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• Question about joins and table with Millions of rows

  - by xRobot

  I have to create 2 tables: Magazine ( 10 millions of rows with these columns: id, title, genres, printing, price ) Author ( 180 millions of rows with these columns: id, name, magazine_id ) . Every author can write on ONLY ONE magazine and every magazine has more authors. So if I want to know all authors of Motors Magazine, I have to use this query: SELECT * FROM Author, Magazine WHERE ( Author.id = Magazine.id ) AND ( genres = 'Motors' ) The same applies to Printing and Price column. To avoid these joins with tables of millions of rows, I thought to use this tables: Magazine ( 10 millions of rows with this column: id, title, genres, printing, price ) Author ( 180 millions of rows with this column: id, name, magazine_id, genres, printing, price ) . and this query: SELECT * FROM Author WHERE genres = 'Motors' Is it a good approach ? I can use Postgresql or Mysql.

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• Why is doing a top(1) on an indexed column in SQL Server slow?

  - by reinier

  I'm puzzled by the following. I have a DB with around 10 million rows, and (among other indices) on 1 column (campaignid_int) is an index. Now I have 700k rows where the campaignid is indeed 3835 For all these rows, the connectionid is the same. I just want to find out this connectionid. use messaging_db; SELECT TOP (1) connectionid FROM outgoing_messages WITH (NOLOCK) WHERE (campaignid_int = 3835) Now this query takes approx 30 seconds to perform! I (with my small db knowledge) would expect that it would take any of the rows, and return me that connectionid If I test this same query for a campaign which only has 1 entry, it goes really fast. So the index works. How would I tackle this and why does this not work? edit: estimated execution plan: select (0%) - top (0%) - clustered index scan (100%)

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• SQL to get friends AND friends of friends of a user

  - by Enrique

  My MySQL tables structure is like this. USER int id varchar username FRIEND_LIST int user_id int friend_id For each friend relationship I insert 2 records in FRIEND_LIST. If user 1 is friend of user 2 then the next rows are inserted into FRIEND_LIST 1,2 2,1 I want to get the friends and friends of friends of an specific user. The select should return columns a, b, c. a: user_id b: friend_id c: username (username of friend_id ) If 1 is friend of 2 and 3. 2 is friend of 3, 4 and 5 3 is friend of 5,6,7 Then the query to get 1's friends and friends of friends should return: 1 2 two 1 3 three 2 1 one 2 3 three 2 4 four 2 5 five 3 1 one 3 5 five 3 6 six 3 7 seven Can I get this rows with a single query?

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• PHP While Loops from Arrays

  - by Michael

  I have a table that contains members names and a field with multiple ID numbers. I want to create a query that returns results where any values in the ID fields overlap with any values in the array. For example: lastname: Smith firstname: John id: 101, 103 I have Array #1 with the values 101, 102, 103 I want the query to output all members who have the values 101 or 102 or 103 listed in their id field with multiple ids listed. Array ( [0] => 101 [1] => 102 [2] => 103 ) $sql="SELECT firstname, lastname, id FROM members WHERE id LIKE '%".$array_num_1."%'"; $result=mysql_query($sql); while ($rows=mysql_fetch_array($result)) { echo $rows['lastname'].', '.$rows['firstname'].'-'.$rows['id']; }

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• How to get count of another table in a left join

  - by Sinan

  I have multiple tables post id Name 1 post-name1 2 post-name2 user id username 1 user1 2 user2 post_user post_id user_id 1 1 2 1 post_comments post_id comment_id 1 1 1 2 1 3 I am using a query like this: SELECT post.id, post.title, user.id AS uid, username FROM `post` LEFT JOIN post_user ON post.id = post_user.post_id LEFT JOIN user ON user.id = post_user.user_id ORDER BY post_date DESC It works as intended. However I would like the get the number of comments for each post too. So how can i modify the this query so I can get the count of comments. Any ideas?

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• Why is doing a top(1) on an indexed column in mssql slow?

  - by reinier

  I'm puzzled by the following. I have a DB with around 10 million rows, and (among other indices) on 1 column is an index. Now I have 700k rows where the campaignid is indeed 3835 For all these rows, the connectionid is the same. I just want to find out this connectionid. use messaging_db; SELECT TOP (1) connectionid FROM outgoing_messages WITH (NOLOCK) WHERE (campaignid_int = 3835) Now this query takes approx 30 seconds to perform! I (with my small db knowledge) would expect that it would take any of the rows, and return me that connectionid If I test this same query for a campaign which only has 1 entry, it goes really fast. So the index works. How would I tackle this and why does this not work?

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• Which field is explain telling me to index?

  - by shady

  I don't understand what this explain statement is saying. Which field needs an index?. The first line to me is confusing because ref is null. Here's the query I'm using: SELECT pp.property_id AS 'good_prop_id', pr.site_number AS 'pr.site_number', CONCAT(pr.site_street_name, ' ', pr.site_street_type) AS 'pr.partial_addr', pr.county FROM realval_newdb.preforeclosures AS pr INNER JOIN realval_newdb.properties_preforeclosures AS pp USE INDEX (mee_id) ON (pr.mee_id = pp.mee_id) INNER JOIN listings_copy AS lc ON (pr.site_number = lc.site_number) AND (lc.site_street_name = CONCAT(pr.site_street_name, ' ', pr.site_street_type)) WHERE lc.site_county = pr.county LIMIT 1; Can anyone help me optimize this query?

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• User has many computers, computers have many attributes in different tables, best way to JOIN?

  - by krismeld

  I have a table for users: USERS: ID | NAME | ---------------- 1 | JOHN | 2 | STEVE | a table for computers: COMPUTERS: ID | USER_ID | ------------------ 13 | 1 | 14 | 1 | a table for processors: PROCESSORS: ID | NAME | --------------------------- 27 | PROCESSOR TYPE 1 | 28 | PROCESSOR TYPE 2 | and a table for harddrives: HARDDRIVES: ID | NAME | ---------------------------| 35 | HARDDRIVE TYPE 25 | 36 | HARDDRIVE TYPE 90 | Each computer can have many attributes from the different attributes tables (processors, harddrives etc), so I have intersection tables like this, to link the attributes to the computers: COMPUTER_PROCESSORS: C_ID | P_ID | --------------| 13 | 27 | 13 | 28 | 14 | 27 | COMPUTER_HARDDRIVES: C_ID | H_ID | --------------| 13 | 35 | So user JOHN, with id 1 owns computer 13 and 14. Computer 13 has processor 27 and 28, and computer 13 has harddrive 35. Computer 14 has processor 27 and no harddrive. Given a user's id, I would like to retrieve a list of that user's computers with each computers attributes. I have figured out a query that gives me a somewhat of a result: SELECT computers.id, processors.id AS p_id, processors.name AS p_name, harddrives.id AS h_id, harddrives.name AS h_name, FROM computers JOIN computer_processors ON (computer_processors.c_id = computers.id) JOIN processors ON (processors.id = computer_processors.p_id) JOIN computer_harddrives ON (computer_harddrives.c_id = computers.id) JOIN harddrives ON (harddrives.id = computer_harddrives.h_id) WHERE computers.user_id = 1 Result: ID | P_ID | P_NAME | H_ID | H_NAME | ----------------------------------------------------------- 13 | 27 | PROCESSOR TYPE 1 | 35 | HARDDRIVE TYPE 25 | 13 | 28 | PROCESSOR TYPE 2 | 35 | HARDDRIVE TYPE 25 | But this has several problems... Computer 14 doesnt show up, because it has no harddrive. Can I somehow make an OUTER JOIN to make sure that all computers show up, even if there a some attributes they don't have? Computer 13 shows up twice, with the same harddrive listet for both. When more attributes are added to a computer (like 3 blocks of ram), the number of rows returned for that computer gets pretty big, and it makes it had to sort the result out in application code. Can I somehow make a query, that groups the two returned rows together? Or a query that returns NULL in the h_name column in the second row, so that all values returned are unique? EDIT: What I would like to return is something like this: ID | P_ID | P_NAME | H_ID | H_NAME | ----------------------------------------------------------- 13 | 27 | PROCESSOR TYPE 1 | 35 | HARDDRIVE TYPE 25 | 13 | 28 | PROCESSOR TYPE 2 | 35 | NULL | 14 | 27 | PROCESSOR TYPE 1 | NULL | NULL | Or whatever result that make it easy to turn it into an array like this [13] => [P_NAME] => [0] => PROCESSOR TYPE 1 [1] => PROCESSOR TYPE 2 [H_NAME] => [0] => HARDDRIVE TYPE 25 [14] => [P_NAME] => [0] => PROCESSOR TYPE 1

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• Table alias -- Unkown column in field list

  - by Jason

  Hi all, I have a sql query which is executing a LEFT JOIN on 2 tables in which some of the columns are ambiguous. I can prefix the joined tables but when I try to prefix one of the columns from the table in the FROM clause, it tells me Unknown column. I even tried giving that table an alias like so ...From points AS p and using "p" to prefix the tables but that didn't work either. Can someone tell me what I'm doing wrong. Here is my query: SELECT point_title, point_url, address, city, state, zip_code, phone, `points`.`lat`, `points`.`longi`, featured, kmlno, image_url, category.title, category_id, point_id, lat, longi, reviews.star_points, reviews.review_id, count(reviews.point_id) as totals FROM (SELECT *, ( 3959 * acos( cos( radians('37.7717185') ) * cos( radians( lat ) ) * cos( radians( longi ) - radians('-122.4438929') ) + sin( radians('37.7717185') ) * sin( radians( lat ) ) ) ) AS distance FROM points HAVING distance < '25') as distResults LEFT JOIN category USING ( category_id ) LEFT JOIN reviews USING ( point_id ) WHERE (point_title LIKE '%Playgrounds%' OR category.title LIKE '%Playgrounds%') GROUP BY point_id ORDER BY totals DESC, distance LIMIT 0 , 10

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• Accessing global variables within functions in PHP

  - by st3

  There are multiple times in one page where I need to connect and subsequently query a MySQL database, yet my code won't let me. I think it might be something to do with how my files are nested but it makes no sense. I am opening the SQL connection in the header file. The top of the offending page looks like the following: <?php $page_title = 'Dashboard'; include('templates/header.inc'); // includes a 'require_once('mysqli_connect.php') and a small query to the database; require_once('includes/functions.php'); require_once('includes/dashboard_sql.php'); // Contains functions which connect to database (which are failing.) ?> I get the PHP error Notice: Undefined variable: dbc in /Library/WebServer/Documents/pediatory_site/includes/dashboard_sql.php Where $dbc is the database connection defined in mysqli_connect.php. If anyone could help me out that would be great.

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• How can I get around MySQL Errcode 13 with SELECT INTO OUTFILE?

  - by Ryan Olson

  but I am trying to dump the contents of a table to a csv file using a MySQL SELECT INTO OUTFILE statement. If I do: SELECT column1, column2 INTO OUTFILE 'outfile.csv' FIELDS TERMINATED BY ',' FROM table_name; outfile.csv will be created on the server in the same directory this database's files are stored in. However, when I change my query to: SELECT column1, column2 INTO OUTFILE '/data/outfile.csv' FIELDS TERMINATED BY ',' FROM table_name; I get: ERROR 1 (HY000): Can't create/write to file '/data/outfile.csv' (Errcode: 13) Errcode 13 is a permissions error, even if I change ownership of /data to mysql:mysql and give it 777 permissions. MySQL is running as user "mysql". Strangely, I can create the file in /tmp, just not in any other directory I've tried, even with permissions set such that user mysql should be able to write to the directory. This is MySQL 5.0.75 running on Ubuntu.

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• Get latest record from second table left joined to first table

  - by codef0rmer

  I have a candidate table say candidates having only id field and i left joined profiles table to it. Table profiles has 2 fields namely, candidate_id & name. e.g. Table candidates: id 1 2 and Table `profiles`: candidate_id name 1 Foobar 1 Foobar2 2 Foobar3 i want the latest name of a candidate in a single query which is given below: SELECT C.id, P.name FROM candidates C LEFT JOIN profiles P ON P.candidate_id = C.id GROUP BY C.id ORDER BY P.name; But this query returns: 1 Foobar 2 Foobar3 Instead of: 1 Foobar2 2 Foobar3

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• Fetching a result twice with deferend name

  - by user1799842

  I have 1 table with tasks named opentask:columns: id,title,description,expires,creator_id,creator_name, executer_id, executer_name, priority_id, status_id1 table with users named user: with columns: user_id, username What I want is to create a query where there will be all columns from opentask table where the executer_id will be equal to the user_id of user table AND the creator_id will be equal to the user_id again. This creates a confusion because the first equality excludes the second.So I need somehow to create a query where I will include the usernames for the executer with something like where "opentask.executer_id=user_user_id" and at the same time I will include the username again (as a differend name?) for the creator with something like "where opentask.executer_id=user_user_id"So I try this, which of course I know that is missing something, can you help? SELECT DISTINCT id, title, description, expires, creator_id, executer_id, oc_opentask.priority_id, oc_opentask.status_id, priority_name, status_name, user_id, username, (SELECT username FROM oc_opentask, oc_user WHERE oc_opentask.creator_id=oc_user.user_id) AS username2 FROM oc_opentask, oc_opentask_priority, oc_user, oc_opentask_status WHERE oc_opentask.priority_id=oc_opentask_priority.priority_id AND oc_opentask.executer_id=oc_user.user_id AND oc_opentask.status_id=oc_opentask_status.status_id ORDER BY oc_opentask.expires DESC

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• sql count function

  - by suryll

  Hi I have three tables and I want to know how much jobs with the wage of 1000 an employee has had The first SQL query gives me the names of all the employees that has recieved 1000 for a job SELECT distinct first_name FROM employee, job, link WHERE job.wage = 1000 AND job.job_id = link.job_id and employee.employee_id = link.employee_id; The second SQL query gives me the total number for all employees of how much jobs they have made for 1000 SELECT count(wage) FROM employee, job, link WHERE job.wage = 1000 AND job.job_id = link.job_id and employee.employee_id = link.employee_id; I was wondering if there was a way of joining both queries and also making the second for each specific employee???

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• adding count( ) column on each row

  - by Arsenal

  I'm not sure if this is even a good question or not. I have a complex query with lot's of unions that searches multiple tables for a certain keyword (user input). All tables in which there is searched are related to the table book. There is paging on the resultset using LIMIT, so there's always a maximum of 10 results that get withdrawn. I want an extra column in the resultset displaying the total amount of results found however. I do not want to do this using a seperate query. Is it possible to add a count() column to the resultset that counts every result found? the output would look like this: ID Title Author Count(...) 1 book_1 auth_1 23 2 book_2 auth_2 23 4 book_4 auth_.. 23 ... Thanks!

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• Select products with users

  - by Ploppe

  I have not worked with SQL for quite a long time, and I need some help for a basic query. I have the three following tables: users (id, name) products (id, name) owners (userid, productid, date) One product can be sold by user A to user B and then back to A. Now, I want the list of all products currently owned by every single user with the date of transaction. Currently, my query is this one, but I'm stuck with old data (first association of one product to one user, and not the newest one): SELECT users.name, products.name, date FROM products JOIN owners ON products.id = owners.id JOIN users ON owners.id = user.id GROUP BY product.id Do you have some hints? Thanks

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• MEB: Taking Incremental Backup using last successful backup

  - by Sagar Jauhari

  Introduction In MySQL Enterprise Backup v3.7.0 (MEB 3.7.0) a new option '–incremental-base' was introduced. Using this option a user can take in incremental backup without specifying the '–start-lsn' option. Description of this option can be found here. Instead of '–start-lsn' the user can provide the location of the last full backup or incremental backup using the 'dir:' prefix. MEB would extract the end LSN of this backup from the mysql.backup_history table as well as the backup_variables.txt file (for verification) to use it as the start LSN of the incremental backup. Because of popular demand, in MEB 3.7.1 the option '-incremental-base' has been extended further. The idea is to allow the user to take an incremental backup as easily as possible using the '–incremental-base' option. With the new option MEB queries the backup_history table for the last successful backup and uses its end LSN as the start LSN for the new incremental backup. It should be noted that the last successful backup is used irrespective of the location of the backup. Details A new prefix 'history:' has been introduced for the –incremental-base option and currently the only permissible value is the string "last_backup". So using the new option an incremental backup can be taken with the following command: $ mysqlbackup --incremental --incremental-backup-dir=/media/mysqlbackup-repo/ --incremental-base=history:last_backup backup When MEB attempts to extract the end LSN of the last successful backup from the mysql.backup_history table, it also scans the corresponding backup destination for the old backup and tries to read the meta files at this backup destination. If a valid backup still exists at the backup destination and the meta files can be read, MEB compares the end LSN found in the mysql.backup_history table with the end LSN found in the backup meta files of the old backup. Assuming that the host MySQL server is alive and mysql.backup_history can be accessed by MEB, the behaviour of MEB with respect to verification of the old end LSN can be summarized as follows: If 'BD' is the backup destination of the last successful backup in mysql.backup_history table and 'BHT' is the mysql.backup_history table if can_read_files_at_BD:     if end_lsn_found_at_BD == end_lsn_of_last_backup_in_BHT:         continue_with_backup()     else         return_with_error() else     continue_with_backup() Advantages Apart from ease of usability an important advantage of this option is that the user can do repeated incremental backups without changing the command line. This is possible using the '–with-timestamp' option along with this new option. For example, the following command $ mysqlbackup --with-timestamp --incremental --incremental-backup-dir=/media/mysqlbackup-repo/ --incremental-base=history:last_backup backup  can be used to perform successive incremental backups in the directory /media/mysqlbackup-repo . Limitations The option '--incremental-base=history:last_backup' should not be used when the user takes different kinds of concurrent backups on the same MySQL server (say different partial backups at multiple locations). should not be used after any temporary or experimental backups performed on the server (which where successful!). needs to be used with precaution since any intermediate successful backup without the –no-connection will be used as the base backup for the next incremental backup.  will give an error in case a valid backup exists at the location of the last successful backup and whose end LSN is different from that of the last successful backup found in the backup_history table. Date: 2012-06-19 HTML generated by org-mode 6.33x in emacs 23

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• Why are transactions not rolling back when using SpringJUnit4ClassRunner/MySQL/Spring/Hibernate

  - by Trevor

  I am doing unit testing and I expect that all data committed to the MySQL database will be rolled back... but this isn't the case. The data is being committed, even though my log was showing that the rollback was happening. I've been wrestling with this for a couple days so my setup has changed quite a bit, here's my current setup. LoginDAOTest.java: @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations={"file:web/WEB-INF/applicationContext-test.xml", "file:web/WEB-INF/dispatcher-servlet-test.xml"}) @TransactionConfiguration(transactionManager = "transactionManager", defaultRollback = true) public class UserServiceTest { private UserService userService; @Test public void should_return_true_when_user_is_logged_in () throws Exception { String[] usernames = {"a","b","c","d"}; for (String username : usernames) { userService.logUserIn(username); assertThat(userService.isUserLoggedIn(username), is(equalTo(true))); } } ApplicationContext-Text.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd"> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> <property name="driverClassName" value="com.mysql.jdbc.Driver"/> <property name="url" value="jdbc:mysql://localhost:3306/test"/> <property name="username" value="root"/> <property name="password" value="Ecosim07"/> </bean> <tx:annotation-driven transaction-manager="transactionManager"/> <bean id="userService" class="Service.UserService"> <property name="userDAO" ref="userDAO"/> </bean> <bean id="userDAO" class="DAO.UserDAO"> <property name="hibernateTemplate" ref="hibernateTemplate"/> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="dataSource" ref="dataSource"/> <property name="mappingResources"> <list> <value>/himapping/User.hbm.xml</value> <value>/himapping/setup.hbm.xml</value> <value>/himapping/UserHistory.hbm.xml</value> </list> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</prop> <prop key="hibernate.show_sql">true</prop> </props> </property> </bean> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager" p:sessionFactory-ref="sessionFactory"/> <bean id="hibernateTemplate" class="org.springframework.orm.hibernate3.HibernateTemplate"> <property name="sessionFactory"> <ref bean="sessionFactory"/> </property> </bean> </beans> I have been reading about the issue, and I've already checked to ensure that the MySQL database tables are setup to use InnoDB. Also I have been able to successfully implement rolling back of transactions outside of my testing suite. So this must be some sort of incorrect setup on my part. Any help would be greatly appreciated :)

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• MySQL query - if not exists - insert into - else - update

  - by user3180931

  I made a simple document generator by the form, this form saves everything to mysql database, It works great, but when someone type a the same 'nrumowy' it creates a new row in mysql, 'nrumowy' is unique, so when someone adds a form with the same 'nrumowy' I want to just update existing data in mysql, I have that code: $con=mysqli_connect("localhost","login","pass","database"); // Check connection if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } // escape variables for security $numerklienta = mysqli_real_escape_string($con, $_POST['numerklienta']); $name = mysqli_real_escape_string($con, $_POST['name']); $hours = mysqli_real_escape_string($con, $_POST['hours']); $date = mysqli_real_escape_string($con, $_POST['date']); $beginDate = mysqli_real_escape_string($con, $_POST['beginDate']); $nrdomu = mysqli_real_escape_string($con, $_POST['nrdomu']); $telefon = mysqli_real_escape_string($con, $_POST['telefon']); $fax = mysqli_real_escape_string($con, $_POST['fax']); $nip = mysqli_real_escape_string($con, $_POST['nip']); $email = mysqli_real_escape_string($con, $_POST['email']); $stronawww = mysqli_real_escape_string($con, $_POST['stronawww']); $branza = mysqli_real_escape_string($con, $_POST['branza']); $vatkodpocztowy = mysqli_real_escape_string($con, $_POST['vatkodpocztowy']); $vatmiejscowosc = mysqli_real_escape_string($con, $_POST['vatmiejscowosc']); $vatulica = mysqli_real_escape_string($con, $_POST['vatulica']); $vatnrdomu = mysqli_real_escape_string($con, $_POST['vatnrdomu']); $vatemail = mysqli_real_escape_string($con, $_POST['vatemail']); $vatosoba = mysqli_real_escape_string($con, $_POST['vatosoba']); $datapublikacji = mysqli_real_escape_string($con, $_POST['datapublikacji']); $rabat = mysqli_real_escape_string($con, $_POST['rabat']); $wartoscnetto = mysqli_real_escape_string($con, $_POST['wartoscnetto']); $typreklamy = mysqli_real_escape_string($con, $_POST['typreklamy']); $inne = mysqli_real_escape_string($con, $_POST['inne']); $inne2 = mysqli_real_escape_string($con, $_POST['inne2']); $inne3 = mysqli_real_escape_string($con, $_POST['inne3']); $zaliczka = mysqli_real_escape_string($con, $_POST['zaliczka']); $liczbarat1 = mysqli_real_escape_string($con, $_POST['liczbarat1']); $zaakceptowaneprzez = mysqli_real_escape_string($con, $_POST['zaakceptowaneprzez']); $telzam = mysqli_real_escape_string($con, $_POST['telzam']); $datapodpis = mysqli_real_escape_string($con, $_POST['datapodpis']); $nrumowy = mysqli_real_escape_string($con, $_POST['nrumowy']); $sql="IF NOT EXISTS ( SELECT * FROM zam WHERE nrumowy = '$nrumowy' ) THEN INSERT INTO zam (numerklienta, name, hours, date, beginDate, nrdomu, telefon, fax, nip, email, stronawww, branza, vatkodpocztowy, vatmiejscowosc, vatulica, vatnrdomu, vatemail, vatosoba, datapublikacji, rabat, wartoscnetto, typreklamy, inne, inne2, inne3, zaliczka, liczbarat1, zaakceptowaneprzez, telzam, datapodpis, nrumowy) VALUES ('$numerklienta', '$name', '$hours', '$date', '$beginDate', '$nrdomu', '$telefon', '$fax', '$nip', '$email', '$stronawww', '$branza', '$vatkodpocztowy', '$vatmiejscowosc', '$vatulica', '$vatnrdomu', '$vatemail', '$vatosoba', '$datapublikacji', '$rabat', '$wartoscnetto', '$typreklamy', '$inne', '$inne2', '$inne3', '$zaliczka', '$liczbarat1', '$zaakceptowaneprzez', '$telzam', '$datapodpis', '$nrumowy' ) ELSE UPDATE zam SET name = '$name', numerklienta = '$numerklienta', hours = '$hours', date = '$date', beginDate = '$beginDate', nrdomu = '$nrdomu', telefon = '$telefon', fax = '$fax', nip = '$nip', email = '$email', stronawww = '$stronawww', branza = '$branza', vatkodpocztowy = '$vatkodpocztowy', vatmiejscowosc = '$vatmiejscowosc', vatulica = '$vatulica', vatnrdomu = '$vatnrdomu', vatemail = '$vatemail', vatosoba = '$vatosoba', datapublikacji = '$datapublikacji', rabat = '$rabat', wartoscnetto = '$wartoscnetto', typreklamy = '$typreklamy', inne = '$inne', inne2 = '$inne2', inne3 = '$inne3', zaliczka = '$zaliczka', liczbarat1 = '$liczbarat1', zaakceptowaneprzez = '$zaakceptowaneprzez', telzam = '$telzam', datapodpis = '$datapodpis' WHERE nrumowy ='$nrumowy' END IF"; if (!mysqli_query($con,$sql)) { die('Error: ' . mysqli_error($con)); } mysqli_close($con); This query without " select..... " and "else update" just a 'insert into' works great, also when I change this 'insert into' to 'update' but I don't know how to make this variable if not exists - insert into - else update

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• Why does Akonadi on KDE 4.6.0 refuse to start?

  - by Patches

  Akonadi refuses to start on my fresh installation of KDE 4.6.0 from the kubuntu-backports PPA on Ubuntu 10.10 Maverick Meerkat, preventing me from usking KMail. Here is the full error output: patches@pleistocene:~/.local/share$ akonadictl start Starting Akonadi Server... done. patches@pleistocene:~/.local/share$ Connecting to deprecated signal QDBusConnectionInterface::serviceOwnerChanged(QString,QString,QString) search paths: ("/home/patches/bin", "/usr/local/sbin", "/usr/local/bin", "/usr/sbin", "/usr/bin", "/sbin", "/bin", "/usr/games", "/usr/sbin", "/usr/local/sbin", "/usr/local/libexec", "/usr/libexec", "/opt/mysql/libexec", "/opt/local/lib/mysql5/bin", "/opt/mysql/sbin") Found mysql_install_db: "/usr/bin/mysql_install_db" Found mysqlcheck: "/usr/bin/mysqlcheck" Database process exited unexpectedly during initial connection! executable: "/usr/sbin/mysqld-akonadi" arguments: ("--defaults-file=/home/patches/.local/share/akonadi//mysql.conf", "--datadir=/home/patches/.local/share/akonadi/db_data/", "--socket=/home/patches/.local/share/akonadi/socket-pleistocene/mysql.socket") stdout: "" stderr: "Could not open required defaults file: /home/patches/.local/share/akonadi//mysql.conf Fatal error in defaults handling. Program aborted 110209 16:41:12 [Warning] Can't create test file /home/patches/.local/share/akonadi/db_data/pleistocene.lower-test 110209 16:41:12 [Warning] Can't create test file /home/patches/.local/share/akonadi/db_data/pleistocene.lower-test 110209 16:41:12 [Note] Plugin 'FEDERATED' is disabled. /usr/sbin/mysqld-akonadi: Can't find file: './mysql/plugin.frm' (errno: 13) 110209 16:41:12 [ERROR] Can't open the mysql.plugin table. Please run mysql_upgrade to create it. 110209 16:41:12 InnoDB: Operating system error number 13 in a file operation. InnoDB: The error means mysqld does not have the access rights to InnoDB: the directory. InnoDB: File name ./ibdata1 InnoDB: File operation call: 'create'. InnoDB: Cannot continue operation. " exit code: 1 process error: "Unknown error" "[ 0: akonadiserver(_Z11akBacktracev+0x35) [0x8086055] 1: akonadiserver() [0x8086516] 2: [0xb772e400] 3: [0xb772e416] 4: /lib/libc.so.6(gsignal+0x51) [0xb6e9f941] 5: /lib/libc.so.6(abort+0x182) [0xb6ea2e42] 6: /usr/lib/libQtCore.so.4(_Z17qt_message_output9QtMsgTypePKc+0x8c) [0xb74d62dc] 7: akonadiserver(_ZN15FileDebugStream9writeDataEPKcx+0xc4) [0x8087574] 8: /usr/lib/libQtCore.so.4(_ZN9QIODevice5writeEPKcx+0x8e) [0xb757168e] 9: /usr/lib/libQtCore.so.4(+0x103425) [0xb7581425] 10: /usr/lib/libQtCore.so.4(_ZN11QTextStreamD1Ev+0x3d) [0xb758295d] 11: akonadiserver(_ZN6QDebugD1Ev+0x43) [0x8081b73] 12: akonadiserver(_ZN13DbConfigMysql19startInternalServerEv+0x1c27) [0x810c177] 13: akonadiserver(_ZN7Akonadi13AkonadiServer20startDatabaseProcessEv+0xe3) [0x8087a23] 14: akonadiserver(_ZN7Akonadi13AkonadiServerC1EP7QObject+0xca) [0x8088b6a] 15: akonadiserver(_ZN7Akonadi13AkonadiServer8instanceEv+0x48) [0x808a1d8] 16: akonadiserver(main+0x364) [0x8080fb4] 17: /lib/libc.so.6(__libc_start_main+0xe7) [0xb6e8bce7] 18: akonadiserver() [0x8080b81] ] " ProcessControl: Application 'akonadiserver' returned with exit code 255 (Unknown error) search paths: ("/home/patches/bin", "/usr/local/sbin", "/usr/local/bin", "/usr/sbin", "/usr/bin", "/sbin", "/bin", "/usr/games", "/usr/sbin", "/usr/local/sbin", "/usr/local/libexec", "/usr/libexec", "/opt/mysql/libexec", "/opt/local/lib/mysql5/bin", "/opt/mysql/sbin") Found mysql_install_db: "/usr/bin/mysql_install_db" Found mysqlcheck: "/usr/bin/mysqlcheck" Database process exited unexpectedly during initial connection! executable: "/usr/sbin/mysqld-akonadi" arguments: ("--defaults-file=/home/patches/.local/share/akonadi//mysql.conf", "--datadir=/home/patches/.local/share/akonadi/db_data/", "--socket=/home/patches/.local/share/akonadi/socket-pleistocene/mysql.socket") stdout: "" stderr: "Could not open required defaults file: /home/patches/.local/share/akonadi//mysql.conf Fatal error in defaults handling. Program aborted 110209 16:41:12 [Warning] Can't create test file /home/patches/.local/share/akonadi/db_data/pleistocene.lower-test 110209 16:41:12 [Warning] Can't create test file /home/patches/.local/share/akonadi/db_data/pleistocene.lower-test 110209 16:41:12 [Note] Plugin 'FEDERATED' is disabled. /usr/sbin/mysqld-akonadi: Can't find file: './mysql/plugin.frm' (errno: 13) 110209 16:41:12 [ERROR] Can't open the mysql.plugin table. Please run mysql_upgrade to create it. 110209 16:41:12 InnoDB: Operating system error number 13 in a file operation. InnoDB: The error means mysqld does not have the access rights to InnoDB: the directory. InnoDB: File name ./ibdata1 InnoDB: File operation call: 'create'. InnoDB: Cannot continue operation. " exit code: 1 process error: "Unknown error" "[ 0: akonadiserver(_Z11akBacktracev+0x35) [0x8086055] 1: akonadiserver() [0x8086516] 2: [0xb77ae400] 3: [0xb77ae416] 4: /lib/libc.so.6(gsignal+0x51) [0xb6f1f941] 5: /lib/libc.so.6(abort+0x182) [0xb6f22e42] 6: /usr/lib/libQtCore.so.4(_Z17qt_message_output9QtMsgTypePKc+0x8c) [0xb75562dc] 7: akonadiserver(_ZN15FileDebugStream9writeDataEPKcx+0xc4) [0x8087574] 8: /usr/lib/libQtCore.so.4(_ZN9QIODevice5writeEPKcx+0x8e) [0xb75f168e] 9: /usr/lib/libQtCore.so.4(+0x103425) [0xb7601425] 10: /usr/lib/libQtCore.so.4(_ZN11QTextStreamD1Ev+0x3d) [0xb760295d] 11: akonadiserver(_ZN6QDebugD1Ev+0x43) [0x8081b73] 12: akonadiserver(_ZN13DbConfigMysql19startInternalServerEv+0x1c27) [0x810c177] 13: akonadiserver(_ZN7Akonadi13AkonadiServer20startDatabaseProcessEv+0xe3) [0x8087a23] 14: akonadiserver(_ZN7Akonadi13AkonadiServerC1EP7QObject+0xca) [0x8088b6a] 15: akonadiserver(_ZN7Akonadi13AkonadiServer8instanceEv+0x48) [0x808a1d8] 16: akonadiserver(main+0x364) [0x8080fb4] 17: /lib/libc.so.6(__libc_start_main+0xe7) [0xb6f0bce7] 18: akonadiserver() [0x8080b81] ] " ProcessControl: Application 'akonadiserver' returned with exit code 255 (Unknown error) search paths: ("/home/patches/bin", "/usr/local/sbin", "/usr/local/bin", "/usr/sbin", "/usr/bin", "/sbin", "/bin", "/usr/games", "/usr/sbin", "/usr/local/sbin", "/usr/local/libexec", "/usr/libexec", "/opt/mysql/libexec", "/opt/local/lib/mysql5/bin", "/opt/mysql/sbin") Found mysql_install_db: "/usr/bin/mysql_install_db" Found mysqlcheck: "/usr/bin/mysqlcheck" Database process exited unexpectedly during initial connection! executable: "/usr/sbin/mysqld-akonadi" arguments: ("--defaults-file=/home/patches/.local/share/akonadi//mysql.conf", "--datadir=/home/patches/.local/share/akonadi/db_data/", "--socket=/home/patches/.local/share/akonadi/socket-pleistocene/mysql.socket") stdout: "" stderr: "Could not open required defaults file: /home/patches/.local/share/akonadi//mysql.conf Fatal error in defaults handling. Program aborted 110209 16:41:12 [Warning] Can't create test file /home/patches/.local/share/akonadi/db_data/pleistocene.lower-test 110209 16:41:12 [Warning] Can't create test file /home/patches/.local/share/akonadi/db_data/pleistocene.lower-test 110209 16:41:12 [Note] Plugin 'FEDERATED' is disabled. /usr/sbin/mysqld-akonadi: Can't find file: './mysql/plugin.frm' (errno: 13) 110209 16:41:12 [ERROR] Can't open the mysql.plugin table. Please run mysql_upgrade to create it. 110209 16:41:12 InnoDB: Operating system error number 13 in a file operation. InnoDB: The error means mysqld does not have the access rights to InnoDB: the directory. InnoDB: File name ./ibdata1 InnoDB: File operation call: 'create'. InnoDB: Cannot continue operation. " exit code: 1 process error: "Unknown error" "[ 0: akonadiserver(_Z11akBacktracev+0x35) [0x8086055] 1: akonadiserver() [0x8086516] 2: [0xb778b400] 3: [0xb778b416] 4: /lib/libc.so.6(gsignal+0x51) [0xb6efc941] 5: /lib/libc.so.6(abort+0x182) [0xb6effe42] 6: /usr/lib/libQtCore.so.4(_Z17qt_message_output9QtMsgTypePKc+0x8c) [0xb75332dc] 7: akonadiserver(_ZN15FileDebugStream9writeDataEPKcx+0xc4) [0x8087574] 8: /usr/lib/libQtCore.so.4(_ZN9QIODevice5writeEPKcx+0x8e) [0xb75ce68e] 9: /usr/lib/libQtCore.so.4(+0x103425) [0xb75de425] 10: /usr/lib/libQtCore.so.4(_ZN11QTextStreamD1Ev+0x3d) [0xb75df95d] 11: akonadiserver(_ZN6QDebugD1Ev+0x43) [0x8081b73] 12: akonadiserver(_ZN13DbConfigMysql19startInternalServerEv+0x1c27) [0x810c177] 13: akonadiserver(_ZN7Akonadi13AkonadiServer20startDatabaseProcessEv+0xe3) [0x8087a23] 14: akonadiserver(_ZN7Akonadi13AkonadiServerC1EP7QObject+0xca) [0x8088b6a] 15: akonadiserver(_ZN7Akonadi13AkonadiServer8instanceEv+0x48) [0x808a1d8] 16: akonadiserver(main+0x364) [0x8080fb4] 17: /lib/libc.so.6(__libc_start_main+0xe7) [0xb6ee8ce7] 18: akonadiserver() [0x8080b81] ] " ProcessControl: Application 'akonadiserver' returned with exit code 255 (Unknown error) search paths: ("/home/patches/bin", "/usr/local/sbin", "/usr/local/bin", "/usr/sbin", "/usr/bin", "/sbin", "/bin", "/usr/games", "/usr/sbin", "/usr/local/sbin", "/usr/local/libexec", "/usr/libexec", "/opt/mysql/libexec", "/opt/local/lib/mysql5/bin", "/opt/mysql/sbin") Found mysql_install_db: "/usr/bin/mysql_install_db" Found mysqlcheck: "/usr/bin/mysqlcheck" Database process exited unexpectedly during initial connection! executable: "/usr/sbin/mysqld-akonadi" arguments: ("--defaults-file=/home/patches/.local/share/akonadi//mysql.conf", "--datadir=/home/patches/.local/share/akonadi/db_data/", "--socket=/home/patches/.local/share/akonadi/socket-pleistocene/mysql.socket") stdout: "" stderr: "Could not open required defaults file: /home/patches/.local/share/akonadi//mysql.conf Fatal error in defaults handling. Program aborted 110209 16:41:12 [Warning] Can't create test file /home/patches/.local/share/akonadi/db_data/pleistocene.lower-test 110209 16:41:12 [Warning] Can't create test file /home/patches/.local/share/akonadi/db_data/pleistocene.lower-test 110209 16:41:12 [Note] Plugin 'FEDERATED' is disabled. /usr/sbin/mysqld-akonadi: Can't find file: './mysql/plugin.frm' (errno: 13) 110209 16:41:12 [ERROR] Can't open the mysql.plugin table. Please run mysql_upgrade to create it. 110209 16:41:12 InnoDB: Operating system error number 13 in a file operation. InnoDB: The error means mysqld does not have the access rights to InnoDB: the directory. InnoDB: File name ./ibdata1 InnoDB: File operation call: 'create'. InnoDB: Cannot continue operation. " exit code: 1 process error: "Unknown error" "[ 0: akonadiserver(_Z11akBacktracev+0x35) [0x8086055] 1: akonadiserver() [0x8086516] 2: [0xb784e400] 3: [0xb784e416] 4: /lib/libc.so.6(gsignal+0x51) [0xb6fbf941] 5: /lib/libc.so.6(abort+0x182) [0xb6fc2e42] 6: /usr/lib/libQtCore.so.4(_Z17qt_message_output9QtMsgTypePKc+0x8c) [0xb75f62dc] 7: akonadiserver(_ZN15FileDebugStream9writeDataEPKcx+0xc4) [0x8087574] 8: /usr/lib/libQtCore.so.4(_ZN9QIODevice5writeEPKcx+0x8e) [0xb769168e] 9: /usr/lib/libQtCore.so.4(+0x103425) [0xb76a1425] 10: /usr/lib/libQtCore.so.4(_ZN11QTextStreamD1Ev+0x3d) [0xb76a295d] 11: akonadiserver(_ZN6QDebugD1Ev+0x43) [0x8081b73] 12: akonadiserver(_ZN13DbConfigMysql19startInternalServerEv+0x1c27) [0x810c177] 13: akonadiserver(_ZN7Akonadi13AkonadiServer20startDatabaseProcessEv+0xe3) [0x8087a23] 14: akonadiserver(_ZN7Akonadi13AkonadiServerC1EP7QObject+0xca) [0x8088b6a] 15: akonadiserver(_ZN7Akonadi13AkonadiServer8instanceEv+0x48) [0x808a1d8] 16: akonadiserver(main+0x364) [0x8080fb4] 17: /lib/libc.so.6(__libc_start_main+0xe7) [0xb6fabce7] 18: akonadiserver() [0x8080b81] ] " ProcessControl: Application 'akonadiserver' returned with exit code 255 (Unknown error) "akonadiserver" crashed too often and will not be restarted! I tried moving the ~/.local/share/akonadi folder and running it fresh, and I also tried starting Akonadi from a brand new user, all to no avail. Requested by @djeikyb: patches@pleistocene:~$ ls -ld ~/.local drwxrwx--- 3 patches patches 4096 2011-02-07 03:15 /home/patches/.local patches@pleistocene:~$ mysql_upgrade Looking for 'mysql' as: mysql Looking for 'mysqlcheck' as: mysqlcheck Running 'mysqlcheck' with connection arguments: '--port=3306' '--socket=/var/run/mysqld/mysqld.sock' mysqlcheck: Got error: 2002: Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) when trying to connect FATAL ERROR: Upgrade failed patches@pleistocene:~$ mysql_upgrade -S ~/.local/share/akonadi/socket-pleistocene/ Looking for 'mysql' as: mysql Looking for 'mysqlcheck' as: mysqlcheck Running 'mysqlcheck' with connection arguments: '--port=3306' '--socket=/var/run/mysqld/mysqld.sock' '--socket=/home/patches/.local/share/akonadi/socket-pleistocene/' mysqlcheck: Got error: 2002: Can't connect to local MySQL server through socket '/home/patches/.local/share/akonadi/socket-pleistocene/' (111) when trying to connect FATAL ERROR: Upgrade failed

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• Optional parameters with named query in Hibernate?

  - by Ickster

  Is there any way to specify optional parameters (such as when search parameters are provided from a form and not all parameters are required) in a named query when using Hibernate? I'm using a native SQL query, but the question is probably applicable to named HQL queries as well. I'm pretty sure the answer to this is 'no', but I haven't find the definitive answer in the documentation yet.

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• hierachical query to return final row

  - by jeff

  I have a hierarchical query that doesn't return an expected row (employee badge = 444). TABLE: hr_data badge fname supervisor_badge 111 Jeff 222 222 Joe 333 333 John 444 444 Tom 444 SQL: SELECT CONNECT_BY_ISCYCLE As IC, badge, fname, supervisor_badge FROM hr_data START WITH badge = '111' CONNECT BY NOCYCLE badge = PRIOR supervisor_badge What is Returned: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 1 333 John 444 What is Expected: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 **0** 333 John 444 **1** 444 Tom 444 How can I get this query to return the employee Tom and then stop?

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• Using Treelist Values to Query a Sitecore Item

  - by kirk.burleson

  I have an item named All Recipes that contains recipes named R1, R2, and R3. I have another item named My Recipes that has a treelist field named Recipes and it contains selected values R2 and R3 from the All Recipes item. The query I'm trying to write is for the Items field of an RSS Feed. What is the query syntax to show the items in All Recipes that appear in the Recipes field of My Recipes?

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• What is wrong with my PHP/MySQL code?

  - by James

  I am building a navigation menu which lists all my categories and subcategories. The problem is it returns only one of these and not all. I have the categories echoed inside the while loop so I'm not sure why it's only showing one result and not all: <?php $query = mysql_query("SELECT * FROM categories_parent"); while ($row = mysql_fetch_assoc($query)) { $id = $row['id']; $name = $row['name']; $slug = $row['slug']; $childStatus = $row['child_status']; // if has child categories if ($childStatus == "1") { echo "<li class='dir'><a href='category.php?slug=$slug'>$name</a>"; echo "<ul id='dropdown'>"; $query = mysql_query("SELECT * FROM categories_child WHERE parent=$id"); while ($row = mysql_fetch_assoc($query)) { $id = $row['id']; $name = $row['name']; $slug = $row['slug']; echo "<li><a href='category.php?slug=$slug'>$name</a></li>"; } echo "</ul>"; echo "</li>"; } // if singular parent else { echo "<li><a href='category.php?slug=$slug'>$name</a></li>"; } } ?> My database tables: -- -- Table structure for table `categories_child` -- CREATE TABLE IF NOT EXISTS `categories_child` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `parent` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=139 ; -- -- Dumping data for table `categories_child` -- INSERT INTO `categories_child` (`id`, `name`, `slug`, `parent`) VALUES (138, 'Britney Spears', 'category/celiberties/britney-spears/', 137), (136, 'Tigers', 'category/animals/tigers/', 136), (137, 'Horses', 'category/animals/horses/', 136), (135, 'Lions', 'category/animals/lions/', 136); -- -- Table structure for table `categories_parent` -- CREATE TABLE IF NOT EXISTS `categories_parent` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `child_status` int(1) NOT NULL DEFAULT '0', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=139 ; -- -- Dumping data for table `categories_parent` -- INSERT INTO `categories_parent` (`id`, `name`, `slug`, `child_status`) VALUES (137, 'Celiberties', 'category/celiberties/', 1), (138, 'TV Shows', 'category/tv-shows/', 0), (136, 'Animals', 'category/animals/', 1);

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• mysql query is producing more results than it should

  - by user253530

  SELECT S.CLIENT,S.IP_DOMAIN as IP, IFNULL(K.DATE, DATE '0000-00-00') AS RecentDate FROM PLD_SERVERS AS S JOIN PLD_SEARCHES AS K ON S.ID = K.SERVER_ID This query will produce as many results as entries in the PLD_SEARCHES. For example: I have 3 entries in PLD_SERVERS and 18 entries in PLD_SEARCHES. The output of this query will be 18 but i need it to be 3 (as the number of PLD_SERVERS entries) with the recent date as a join field from PLD_SEARCHES.

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