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  • Historical Rolling Daily sum

    - by user2980057
    I have a table of consisting of Dates and the amount of revenue recorded for that day going back for about 12 years. What I would like to do with this data is create a new table with Dates and prior 7-day revenue numbers. Any guidance would be greatly appreciated. Below is an example of what my source table and what my results would need to look like.... Source Table.. DATE | Revenue 12/31/2013 | 200 12/30/2013 | 300 12/29/2013 | 400 12/28/2013 | 100 12/27/2013 | 200 12/26/2013 | 150 12/25/2013 | 350 12/24/2013 | 450 12/23/2013 | 200 12/22/2013 | 300 12/21/2013 | 100 12/20/2013 | 300 Resulting Table... DATE | 7Dayrev 12/31/2013 | 1700 12/30/2013 | 1950 12/29/2013 | 1850 12/28/2013 | 1750 12/27/2013 | 1750 12/26/2013 | 1850 ETC......

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  • Calculate sum of objects for each unique object property in Ruby

    - by macek
    I was helping with an answer in this question and it sparked a question of my own. Pie is an object that has a pieces array made of of PiePiece objects. Each PiePiece has a flavor attribute How do I create a hash that looks like this: # flavor => number of pieces { :cherry => 3 :apple => 1 :strawberry => 2 } This works, but I think it could be improved def inventory hash = {} pieces.each do |p| hash[p.flavor] ||= 0 hash[p.flavor] += 1 end hash end Any ideas?

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  • summing the sum in mysql

    - by JPro
    Hi, Say If I get a resultset in mysql as : ID count(posts) 101 2344 102 3245 103 232 104 23 Is there any way to get the tota count of count(posts) in the query itself, like this? ID count(posts) 101 2344 102 3245 103 232 104 23 ------ 5844

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  • How to autosum value on dropdown and radio select

    - by Wilf
    I'm working on an auto calculation form which is a total column will change after a radio and a dropdown is clicked. I can make the total change for both dropdowns but the problem occurs when I tried to add a radio option. Here is my code. HTML Ages 10+: <select id="Adult" name="Adult"> <option selected="selected" value="0">0</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> </select> <br />Ages 3-9: <select id="Child" name="Child"> <option selected="selected" value="0">0</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> </select> <br />Food <input type="radio" name="food" id="food0" value="0" /> <label for="food0">No</label> <input type="radio" name="food" id="food1" value="10" /> <label for="food1">Yes</label> <table width="100%" border="1" align="center"> <tr> <td>Product</td> <td>Ages 10+</td> <td>Ages 3-9</td> <td>Food</td> <td>Price</td> </tr> <tr> <td>2 Day Ticket</td> <td>$235.00</td> <td>$223.00</td> <td><span id="food">0</span> </td> <td>$<span class="amount" id="2DayTotal"></span> </td> </tr> <tr> <td>3 Day Ticket</td> <td>$301.00</td> <td>$285.00</td> <td><span id="food">0</span> </td> <td>$<span class="amount" id="3DayTotal"></span> </td> </tr> <tr> <td>4 Day Ticket</td> <td>$315.00</td> <td>$298.00</td> <td><span id="food">0</span> </td> <td>$<span class="amount" id="4DayTotal"></span> </td> </tr> <tr> <td>5 Day Ticket</td> <td>$328.00</td> <td>$309.00</td> <td><span id="food">0</span> </td> <td>$<span class="amount" id="5DayTotal"></span> </td> </tr> </table> JavaScript var numAdult = 0; var numChild = 0; $("#Adult").change(function () { numAdult = $("#Adult").val(); calcTotals(); }); $("#Child").change(function () { numChild = $("#Child").val(); calcTotals(); }); $('input[type=radio]').change(function(evt) { $('#food').html($(this).val()); }); function calcTotals() { $("#2DayTotal").text(235 * numAdult + 223 * numChild); $("#3DayTotal").text(301 * numAdult + 285 * numChild); $("#4DayTotal").text(315 * numAdult + 298 * numChild); $("#5DayTotal").text(328 * numAdult + 309 * numChild); } The issues are: I'd like the food column change to it's value when a radio is click. It works only the first id. After a radio is clicked. A fumction calcTotals() is called to sum an additional food cost. Demo here : http://jsfiddle.net/4Jegn/178/ Please be advice.

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  • MS-Access 2007 Time Online Report

    - by Daniel
    I have the following data in my database: MemberID | DateTime ------------------------------------- 1 | 31/03/2010 3:45:49 PM 2 | 31/03/2010 3:55:29 PM 1 | 31/03/2010 4:45:49 PM Every time a user is authenticated or un-authenticated this log appears in the database. What I want to be able to do is total the time for a given user and date. Member 1 was online for 1 hour and 37 minutes. I would like to do this with sql as a report in access 2007 if anyone could help, that would be appreciated. Cheers, Daniel

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  • PHP: find 2 or more numbers from a list of N numbers that can add up towards a given ammount

    - by Splash
    Hi Guys, I am trying to create a little php script that can make my life a bit easier. Basically, I am going to have 21 text fields on a page where I am going to input 20 different numbers. In the last field I will enter a number let's call it the TOTAL AMMOUNT. All I want the script to do is to point out which numbers from the 20 fields added up will come up to TOTAL AMMOUNT. Example: field1= 25.23 field2= 34.45 field3= 56.67 field4= 63.54 field5= 87.54 .... field20= 4.2 Total Ammount= 81.90 Output: field1+fields3=81.90 Some of the fields might have 0 as value because sometimes I only need to enter 5-15 fields and the maximum will be 20. If someone can help me out with the php code for this, will be greatly appreciated.

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  • linq subquery child collection to string

    - by bill
    Hi All, i am trying to figure out how to write a linq query that will return a child collections "name" property as a string. I have a BO that has a "options" property where the options are the "name" property of each option in an "order" object. I would like the result to look something like order.id = 12312 order.date = 12/03/10 order.options = "Option 1 Name, Option 2 Name, Option 3 Name" I hope this makes sense. thanks for any and all help!

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  • Sum variable range of cells using "today's" date as starting point.

    - by Jason
    How do you sum a variable range of cells based upon today's date in MS Excel 2003. Spreadsheet format: Variable range = # of days to sum Date range = listed in row 1, 1 day per cell (example A1=1/1/10, B1=1/2/10, C1=1/3/10....) Numbers to be summed - listed in row 2, X number per cell (example A2=8, B2=6, C2=1.....) example problem: IF variable range = 2 & Current Date = 1/2/10 then...Sum(b2:c2)=7 I am able to sum the entire row based upon current date using the following formula but am not able to add the variable range to the sum function. =SUMIF(A1:C1,"="&TODAY(),A2:C2)

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  • How do I combine two rows of same part, but add quantities?

    - by Tom
    I have table "PICKITEM" PARTID QTY A 1 A 3 B 11 C 8 D 5 D 3 I need a select statement that will return one line for like PARTIDs and add the qty field to together, yet also return the rest of the lines in the table as is PARTID QTY A 4 B 11 C 8 D 8 Probably a newb question, but I am new to SQL syntax and queries. Any help in getting me on the right path would be appreciated!

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  • MDX , Calculate Number of days when the cummulative sum of Revenues from end of a month date match with the given debt amount.

    - by Shuchi
    Hi, I have a financial cube and i have to calculate Daily Sales Outstanding as : Number of Days between the selected month last date and the earliest transaction date when cummulative sum of Revenue from last date of the month till the date where sum revenue <= the debt amount for the date . e.g On 31/12/2009 my debt amount = 2,500,000 31-Dec-09 30-Nov-09 15-Oct-09 31-Oct-09 Revenue 1,000,000 1,000,000 500,000 1,0000 Cummulative sum of revenue 1,000,000 2,00,000 2,500,000 4,000,000 No of Days 31 30 16 On 15/Oct/09 cummulative revenue is 2,500,000 which equals my debt amount on that day Count of Days = 31 + 31 + 16 = 76 Days. In other words Sum Revenue from the selected date backwards until sum total equals or exeeds the total to date balance of the debtors. Any help will be highly appreciated . If i haven't explained clearly enough or if you need more information then please let me know. Thanks in advance . Shuchi.

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  • How can I get running totals of integer values from a SortedDictionary?

    - by user578083
    SortedDictionary<int, string> typeDictionary = new SortedDictionary<int, string>(); SortedDictionary<int, int> lengthDictionary = new SortedDictionary<int, int>(); lengthDictionary has values in key value pair as follows: <1,20> <2,8> <3,10> <4,5> i want LINQ query which will return me new list like as follows <1,20> <2,20+8=28> // 20 from key 1 <3,28+10=38> // 28 from key 2 <4,38+5=43> // 38 from key 3 Result should like this: <1,20> <2,28> <3,38> <4,43>

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  • Python TEA implementation

    - by Gaks
    Anybody knows proper python implementation of TEA (Tiny Encryption Algorithm)? I tried the one I've found here: http://sysadminco.com/code/python-tea/ - but it does not seem to work properly. It returns different results than other implementations in C or Java. I guess it's caused by completely different data types in python (or no data types in fact). Here's the code and an example: def encipher(v, k): y=v[0];z=v[1];sum=0;delta=0x9E3779B9;n=32 w=[0,0] while(n>0): y += (z << 4 ^ z >> 5) + z ^ sum + k[sum & 3] y &= 4294967295L # maxsize of 32-bit integer sum += delta z += (y << 4 ^ y >> 5) + y ^ sum + k[sum>>11 & 3] z &= 4294967295L n -= 1 w[0]=y; w[1]=z return w def decipher(v, k): y=v[0] z=v[1] sum=0xC6EF3720 delta=0x9E3779B9 n=32 w=[0,0] # sum = delta<<5, in general sum = delta * n while(n>0): z -= (y << 4 ^ y >> 5) + y ^ sum + k[sum>>11 & 3] z &= 4294967295L sum -= delta y -= (z << 4 ^ z >> 5) + z ^ sum + k[sum&3] y &= 4294967295L n -= 1 w[0]=y; w[1]=z return w Python example: >>> import tea >>> key = [0xbe168aa1, 0x16c498a3, 0x5e87b018, 0x56de7805] >>> v = [0xe15034c8, 0x260fd6d5] >>> res = tea.encipher(v, key) >>> "%X %X" % (res[0], res[1]) **'70D16811 F935148F'** C example: #include <unistd.h> #include <stdio.h> void encipher(unsigned long *const v,unsigned long *const w, const unsigned long *const k) { register unsigned long y=v[0],z=v[1],sum=0,delta=0x9E3779B9, a=k[0],b=k[1],c=k[2],d=k[3],n=32; while(n-->0) { sum += delta; y += (z << 4)+a ^ z+sum ^ (z >> 5)+b; z += (y << 4)+c ^ y+sum ^ (y >> 5)+d; } w[0]=y; w[1]=z; } int main() { unsigned long v[] = {0xe15034c8, 0x260fd6d5}; unsigned long key[] = {0xbe168aa1, 0x16c498a3, 0x5e87b018, 0x56de7805}; unsigned long res[2]; encipher(v, res, key); printf("%X %X\n", res[0], res[1]); return 0; } $ ./tea **D6942D68 6F87870D** Please note, that both examples were run with the same input data (v and key), but results were different. I'm pretty sure C implementation is correct - it comes from a site referenced by wikipedia (I couldn't post a link to it because I don't have enough reputation points yet - some antispam thing)

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  • Why binding is not a native feature in most of the languages?

    - by Gulshan
    IMHO binding a variable to another variable or an expression is a very common scenario in mathematics. In fact, in the beginning, many students think the assignment operator(=) is some kind of binding. But in most of the languages, binding is not supported as a native feature. In some languages like C#, binding is supported in some cases with some conditions fulfilled. But IMHO implementing this as a native feature was as simple as changing the following code- int a,b,sum; sum := a + b; a = 10; b = 20; a++; to this- int a,b,sum; a = 10; sum = a + b; b = 20; sum = a + b; a++; sum = a + b; Meaning placing the binding instruction as assignments after every instruction changing values of any of the variable contained in the expression at right side. After this, trimming redundant instructions (or optimization in assembly after compilation) will do. So, why it is not supported natively in most of the languages. Specially in the C-family of languages? Update: From different opinions, I think I should define this proposed "binding" more precisely- This is one way binding. Only sum is bound to a+b, not the vice versa. The scope of the binding is local. Once the binding is established, it cannot be changed. Meaning, once sum is bound to a+b, sum will always be a+b. Hope the idea is clearer now. Update 2: I just wanted this P# feature. Hope it will be there in future.

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  • Solving the puzzle in javascript [on hold]

    - by Gandalf StormCrow
    I've recently try to brush up my javascript skills, so I have a friend who gives me puzzles from time to time to solve. Yesterday I got this : function testFun() { f = {}; for( var i=0 ; i<3 : i++ ) { f[i] = function() { alert("sum='+i+f.length); } } return f; } Expected Results: testFun()[0]() should alert “sum=0” testFun()[1]() should alert “sum=2” testFun()[2]() should alert “sum=4” I did this which does like requested above: function testFun() { var i, f = {}; for (i = 0; i < 3; i++) { f[i] = (function(number) { return function() { alert("sum=" + (number * 2)); } }(i)); } return f; } Today I got new puzzle : Name everything wrong with this javascript code, then tell how you would re-write it. function testFun(fInput) { f = fInput || {}; // append three functions for( var i=0 ; i<3 : i++ ) { f[i] = function() { alert("sum='+i+f.length); } } return f; } // Sample Expected Results (do not change) myvar = testFun(); myvar[0](); // should alert “sum=0” myvar[1](); // should alert “sum=2” testFun(['a'])[2](); // should alert “sum=5”`enter code here How do I accomplish the third case testFun(['a'])[2]()? Also could my answer from yesterday be written better and what can be improved if so?

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  • Create a fast algorithm for a "weighted" median

    - by Hameer Abbasi
    Suppose we have a set S with k elements of 2-dimensional vectors, (x, n). What would be the most efficient algorithm to calculate the median of the weighted set? By "weighted set", I mean that the number x has a weight n. Here is an example (inefficient due to sorting) algorithm, where Sx is the x-part, and Sn is the n-part. Assume that all co-ordinate pairs are already arranged in Sx, with the respective changes also being done in Sn, and the sum of n is sumN: sum <= 0; i<= 0 while(sum < sumN) sum <= sum + Sn(i) ++i if(sum > sumN/2) return Sx(i) else return (Sx(i)*Sn(i) + Sx(i+1)*Sn(i+1))/(Sn(i) + Sn(i+1)) EDIT: Would this hold in two or more dimensions, if we were to calculate the median first in one dimension, then in another, with n being the sum along that dimension in the second pass?

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  • How can I provide values for non-grouped columns in NHibernate?

    - by ddc0660
    I have a criteria query: Session.CreateCriteria<Sell043Report>() .SetProjection(.ProjectionList() .Add(LambdaProjection.GroupProperty<Sell043Report>(r => r.location)) .Add(LambdaProjection.GroupProperty<Sell043Report>(r => r.agent)) .Add(LambdaProjection.GroupProperty<Sell043Report>(r => r.cusip)) .Add(LambdaProjection.GroupProperty<Sell043Report>(r => r.SettlementDate)) .Add(LambdaProjection.GroupProperty<Sell043Report>(r => r.salePrice)) .Add(LambdaProjection.GroupProperty<Sell043Report>(r => r.foreignFx)) .Add(LambdaProjection.GroupProperty<Sell043Report>(r => r.batchNumber)) .Add(LambdaProjection.GroupProperty<Sell043Report>(r => r.origSaleDate)) .Add(LambdaProjection.GroupProperty<Sell043Report>(r => r.planName)) .Add(LambdaProjection.GroupProperty<Sell043Report>(r => r.dateTimeAdded)) .Add(LambdaProjection.Sum<Sell043Report>(r => r.shares)) .Add(LambdaProjection.Sum<Sell043Report>(r => r.netMoney)) .Add(LambdaProjection.Sum<Sell043Report>(r => r.grossMoney)) .Add(LambdaProjection.Sum<Sell043Report>(r => r.taxWithheld)) .Add(LambdaProjection.Sum<Sell043Report>(r => r.fees))) .List<Sell043Report>(); that generates the following SQL: SELECT this_.location as y0_, this_.agent as y1_, this_.cusip as y2_, this_.SettlementDate as y3_, this_.salePrice as y4_, this_.foreignFx as y5_, this_.batchNumber as y6_, this_.origSaleDate as y7_, this_.planName as y8_, this_.dateTimeAdded as y9_, sum(this_.shares) as y10_, sum(this_.netMoney) as y11_, sum(this_.grossMoney) as y12_, sum(this_.taxWithheld) as y13_, sum(this_.fees) as y14_ FROM MIS_IPS_Sell043Report this_ GROUP BY this_.location, this_.agent, this_.cusip, this_.SettlementDate, this_.salePrice, this_.foreignFx, this_.batchNumber, this_.origSaleDate, this_.planName, this_.dateTimeAdded however the Sell043Report table has additional columns than those listed in the SELECT statement so I'm receiving this error when attempting to get a list of Sell043Reports: System.ArgumentException: The value "System.Object[]" is not of type "xyz.Sell043Report" and cannot be used in this generic collection. I suspect the problem is that I'm not selecting all of the columns for a Sell043Report and so it doesn't know how to map the dataset to the object. I'm trying to achieve something like this: SELECT this_.location as y0_, this_.agent as y1_, this_.cusip as y2_, this_.SettlementDate as y3_, this_.salePrice as y4_, this_.foreignFx as y5_, this_.batchNumber as y6_, this_.origSaleDate as y7_, this_.planName as y8_, this_.dateTimeAdded as y9_, sum(this_.shares) as y10_, sum(this_.netMoney) as y11_, sum(this_.grossMoney) as y12_, sum(this_.taxWithheld) as y13_, sum(this_.fees) as y14_, '' as Address1, '' as Address2 // etc FROM MIS_IPS_Sell043Report this_ GROUP BY this_.location, this_.agent, this_.cusip, this_.SettlementDate, this_.salePrice, this_.foreignFx, this_.batchNumber, this_.origSaleDate, this_.planName, this_.dateTimeAdded How can I do this using NHibernate?

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  • Cant install software

    - by user53209
    So I just installed the ubuntu 11.10 .. And when i goto software center and try to download any software(use source).. all i get is a window saying that "Failed to download repository information" , "check your internet connection" and W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric_restricted_binary-i386_Packages Hash Sum mismatch , W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric_universe_binary-i386_Packages Hash Sum mismatch , W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric_multiverse_binary-i386_Packages Hash Sum mismatch , W:Failed to fetch htt p ://archive.ubuntu.com/ubuntu/dists/oneiric/main/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric_main_i18n_Index , W:Failed to fetch http ://archive.ubuntu.com/ubuntu/dists/oneiric/multiverse/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric_multiverse_i18n_Index , W:Failed to fetch htt ://archive.ubuntu.com/ubuntu/dists/oneiric/restricted/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric_restricted_i18n_Index , W:Failed to fetch ht tp://archive.ubuntu.com/ubuntu/dists/oneiric/universe/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric_universe_i18n_Index , W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-updates_main_source_Sources Hash Sum mismatch , W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-updates_restricted_binary-i386_Packages Hash Sum mismatch , W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-updates_universe_binary-i386_Packages Hash Sum mismatch , W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-updates_multiverse_binary-i386_Packages Hash Sum mismatch , W:Failed to fetch h tp://archive.ubuntu.com/ubuntu/dists/oneiric-updates/main/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-updates_main_i18n_Index , W:Failed to fetch h ttp://archive.ubuntu.com/ubuntu/dists/oneiric-updates/multiverse/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-updates_multiverse_i18n_Index , W:Failed to fetch ht tp://archive.ubuntu.com/ubuntu/dists/oneiric-updates/restricted/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-updates_restricted_i18n_Index , W:Failed to fetch htt p://archive.ubuntu.com/ubuntu/dists/oneiric-updates/universe/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-updates_universe_i18n_Index , W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-backports_main_source_Sources Hash Sum mismatch , W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-backports_restricted_binary-i386_Packages Hash Sum mismatch , W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-backports_universe_binary-i386_Packages Hash Sum mismatch , W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-backports_multiverse_binary-i386_Packages Hash Sum mismatch , W:Failed to fetch h ttp://archive.ubuntu.com/ubuntu/dists/oneiric-backports/main/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-backports_main_i18n_Index , W:Failed to fetch h ttp://archive.ubuntu.com/ubuntu/dists/oneiric-backports/multiverse/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-backports_multiverse_i18n_Index , W:Failed to fetch ht tp://archive.ubuntu.com/ubuntu/dists/oneiric-backports/restricted/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-backports_restricted_i18n_Index , W:Failed to fetch ht tp://archive.ubuntu.com/ubuntu/dists/oneiric-backports/universe/i18n/Index No Hash entry in Release file /var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-backports_universe_i18n_Index , W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_oneiric-security_main_source_Sources Hash Sum mismatch , E:Some index files failed to download. They have been ignored, or old ones used instead." Neglect the http typos, its to evade the 2 hyperlink.. I tried making a file in the apt.conf.d folder also, and added proxy entries, also set the system proxy.. and also the "network proxy", but nothing works.. And now I cant install any software!! Help needed

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  • How can I sum number of rows of a table in SQL ORACLE?

    - by Christian Magro
    Dear community I have the follow instruction on SQL ORACLE: SELECT COUNT(FE_DAY) FROM TI_DATE WHERE (FE_MO = 02 AND FE_YEAR in ('2011', '2012')) GROUP BY FE_DAY In this instruction effectively obtain like SQL Answer a list of number that they sum=10 .But How can I don't show rows .I need only show the row's sum=10 I tried to apply the follow SQL instruction also: SELECT SUM(COUNT(FE_DAY)) FROM TI_DATE WHERE (FE_MO = 02 AND FE_YEAR in ('2011', '2012')) GROUP BY FE_DAY But the answer was 57, different of the number of rows, that I need.

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  • How to make a SUM of Dictionary Value nested into a list with LINQ ?

    - by user551108
    Hi All, I have a product object declared as : Product { int ProductID; string ProductName; int ProductTypeID; string ProductTypeName; int UnitsSold Dictionary <string, int> UnitsSoldByYear; } I want to make a sum on UnitsSold and UnitsSoldByYear properties with a Linq query but I didn't know how to make this kind of sum on a dictionary ! Here is my begining linq query code : var ProductTypeSum = from i in ProductsList group i by new { i.ProductTypeID, i.ProductTypeName} into pt select new { ProductTypeID= pt.Key.ProductTypeID, ProductTypeName= pt.Key.ProductTypeName, UnitsSoldSum= pt.Sum(i => i.UnitsSold), // How to make a Dictionary sum here } Thank you for your help !

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  • Finding k elements of length-n list that sum to less than t in O(nlogk) time

    - by tresbot
    This is from Programming Pearls ed. 2, Column 2, Problem 8: Given a set of n real numbers, a real number t, and an integer k, how quickly can you determine whether there exists a k-element subset of the set that sums to at most t? One easy solution is to sort and sum the first k elements, which is our best hope to find such a sum. However, in the solutions section Bentley alludes to a solution that takes nlog(k) time, though he gives no hints for how to find it. I've been struggling with this; one thought I had was to go through the list and add all the elements less than t/k (in O(n) time); say there are m1 < k such elements, and they sum to s1 < t. Then we are left needing k - m1 elements, so we can scan through the list again in O(n) time looking for all elements less than (t - s1)/(k - m1). Add in again, to get s2 and m2, then again if m2 < k, look for all elements less than (t - s2)/(k - m2). So: def kSubsetSumUnderT(inList, k, t): outList = [] s = 0 m = 0 while len(outList) < k: toJoin = [i for i in inList where i < (t - s)/(k - m)] if len(toJoin): if len(toJoin) >= k - m: toJoin.sort() if(s0 + sum(toJoin[0:(k - m - 1)]) < t: return True return False outList = outList + toJoin s += sum(toJoin) m += len(toJoin) else: return False My intuition is that this might be the O(nlog(k)) algorithm, but I am having a hard time proving it to myself. Thoughts?

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  • Sum if ONLY all the cells have a value?

    - by Mike
    Hi I need to sum 9 cells of data, each one on a separate sheet, but always in the same location. I only want a figure returned when all the cells have data, even if it's a 0. But, if one of the cells is blank I want a blank return. I'm trying to get my head around, making it up actually, where the IFs and ISBLANK and SUMS would go. Any pointers would be greatly appreciated. SUM(IF(ISBLANK(RANGEA,OR(RANGEB),0,ALLRANGES))) Many thanks Michael

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