Search Results

Search found 10005 results on 401 pages for 'regex trouble'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 119/401 | < Previous Page | 115 116 117 118 119 120 121 122 123 124 125 126  | Next Page >

  • Replacing text node of HTML input in PHP

    - by Aman Kumar Jain
    Hi, I want to replace all the text nodes in a html text. I'll explain with an example: $html = " <div> <p> text2 text2 word text2 <span>abcd</span> text2 text2 word text2 <p> this is a long, very long statement with punctuations. </div> I want to replace "text2 text2 word text2" with "<span>text2 text2 word text2</span>" and "this is a long, very long statement with punctuations." with "<span>this is a long, very long statement with punctuations.</span>" What should be the regular expression for the same?

    Read the article

  • [PHP] preg_replace: replacing using %

    - by Juan
    Hi all, I'm using the function preg_replace but I cannot figure out how to make it work, the function just doesn't seem to work for me. What I'm trying to do is to convert a string into a link if any word contains the % (percentage) character. For instance if I have the string "go to %mysite", I'd like to convert the mysite word into a link. I tried the following... $data = "go to %mysite"; $result = preg_replace('/(^|[\s\.\,\:\;]+)%([A-Za-z0-9]{1,64})/e', '\\1%<a href=#>\\2</a>', $data); ...but it doesn't work. Any help on this would be much appreciated. Thanks Juan

    Read the article

  • using regular expression in Java

    - by Mrityunjay
    Hi, i need to check a string that should contain only ABCDEFG characters, in any sequence and with only 7 characters. Please let me know the correct way of using regular expression. as corrently i am using String abs = "ABPID"; if(!Pattern.matches("[[ABCDEFG]", abs)) System.out.println("Error"); i am using the following code which works when i use the String abcdefg but for other cases it fails. please help me out.

    Read the article

  • Redirect visitor with .htaccess

    - by Aaron
    Hi all, I've got an e-shop on a virtual server that's been used as a subdirectory for the last few years, but now I'm finally giving the VS it's own domain name. What I really need is visitors to the old URL to be transparently (and 301) redirected to the new URL with everything after /eshop/ maintained and apended to the new host. I.e. http://www.example.com/eshop/page.php - http://www.newdomain.com/page.php Any help would be greatly appreciated.

    Read the article

  • Extract a regular expression match in R version 2.10

    - by tovare
    Hi, I'm trying to extract a number from a string. And do something like this [0-9]+ on this string "aaaa12xxxx" and get "12". I thought it would be something like: > grep("[0-9]+","aaa12xxx", value=TRUE) [1] "aaa12xxx" And then I figured... > sub("[0-9]+", "\\1", "aaa12xxxx") [1] "aaa12xxx" But I got some form of response doing: > sub("[0-9]+", "ARGH!", "aaa12xxxx") [1] "aaaARGH!xxx" There's a small detail I'm missing Please advice :-) I'm using R version 2.10.1 (2009-12-14) Thanks ! Comments on the solution The best solution is to ignore the standard functions and install Hadley Wickham's stringr package to get something that actually makes sense. Kudos to Marek for figuring out how the standard library worked.

    Read the article

  • Match string which doesn't start with

    - by Pinky
    I have a string that looks like this: var str = "Hello world, &nbsp;hello &gt;world, hello world!"; ... and I'd like to replace all the hellos with e.g. bye and world with earth, except the words that start with &nbsp or &gt. Those should be ignored. So the result should be: bye earth, &nbsp;hello &gt;world, bye earth! Tried to this with str.replace(/(?!\&nbsp;)hello/gi,'bye')); But it doesn't work.

    Read the article

  • Regular Expression :match string containing only non repeating words

    - by nash
    I have this situation(Java code): 1) a string such as : "A wild adventure" should match. 2) a string with adjacent repeated words: "A wild wild adventure" shouldn't match. With this regular expression: .* \b(\w+)\b\s*\1\b.* i can match strings containing adjacent repeated words. How to reverse the situation i.e how to match strings which do not contain adjacent repeat words

    Read the article

  • regular expression code

    - by Gaia Andreoletti
    Deal all, I need to find match between two tab delimited files files like this: File 1: ID1 1 65383896 65383896 G C PCNXL3 ID1 2 56788990 55678900 T A ACT1 ID1 1 56788990 55678900 T A PRO55 File 2 ID2 34 65383896 65383896 G C MET5 ID2 2 56788990 55678900 T A ACT1 ID2 2 56788990 55678900 T A HLA what I would like to do is to retrive the matching line between the two file. What I would like to match is everyting after the gene ID So far I have written this code but unfortunately perl keeps giving me the error: use of "Use of uninitialized value in pattern match (m//)" Could you please help me figure out where i am doing it wrong? Thank you in advance! use strict; open (INA, $ARGV[0]) || die "cannot to open gene file"; open (INB, $ARGV[1]) || die "cannot to open coding_annotated.var files"; my @sample1 = <INA>; my @sample2 = <INB>; foreach my $line (@sample1) { my @tab = split (/\t/, $line); my $chr = $tab[1]; my $start = $tab[2]; my $end = $tab[3]; my $ref = $tab[4]; my $alt = $tab[5]; my $name = $tab[6]; foreach my $item (@sample2){ my @fields = split (/\t/,$item); if ($fields[1]=~ m/$chr(.*)/ && $fields[2]=~ m/$start(.*)/ && $fields[4]=~ m/$ref(.*)/ && $fields[5]=~ m/$alt(.*)/&& $fields[6]=~ m/$name(.*)/){ print $line,"\n",$item; } } }

    Read the article

  • perl ENV value avoid escape

    - by Michael
    In my makefile I have command in variable like this substitute := perl -p -e 's/@([^@]+)@/"$(update_url)"/ge' > output.txt update_url := em:updateURL=\"http:\/\/bla\/update.rdf\"\n this works fine when I run command in target and I have newline, quotes however I need to replace $(update_url)" with environment variable, using expression like this #substitute := perl -p -e 's/@([^@]+)@/defined $$ENV{$$1} ? $$ENV{$$1} : $$1/ge' I am exporting those variables from makefile. This gives me literally em:updateURL=\"http:\/\/bla\/update.rdf\"\n on output file... so how to make the second version to give output like first version?

    Read the article

  • A "smart" (forgiving) date parser?

    - by jdmuys
    I have to migrate a very large dataset from one system to another. One of the "source" column contains a date but is really a string with no constraint, while the destination system mandates a date in the format yyyy-mm-dd. Many, but not all, of the source dates are formatted as yyyymmdd. So to coerce them to the expected format, I do (in Perl): return "$1-$2-$3" if ($val =~ /(\d{4})[-\/]*(\d{2})[-\/]*(\d{2})/); The problem arises when the source dates moves away from the "generic" yyyymmdd. The goal is to salvage as many dates as possible, before giving up. Example source strings include: 21/3/1998, March 2004, 2001, 3/4/97 I can try to match as many of the examples I can find with a succession of regular expressions such as the one above. But is there something smarter to do? Am I not reinventing the wheel? Is there a library somewhere doing something similar? I couldn't find anything relevant googling "forgiving date parser". (any language is OK).

    Read the article

  • PHP RegExpr error Unkown modifier '('

    - by Anonymous
    I have this regular expression: ([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?) its for extracting links to topics from forum Now when i use it in my script $url = "([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?)"; preg_match_all spits: "Unknown modifier '('" Can anyone help me with this obviously stupid problem

    Read the article

  • Use Regular expression with fileinput

    - by chrissygormley
    Hello, I am trying to replace a variable stored in another file using regular expression. The code I have tried is: r = re.compile(r"self\.uid\s*=\s*('\w{12})'") for line in fileinput.input(['file.py'], inplace=True): print line.replace(r.match(line), sys.argv[1]), The format of the variable in the file is: self.uid = '027FC8EBC2D1' I am trying to pass in a parameter in this format and use regular expression to verify that the sys.argv[1] is correct format and to find the variable stored in this file and replace it with the new variable. Can anyone help. Thanks for the help.

    Read the article

  • Regular Expression Question

    - by zyq524
    I'm trying to use regular expression to extract the comments in the heading of a file. For example, the source code may look like: //This is an example file. //Please help me. #include "test.h" int main() //main function { ... } What I want to extract from the code are the first two lines, i.e. //This is an example file. //Please help me. Any idea?

    Read the article

  • Explain a block of crazy JS code inside Sizzle(the CSS selector engine)

    - by Andy Li
    So, here is the function for pre-filtering "CHILD": function(match){ if ( match[1] === "nth" ) { // parse equations like 'even', 'odd', '5', '2n', '3n+2', '4n-1', '-n+6' var test = /(-?)(\d*)n((?:\+|-)?\d*)/.exec( match[2] === "even" && "2n" || match[2] === "odd" && "2n+1" || !/\D/.test( match[2] ) && "0n+" + match[2] || match[2]); // calculate the numbers (first)n+(last) including if they are negative match[2] = (test[1] + (test[2] || 1)) - 0; match[3] = test[3] - 0; } // TODO: Move to normal caching system match[0] = done++; return match; } The code is extracted from line 442-458 of sizzle.js. So, why is the line var test = ..., have the exec inputing a boolean? Or is that really a string? Can someone explain it by splitting it into a few more lines of code?

    Read the article

  • need code for search another character

    - by klox
    hi,all..i have this code: var str = "KD-R435MUN2D"; var hasUD; var patt1 = str.match(/U/gi); var patt2 = str.match(/D/gi); if (patt1 && patt2) { hasUD = 'UD'; } else { hasUD = false; } document.write(hasUD); how to modify this code if i want search JD from var str="KD-S35JWD"..i try this but doesn't work: <script type="text/javascript"> var str = "KD-R435jwd"; var hasUD; var hasJD; var patt1 = str.match(/U/gi); var patt2 = str.match(/J/gi); var patt3 = str.match(/D/gi); if (patt1 && patt3) { hasUD = 'UD'; document.write(hasUD); } elseif (patt2 && patt3) { hasJD = 'JD'; document.write(hasJD); } </script>

    Read the article

  • How to use regular expressions to pull a substring? (screen scraping)

    - by Diego
    Hey guys, i'm really trying to understand regular expressions while scraping a site, i've been using it in my code enough to pull the following, but am stuck here. I need to quickly grab this: http://www.example.com/online/store/TitleDetail?detail&sku=123456789 from this: ('<a href="javascript:if(handleDoubleClick(this.id)){window.location=\'http://www.example.com/online/store/TitleDetail?detail&sku=123456789\';}" id="getTitleDetails_123456789">\r\n\t\t\t \tcheck store inventory\r\n\t\t\t </a>', 1) This is where I got confused. any ideas?

    Read the article

  • what is the return value of BeautifulSoup.find ?

    - by prosseek
    I run to get some value as score. score = soup.find('div', attrs={'class' : 'summarycount'}) I run 'print score' to get as follows. <div class=\"summarycount\">524</div> I need to extract the number part. I used re module but failed. m = re.search("[^\d]+(\d+)", score) TypeError: expected string or buffer function search in re.py at line 142 return _compile(pattern, flags).search(string) What's the return type of the find function? How to get the number from the score variable? Is there any easy way to let BeautifulSoup to return the value(in this case 524) itself?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 115 116 117 118 119 120 121 122 123 124 125 126  | Next Page >