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  • Query only the first detail record for each master record

    - by Neal S.
    If I have the following master-detail relationship: owner_tbl auto_tbl --------- -------- owner --- owner auto year And I have the following table data: owner_tbl auto_tbl --------- -------- john john, corvette, 1968 john, prius, 2008 james james, f-150, 2004 james, cadillac, 2002 james, accord, 2009 jeff jeff, tesla, 2010 jeff, hyundai, 1996 Now, I want to perform a query that returns the following result: john, corvette, 1968 jeff, hyundai, 1996 james, cadillac, 2002 The query should join the two tables, and sort all the records on the "year" field, but only return the first detail record for each master record. I know how to join the tables and sort on the "year" field, but it's not clear how (or if) I might be able to only retrieve the first joined record for each owner. Three related questions: Can I perform this kind of query using LINQ-to-SQL? Can I perform the query using T-SQL? Would it be best to just create a stored procedure for the query given its likely complexity?

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  • Odd SQL Results

    - by Ryan Burnham
    So i have the following query Select id, [First], [Last] , [Business] as contactbusiness, (Case When ([Business] != '' or [Business] is not null) Then [Business] Else 'No Phone Number' END) from contacts The results look like id First Last contactbusiness (No column name) 2 John Smith 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number I'd expect record 2 to also show No Phone Number If i change the "[Business] is not null" to [Business] != null then i get the correct results id First Last contactbusiness (No column name) 2 John Smith No Phone Number 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number Normally you need to use is not null rather than != null. whats going on here?

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  • How to get only one row for each distinct value in the column ?

    - by Chavdar
    Hi Everybody, I have a question about Access.If for example I have a table with the following data : NAME | ADDRESS John Taylor | 33 Dundas Ave. John Taylor | 55 Shane Ave. John Taylor | 786 Edward St. Ted Charles | 785 Bloor St. Ted Charles | 90 New York Ave. I want to get one record for each person no matter of the address.For example : NAME | ADDRESS John Taylor | 33 Dundas Ave. Ted Charles | 90 New York Ave. Can this be done with queries only ? I tried using DISTINCT, but when I am selecting both columns, the combination is allways unique so I get all the rows. Thank you !

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  • c# ListView unable to check a checkbox! Strange problem.

    - by Kurt
    This is a strange problem, I've not added much code as I don't know were to start. I have a listview control in virtual mode, if I filter the listview to show me all people called John, I then see 3 users called John, I then cancel the filter setting all values to null and return all data to the listview, I now have several hundred items in the list but I can only see 30 on screen unless I scroll down the listview. I then use the code below to check a checkbox in each row, all get checked apart from the 3 Johns but if I can see 1 of the 3 Johns in listview without scrolling and then run the code below the visible John is checked. for (int i = 0; i < this._items.Count; i++) { this._items[i].Checked = true; } I have checked the status of the checkbox just before it is checked in the above code and if John is visible then the checkbox believes it is unchecked (false), if it is not visible it belives it is checked (true). So having one visible John on screen the checkbox looks unchecked and running a test proves it is unchecked, for the two Johns I can't see they believe they are checked but if I scroll down so I can see them they aren't. Any ideas? Thanks

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  • Objective C - when should "typedef" precede "enum", and when should an enum be named?

    - by Scott Pendleton
    In sample code, I have seen this: typedef enum Ename { Bob, Mary, John} EmployeeName; and this: typedef enum {Bob, Mary, John} EmployeeName; and this: typedef enum {Bob, Mary, John}; but what compiled successfully for me was this: enum {Bob, Mary, John}; I put that line in a .h file above the @interface line, and then when I #import that .h file into a different class's .m file, methods there can see the enum. So, when are the other variants needed? If I could name the enum something like EmployeeNames, and then, when I type "EmployeeNames" followed by a ".", it would be nice if a list pops up showing what the enum choices are.

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  • How to differenciate the data when doing a UNION on 2 SELECTS ?

    - by wiooz
    If I have the following two tables : Employes Bob Gina John Customers Sandra Pete Mom I will do a UNION for having : Everyone Bob Gina John Sandra Pete Mom The question is : In my result, how can I creat a dumn column of differenciate the data from my tables ? Everyone Bob (Emp) Gina (Emp) John (Emp Sandra (Cus) Pete (Cus) Mom (Cus) I want to know from with table the entry is from withouth adding a new column in the database... SELECT Employes.name FROM Employes UNION SELECT Customers.name FROM Customers;

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  • Perl script matching a certain patern

    - by kivien
    Assuming the file.txt is as follows:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The perl code is as follows:- open ( FILE, "file.txt" ) || die "can't open file!"; @lines = <FILE>; close (FILE); $string = "John Depp"; foreach $line (@lines) { if ($line =~ $string) { print "$line"; } } The output is going to be first and fourth line. I want to make it working for the file having random line breaks rather than one English sentence per line. I mean it should also work for the following:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The output should be first and fourth sentence. Any ideas please?

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  • Confused with ECMAScript Language Specification Function Calls section

    - by Ding
    Hi, I am reading ECMAScript Language Specification Function Calls section Can someone rephrase or detailed explains the following sentense for me? The production CallExpression : MemberExpression Arguments is evaluated as follows: Evaluate MemberExpression. let's take this code as an example. var john = { name: 'John', greet: function(person) { alert("Hi " + person + ", my name is " + this.name); } }; john.greet("Mark"); Take above code as an example, what does production CallExpression mean? what is MemberExpression in this case, john.greet? Thanks!

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  • ruby eval('\1') of gsub possible?

    - by Horace Ho
    I try to replace a sub-str by the content of a valiable where its name matches the sub-str by: >> str = "Hello **name**" => "Hello **name**" >> name = "John" => "John" str.gsub(/\*\*(.*)\*\*/, eval('\1')) # => error! the last line in the code above is a syntax error. and: >> str.gsub(/\*\*(.*)\*\*/, '\1') => "Hello name" >> str.gsub(/\*\*(.*)\*\*/, eval("name")) => "Hello John" what I want is the result of: str.gsub(/\*\*(.*)\*\*/, eval("name")) # => "Hello John" any help will be appreciated. thx!

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  • How can I print lines that match a pattern in Perl?

    - by kivien
    Assuming the file.txt having just one sentence per line as follows:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The perl code is as follows:- open ( FILE, "file.txt" ) || die "can't open file!"; @lines = <FILE>; close (FILE); $string = "John Depp"; foreach $line (@lines) { if ($line =~ $string) { print "$line"; } } The output is going to be first and fourth line. I want to make it working for the file having random line breaks rather than one English sentence per line. I mean it should also work for the following:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The output should be first and fourth sentence. Any ideas please?

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  • Class Problem (c++ and prolog)

    - by Joshua Green
    I am using the C++ interface to Prolog (the classes and methods of SWI-cpp.h). For working out a simple backtracking that john likes mary and emma and sara: likes(john, mary). likes(john, emma). likes(john, ashley). I can just do: { PlFrame fr; PlTermv av(2); av[0] = PlCompound("john"); PlQuery q("likes", av); while (q.next_solution()) { cout << (char*)av[1] << endl; } } This works in a separate code, so the syntax is correct. But I am also trying to get this simple backtracking to work within a class: class UserTaskProlog { public: UserTaskProlog(ArRobot* r); ~UserTaskProlog(); protected: int cycles; char* argv[1]; ArRobot* robot; void logTask(); }; This class works fine, with my cycles variable incrementing every robot cycle. However, when I run my main code, I get an Unhandled Exception error message: UserTaskProlog::UserTaskProlog(ArRobot* r) : robotTaskFunc(this, &UserTaskProlog::logTask) { cycles = 0; PlEngine e(argv[0]); PlCall("consult('myFile.pl')"); robot->addSensorInterpTask("UserTaskProlog", 50, &robotTaskFunc); } UserTaskProlog::~UserTaskProlog() { robot->remSensorInterpTask(&robotTaskFunc); // Do I need a destructor here for pl? } void UserTaskProlog::logTask() { cycles++; cout << cycles; { PlFrame fr; PlTermv av(2); av[0] = PlCompound("john"); PlQuery q("likes", av); while (q.next_solution()) { cout << (char*)av[1] << endl; } } } I have my opening and closing brackets for PlFrame. I have my frame, my query, etc... The exact same code that backtracks and prints out mary and emma and sara. What am I missing here that I get an error message? Here is what I think the code should do: I expect mary and emma and sara to be printed out once, every time cycles increments. However, it opens SWI-cpp.h file automatically and points to class PlFrame. What is it trying to tell me? I don't see anything wrong with my PlFrame class declaration. Thanks,

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  • Split a line from a para in java

    - by John
    Hi... I am having problem splitting a para into line.... i need to first read a file then split in into lines if i get a . or ! or ? I also need to remove any extra white space... This is wad i've written so far.... try { Scanner line = new Scanner(mFile); mLine = line.nextLine(); String Matrix[]=mLine.split("\\."); for (int i = 0; i < Matrix.length; ++i) { System.out.println(Matrix[i]); } Input: Hi. My name is John. Who are you ? Output: Hi My name is John Who are you

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  • Excel code question

    - by karatekid
    I have 2 different excel files(all people and special people) that i want to kick special people from all people. Cant find a way.. if you don't understand check my example: all people special people ---------- -------------- 1-john 1-john 2-jim 2-marry 3-mariah 4-russel 5-marry I want: all people special people ---------- -------------- 1-jim 1-john 2-mariah 2-marry 3-russel

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  • Is it possible to use ContainsTable to get results for more than one column?

    - by LockeCJ
    Consider the following table: People FirstName nvarchar(50) LastName nvarchar(50) Let's assume for the moment that this table has a full-text index on it for both columns. Let's suppose that I wanted to find all of the people named "John Smith" in this table. The following query seems like a perfectly rational way to accomplish this: SELECT * from People p INNER JOIN CONTAINSTABLE(People,*,'"John*" AND "Smith*"') Unfortunately, this will return no results, assuming that there is no record in the People table that contains both "John" and "Smith" in either the FirstName or LastName columns. It will not match a record with "John" in the FirstName column, and "Smith" in the LastName column, or vice-versa. My question is this: How does one accomplish what I'm trying to do above? Please consider that the example above is simplified. The real table I'm working with has ten columns and the input I'm receiving is a single string which is split up based on standard word breakers (space, dash, etc.)

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  • Why should I prepend my custom attributes with "data-"?

    - by Horace Loeb
    So any custom data attribute that I use should start with "data-": <li class="user" data-name="John Resig" data-city="Boston" data-lang="js" data-food="Bacon"> <b>John says:</b> <span>Hello, how are you?</span> </li> Will anything bad happen if I just ignore this? I.e.: <li class="user" name="John Resig" city="Boston" lang="js" food="Bacon"> <b>John says:</b> <span>Hello, how are you?</span> </li> I guess one bad thing is that my custom attributes could conflict with HTML attributes with special meanings (e.g., name), but aside from this, is there a problem with just writing "example_text" instead of "data-example_text"? (It won't validate, but who cares?)

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  • Graph databases and Php

    - by stagas
    I want to use a graph database using php. Can you point out some resources on where to get started? Is there any example code / tutorial out there? Or are there any other methods of storing data that relate to each other in totally random/abstract situations? Very abstract example of the relations needed: John relates to Mary, both relate to School, John is Tall, Mary is Short, John has Blue Eyes, Mary has Green Eyes, query I want is which people are related to 'Short people that have Green Eyes and go to School' - answer John It is possible in MySQL but it would require a fixed set of attributes/columns for each item and a complex non-flexible query, instead I need every attribute to be an item by itself and instead of 'belonging' to something, to be 'related' to something.

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  • scala integer weirdness

    - by williamstw
    Suppose you inadvertently use Integer instead of Int, as in this code: import scala.collection.mutable.Map val contributors = Map[String,Integer]() val count = contributors.getOrElseUpdate("john",0) contributors.put("john",count+1) println(contributors) Compiler output: (fragment of test.scala):7: error: type mismatch; found : Int(1) required: String contributors.put("john",count+1) ^ Why "required: String"?

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  • How to check for mutual existence of Fields in same table in Two columns

    - by ranabra
    I tried using "Exist" and "IN". Not only did I not succeed, it didn't seem as an efficient solution. Here is a simplified example: TblMyTable WorkerUserName  -  WorkerDegree  -  ManagerUserName  -  ManagerDegree I need a query where there is a mutual connection / existence. What I mean is only where the worker, ex. "John" has a manager named "Mary", and where Mary the manager has a worker named "John". John the worker can have several managers and Mary the manager can have several workers. So the result will be (the order doesn't matter) ideally in one line: John - BSc  --  Mary - M.A. or Mary - M.A.  --  John - BSc The punchline is it's only one table. it is not really managers and workers, this is just a simplification of the situation. In the real situation both are equal, in a Table of names of users working with other users. Database is SQL 2005. Many thanx in advance  

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  • Filter entities that match all pairs

    - by Jon
    I have an entity (let's say Person) with a set of arbitrary attributes with a known subset of values. I need to search for all of these entities that match all my filter conditions. For example, my table structures look like this: Person: id | name 1 | John Doe 2 | Jane Roe 3 | John Smith Attribute: id | attr_name 1 | Sex 2 | Eye Color ValidValue: id | attr_id | value_name 1 | 1 | Male 2 | 1 | Female 3 | 2 | Blue 4 | 2 | Green 5 | 2 | Brown PersonAttributes id | person_id | attr_id | value_id 1 | 1 | 1 | 1 2 | 1 | 2 | 3 3 | 2 | 1 | 2 4 | 2 | 2 | 4 5 | 3 | 1 | 1 6 | 3 | 2 | 4 In JPA, I have entities built for all of these tables. What I'd like to do is perform a search for all entities matching a given set of attribute-value pairs. For instance, I'd like to be able to find all males (John Doe and John Smith), all people with green eyes (Jane Roe or John Smith), or all females with green eyes (Jane Roe). I see that I can already take advantage of the fact that I only really need to match on value_id, since that's already unique and tied to the attr_id. But where can I go from there?

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  • How can I 'transpose' my data using SQL and remove duplicates at the same time?

    - by Remnant
    I have the following data structure in my database: LastName FirstName CourseName John Day Pricing John Day Marketing John Day Finance Lisa Smith Marketing Lisa Smith Finance etc... The data shows employess within a business and which courses they have shown a preference to attend. The number of courses per employee will vary (i.e. as above, John has 3 courses and Lisa 2). I need to take this data from the database and pass it to a webpage view (asp.net mvc). I would like the data that comes out of my database to match the view as much as possible and want to transform the data using SQl so that it looks like the following: LastName FirstName Course1 Course2 Course3 John Day Pricing Marketing Finance Lisa Smith Marketing Finance Any thoughts on how this may be achieved? Note: one of the reasons I am trying this approach is that the original data structure does not easily lend itself to be iterated over using the typical mvc syntax: <% foreach (var item in Model.courseData) { %> Because of the duplication of names in the orignal data I would end up with lots of conditionals in my View which I would like to avoid. I have tried transforming the data using c# in my ViewModel but have found it tough going and feel that I could lighten the workload by leveraging SQL before I return the data. Thanks.

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  • VBScript + Regular Expressions

    - by Karthik
    Dim sString sString = "John;Mary;Anne;Adam;Bill;Ester" Is there a regex I can use to retrieve the following from the above list: John (; at the end of the name) Anne (; at the beginning and end) Ester (; at the beginning) I am currently using the following regex for each: 1. Joh.* 2. .*An.* 3. .*st.* But, the above retrieves the entire string instead of the values I want. How can I get the correct values? Code: Dim oRegex : Set oRegex = New RegExp oRegex.Global = False oRegex.IgnoreCase = False 'John oRegex.Pattern = "Joh.*" Set oMatch = oRegex.Execute(sString) sName = oMatch(0) The above code retrieves the entire string, instead of only John. Same issue with the others :(

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  • Match entities fulfilling filter (strict superset of search)

    - by Jon
    I have an entity (let's say Person) with a set of arbitrary attributes with a known subset of values. I need to search for all of these entities that match all my filter conditions. That is, given a set of Attributes A, I need to find all people that have a set of Attributes that are a superset of A. For example, my table structures look like this: Person: id | name 1 | John Doe 2 | Jane Roe 3 | John Smith Attribute: id | attr_name 1 | Sex 2 | Eye Color ValidValue: id | attr_id | value_name 1 | 1 | Male 2 | 1 | Female 3 | 2 | Blue 4 | 2 | Green 5 | 2 | Brown PersonAttributes id | person_id | attr_id | value_id 1 | 1 | 1 | 1 2 | 1 | 2 | 3 3 | 2 | 1 | 2 4 | 2 | 2 | 4 5 | 3 | 1 | 1 6 | 3 | 2 | 4 In JPA, I have entities built for all of these tables. What I'd like to do is perform a search for all entities matching a given set of attribute-value pairs. For instance, I'd like to be able to find all males (John Doe and John Smith), all people with green eyes (Jane Roe or John Smith), or all females with green eyes (Jane Roe). I see that I can already take advantage of the fact that I only really need to match on value_id, since that's already unique and tied to the attr_id. But where can I go from there? I've been trying to do something like the following, given that the ValidValue is unique in all cases: select distinct p from Person p join p.personAttributes a where a.value IN (:values) Then I've tried putting my set of required values in as "values", but that gives me errors no matter how I try to structure that. I also have to get a little more complicated, as follows, but at this point I'd be happy with solving the first problem cleanly. However, if it's possible, the Attribute table actually has a field for default value: id | attr_name | default_value 1 | Sex | 1 2 | Eye Color | 5 If the value you're searching on happens to be the default value, I want it to return any people that have no explicit value set for that attribute, because in the application logic, that means they inherit the default value. Again, I'm more concerned about the primary question, but if someone who can help with that also has some idea of how to do this one, I'd be extremely grateful.

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  • Labeled fixtures for associations in Rails 3 broken

    - by elsurudo
    After upgrading to Rails 3, fixtures that refer to other labelled fixtures (for relationships) stop working. Instead of finding the actual fixture with that name, the fixture label is interpreted as a string. Example: # Dog.yml sparky: name: Sparky owner: john # Person.yml john: name: John Where Dog "belongs to" person. The error message is: SQLite3::SQLException: table dogs has no column named 'owner'

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