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  • Django admin.py missing field error

    - by user782400
    When I include 'caption', I get an error saying EntryAdmin.fieldsets[1][1]['fields']' refers to field 'caption' that is missing from the form In the admin.py; I have imported the classes from joe.models import Entry,Image Is that because my class from models.py is not getting imported properly ? Need help in resolving this issue. Thanks. models.py class Image(models.Model): image = models.ImageField(upload_to='joe') caption = models.CharField(max_length=200) imageSrc = models.URLField(max_length=200) user = models.CharField(max_length=20) class Entry(models.Model): image = models.ForeignKey(Image) mimeType = models.CharField(max_length=20) name = models.CharField(max_length=200) password = models.URLField(max_length=50) admin.py class EntryAdmin(admin.ModelAdmin): fieldsets = [ ('File info', {'fields': ['name','password']}), ('Upload image', {'fields': ['image','caption']})] list_display = ('name', 'mimeType', 'password') admin.site.register(Entry, EntryAdmin) admin.site.register(Image)

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  • Django templates tag error

    - by Hulk
    def _table_(request,id,has_permissions): dict = {} dict.update(get_newdata(request,rid)) return render_to_response('home/_display.html',context_instance=RequestContext(request,{'dict': dict, 'rid' : rid, 'has_permissions' : str(has_permissions)})) In templates the code is as, {% if has_permissions == "1" %} <input type="button" value="Edit" id="edit" onclick="javascript:edit('{{id}}')" style="display:inline;"/>&nbsp;&nbsp;&nbsp;&nbsp; {% endif %} There is a template error in has_permissions line. Can any 1 tell me what is wrong here. has_permissions has the value 1 or 0.

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  • querying for timestamp field in django

    - by Hulk
    In my views i have the date in the following format s_date=20090106 and e_date=20100106 The model is defined as class Activity(models.Model): timestamp = models.DateTimeField(auto_now_add=True) how to query for the timestamp filed with the above info. Activity.objects.filter(timestamp>=s_date and timestamp<=e_date) Thanks.....

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  • Creating a QuerySet based on a ManyToManyField in Django

    - by River Tam
    So I've got two classes; Picture and Tag that are as follows: class Tag(models.Model): pics = models.ManyToManyField('Picture', blank=True) name = models.CharField(max_length=30) # stuff omitted class Picture(models.Model): name = models.CharField(max_length=100) pub_date = models.DateTimeField('date published') tags = models.ManyToManyField('Tag', blank=True) content = models.ImageField(upload_to='instaton') #stuff omitted And what I'd like to do is get a queryset (for a ListView) given a tag name that contains the most recent X number of Pictures that are tagged as such. I've looked up very similar problems, but none of the responses make any sense to me at all. How would I go about creating this queryset?

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  • Django templates check condition

    - by Hulk
    If there are are no values in the table how can should the code be to indicate no name found else show the drop down box in the below code {% for name in dict.names %} <option value="{{name.id}}" {% for selected_id in selected_name %}{% ifequal name.id selected_id %} {{ selected }} {% endifequal %} {% endfor %}>{{name.firstname}}</option>{% endfor %} </select> Thanks..

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  • Django - calling full_clean() inside of clean() equivalent?

    - by orokusaki
    For transaction purposes, I need all field validations to run before clean() is done. Is this possible? My thinking is this: @transaction.commit_on_success def clean(self): # Some fun stuff here. self.full_clean() # I know this isn't correct, but it illustrates my point. but obviously that's not correct, because it would be recursive. Is there a way to make sure that everything that full_clean() does is done inside clean()?

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  • Debugging "Premature end of script headers" - WSGI/Django [migrated]

    - by Marcin
    I have recently deployed an app to a shared host (webfaction), and for no apparent reason, my site will not load at all (it worked until today). It is a django app, but the django.log is not even created; the only clue is that in one of the logs, I get the error message: "Premature end of script headers", identifying my wsgi file as the source. I've tried to add logging to my wsgi file, but I can't find any log created for it. Is there any recommended way to debug this error? I am on the point of tearing my hair out. My WSGI file: import os import sys from django.core.handlers.wsgi import WSGIHandler import logging logger = logging.getLogger(__name__) os.environ['DJANGO_SETTINGS_MODULE'] = 'settings' os.environ['CELERY_LOADER'] = 'django' virtenv = os.path.expanduser("~/webapps/django/oneclickcosvirt/") activate_this = virtenv + "bin/activate_this.py" execfile(activate_this, dict(__file__=activate_this)) # if 'VIRTUAL_ENV' not in os.environ: # os.environ['VIRTUAL_ENV'] = virtenv sys.path.append(os.path.dirname(virtenv+'oneclickcos/')) logger.debug('About to run WSGIHandler') try: application = WSGIHandler() except (Exception,), e: logger.debug('Exception starting wsgihandler: %s' % e) raise e

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  • Disabling email-style usernames in Django 1.2 with django-registration

    - by shacker
    Django 1.2 allows usernames to take the form of an email address. Changed in Django 1.2: Usernames may now contain @, +, . and - characters I know that's a much-requested feature, but what if you don't want the new behavior? It makes for messy usernames in profile URLs and seems to break django-registration (if a user registers an account with an email-style username, the link in the django-registration activation email returns 404). Does anyone have a recipe for restoring the old behavior and disabling email-style usernames?

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  • Does Django cache url regex patterns somehow?

    - by Emre Sevinç
    I'm a Django newbie who needs help: Even though I change some urls in my urls.py I keep on getting the same error message from Django. Here is the relevant line from my settings.py: ROOT_URLCONF = 'mydjango.urls' Here is my urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^mydjango/', include('mydjango.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: #(r'^admin/doc/', include(django.contrib.admindocs.urls)), # (r'^polls/', include('mydjango.polls.urls')), (r'^$', 'mydjango.polls.views.homepage'), (r'^polls/$', 'mydjango.polls.views.index'), (r'^polls/(?P<poll_id>\d+)/$', 'mydjango.polls.views.detail'), (r'^polls/(?P<poll_id>\d+)/results/$', 'mydjango.polls.views.results'), (r'^polls/(?P<poll_id>\d+)/vote/$', 'mydjango.polls.views.vote'), (r'^polls/randomTest1/', 'mydjango.polls.views.randomTest1'), (r'^admin/', include(admin.site.urls)), ) So I expect that whenever I visit http://mydjango.yafz.org/polls/randomTest1/ the mydjango.polls.views.randomTest1 function should run because in my polls/views.py I have the relevant function: def randomTest1(request): # mainText = request.POST['mainText'] return HttpResponse("Default random test") However I keep on getting the following error message: Page not found (404) Request Method: GET Request URL: http://mydjango.yafz.org/polls/randomTest1 Using the URLconf defined in mydjango.urls, Django tried these URL patterns, in this order: 1. ^$ 2. ^polls/$ 3. ^polls/(?P<poll_id>\d+)/$ 4. ^polls/(?P<poll_id>\d+)/results/$ 5. ^polls/(?P<poll_id>\d+)/vote/$ 6. ^admin/ 7. ^polls/randomTest/$ The current URL, polls/randomTest1, didn't match any of these. I'm surprised because again and again I check urls.py and there is no ^polls/randomTest/$ in it, but there is ^polls/randomTest1/' It seems like Django is somehow storing the previous contents of urls.py and I just don't know how to make my latest changes effective. Any ideas? Why do I keep on seeing some old version of regexes when I try to load that page even though I changed my urls.py?

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  • force delete row on django app after migration

    - by unsorted
    After a migration with south, I ended up deleting a column. Now the current data in one of my tables is screwed up and I want to delete it, but attempts to delete just result in an error: >>> d = Degree.objects.all() >>> d.delete() Traceback (most recent call last): File "<console>", line 1, in <module> File "C:\Python26\lib\site-packages\django\db\models\query.py", line 440, in d elete for i, obj in izip(xrange(CHUNK_SIZE), del_itr): File "C:\Python26\lib\site-packages\django\db\models\query.py", line 106, in _ result_iter self._fill_cache() File "C:\Python26\lib\site-packages\django\db\models\query.py", line 760, in _ fill_cache self._result_cache.append(self._iter.next()) File "C:\Python26\lib\site-packages\django\db\models\query.py", line 269, in i terator for row in compiler.results_iter(): File "C:\Python26\lib\site-packages\django\db\models\sql\compiler.py", line 67 2, in results_iter for rows in self.execute_sql(MULTI): File "C:\Python26\lib\site-packages\django\db\models\sql\compiler.py", line 72 7, in execute_sql cursor.execute(sql, params) File "C:\Python26\lib\site-packages\django\db\backends\util.py", line 15, in e xecute return self.cursor.execute(sql, params) File "C:\Python26\lib\site-packages\django\db\backends\sqlite3\base.py", line 200, in execute return Database.Cursor.execute(self, query, params) DatabaseError: no such column: students_degree.abbrev >>> Is there a simple way to just force a delete? Do I drop the table and then rerun manage.py schemamigration to recreate the table in south?

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  • 2-step user registration with Django

    - by David S
    I'm creating a website with Django and want a fairly common 2-step user registration. What I mean by this is that the user fills in the some basic user information + some application specific information (sort of like a coupon value). Upon submit, an email is sent to ensure email address is valid. This email should contain a link to click on to "finish" the registration. When the link is clicked, the user is marked as validated and they are directed to a new page to complete optional "user profile" type information. So, pretty basic stuff. I have done some research and found django-registration by James Bennett. I do know who James is and have seen him at PyCons and DjanoCons in the past. There is obviously very few people in the world that know Django better than James (so, I know the quality of the code/app is good). But, it almost seems like a bit of over kill. I've read through the docs and was a bit confused (maybe I'm just being a bit dense today). I believe that if I do use django-registration, I will need to have some custom forms, etc. Is there anything else out there I should evaluate? Or are there any good tutorials or videos on using django-registration? I've done a bit of googling, but haven't found anything. But, I suspect that it might be a case of a lot of very common words that don't really find what you are looking for (django user registration tutorial/example). Or is just a case where it would be just about as easy to build your own solution with Django forms, etc? Here is the tech stack I'm using: Python 2.7.2 Django 1.3.1 PostgreSQL 9.1 psycopg2 2.4.1 Twitter Bootstrap 2.0.2

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  • error in implementing static files in django

    - by POOJA GUPTA
    my settings.py file:- STATIC_ROOT = '/home/pooja/Desktop/static/' # URL prefix for static files. STATIC_URL = '/static/' # Additional locations of static files STATICFILES_DIRS = ( '/home/pooja/Desktop/mysite/search/static', ) my urls.py file:- from django.conf.urls import patterns, include, url from django.contrib.staticfiles.urls import staticfiles_urlpatterns from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', url(r'^search/$','search.views.front_page'), url(r'^admin/', include(admin.site.urls)), ) urlpatterns += staticfiles_urlpatterns() I have created an app using django which seraches the keywords in 10 xml documents and then return their frequency count displayed as graphical representation and list of filenames and their respective counts.Now the list has filenames hyperlinked, I want to display them on the django server when user clicks them , for that I have used static files provision in django. Hyperlinking has been done in this manner: <ul> {% for l in list1 %} <li><a href="{{STATIC_URL}}static/{{l.file_name}}">{{l.file_name}}</a{{l.frequency_count</li> {% endfor %} </ul> Now when I run my app on the server, everything is running fine but as soon as I click on the filename, it gives me this error : Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order: ^search/$ ^admin/ ^static\/(?P<path>.*)$ The current URL, search/static/books.xml, didn't match any of these. I don't know why this error is coming, because I have followed the steps required to achieve this. I have posted my urls.py file and it is showing error in that only. I'm new to django , so Please help

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  • How to make a model instance read-only after saving it once?

    - by Ryszard Szopa
    One of the functionalities in a Django project I am writing is sending a newsletter. I have a model, Newsletter and a function, send_newsletter, which I have registered to listen to Newsletter's post_save signal. When the newsletter object is saved via the admin interface, send_newsletter checks if created is True, and if yes it actually sends the mail. However, it doesn't make much sense to edit a newsletter that has already been sent, for the obvious reasons. Is there a way of making the Newsletter object read-only once it has been saved? Edit: I know I can override the save method of the object to raise an error or do nothin if the object existed. However, I don't see the point of doing that. As for the former, I don't know where to catch that error and how to communicate the user the fact that the object wasn't saved. As for the latter, giving the user false feedback (the admin interface saying that the save succeded) doesn't seem like a Good Thing. What I really want is allow the user to use the Admin interface to write the newsletter and send it, and then browse the newsletters that have already been sent. I would like the admin interface to show the data for sent newsletters in an non-editable input box, without the "Save" button. Alternatively I would like the "Save" button to be inactive.

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  • django internationalization doesn't work

    - by xRobot
    I have: * created translation strings in the template and in the application view. * run this command: django-admin.py makemessages -l it and the file it/LC_MESSAGES/django.po has been created * translated strings in the django.po file. * run this command: django-admin.py compilemessages and I receive: processing file django.po in /home/jobber/Desktop/library/books/locale/it/LC_MESSAGES * set this in settings.py: LANGUAGE_CODE = 'it' TEMPLATE_CONTEXT_PROCESSORS = ( "django.core.context_processors.auth", "django.core.context_processors.debug", "django.core.context_processors.i18n", "django.core.context_processors.media", ) USE_I18N = True MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.middleware.locale.LocaleMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', ) but.... translation doesn't work !! I always see english text. Why ?

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  • Programmatically specifying Django model attributes

    - by mojbro
    Hi! I would like to add attributes to a Django models programmatically, at run time. For instance, lets say I have a Car model class and want to add one price attribute (database column) per currency, given a list of currencies. What is the best way to do this? I had an approach that I thought would work, but it didn't exactly. This is how I tried doing it, using the car example above: from django.db import models class Car(models.Model): name = models.CharField(max_length=50) currencies = ['EUR', 'USD'] for currency in currencies: Car.add_to_class('price_%s' % currency.lower(), models.IntegerField()) This does seem to work pretty well at first sight: $ ./manage.py syncdb Creating table shop_car $ ./manage.py dbshell shop=# \d shop_car Table "public.shop_car" Column | Type | Modifiers -----------+-----------------------+------------------------------------------------------- id | integer | not null default nextval('shop_car_id_seq'::regclass) name | character varying(50) | not null price_eur | integer | not null price_usd | integer | not null Indexes: "shop_car_pkey" PRIMARY KEY, btree (id) But when I try to create a new Car, it doesn't really work anymore: >>> from shop.models import Car >>> mycar = Car(name='VW Jetta', price_eur=100, price_usd=130) >>> mycar <Car: Car object> >>> mycar.save() Traceback (most recent call last): File "<console>", line 1, in <module> File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/base.py", line 410, in save self.save_base(force_insert=force_insert, force_update=force_update) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/base.py", line 495, in save_base result = manager._insert(values, return_id=update_pk) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/manager.py", line 177, in _insert return insert_query(self.model, values, **kwargs) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/query.py", line 1087, in insert_query return query.execute_sql(return_id) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/sql/subqueries.py", line 320, in execute_sql cursor = super(InsertQuery, self).execute_sql(None) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/sql/query.py", line 2369, in execute_sql cursor.execute(sql, params) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/backends/util.py", line 19, in execute return self.cursor.execute(sql, params) ProgrammingError: column "price_eur" specified more than once LINE 1: ...NTO "shop_car" ("name", "price_eur", "price_usd", "price_eur... ^

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  • Django: CharField with fixed length, how?

    - by Giovanni Di Milia
    Hi everybody, I wold like to have in my model a CharField with fixed length. In other words I want that only a specified length is valid. I tried to do something like volumenumber = models.CharField('Volume Number', max_length=4, min_length=4) but it gives me an error (it seems that I can use both max_length and min_length at the same time). Is there another quick way? Thanks EDIT: Following the suggestions of some people I will be a bit more specific: My model is this: class Volume(models.Model): vid = models.AutoField(primary_key=True) jid = models.ForeignKey(Journals, db_column='jid', null=True, verbose_name = "Journal") volumenumber = models.CharField('Volume Number') date_publication = models.CharField('Date of Publication', max_length=6, blank=True) class Meta: db_table = u'volume' verbose_name = "Volume" ordering = ['jid', 'volumenumber'] unique_together = ('jid', 'volumenumber') def __unicode__(self): return (str(self.jid) + ' - ' + str(self.volumenumber)) What I want is that the volumenumber must be exactly 4 characters. I.E. if someone insert '4b' django gives an error because it expects a string of 4 characters. So I tried with volumenumber = models.CharField('Volume Number', max_length=4, min_length=4) but it gives me this error: Validating models... Unhandled exception in thread started by <function inner_run at 0x70feb0> Traceback (most recent call last): File "/Library/Python/2.5/site-packages/django/core/management/commands/runserver.py", line 48, in inner_run self.validate(display_num_errors=True) File "/Library/Python/2.5/site-packages/django/core/management/base.py", line 249, in validate num_errors = get_validation_errors(s, app) File "/Library/Python/2.5/site-packages/django/core/management/validation.py", line 28, in get_validation_errors for (app_name, error) in get_app_errors().items(): File "/Library/Python/2.5/site-packages/django/db/models/loading.py", line 131, in get_app_errors self._populate() File "/Library/Python/2.5/site-packages/django/db/models/loading.py", line 58, in _populate self.load_app(app_name, True) File "/Library/Python/2.5/site-packages/django/db/models/loading.py", line 74, in load_app models = import_module('.models', app_name) File "/Library/Python/2.5/site-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/Users/Giovanni/src/djangoTestSite/../djangoTestSite/journaldb/models.py", line 120, in <module> class Volume(models.Model): File "/Users/Giovanni/src/djangoTestSite/../djangoTestSite/journaldb/models.py", line 123, in Volume volumenumber = models.CharField('Volume Number', max_length=4, min_length=4) TypeError: __init__() got an unexpected keyword argument 'min_length' That obviously doesn't appear if I use only "max_length" OR "min_length". I read the documentation on the django web site and it seems that I'm right (I cannot use both together) so I'm asking if there is another way to solve the problem. Thanks again

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  • django-registration with paypal integration

    - by GrumpyCanuck
    I'm trying to figure out how to integrate django-registration with django-paypal. Being a Django n00b, I'm trying to figure out how to implement a flow like this: User signs up using django-registation with 'active' flag set to 0 After registering, send user to PayPal for a subscription When they come back from PayPal successfully, I want to set 'active' to 1 I've been looking at the django-registration documentation and don't quite understand how to use different backends or implement a flow the way I want. Any tips on how to accomplish this would be greatly appreciated. django-paypal won't be a problem for me as I've done PayPal integration before (in PHP for a self-published book about CakePHP).

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  • extending django usermodel

    - by imran-glt
    Hi i am trying to create a signup form for my django app. for this i have extended the user model. This is my Forms.py from contact.models import register from django import forms from django.contrib import auth class registerForm(forms.ModelForm): class Meta: model=register fields = ('latitude', 'longitude', 'status') class Meta: model = auth.models.User # this gives me the User fields fields = ('username', 'first_name', 'last_name', 'email') and this is my model.py from django.db import models from django.contrib.auth.models import User STATUS_CHOICES = ( ('Online', 'Online.'), ('Busy', 'Busy.'), ('AppearOffline', 'AppearOffline.'),) class register(models.Model): user = models.ForeignKey('auth.User', unique = True) latitude = models.DecimalField(max_digits=8, decimal_places=6) longitude = models.DecimalField(max_digits=8, decimal_places=6) status = models.CharField(max_length=8,choices=STATUS_CHOICES, blank= True, null=True) i dont know where i am making a mistake. the users passwords are not accepted at the login and the latitude and logitude are not saved against the created user user. i am fiarly new to django and dont know what to do any body have any solution .?

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  • django objects.all() method issue

    - by xlione
    after I saved one item using MyModelClass.save() method of django in one view/page , at another view I use MyModelClass.objects.all() to list all items in MyModelClass but the newly added one always is missing at the new page. i am using django 1.1 i am using mysql middleware setting MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.middleware.locale.LocaleMiddleware', ) my model: class Company(models.Model): name = models.CharField(max_length=500) description = models.CharField(max_length=500,null=True) addcompany view def addcompany(request): if request.POST: form = AddCompanyForm(request.POST) if form.is_valid(): companyname = form.cleaned_data['companyname'] c = Company(name=companyname,description='description') c.save() return HttpResponseRedirect('/admins/') else: form = AddCompanyForm() return render_to_response('user/addcompany.html',{'form':form},context_instance=RequestContext(request)) after this page in another view i called this form in another view class CompanyForm(forms.Form): companies=((0,' '),) for o in CcicCompany.objects.all(): x=o.id,o.name companies+=(x,) company = forms.ChoiceField(choices=companies,label='Company Name') to list all companies but the recently added one is missing. The transaction should be successful, since after i do a apache server reboot , i can see the newly added company name Thanks for any help...

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  • django shopping cart as a beginner

    - by Jacques Knie
    Hi, i'm quite new to django and trying to add a shopping cart to a simple webshop. What I need is a simple cart that can be filled and presents its content, which is then sent to the vendor via email. So Satchmo might be too big for this task. Therefore i chose django-cart (http://code.google.com/p/django-cart/) which causes some problems now. 1. Is django-cart the right thing? Or are there any better approaches to this task? 2. As I am a beginner even django-cart makes me struggle. I used the view and the template of the django-cart-website, but writing a form that can be used to add products to the cart took me hours. I probably need help in understanding the general layout of a shopping cart and its integration into a website. 3. Two more specific questions: Is it possible to dynamically populate a formfield in a template (e.g. with {{ object.id }})? Is django-cart able to change (update) the contents of a cart? I hope it's not too many questions at once. Thanks in advance Jacques

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  • How to add manytomany field to flatpage admin

    - by valya
    Hello! I have a site with Flatpages, and now I need to be able to add galleries (Gallery model) to the page. This is going to be ManyToManyField, so there is no need to change the flatpages table. But I still can't define ManyToManyField in proxy class. I can define ManyToManyField in Gallery model, but it isn't comfortable for the client. How can I change FlatPage Admin to add a ManyToManyField from Galleries model?

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  • Copying contents of a model

    - by Hulk
    If there exists an old data of a model say , query=Emp.objects.filter(pk=profile.id) Is there a easier way to copy the same values into the same model again.. Now that the id will be different so.. I have this requirement. Thanks..

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  • Cannot assign - must be a "UserProfile" instance

    - by webvulture
    I have a class UserProfile defined which takes the default user as a foreign key. Now another class A has a foreign key to UserProfile. So for saving any instance in class A, how do i give it the userprofile object. Also, does making a class UserProfile mean that class user is still used and class UserProfile is just some other table? I need to know this as I have to take care of the user profile creation, so I should know what gets stored where? -- Confused

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  • Copying contents of a module

    - by Hulk
    If there exists an old data of a model say , query=Emp.objects.filter(pk=profile.id) Is there a easier way to copy the same values into the same model again.. Now that the id will be different so.. I have this requirement. Thanks..

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