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  • The Social Content Conundrum

    - by Mike Stiles
    Here’s the social content conundrum: people who are not entertainers are being asked to entertain. Despite a world of skilled MBAs, marketing savants, technological innovators, analysts, social strategists and consultants, every development in social for brands keeps boomeranging right back to the same unavoidable truth. Success hinges on having content creators who know how to entertain the target audience. You can’t make this all about business-processes. You can’t make this all about technology, though data is critical and helps inform content. This is about having human beings who know the audience, know what they’d love to see, and can create the magic that will draw and hold them. Since showing up in the News Feed is critical for exposition and engagement, and since social ads primarily serve to amplify content that’s performing well, I’m comfortable saying content creators are becoming exponentially recruited and valued. They will no longer be commodities. They’ll be your stars. Social has fundamentally changed the relationship between brand and consumer. No longer can the customer be told to sit down, shut up, and listen to our ads. It’s now all about what consumers are willing to watch or read. Their patience for subjecting themselves to material they aren’t interested in is waning. Therefore, brands must now be producers of entertainment and information content, not merely placers of ads within someone else’s content. Social has given you a huge stage, with an audience sitting out there waiting to see what you’re going to do. What are you putting on that stage? For most corporate environments, entertaining is alien. It’s risky and subjective. Most operate around two foundational principles: control and fear. To entertain and inform with branded content, some control has to go. You control the product. Past that, control is being transferred into the hands of the consumer. The “fear first” culture also has to yield. If you strive to never make waves, you will move absolutely nothing. Because most corporations don’t house entertainers, they must be found then trusted. They’re usually a little weird. The ideas they’ll bring may seem “out there.” But like any business professional, they’ve gone through the training and experiences that make them uniquely good at what they do, even if you don’t quite understand them. It’s okay. It’s what the audience thinks that matters. Get it right, and you’ll be generating one ambassador after another who’s proud to be identified with the brand and will regularly consume and share your content. Entertainment entities are able to shape our culture and succeed beyond their wildest dreams by being beholden to one thing…what the public likes and wants. When brands put the same emphasis on crowd-pleasing content, they too will enjoy brand fame the likes of which they’ve never seen. The stage is yours. Now get out there and go for that applause.

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  • Duplicating someone's content legitimately & writing HTML to support that

    - by Codecraft
    I want to add content from other blogs to my own (with the authors permission) to help build additional relevant content and support articles I've found useful that others have written. I'm looking into how to do this responsibly - ie, by giving the original content author a boost and not competing against them for search traffic which should go to their site. In order to keep my duplicate content out of search, and to hint to the search engines where the original content is to be found i've implemented: <head> <meta name='robots' content='noindex, follow'> <link rel='canonical' href='http://www.originalblog.com/original-post.html' /> </head> Additionally, to boost the original article and to let readers know where it came from i'll be adding something like this: <div> Article originally written by <a href='http://www.authorswebsite.com'>Authors Name</a> and reproduced with permission.<br/> <a href='http://www.originalblog.com/original-post.html' target='new'> Read the original article here. </a> </div> All that remains is a way to 'officially' credit the original author in the HTML for the search spiders to see. Can anyone tell me a way to do this possibly using rel="author" (as far as I can see thats only good for my own original content), or perhaps it doesn't matter given that the reproduced pages will be kept out of search engines? Also, have I overlooked anything in the approach?

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  • Android Update Layout Content

    - by GuyNoir
    I'm looking for a way to update a layout's content with a new view. Is there any way to easily do this. It would be similar to how tabs work, but I don't want to have to get into extending the current tab structure if I don't have to. The final result would be a few buttons that would switch the content in a specific linearlayout for each button. Any help?

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  • Returned content type - Restlet

    - by DutrowLLC
    How do you set the content type in Restlet? In this case, I'd like to set the content type to ""text/xml". I have: public class SubResource extends ServerResource { @Get public Representation get(Representation representation){ setStatus(Status.SUCCESS_OK); StringRepresentation sr = new StringRepresentation(getSomeXml()); return sr; } } I'm unsure even if it is a value that is set in the Representation, or if it is set from the ServerResource class the same way that the return code is.

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  • Making JSP page not set the response content-type

    - by doublep
    Is it possible to make JSP pages not set any content type on response? In my setup, JSP doesn't directly generate the response, but rather an intermediate presentation, which is then processed by additional Java code that creates HTML or JSON based on that. So, can I somehow make JSP not set content-type on the response and leave it to the intermediate code? If I just remove contentType="..." in a JSP, it still defaults to text/html.

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  • Lxml or Xpath content print

    - by Angelo
    function= def parseTitle(self, post): """ Returns title string with spaces replaced by dots "" return post.xpath('h2')[0].text.replace('.', ' ') i would to see the content of post. Tried all . How can i properly debug the content. ir is an webstite of movies where i rip links and tittle. So this one should parse the title.and i am sure H@ is not existing , how to print/debug it?

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  • universal content manager

    - by ankur
    I found one limitation in Oracle UCM. Well it might not be limitation but I am not able to figure it out yet: I didn't find mapping between metadata and content type. What if I wish to associate different set of metadata with different content type which is likely the case? Thanks.

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  • CSS resizable menu and content background images

    - by Hristo
    Hello, I need to have resizable menu and content background images for my site, so both of them get stretched whenever the menu entries are too many, or the contents go outside the borders of the content background. I need vertical stretching. Could you, please, give me a hint (an actual answer would work as well) or a link to a good example? Thank you very much in advance!

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  • How to stream partial content with ASP.NET MVC FileStreamResult

    - by o_o
    We're using a FileStreamResult to provide video data to a Silverlight MediaElement based video player: public ActionResult Preview(Guid id) { return new FileStreamResult( Services.AssetStore.GetStream(id, ContentType.Preview), "application/octet-stream"); } Unfortunately, the Silverlight video player downloads the entire video file before it starts playing. This behavior is expected as our Preview Action does not support downloading partial content. (side note: if the file is hosted in an IIS virtual directory we can start playback at any location in the video while it is still downloading. however for security and auditing reasons we can't provide a direct download link. so this is not an option.) How can we improve the Controller Action to support partial HTTP content? I assume we first have to inform the client that we support it (adding an "Accept-Ranges:bytes" header to a HEAD request), then we have to evaluate the HTTP "Range" header and stream the requested file range with a response code of 206. Will that work with ASP.NET MVC hosted on IIS6? Is there already some code available? Also see: http://en.wikipedia.org/wiki/List_of_HTTP_headers http://blogs.msdn.com/anilkumargupta/archive/2009/04/29/downloadprogress-downloadprogressoffset-and-bufferprogress-of-the-mediaelement.aspx http://benramsey.com/archives/206-partial-content-and-range-requests/

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  • Not to miss! Today’s web seminar on content integration with Oracle Apps

    - by Lance Shaw
    Hello everyone.  The first web seminar in a three-part series kicks off later today, focused on the value of delivering and controlling the flow of content in the context of your most critical business applications.   If you are using Oracle E-Business Suite, PeopleSoft Enterprise, JD Edwards EnterpriseOne or Siebel CRM, we heartily recommend you investigate the value of centralizing the delivery of scanned images, forms, faxes and digital documents within those processes.  The improvements in efficiency and productivity can result in some impressive cost savings. One customer recently reported that they had realized an impressive ROI of 180% and that the investment in this new technology had paid for itself in a mere 6 months.  We hope you can spare some time today to join us at 1pm Eastern Time / 10am Pacific Time / 18:00 GMT. We think you will find it time well spent.   Click here to attend.  We look forward to seeing you there!

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  • Programmatically copying custom content type and columns from one web to another

    - by BeraCim
    Hi all: I'm experiencing a very stubborn problem when copying custom content type and its columns from one web to another within the same site. Basically, this is the code that I have: foreach (SPField field in existingWeb.Fields) { if (!destinationWeb.Fields.ContainsField(field.Title)) { destinationWeb.Fields.AddFieldAsXml(field.SchemaXml); destinationWeb.Update(); } } foreach (SPContentType existingWebCt in destinationWeb.ContentType) { SPContentType newContentType = new SPContentType(existingWebCt.Parent, destinationWeb.ContentTypes, existingWebCt.Name); foreach (SPFieldLink fieldLink in existingWebCt.FieldLinks) { SPField sourceField = existingWebCt.Fields[fieldLink.Id]; if (destinationWeb.Fields.ContainsField(sourceField.Title)) { SPFieldLink destinationWebFieldLink = new SPFieldLink(destinationWeb.Fields[sourceField.Title]); newContentType.FieldLinks.Add(destinationWebFieldLink); } } } existingWeb and destinationWeb are 2 webs within the same site. The code runs fine. But the problem is that in the SITE Content Type screen (under site settings), when I click the custom column link in the custom content type, I got an error saying: Invalid field name {UID}. The UID is the same UID as the custom column in the existing site. I checked with my web settings after completion. I can see the custom list (which I created with an item for testing purpose), but the custom column is gone from the view (though the actual data is still there... just have to check the box to get it to display). But I think that is less important... more of fyi. I've also gotten a variety of different exceptions should I copy things wrongly. Google has failed to help me out on this one. Does anyone know what I'm missing in order to get that link to work again? Thanks.

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  • How to remove duplicate content, which is still indexed, but not linked to anymore?

    - by David
    A bug in the tool, which we use to create search-engine-friendly URLs changed our whole URL-structure overnight, and we only noticed after Google already indexed the page. Now, we have a massive duplicate content issue, causing a harsh drop in rankings. Webmaster Tools shows over 1,000 duplicate title tags, so I don't think, Google understands what is going on. Right URL: abc.com/price/sharp-ah-l13-12000-btu.html Wrong URL: abc.com/item/sharp-l-series-ahl13-12000-btu.html (created by mistake) After that, we ... Changed back all URLs to the "Right URLs" Set up a 301-redirect for all "Wrong URLs" a few days later Now, still a massive amount of pages is in the index twice. As we do not link internally to the "Wrong URLs" anymore, I am not sure, if Google will re-crawl them very soon. What can we do to solve this issue and tell Google, that all the "Wrong URLs" now redirect to the "Right URLs"? Best, David

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  • ActionScript 3.0 Getting Size/Coordinates From Loader Content

    - by TheDarkIn1978
    i'm attempting to position a textfield to the bottom left of an image that is added to the display list from the Loader() class. i don't know how to access the width/height information of the image. var dragSprite:Sprite = new Sprite(); this.addChild(dragSprite); var imageLoader:Loader = new Loader(); imageLoader.load(new URLRequest("picture.jpg")); imageLoader.contentLoaderInfo.addEventListener(Event.COMPLETE, displayPic, false, 0, true); function displayPic(evt:Event):void { dragSprite.addChild(evt.target.content); evt.target.removeEventListener(Event.COMPLETE, displayPic); } var tf:TextField = new TextField(); tf.text = "Picture Title"; tf.width = 200; tf.height = 14; tf.x //same x coordinate of dragSprite tf.y //same y coordinate of dragSprite, plus picture height, plus gap between picture and text addChild(tf); within the displayPic function, i could assign the evt.target.content.height and evt.target.content.width to variables that i could use to position the text field, but i assume there is a better way?

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  • How to handle error with content-disposition

    - by František Žiacik
    Hi, how should I handle an exception that occurs after sending a Content-Disposition header for an attachment? I'm trying to generate a report at server and send it as a file, but if an exception occurs during the report generation, the error message itself is sent to browser which still takes it as a content of a file and shows a Save As dialog. User cannot know there was an error generating report, saves the file which is in wrong format now. Is there a way to cancel the response with this header and redirect to an error page? Or what else can I do to inform user about the error? Probably I could generate the report first and only if there was no error send the headers, but I want the report render directly to the Response output stream so that it does not need to stay in memory. Here is my code: this.Response.ContentType = "application/octet-stream"; this.Response.AddHeader("Content-Disposition", @"attachment; filename=""" + item.Name + @""""); this.Response.Flush(); GenerateReportTo(this.Response.OutputStream); // Exception occurs Thanks for any suggestions

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  • Set button content in a label (custom control)

    - by user1881207
    Instead of voting negative this question, answer to tell me what's wrong! I want to set the Button Content in a label in the custom control, because when I use it, the Content property is not visible and the button is empty (no text). <Button x:Class="WpfApplication1.UserControl1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" mc:Ignorable="d" d:DesignHeight="35" d:DesignWidth="273" Content="Button"> <Button.Template> <ControlTemplate> <Grid> <Rectangle Name="rGridBack" StrokeThickness="1"> <Rectangle.Fill> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF4D4D4D" Offset="1" /> <GradientStop Color="#FF404040" Offset="0" /> </LinearGradientBrush> </Rectangle.Fill> <Rectangle.Stroke> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF4F4F4F" Offset="0" /> <GradientStop Color="#FF5B5B5B" Offset="1" /> </LinearGradientBrush> </Rectangle.Stroke> </Rectangle> <Rectangle Fill="#FF1E1E1E" Margin="1,1,1,1" Name="rThickness" /> <Rectangle Margin="2,2,2,2" Name="rGridTop" StrokeThickness="1"> <Rectangle.Fill> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF68686C" Offset="0" /> <GradientStop Color="#FF474747" Offset="1" /> </LinearGradientBrush> </Rectangle.Fill> <Rectangle.Stroke> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF7F7F7F" Offset="0" /> <GradientStop Color="#FF575757" Offset="1" /> </LinearGradientBrush> </Rectangle.Stroke> </Rectangle> <!--This label is where I want to set the Button.Content property--> <Label FontWeight="Normal" Foreground="White" HorizontalContentAlignment="Center" Name="tblckStep1Desc" Padding="0" VerticalContentAlignment="Center"> <Label.Effect> <DropShadowEffect BlurRadius="2" Color="Black" Direction="330" Opacity="0.7" ShadowDepth="1.5" /> </Label.Effect> </Label> </Grid> <ControlTemplate.Triggers> <Trigger Property="Button.Content" Value=""> <Setter Property="Content" TargetName="tblckStep1Desc"> </Setter> </Trigger> <Trigger Property="UIElement.IsMouseOver" Value="True"> <Setter Property="Shape.Fill" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF838383" Offset="0" /> <GradientStop Color="#FF545454" Offset="1" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF595959" Offset="1" /> <GradientStop Color="#FF929292" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridBack"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF414141" Offset="0" /> <GradientStop Color="#FF565656" Offset="1" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Fill" TargetName="rThickness"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF181818" Offset="1" /> <GradientStop Color="#FF181818" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> </Trigger> <Trigger Property="UIElement.IsEnabled" Value="False"> <Setter Property="Shape.Fill" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF68686C" Offset="0" /> <GradientStop Color="#FF474747" Offset="1" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF7F7F7F" Offset="0" /> <GradientStop Color="#FF575757" Offset="1" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridBack"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF4F4F4F" Offset="0" /> <GradientStop Color="#FF5B5B5B" Offset="1" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Fill" TargetName="rThickness"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF1E1E1E" Offset="1" /> <GradientStop Color="#FF1E1E1E" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Control.Foreground" TargetName="tblckStep1Desc"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF898989" Offset="1" /> <GradientStop Color="#FF898989" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> </Trigger> <Trigger Property="ButtonBase.IsPressed" Value="True"> <Setter Property="Shape.Fill" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF313131" Offset="1" /> <GradientStop Color="#FF2E2E2E" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF1F1F1F" Offset="1" /> <GradientStop Color="#FF1F1F1F" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridBack"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF414141" Offset="1" /> <GradientStop Color="#FF565656" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Fill" TargetName="rThickness"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF0C0C0C" Offset="1" /> <GradientStop Color="#FF0C0C0C" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> </Trigger> </ControlTemplate.Triggers> </ControlTemplate> </Button.Template> The button is based on Adobe CS5 suite on dialog forms, because a lot of code.

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  • Approaches for cross server content sharing?

    - by Anonymity
    I've currently been tasked with finding a best solution to serving up content on our new site from another one of our other sites. Several approaches suggested to me, that I've looked into include using SharePoint's Lists Web Service to grab the list through javascript - which results in XSS and is not an option. Another suggestion was to build a server side custom web service and use SharePoint Request Forms to get the information - this is something I've only very briefly looked at. It's been suggested that I try permitting the requesting site in the HTTP headers of the serving site since I have access to both. This ultimately resulted in a semi-working solution that had major security holes. (I had to include username/password in the request to appease AD Authentication). This was done by allowing Access-Control-Allow-Origin: * The most direct approach I could think of was to simply build in the webpart in our new environment to have the authors manually update this content the same as they would on the other site. Are any one of the suggestions here more valid than another? Which would be the best approach? Are there other suggestions I may be overlooking? I'm also not sure if WebCrawling or Content Scrapping really holds water here...

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  • How can I create multiple mini-sites with similar/duplicate content without hurting my search engine rank?

    - by ekpyrotic
    Essential background: I run a small company that lets members of the public post handwritten letters to their local politician (UK-based). Every week a number of early stage bills (called Early Day Motions) are submitted for debate in the House of Commons, and supporters of the motion will contact their local Members of Parliament, asking them to sign the motion. The crux: I want to target these EDMs with customised mini-sites, so when people search "EDM xxx", they find my customised mini-site, specifically targeting that EDM (i.e., "Send a handwritten letter to your MP asking them to sign EDM xxx"). At the moment, all these mini-sites (and my homepage) have duplicate content with only the relevant EDM name, number, and background image changed. (For example, http://mailmymp.com and http://mailmymp.com/edm/teaching-life-saving-skills-at-school-edm-550.php). The question: Firstly, will this hurt my potential search engine ranking? And, if so, what's the best way to target these political campaigns in an efficient manner without hurting my SEO prospects?

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  • What Is SEO Friendly Content?

    SEO friendly content is nothing but the content that is written keeping in mind the way in which search engines would view that content. SEO friendly content does not imply writing for search engines but taking their view of forming opinions into consideration.

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  • Website Content is King - True?

    There is truth to the line - Content is King! It is content that converts. With poor content your traffic is wasted and sales are lost. Great content not only speaks to readers but also to the search engines - letting them know what searches you are relevant to.

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  • http-equiv=content-language alternative - the way of specifying document language

    - by tugberk
    Lots of web sites uses following meta tag to specify the default language of the document: <meta http-equiv="content-language" content="es-ES"> When I go to w3c site: http://www.w3.org/TR/2011/WD-html-markup-20110113/meta.http-equiv.content-language.html#meta.http-equiv.content-language I get this: Using the meta element to specify the document-wide default language is obsolete. Consider specifying the language on the root element instead. What is the way of specifying document language now?

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  • Google I/O 2012 - Get your Content on Google TV

    Google I/O 2012 - Get your Content on Google TV Christian Kurzke , Andrew Jeon, Mark Lindner Google TV devices are typically the largest screen in the house, which makes them a prime platform for developers who want to distribute high quality, long form content right to the living room. We will talk about different options for hosting, streaming and securing your content on Google TV, and how to ensure your audience has a great experience viewing your content. For all I/O 2012 sessions, go to developers.google.com From: GoogleDevelopers Views: 1562 26 ratings Time: 01:01:00 More in Science & Technology

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