Search Results

Search found 1682 results on 68 pages for 'colors'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 12/68 | < Previous Page | 8 9 10 11 12 13 14 15 16 17 18 19  | Next Page >

  • finding "distance" between two pixel's colors.

    - by igor
    Once more something relatively simple, but confused as to what they want. the method to find distance on cartesian coordinate system is distance=sqrt[(x2-x1)^2 + (y2-y1)^2] but how do i apply it here? //Requires: testColor to be a valid Color //Effects: returns the "distance" between the current Pixel's color and // the passed color // uses the standard method to calculate "distance" // uses the same formula as finding distance on a // Cartesian coordinate system double colorDistance(Color testColor) const;

    Read the article

  • Can I get consistent CSS colors across browsers?

    - by Trevor Burnham
    I'm testing a new site, and I have a div with background-color: #bbf6bb; That seems innocuous enough to me. And yet, on my MacBook Pro, the color looks very different in Firefox 3.6 vs. Safari 4. In Safari, it's the color I'd expect from the hex value: a pale green. In Firefox, there's a definite bluish tint, making the color turquoise. I'm aware of color inconsistencies that result from different treatment of images across browsers, but in pure CSS? Really? I'm guessing that Firefox trying to correct for my display in hopes of delivering better consistency with print, but I'd much rather have my site look the same hue to my users regardless of their choice of browser. Any ideas? Can someone confirm that Firefox is the culprit here? [Update: This seems to have been a fluke. Specifically, it's a narrow issue with Firefox—see my answer below. I'm puzzled, but relieved.]

    Read the article

  • Alpha blending colors in .NET Compact Framwork 2.0

    - by Adam Haile
    In the Full .NET framework you can use the Color.FromArgb() method to create a new color with alpha blending, like this: Color blended = Color.FromArgb(alpha, color); or Color blended = Color.FromArgb(alpha, red, green , blue); However in the Compact Framework (2.0 specifically), neither of those prototypes are valid, you only get: Color.FromArgb(int red, int green, int blue); and Color.FromArgb(int val); The first one, obviously, doesn't even let you enter an alpha value, but the documentation for the latter shows that "val" is a 32bit ARGB value (as 0xAARRGGBB as opposed to the standard 24bit 0xRRGGBB), so it would make sense that you could just build the ARGB value and pass it to the function. I tried this with the following: private Color FromARGB(byte alpha, byte red, byte green, byte blue) { int val = (alpha << 24) | (red << 16) | (green << 8) | blue; return Color.FromArgb(val); } But no matter what I do, the alpha blending never works, the resulting color always as full opacity, even when setting the alpha value to 0. Has anyone gotten this to work on Compact Framework?

    Read the article

  • How to give alternating table rows different background colors using PHP

    - by Sam
    I have a table of data that is generated dynamically based on the contents stored in a mysql database. This is how my code looks: <table border="1"> <tr> <th>Name</th> <th>Description</th> <th>URL</th> </tr> <?php $query = mysql_query("SELECT * FROM categories"); while ($row = mysql_fetch_assoc($query)) { $catName = $row['name']; $catDes = $row['description']; $catUrl = $row['url']; echo "<tr class=''>"; echo "<td>$catName</td>"; echo "<td>$catDes</td>"; echo "<td>$catUrl</td>"; echo "</tr>"; } ?> </table> Now if the table was static, then I would just assign each alternating table row one of 2 styles in repeated order: .whiteBackground { background-color: #fff; } .grayBackground { background-color: #ccc; } and that would be the end of that. However since the table rows are dynamically generated, how can I achieve this?

    Read the article

  • Different background colors for the top and bottom of a UITableView

    - by Aaron Brethorst
    If you look at your Inbox in iPhone OS 3.0's Mail app, you'll see that swiping down displays a grayish background color above the UISearchBar. Now, if you scroll down to the bottom of the table, you'll see that the background color at that end is white. I can think of a couple ways of solving this problem, but they're pretty hacky: Change the table view's background color depending on the current scrollOffset by overriding -scrollViewDidScroll: Give the UITableView a clear background color and then set its superview's backgroundColor to a gradient pattern image. Does anyone know what the "best practice" solution is for this problem? thanks.

    Read the article

  • View plain text files with different background colors in Mac OSX, for different programming languag

    - by Werner
    Hi, I work with Mac OS X Leopard. I usually have 5 or 10 text files opened at the same time with different programming languages; one for a bash script, another for a python one, etc. When I use exposé all of them look the same, so it is difficult to select them. I wonder how could I work with just plain text files in OSX, so when they are opened in an editor the background color changes or some other thign, so when using exposé it is clear to me which window belongs to what language. I thought about inserting some kind of info to the last line of each document, and then creat some applescript that converts it to RTF or someother text document which includes color in bacjground, so then it is opened with textmate or someother app. Do you know a better approach for this? Thanks

    Read the article

  • Gradient colors in Internet Explorer

    - by Jeremy
    I know that Internet Explorer has some proprietary extensions so that you can do things like create divs with a gradient background. I can't remember the element name or it's usage. Does anyone have some examples or links?

    Read the article

  • Assign different colors to individual array elements

    - by rk.
    Say I have the array, arr1. I want to print this array (i.e. just display the numbers) but, I want to color the numbers based on their values. If arr1[i]<15, green, if arr1[i]20, red, else orange. Something to this effect. var arr1 = [ 5,10,13,19,21,25,22,18,15,13,11,12,15,20,18,17,16,18,23,25,25,22,18,15,13,11,12,15,20,18]; Here is what I tried doing: for(var i=0; i<arr1.length;i++){ if(arr1[i]<15){ var temp = $(this).css("color","green"); $this.text(temp); } else if(arr1[i]>20){ var temp = $(this).css("color","red"); $this.text(temp); } else { var temp = $(this).css("color","orange"); $this.text(temp); } } I tried changing the css property of individual elements and them adding them to the div, but it did not work for me. Can someone suggest how should I go about doing this?

    Read the article

  • R: Plotting a graph with different colors of points based on advanced criteria

    - by balconydoor
    What I would like to do is a plot (using ggplot), where the x axis represent years which have a different colour for the last three years in the plot than the rest. The last three years should also meet a certain criteria and based on this the last three years can either be red or green. The criteria is that the mean of the last three years should be less (making it green) or more (making it red) than the 66%-percentile of the remaining years. So far I have made two different functions calculating the last three year mean: LYM3 <- function (x) { LYM3 <- tail(x,3) mean(LYM3$Data,na.rm=T) } And the 66%-percentile for the remaining: perc66 <- function(x) { percentile <- head(x,-3) quantile(percentile$Data, .66, names=F,na.rm=T) } Here are two sets of data that can be used in the calculations (plots), the first which is an example from my real data where LYM3(df1) < perc66(df1) and the second is just made up data where LYM3 perc66. df1<- data.frame(Year=c(1979:2010), Data=c(347261.87, 145071.29, 110181.93, 183016.71, 210995.67, 205207.33, 103291.78, 247182.10, 152894.45, 170771.50, 206534.55, 287770.86, 223832.43, 297542.86, 267343.54, 475485.47, 224575.08, 147607.81, 171732.38, 126818.10, 165801.08, 136921.58, 136947.63, 83428.05, 144295.87, 68566.23, 59943.05, 49909.08, 52149.11, 117627.75, 132127.79, 130463.80)) df2 <- data.frame(Year=c(1979:2010), Data=c(sample(50,29,replace=T),75,75,75)) Here’s my code for my plot so far: plot <- ggplot(df1, aes(x=Year, y=Data)) + theme_bw() + geom_point(size=3, aes(colour=ifelse(df1$Year<2008, "black",ifelse(LYM3(df1) < perc66(df1),"green","red")))) + geom_line() + scale_x_continuous(breaks=c(1980,1985,1990,1995,2000,2005,2010), limits=c(1978,2011)) plot As you notice it doesn’t really do what I want it to do. The only thing it does seem to do is that it turns the years before 2008 into one level and those after into another one and base the point colour off these two levels. Since I don’t want this year to be stationary either, I made another tiny function: fun3 <- function(x) { df <- subset(x, Year==(max(Year)-2)) df$Year } So the previous code would have the same effect as: geom_point(size=3, aes(colour=ifelse(df1$Year<fun3(df1), "black","red"))) But it still does not care about my colours. Why does it make the years into levels? And how come an ifelse function doesn’t work within another one in this case? How would it be possible to the arguments to do what I like? I realise this might be a bit messy, asking for a lot at the same time, but I hope my description is pretty clear. It would be helpful if someone could at least point me in the right direction. I tried to put the code for the plot into a function as well so I wouldn’t have to change the data frame at all functions within the plot, but I can’t get it to work. Thank you!

    Read the article

  • Using variables for colors in table cells

    - by Mark Robinson
    Using the variables extension, I want to change the background color of a cell in a table. So far I've done this: {{#vardefine:green|<span style="background:Green; color:White">text</span>}} The problem is that, when I add {{#var:green}} to the cell, only the text itself has a green background. Ideally, I want the whole cell to have a background color, like it does if I use this: | bgcolor="#ff00ff" | test or this | style="background:silver" |silver in the cell. Does anyone know how to solve this?

    Read the article

  • Business Objects ver 3 Alternate Row/Column Colors not active

    - by boxeo47
    I am converting reports from version 2 to version 3. When I select the vertical table in the report, the propeties box appears but any changes I make is not reflected in the table. If I change any attributes at the column or cell level however, the changes are taken. The problem is that some attributes like alternate row coloring are not available at the column level.

    Read the article

  • Alternate colors on click with jQuery

    - by Jace Cotton
    I'm sure there is a simple solution to this, and I'm sure this is a duplicate question, though I have been unable to solve my solution particularly because I don't really know how to phrase it in order to search for other questions/solutions, so I'm coming here hoping for some help. Basically, I have spans with classes that assigns a background-color property, and inside those spans are words. I have three of these spans, and each time a user clicks on a span I want the class to change (thus changing the background color and inner text). HTML: <span class="alternate"> <span class="blue showing">Lorem</span> <span class="green">Ipsum</span> <span class="red">Dolor</span> </span> CSS: .alternate span { display : none } .alternate .showing { display : inline } .blue { background : blue } .green { background : green } .red { background : red } jQuery: $(".alternate span").each(function() { $(this).on("click", function() { $(this).removeClass("showing"); $(this).next().addClass("showing"); }); }); This solution works great using $.next until I get to the third click, whereafter .showing is removed, and is not added since there are no more $.next options. How do I, after getting to the last-child, add .showing to the first-child and then start over? I have tried various options including if($(".alternate span:last-child").hasClass("showing")) { etc. etc. }, and I attempted to use an array and for loop though I failed to make it work. Newb question, I know, but I can't seem to solve this so as a last resort I'm coming here.

    Read the article

  • Merge 2 Colors to make a tranparent Ovelap?

    - by CrazyJoe
    I have two System.Windows.Media.Color (a and b)and need to get a and put over b to simulate tranparency. to use in my merge method: public static Image Merge(Image a,Image b) { for(int x=0;x < b.Width;x++ ) { for (int y = 0; y < b.Height; y++) { a.SetPixel(x, y, b.GetPixel(x, y)); } } return a; } Help Thank's!!

    Read the article

  • Toggling row colors

    - by cf_PhillipSenn
    I have a table cell in the footer that allows the user to turn on row coloring: $('#highlight').click(function() { $(this).parents('table').RowColors(); }) // From Chapter 7 of Learning jQuery $.fn.RowColors = function() { $('tbody tr:odd', this).removeClass('even').addClass('odd'); $('tbody tr:even', this).removeClass('odd').addClass('even'); return this; }; Q: How do I write a selector that says: IF there is at least 1 row with class="even", then remove both "even" and "odd" ELSE execute the RowColors function.

    Read the article

  • click events issue in jquery.

    - by alex
    I don't know if the title explain this situation well. Below is a code i wrote to create div elements when the button is pressed. Then By clicking on any of the created divs, we can change the div background by choosing a color from the drop down box. However if i click on another div and tried to change the color by selecting another color from the drop down, the previously clicked divs also gets affected by the new color. Why is this happening. I only want the selected div to change color, without affecting the previously clicked divs. I read allot of threads on this site, some of which talks about unbinding clicks, but I'm unable to solve the problem. Thanks for the help. <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js" type="text/javascript"></script> <style> .aaa { width:100px; height:100px;background-color:#ccc;margin-bottom:5px;} p{widht:500px; height:500px; margin:0px; padding:0px;border:2px solid red;color:#000;} </style> <select id="item_select" name="item"> <option value="1">red</option> <option value="2">blue</option> <option value="3">green</option> </select> <button>Click to create divs</button> <p id="ptest"></p> <script type="text/javascript"> var dividcount = 1; $("button").click(run); function run(){ var myDiv = $('<div id=lar'+dividcount+' class=aaa></div>'); $(myDiv).clone().appendTo('#ptest'); $(dividcount++); $("div").bind('click',(function() { var box = $("div").index(this); var idd = (this.id); $("#"+idd).text("div #"+idd); $("select").change(function(){ var str= $("select option:selected").text(); $("#"+idd).css("background-color",str); }); })); }; </script>

    Read the article

  • Soft Paint Bucket Fill: Colour Equality

    - by Bart van Heukelom
    I'm making a small app where children can fill preset illustrations with colours. I've succesfully implemented an MS-paint style paint bucket using the flood fill argorithm. However, near the edges of image elements pixels are left unfilled, because the lines are anti-aliased. This is because the current condition on whether to fill is colourAtCurrentPixel == colourToReplace (the colours are RGB uints) I'd like to add a smoothing/treshold option like in Photoshop and other sophisticated tools, but what's the algorithm to determine the equality/distance between two colours? if (match(pixel(x,y), colourToReplace) setpixel(x,y,colourToReplaceWith) How to fill in match()? Here's my current full code: var b:BitmapData = settings.background; b.lock(); var from:uint = b.getPixel(x,y); var q:Array = []; var xx:int; var yy:int; var w:int = b.width; var h:int = b.height; q.push(y*w + x); while (q.length != 0) { var xy:int = q.shift(); xx = xy % w; yy = (xy - xx) / w; if (b.getPixel(xx,yy) == from) { b.setPixel(xx,yy,to); if (xx != 0) q.push(xy-1); if (xx != w-1) q.push(xy+1); if (yy != 0) q.push(xy-w); if (yy != h-1) q.push(xy+w); } } b.unlock(null);

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 8 9 10 11 12 13 14 15 16 17 18 19  | Next Page >