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  • Bash-Scripting - Munin Plugin don't work

    - by FTV Admin
    i have written a munin-plugin to count the http-statuscodes of lighttpd. The script: #!/bin/bash ###################################### # Munin-Script: Lighttpd-Statuscodes # ###################################### ##Config # path to lighttpd access.log LIGHTTPD_ACCESS_LOG_PATH="/var/log/lighttpd/access.log" # rows to parse in logfile (higher value incrase time to run plugin. if value to low you may get bad counting) LOG_ROWS="200000" # #munin case $1 in autoconf) # check config AVAILABLE=`ls $LIGHTTPD_ACCESS_LOG_PATH` if [ "$AVAILABLE" = "$LIGHTTPD_ACCESS_LOG_PATH" ]; then echo "yes" else echo "No: "$AVAILABLE echo "Please check your config!" fi exit 0;; config) # graph config cat <<'EOM' graph_title Lighhtpd Statuscodes graph_vlabel http-statuscodes / min graph_category lighttpd 1xx.label 1xx 2xx.label 2xx 3xx.label 3xx 4xx.label 4xx 5xx.label 5xx EOM exit 0;; esac ## calculate AVAILABLE=`ls $LIGHTTPD_ACCESS_LOG_PATH` if [ "$AVAILABLE" = "$LIGHTTPD_ACCESS_LOG_PATH" ]; then TIME_NOW=`date` CODE_1xx="0" CODE_2xx="0" CODE_3xx="0" CODE_4xx="0" CODE_5xx="0" for i in 1 2 3 4 5; do TIME5=`date +%d/%b/%Y:%k:%M --date "$TIME_NOW -"$i"min"` CODE_1xx=$(( $CODE_1xx + `tail -n $LOG_ROWS $LIGHTTPD_ACCESS_LOG_PATH | grep "$TIME5" | grep 'HTTP/1.1" 1' | grep -c " "` )) CODE_2xx=$(( $CODE_2xx + `tail -n $LOG_ROWS $LIGHTTPD_ACCESS_LOG_PATH | grep "$TIME5" | grep 'HTTP/1.1" 2' | grep -c " "` )) CODE_3xx=$(( $CODE_3xx + `tail -n $LOG_ROWS $LIGHTTPD_ACCESS_LOG_PATH | grep "$TIME5" | grep 'HTTP/1.1" 3' | grep -c " "` )) CODE_4xx=$(( $CODE_4xx + `tail -n $LOG_ROWS $LIGHTTPD_ACCESS_LOG_PATH | grep "$TIME5" | grep 'HTTP/1.1" 4' | grep -c " "` )) CODE_5xx=$(( $CODE_5xx + `tail -n $LOG_ROWS $LIGHTTPD_ACCESS_LOG_PATH | grep "$TIME5" | grep 'HTTP/1.1" 5' | grep -c " "` )) done CODE_1xx=$(( $CODE_1xx / 5 )) CODE_2xx=$(( $CODE_2xx / 5 )) CODE_3xx=$(( $CODE_3xx / 5 )) CODE_4xx=$(( $CODE_4xx / 5 )) CODE_5xx=$(( $CODE_5xx / 5 )) echo "1xx.value "$CODE_1xx echo "2xx.value "$CODE_2xx echo "3xx.value "$CODE_3xx echo "4xx.value "$CODE_4xx echo "5xx.value "$CODE_5xx else echo "1xx.value U" echo "2xx.value U" echo "3xx.value U" echo "4xx.value U" echo "5xx.value U" fi If i run the script on local machine it runs perfectly: root@server1 /etc/munin/plugins # ll lrwxrwxrwx 1 root root 45 2011-12-19 15:23 lighttpd_statuscodes -> /usr/share/munin/plugins/lighttpd_statuscodes* root@server1 /etc/munin/plugins # ./lighttpd_statuscodes autoconf yes root@server1 /etc/munin/plugins # ./lighttpd_statuscodes config graph_title Lighhtpd Statuscodes graph_vlabel http-statuscodes / min graph_category lighttpd 1xx.label 1xx 2xx.label 2xx 3xx.label 3xx 4xx.label 4xx 5xx.label 5xx root@server1 /etc/munin/plugins #./lighttpd_statuscodes 1xx.value 0 2xx.value 5834 3xx.value 1892 4xx.value 0 5xx.value 0 But Munin shows no graph: http://s1.directupload.net/images/111219/3psgq3vb.jpg I have tested the Plugin from munin-server via telnet: root@munin-server /etc/munin/plugins/ # telnet 123.123.123.123 4949 Trying 123.123.123.123... Connected to 123.123.123.123. Escape character is '^]'. # munin node at server1.cluster1 fetch lighttpd_statuscodes 1xx.value U 2xx.value U 3xx.value U 4xx.value U 5xx.value U . Connection closed by foreign host. You can see in the script that value = U only printed, when the script can't check the lighttpd's access.log. But why can't script do it, when running via munin, and when running on local machine all is ok? Is there a bug in my bash-script? I have no Idea. Thanks for helping!

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  • how to set multiple white spaces (ex: tabs) as delimiters in bash's `cut`

    - by Idlecool
    I want to retrieve the cpu usage/free percentage from mpstat output. The bash cut can be used to retrieve such details but i dont know what should be the delimiter viz. [idlecool@archbitch proc]$ mpstat | grep "all" | cut -d '$x' -f11 what should be $x so that i can skip white spaces and select value corresponding to %idle? Output of mpstat: [idlecool@archbitch proc]$ mpstat Linux 2.6.36-ARCH (archbitch) 01/14/11 _i686_ (2 CPU) 19:58:53 CPU %usr %nice %sys %iowait %irq %soft %steal %guest %idle 19:58:53 all 5.51 0.01 2.96 0.84 0.00 0.01 0.00 0.00 90.66

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  • Gettings the `which application` output in Bash

    - by Prudnikov
    Here is my original question at StackOverflow.com This is the script I wrote #!/usr/bin/env bash GP=`/usr/bin/which git` PWD=`pwd` echo "PATH IS: ${GP}" echo "PWD IS: ${PWD}" and output is PATH IS: PWD IS: /Users/user/tmp So the question is how to get which git output? I'm running it on Mac OS X 10.6.2.

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  • send process straight to bg in bash

    - by ItsNannerpuss
    I find I frequently use the combination of Suspend (^Z) then send to background (bg) in bash. Ideally I would like an alternate keyboard shortcut that negates the need to follow ^Z with the bg command, and just send the active process straight to background. Does this exist? Edit: I should have been more specific, but appending & to the command is not sufficient, as they often require interaction (stdin) between launch and backgrounding. So: launch interact background

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  • Bash or Zsh - which one and why?

    - by Andrew
    So, the question pretty much says it all. I'm on Snow Leopard, and I do a lot of web development, particularly in Rails 3 which makes heavy use of the console. I've seen some notable bloggers etc. mention Zsh as their preference over Bash, but I don't know what difference it would make. Could anyone give me a good comparison of what difference there is and what might make one prefer one option or the other? Thanks!

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  • SQL SERVER – Simple Explanation and Puzzle with SOUNDEX Function and DIFFERENCE Function

    - by pinaldave
    Earlier this week I asked a question where I asked how to Swap Values of the column without using CASE Statement. Read here: A Puzzle – Swap Value of Column Without Case Statement,there were more than 50 solutions proposed in the comment. There were many creative solutions. I have mentioned my personal favorite (different ones) here: Solution of Puzzle – Swap Value of Column Without Case Statement. However, I received lots of questions regarding one of the Solution by SIJIN KUMAR V P. He has used the function SOUNDEX in his solution. The request was to explain how SOUNDEX and DIFFERENCE works. Well, there are pretty decent documentations provided over here SOUNDEX function and DIFFERENCE over on MSDN and if I attempt to explain this function I will end up writing the same details which are available on MSDN. Instead of writing theory, we will try to learn this function by using a couple of simple puzzles. You try to solve the puzzles using the MSDN and see if you can learn something very quickly. In simple words - SOUNDEX converts an alphanumeric string to a four-character code to find similar-sounding words or names. The first character of the code is the first character of character_expression and the second through fourth characters of the code are numbers that represent the letters in the expression. Vowels incharacter_expression are ignored unless they are the first letter of the string. DIFFERENCE function returns an integer value. The  integer returned is the number of characters in the SOUNDEX values that are the same. The return value ranges from 0 through 4: 0 indicates weak or no similarity, and 4 indicates strong similarity or the same values. Learning Puzzle 1: Now let us run following four queries and observe its output. SELECT SOUNDEX('SQLAuthority') SdxValue SELECT SOUNDEX('SLTR') SdxValue SELECT SOUNDEX('SaLaTaRa') SdxValue SELECT SOUNDEX('SaLaTaRaM') SdxValue When you look at the result set all the four values are same. The reason for all the values to be same is as for SQL Server SOUNDEX function all the four strings are similarly sounding string. Learning Puzzle 2: Now let us run following five queries and observe its output. SELECT DIFFERENCE (SOUNDEX('SLTR'),SOUNDEX('SQLAuthority')) SELECT DIFFERENCE (SOUNDEX('TH'),SOUNDEX('SQLAuthority')) SELECT DIFFERENCE ('SQLAuthority',SOUNDEX('SQLAuthority')) SELECT DIFFERENCE ('SLTR',SOUNDEX('SQLAuthority')) SELECT DIFFERENCE ('SLTR','SQLAuthority') When you look at the result set you will get the result in the ranges from 1 to 4. Here is how it works if your result is 0 which means absolutely not relevant to each other and if your result is 1 which means the results are relevant to each other. Have you ever used above two functions in your business need or on production server? If yes, would you please leave a comment with use cases. I believe it will be beneficial to everyone. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Function keys on an external keyboard

    - by asymptotically
    So I bought a keyboard for my laptop. Unfortunately, it doesn't have the function key (though I know many people say it's useless). On my laptop, I control volume with the function key and F9-11. How can I get the same functionality on my external keyboard? The advanced keyboard settings don't have an option related to the function key. More specifically, it would be great if I could map it to my 'Menu' key which I'm never going to use. Or is there a way to get full functionality without it?

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  • reference function from another function

    - by JohnWong
    I forgot how to reference another function into a function in C++? In python it is declare as a class so that I can use it. double footInches(double foot) { double inches = (1.0/12.00) * foot; return inches; } double inchMeter(double inch) { double meter = 39.37 * (footInches(inches)); return meter; } I want to reference footInches in inchMeter.

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  • How to overwrite the data in a file with bash

    - by Stefan Liebenberg
    I'm writing a bash script that encrypts the data of a folder or file #!/bin/bash file_name=$1 tmp_file=/tmp/tmpfile.tar # tar compress file tar -cf $tmp_file $file_name; # encrypt file gpg -c $tmp_file # remove temp file rm -rf $tmp_file $file_name # mv encrypted file to orignal place mv ${tmp_file}.gpg $file_name but the data will still be recoverable by using photorec or similar methods... Is there a way to ensure the absolute deletion of the original file in bash? Thank You Stefan

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  • How to automatically add user account *and* password with a Bash script

    - by ModernCarpentry
    I need to have the ability to create user accounts on my Linux ( Fedora 10 ) and automatically assign a password via a bash script ( or otherwise, if need be ). It's easy to create the user via Bash eg: [whoever@server ]# /usr/sbin/useradd newuser But is it possible to assign a password in Bash, something functionally similar to this (but automated): [whoever@server ]# passwd newuser Changing password for user testpass. New UNIX password: Retype new UNIX password: passwd: all authentication tokens updated successfully. [whoever@server ]#

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  • bash script to check running process

    - by elasticsecurity
    I wrote a bash-script to check if a process is running. It doesn't work since the ps command always returns exit code 1. When I run the ps command from the command-line, the $? is correctly set, but within the script it is always 1. Any idea? #!/bin/bash SERVICE=$1 ps -a | grep -v grep | grep $1 > /dev/null result=$? echo "exit code: ${result}" if [ "${result}" -eq "0" ] ; then echo "`date`: $SERVICE service running, everything is fine" else echo "`date`: $SERVICE is not running" fi Bash version: GNU bash, version 3.2.25(1)-release (x86_64-redhat-linux-gnu)

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  • Quicker searching in JScript using the Bash

    - by gentlesea
    I am using the following JScript code to search for a string inside a file: var myFile = aqFile.OpenTextFile(fileToSearchIn, aqFile.faRead, aqFile.ctANSI); while(!myFile.IsEndOfFile()) { s = myFile.ReadLine(); if (aqString.Find(s, searchString) != -1) Log.Checkpoint(searchString + " found.", s); } myFile.Close(); This is rather slow. I was thinking about using bash commands in order to speed up the search in file process: var WshShell = new ActiveXObject("WScript.Shell"); var oExec = WshShell.Exec("C:\\cygwin\\bin\\bash.exe -c 'cat \"" + folderName + "/" + fileName + "\"'"); while (!oExec.StdOut.AtEndOfStream) Log.Checkpoint(oExec.StdOut.ReadLine()); while (!oExec.StdErr.AtEndOfStream) Log.Error(oExec.StdErr.ReadLine()); Since every time bash.exe is started a new window opens the searching is not faster than before. Is there a possibility to have the bash run in the background using another switch?

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  • Unable to modify git bash Windows shortcut

    - by netgirlk
    Under Windows 7 I'd like to change the settings for the Git Bash Here shell extension command window, e.g. width, height and font. But when I do this, I get an error "Unable to modify the shortcut". I can modify the shortcut for Git Bash in the Start menu by using "Run as administrator..." This works, but only for Bash windows opened from the Start menu. It doesn't work for the "Git Bash Here" shell extension and there's no "Run as administrator..." option on right-click context menu. How do you do it?

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  • Bash script to log in over SSH

    - by user1042928
    Sorry if this seems like a dumb question but I am just learning bash scripting. For a school project we need to code an RTX that runs in Unix. It runs as a process in terminal and takes in user input and then prints it to the screen. I want to write a bash script to test that it can respond to lots of quick user input without overflowing or failing. My main problem is that once the RTX starts the bash script will stop on that line until the RTX terminates and only then print the loop to the terminal (instead of printing it to the RTX prompt as I intend it to). I have tried running the RTX in the background but that didn't work. I need to find a way to redirect input to the RTX while it is still running with a bash script. Google searches didn't come up with examples that I understood/could adapt. Any help is appreciated. #!/bin/bash # declare STRING variable STRING="RTX Worked =D" #Start the rtx in a new process, stuck on this line until rtx terminates. ./main #Somehow redirect io to the rtx. for i in `seq 1 100`; do echo $i echo " \n" done echo $STRING

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  • Bash can't start a programme that's there and has all the right permissions

    - by Rory
    This is a gentoo server. There's a programme prog that can't execute. (Yes the execute permission is set) About the file $ ls prog $ ./prog bash: ./prog: No such file or directory $ file prog prog: ELF 32-bit LSB executable, Intel 80386, version 1 (SYSV), for GNU/Linux 2.2.5, dynamically linked (uses shared libs), not stripped $ pwd /usr/local/bin $ /usr/local/bin/prog bash: /usr/local/bin/prog: No such file or directory $ less prog | head ELF Header: Magic: 7f 45 4c 46 01 01 01 00 00 00 00 00 00 00 00 00 Class: ELF32 Data: 2's complement, little endian Version: 1 (current) OS/ABI: UNIX - System V ABI Version: 0 Type: EXEC (Executable file) Machine: Intel 80386 Version: 0x1 I have a fancy less, to show that it's an actual executable, here's some more data: $ xxd prog |head 0000000: 7f45 4c46 0101 0100 0000 0000 0000 0000 .ELF............ 0000010: 0200 0300 0100 0000 c092 0408 3400 0000 ............4... 0000020: 0401 0a00 0000 0000 3400 2000 0700 2800 ........4. ...(. 0000030: 2600 2300 0600 0000 3400 0000 3480 0408 &.#.....4...4... 0000040: 3480 0408 e000 0000 e000 0000 0500 0000 4............... 0000050: 0400 0000 0300 0000 1401 0000 1481 0408 ................ 0000060: 1481 0408 1300 0000 1300 0000 0400 0000 ................ 0000070: 0100 0000 0100 0000 0000 0000 0080 0408 ................ 0000080: 0080 0408 21f1 0500 21f1 0500 0500 0000 ....!...!....... 0000090: 0010 0000 0100 0000 40f1 0500 4081 0a08 ........@...@... and $ ls -l prog -rwxrwxr-x 1 1000 devs 725706 Aug 6 2007 prog $ ldd prog not a dynamic executable $ strace ./prog 1249403877.639076 execve("./prog", ["./prog"], [/* 27 vars */]) = -1 ENOENT (No such file or directory) 1249403877.640645 dup(2) = 3 1249403877.640875 fcntl(3, F_GETFL) = 0x8002 (flags O_RDWR|O_LARGEFILE) 1249403877.641143 fstat(3, {st_mode=S_IFCHR|0620, st_rdev=makedev(136, 0), ...}) = 0 1249403877.641484 mmap(NULL, 4096, PROT_READ|PROT_WRITE, MAP_PRIVATE|MAP_ANONYMOUS, -1, 0) = 0x2b3b8954a000 1249403877.641747 lseek(3, 0, SEEK_CUR) = -1 ESPIPE (Illegal seek) 1249403877.642045 write(3, "strace: exec: No such file or dir"..., 40strace: exec: No such file or directory ) = 40 1249403877.642324 close(3) = 0 1249403877.642531 munmap(0x2b3b8954a000, 4096) = 0 1249403877.642735 exit_group(1) = ? About the server FTR the server is a xen domU, and the programme is a closed source linux application. This VM is a copy of another VM that has the same root filesystem (including this programme), that works fine. I've tried all the above as root and same problem. Did I mention the root filesystem is mounted over NFS. However it's mounted 'defaults,nosuid', which should include execute. Also I am able to run many other programmes from that mounted drive /proc/cpuinfo: processor : 0 vendor_id : GenuineIntel cpu family : 15 model : 4 model name : Intel(R) Xeon(TM) CPU 3.00GHz stepping : 1 cpu MHz : 2992.692 cache size : 1024 KB fpu : yes fpu_exception : yes cpuid level : 5 wp : yes flags : fpu tsc msr pae mce cx8 apic mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm syscall nx lm constant_tsc pni monitor ds_cpl cid cx16 xtpr bogmips : 5989.55 clflush size : 64 cache_alignment : 128 address sizes : 36 bits physical, 48 bits virtual power management: Example of a file that I can run I can run other programmes on that mounted filesystem on that server. For example: $ ls -l ls -rwxr-xr-x 1 root root 105576 Jul 25 17:14 ls $ file ls ls: ELF 64-bit LSB executable, x86-64, version 1 (SYSV), for GNU/Linux 2.6.9, dynamically linked (uses shared libs), stripped $ ./ls attr cat cut echo getfacl ln more ... (you get the idea) ... rmdir sort tty $ less ls | head ELF Header: Magic: 7f 45 4c 46 02 01 01 00 00 00 00 00 00 00 00 00 Class: ELF64 Data: 2's complement, little endian Version: 1 (current) OS/ABI: UNIX - System V ABI Version: 0 Type: EXEC (Executable file) Machine: Advanced Micro Devices X86-64 Version: 0x1

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  • segfault when cd-ing into certain directories in bash

    - by user84207
    I have noticed this very strange behavior recently. After cd into certain directories, I get a segfault on the terminal. --- SIGSEGV (Segmentation fault) @ 0 (0) --- --- SIGSEGV (Segmentation fault) @ 0 (0) --- +++ killed by SIGSEGV (core dumped) +++ segmentation fault (core dumped) I proceeded to strace a bash session in which I cd into the target directory, and was able to reproduce the problem. I attached the log to this pastebin: I paste below the few lines from the read of "cd stumpwm", which is the directory in question, until the segfault. I included a few of the repetitions of calls to "rt_sigprocmask" and "brk" to give a glimpse of the pattern, which occurs for most of the strace, read(0, cd stumpwm "c", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "d", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, " ", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "s", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "t", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "u", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "m", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "p", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "w", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "m", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "\n", 1) = 1 rt_sigprocmask(SIG_BLOCK, [INT], [], 8) = 0 ioctl(0, SNDCTL_TMR_TIMEBASE or TCGETS, {B38400 opost isig -icanon -echo ...}) = 0 ioctl(0, SNDCTL_TMR_STOP or TCSETSW, {B38400 opost isig icanon -echo ...}) = 0 ioctl(0, SNDCTL_TMR_TIMEBASE or TCGETS, {B38400 opost isig icanon -echo ...}) = 0 rt_sigprocmask(SIG_SETMASK, [], NULL, 8) = 0 rt_sigaction(SIGINT, {0x457d50, [], SA_RESTORER, 0x7ffff76254a0}, {0x49edc0, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGTERM, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGQUIT, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGALRM, {0x457f50, [HUP INT ILL TRAP ABRT BUS FPE USR1 SEGV USR2 PIPE ALRM TERM XCPU XFSZ VTALRM SYS], SA_RESTORER, 0x7ffff76254a0}, {0x49edc0, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGTSTP, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGTTOU, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGTTIN, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGWINCH, {0x457920, [], SA_RESTORER, 0x7ffff76254a0}, {0x49e6e0, [], SA_RESTORER|SA_RESTART, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGINT, {0x457d50, [], SA_RESTORER, 0x7ffff76254a0}, {0x457d50, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 brk(0xa9a000) = 0xa9a000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xa9b000) = 0xa9b000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xa9c000) = 0xa9c000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xa9d000) = 0xa9d000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xa9e000) = 0xa9e000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xa9f000) = 0xa9f000 brk(0xaa0000) = 0xaa0000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xaa1000) = 0xaa1000 brk(0xaa2000) = 0xaa2000 (pattern of rt_sigprocmask, brk continues ...) rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0x1d5b000) = 0x1d5b000 brk(0x1d5c000) = 0x1d5c000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0x1d5d000) = 0x1d5d000 brk(0x1d5e000) = 0x1d5e000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 --- SIGSEGV (Segmentation fault) @ 0 (0) --- --- SIGSEGV (Segmentation fault) @ 0 (0) --- +++ killed by SIGSEGV (core dumped) +++ segmentation fault (core dumped) How can I debug this? Is this likely to be a bash problem? The error does not occur with another shell, such as eshell. I have also run an fschk, although I haven't been able to see the output because of this bug.

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  • In GNU Screen, Recalled bash history command displays one character position to the left of actual location

    - by vergueishon
    I am running Red Hat 5 32-bit (2.6.18-194.26.1.el5). The issue is that when I recall any previous command in bash's history, the first character in the command is displayed immediately after the shell prompt, without any intervening space, likeso: \[me@mymachine tmp]$man mysql If I enter a Ctrl-C, and retype the command, it looks likeso: \[me@mymachine tmp]$ man mysql This makes recalling a command and editing it before re-entering a real pain. Basically, if I try to edit a recalled command, my changes occur one character position to the left (I believe) of what I see on the screen. It's a bit tedious to describe, and appears to only happen with commands with a large number of arguments. UPDATE: The contents of /etc/sysconfig/bash-prompt-screen, 1 #!/bin/bash 2 echo -n $'\033'"_${USER}@${HOSTNAME%%.*}:${PWD/#$HOME/~}"$'\033\\\\' and the contents of /etc/bashrc, 24 screen) 25 if [ -e /etc/sysconfig/bash-prompt-screen ]; then 26 PROMPT_COMMAND=/etc/sysconfig/bash-prompt-screen 27 else 28 PROMPT_COMMAND='echo -ne "\033_${USER}@${HOSTNAME%%.*}:${PWD/#$HOME/~}"; echo -ne "\033\\"' 29 fi 30 ;; I've disable bash-prompt-screen by renaming it--this fixed it. It's entirely possible that there is a fix to the bash-prompt-screen prompt line in the latest version of screen for RHEL 5. The error is seen under Screen version 4.00.03 (FAU) 23-Oct-06. (I noticed an update in the queue, which is installing as I write this.)

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  • complex arguments for function

    - by myPost1
    My task is to create function funCall taking four arguments : pointer for 2d array of ints that stores pairs of numbers variable int maintaining number of numbers in 2d array pointer for table of pointers to functions int variable storing info about number of pointers to functions I was thinking about something like this : typedef int(*funPtr)(int, int); funPtr arrayOfFuncPtrs[]; void funCall( *int[][]k, int a, *funPtr z, int b); { }

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  • Must declare function prototype in C?

    - by Mohit Deshpande
    I am kind of new to C (I have prior Java, C#, and some C++ experience). In C, is it necessary to declare a function prototype or can the code compile without it? Is it good programming practice to do so? Or does it just depend on the compiler? (I am running Ubuntu 9.10 and using the GNU C Compiler, or gcc, under the Code::Blocks IDE)

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  • Proper way to let user enter password for a bash script using only the GUI (with the terminal hidden)

    - by MountainX
    I have made a bash script that uses kdialog exclusively for interacting with the user. It is launched from a ".desktop" file so the user never sees the terminal. It looks 100% like a GUI app (even though it is just a bash script). It runs in KDE only (Kubuntu 12.04). My only problem is handling password input securely and conveniently. I can't find a satisfactory solution. The script was designed to be run as a normal user and to prompt for the password when a sudo command is first needed. In this way, most commands, those not requiring sudo rights, are run as the normal user. What happens (when the script is run from the terminal) is that the user is prompted for their password once and the default sudo timeout allows the script to finish, including any additional sudo commands, without prompting the user again. This is how I want it to work when run behind the GUI too. The main problem is that using kdesudo to launch my script, which is the standard GUI way, means that the entire script is executed by the root user. So file ownerships get assigned to the root user, I can't rely upon ~/ in paths, and many other things are less than ideal. Running the entire script as the root user is just a very unsatisfactory solution and I think it is a bad practice. I appreciate any ideas for letting a user enter the sudo password just once via GUI while not running the whole script as root. Thanks.

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  • getting bash to load my PATH over SSH

    - by Eli Bendersky
    This problem comes up with me trying to make svnserve (Subversion server) available on a server through SSH. I compiled SVN and installed it in $HOME/bin. Local access to it (not through SSH) works fine. Connections to svn+ssh fail due to: bash: svnserve: command not found Debugging this, I've found that: ssh user@server "which svnserve" says: which: no svnserve in (/usr/bin:/bin) This is strange, because I've updated the path to $HOME/bin in my .bashrc, and also added it in ~/.ssh/environment. However, it seems like the SSH doesn't read it. Although when I run: ssh user@server "echo $PATH" It does print my updated path! What's going on here? How can I make SSH find my svnserve? Thanks in advance

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  • CentOS Backup BASH Script

    - by user1062058
    I just wrote this script for backing up everything into a tar.gz file. Does it look okay? How can I get the tar file to transfer itself over to another server after executing? FTP from itself? I'm going to put this script into a weekly cron. #!/bin/bash rm ~/backup.tar.gz #removes old backup BACKUP_DIRS=$HOME #$HOME is builtin, it goes to /home/ and all child dirs tar -cvzf backup.tar.gz $BACKUP_DIRS # run tar -zxvf to extract backup.tar.gz Thanks.

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