null value passed. write thread: class OutputThread extends Thread{ /****************** Writes the line with search string to the output file *************/ Thread runner1,runner; File Out_File; public OutputThread() { } public OutputThread(Thread runner,File Out_File) { runner1 = new Thread(this,"writeThread"); // (1) Create a new thread. this.Out_File=Out_File; this.runner=runner; runner1.start(); // (2) Start the thread. } public void run() { try{ BufferedWriter bufferedWriter=new BufferedWriter(new FileWriter(Out_File,true)); System.out.println("inside write"); synchronized(runner){ System.out.println("inside wait"); runner.wait(); } System.out.println("outside wait"); // bufferedWriter.write(line.toString()); Buffer Buf = new Buffer(); bufferedWriter.write(Buf.buffers); System.out.println(Buf.buffers); bufferedWriter.flush(); } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } } Read Thraed: class FileThread extends Thread{ Thread runner; File dir; String search_string,stats; File Out_File,final_output; StringBuffer sb = new StringBuffer(); public FileThread() { } public FileThread(CountDownLatch latch,String threadName,File dir,String search_string,File Out_File,File final_output,String stats) { runner = new Thread(this, threadName); // (1) Create a new thread. this.dir=dir; this.search_string=search_string; this.Out_File=Out_File; this.stats=stats; this.final_output=final_output; this.latch=latch; runner.start(); // (2) Start the thread. } public void run() { try{ Enumeration entries; ZipFile zipFile; String source_file_name = dir.toString(); File Source_file = dir; String extension; OutputThread out = new OutputThread(runner,Out_File); int dotPos = source_file_name.lastIndexOf("."); extension = source_file_name.substring(dotPos+1); if(extension.equals("zip")) { zipFile = new ZipFile(source_file_name); entries = zipFile.entries(); while(entries.hasMoreElements()) { ZipEntry entry = (ZipEntry)entries.nextElement(); if(entry.isDirectory()) { (new File(entry.getName())).mkdir(); continue; } searchString(runner,entry.getName(),new BufferedInputStream(zipFile.getInputStream(entry)),Out_File,final_output,search_string,stats); } zipFile.close(); } else { searchString(runner,Source_file.toString(),new BufferedInputStream(new FileInputStream(Source_file)),Out_File,final_output,search_string,stats); } } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } /********* Reads the Input Files and Searches for the String ******************************/ public void searchString(Thread runner,String Source_File,BufferedInputStream in,File output_file,File final_output,String search,String stats) { int count = 0; int countw = 0; int countl=0; String s; String[] str; String newLine = System.getProperty("line.separator"); try { BufferedReader br2 = new BufferedReader(new InputStreamReader(in)); //OutputFile outfile = new OutputFile(); BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(output_file,true)); Buffer Buf = new Buffer(); //StringBuffer sb = new StringBuffer(); StringBuffer sb1 = new StringBuffer(); while((s = br2.readLine()) != null ) { str = s.split(search); count = str.length-1; countw += count; if(s.contains(search)){ countl++; sb.append(s); sb.append(newLine); } if(countl%100==0) { System.out.println("inside count"); Buf.setBuffers(sb.toString()); sb.delete(0,sb.length()); System.out.println("outside notify"); synchronized(runner) { runner.notify(); } //outfile.WriteFile(sb,bufferedWriter); //sb.delete(0,sb.length()); } } } synchronized(runner) { runner.notify(); } br2.close(); in.close(); if(countw == 0) { System.out.println("Input File : "+Source_File ); System.out.println("Word not found"); System.exit(0); } else { System.out.println("Input File : "+Source_File ); System.out.println("Matched word count : "+countw ); System.out.println("Lines with Search String : "+countl); System.out.println("Output File : "+output_file.toString()); System.out.println(); } } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } }

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  • Java Client-Server problem when sending multiple files

    - by Jim
    Client public void transferImage() { File file = new File(ServerStats.clientFolder); String[] files = file.list(); int numFiles = files.length; boolean done = false; BufferedInputStream bis; BufferedOutputStream bos; int num; byte[] byteArray; long count; long len; Socket socket = null ; while (!done){ try{ socket = new Socket(ServerStats.imgServerName,ServerStats.imgServerPort) ; InputStream inStream = socket.getInputStream() ; OutputStream outStream = socket.getOutputStream() ; System.out.println("Connected to : " + ServerStats.imgServerName); BufferedReader inm = new BufferedReader(new InputStreamReader(inStream)); PrintWriter out = new PrintWriter(outStream, true /* autoFlush */); for (int itor = 0; itor < numFiles; itor++) { String fileName = files[itor]; System.out.println("transfer: " + fileName); File sentFile = new File(fileName); len = sentFile.length(); len++; System.out.println(len); out.println(len); out.println(sentFile); //SENDFILE bis = new BufferedInputStream(new FileInputStream(fileName)); bos = new BufferedOutputStream(socket.getOutputStream( )); byteArray = new byte[1000000]; count = 0; while ( count < len ){ num = bis.read(byteArray); bos.write(byteArray,0,num); count++; } bos.close(); bis.close(); System.out.println("file done: " + itor); } done = true; }catch (Exception e) { System.err.println(e) ; } } } Server public static void main(String[] args) { BufferedInputStream bis; BufferedOutputStream bos; int num; File file = new File(ServerStats.serverFolder); if (!(file.exists())){ file.mkdir(); } try { int i = 1; ServerSocket socket = new ServerSocket(ServerStats.imgServerPort); Socket incoming = socket.accept(); System.out.println("Spawning " + i); try { try{ if (!(file.exists())){ file.mkdir(); } InputStream inStream = incoming.getInputStream(); OutputStream outStream = incoming.getOutputStream(); BufferedReader inm = new BufferedReader(new InputStreamReader(inStream)); PrintWriter out = new PrintWriter(outStream, true /* autoFlush */); String length2 = inm.readLine(); System.out.println(length2); String filename = inm.readLine(); System.out.println("Filename = " + filename); out.println("ACK: Filename received = " + filename); //RECIEVE and WRITE FILE byte[] receivedData = new byte[1000000]; bis = new BufferedInputStream(incoming.getInputStream()); bos = new BufferedOutputStream(new FileOutputStream(ServerStats.serverFolder + "/" + filename)); long length = (long)Integer.parseInt(length2); length++; long counter = 0; while (counter < length){ num = bis.read(receivedData); bos.write(receivedData,0,num); counter ++; } System.out.println(counter); bos.close(); bis.close(); File receivedFile = new File(filename); long receivedLen = receivedFile.length(); out.println("ACK: Length of received file = " + receivedLen); } finally { incoming.close(); } } catch (IOException e){ e.printStackTrace(); } } catch (IOException e1){ e1.printStackTrace(); } } The code is some I found, and I have slightly modified it, but I am having problems transferring multiple images over the server. Output on Client: run ServerQueue.Client Connected to : localhost transfer: Picture 012.jpg 1312743 java.lang.ArrayIndexOutOfBoundsException Connected to : localhost transfer: Picture 012.jpg 1312743 Cant seem to get it to transfer multiple images. But bothsides I think crash or something because the file never finishes transfering

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  • Creando un File Upload

    - by jaullo
    Para iniciar hablaremos un poco sobre el control File Upload, de esta forma daremos una idea general de que es y como trabaja. El File Upload es un control de asp.net que permite que los usuarios seleccionen un archivo de cualquier ubicación en el equipo y lo suban a un directorio predeterminado a traves de una página asp.net. En principio este control esta limitado para no permitir subir archivos de mas de 4 MB. Sin embargo, desde el webconfig de nuestra aplicacón podremos cambiar ese valor, ya sea para aumentarlo o bien para disminuirlo. Nuestro ejemplo, se enfocará en crear un webcontrol que permita seleccionar un archivo y guardarlo, asi que empecemos. Lo primero será agregar a nuestra página un webcontrol que llamaremos Upload.ascx Posteriormente en nuestro webcontrol, agregamos el siguiente código: <table style="width: 100%">         <tr>             <td colspan="3">             <div align="center">                  <asp:Label ID="Label1" runat="server" Text="File Upload"></asp:Label>              </div>             </td>                    </tr>         <tr>             <td style="width: 456px" rowspan="2">                                                             &nbsp;</td>             <td style="width: 386px">                                <div align="center">                         <asp:FileUpload ID="FileUpload1" runat="server" Height="24px" Width="243px" />                         <span id="Span1" runat="server" />                            </div>                      </td>             <td rowspan="2">                                                             </td>         </tr>         <tr>             <td style="width: 386px">                 <div align="center">                      <asp:ImageButton Id="btnupload" runat="server" OnClick="btnupload_Click"                     ImageUrl="~/Styles/img/upload.png" style="text-align: center" />           </div>                  </td>         </tr>         <tr>             <td colspan="3">                 &nbsp;</td>         </tr>     </table>  De esta forma nuestro control deberá verse algo así   Por último en el code behin de nuestro control agregamos el código a nuestro boton, el cual será el encargado de leer el archivo que se encuentra en el File Upload y guardarlo en la ruta especificada.  Protected Sub btnupload_Click(ByVal sender As Object, ByVal e As System.Web.UI.ImageClickEventArgs) Handles btnupload.Click         If FileUpload1.HasFile Then             Dim fileExt As String             fileExt = System.IO.Path.GetExtension(FileUpload1.FileName)             If (fileExt = ".exe") Then                 Label1.Text = "You can´t upload .exe file!"             Else                 Try                     FileUpload1.SaveAs(decrpath & _                        FileUpload1.FileName)                     Label1.Text = "File name: " & _                       FileUpload1.PostedFile.FileName & "<br>" & _                       "File Size: " & _                       FileUpload1.PostedFile.ContentLength & " kb<br>" & _                       "Content type: " & _                       FileUpload1.PostedFile.ContentType                 Catch ex As Exception                     Label1.Text = "ERROR: " & ex.Message.ToString()                 End Try             End If         Else             Label1.Text = "You have not specified a file!"         End If            End Sub   Como vemos en el código anterior tambien hemos agregado otros elementos los cuales nos dirán el nombre del archivo, el tipo de contenido y el tamaño en kb una vez que el archivo ha sido súbido al servidor. Por último deben tomar en cuenta que decrpath es la ruta en donde será subido el archivo, la cual deben variar a su gusto.

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    I'm new to ofbiz so try to keep your answer as simple as possibly. If you can give examples that would be kind. My problem is I created a project inside the ofbiz/hot-deploy folder namely productionmgntSystem. Inside the folder ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem I created a file app_details_1.ftl. The following are the code of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server. The file is get from user " tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1". But the file is not uploaded. Give me a good solution for uploading a file to the server.

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  • Oracle Releases New Mainframe Re-Hosting in Oracle Tuxedo 11g

    - by Jason Williamson
    I'm excited to say that we've released our next generation of Re-hosting in 11g. In fact I'm doing some hands-on labs now for our Systems Integrators in Italy in a couple of weeks and targeting Latin America next month. If you are an SI, or Rehosting firm and are looking to become an Oracle Partner or get a better understanding of Tuxedo and how to use the workbench for rehosting...drop me a line. Oracle Tuxedo Application Runtime for CICS and Batch 11g provides a CICS API emulation and Batch environment that exploits the full range of Oracle Tuxedo's capabilities. Re-hosted applications run in a multi-node, grid environment with centralized production control. Also, enterprise integration of CICS application services benefits from an open and SOA-enabled framework. Key features include: CICS Application Runtime: Can run IBM CICS applications unchanged in an application grid, which enables the distribution of large workloads across multiple processors and nodes. This simplifies CICS administration and can scale to over 100,000 users and over 50,000 transactions per second. 3270 Terminal Server: Protects business users from change through support for tn3270 terminal emulation. Distributed CICS Resource Management: Simplifies deployment and administration by allowing customers to run CICS regions in a distributed configuration. Batch Application Runtime: Provides robust IBM JES-like job management that enables local or remote job submissions. In addition, distributed batch initiators can enable parallelization of jobs and support fail-over, shortening the batch window and helping to meet stringent SLAs. Batch Execution Environment: Helps to run IBM batch unchanged and also supports JCL functionality and all common batch utilities. Oracle Tuxedo Application Rehosting Workbench 11g provides a set of automated migration tools integrated around a central repository. The tools provide high precision which results in very low error rates and the ability to handle large applications. This enables less expensive, low-risk migration projects. Key capabilities include: Workbench Repository and Cataloguer: Ensures integrity of the migrated application assets through full dependency checking. The Cataloguer generates and maintains all relevant meta-data on source and target components. File Migrator: Supports reliable migration of datasets and flat files to an ISAM or Oracle Database 11g. This is done through the automated migration utilities for data unloading, reloading and validation. It also generates logical access functions to shield developers from data repository changes. DB2 Migrator: Similarly, this tool automates the migration of DB2 schema and data to Oracle Database 11g. COBOL Migrator: Supports migration of IBM mainframe COBOL assets (OLTP and Batch) to open systems. Adapts programs for compiler dialects and data access variations. JCL Migrator: Supports migration of IBM JCL jobs to a Tuxedo ART environment, maintaining the flow and characteristics of batch jobs.

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  • Sorted list of file names in a folder in VBA?

    - by Karsten W.
    Is there a way to get a sorted list of file names of a folder in VBA? Up to now, I arrived at Dim fso As Object Dim objFolder As Object Dim objFileList As Object Dim vFile As Variant Dim sFolder As String sFolder = "C:\Docs" Set fso = CreateObject("Scripting.FileSystemObject") Set objFolder = fso.GetFolder(sFolder) Set objFileList = objFolder.Files For Each vFile In objFileList ' do something ' Next vFile but it is crucial to be sure the processing order of the for loop is determined by the file names... Any help appreciated!

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  • MS-DOS find command

    - by mihai
    Hi, I have the following command: find Acc*\bin\Debug\*.pdb > temp.txt Looking in temp.txt, I have: Accounting/bin/Debug/Accounting.pdb Accounting/bin/Debug/BackendProcess.pdb NOTE the forward slashes. Why does it output file names like this? And how do I get it to output backslashes, so I can use del on those files? Thanks

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  • Linking the Linker script file to source code

    - by user304097
    Hello , I am new to GNU compiler. I have a C source code file which contains some structures and variables in which I need to place certain variables at a particular locations. So, I have written a linker script file and used the __ attribute__("SECTION") at variable declaration, in C source code. I am using a GNU compiler (cygwin) to compile the source code and creating a .hex file using -objcopy option, but I am not getting how to link my linker script file at compilation to relocate the variables accordingly. I am attaching the linker script file and the C source file for the reference. Please help me link the linker script file to my source code, while creating the .hex file using GNU. /*linker script file*/ /*defining memory regions*/ MEMORY { base_table_ram : org = 0x00700000, len = 0x00000100 /*base table area for BASE table*/ mem2 : org =0x00800200, len = 0x00000300 /* other structure variables*/ } /*Sections directive definitions*/ SECTIONS { BASE_TABLE : { } > base_table_ram GROUP : { .text : { } { *(SEG_HEADER) } .data : { } { *(SEG_HEADER) } .bss : { } { *(SEG_HEADER) } } > mem2 } C source code: const UINT8 un8_Offset_1 __attribute__((section("BASE_TABLE"))) = 0x1A; const UINT8 un8_Offset_2 __attribute__((section("BASE_TABLE"))) = 0x2A; const UINT8 un8_Offset_3 __attribute__((section("BASE_TABLE"))) = 0x3A; const UINT8 un8_Offset_4 __attribute__((section("BASE_TABLE"))) = 0x4A; const UINT8 un8_Offset_5 __attribute__((section("BASE_TABLE"))) = 0x5A; const UINT8 un8_Offset_6 __attribute__((section("SEG_HEADER"))) = 0x6A; My intention is to place the variables of section "BASE_TABLE" at the address defined i the linker script file and the remaining variables at the "SEG_HEADER" defined in the linker script file above. But after compilation when I look in to the .hex file the different section variables are located in different hex records, located at an address of 0x00, not the one given in linker script file . Please help me in linking the linker script file to source code. Are there any command line options to link the linker script file, if any plese provide me with the info how to use the options. Thanks in advance, SureshDN.

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  • How to add the time stamp to the log file

    - by swati
    ello Everyone, I am new to using apache logger . I have downloaded the log4j-xx and i have the following text configuration file Set root logger level to DEBUG and its only appender to mainFormat. log4j.rootLogger = TRACE, mainFormat, FILE mainFormat is set to be a ConsoleAppender. log4j.appender.mainFormat=org.apache.log4j.ConsoleAppender mainFormat uses PatternLayout. log4j.appender.mainFormat.layout=org.apache.log4j.PatternLayout log4j.appender.mainFormat.layout.ConversionPattern=%d [%t] %-5p %c - %m%n File makes a file of the output. log4j.appender.FILE=org.apache.log4j.FileAppender log4j.appender.FILE.File=log4j_HAPR001_OutputFile.log log4j.appender.FILE.layout=org.apache.log4j.PatternLayout log4j.appender.FILE.layout.ConversionPattern=%d [%t] %-5p %c - %m%n i use the above config file to create the log file. Now i wanted to add the current time stamp to the log file. Is there any way to do this. If yes can some one please give me the instructions how to do. Thanks in advance.

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  • store SID in a variable

    - by user361191
    Hi, I need a way to store the current user's SID in a variable, I tried a lot of variants of: setlocal enableextensions for /f "tokens=*" %%a in ( '"wmic path win32_useraccount where name='%UserName%' get sid"' ) do ( if not "%%a"=="" set myvar=%%a echo/%%myvar%%=%myvar% pause endlocal None are working wmic path win32_useraccount where name='%UserName%' get sid should be returning 3 lines, i need the second one stored in a variabel Can someone fix my script? edit btw; I am using a .cmd file

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  • Sending Email with attachment, sends a blank file.

    - by pankaj
    I am using this code: File myDir = new File(getApplicationContext().getFilesDir().getAbsolutePath()); try { Log.i("CSV Testing ", "CSV file creating"); FileWriter fw = new FileWriter(myDir + "/myfile.csv"); // // write data to file // Log.i("CSV Testing ", "CSV file created and your data has been saved"); // Process for sending email with CSV file File CSVFile = new File(myDir,"myfile.csv"); if(CSVFile.exists()) { Log.i("CSV FILE", "CSV file exists"); } else { Log.i("CSV FILE", "CSV file not exists"); } Log.i("SEND EMAIL TESTING", "Email sending"); Intent emailIntent = new Intent(android.content.Intent.ACTION_SEND); emailIntent.setType("text/csv"); emailIntent .putExtra(android.content.Intent.EXTRA_EMAIL, new String[]{"myemailid"}); emailIntent .putExtra(android.content.Intent.EXTRA_SUBJECT, "my subject"); emailIntent .putExtra(android.content.Intent.EXTRA_TEXT, "_____________\n Regards \n Pankaj \n ____________ "); emailIntent.putExtra(Intent.EXTRA_STREAM, Uri.parse("file://" + CSVFile.getAbsolutePath())); emailIntent.setType("message/rfc822"); // Shows all application that supports SEND activity try { startActivity(Intent.createChooser(emailIntent, "Send mail...")); } catch (android.content.ActivityNotFoundException ex) { showMSG("There are no email clients installed."); } Log.i("SEND EMAIL TESTING", "Email sent"); } catch (FileNotFoundException e) { Log.i("ExportCSV Exception", e.toString()); } catch (IOException e) { Log.i("ExportCSV Exception", e.toString()); } But it sends myfile.csv as a blank file. I checked it from file explorer, where myfile.csv is not blank and contains right data. How can I solve this?

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  • PHP Mcrypt - Encrypting / Decrypting file

    - by whitman6732
    Trying to write a couple of functions that will encrypt or decrypt a file and am using the class found here to try and accomplish this: http://www.itnewb.com/v/PHP-Encryption-Decryption-Using-the-MCrypt-Library-libmcrypt The encryption function below seems to work, in that it appears to encrypt the file and place it in the intended directory. I'm trying to decrypt the file now, and it just dies with the message "Failed to complete decryption" (which is coded in there...) There's nothing in the php error logs, so I'm not sure why it's failing, but as mcrypt is entirely new to me, I'm more than inclined to believe I'm doing something wrong here... Here are the functions: //ENCRYPT FILE function encryptFile() { global $cryptastic; $pass = PGPPASS; $salt = PGPSALT; $key = $cryptastic->pbkdf2($pass, $salt, 1000, 32) or die("Failed to generate secret key."); if ($handle = opendir(PATH.'/ftpd')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { $newfile = PATH.'/encrypted/'.$file.'.txt'; $msg = file_get_contents(PATH.'/ftpd/'.$file); $encrypted = $cryptastic->encrypt($msg, $key) or die("Failed to complete encryption."); $nfile = fopen($newfile, 'w'); fwrite($nfile, $encrypted); fclose($nfile); unlink(PATH.'/ftpd/'.$file); } } closedir($handle); } //DECRYPT FILE function inFTP() { global $cryptastic; $pass = PGPPASS; $salt = PGPSALT; $key = $cryptastic->pbkdf2($pass, $salt, 1000, 32) or die("Failed to generate secret key."); if ($handle = opendir(PATH.'/encrypted')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { $newfile = PATH.'/decrypted/'.$file; $msg = PATH.'/encrypted/'.$file; $decrypted = $cryptastic->decrypt($msg, $key) or die("Failed to complete decryption."); $nfile = fopen($newfile, 'w'); fwrite($nfile, $decrypted); fclose($nfile); //unlink(PATH.'/encrypted/'.$file); } } closedir($handle); } //$crypt->decrypt($file); }

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  • Make CMD sensitive to use with MySQL?

    - by acidzombie24
    I have a cleanup scrip in a bat file and i wanted to do the below but the problem is i get a mysql error saying unknown database and showing it as testdb. I guess i can change my code testdb but i would like to know. How do i have windows cmd use case sensitivity so i can execute queries properly instead of always in lower case? mysql.exe -u root -q "drop database TestDB; create database TestDB;"

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