Search Results

Search found 31882 results on 1276 pages for 'mailing list'.

Page 12/1276 | < Previous Page | 8 9 10 11 12 13 14 15 16 17 18 19  | Next Page >

  • Use /etc/aliases to send to a mailing-list using sendmail

    - by Pixoo
    I'm trying to configure my Debian (6.0) server to forward emails sent to root to a mailing-list. I set the ML address in /etc/aliases this way: root: [email protected] I then called newaliases. It doesn't work but when I call mail from the command line it works :/ echo "test" | mail -s"test message" [email protected] If I set my own email address in /etc/aliases it's working too. Any idea where it could come from ? Thanks

    Read the article

  • this is my first time asking here, I wanted to create a linked list while sorting it thanks

    - by user2738718
    package practise; public class Node { // node contains data and next public int data; public Node next; //constructor public Node (int data, Node next){ this.data = data; this.next = next; } //list insert method public void insert(Node list, int s){ //case 1 if only one element in the list if(list.next == null && list.data > s) { Node T = new Node(s,list); } else if(list.next == null && list.data < s) { Node T = new Node(s,null); list.next = T; } //case 2 if more than 1 element in the list // 3 elements present I set prev to null and curr to list then performed while loop if(list.next.next != null) { Node curr = list; Node prev = null; while(curr != null) { prev = curr; curr = curr.next; if(curr.data > s && prev.data < s){ Node T = new Node(s,curr); prev.next = T; } } // case 3 at the end checks for the data if(prev.data < s){ Node T = new Node(s,null); prev.next = T; } } } } // this is a hw problem, i created the insert method so i can check and place it in the correct order so my list is sorted This is how far I got, please correct me if I am wrong, I keep inserting node in the main method, Node root = new Node(); and root.insert() to add.

    Read the article

  • List<> capacity has more items than added.

    - by Pete
    List <string> ali = new List<string>(); ali.Clear(); ali.Add("apple"); ali.Add("orange"); ali.Add("banana"); ali.Add("cherry"); ali.Add("mango"); ali.Add("plum"); ali.Add("jackfruit"); Console.WriteLine("the List has {0} items in it.",ali.Capacity.ToString()); when I run this the Console displays: the List has 8 items in it. I don't understand why its showing a capacity of 8, when I only added 7 items.

    Read the article

  • LIST<> AddRange throwing ArgumentException

    - by Tim
    Hi all, I have a particular method that is occasionally crashing with an ArgumentException: Destination array was not long enough. Check destIndex and length, and the array's lower bounds.: at System.Array.Copy(Array sourceArray, Int32 sourceIndex, Array destinationArray, Int32 destinationIndex, Int32 length, Boolean reliable) at System.Collections.Generic.List`1.CopyTo(T[] array, Int32 arrayIndex) at System.Collections.Generic.List`1.InsertRange(Int32 index, IEnumerable`1 collection) at System.Collections.Generic.List`1.AddRange(IEnumerable`1 collection) The code that is causing this crash looks something like this: List<MyType> objects = new List<MyType>(100); objects = FindObjects(someParam); objects.AddRange(FindObjects(someOtherParam); According to MSDN, List<.AddRange() should automatically resize itself as needed: If the new Count (the current Count plus the size of the collection) will be greater than Capacity, the capacity of the List<(Of <(T)) is increased by automatically reallocating the internal array to accommodate the new elements, and the existing elements are copied to the new array before the new elements are added. Can someone think of a circumstance in which AddRange could throw this type of exception?

    Read the article

  • Advanced Python list comprehension

    - by Yuval A
    Given two lists: chars = ['ab', 'bc', 'ca'] words = ['abc', 'bca', 'dac', 'dbc', 'cba'] how can you use list comprehensions to generate a filtered list of words by the following condition: given that each word is of length n and chars is of length n as well, the filtered list should include only words that each i-th character is in the i string in words. In this case, we should get ['abc', 'bca'] as a result. (If this looks familiar to anyone, this was one of the questions in the previous Google code jam)

    Read the article

  • Python: Slicing a list into n nearly-equal-length partitions

    - by Drew
    I'm looking for a fast, clean, pythonic way to divide a list into exactly n nearly-equal partitions. partition([1,2,3,4,5],5)->[[1],[2],[3],[4],[5]] partition([1,2,3,4,5],2)->[[1,2],[3,4,5]] (or [[1,2,3],[4,5]]) partition([1,2,3,4,5],3)->[[1,2],[3,4],[5]] (there are other ways to slice this one too) There are several answers in here http://stackoverflow.com/questions/1335392/iteration-over-list-slices that run very close to what I want, except they are focused on the size of the list, and I care about the number of the lists (some of them also pad with None). These are trivially converted, obviously, but I'm looking for a best practice. Similarly, people have pointed out great solutions here http://stackoverflow.com/questions/312443/how-do-you-split-a-list-into-evenly-sized-chunks-in-python for a very similar problem, but I'm more interested in the number of partitions than the specific size, as long as it's within 1. Again, this is trivially convertible, but I'm looking for a best practice.

    Read the article

  • Equals method of System.Collections.Generic.List<T>...?

    - by Sambo
    I'm creating a class that derives from List... public class MyList : List<MyListItem> {} I've overridden Equals of MyListItem... public override bool Equals(object obj) { MyListItem li = obj as MyListItem; return (ID == li.ID); // ID is a property of MyListItem } I would like to have an Equals method in the MyList object too which will compare each item in the list, calling Equals() on each MyListItem object. It would be nice to simply call... MyList l1 = new MyList() { new MyListItem(1), new MyListItem(2) }; MyList l2 = new MyList() { new MyListItem(1), new MyListItem(2) }; if (l1 == l2) { ... } ...and have the comparisons of the list done by value. What's the best way...?

    Read the article

  • List problem in Reporting Services 2005

    - by Kris
    Hi, I have a problem with a list in srss 2005. The list is grouping too much information and I dont know how to un-group it. I made a picture to show it. But because I'm new, I can only show it with this link: http://img32.imageshack.us/img32/6058/listproblem.gif So the list is also grouping the weeks, but that is not what I would like. Does anyone know how to change this? (in the designer view) Thanks in advance, Kris

    Read the article

  • F# Active Pattern List.filter or equivalent

    - by akaphenom
    I have a records of types type tradeLeg = { id : int ; tradeId : int ; legActivity : LegActivityType ; actedOn : DateTime ; estimates : legComponents ; entryType : ShareOrDollarBased ; confirmedPrice: DollarsPerShare option; actuals : legComponents option ; type trade = { id : int ; securityId : int ; ricCode : string ; tradeActivity : TradeType ; enteredOn : DateTime ; closedOn : DateTime ; tradeLegs : tradeLeg list ; } Obviously the tradeLegs are a type off of a trade. A leg may be settled or unsettled (or unsettled but price confirmed) - thus I have defined the active pattern: let (|LegIsSettled|LegIsConfirmed|LegIsUnsettled|) (l: tradeLeg) = if Helper.exists l.actuals then LegIsSettled elif Helper.exists l.confirmedPrice then LegIsConfirmed else LegIsUnsettled and then to determine if a trade is settled (based on all legs matching LegIsSettled pattern: let (|TradeIsSettled|TradeIsUnsettled|) (t: trade) = if List.exists ( fun l -> match l with | LegIsSettled -> false | _ -> true) t.tradeLegs then TradeIsSettled else TradeIsUnsettled I can see some advantages of this use of active patterns, however i would think there is a more efficient way to see if any item of a list either matches (or doesn't) an actie pattern without having to write a lambda expression specifically for it, and using List.exist. Question is two fold: is there a more concise way to express this? is there a way to abstract the functionality / expression (fun l - match l with | LegIsSettled - false | _ - true) Such that let itemMatchesPattern pattern item = match item with | pattern -> true | _ -> false such I could write (as I am reusing this design-pattern): let curriedItemMatchesPattern = itemMatchesPattern LegIsSettled if List.exists curriedItemMatchesPattern t.tradeLegs then TradeIsSettled else TradeIsUnsettled Thoughts?

    Read the article

  • C# remove redundant paths from a list

    - by andrew
    Say I have this list List<string> sampleList = new List<string> { "C:\\Folder1", "D:\\Folder2", "C:\\Folder1\\Folder3", "C:\\Folder111\\Folder4" }; I'd like to remove the paths that are contained in other folders, for example we have C:\Folder1 and C:\Folder1\Folder3 the second entry should go away because C:\Folder1 contains C:\Folder1\Folder3 is there something that does that in the .net framework or do i have to write the algo myself?

    Read the article

  • Racket: change dotted pair to list

    - by user2963128
    I have a program that recursively calls a hashtable and prints out data from it. Unfortunately my hashtable seems to be saving data as dotted pairs so when I call the hashtable I get an error saying that there is no data for it because its tryign to search the hashtable for a dotted pair instead of a list. Is there an easy way to make the dotted pair into a regular list? IE im getting '("was" . "beginning") instead of '("was" "beginning") Is there a way to change this without re-writing how my hashtable store stuff? im using the let function to set a variable to this and then calling another function based on this variable (let ((data ( list-ref(hash-ref Ngram-table key) (random (length (hash-ref Ngram-table key)))))) is there a way to make the value stored in data just a list like this '("var1" "var2") instead of a dotted pair? edit: im getting dotted pairs because im using let to set data to the part of the hashtable's key and one of the elements in that hash.

    Read the article

  • parsing list in python

    - by lakshmipathi
    I have list in python which has following entries name-1 name-2 name-3 name-4 name-1 name-2 name-3 name-4 name-1 name-2 name-3 name-4 I would like remove name-1 from list except its first appearance -- resultant list should look like name-1 name-2 name-3 name-4 name-2 name-3 name-4 name-2 name-3 name-4 How to achieve this ?

    Read the article

  • List.Sort in C#: comparer being called with null object

    - by cbp
    I am getting strange behaviour using the built-in C# List.Sort function with a custom comparer. For some reason it sometimes calls the comparer class's Compare method with a null object as one of the parameters. But if I check the list with the debugger there are no null objects in the collection. My comparer class looks like this: public class DelegateToComparer<T> : IComparer<T> { private readonly Func<T,T,int> _comparer; public int Compare(T x, T y) { return _comparer(x, y); } public DelegateToComparer(Func<T, T, int> comparer) { _comparer = comparer; } } This allows a delegate to be passed to the List.Sort method, like this: mylist.Sort(new DelegateToComparer<MyClass>( (x, y) => { return x.SomeProp.CompareTo(y.SomeProp); }); So the above delegate will throw a null reference exception for the x parameter, even though no elements of mylist are null. UPDATE: Yes I am absolutely sure that it is parameter x throwing the null reference exception! UPDATE: Instead of using the framework's List.Sort method, I tried a custom sort method (i.e. new BubbleSort().Sort(mylist)) and the problem went away. As I suspected, the List.Sort method passes null to the comparer for some reason.

    Read the article

  • Sharepoint List Filter by Profile Property

    - by Lina Al Dana
    How would you filter a list in Sharepoint (WSS 3.0) by a current user's profile property. For example, I have a list with a Department column and I want to filter the list based on the current user's department (which would be a user profile's property). Any idea's on how to do this?

    Read the article

  • Using jQuery to Dynamically Insert Into List Alphabetically

    - by Dex
    I have two ordered lists next to each other. When I take a node out of one list I want to insert it alphabetically into the other list. The catch is that I want to take just the one element out and place it back in the other list without refreshing the entire list. The strange thing is that when I insert into the list on the right, it works fine, but when I insert back into the list on the left, the order never comes out right. I have also tried reading everything into an array and sorting it there just in case the children() method isn't returning things in the order they are displayed, but I still get the same results. Here is my jQuery: function moveNode(node, to_list, order_by){ rightful_index = 1; $(to_list) .children() .each(function(){ var ordering_field = (order_by == "A") ? "ingredient_display" : "local_counter"; var compA = $(node).attr(ordering_field).toUpperCase(); var compB = $(this).attr(ordering_field).toUpperCase(); var C = ((compA > compB) ? 1 : 0); if( C == 1 ){ rightful_index++; } }); if(rightful_index > $(to_list).children().length){ $(node).fadeOut("fast", function(){ $(to_list).append($(node)); $(node).fadeIn("fast"); }); }else{ $(node).fadeOut("fast", function(){ $(to_list + " li:nth-child(" + rightful_index + ")").before($(node)); $(node).fadeIn("fast"); }); } } Here is what my html looks like: <ol> <li ingredient_display="Enriched Pasta" ingredient_id="101635" local_counter="1"> <span class="rank">1</span> <span class="rounded-corners"> <span class="plus_sign">&nbsp;&nbsp;+&nbsp;&nbsp;</span> <div class="ingredient">Enriched Pasta</div> <span class="minus_sign">&nbsp;&nbsp;-&nbsp;&nbsp;</span> </span> </li> </ol>

    Read the article

  • Insert a list of objects using MyBatis 3

    - by T Soares
    I've tried to insert a list in a database but I've got some the error: org.springframework.jdbc.BadSqlGrammarException: SqlSession operation; bad SQL grammar []; nested exception is java.sql.SQLException: ORA-00913: too many values (...). The code that I've used: <insert id="insertListMyObject" parameterType="java.util.List" > INSERT INTO my_table (ID_ITEM, ATT1, ATT2) VALUES <foreach collection="list" item="item" index="index" open="(" close=")" separator=","> #{item.idItem, jdbcType=BIGINT}, #{item.att1, jdbcType=INTEGER}, #{item.att2, jdbcType=STRING} </foreach> </insert> My dao cals the method: SqlSessionTemplate().insert(MAPPER+".insertListMyObject", parameterList); Where the parameterList is: List<MyObjects>. Does someone have a clue about what's this error? Or if does exists a better way to do multiples inserts operation. Many thanks!

    Read the article

  • Passing empty list as parameter to JPA query throws error

    - by Tuukka Mustonen
    If I pass an empty list into a JPA query, I get an error. For example: List<Municipality> municipalities = myDao.findAll(); // returns empty list em.createQuery("SELECT p FROM Profile p JOIN p.municipality m WHERE m IN (:municipalities)") .setParameter("municipalities", municipalities) .getResultList(); Because the list is empty, Hibernate generates this in SQL as "IN ()", which gives me error with Hypersonic database. There is a ticket for this in Hibernate issue tracking but there are not many comments/activity there. I don't know about support in other ORM products or in JPA spec either. I don't like the idea of having to manually check for null objects and empty lists every time. Is there some commonly known approach/extension to this? How do you handle these situations?

    Read the article

  • Converting a list of an Structure into datatable

    - by strakastroukas
    I saw a lot of examples regarding conversion of a list to data-table. I would like to convert a list of structure into a data-table. How can i do that? My structure is like ... Structure MainStruct Dim Ans1 As String Dim Ans2 As String Dim Ans3 As String Dim Skipped As Boolean End Structure and... Dim St As New MainStruct Dim Build As New List(Of MainStruct) I would like to convert the Build to a datatable

    Read the article

  • Efficient method to calculate the rank vector of a list in Python

    - by Tamás
    I'm looking for an efficient way to calculate the rank vector of a list in Python, similar to R's rank function. In a simple list with no ties between the elements, element i of the rank vector of a list l should be x if and only if l[i] is the x-th element in the sorted list. This is simple so far, the following code snippet does the trick: def rank_simple(vector): return [rank for rank in sorted(range(n), key=vector.__getitem__)] Things get complicated, however, if the original list has ties (i.e. multiple elements with the same value). In that case, all the elements having the same value should have the same rank, which is the average of their ranks obtained using the naive method above. So, for instance, if I have [1, 2, 3, 3, 3, 4, 5], the naive ranking gives me [0, 1, 2, 3, 4, 5, 6], but what I would like to have is [0, 1, 3, 3, 3, 5, 6]. Which one would be the most efficient way to do this in Python? Footnote: I don't know if NumPy already has a method to achieve this or not; if it does, please let me know, but I would be interested in a pure Python solution anyway as I'm developing a tool which should work without NumPy as well.

    Read the article

< Previous Page | 8 9 10 11 12 13 14 15 16 17 18 19  | Next Page >