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  • Unique constraint not created in JPA

    - by homaxto
    I have created the following entity bean, and specified two columns as being unique. Now my problem is that the table is created without the unique constraint, and no errors in the log. Does anyone have an idea? @Entity @Table(name = "cm_blockList", uniqueConstraints = @UniqueConstraint(columnNames = {"terminal", "blockType"})) public class BlockList { @Id @GeneratedValue(strategy = GenerationType.AUTO) private int id; @ManyToOne(cascade = CascadeType.PERSIST) @JoinColumn(name="terminal") private Terminal terminal; @Enumerated(EnumType.STRING) private BlockType blockType; private String regEx; }

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  • GWT Deserialisation of Persistent Entities (JPA)

    - by slartidan
    Hi everyone, I am currently developing Java/GWT-application which is hosted on a weblogic application server. I am using EJB3.0 with EclipseLink as persistence layer. Sadly my GWT has problems to deserialize persistent entities. It might be helpful for you to know, that I have the EclipseLink-Library in my classpath (including javax.persistence.Entity) am not recieving the persistence objects from a database or persistence-manager - I am creating the objects with standard java code use Eclipse IDE for Java EE Developers for development and deploying and I am compiling my GWT code with the GWT-Plugin (GWT 2.1.0) - my source code is split up in several projects am pretty sure, that the problems occures on client side, since the HTTP response of my server is the same in my working and in my not working example tried to patch javax.persistence.Entity and tried to include several libraries which included javax.persistence.Entity but nothing was helping In my server provides a list of instances of class SerialClass; the interface looks like this: public interface GreetingService extends RemoteService { List<SerialClass> greetServer(); } My onModuleLoad()-Method gets those instances and creates a browser-popup with the information: public void onModuleLoad() { GreetingServiceAsync server = (GreetingServiceAsync) GWT.create(GreetingService.class); server.greetServer(new AsyncCallback<List<SerialClass>>() { public void onFailure(Throwable caught) { } public void onSuccess(List<SerialClass> result) { String resultString = ""; try { for (SerialClass serial : result) { if (serial == null) { resultString += "null "; } else { resultString += ">" + serial.id + "< "; } } } catch (Throwable t) { Window.alert("failed to process"); } Window.alert("success:" + resultString); } }); } My server is looking like this: public class GreetingServiceImpl extends RemoteServiceServlet implements GreetingService { public List<SerialClass> greetServer() throws IllegalArgumentException { List<SerialClass> list = new ArrayList<SerialClass>(); for (int i = 0; i < 100; i++) { list.add(new SerialClass()); } return list; } } Case 1 = everything works fine I am using this SerialClass (either without any annotation, or with any annotation other than Entity - for example javax.persistence.PersistenceContext works fine): //@Entity public class SerialClass implements Serializable, IsSerializable { public int id = 4711; } The popup contains (as expected): success:>4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< >4711< The data sent over HTTP looks like this: //OK[4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,100,1,["java.util.ArrayList/3821976829","serial.shared.SerialClass/10650133"],0,6] Case 2 = its not working at all I am using this SerialClass: @Entity public class SerialClass implements Serializable, IsSerializable { public int id = 4711; } My popup contains (THIS IS MY PROBLEM): success:>2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null >2< null The data sent over HTTP looks like this (exactly the same!): //OK[4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,4711,2,100,1,["java.util.ArrayList/3821976829","serial.shared.SerialClass/10650133"],0,6] There is no suspicious logging output - neither on server, nor on client. All HTTP-responses have return code 200. My current workaround I am going to try to create transfer objects as a copy of my SerialClass - those transfer objects will look exactly the same, but will not have the @Entity annotation. Alternatively I could try to use the RequestFactory (thanks to @Hilbrand for the hint). I really don't know how to solve that problem and I'm really thankful about any suggestions, hints, tips, links, etc.

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  • JPA: persisting object, parent is ok but child not updated

    - by James.Elsey
    Hello, I have my domain object, Client, I've got a form on my JSP that is pre-populated with its data, I can take in amended values, and persist the object. Client has an abstract entity called MarketResearch, which is then extended by one of three more concrete sub-classes. I have a form to pre-populate some MarketResearch data, but when I make changes and try to persist the Client, it doesn't get saved, can someone give me some pointers on where I've gone wrong? My 3 domain classes are as follows (removed accessors etc) public class Client extends NamedEntity { @OneToOne @JoinColumn(name = "MARKET_RESEARCH_ID") private MarketResearch marketResearch; ... } @Inheritance(strategy = InheritanceType.JOINED) public abstract class MarketResearch extends AbstractEntity { ... } @Entity(name="MARKETRESEARCHLG") public class MarketResearchLocalGovernment extends MarketResearch { @Column(name = "CURRENT_HR_SYSTEM") private String currentHRSystem; ... } This is how I'm persisting public void persistClient(Client client) { if (client.getId() != null) { getJpaTemplate().merge(client); getJpaTemplate().flush(); } else { getJpaTemplate().persist(client); } } To summarize, if I change something on the parent object, it persists, but if I change something on the child object it doesn't. Have I missed something blatantly obvious? Thanks

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  • Problem updating collection using JPA

    - by FarmBoy
    I have an entity class Foo foo that contains Collection<Bar> bars. I've tried a variety of ways, but I'm unable to successfully update my collection. One attempt: foo = em.find(key); foo.getBars().clear(); foo.setBars(bars); em.flush; \\ commit, etc. This appends the new collection to the old one. Another attempt: foo = em.find(key); bars = foo.getBars(); for (Bar bar : bars) { em.remove(bar); } em.flush; At this point, I thought I could add the new collection, but I find that the entity foo has been wiped out. Here are some annotations. In Foo: @OneToMany(cascade = { CascadeType.ALL }, mappedBy = "foo") private List<Bar> bars; In Bar: @ManyToOne(optional = false, cascade = { CascadeType.ALL }) @JoinColumn(name = "FOO_ID") private Foo foo; Has anyone else had trouble with this? Any ideas?

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  • Forcing a method to be non-transactional in JPA (Eclipselink)

    - by rhinds
    Hi, I am developing an application using Eclipselink and as part of the app I need to be able to manipulate some of the objects which involves changing data without it being persisted to the database (i merging/changing objects for some batch generation processes). I am reluctant to change the data in the Entity objects, as there is a risk that even though i have not marked the methods as @Transactional, this method could in the future be inadvertantly called from within a transactional method and these changes could be persisted. So my question is, is there anyway to get around this? Such as force a method to always be non-transactional regardless; terminate any transactionality as soon as the method is started; etc. I know there is a .detach() method that can detach the objects from the Entity Manager, however, there are many objects and this seems like a potentially error prone fail-safe on my code.

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  • Strange befaviour of spring transaction support for JPA + Hibernate +@Transactional annotation

    - by abovesun
    I found out really strange behavior on relatively simple use case, probably I can't understand it because of not deep knowledges of spring @Transactional nature, but this is quite interesting. I have simple User dao that extends spring JpaDaoSupport class and contains standard save method: @Transactional public User save(User user) { getJpaTemplate().persist(user); return user; } If was working fine until I've add new method to same class: User getSuperUser(), this method should return user with isAdmin == true, and if there is no super user in db, method should create one. Thats how it was looking like: public User createSuperUser() { User admin = null; try { admin = (User) getJpaTemplate().execute(new JpaCallback() { public Object doInJpa(EntityManager em) throws PersistenceException { return em.createQuery("select u from UserImpl u where u.admin = true").getSingleResult(); } }); } catch (EmptyResultDataAccessException ex) { User admin = new User('login', 'password'); admin.setAdmin(true); save(admin); // THIS IS THE POINT WHERE STRANGE THING COMING OUT } return admin; } As you see code is strange forward and I was very confused when found out that no transaction was created and committed on invocation of save(admin) method and no new user wasn't actually created despite @Transactional annotation. In result we have situation: when save() method invokes from outside of UserDAO class - @Transactional annotation counted and user successfully created, but if save() invokes from inside of other method of the same dao class - @Transactional annotation ignored. Here how I was change save() method to force it always create transaction. public User save(User user) { getJpaTemplate().execute(new JpaCallback() { public Object doInJpa(EntityManager em) throws PersistenceException { em.getTransaction().begin(); em.persist(user); em.getTransaction().commit(); return null; } }); return user; } As you see I manually invoke begin and commit. Any ideas?

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  • JPA 2.0 How to persist in order

    - by parhs
    hello i am having two entities... Exam and Exam_Normal EXAM @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private Long id; private String name; private String codeName; @Enumerated(EnumType.STRING) private ExamType examType; @ManyToOne private Category category; @OneToMany(mappedBy="id",cascade=CascadeType.PERSIST) @OrderBy("id") private List<Exam_Normal> exam_Normal; EXAM_NORMAL @Id private Long item; @Id @ManyToOne private Exam id; @Enumerated(EnumType.STRING) private Gender gender; private Integer age_month_from; private Integer age_month_to; The problem is that if i put a list of EXAM_NORMAL at an EXAM class if i try to persist(EXAM) i get an error because it tries to persist EXAM_NORMAL first but it cant because the primary keyof EXAM is missing because it isnt persisted... Is there any way to define the order?Or i should set null the list ,persist and then set the list again ? thanks:)

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  • Two Persistence Units, Two entityManagerFactory(s), SPring, JPA, Hibernate

    - by sebajb
    I am using Two entityManagerFactory{1,2} based on two persistence units, autowired through spring, hibernate, with resource local. My DaoImpls are configured with the PersistenceUnit(unitName='...') according to the unit needed. I was under the impression that using them with the unitName specified would allow me to use x number of PUs without problem but I still get: expected single matching bean but found two: [emf1, emf2]. Am I missing some other configuration?

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  • where is the best palce to count the lazy load property using JPA

    - by Ke
    Let's say we have a "Question" and "Answer" entity, @Entity public class Question extends IdEntity { @Lob private String content; @Transient private int answerTotal; @OneToMany(fetch = FetchType.LAZY) private List<Answer> answers = new ArrayList<Answer>(); ...... I need to tell how many answers for the question every time Question is queryed. So I need to do count: String count = "select count(o) from Answer o WHERE o.question=:q"; My question is, where is the best place to do the count? (Because I did a lot of query about Question entity, by date, by tag, by category, by asker, etc. It is obviously not a good solution to add count operation in each query. My first attempt is to implement a @PostLoad listener, so every time Question entity is loaded, I do count. However, EntityManager cannot be injected in listener. So this way does not work. Any hint?

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  • Persist data when the table was not mapped (JPA EclipseLink)

    - by enrique
    Hi everybody I need some help in persisting data into a table that has not been mapped... The issue is that the database we have has a table which all of its columns are foreign keys so by mapping the whole database all of the tables are correctly mapped. However that table called "category" is not mapped. The way in which we can browse the data is by passing for the table I mentioned using the @jointable annotation which was set by the system in the other tables with which "category" has a relation. So we can go ahead and using the collections and perform a query. But the issue comes when I want to persist data into that table because there´s no any entity. We tried to persist through the collections but no luck. Then I have just tried by creating the entity with its PK and Facade all by hand. However when I try to persist using the Merge method the system tries to perform an Insert when it is supposed to perform an Update. So obviously it returns an error. Does anybody have an idea on this situation? Thanks.-

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  • JPA 2.0 Eclipse Link ... Composite primary keys

    - by Parhs
    I have two entities(actually more but it doenst matter) Exam and Exam_Normals Its a oneToMany relationship... The problem is that i need a primary key for Exams_Normals PK (Exam_ID Item) Item should be 1 2 3 4 5 etc.... But cant achieve it getting errors An alternative would be to: I cound use an IDENTITY and a ManyToOne relationship at Exam_Normals but that should be like PK(Exam_Normals_ID) and a reference to Exam and an extra collumn Item to keep an order.. SO 3 collumns But to avoid the alternative tried I tried with @IdClass and got errors Tried @EmbeddedID everything nothing works Any idea??

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  • Question on jpa joined table inheritance

    - by soontobeared
    Hi, The 'DiscriminatorColumn' annotation isn't creating any column in my parent entity. Where am I going wrong ? Here's my code @Entity @Inheritance(strategy=InheritanceType.JOINED) @DiscriminatorColumn(name="TYPE", discriminatorType=DiscriminatorType.STRING,length=20) public class WorkUnit extends BaseEntityClass implements Serializable{ @Entity @DiscriminatorValue(value="G") @Table(name="Group_") @PrimaryKeyJoinColumn public class Group extends WorkUnit implements Serializable{

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  • JPA @version - can it be used to calcualate version of a table entry

    - by OpenSource
    Hi, Please consider the following table (created using a corresponding entity) request ------- id requestor type version items 1 a t1 1 5 2 a t1 2 3 3 b t1 1 2 4 a t2 1 4 5 a t1 3 9 The above is what I want to achieve. The version field is a calculated field others are user provided. Basically the request's version needs to be calculated based on the combination of requestor and the type. The first occurance with a given combination will have a version 1 then version 2 and so on. I tried various things using @version on a different entity with just the three columns and joining the two entities using ManytoOne etc but I'm not able to get to the desired outcome. I dont want to confuse you with the things I tried. Since the objective is simple there should be an easier way I suppose? Can you please help? - any help greatly appreciated! thanks in advance

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  • JPA GeneratedValue with GenerationType.TABLE does a big jump after jvm restart

    - by joeduardo
    When I start my server and add an entry, the generated id will start with 1, 2, so on and so forth. After a restart, adding an entry would generate an id like 32,xxx. Another restart and adding of entry would generate an id like 65,xxx. I don't know why this is happening. Here's a snippet of the annotation I'm using for my id. I'm using Hibernate. @Id @GeneratedValue(strategy = GenerationType.TABLE) private Long id;

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  • JPA Problems mapping relationships

    - by Rosen Martev
    Hello. I have a problem when I try to persist my model. An exception is thrown when creating the EntityManagerFactory: Blockquote javax.persistence.PersistenceException: [PersistenceUnit: NIF] Unable to build EntityManagerFactory at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:677) at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:126) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:52) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:34) at project.serealization.util.PersistentManager.createSession(PersistentManager.java:24) at project.serealization.SerializationTest.testProject(SerializationTest.java:25) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at junit.framework.TestCase.runTest(TestCase.java:168) at junit.framework.TestCase.runBare(TestCase.java:134) at junit.framework.TestResult$1.protect(TestResult.java:110) at junit.framework.TestResult.runProtected(TestResult.java:128) at junit.framework.TestResult.run(TestResult.java:113) at junit.framework.TestCase.run(TestCase.java:124) at junit.framework.TestSuite.runTest(TestSuite.java:232) at junit.framework.TestSuite.run(TestSuite.java:227) at org.junit.internal.runners.JUnit38ClassRunner.run(JUnit38ClassRunner.java:79) at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:46) at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197) Caused by: org.hibernate.HibernateException: Wrong column type in nif.action_element for column FLOW_ID. Found: double, expected: bigint at org.hibernate.mapping.Table.validateColumns(Table.java:284) at org.hibernate.cfg.Configuration.validateSchema(Configuration.java:1116) at org.hibernate.tool.hbm2ddl.SchemaValidator.validate(SchemaValidator.java:139) at org.hibernate.impl.SessionFactoryImpl.(SessionFactoryImpl.java:349) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1327) at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:867) at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:669) ... 24 more The code for SimpleActionElement and SimpleFlow is as follows: @Entity public class SimpleActionElement { @OneToOne(cascade = CascadeType.ALL, targetEntity = SimpleFlow.class) @JoinColumn(name = "FLOW_ID") private SimpleFlow<T> flow; ... } @Entity public class SimpleFlow<T> { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "ELEMENT_ID") private Long element_id; ... }

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  • How to declare different non-JPA annotations on embedded classes

    - by e99y
    @Embedded public class EmbedMe { private String prop1; private String prop2; } @Entity public class EncryptedEmbedded { @Embeddable private EmbedMe enc; } I am current using Jasypt for encryption. Is there a way to indicate that the @Embeddable in EncryptedEmbedded will use @Type(value = "newDeclaredTypeHere") per attribute (prop1, prop2)? Thanks in advance... ;)

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  • JPA Native Query (SQL View)

    - by Uchenna
    I have two Entities Customer and Account. @Entity @Table(name="customer") public class Customer { private Long id; private String name; private String accountType; private String accountName; ... } @Entity @Table(name="account") public class Account { private Long id; private String accountName; private String accountType; ... } i have a an sql query select a.id as account_id, a.account_name, a.account_type, d.id, d.name from account a, customer d Assumption account and customer tables are created during application startup. accountType and accountName fields of Customer entity should not be created. That is, only id and name columns will be created. Question How do i run the above sql query and return a Customer Entity Object with the accountType and accountName properties populated with sql query's account_name and account_type values. Thanks

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  • hibernate jpa criteriabuilder ignore case queries

    - by user373201
    How to do a like ignore case query using criteria builder. For description property I want to do something like upper(description) like '%xyz%' I have the following query CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder(); CriteriaQuery<Person> personCriteriaQuery = criteriaBuilder.createQuery(Person.class); Root<Person> personRoot = personCriteriaQuery.from(Person.class); personCriteriaQuery.select(personRoot); personCriteriaQuery.where(criteriaBuilder.like(personRoot.get(Person_.description), "%"+filter.getDescription().toUpperCase()+"%")); List<Person> pageResults = entityManager.createQuery(personCriteriaQuery).getResultList();

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  • JPA entity relations are not populated after .persist()

    - by Tomik
    Hello, this is a sample of my two entities: @Entity public class Post implements Serializable { @OneToMany(mappedBy = "post", fetch = javax.persistence.FetchType.EAGER) @OrderBy("revision DESC") public List<PostRevision> revisions; @Entity(name="post_revision") public class PostRevision implements Serializable { @ManyToOne public Post post; private Integer revision; @PrePersist private void prePersist() { List<PostRevision> list = post.revisions; if(list.size() >= 1) revision = list.get(list.size() - 1).revision + 1; else revision = 1; } So, there's a "post" and it can have several revisions. During persisting of the revision, entity takes a look at the list of the existing revisions and finds the next revision number. Problem is that Post.revisions is NULL but I think it should be automatically populated. I guess there's some kind of problem in my source code but I don't know where. Here's my "persistence" code: Post post = new Post(); PostRevision revision = new PostRevision(); revision.post = post; em.persist(post); em.persist(revision); em.flush(); I think that after persisting "post", it becomes "managed" and all the relations should be populated from now on. Thanks for help! (Note: public attributes are just for demonstration)

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  • JPQL: unknown state or association field (EclipseLink)

    - by Kawu
    I have an Employee entity which inherits from Person and OrganizationalUnit: OrganizationalUnit: @MappedSuperclass public abstract class OrganizationalUnit implements Serializable { @Id private Long id; @Basic( optional = false ) private String name; public Long getId() { return this.id; } public void setId( Long id ) { this.id = id; } public String getName() { return this.name; } public void setName( String name ) { this.name = name; } // ... } Person: @MappedSuperclass public abstract class Person extends OrganizationalUnit { private String lastName; private String firstName; public String getLastName() { return this.lastName; } public void setLastName( String lastName ) { this.lastName = lastName; } public String getFirstName() { return this.firstName; } public void setFirstName( String firstName ) { this.firstName = firstName; } /** * Returns names of the form "John Doe". */ @Override public String getName() { return this.firstName + " " + this.lastName; } @Override public void setName( String name ) { throw new UnsupportedOperationException( "Name cannot be set explicitly!" ); } /** * Returns names of the form "Doe, John". */ public String getFormalName() { return this.lastName + ", " + this.firstName; } // ... } Employee entity: @Entity @Table( name = "EMPLOYEES" ) @AttributeOverrides ( { @AttributeOverride( name = "id", column = @Column( name = "EMPLOYEE_ID" ) ), @AttributeOverride( name = "name", column = @Column( name = "LASTNAME", insertable = false, updatable = false ) ), @AttributeOverride( name = "firstName", column = @Column( name = "FIRSTNAME" ) ), @AttributeOverride( name = "lastName", column = @Column( name = "LASTNAME" ) ), } ) @NamedQueries ( { @NamedQuery( name = "Employee.FIND_BY_FORMAL_NAME", query = "SELECT emp " + "FROM Employee emp " + "WHERE emp.formalName = :formalName" ) } ) public class Employee extends Person { @Column( name = "EMPLOYEE_NO" ) private String nbr; // lots of other stuff... } I then attempted to find an employee by its formal name, e.g. "Doe, John" using the query above: SELECT emp FROM Employee emp WHERE emp.formalName = :formalName However, this gives me an exception on deploying to EclipseLink: Exception while preparing the app : Exception [EclipseLink-8030] (Eclipse Persistence Services - 2.3.2.v20111125-r10461): org.eclipse.persistence.exceptions.JPQLException Exception Description: Error compiling the query [Employee.FIND_BY_CLIENT_AND_FORMAL_NAME: SELECT emp FROM Employee emp JOIN FETCH emp.client JOIN FETCH emp.unit WHERE emp.client.id = :clientId AND emp.formalName = :formalName], line 1, column 115: unknown state or association field [formalName] of class [de.bnext.core.common.entity.Employee]. Local Exception Stack: Exception [EclipseLink-8030] (Eclipse Persistence Services - 2.3.2.v20111125-r10461): org.eclipse.persistence.exceptions.JPQLException Exception Description: Error compiling the query [Employee.FIND_BY_CLIENT_AND_FORMAL_NAME: SELECT emp FROM Employee emp JOIN FETCH emp.client JOIN FETCH emp.unit WHERE emp.client.id = :clientId AND emp.formalName = :formalName], line 1, column 115: unknown state or association field [formalName] of class [de.bnext.core.common.entity.Employee]. Qs: What's wrong? Is it prohibited to use "artificial" properties in JPQL, here the WHERE clause? What are the premises here? I checked the capitalization and spelling many times, I'm out of luck.

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  • ORM solutions (JPA; Hibernate) vs. JDBC

    - by Grasper
    I need to be able to insert/update objects at a consistent rate of at least 8000 objects every 5 seconds in an in-memory HSQL database. I have done some comparison performance testing between Spring/Hibernate/JPA and pure JDBC. I have found a significant difference in performance using HSQL.. With Spring/Hib/JPA, I can insert 3000-4000 of my 1.5 KB objects (with a One-Many and a Many-Many relationship) in 5 seconds, while with direct JDBC calls I can insert 10,000-12,000 of those same objects. I cannot figure out why there is such a huge discrepancy. I have tweaked the Spring/Hib/JPA settings a lot trying to get close in performance without luck. I want to use Spring/Hib/JPA for future purposes, expandability, and because the foreign key relationships (one-many and many-many) are difficult to maintain by hand; but the performance requirements seem to point towards using pure JDBC. Any ideas of why there would be such a huge discrepancy?

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  • What transaction manager should I use for JBDC template When using JPA ?

    - by Sajid
    I am using standard JPA transaction manager for my JPA transactions. However, now I want to add some JDBC entities which will share the same 'datasource'. How can I make the JDBC operations transactional with spring transaction? Do I need to swith to JTA transaction managers? Is it possible to use both JPA & JDBC transactional service with same datasource? Even better, is it possible to mix these two transactions?

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  • Is there any advantage for using a library other than Hibernate for JPA?

    - by Jeduan Cornejo
    Hi, I've been using JPA for some time now and been in projects where we've used both Hibernate Annotations and Toplink Essentials. AFAIK the project leader chose Toplink because Netbeans had it integrated and seemed to be the easy thing to do. However when looking for help, most of the literature seemed to assume that you are using Hibernate as the JPA provider, so, the question is, is have you found any advantage, performance or otherwise for not using the de-facto standard for JPA, Hibernate?

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  • Is JPA + EJB to much slow (or heavy) for over Internet transactions?

    - by Xavier Callejas
    Hi, I am developing a stand-alone java client application that connects to a Glassfish v3 application for JPA/EJB facade style transactions. In other words, my client application do not connect directly to the database to CRUD, but it transfers JPA objets using EJB stateless sessions. I have scenarios where this client application will be used in an external network connected with a VPN over Internet with a client connection of 512kbp/DSL, and a simple query takes so much time, I'm seeing the traffic graph and when I merge a entity in the client application I see megabytes of traffic (I couldn't believe how a purchase order entity could weight more than 1 mb). I have LAZY fetch in almost every many-to-many relationship, but I have a lot of many-to-one relationships between entities (but this is the great advantage of JPA!). Could I do something to accelerate the the speed of transactions between JPA/EJB server and the remote java client? Thank you in advance.

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