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  • SSAS Compare version 1.0 released

    - by Red Gate Software BI Tools Team
    We’re pleased to announce that SSAS Compare version 1.0 has been released as a free tool. Version 1.0 includes: Comparisons of live databases and XMLA or Analysis Services Project files MDX syntax diffs and highlighting Server comparisons Deployment wizard with summaries of scripted actions Bug fixes and engine and UI refinements We’ve tested it on as many cube configurations as we could find (not just good old AdventureWorks!), but we can’t provide support for free tools — so if you’re reliant on SSAS Compare for your cube deployment, use it at your own risk. See the user license agreement in the installer for more details. SSAS Compare’s come a long way from its humble beginnings as an internal tool first developed for Red Gate’s own BI developers. Today’s SSAS Compare is now much more stable — not to mention much easier to use — and something the team is proud to have released with Red Gate’s name on. Next: Deployment Manager We’re working on integrating SSAS Compare cube deployment with our new Deployment Manager tool, so you’ll be able to create cube deployment scripts and automate the deployment process, too.  We’re documenting the process in a white paper we’ll publish online in the next week. Thank you! Thanks to all the SSAS Compare users out there. Without your feedback, we could never have produced such a stable product so quickly. We hope you continue to find useful. See you in Deployment Manager!  

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  • Why doesn't the highlighted part of the JavaScript work?

    - by Dor Cohen
    Why isn't the 'confirm password and password the same' part working? Meaning, the part that uses the 'getElementById' to adress the password and confirmpassword. Every part works but that particular part. It doesn't show a red box around the text fields. Can anyone help me? <html> <head> </head> <script> function submitinfo() { var firstname = document.getElementById("firstname").value; var lastname = document.getElementById("lastname").value; var username = document.getElementById("username").value; var password = document.getElementById("password").value; var confirmpassword = document.getElementById("confirmpassword").value; var email = document.getElementById("email").value; if(firstname !== "" && document.getElementById("firstname").style.borderColor == "red")     {     document.getElementById("firstname").style.border = "none"     } if(lastname !== "" && document.getElementById("lastname").style.borderColor == "red") { document.getElementById("lastname").style.border = "none" } if(username !== "" && document.getElementById("username").style.borderColor == "red") { document.getElementById("username").style.border = "none" } if(password !== "" && document.getElementById("password").style.borderColor == "red") { document.getElementById("password").style.border = "none" } if(confirmpassword !== "" && document.getElementById("confirmpassword").style.borderColor == "red") { document.getElementById("confirmpassword").style.border = "none" } if(email !== "" && document.getElementById("email").style.borderColor == "red") { document.getElementById("email").style.border = "none" } if(firstname == "") { document.getElementById("firstname").style.borderColor = "red"; document.getElementById("firstname").style.borderStyle = "solid"; } if(lastname == "") { document.getElementById("lastname").style.borderColor = "red"; document.getElementById("lastname").style.borderStyle = "solid"; } if(username == "") { document.getElementById("username").style.borderColor = "red"; document.getElementById("username").style.borderStyle = "solid"; } if(password == "") { document.getElementById("password").style.borderColor = "red"; document.getElementById("password").style.borderStyle = "solid"; } if(confirmpassword == "") { document.getElementById("confirmpassword").style.borderColor = "red"; document.getElementById("confirmpassword").style.borderStyle = "solid"; } if(email == "") { document.getElementById("email").style.borderColor = "red"; document.getElementById("email").style.borderStyle = "solid"; } if(password !== "" && confirmpassword !== "" && document.getElementById("password").style.border == "none" && document.getElementById("confirmpassword").style.border == "none" && password !== confirmpassword) { document.getElementById("password").style.border = "red"; document.getElementById("confirmpassword").style.border = "red"; } if(firstname && lastname && username && password && confirmpassword && email !== "") { window.open() } } </script> <h><font size=4 color=3BCCBE><b>Full Name</b></font><h/> <br> <input type="text" id="firstname" size="15px" placeholder="First"> <input type="text" id="lastname" size="15px" placeholder="Last"> <br> <br> <br> <br> <h><font size=4 color=3BCCBE><b>Choose your username</b></font></h> <br> <input type="text" id="username" size="37px"> <br> <p><font size=3 color="grey">atleast 6 characters long</font></p> <br> <h><font size=4 color=3BCCBE><b>Create a password</b></font></h> <br> <input type="password" id="password" size="37px"> <br> <br> <br> <br> <h><font size=4 color=3BCCBE><b>Confirm your password</b></font><h/> <br> <input type="password" id="confirmpassword" size="37px"> <br> <br> <br> <br> <h><font size=4 color=3BCCBE><b>Email address</b></font><h/> <br> <input type="text" id="email" size="37px"> <br> <br> <br> <br> <input type="button" value="Submit" onclick="submitinfo()" style="height:50px; width:85px; font-size:22px;> <br> </body> </html>

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  • iPhone like red badge notification in a WPF project?

    - by Norbert
    I have a C# WPF project which generates daily and weekly reports automatically. I want to inform the user when new reports are available, so I thought of a badge like on the iPhone where the number of new messages appears on a little red circle: I thought of three images: Two images with semi circles on the left and right if the number to display is small. And a third image for the middle for the case that the number is large (123) and wouldn't fit in a circle. I want a glossy effect, so I've thought of pictures. Does anyone have a good idea how to do this without pictures but programmatically?

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  • How can I update fontconfig to a newer version in Red Hat 5.3?

    - by yan bellavance
    I want to update fontconfig to a newer version but it seems that the OS is still finding the old fontconfig and I need the newer version to build qt. How do I make Red Hat 5.3 see the newer version? I do not know if this helps but when I did a search for fontconfig I found some files in a folder called cache. When I do yum update it tells me everything is up to date but that version is too old and is missing FcFreeTypeQueryFace. Just send me a comment if this is wrong site and ill change it.

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  • TortoiseSVN shows red ! decorator for folder, but no files within it are marked with !

    - by Clay Nichols
    I'm new to SVN. I'm using the latest version (svn 1.6.9, TortoiseSVN 1.6.7.18415). Some folders who a red exclamation point next to them. If I drill down, I find a sub folder with ! as well but no files within that are marked with ! (all are either a green checkmark or no icon (because they are Ignored (like .exe files) . What I've tried: Cleanup {reported success} Add {reports nothing to add. All files either under version control has been ignored per the .ignore property. Commit {succeeds} SVNupdate {succeeds} Restarted computer. Some oddities: -I had a bunch of CVS folders (these files were copied over from a PC that was using CVS but we don't need that version history so I didn't import it into SVN). I deleted those CVS\ folders and they are showing up (as unversioned files) when I CheckIn. Any ideas?

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  • Red Hat cluster: Failure of one of two services sharing the same virtual IP tears down IP

    - by js.
    I'm creating a 2+1 failover cluster under Red Hat 5.5 with 4 services of which 2 have to run on the same node, sharing the same virtual IP address. One of the services on each node needs a (SAN) disk, the other doesn't. I'm using HA-LVM. When I shut down (via ifdown) the two interfaces connected to the SAN to simulate SAN failure, the service needing the disk is disabled, the other keeps running, as expected. Surprisingly (and unfortunately), the virtual IP address shared by the two services on the same machine is also removed, rendering the still-running service useless. How can I configure the cluster to keep the IP address up?

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  • Given a string of red and blue balls, find min number of swaps to club the colors together

    - by efficiencyIsBliss
    We are given a string of the form: RBBR, where R - red and B - blue. We need to find the minimum number of swaps required in order to club the colors together. In the above case that answer would be 1 to get RRBB or BBRR. I feel like an algorithm to sort a partially sorted array would be useful here since a simple sort would give us the number of swaps, but we want the minimum number of swaps. Any ideas? This is allegedly a Microsoft interview question according to this.

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  • How to SSH into Red Hat Linux (virtual box guest) from Windows 7 (host)?

    - by Gary Hunter
    I have RHEL running in Virtual Box and my native OS is Win 7. From a purely educational standpoint, I want to be able to access RHEL from Win 7 over SSH. I download putty but don;t know how to make it do what I want. Ideally, I would like to use the linux command prompt at a minimum and preferably access the GUI apps also. IS this possible? I am just trying to explore and expand my linux knowledge. Thanks for your time. Gary Hunter

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  • How to install software packages on a shared Red Hat Linux host account without root access or rpm?

    - by jeff
    I have a shared RHEL 4 host account where I do not have root privileges. I would like to install Git and Bash Complete in a way that they can be upgraded easily. To date, I've just been installing from source providing $HOME as a prefix to autoconf. Obviously this isn't ideal as I need to hunt down the files associated with the version I'm upgrading away from and delete them. I've tried using rpm but I just get -bash: rpm: command not found back so it's not available. I also looked into checkinstall but it looks like that requires rpm, dpkg, or Slackware's package manager to be available. Is there anything out there that can be used like a package manager without requiring root access or an existing package manager?

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  • Intel video driver upgrade now makes my external monitor display red-only with HDMI cable.

    - by Eli
    I have an HP G60 notebook with a Mobile Intel 4 Series Express Chipset video display (Driver version is 8.15.10.2021). OS is Win7 Home Premium. I also have an LG widescreen display that I was connecting to the laptop using an HDMI cable. It was working great, until I applied an Intel 4 Series Express Chipset update from Windows Update. After the update, if I plug the laptop to the monitor using the HDMI cable, it appears I only get the Magenta channel, cause that is all I see. If I connect with the VGA cable, it works fine. So, is it possible it is just the HDMI cable (which IS cheap in this case - fire sale at Blockbuster), and not related to the video driver update at all?

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  • How can I remount an NFS volume on Red Hat Linux?

    - by user76177
    I changed the user id of a user on an NFS client that mounts a volume from another server. My goal is to get the 2 users to have the same id, so that both servers can read and write to the volume. I changed the id successfully on the client system, but now when I look at the NFS mount from that system, it reports the files being owned by the old id. So it looks like I need to "refresh" that mount. I have found many instructions on how to remount, but each seems slightly different according to the type of system. Is there a simple command I can run to get the mounted volume to refresh so that it interprets the new user settings?

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  • asp.net, how to change text color to red in child nodes in VB codes?

    - by StudentIT
    I got everything worked now by list of server Name but I want to add a IF statement by checking a column from SQL Server called Compliance by either True or False value listed. If it False, the Name will change text color to Red. If it True, the Name won't change text color. I am not sure how add that in VB codes side. I am pretty sure that I would need to put IF statement inside While dr.Read(). I am pretty new to VB.Net and not sure which VB code that change text color. Here is my VB codes, Sub loadData() 'clear treeview control TreeViewGroups.Nodes.Clear() 'fetch owner data and save to in memory table Dim sqlConn As New System.Data.SqlClient.SqlConnection((ConfigurationManager.ConnectionStrings("SOCT").ConnectionString)) Dim strSqlSecondary As String = "SELECT [Name] FROM [dbo].[ServerOwners] where SecondaryOwner like @uid order by [name]" 'Getting a list of True or False from Compliance column Dim strSqlCompliance As String = "SELECT [Compliance] FROM [dbo].[ServerOwners] where SecondaryOwner like @uid order by [name]" Dim cmdSecondary As New System.Data.SqlClient.SqlCommand(strSqlSecondary, sqlConn) Dim cmdCompliance As New System.Data.SqlClient.SqlCommand(strSqlCompliance, sqlConn) cmdSecondary.Parameters.AddWithValue("@uid", TNN.NEAt.GetUserID()) cmdCompliance.Parameters.AddWithValue("@uid", TNN.NEAt.GetUserID()) Dim dr As System.Data.SqlClient.SqlDataReader Try sqlConn.Open() Dim root As TreeNode Dim rootNode As TreeNode Dim firstNode As Integer = 0 'Load Primary Owner Node 'Create RootTreeNode dr = cmdSecondary.ExecuteReader() If dr.HasRows Then 'Load Secondary Owner Node 'Create RootTreeNode root = New TreeNode("Secondary Owner", "Secondary Owner") TreeViewGroups.Nodes.Add(root) root.SelectAction = TreeNodeSelectAction.None rootNode = TreeViewGroups.Nodes(firstNode) 'populate the child nodes While dr.Read() Dim child As TreeNode = New TreeNode(dr("Name"), dr("Name")) rootNode.ChildNodes.Add(child) child.SelectAction = TreeNodeSelectAction.None End While dr.Close() cmdSecondary.Dispose() End If 'check if treeview has nodes If TreeViewGroups.Nodes.Count = 0 Then noServers() End If Catch ex As Exception hide() PanelError.Visible = True LabelError.Text = ex.ToString() Finally sqlConn.Dispose() End Try End Sub

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  • Is a red-black tree my ideal data structure?

    - by Hugo van der Sanden
    I have a collection of items (big rationals) that I'll be processing. In each case, processing will consist of removing the smallest item in the collection, doing some work, and then adding 0-2 new items (which will always be larger than the removed item). The collection will be initialised with one item, and work will continue until it is empty. I'm not sure what size the collection is likely to reach, but I'd expect in the range 1M-100M items. I will not need to locate any item other than the smallest. I'm currently planning to use a red-black tree, possibly tweaked to keep a pointer to the smallest item. However I've never used one before, and I'm unsure whether my pattern of use fits its characteristics well. 1) Is there a danger the pattern of deletion from the left + random insertion will affect performance, eg by requiring a significantly higher number of rotations than random deletion would? Or will delete and insert operations still be O(log n) with this pattern of use? 2) Would some other data structure give me better performance, either because of the deletion pattern or taking advantage of the fact I only ever need to find the smallest item? Update: glad I asked, the binary heap is clearly a better solution for this case, and as promised turned out to be very easy to implement. Hugo

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  • help with boxplot needed

    - by kathy_BJ
    I am new to R, can anyone help me with boxplot for a dataset like: file1 col1 col2 col3 col4 col5 050350005 101 56.625 48.318 RED 051010002 106 50.625 46.990 GREEN 051190007 25 65.875 74.545 BLUE 051191002 246 52.875 57.070 RED 220050004 55 70 80.274 BLUE 220150008 75 67.750 62.749 RED 220170001 77 65.750 54.307 GREEN file2 col1 col2 col3 col4 col5 050350005 101 56.625 57 RED 051010002 106 50.625 77 GREEN 051190007 25 65.875 51.6 BLUE 051191002 246 52.875 55.070 RED 220050004 55 70 32 BLUE 220150008 75 67.750 32.49 RED 220170001 77 65.750 84.07 GREEN for each color (red,green and blue), I need to compare file1 and file2 by making box plot with MB and RMSE for (col4-col3) for file1 and file2 by dividing col2 in different group: if col2<20,20<=col2<50, 50 <= col2 <70, col2 =70. That is, for the boxplot, the x is (<20, 20-50,50-70, 70), while y is MB (and RMSE) of the difference of col4 and col3 I hope I didn't confuse anybody. Thank you so much.

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  • iPhone switch statement using enum

    - by Boris
    I have defined an enum in a header file of a class : typedef enum{ RED = 0, BLUE, Green } Colors; - (void) switchTest:(Colors)testColor; and in the implementation file I have : - (void) switchTest:(Colors)testColor{ if(testColor == RED){ NSLog(@"Red selected"); } switch(testColor){ case RED: NSLog(@"Red selected again !"); break; default: NSLog(@"default selected"); break; } } My code compiles correctly without warrnings. When calling the switchTest method with RED, the output is : "Red selected" but once the first line of the switch runs, the application quits unexpectedly and without warrnings/errors. I don't mind using if/else syntax but I would like to understand my mistake.

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  • Why does Color.IsNamedColor not work when I create a color using Color.FromArgb()?

    - by Jon B
    In my app I allow the user to build a color, and then show him the name or value of the color later on. If the user picks red (full red, not red-ish), I want to show him "red". If he picks some strange color, then the hex value would be just fine. Here's sample code that demonstrates the problem: static string GetName(int r, int g, int b) { Color c = Color.FromArgb(r, g, b); // Note that specifying a = 255 doesn't make a difference if (c.IsNamedColor) { return c.Name; } else { // return hex value } } Even with very obvious colors like red IsNamedColor never returns true. Looking at the ARGB values for my color and Color.Red, I see no difference. However, calling Color.Red.GetHashCode() returns a different hash code than Color.FromArgb(255, 0, 0).GetHashCode(). How can I create a color using user specified RGB values and have the Name property come out right?

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  • R scatterplot overplotting color

    - by rgeekay
    So far I have this: qplot(df[[1]], as.numeric(rownames(df)), group=df[[2]], color=df[[2]], ylab="") I want to use different colors for the points in the 2 groups - perhaps a lighter shade for the what's in black now and a darker - say, red for what's in blue. Also, I want to use hexbin kind of thing for group=0 but not for group=1. I'm not able to get the syntax to get this working. In the current plot 0 is in black and 1 is in blue. Added: I worked on it some more, and by using factor and scale_colour_manual, I got the grey color for 0 and red for 1: > palette1 [1] "grey" "red" "blue" "violet" "black" fy=factor(y, labels=c('grey', 'red')) qplot(x, seq(1:length(x)),col=fy, ylab="") + geom_point() + scale_colour_manual(values=palette1) Pending questions are: How to first plot all the grey and then red on top (some of the red is now hidden because the grey is plotted over). How to apply the hexbin logic for group0 i.e. the grey points only and not for the red.

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  • Change specificity by child

    - by jim red
    hi I'd like to integrate a theme tag to my elements so they appear in diffrent colours. But since the css selectors have the same css specificity the latest overrides the earlier defined rule. this is an example that shows my problem: .... <div class="red"> <div class="box">This should be red</div> <div class="yellow"> ... <div class="box">This should be yellow (nested in x levels under the div.yellow)</div> ... </div> .... and here my css .box { width: 100px; height: 100px; } .yellow { background-color: yellow; } .red { background-color: red; } the box should be listed somewhere, but as soon as it is a sub child of another color definition it should been overwritten. thanks for any help! //jim

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  • Excel 2007 Conditional Formatting is not properly using custom formula provided

    - by Charles
    In Excel 2007, I want to conditionally color a row if it is odd numbered and then vary the coloring depending on if a specific cell (in column E) in that row contains a number (green) or empty(red). E.g. if E15 has a value of 2 and E13 has no entry, I would expect row 15 to be green and row 13 to be red. My two formulas are: To color red: =IF((MOD(ROW(),2) = 1),NOT(ISNUMBER(INDIRECT("$E$"&ROW()))), FALSE) To color green: =IF((MOD(ROW(),2) = 1),ISNUMBER(INDIRECT("E"&ROW())), FALSE) If I paste these formulas into cells on the worksheet I get the expected values. For row 15 the "red" equation is false and the "green" equation is true. For Row 13 the "red" equation is true and the "green equation is false. However if I use these formulas in the conditional formating use formula feature, all of my rows are red, any thoughts?

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  • Why does my Opengl es android testbed app not render anything besides a red screen?

    - by nathan
    For some reason my code here (this is the entire thing) doesnt actually render anything besides a red screen.. can anyone tell me why? package com.ntu.way2fungames.earth.testbed; import java.nio.FloatBuffer; import javax.microedition.khronos.egl.EGLConfig; import javax.microedition.khronos.opengles.GL10; import android.app.Activity; import android.content.Context; import android.opengl.GLSurfaceView; import android.opengl.GLSurfaceView.Renderer; import android.os.Bundle; public class projectiles extends Activity { GLSurfaceView lGLView; Renderer lGLRenderer; float projectilesX[]= new float[5001]; float projectilesY[]= new float[5001]; float projectilesXa[]= new float[5001]; float projectilesYa[]= new float[5001]; float projectilesTheta[]= new float[5001]; float projectilesSpeed[]= new float[5001]; private static FloatBuffer drawBuffer; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); SetupProjectiles(); Context mContext = this.getWindow().getContext(); lGLView= new MyView(mContext); lGLRenderer= new MyRenderer(); lGLView.setRenderer(lGLRenderer); setContentView(lGLView); } private void SetupProjectiles() { int i=0; for (i=5000;i>0;i=i-1){ projectilesX[i] = 240; projectilesY[i] = 427; float theta = (float) ((i/5000)*Math.PI*2); projectilesXa[i] = (float) Math.cos(theta); projectilesYa[i] = (float) Math.sin(theta); projectilesTheta[i]= theta; projectilesSpeed[i]= (float) (Math.random()+1); } } public class MyView extends GLSurfaceView{ public MyView(Context context) { super(context); // TODO Auto-generated constructor stub } } public class MyRenderer implements Renderer{ private float[] projectilecords = new float[] { .0f, .5f, 0, -.5f, 0f, 0, .5f, 0f, 0, 0, -5f, 0, }; @Override public void onDrawFrame(GL10 gl) { gl.glClear(GL10.GL_COLOR_BUFFER_BIT); gl.glMatrixMode(GL10.GL_MODELVIEW); //gl.glLoadIdentity(); gl.glEnableClientState(GL10.GL_VERTEX_ARRAY); for (int i=5000;i>4500;i=i-1){ //drawing section gl.glLoadIdentity(); gl.glColor4f(.9f, .9f,.9f,.9f); gl.glTranslatef(projectilesY[i], projectilesX[i],1); gl.glVertexPointer(3, GL10.GL_FLOAT, 0, drawBuffer); gl.glDrawArrays(GL10.GL_TRIANGLE_STRIP, 0, 12); //physics section projectilesX[i]=projectilesX[i]+projectilesXa[i]; projectilesY[i]=projectilesY[i]+projectilesYa[i]; } gl.glDisableClientState(GL10.GL_VERTEX_ARRAY); } @Override public void onSurfaceChanged(GL10 gl, int width, int height) { if (height == 0) height = 1; // draw on the entire screen gl.glViewport(0, 0, width, height); // setup projection matrix gl.glMatrixMode(GL10.GL_PROJECTION); gl.glLoadIdentity(); gl.glOrthof(0,width,height,0, -100, 100); } @Override public void onSurfaceCreated(GL10 gl, EGLConfig arg1) { gl.glShadeModel(GL10.GL_SMOOTH); gl.glClearColor(1f, .01f, .01f, 1f); gl.glClearDepthf(1.0f); gl.glEnable(GL10.GL_DEPTH_TEST); gl.glDepthFunc(GL10.GL_LEQUAL); gl.glHint(GL10.GL_PERSPECTIVE_CORRECTION_HINT, GL10.GL_NICEST); drawBuffer = FloatBuffer.wrap(projectilecords); } } }

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  • Estudio de caso: CFO de At&T le apunta a la tecnología para transformar las Finanzas Globales

    - by RED League Heroes-Oracle
    AT&T es una de las pocas multinacionales modernas que han participado de todas las etapas anteriores de la innovación de las telecomunicaciones, de Alexander Graham Bell como inventor solitario, a Bell Labs, a los lanzamientos acelerados en las fundiciones de AT&T. La tecnología es el corazón de todo lo que AT&T hace, incluyendo sus inversiones en innovaciones tecnológicas para permitir que las finanzas de AT&T trabajen más estratégicamente con los negocios para asegurar que las inversiones en las iniciativas de crecimiento sean exitosas. Según John Stephens, Vicepresidente Ejecutivo y director financiero de AT&T, la empresa ha trazado un plan de inversión de tres años para mejorar y aumentar sus redes IP de banda ancha alámbricas e inalámbricas. El plan incluye la implementación del servicio 4G LTE para 300 millones de personas en los Estados Unidos, expansión de IP de banda ancha de alta velocidad a unos 57 millones de hogares de clientes y una expansión de la fibra a 1 millón de clientes corporativos adicionales en su área de servicio de telefonía fija. "La necesidad de velocidad es mayor que nunca, y este proyecto es nuestro paso hacia la innovación para ofrecer tal velocidad," dice Stephens. Como AT&T moderniza su infraestructura global, sus procesos operacionales se hacen tan poderosos como su red. Ha sido una tarea grande y compleja, pero Stephens se complace al decir que el departamento de finanzas de AT&T ha adoptado su papel de catalizador corporativo. Empezó con un concepto simple: "Vamos a hacer que todos hablen en el mismo idioma". Esto llevó a la consolidación de sistemas financieros heredados de las empresas adquiridas. No fue una tarea sencilla, dado que la empresa pasó por más de cinco adquisiciones importantes y un sinfín de otras transacciones. En 2007, AT&T tenía 17 aplicaciones apenas en la función de cuentas por pagar. Hoy, el número se ha reducido a dos. Asimismo, hubo 50 sistemas de reportes gerenciales oficiales y ahora hay tres, con planes de excluir uno de ellos. Al tener un único lenguaje volcado a las Finanzas en toda la empresa, el equipo de finanzas de AT&T ha eliminado las varias versiones de los mismos datos, reduciendo la posible confusión en las discusiones y en las decisiones de estrategia de negocios. Estos pasos también han reducido los costos y aceleraron la toma de decisiones. "Lo lindo de los sistemas es que permiten que la gente talentosa con habilidades analíticas usen su tiempo en esa zona, en vez de gastar tiempo en recolección, agregación y organización de los datos," señala Stephens. "Tenemos un proceso eficiente y eficaz que hace que nosotros, dejemos a la gente libre para dedicarse a aquello en que son realmente buenos. Y tenemos un equipo de alta calidad y ellos están en su mejor punto cuando son capaces de hacer su función para apoyar a la unidad de negocio”AT&T es una de las pocas multinacionales modernas que han participado de todas las etapas anteriores de la innovación de las telecomunicaciones, de Alexander Graham Bell como inventor solitario, a Bell Labs, a los lanzamientos acelerados en las fundiciones de AT&T. La tecnología es el corazón de todo lo que AT&T hace, incluyendo sus inversiones en innovaciones tecnológicas para permitir que las finanzas de AT&T trabajen más estratégicamente con los negocios para asegurar que las inversiones en las iniciativas de crecimiento sean exitosas.  Según John Stephens, Vicepresidente Ejecutivo y director financiero de AT&T, la empresa ha trazado un plan de inversión de tres años para mejorar y aumentar sus redes IP de banda ancha alámbricas e inalámbricas. El plan incluye la implementación del servicio 4G LTE para 300 millones de personas en los Estados Unidos, expansión de IP de banda ancha de alta velocidad a unos 57 millones de hogares de clientes y una expansión de la fibra a 1 millón de clientes corporativos adicionales en su área de servicio de telefonía fija. "La necesidad de velocidad es mayor que nunca, y este proyecto es nuestro paso hacia la innovación para ofrecer tal velocidad," dice Stephens. Como AT&T moderniza su infraestructura global, sus procesos operacionales se hacen tan poderosos como su red. Ha sido una tarea grande y compleja, pero Stephens se complace al decir que el departamento de finanzas de AT&T ha adoptado su papel de catalizador corporativo. Empezó con un concepto simple: "Vamos a hacer que todos hablen en el mismo idioma". Esto llevó a la consolidación de sistemas financieros heredados de las empresas adquiridas. No fue una tarea sencilla, dado que la empresa pasó por más de cinco adquisiciones importantes y un sinfín de otras transacciones. En 2007, AT&T tenía 17 aplicaciones apenas en la función de cuentas por pagar. Hoy, el número se ha reducido a dos. Asimismo, hubo 50 sistemas de reportes gerenciales oficiales y ahora hay tres, con planes de excluir uno de ellos. Al tener un único lenguaje volcado a las Finanzas en toda la empresa, el equipo de finanzas de AT&T ha eliminado las varias versiones de los mismos datos, reduciendo la posible confusión en las discusiones y en las decisiones de estrategia de negocios. Estos pasos también han reducido los costos y aceleraron la toma de decisiones. "Lo lindo de los sistemas es que permiten que la gente talentosa con habilidades analíticas usen su tiempo en esa zona, en vez de gastar tiempo en recolección, agregación y organización de los datos," señala Stephens. "Tenemos un proceso eficiente y eficaz que hace que nosotros, dejemos a la gente libre para dedicarse a aquello en que son realmente buenos. Y tenemos un equipo de alta calidad y ellos están en su mejor punto cuando son capaces de hacer su función para apoyar a la unidad de negocio”

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  • Databinding, using formulas for unusual binding possible?

    - by Rattenmann
    Edit: added Info for WPF being used I am trying to bind a list of custom objects to a DataGrid. Straight binding seems easy enough, but i need to specify some complex formulas for some extra fields that do not directly show up in my class. Also i want to be able to EDIT the data in the Grid and get updates on related fields. Let me show you an example, because it is really hard to explain. I will simplify it to rooms with items. Each item can be red and blue. My Class looks like this: public class room { public string strRoomName { set; get; } public string strItemname { set; get; } public int intRedItem { set; get; } public int intBlueItem { set; get; } } Now if i use dataTable.ItemSource = myList; i get something like this: nr. | room | name | red | blue 1. living room, ball, 2, 1 2. sleeping room, bunny, 4, 1 3. living room, chair, 3, 2 4. kitchen, ball, 4, 7 5. garage, chair, 1, 4 Now for the complex part i need help with. I want every item to be the same number, red and blue. And because this does not hold true i want to see the "inbalance" per room AND globally like this: nr. | room | name | red | blue | missing | global red | global blue | global missing 1. living room, ball, 2, 1, 1 blue, 6, 7, 1 red 2. sleeping room, bunny, 4, 1, 3 blue, 4, 1, 3 blue 3. living room, chair, 3, 2, 1 blue, 4, 6, 2 red 4. kitchen, ball, 4, 7, 3 red, 6, 7, 1 red 5. garage, chair, 1, 4, 3 red, 4, 6, 2 red As you can see this smeels like excel formulas, i am unsure how to handle this in c# code however. You can also see i need to use data in the same row, but also get data from other rows that match one propertiy (the items name). Also if i change the blue value=1 in line 1 to value=2, i want line 1 to read like this: 1. living room, ball, 2, 2, even, 6, 8, 2 red and of corse line 4 needs to change to: 4. kitchen, ball, 4, 7, 3 red, 6, 8, 2 red As i said, this smells like excel, that's why i am really upset about myself not finding an easy solution. Surely enough c# offers some way to handle this stuff, right? Disclaimer: It is totally possible that i need a complete differend approach, pointing that out ot me is perfectly fine. Be it other ways to handle this, or a better way to structure my class. I am ok with every way to handle this as it is for learning purposes. I am simply doing programms for fun next to my college and just so happen to hit these kinda things that bug me out because i don't find a clean solution. And then i neglect my studies because i want to solve my (unreleated to studys,...) issue. Just can't stand having unsolved coding stuff around, don't judge me! ;-) And big thanks in advance if you have gotten this far in my post. It sure must be confusing with all those reds and blues. Edit: After reading trough your answers and testing my skills to implement your hints, i now have the following code as my class: public class RoomList : ObservableCollection<room> { public RoomList() : base() { Add(new room() { strRoomName = "living room", strItemname = "ball", intRedItem = 2, intBlueItem = 1 }); Add(new room() { strRoomName = "sleeping room", strItemname = "bunny", intRedItem = 4, intBlueItem = 1 }); Add(new room() { strRoomName = "living room", strItemname = "chair", intRedItem = 3, intBlueItem = 2 }); Add(new room() { strRoomName = "kitchen", strItemname = "ball", intRedItem = 4, intBlueItem = 7 }); Add(new room() { strRoomName = "garage", strItemname = "chair", intRedItem = 1, intBlueItem = 4 }); } } //rooms public class room : INotifyPropertyChanged { public string strRoomName { set; get; } public string strItemname { set; get; } public int intRedItem { get { return intRedItem; } set { intRedItem = value; NotifyPropertyChanged("intRedItem", "strMissing"); } } public int intBlueItem { get { return intBlueItem; } set { intBlueItem = value; NotifyPropertyChanged("intBlueItem", "strMissing"); } } public string strMissing { get { int missingCount = intRedItem - intBlueItem; return missingCount == 0 ? "Even" : missingCount.ToString(); } } public event PropertyChangedEventHandler PropertyChanged; public void NotifyPropertyChanged(params string[] propertyNames) { if (PropertyChanged != null) { foreach (string propertyName in propertyNames) { PropertyChanged(this, new PropertyChangedEventArgs(propertyName)); } } } } I got the "missing" field working right away, thanks alot for that tip. It really was as easy as i imagined and will be of great use for future projects. Still two (three maybe....) things i am missing tho. The above code terminates with a "System.StackOverflowException" in the setter of intRedItem and intBlueItem. I fail to see the error, that could be due to being 4:30am here, or my lack of understanding. Second issue: I followed the link to ObservableCollections as you can see from my code above. Yet i am unsure how to actually use that collection. Putting it as DataContent like suggested on that page shows a missing ressource. Adding it as a ressource like listed there crashes my VSExpress designer and leads to the programm not starting. So for now i am still using my old approach of a list like this: listRooms.Add(new room() { strRoomName = "living room", strItemname = "ball", intRedItem = 2, intBlueItem = 1 }); listRooms.Add(new room() { strRoomName = "sleeping room", strItemname = "bunny", intRedItem = 4, intBlueItem = 1 }); listRooms.Add(new room() { strRoomName = "living room", strItemname = "chair", intRedItem = 3, intBlueItem = 2 }); listRooms.Add(new room() { strRoomName = "kitchen", strItemname = "ball", intRedItem = 4, intBlueItem = 7 }); listRooms.Add(new room() { strRoomName = "garage", strItemname = "chair", intRedItem = 1, intBlueItem = 4 }); datagridRooms.ItemsSource = listRooms; And lastly: When testing before adding the notifyevents i tried to implement a proterty that looped trough the other objects, without any luck. The "missingItem" property worked so easy, yet it only tries to access "it's own" properties kind of. I need to access other objects, like "all objects that have the same room value". The idea behind this is that i am trying to calculate a value from other objects without even having those objects yet, at least in my logic. Where is the flaw in my thinking? Those 5 objects are added and created (?) one after another. So if the first tries to set it's "all red balls in my room AND all other rooms" value,.. how could it know about the balls in the kitchen, that get added as 4th object? So far so good tho, got on the right track i think. Just need some sleep first.

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  • validation functions in google apps script is not working properly

    - by chocka
    I create a i/p form in google site using Apps Script and i did the validation using the Apps Script coding. Validation functions available in Apps script is not satisfying all the possibility of checking the error. function validate(e) { var app = UiApp.getActiveApplication(); var flag=0; var text = app.getElementById('name'); var textrequired = app.getElementById('namerequired'); var number = app.getElementById('number'); var numberrequired = app.getElementById('numberrequired'); var email = app.getElementById('email'); var emailrequired = app.getElementById('emailrequired'); var submit = app.getElementById('submit_button'); var valid = app.createClientHandler() .validateNumber(number) .validateNotInteger(text) .validateEmail(email) .forTargets(submit).setEnabled(true) .forTargets(number,text,email).setStyleAttribute("color","black") .forTargets(numberrequired,textrequired,emailrequired).setText('*').setStyleAttribute("color", "red").setVisible(true); var invalidno = app.createClientHandler().validateNotNumber(number).validateMatches(number, '').forTargets(number).setStyleAttribute("color", "red").forTargets(submit).setEnabled(false).forTargets(numberrequired).setText('Please Enter a Valid No.').setStyleAttribute("color", "red").setVisible(true); var validno = app.createClientHandler().validateNumber(number).forTargets(number).setStyleAttribute("color","black").forTargets(numberrequired).setText('*').setStyleAttribute("color", "red").setVisible(true); var invalidText=app.createClientHandler().validateNumber(text).validateMatches(text, '').forTargets(text).setStyleAttribute("color", "red").forTargets(submit).setEnabled(false).forTargets(textrequired).setText('Please Enter a Valid Name.').setStyleAttribute("color", "red").setVisible(true); var validText=app.createClientHandler().validateNotNumber(text).forTargets(text).setStyleAttribute("color","black").forTargets(textrequired).setText('*').setStyleAttribute("color", "red").setVisible(true); var invalidemail=app.createClientHandler().validateNotEmail(email).validateMatches(email, '').forTargets(email).setStyleAttribute("color", "red").forTargets(submit).setEnabled(false).forTargets(emailrequired).setText('Please Enter a Valid Mail-Id.').setStyleAttribute("color", "red").setVisible(true); var validemail=app.createClientHandler().validateEmail(email).forTargets(email).setStyleAttribute("color","black").forTargets(emailrequired).setText('*').setStyleAttribute("color", "red").setVisible(true); number.addKeyPressHandler(invalidno).addKeyPressHandler(validno).addKeyPressHandler(valid).addKeyPressHandler(invalidText).addKeyPressHandler(invalidemail); text.addKeyPressHandler(invalidText).addKeyPressHandler(validText).addKeyPressHandler(valid).addKeyPressHandler(invalidno).addKeyPressHandler(invalidemail); email.addKeyPressHandler(invalidemail).addKeyPressHandler(validemail).addKeyPressHandler(valid).addKeyPressHandler(invalidno).addKeyPressHandler(invalidText); if (text == ''){flag = 1;} if (email == ''){flag = 1;} if (number == ''){flag = 1;} if(flag == 1){submit.setEnabled(false);} return app; } I just placed my Validation function using Apps Script. I don't know why its not satisfying all the possibilities of the validation. And also i have to do is to enable the submit button after all the fields satisfy the validation. After once it enabled, if i make any error in any field it will not get disable correctly. I wrote the coding correctly i think so. Please take a look at my validation function and give me some suggestion to make it possible. Please guide me, Thanks & Regards, chocka.

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  • CSS selector for first element with class

    - by Rajat
    I have a bunch of elements with a classname <p class="red"></p> <div class="red"></div> I cant seem to select the first element with the class="red" using the following CSS rule: .red:first-child{ border:5px solid red; } What is wrong in this selector and how to correct it ??

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