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• SQL SERVER – Weekly Series – Memory Lane – #039

  - by Pinal Dave

  Here is the list of selected articles of SQLAuthority.com across all these years. Instead of just listing all the articles I have selected a few of my most favorite articles and have listed them here with additional notes below it. Let me know which one of the following is your favorite article from memory lane. 2007 FQL – Facebook Query Language Facebook list following advantages of FQL: Condensed XML reduces bandwidth and parsing costs. More complex requests can reduce the number of requests necessary. Provides a single consistent, unified interface for all of your data. It’s fun! UDF – Get the Day of the Week Function The day of the week can be retrieved in SQL Server by using the DatePart function. The value returned by the function is between 1 (Sunday) and 7 (Saturday). To convert this to a string representing the day of the week, use a CASE statement. UDF – Function to Get Previous And Next Work Day – Exclude Saturday and Sunday While reading ColdFusion blog of Ben Nadel Getting the Previous Day In ColdFusion, Excluding Saturday And Sunday, I realize that I use similar function on my SQL Server Database. This function excludes the Weekends (Saturday and Sunday), and it gets previous as well as next work day. Complete Series of SQL Server Interview Questions and Answers Data Warehousing Interview Questions and Answers – Introduction Data Warehousing Interview Questions and Answers – Part 1 Data Warehousing Interview Questions and Answers – Part 2 Data Warehousing Interview Questions and Answers – Part 3 Data Warehousing Interview Questions and Answers Complete List Download 2008 Introduction to Log Viewer In SQL Server all the windows event logs can be seen along with SQL Server logs. Interface for all the logs is same and can be launched from the same place. This log can be exported and filtered as well. DBCC SHRINKFILE Takes Long Time to Run If you are DBA who are involved with Database Maintenance and file group maintenance, you must have experience that many times DBCC SHRINKFILE operations takes a long time but any other operations with Database are relatively quicker. mssqlsystemresource – Resource Database The purpose of resource database is to facilitates upgrading to the new version of SQL Server without any hassle. In previous versions whenever version of SQL Server was upgraded all the previous version system objects needs to be dropped and new version system objects to be created. 2009 Puzzle – Write Script to Generate Primary Key and Foreign Key In SQL Server Management Studio (SSMS), there is no option to script all the keys. If one is required to script keys they will have to manually script each key one at a time. If database has many tables, generating one key at a time can be a very intricate task. I want to throw a question to all of you if any of you have scripts for the same purpose. Maximizing View of SQL Server Management Studio – Full Screen – New Screen I had explained the following two different methods: 1) Open Results in Separate Tab - This is a very interesting method as result pan shows up in a different tab instead of the splitting screen horizontally. 2) Open SSMS in Full Screen - This works always and to its best. Not many people are aware of this method; hence, very few people use it to enhance performance. 2010 Find Queries using Parallelism from Cached Plan T-SQL script gets all the queries and their execution plan where parallelism operations are kicked up. Pay attention there is TOP 10 is used, if you have lots of transactional operations, I suggest that you change TOP 10 to TOP 50 This is the list of the all the articles in the series of computed columns. SQL SERVER – Computed Column – PERSISTED and Storage This article talks about how computed columns are created and why they take more storage space than before. SQL SERVER – Computed Column – PERSISTED and Performance This article talks about how PERSISTED columns give better performance than non-persisted columns. SQL SERVER – Computed Column – PERSISTED and Performance – Part 2 This article talks about how non-persisted columns give better performance than PERSISTED columns. SQL SERVER – Computed Column and Performance – Part 3 This article talks about how Index improves the performance of Computed Columns. SQL SERVER – Computed Column – PERSISTED and Storage – Part 2 This article talks about how creating index on computed column does not grow the row length of table. SQL SERVER – Computed Columns – Index and Performance This article summarized all the articles related to computed columns. 2011 SQL SERVER – Interview Questions and Answers – Frequently Asked Questions – Data Warehousing Concepts – Day 21 of 31 What is Data Warehousing? What is Business Intelligence (BI)? What is a Dimension Table? What is Dimensional Modeling? What is a Fact Table? What are the Fundamental Stages of Data Warehousing? What are the Different Methods of Loading Dimension tables? Describes the Foreign Key Columns in Fact Table and Dimension Table? What is Data Mining? What is the Difference between a View and a Materialized View? SQL SERVER – Interview Questions and Answers – Frequently Asked Questions – Data Warehousing Concepts – Day 22 of 31 What is OLTP? What is OLAP? What is the Difference between OLTP and OLAP? What is ODS? What is ER Diagram? SQL SERVER – Interview Questions and Answers – Frequently Asked Questions – Data Warehousing Concepts – Day 23 of 31 What is ETL? What is VLDB? Is OLTP Database is Design Optimal for Data Warehouse? If denormalizing improves Data Warehouse Processes, then why is the Fact Table is in the Normal Form? What are Lookup Tables? What are Aggregate Tables? What is Real-Time Data-Warehousing? What are Conformed Dimensions? What is a Conformed Fact? How do you Load the Time Dimension? What is a Level of Granularity of a Fact Table? What are Non-Additive Facts? What is a Factless Facts Table? What are Slowly Changing Dimensions (SCD)? SQL SERVER – Interview Questions and Answers – Frequently Asked Questions – Data Warehousing Concepts – Day 24 of 31 What is Hybrid Slowly Changing Dimension? What is BUS Schema? What is a Star Schema? What Snow Flake Schema? Differences between the Star and Snowflake Schema? What is Difference between ER Modeling and Dimensional Modeling? What is Degenerate Dimension Table? Why is Data Modeling Important? What is a Surrogate Key? What is Junk Dimension? What is a Data Mart? What is the Difference between OLAP and Data Warehouse? What is a Cube and Linked Cube with Reference to Data Warehouse? What is Snapshot with Reference to Data Warehouse? What is Active Data Warehousing? What is the Difference between Data Warehousing and Business Intelligence? What is MDS? Explain the Paradigm of Bill Inmon and Ralph Kimball. SQL SERVER – Azure Interview Questions and Answers – Guest Post by Paras Doshi – Day 25 of 31 Paras Doshi has submitted 21 interesting question and answers for SQL Azure. 1.What is SQL Azure? 2.What is cloud computing? 3.How is SQL Azure different than SQL server? 4.How many replicas are maintained for each SQL Azure database? 5.How can we migrate from SQL server to SQL Azure? 6.Which tools are available to manage SQL Azure databases and servers? 7.Tell me something about security and SQL Azure. 8.What is SQL Azure Firewall? 9.What is the difference between web edition and business edition? 10.How do we synchronize On Premise SQL server with SQL Azure? 11.How do we Backup SQL Azure Data? 12.What is the current pricing model of SQL Azure? 13.What is the current limitation of the size of SQL Azure DB? 14.How do you handle datasets larger than 50 GB? 15.What happens when the SQL Azure database reaches Max Size? 16.How many databases can we create in a single server? 17.How many servers can we create in a single subscription? 18.How do you improve the performance of a SQL Azure Database? 19.What is code near application topology? 20.What were the latest updates to SQL Azure service? 21.When does a workload on SQL Azure get throttled? SQL SERVER – Interview Questions and Answers – Guest Post by Malathi Mahadevan – Day 26 of 31 Malachi had asked a simple question which has several answers. Each answer makes you think and ponder about the reality of the IT world. Look at the simple question – ‘What is the toughest challenge you have faced in your present job and how did you handle it’? and its various answers. Each answer has its own story. SQL SERVER – Interview Questions and Answers – Guest Post by Rick Morelan – Day 27 of 31 Rick Morelan of Joes2Pros has written an excellent blog post on the subject how to find top N values. Most people are fully aware of how the TOP keyword works with a SELECT statement. After years preparing so many students to pass the SQL Certification I noticed they were pretty well prepared for job interviews too. Yes, they would do well in the interview but not great. There seemed to be a few questions that would come up repeatedly for almost everyone. Rick addresses similar questions in his lucid writing skills. 2012 Observation of Top with Index and Order of Resultset SQL Server has lots of things to learn and share. It is amazing to see how people evaluate and understand different techniques and styles differently when implementing. The real reason may be absolutely different but we may blame something totally different for the incorrect results. Read the blog post to learn more. How do I Record Video and Webcast How to Convert Hex to Decimal or INT Earlier I asked regarding a question about how to convert Hex to Decimal. I promised that I will post an answer with Due Credit to the author but never got around to post a blog post around it. Read the original post over here SQL SERVER – Question – How to Convert Hex to Decimal. Query to Get Unique Distinct Data Based on Condition – Eliminate Duplicate Data from Resultset The natural reaction will be to suggest DISTINCT or GROUP BY. However, not all the questions can be solved by DISTINCT or GROUP BY. Let us see the following example, where a user wanted only latest records to be displayed. Let us see the example to understand further. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Memory Lane, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• SQL SERVER – Two Puzzles – Answer and Win USD 25 Gift Card

  - by pinaldave

  Today I have two simple T-SQL Puzzle. You can answer them and win USD 25 Gift card. The gift card will be sent in email to winner. You will get choice of Gift Card brand based on your preference and country location. Puzzle 1: What will be the outcome and why? DECLARE @x REAL; SET @x = 9E-40 SELECT @x; The outcome here is obvious as I have used negative number in assignment. What is the reason behind the same? Puzzle 2: Why will be the outcome different from Puzzle 1: DECLARE @y REAL; SET @y = 9E+40 SELECT @y; The outcome of this puzzle very different from puzzle 1  as I have used positive number. There is number six (6) in the resultset why? Msg 232, Level 16, State 2, Line 2 Arithmetic overflow error for type real, value = 90000000000000006000000000000000000000000.000000. How to participate To win the Gift Card USD 25 you will have to answer both of the question on my Facebook page. If you are on twitter – you can increase the chance of winning by tweeting your participation. This contest is open for any one from any country. The winner will be selected Randomly. Winner will be announced on July 7, 2011. Related Post: SQLAuthority News – Monthly list of Puzzles and Solutions on SQLAuthority.com Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology

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• SQL SERVER – Introduction to PERCENT_RANK() – Analytic Functions Introduced in SQL Server 2012

  - by pinaldave

  SQL Server 2012 introduces new analytical functions PERCENT_RANK(). This function returns relative standing of a value within a query result set or partition. It will be very difficult to explain this in words so I’d like to attempt to explain its function through a brief example. Instead of creating a new table, I will be using the AdventureWorks sample database as most developers use that for experiment purposes. Now let’s have fun following query: USE AdventureWorks GO SELECT SalesOrderID, OrderQty, RANK() OVER(ORDER BY SalesOrderID) Rnk, PERCENT_RANK() OVER(ORDER BY SalesOrderID) AS PctDist FROM Sales.SalesOrderDetail WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY PctDist DESC GO The above query will give us the following result: Now let us understand the resultset. You will notice that I have also included the RANK() function along with this query. The reason to include RANK() function was as this query is infect uses RANK function and find the relative standing of the query. The formula to find PERCENT_RANK() is as following: PERCENT_RANK() = (RANK() – 1) / (Total Rows – 1) If you want to read more about this function read here. Now let us attempt the same example with PARTITION BY clause USE AdventureWorks GO SELECT SalesOrderID, OrderQty, ProductID, RANK() OVER(PARTITION BY SalesOrderID ORDER BY ProductID ) Rnk, PERCENT_RANK() OVER(PARTITION BY SalesOrderID ORDER BY ProductID ) AS PctDist FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY PctDist DESC GO Now you will notice that the same logic is followed in follow result set. I have now quick question to you – how many of you know the logic/formula of PERCENT_RANK() before this blog post? Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• What is the best way to work with large databases in Java depending on context?

  - by Singletony

  Hi guys. We are trying to figure out the best practice for working with very large DBs in Java. What we do is a kind of BI, i.e analyzing very large DBs, and using them to create intermediate DBs that represent intelligent knowledge of the DBs. We are currently using JDBC, and just preforming queries using a ResultSet. As more and more data is being created, we are wondering whether more appropriate ways exist for parsing and manipulating these large DBs: We need to support 'chunk' manipulation and not an entire DB at once(e.g. limit in JDBC, very poor performance) We do not need to be constantly connected since we are just pulling results and creating new tables of our own. We want to understand JDBC alternatives, with respect to advantages and disadvantages. Whether you think JDBC is the way to go or not, what are the best practices to go by depending on context (e.g. for large DBs queried in chunks) ? If my question is not clear, I will gladly elaborate! THANK YOU SO MUCH!

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• SQL Server Maintenence Plan error on an offline Database

  - by Sean Earp

  Today is SQL day for me :) I have a maintenance plan that is failing to run with the following error: Failed:(-1073548784) Executing the query "USE [SharedServices1_DB]" failed with the following error: "Database 'SharedServices1_DB' cannot be opened because it is offline.". Possible failure reasons: Problems with the query, "ResultSet" property not set correctly, parameters not set correctly, or connection not established correctly. where SharedServices1_DB is a database that is set to offline. I would like to exclude this database from the maintenance plan, but when the database is offline, it does not show up at all as a "specific database" in the maintenance plan task, and if I bring it online, it is already unchecked in the maintenance plan task. How can I exclude an offline database from a maintenance plan?

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• Oracle SQL Developer: Fetching SQL Statement Result Sets

  - by thatjeffsmith

  Running queries, browsing tables – you are often faced with many thousands, if not millions, of rows. Most people are happy with looking at the first few rows. But occasionally you need to see more. SQL Developer doesn’t show you all records, all at once. Instead, it brings the records down in ‘chunks,’ or as-needed. How It Works There is a preference that tells SQL Developer how many records to get in a single request, or ‘fetch’ of records. The default is 50… So if I run a query that returns MORE than 50 rows: There’s more than 50 records in this resultset, but we have 50 in the grid to start with. We don’t know how many records are in this result set actually. To show the record count here, we actually go physically query the database with a row count type query. All we know is that the query has finished executing, and that there are rows available to go fetch. It tells us when it’s done. As you scroll through the grid, if you get to record 50 and scroll more, we’ll get 50 more records. Or, you can cheat to get to the ‘bottom’ of the result set. You can ask SQL Developer to just to get all the records at once… Once all the records have been fetched, you’ll see this: All rows fetched! A word of caution There’s a reason we have the default set to 50 and not 1000. Bringing back data can get expensive and heavy. We’ve found the best performance to be found in that 50 to 200 record range.

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• The one feature that would make me invest in SSIS 2012

  - by Peter Larsson

  This week I was invited my Microsoft to give two presentations in Slovenia. My presentations went well and I had good energy and the audience was interacting with me. When I had some time over from networking and partying, I attended a few other presentations. At least the ones who where held in English. One of these was "SQL Server Integration Services 2012 - All the News, and More", given by Davide Mauri, a fellow co-worker from SolidQ. We started to talk and soon came into the details of the new things in SSIS 2012. All of the official things Davide talked about are good stuff, but for me, the best thing is one he didn't cover in his presentation. In earlier versions of SSIS than 2012, it is possible to have a stored procedure to act as a data source, as long as it doesn't have a temp table in it. In that case, you will get an error message from SSIS that "Metadata could not be found". This is still true with SSIS 2012, so the thing I am talking about is not really a SSIS feature, it's a SQL Server 2012 feature. And this is the EXECUTE WITH RESULTSETS feature! With this, you can have a stored procedure with a temp table to deliver the resultset to SSIS, if you execute the stored procedure from SSIS and add the "WITH RESULTSETS" option. If you do this, SSIS is able to take the metadata from the code you write in SSIS and not from the stored procedure! And it's very fast too. Let's say you have a stored procedure in earlier versions and when referencing that stored procedure in SSIS forced SSIS to call the stored procedure (which can take hours), to retrieve the metadata. Now, with RESULTSETS, SSIS 2012 can continue in milliseconds! This is because you provide the metadata in the RESULTSETS clause, and if the data from the stored procedure doesn't match this RESULTSETS, you will get an error anyway, so it makes sense Microsoft has provided this optimization for us.

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• Crawling a Content Folio

  - by Kyle Hatlestad

  Content Folios in WebCenter Content allow you to assemble, track, and access a logical group of documents and/or links.  It allows you to manage them as just a list of items (simple folio) or organized as a hierarchy (advanced folio).  The built-in UI in content server allows you to work with these folios, but publishing them or consuming them externally can be a bit of a challenge.   The folios themselves are actually XML files that contain the structure, attributes, and pointers to the content items.  So to publish this somewhere, such as a Site Studio page, you could perhaps use an XML parser to traverse the structure and create your output.  But XML parsers are not always the easiest or most efficient to use.  In order to more easily crawl and consume a Content Folio, Ed Bryant - Principal Sales Consultant, wrote a component to do just that.  His component adds a service which does all the work for you and returns the folio structure as a simple resultset.  So consuming and publishing that folio on a Site Studio page or in your portal using RIDC is a breeze!  For example, let's take an advanced Content Folio example like this: If we look at the native file, the XML looks like this: But if we access the folio using the new service - http://server/cs/idcplg?IdcService=FOLIO_CRAWL&dDocName=ecm008003&IsPageDebug=1 - this is what the result set looks like (using the IsPageDebug parameter). Given this as the result set, it makes it very easy to consume and repurpose that folio. You can download a copy of the sample component here. Special thanks to Ed for letting me share this component!

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• SQL SERVER – Storing Variable Values in Temporary Array or Temporary List

  - by pinaldave

  SQL Server does not support arrays or a dynamic length storage mechanism like list. Absolutely there are some clever workarounds and few extra-ordinary solutions but everybody can;t come up with such solution. Additionally, sometime the requirements are very simple that doing extraordinary coding is not required. Here is the simple case. Let us say here are the values: a, 10, 20, c, 30, d. Now the requirement is to store them in a array or list. It is very easy to do the same in C# or C. However, there is no quick way to do the same in SQL Server. Every single time when I get such requirement, I create a table variable and store the values in the table variables. Here is the example: For SQL Server 2012: DECLARE @ListofIDs TABLE(IDs VARCHAR(100)); INSERT INTO @ListofIDs VALUES('a'),('10'),('20'),('c'),('30'),('d'); SELECT IDs FROM @ListofIDs; GO When executed above script it will give following resultset. Above script will work in SQL Server 2012 only for SQL Server 2008 and earlier version run following code. DECLARE @ListofIDs TABLE(IDs VARCHAR(100), ID INT IDENTITY(1,1)); INSERT INTO @ListofIDs SELECT 'a' UNION ALL SELECT '10' UNION ALL SELECT '20' UNION ALL SELECT 'c' UNION ALL SELECT '30' UNION ALL SELECT 'd'; SELECT IDs FROM @ListofIDs; GO Now in this case, I have to convert numbers to varchars because I have to store mix datatypes in a single column. Additionally, this quick solution does not give any features of arrays (like inserting values in between as well accessing values using array index). Well, do you ever have to store temporary multiple values in SQL Server – if the count of values are dynamic and datatype is not specified early how will you about storing values which can be used later in the programming. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• SQL SERVER – A Puzzle Part 2 – Fun with SEQUENCE in SQL Server 2012 – Guess the Next Value

  - by pinaldave

  Before continuing this blog post – please read the first part of the SEQUENCE Puzzle here A Puzzle – Fun with SEQUENCE in SQL Server 2012 – Guess the Next Value. Where we played a simple guessing game about predicting next value. The answers the of puzzle is shared on the blog posts as a comment. Now here is the next puzzle based on yesterday’s puzzle. First execute the script which I have written here. The only difference between yesterday’s script is that I have removed the MINVALUE as 1 from the syntax. Now guess what will be the next value as requested in the query. USE TempDB GO -- Create sequence CREATE SEQUENCE dbo.SequenceID AS BIGINT START WITH 3 INCREMENT BY 1 MAXVALUE 5 CYCLE NO CACHE; GO -- Following will return 3 SELECT next value FOR dbo.SequenceID; -- Following will return 4 SELECT next value FOR dbo.SequenceID; -- Following will return 5 SELECT next value FOR dbo.SequenceID; -- Following will return which number SELECT next value FOR dbo.SequenceID; -- Clean up DROP SEQUENCE dbo.SequenceID; GO Above script gave me following resultset. 3 is the starting value and 5 is the maximum value. Once Sequence reaches to maximum value what happens? and WHY? I (kindly) suggest you try to attempt to answer this question without running this code in SQL Server 2012. I am very confident that irrespective of SQL Server version you are running you will have great learning. I will follow up of the answer in comments below. Recently my friend Vinod Kumar wrote excellent blog post on SQL Server 2012: Using SEQUENCE, you can head over there for learning sequence in details. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• Query a Log4Net-database

  - by pinhack

  So if you use Log4Net to log into a database (i.e. using the AdoNetAppender), how can you conveniently get an overview of what has happend ? Well, you could try the following Query ( T-SQL ):   SELECT convert(varchar(10),LogDB.Date,121) as Datum, LogDB.Level, LogDB.Logger,COUNT(LogDB.Logger) as Counter From Log4Net.dbo.Log as LogDB  where Level <> 'DEBUG' AND convert(varchar(10),LogDB.Date,121) like '2010-03-25' GROUP BY convert(varchar(10),LogDB.Date,121),LogDB.Level,LogDB.Logger ORDER BY counter desc This query will give you the number of events by the Logger at a specified date - and it's easy to customize, just adjust the Date and the Level to your needs. You need a bit more information than that? How about this query:  Select  convert(varchar(10),LogDB.Date,121) as Datum,LogDB.Level,LogDB.Message,LogDB.Logger ,count(LogDB.Message) as counter From Log4Net.dbo.Log as LogDB where Level <> 'DEBUG' AND convert(varchar(10),LogDB.Date,121) like '2010-03-25' GROUP BY convert(varchar(10),LogDB.Date,121),LogDB.Level,LogDB.Message,LogDB.Logger ORDER BY counter desc Similar to the first one, but inclusive the Message - which will return a much larger resultset.

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• From a DDD perspective is a report generating service a domain service or an infrastructure service?

  - by Songo

  Let assume we have the following service whose responsibility is to generate Excel reports: class ExcelReportService{ public String generateReport(String fileFormatFilePath, ResultSet data){ ReportFormat reportFormat = new ReportFormat(fileFormatFilePath); ExcelDataFormatterService excelDataFormatterService = new ExcelDataFormatterService(); FormattedData formattedData = excelDataFormatterService.format(data); ExcelFileService excelFileService = new ExcelFileService(); String reportPath= excelFileService.generateReport(reportFormat,formattedData); return reportPath; } } This is pseudo code for the service I want to design where: fileFormatFilePath: path to a configuration file where I'll keep the format of my excel file (headers, column widths, number of columns,..etc) data: the actual records returned from the database. This data can't be used directly coz I might need to make further calculations to the data before inserting them to the excel file. ReportFormat: Value object to hold the report format, has methods like getHeaders(), getColumnWidth(),...etc. ExcelDataFormatterService: a service to hold any logic that need to be applied to the data returned from the database before inserting it to the file. FormattedData: Value object the represents the formatted data to be inserted. ExcelFileService: a wrapper top the 3rd party library that generates the excel file. Now how do you determine whether a service is an infrastructure or domain service? I have the following 3 services here: ExcelReportService, ExcelDataFormatterService and ExcelFileService?

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• Sql database dumps failing every night

  - by chaseman36

  Hey guys, I have sql05 and my maintenance plan which backs up a database to an external storage SAN, has been failing every night. Here is my error: Executing the query "BACKUP DATABASE [master] TO DISK = N'\\192.168.x.x\vmbackup\server\dbbackup\master_backup_201004222300.bak' WITH NOFORMAT, NOINIT, NAME = N'master_backup_20100422230002', SKIP, REWIND, NOUNLOAD, STATS = 10 " failed with the following error: "Cannot open backup device '\\192.168.x.x\vmbackup\server\dbbackup\master_backup_201004222300.bak'. Operating system error 5(Access is denied.). BACKUP DATABASE is terminating abnormally.". Possible failure reasons: Problems with the query, "ResultSet" property not set correctly, parameters not set correctly, or connection not established correctly. I googled this error and tried adding permissions to the backup device for network service as recommended at experts exchange, no dice. Does anyone have any ideas?

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• how to get the result query one by one in jsp and mysql

  - by user261002

  I am trying to implement as Online Mock exam in JSP, but I have a problem to get the questions one by one, it get connceted for the first time, and show me the first question and answers, but when I click on "next" again, it still show me the first question, I think by clicking on "next" it start querying again. please help me. this is my bean : database.SQLSelectStatement sqlselect; database.SQLSelectStatement sqlselect2; static ResultSet questions; static ResultSetMetaData rsm; static ResultSet answers; public void setConnection() throws SQLException { if (database.DatabaseManager.getInstance().connectionOK()) { sqlselect = new database.SQLSelectStatement("question", "question", "0"); sqlselect2 = new database.SQLSelectStatement("answers", "question_id", "0"); questions = sqlselect.executeWithNoCondition(); } } public int i=0; public String getQuestions() throws SQLException { String result = ""; rsm = questions.getMetaData(); for (int i = 0; i < rsm.getColumnCount(); i++) { result += "<th>" + rsm.getColumnName(i + 1) + "</th>"; } if (!questions.isLast()) { questions.next(); System.out.println(i+1); result += "<tr>"; result += "<td>" + questions.getInt(1) + "</td>"; result += "<td>" + questions.getString(2) + "</td>"; result += "</tr>"; result += "<tr>"; sqlselect2.setValue(String.valueOf(questions.getInt(1))); answers = sqlselect2.Execute(); while (answers.next()) { result += "<tr> <td colspan='2'><input type='radio' name='answer' value='" + answers.getString(2) + "'> " + answers.getString(2) + "</td></tr>"; } result += "</tr>"; answers.close(); } return result; } this is the HTML: <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>JSP Page</title> </head> <body> <h1>JSP Page</h1> <jsp:useBean id="exam" class="exam.ExamQuestions"></jsp:useBean> <% exam.setConnection(); %> <form method="post"> <table > <%=exam.getQuestions()%> </table> <input type="submit" name="action" value="next"/> </form> <% String action = request.getParameter("action"); if ("next".equals(action)) { out.println(request.getParameter("answer")); } %> </body> </html>

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• MySQL access classes in PHP

  - by Mike

  I have a connection class for MySQL that looks like this: class MySQLConnect { private $connection; private static $instances = 0; function __construct() { if(MySQLConnect::$instances == 0) { //Connect to MySQL server $this->connection = mysql_connect(MySQLConfig::HOST, MySQLConfig::USER, MySQLConfig::PASS) or die("Error: Unable to connect to the MySQL Server."); MySQLConnect::$instances = 1; } else { $msg = "Close the existing instance of the MySQLConnector class."; die($msg); } } public function singleQuery($query, $databasename) { mysql_select_db(MySQLConfig::DB, $this->connection) or die("Error: Could not select database " . MySQLConfig::DB . " from the server."); $result = mysql_query($query) or die('Query failed.'); return $result; } public function createResultSet($query, $databasename) { $rs = new MySQLResultSet($query, MySQLConfig::DB, $this->connection ) ; return $rs; } public function close() { MySQLConnect::$instances = 0; if(isset($this->connection) ) { mysql_close($this->connection) ; unset($this->connection) ; } } public function __destruct() { $this->close(); } } The MySQLResultSet class looks like this: class MySQLResultSet implements Iterator { private $query; private $databasename; private $connection; private $result; private $currentRow; private $key = 0; private $valid; public function __construct($query, $databasename, $connection) { $this->query = $query; //Select the database $selectedDatabase = mysql_select_db($databasename, $connection) or die("Error: Could not select database " . $this->dbname . " from the server."); $this->result = mysql_query($this->query) or die('Query failed.'); $this->rewind(); } public function getResult() { return $this->result; } // public function getRow() // { // return mysql_fetch_row($this->result); // } public function getNumberRows() { return mysql_num_rows($this->result); } //current() returns the current row public function current() { return $this->currentRow; } //key() returns the current index public function key() { return $this->key; } //next() moves forward one index public function next() { if($this->currentRow = mysql_fetch_array($this->result) ) { $this->valid = true; $this->key++; }else{ $this->valid = false; } } //rewind() moves to the starting index public function rewind() { $this->key = 0; if(mysql_num_rows($this->result) > 0) { if(mysql_data_seek($this->result, 0) ) { $this->valid = true; $this->key = 0; $this->currentRow = mysql_fetch_array($this->result); } } else { $this->valid = false; } } //valid returns 1 if the current position is a valid array index //and 0 if it is not valid public function valid() { return $this->valid; } } The following class is an example of how I am accessing the database: class ImageCount { public function getCount() { $mysqlConnector = new MySQLConnect(); $query = "SELECT * FROM images;"; $resultSet = $mysqlConnector->createResultSet($query, MySQLConfig::DB); $mysqlConnector->close(); return $resultSet->getNumberRows(); } } I use the ImageCount class like this: if(!ImageCount::getCount()) { //Do something } Question: Is this an okay way to access the database? Could anybody recommend an alternative method if it is bad? Thank-you.

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• Calculating the Size (in Bytes and MB) of a Oracle Coherence Cache

  - by Ricardo Ferreira

  The concept and usage of data grids are becoming very popular in this days since this type of technology are evolving very fast with some cool lead products like Oracle Coherence. Once for a while, developers need an programmatic way to calculate the total size of a specific cache that are residing in the data grid. In this post, I will show how to accomplish this using Oracle Coherence API. This example has been tested with 3.6, 3.7 and 3.7.1 versions of Oracle Coherence. To start the development of this example, you need to create a POJO ("Plain Old Java Object") that represents a data structure that will hold user data. This data structure will also create an internal fat so I call that should increase considerably the size of each instance in the heap memory. Create a Java class named "Person" as shown in the listing below. package com.oracle.coherence.domain; import java.io.Serializable; import java.util.ArrayList; import java.util.HashMap; import java.util.List; import java.util.Random; @SuppressWarnings("serial") public class Person implements Serializable { private String firstName; private String lastName; private List<Object> fat; private String email; public Person() { generateFat(); } public Person(String firstName, String lastName, String email) { setFirstName(firstName); setLastName(lastName); setEmail(email); generateFat(); } private void generateFat() { fat = new ArrayList<Object>(); Random random = new Random(); for (int i = 0; i < random.nextInt(18000); i++) { HashMap<Long, Double> internalFat = new HashMap<Long, Double>(); for (int j = 0; j < random.nextInt(10000); j++) { internalFat.put(random.nextLong(), random.nextDouble()); } fat.add(internalFat); } } public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } } Now let's create a Java program that will start a data grid into Coherence and will create a cache named "People", that will hold people instances with sequential integer keys. Each person created in this program will trigger the execution of a custom constructor created in the People class that instantiates an internal fat (the random amount of data generated to increase the size of the object) for each person. Create a Java class named "CreatePeopleCacheAndPopulateWithData" as shown in the listing below. package com.oracle.coherence.demo; import com.oracle.coherence.domain.Person; import com.tangosol.net.CacheFactory; import com.tangosol.net.NamedCache; public class CreatePeopleCacheAndPopulateWithData { public static void main(String[] args) { // Asks Coherence for a new cache named "People"... NamedCache people = CacheFactory.getCache("People"); // Creates three people that will be putted into the data grid. Each person // generates an internal fat that should increase its size in terms of bytes... Person pessoa1 = new Person("Ricardo", "Ferreira", "[email protected]"); Person pessoa2 = new Person("Vitor", "Ferreira", "[email protected]"); Person pessoa3 = new Person("Vivian", "Ferreira", "[email protected]"); // Insert three people at the data grid... people.put(1, pessoa1); people.put(2, pessoa2); people.put(3, pessoa3); // Waits for 5 minutes until the user runs the Java program // that calculates the total size of the people cache... try { System.out.println("---> Waiting for 5 minutes for the cache size calculation..."); Thread.sleep(300000); } catch (InterruptedException ie) { ie.printStackTrace(); } } } Finally, let's create a Java program that, using the Coherence API and JMX, will calculate the total size of each cache that the data grid is currently managing. The approach used in this example was retrieve every cache that the data grid are currently managing, but if you are interested on an specific cache, the same approach can be used, you should only filter witch cache will be looked for. Create a Java class named "CalculateTheSizeOfPeopleCache" as shown in the listing below. package com.oracle.coherence.demo; import java.text.DecimalFormat; import java.util.Map; import java.util.Set; import java.util.TreeMap; import javax.management.MBeanServer; import javax.management.MBeanServerFactory; import javax.management.ObjectName; import com.tangosol.net.CacheFactory; public class CalculateTheSizeOfPeopleCache { @SuppressWarnings({ "unchecked", "rawtypes" }) private void run() throws Exception { // Enable JMX support in this Coherence data grid session... System.setProperty("tangosol.coherence.management", "all"); // Create a sample cache just to access the data grid... CacheFactory.getCache(MBeanServerFactory.class.getName()); // Gets the JMX server from Coherence data grid... MBeanServer jmxServer = getJMXServer(); // Creates a internal data structure that would maintain // the statistics from each cache in the data grid... Map cacheList = new TreeMap(); Set jmxObjectList = jmxServer.queryNames(new ObjectName("Coherence:type=Cache,*"), null); for (Object jmxObject : jmxObjectList) { ObjectName jmxObjectName = (ObjectName) jmxObject; String cacheName = jmxObjectName.getKeyProperty("name"); if (cacheName.equals(MBeanServerFactory.class.getName())) { continue; } else { cacheList.put(cacheName, new Statistics(cacheName)); } } // Updates the internal data structure with statistic data // retrieved from caches inside the in-memory data grid... Set<String> cacheNames = cacheList.keySet(); for (String cacheName : cacheNames) { Set resultSet = jmxServer.queryNames( new ObjectName("Coherence:type=Cache,name=" + cacheName + ",*"), null); for (Object resultSetRef : resultSet) { ObjectName objectName = (ObjectName) resultSetRef; if (objectName.getKeyProperty("tier").equals("back")) { int unit = (Integer) jmxServer.getAttribute(objectName, "Units"); int size = (Integer) jmxServer.getAttribute(objectName, "Size"); Statistics statistics = (Statistics) cacheList.get(cacheName); statistics.incrementUnit(unit); statistics.incrementSize(size); cacheList.put(cacheName, statistics); } } } // Finally... print the objects from the internal data // structure that represents the statistics from caches... cacheNames = cacheList.keySet(); for (String cacheName : cacheNames) { Statistics estatisticas = (Statistics) cacheList.get(cacheName); System.out.println(estatisticas); } } public MBeanServer getJMXServer() { MBeanServer jmxServer = null; for (Object jmxServerRef : MBeanServerFactory.findMBeanServer(null)) { jmxServer = (MBeanServer) jmxServerRef; if (jmxServer.getDefaultDomain().equals(DEFAULT_DOMAIN) || DEFAULT_DOMAIN.length() == 0) { break; } jmxServer = null; } if (jmxServer == null) { jmxServer = MBeanServerFactory.createMBeanServer(DEFAULT_DOMAIN); } return jmxServer; } private class Statistics { private long unit; private long size; private String cacheName; public Statistics(String cacheName) { this.cacheName = cacheName; } public void incrementUnit(long unit) { this.unit += unit; } public void incrementSize(long size) { this.size += size; } public long getUnit() { return unit; } public long getSize() { return size; } public double getUnitInMB() { return unit / (1024.0 * 1024.0); } public double getAverageSize() { return size == 0 ? 0 : unit / size; } public String toString() { StringBuffer sb = new StringBuffer(); sb.append("\nCache Statistics of '").append(cacheName).append("':\n"); sb.append(" - Total Entries of Cache -----> " + getSize()).append("\n"); sb.append(" - Used Memory (Bytes) --------> " + getUnit()).append("\n"); sb.append(" - Used Memory (MB) -----------> " + FORMAT.format(getUnitInMB())).append("\n"); sb.append(" - Object Average Size --------> " + FORMAT.format(getAverageSize())).append("\n"); return sb.toString(); } } public static void main(String[] args) throws Exception { new CalculateTheSizeOfPeopleCache().run(); } public static final DecimalFormat FORMAT = new DecimalFormat("###.###"); public static final String DEFAULT_DOMAIN = ""; public static final String DOMAIN_NAME = "Coherence"; } I've commented the overall example so, I don't think that you should get into trouble to understand it. Basically we are dealing with JMX. The first thing to do is enable JMX support for the Coherence client (ie, an JVM that will only retrieve values from the data grid and will not integrate the cluster) application. This can be done very easily using the runtime "tangosol.coherence.management" system property. Consult the Coherence documentation for JMX to understand the possible values that could be applied. The program creates an in memory data structure that holds a custom class created called "Statistics". This class represents the information that we are interested to see, which in this case are the size in bytes and in MB of the caches. An instance of this class is created for each cache that are currently managed by the data grid. Using JMX specific methods, we retrieve the information that are relevant for calculate the total size of the caches. To test this example, you should execute first the CreatePeopleCacheAndPopulateWithData.java program and after the CreatePeopleCacheAndPopulateWithData.java program. The results in the console should be something like this: 2012-06-23 13:29:31.188/4.970 Oracle Coherence 3.6.0.4 <Info> (thread=Main Thread, member=n/a): Loaded operational configuration from "jar:file:/E:/Oracle/Middleware/oepe_11gR1PS4/workspace/calcular-tamanho-cache-coherence/lib/coherence.jar!/tangosol-coherence.xml" 2012-06-23 13:29:31.219/5.001 Oracle Coherence 3.6.0.4 <Info> (thread=Main Thread, member=n/a): Loaded operational overrides from "jar:file:/E:/Oracle/Middleware/oepe_11gR1PS4/workspace/calcular-tamanho-cache-coherence/lib/coherence.jar!/tangosol-coherence-override-dev.xml" 2012-06-23 13:29:31.219/5.001 Oracle Coherence 3.6.0.4 <D5> (thread=Main Thread, member=n/a): Optional configuration override "/tangosol-coherence-override.xml" is not specified 2012-06-23 13:29:31.266/5.048 Oracle Coherence 3.6.0.4 <D5> (thread=Main Thread, member=n/a): Optional configuration override "/custom-mbeans.xml" is not specified Oracle Coherence Version 3.6.0.4 Build 19111 Grid Edition: Development mode Copyright (c) 2000, 2010, Oracle and/or its affiliates. All rights reserved. 2012-06-23 13:29:33.156/6.938 Oracle Coherence GE 3.6.0.4 <Info> (thread=Main Thread, member=n/a): Loaded Reporter configuration from "jar:file:/E:/Oracle/Middleware/oepe_11gR1PS4/workspace/calcular-tamanho-cache-coherence/lib/coherence.jar!/reports/report-group.xml" 2012-06-23 13:29:33.500/7.282 Oracle Coherence GE 3.6.0.4 <Info> (thread=Main Thread, member=n/a): Loaded cache configuration from "jar:file:/E:/Oracle/Middleware/oepe_11gR1PS4/workspace/calcular-tamanho-cache-coherence/lib/coherence.jar!/coherence-cache-config.xml" 2012-06-23 13:29:35.391/9.173 Oracle Coherence GE 3.6.0.4 <D4> (thread=Main Thread, member=n/a): TCMP bound to /192.168.177.133:8090 using SystemSocketProvider 2012-06-23 13:29:37.062/10.844 Oracle Coherence GE 3.6.0.4 <Info> (thread=Cluster, member=n/a): This Member(Id=2, Timestamp=2012-06-23 13:29:36.899, Address=192.168.177.133:8090, MachineId=55685, Location=process:244, Role=Oracle, Edition=Grid Edition, Mode=Development, CpuCount=2, SocketCount=2) joined cluster "cluster:0xC4DB" with senior Member(Id=1, Timestamp=2012-06-23 13:29:14.031, Address=192.168.177.133:8088, MachineId=55685, Location=process:1128, Role=CreatePeopleCacheAndPopulateWith, Edition=Grid Edition, Mode=Development, CpuCount=2, SocketCount=2) 2012-06-23 13:29:37.172/10.954 Oracle Coherence GE 3.6.0.4 <D5> (thread=Cluster, member=n/a): Member 1 joined Service Cluster with senior member 1 2012-06-23 13:29:37.188/10.970 Oracle Coherence GE 3.6.0.4 <D5> (thread=Cluster, member=n/a): Member 1 joined Service Management with senior member 1 2012-06-23 13:29:37.188/10.970 Oracle Coherence GE 3.6.0.4 <D5> (thread=Cluster, member=n/a): Member 1 joined Service DistributedCache with senior member 1 2012-06-23 13:29:37.188/10.970 Oracle Coherence GE 3.6.0.4 <Info> (thread=Main Thread, member=n/a): Started cluster Name=cluster:0xC4DB Group{Address=224.3.6.0, Port=36000, TTL=4} MasterMemberSet ( ThisMember=Member(Id=2, Timestamp=2012-06-23 13:29:36.899, Address=192.168.177.133:8090, MachineId=55685, Location=process:244, Role=Oracle) OldestMember=Member(Id=1, Timestamp=2012-06-23 13:29:14.031, Address=192.168.177.133:8088, MachineId=55685, Location=process:1128, Role=CreatePeopleCacheAndPopulateWith) ActualMemberSet=MemberSet(Size=2, BitSetCount=2 Member(Id=1, Timestamp=2012-06-23 13:29:14.031, Address=192.168.177.133:8088, MachineId=55685, Location=process:1128, Role=CreatePeopleCacheAndPopulateWith) Member(Id=2, Timestamp=2012-06-23 13:29:36.899, Address=192.168.177.133:8090, MachineId=55685, Location=process:244, Role=Oracle) ) RecycleMillis=1200000 RecycleSet=MemberSet(Size=0, BitSetCount=0 ) ) TcpRing{Connections=[1]} IpMonitor{AddressListSize=0} 2012-06-23 13:29:37.891/11.673 Oracle Coherence GE 3.6.0.4 <D5> (thread=Invocation:Management, member=2): Service Management joined the cluster with senior service member 1 2012-06-23 13:29:39.203/12.985 Oracle Coherence GE 3.6.0.4 <D5> (thread=DistributedCache, member=2): Service DistributedCache joined the cluster with senior service member 1 2012-06-23 13:29:39.297/13.079 Oracle Coherence GE 3.6.0.4 <D4> (thread=DistributedCache, member=2): Asking member 1 for 128 primary partitions Cache Statistics of 'People': - Total Entries of Cache -----> 3 - Used Memory (Bytes) --------> 883920 - Used Memory (MB) -----------> 0.843 - Object Average Size --------> 294640 I hope that this post could save you some time when calculate the total size of Coherence cache became a requirement for your high scalable system using data grids. See you!

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• How can I eager-load a child collection mapped to a non-primary key in NHibernate 2.1.2?

  - by David Rubin

  Hi, I have two objects with a many-to-many relationship between them, as follows: public class LeftHandSide { public LeftHandSide() { Name = String.Empty; Rights = new HashSet<RightHandSide>(); } public int Id { get; set; } public string Name { get; set; } public ICollection<RightHandSide> Rights { get; set; } } public class RightHandSide { public RightHandSide() { OtherProp = String.Empty; Lefts = new HashSet<LeftHandSide>(); } public int Id { get; set; } public string OtherProp { get; set; } public ICollection<LeftHandSide> Lefts { get; set; } } and I'm using a legacy database, so my mappings look like: Notice that LeftHandSide and RightHandSide are associated by a different column than RightHandSide's primary key. <class name="LeftHandSide" table="[dbo].[lefts]" lazy="false"> <id name="Id" column="ID" unsaved-value="0"> <generator class="identity" /> </id> <property name="Name" not-null="true" /> <set name="Rights" table="[dbo].[lefts2rights]"> <key column="leftId" /> <!-- THIS IS THE IMPORTANT BIT: I MUST USE PROPERTY-REF --> <many-to-many class="RightHandSide" column="rightProp" property-ref="OtherProp" /> </set> </class> <class name="RightHandSide" table="[dbo].[rights]" lazy="false"> <id name="Id" column="id" unsaved-value="0"> <generator class="identity" /> </id> <property name="OtherProp" column="otherProp" /> <set name="Lefts" table="[dbo].[lefts2rights]"> <!-- THIS IS THE IMPORTANT BIT: I MUST USE PROPERTY-REF --> <key column="rightProp" property-ref="OtherProp" /> <many-to-many class="LeftHandSide" column="leftId" /> </set> </class> The problem comes when I go to do a query: LeftHandSide lhs = _session.CreateCriteria<LeftHandSide>() .Add(Expression.IdEq(13)) .UniqueResult<LeftHandSide>(); works just fine. But LeftHandSide lhs = _session.CreateCriteria<LeftHandSide>() .Add(Expression.IdEq(13)) .SetFetchMode("Rights", FetchMode.Join) .UniqueResult<LeftHandSide>(); throws an exception (see below). Interestingly, RightHandSide rhs = _session.CreateCriteria<RightHandSide>() .Add(Expression.IdEq(127)) .SetFetchMode("Lefts", FetchMode.Join) .UniqueResult<RightHandSide>(); seems to be perfectly fine as well. NHibernate.Exceptions.GenericADOException Message: Error performing LoadByUniqueKey[SQL: SQL not available] Source: NHibernate StackTrace: c:\opt\nhibernate\2.1.2\source\src\NHibernate\Type\EntityType.cs(563,0): at NHibernate.Type.EntityType.LoadByUniqueKey(String entityName, String uniqueKeyPropertyName, Object key, ISessionImplementor session) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Type\EntityType.cs(428,0): at NHibernate.Type.EntityType.ResolveIdentifier(Object value, ISessionImplementor session, Object owner) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Type\EntityType.cs(300,0): at NHibernate.Type.EntityType.NullSafeGet(IDataReader rs, String[] names, ISessionImplementor session, Object owner) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Persister\Collection\AbstractCollectionPersister.cs(695,0): at NHibernate.Persister.Collection.AbstractCollectionPersister.ReadElement(IDataReader rs, Object owner, String[] aliases, ISessionImplementor session) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Collection\Generic\PersistentGenericSet.cs(54,0): at NHibernate.Collection.Generic.PersistentGenericSet`1.ReadFrom(IDataReader rs, ICollectionPersister role, ICollectionAliases descriptor, Object owner) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Loader\Loader.cs(706,0): at NHibernate.Loader.Loader.ReadCollectionElement(Object optionalOwner, Object optionalKey, ICollectionPersister persister, ICollectionAliases descriptor, IDataReader rs, ISessionImplementor session) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Loader\Loader.cs(385,0): at NHibernate.Loader.Loader.ReadCollectionElements(Object[] row, IDataReader resultSet, ISessionImplementor session) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Loader\Loader.cs(326,0): at NHibernate.Loader.Loader.GetRowFromResultSet(IDataReader resultSet, ISessionImplementor session, QueryParameters queryParameters, LockMode[] lockModeArray, EntityKey optionalObjectKey, IList hydratedObjects, EntityKey[] keys, Boolean returnProxies) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Loader\Loader.cs(453,0): at NHibernate.Loader.Loader.DoQuery(ISessionImplementor session, QueryParameters queryParameters, Boolean returnProxies) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Loader\Loader.cs(236,0): at NHibernate.Loader.Loader.DoQueryAndInitializeNonLazyCollections(ISessionImplementor session, QueryParameters queryParameters, Boolean returnProxies) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Loader\Loader.cs(1649,0): at NHibernate.Loader.Loader.DoList(ISessionImplementor session, QueryParameters queryParameters) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Loader\Loader.cs(1568,0): at NHibernate.Loader.Loader.ListIgnoreQueryCache(ISessionImplementor session, QueryParameters queryParameters) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Loader\Loader.cs(1562,0): at NHibernate.Loader.Loader.List(ISessionImplementor session, QueryParameters queryParameters, ISet`1 querySpaces, IType[] resultTypes) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Loader\Criteria\CriteriaLoader.cs(73,0): at NHibernate.Loader.Criteria.CriteriaLoader.List(ISessionImplementor session) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Impl\SessionImpl.cs(1936,0): at NHibernate.Impl.SessionImpl.List(CriteriaImpl criteria, IList results) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Impl\CriteriaImpl.cs(246,0): at NHibernate.Impl.CriteriaImpl.List(IList results) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Impl\CriteriaImpl.cs(237,0): at NHibernate.Impl.CriteriaImpl.List() c:\opt\nhibernate\2.1.2\source\src\NHibernate\Impl\CriteriaImpl.cs(398,0): at NHibernate.Impl.CriteriaImpl.UniqueResult() c:\opt\nhibernate\2.1.2\source\src\NHibernate\Impl\CriteriaImpl.cs(263,0): at NHibernate.Impl.CriteriaImpl.UniqueResult[T]() D:\proj\CMS3\branches\nh_auth\DomainModel2Tests\Authorization\TempTests.cs(46,0): at CMS.DomainModel.Authorization.TempTests.Test1() Inner Exception System.Collections.Generic.KeyNotFoundException Message: The given key was not present in the dictionary. Source: mscorlib StackTrace: at System.ThrowHelper.ThrowKeyNotFoundException() at System.Collections.Generic.Dictionary`2.get_Item(TKey key) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Persister\Entity\AbstractEntityPersister.cs(2047,0): at NHibernate.Persister.Entity.AbstractEntityPersister.GetAppropriateUniqueKeyLoader(String propertyName, IDictionary`2 enabledFilters) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Persister\Entity\AbstractEntityPersister.cs(2037,0): at NHibernate.Persister.Entity.AbstractEntityPersister.LoadByUniqueKey(String propertyName, Object uniqueKey, ISessionImplementor session) c:\opt\nhibernate\2.1.2\source\src\NHibernate\Type\EntityType.cs(552,0): at NHibernate.Type.EntityType.LoadByUniqueKey(String entityName, String uniqueKeyPropertyName, Object key, ISessionImplementor session) I'm using NHibernate 2.1.2 and I've been debugging into the NHibernate source, but I'm coming up empty. Any suggestions? Thanks so much!

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• Unit testing a database connection and general questions on database-dependent code and unit testing

  - by dotnetdev

  Hi, If I have a method which establishes a database connection, how could this method be tested? Returning a bool in the event of a successful connection is one way, but is that the best way? From a testability method, is it best to have the connection method as one method and the method to get data back a seperate method? Also, how would I test methods which get back data from a database? I may do an assert against expected data but the actual data can change and still be the right resultset. EDIT: For the last point, to check data, if it's supposed to be a list of cars, then I can check they are real car models. Or if they are a bunch of web servers, I can have a list of existant web servers on the system, return that from the code under test, and get the test result. If the results are different, the data is the issue but the query not? THnaks

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• mysql query using jdbc

  - by S.PRATHIBA

  Hi all, I have the following table: Service_ID feedback 31 1 32 1 33 1 1 I have the sample code to find the sum: ResultSet res = st.executeQuery("SELECT Service_ID,SUM(consumer_feedback) FROM consumer5 group by Service_ID"); while (res.next()) { int data=res.getInt(1); System.out.println(data); System.out.println("\n\n"); int c1 = res.getInt(2); e[m]=res.getInt(2); System.out.println("\n \n m is "+m+" e[m] is "+e[m]); if(e[m]<0) e[m]=0; m++; System.out.print(c1); System.out.println("\t\t"); } i have to get the output as 31 1 32 1 33 1 I am getting it.But for my project i have 34,35 also.I should get theoutput as 31 1 32 1 33 1 34 0 35 0

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• populate jsp drop down with database info

  - by Cano63

  Hello, people, i,m looking for the way to populate a jsp dropdown. I want that when the jsp load it fill the dropdown with the info that i have in a database table. Down I,m icluding the code of my class that will create the array and fill it with the database info. Whant i don,t know is how to call that class from my jsp and fill the dropdown. '// this will create my array public static ArrayList getBrandsMakes() { ArrayList arrayBrandsMake = new ArrayList(); while(rs.next()) { arrayBrandsMake.add(loadOB(rs)); // CARGO MI ARREGLO CON UN OBJETO } return arrayBrandsMake; } } //this will load my array object private static DropDownBrands loadOB(ResultSet rs)throws SQLException { DropDownBrands OB = new DropDownBrands (); OB.setBrands("BRAN"); return OB; } '

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• T-SQL XML Query, how to seperate matching nodes into individual rows?

  - by FlySwat

  I have a table that has a column full of XML like: <parent> <child> <name>Sally</name> </child> <child> <name>Bobby</name> </child> </parent> I'm trying to extract all of the names of the children into seperate rows. My desired resultset would look like: Sally Bobby However, if I do something like: SELECT data.query('data(//parents/child/name)') FROM stuff I get back a single row that looks like Sally Bobby What am I doing wrong with the XPath?

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• Defaultifempty seems to work in linq to entities

  - by Rand

  I'm new to linq and linq to entities so I might have gone wrong in my assumptions, but I've been unknowingly trying to use DefaultIfEmpty in L2E. For some reason if I turn the resultset into a List, the Defaultifempty() works I don't know if I've inadvertantly crossed over into Linq area. The code below works, can anyone tell me why? And if it does work great, then it'll be of help to other people. var results = (from u in rv.tbl_user .Include("tbl_pics") .Include("tbl_area") .Include("tbl_province") .ToList() where u.tbl_province.idtbl_Province == prov select new { u.firstName, u.cellNumber, u.tbl_area.Area, u.ID,u.tbl_province.Province_desc, pic = (from p3 in u.tbl_pics where p3.tbl_user.ID == u.ID select p3.pic_path).DefaultIfEmpty("defaultpic.jpg").First() }).ToList();

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• Problems with Date, preparedStatement, JDBC and PostgreSQL

  - by GuidoMB

  I Have to get a movie from a PostgreSQL database that matches a given title and release date. title is a character(75) and releaseDate is a date. I Have this code: String query = "SELECT * FROM \"Movie\" WHERE title = ? AND \"releaseDate\" = ?)"; Connection conn = connectionManager.getConnection(); PreparedStatement stmt = conn.prepareStatement(query); java.sql.Date date = new java.sql.Date(releaseDate.getTime()); stmt.setString(1, title); stmt.setDate(2, date); ResultSet result = stmt.executeQuery(); but it's not working because the releaseDate is not matching when it should. The query SELECT * FROM "Movie" WHERE title = A_MOVIE AND "releaseDate" = A_DATE works perfectly on a command shell using psql

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• Need to preserve order of elements sent in JSON from Java

  - by Kush

  I'm using JSON.org APIs for Java to use JSON in my JSP webapp, I know JSONObject doesn't preserve order of elements the way they are put into it and one has to use JSONArray for that but I don't know how to use it since I need to send key and value both as received from the database, and here I'm sending data to jQuery via JSON where I need the order of data to be maintained. Following is my servlet code, where I'm getting results from the database using ORDER BY and hence I want the order to be exact as returned from the database. Also this JSON object requested using $.post method of jQuery and is used to populate dropdown on reciever page. ResultSet rs = st.executeQuery("SELECT * FROM tbl_state order by state_name"); JSONObject options = new JSONObject(); while(rs.next()) options.put(rs.getString("state_id"),rs.getString("state_name")); response.setContentType("application/json"); response.setCharacterEncoding("UTF-8"); response.getWriter().write(options); Thanks.

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• Mysql Error in query statements

  - by Mark Estrada

  Hi All, I am trying to acquaint myself on Mysql syntax. I only have used MSSQL so far. I downloaded the Mysql Query Browser and have installed the Mysql Version 5.1 I wanted to run this line of code in the resultset tab of mysql but I keep on encountering below error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'declare iCtr int' at line 1 declare iCtr int; set iCtr = 1; while iCtr < 1000 begin insert into employee (emp_id,emp_first_name,emp_last_name,status_id) values (iCtr, 'firstName' + iCtr, 'lastName' + iCtr, 1) set iCtr = iCtr + 1; end I just wanted to populate my employees table but I cannot get past the mysql syntax. Any advise please. Thanks

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