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  • Yet another Python Windows CMD mklink problem ... can't get it to work!

    - by Felix Dombek
    OK I have just posted another question which outlined my program but the specific problem was different. Now, my program just stops working without any message whatsoever. I'd be grateful if someone could help me here. I want to create symlinks for each file in a directory structure, all in one large flat folder, and have the following code by now: # loop over directory structure: # for all items in current directory, # if item is directory, recurse into it; # else it's a file, then create a symlink for it def makelinks(folder, targetfolder, cmdprocess = None): if not cmdprocess: cmdprocess = subprocess.Popen("cmd", stdin = subprocess.PIPE, stdout = subprocess.PIPE, stderr = subprocess.PIPE) print(folder) for name in os.listdir(folder): fullname = os.path.join(folder, name) if os.path.isdir(fullname): makelinks(fullname, targetfolder, cmdprocess) else: makelink(fullname, targetfolder, cmdprocess) #for a given file, create one symlink in the target folder def makelink(fullname, targetfolder, cmdprocess): linkname = os.path.join(targetfolder, re.sub(r"[\/\\\:\*\?\"\<\>\|]", "-", fullname)) if not os.path.exists(linkname): try: os.remove(linkname) print("Invalid symlink removed:", linkname) except: pass if not os.path.exists(linkname): cmdprocess.stdin.write("mklink " + linkname + " " + fullname + "\r\n") So this is a top-down recursion where first the folder name is printed, then the subdirectories are processed. If I run this now over some folder, the whole thing just stops after 10 or so symbolic links. Here is the output: D:\Musik\neu D:\Musik\neu\# Electronic D:\Musik\neu\# Electronic\# tag & reencode D:\Musik\neu\# Electronic\# tag & reencode\ChillOutMix D:\Musik\neu\# Electronic\# tag & reencode\Unknown D&B D:\Musik\neu\# Electronic\# tag & reencode\Unknown D&B 2 The program still seems to run but no new output is generated. It created 9 symlinks for some files in the # tag & reencode and the first three files in the ChillOutMix folder. The cmd.exe Window is still open and empty, and shows in its title bar that it is currently processing the mklink command for the third file in ChillOutMix. I tried to insert a time.sleep(2) after each cmdprocess.stdin.write in case Python is just too fast for the cmd process, but it doesn't help. Does anyone know what the problem might be?

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  • git- how to troubleshoot "cannot find command"

    - by Frank Schwieterman
    I need help getting git extensions to run with msysgit. I have had bad luck with extensions git-tfs and git-fetchall, in both cases it is the same problem. The addon will require a file to be placed where git can find it (git-tfs.exe and git-fetchall.sh). I understand this to mean the files need to be in a directory that is in the 'PATH' environment variable. In both cases I get stuck at this point: $ git-diffall bash: git-diffall: command not found When I run echo %PATH% from a regular command shell, it shows my path variable includes the directories where git-diffall and git-tfs are. How can I debug this, or am I missing something? Is there a way within msysgit to verify the command search path is what I expect?

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  • Svn repository split problem

    - by Tuminoid
    I want to split a directory from a large Subversion repository to a repository of its own, and keep the history of the files in that directory. I tried the regular way of doing it first svnadmin dump /path/to/repo > largerepo.dump cat largerepo.dump | svndumpfilter include my/directory >mydir.dump but that does not work, since the directory has been moved and copied over the years and files have been moved into and out of it to other parts of the repository. The result is a lot of these: svndumpfilter: Invalid copy source path '/some/old/path' Next thing I tried is to include those /some/old/path as they appear and after a long, long list of files and directories included, the svndumpfilter completes, BUT importing the resulting dump isn't producing the same files as the current directory has. So, how do I properly split the directory from that repository while keeping the history? EDIT: I specifically want trunk/myproj to be the trunk in a new repository PLUS have the new repository include none of the other old stuff, ie. there should not be possibility for anyone to update to old revision before the split and get/see the files. The svndumpfilter solution I tried would achieve exactly that, sadly its not doable since the path/files have been moved around. The solution by ng isn't accetable since its basically a clone+removal of extras which keeps ALL the history, not just relevant myproj history. BUMP C'moon, there must be someone who definitely knows if this is doable or not, and how!

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  • appcfg.py upload_data entity kind problem

    - by Dingo
    Hi, I am developing application on app-engine-path and I would like to upload some data to datastore. For example I have a model models/places.py: class Place(db.Model): name = db.StringProperty() longitude = db.FloatProperty() latitude = db.FloatProperty() If I save this in view, kind() of this entity is "models_place". All is ok, Place.all() in view work fine. But: If I upload some next row using appcfg.py upload_data, the kind() of this entities is Place. loader.py look like this: import datetime, os, sys from google.appengine.ext import db from google.appengine.tools import bulkloader libs_path = os.path.join("/home/martin/myproject/src/") if libs_path not in sys.path: sys.path.insert(0, libs_path) from models import places class AlbumLoader(bulkloader.Loader): def __init__(self): bulkloader.Loader.__init__(self, 'Place', [('name', lambda x: x.decode('utf-8')), ('longitude', float), ('latitude', float), ]) loaders = [AlbumLoader] and command for uploading: python /usr/local/google_appengine/appcfg.py upload_data --config_file=places_loader.py --kind=models_place --filename=data/places.csv --url=http://localhost:8000/remote_api /home/martin/myproject/src/

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  • How to set property only on second column of a ListView?

    - by Lernkurve
    Introduction I have a ListView and want to format only the second column. The following XAML code does that: <ListView x:Name="listview"> <ListView.View> <GridView> <GridViewColumn Header="Property" DisplayMemberBinding="{Binding Path=Key}" Width="100"/> <!-- <GridViewColumn Header="Value" DisplayMemberBinding="{Binding Path=Value}" Width="250">--> <GridViewColumn Header="Value" Width="250"> <GridViewColumn.CellTemplate> <DataTemplate> <TextBlock Text="{Binding Path=Value}" Foreground="CornflowerBlue" AutomationProperties.Name={Binding Path="Key"}/> </DataTemplate> </GridViewColumn.CellTemplate> </GridViewColumn> </GridView> </ListView.View> </ListView> The one problem I have is that the AutomationProperties.Name property is not being set. I was checking it with the Coded UI Test Builder and the property is empty. The Text and the Foreground property are being set correctly. Question Does anyone know why AutomationProperties.Name is not being set? Additional information Strangly enough, the following XAML code does set the AutomationProperties.Name <ListView x:Name="listview"> <ListView.Resources> <Style TargetType="TextBlock"> <Setter Property="AutomationProperties.Name" Value="{Binding Key}"/> </Style> </ListView.Resources> <ListView.View> <GridView> <GridViewColumn Header="Property" DisplayMemberBinding="{Binding Path=Key}" Width="100"/> <GridViewColumn Header="Value" DisplayMemberBinding="{Binding Path=Value}" Width="250"/> </GridView> </ListView.View> </ListView> The problem here though is that AutomationProperties.Name is being set on all the columns. But I only want it on the second one because otherwise my Coded UI Test code returns the wrong value (that of the first column, instead of that of the second column which I want).

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  • asp.net root paths

    - by dejavu
    I am getting the exception when trying to save a file: System.Web.HttpException: The SaveAs method is configured to require a rooted path, and the path '~/Thumbs/TestDoc2//small/ImageExtractStream.bmp' is not rooted. at System.Web.HttpPostedFile.SaveAs(String filename) at System.Web.HttpPostedFileWrapper.SaveAs(String filename) at PitchPortal.Core.Extensions.ThumbExtensions.SaveSmallThumb(Thumb image) in C:\Users\Bich Vu\Documents\Visual Studio 2008\Projects\PitchPortal\PitchPortal.Core\Extensions\ThumbExenstions.cs:line 23 the code is below: public static void SaveSmallThumb(this Thumb image) { var logger = Microsoft.Practices.ServiceLocation.ServiceLocator.Current.GetInstance<ILoggingService>(); string savedFileName = HttpContext.Current.Server.MapPath(Path.Combine( image.SmallThumbFolderPath, Path.GetFileName(image.PostedFile.FileName))); try { image.PostedFile.SaveAs(savedFileName); } catch (Exception ex) { logger.Log(ex.ToString()); } } I cant see what is wrong here, any tips?

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  • Implementing a State Machine in Angular.js to control routing

    - by ldn_tech_exec
    Can anyone help me with integrating a state machine to control routing? What's the best method to do this? Create a service? I need to basically intercept every $location request, run the state machine and let it figure out what the next $location.path should be. Think of the problem like a bank of questions that get added and removed over time. The user visits once in a while, passes in the user's answers object to the statemachine, and the statemachine figures out which question to load. This is my pseudocode, but i need to figure out where to put this or what event I can hook into to make sure all route requests are passed through the machine. Do I need a specific stateMachine controller? Do I create a service? Where do I use the service? Do I need to override $locationProvider? $scope.user.answers = [{ id: 32, answer: "whatever" }, { id:33, answer: "another answer" }] $scope.questions = [{ id:32, question:"what is your name?", path:"/question/1" },{ id:34, question:"how old are you?", path:"/question/2" }] var questions = $scope.questions; angular.forEach(questions, function(question) { if(question.id !exist in $scope.user.answers.id) { $location.path = question.path break; }); Thanks

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  • How to add system property equivalent to java -D in Ant

    - by Shervin
    Hi. I need to set java -Djava.library.path=/some/path and I want to do it when I am running my ant script, building my jar. I think I have to use <sysproperty key="java.library.path" value="/some/path"/> but it doesnt work. I cannot make the syntax work. The only thing I have Googled and found is sysproperty in conjunction with <java classname> but that doesnt make any sense to me. I am not sure if this is relevant, but I am using ant to create a ear and deploying this ear in JBoss.

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  • Sharepoint Variations Error

    - by marcocampos
    I'm getting some crazy errors when trying to create variations in Sharepoint. Has anybody seen this error? PublishingPage::AttemptPairUpWithPage() Ends. this: http://wseasp05/PT/Paginas/Destaque1.aspx, destPageUrl: /ES/Paginas/Destaque1.aspx Begin DeploymentWrapper::SynchronizePeerPages(), sourcePage = Paginas/Destaque1.aspx DeploymentWrapper::SynchronizePeerPages(), synchronizeDestUrl = /ES/Paginas/Destaque1.aspx Access to the path 'C:\Windows\TEMP\11c7c12e-030d-4860-a942-f5ab71f0930d\ExportSettings.xml' is denied. at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share, Int32 bufferSize, FileOptions options, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share, Int32 bufferSize, FileOptions options) at System.IO.FileInfo.Create() at Microsoft.SharePoint.Deployment.Ex... ...portDataFileManager.Initialize() at Microsoft.SharePoint.Deployment.SPExport.InitializeExport() at Microsoft.SharePoint.Deployment.SPExport.Run() Export Completed. DeploymentWrapper.SynchronizePeerPages() catches UnauthorizedAccessException. Spawn failed for /ES/Paginas/Destaque1.aspx End of DeploymentWrapper.SynchronizePeerPages() Thanks in advance.

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  • Users being forced to re-login randomly, before session and auth ticket timeout values are reached

    - by Don
    I'm having reports and complaints from my user that they will be using a screen and get kicked back to the login screen immediately on their next request. It doesn't happen all the time but randomly. After looking at the Web server the error that shows up in the application event log is: Event code: 4005 Event message: Forms authentication failed for the request. Reason: The ticket supplied has expired. Everything that I read starts out with people asking about web gardens or load balancing. We are not using either of those. We're a single Windows 2003 (32-bit OS, 64-bit hardware) Server with IIS6. This is the only website on this server too. This behavior does not generate any application exceptions or visible issues to the user. They just get booted back to the login screen and are forced to login. As you can imagine this is extremely annoying and counter-productive for our users. Here's what I have set in my web.config for the application in the root: <authentication mode="Forms"> <forms name=".TcaNet" protection="All" timeout="40" loginUrl="~/Login.aspx" defaultUrl="~/MyHome.aspx" path="/" slidingExpiration="true" requireSSL="false" /> </authentication> I have also read that if you have some locations setup that no longer exist or are bogus you could have issues. My path attributes are all valid directories so that shouldn't be the problem: <location path="js"> <system.web> <authorization> <allow users="*" /> </authorization> </system.web> </location> <location path="images"> <system.web> <authorization> <allow users="*" /> </authorization> </system.web> </location> <location path="anon"> <system.web> <authorization> <allow users="*" /> </authorization> </system.web> </location> <location path="App_Themes"> <system.web> <authorization> <allow users="*" /> </authorization> </system.web> </location> <location path="NonSSL"> <system.web> <authorization> <allow users="*" /> </authorization> </system.web> </location> The only thing I'm not clear on is if my timeout value in the forms property for the auth ticket has to be the same as my session timeout value (defined in the app's configuration in IIS). I've read some things that say you should have the authentication timeout shorter (40) than the session timeout (45) to avoid possible complications. Either way we have users that get kicked to the login screen a minute or two after their last action. So the session definitely should not be expiring. Update 2/23/09: I've since set the session timeout and authentication ticket timeout values to both be 45 and the problem still seems to be happening. The only other web.config in the application is in 1 virtual directory that hosts Community Server. That web.config's authentication settings are as follows: <authentication mode="Forms"> <forms name=".TcaNet" protection="All" timeout="40" loginUrl="~/Login.aspx" defaultUrl="~/MyHome.aspx" path="/" slidingExpiration="true" requireSSL="true" /> </authentication> And while I don't believe it applies unless you're in a web garden, I have both of the machine key values set in both web.config files to be the same (removed for convenience): <machineKey validationKey="<MYVALIDATIONKEYHERE>" decryptionKey="<MYDECRYPTIONKEYHERE>" validation="SHA1" /> <machineKey validationKey="<MYVALIDATIONKEYHERE>" decryptionKey="<MYDECRYPTIONKEYHERE>" validation="SHA1"/> Any help with this would be greatly appreciated. This seems to be one of those problems that yields a ton of Google results, none of which seem to be fitting into my situation so far.

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  • problem with MANIFEST.MF in jar

    - by dhananjay
    I have created my jar file in the following folder: /usr/local/bin/niidle.jar And I have one jarfile which is in the following folder /Projects/EnwelibDatedOct13/Niidle/lib/hector-0.6.0-17.jar And this file 'hector-0.6.0-17.jar' I have to include in MANIFEST.MF in jar. And when I mention class path in MANIFEST.MF as follows: Manifest-Version: 1.0 Main-Class: com.ensarm.niidle.web.scraper.NiidleScrapeManager Class-Path: /Projects/EnwelibDatedOct13/Niidle/lib/hector-0.6.0-17.jar When I run this using command: java -jar /usr/local/bin/niidle.jar It works properly.. But I dont want to give full Class-Path name, I have to give Class-Path as follows: Manifest-Version: 1.0 Main-Class: com.ensarm.niidle.web.scraper.NiidleScrapeManager Class-Path: lib/hector-0.6.0-17.jar And when I run this using command: java -jar /usr/local/bin/niidle.jar It is showing error message: Exception in thread "main" java.lang.NoClassDefFoundError: me/prettyprint/hector/api/Serializer at com.ensarm.niidle.web.scraper.NiidleScrapeManager.main(NiidleScrapeManager.java:21) Caused by: java.lang.ClassNotFoundException: me.prettyprint.hector.api.Serializer at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) at java.lang.ClassLoader.loadClass(ClassLoader.java:252) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) ... 1 more Please tell me solution for that...

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  • Add shading to clipped UIView

    - by huggie
    I'm creating an iphone application. I have this UIView whose content is clipped with a path. I want to add shading and/or shadow to it. What's the best way to do this? For shadow, I tried CGContextSetShadow() but it doesn't seem to have an effect (perhaps it's drawing outside the shown region?) . How about shading? I want it to appear along the path. What's the best way to go about it? Is it to create another narrow clip strip along the original clipping path (if it's possible to have two clip path... ) Or does this need to be done in another CALayer? I am not even sure what that is yet.

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  • Grails UrlMappings with .html

    - by Glennn
    I'm developing a Grails web application (mainly as a learning exercise). I have previously written some standard Grails apps, but in this case I wanted to try creating a controller that would intercept all requests (including static html) of the form: <a href="/testApp/testJsp.jsp">test 1</a> <a href="/testApp/testGsp.gsp">test 2</a> <a href="/testApp/testHtm.htm">test 3</a> <a href="/testApp/testHtml.html">test 4</a> The intent is to do some simple business logic (auditing) each time a user clicks a link. I know I could do this using a Filter (or a range of other methods), however I thought this should work too and wanted to do this using a Grails framework. I set up the Grail UrlMappings.groovy file to map all URLs of that form (/$myPathParam?) to a single controller: class UrlMappings { static mappings = { "/$controller/$action?/$id?"{ constraints { } } "/$path?" (controller: 'auditRecord', action: 'showPage') "500"(view:'/error') } } In that controller (in the appropriate "showPage" action) I've been printing out the path information, for example: def showPage = { println "params.path = " + params.path ... render(view: resultingView) } The results of the println in the showPage action for each of my four links are testJsp.jsp testGsp.gsp testHtm.htm testHtml Why is the last one "testHtml", not "testHtml.html"? In a previous (Stack Overflow query) Olexandr encountered this issue and was advised to simply concatenate the value of request.format - which, indeed, does return "html". However request.format also returns "html" for all four links. I'm interested in gaining an understanding of what Grails is doing and why. Is there some way to configure Grails so the params.path variable in the controller shows "testHtml.html" rather than stripping off the "html" extension? It doesn't seem to remove the extension for any other file type (including .htm). Is there a good reason it's doing this? I know that it is a bit unusual to use a controller for static html, but still would like to understand what's going on.

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  • Why do I get "Error 6060" when I try to use DBD::Advantage with a 64-bit perl on Linux?

    - by WarheadsSE
    I realize that I am attempting to go beyond the "supported" behavior of the manf's released drivers for Perl, after all they have only released it in package with x86 .so's. However, since I cannot use their package with x64 Perl on a RHEL 5.4 x86_64 box, and maintaining a seperate install of x86 Perl just for this one package, I have made an attempt to get this puppy working thanks to released 64-bit .so's that accompany other driver packages for Advantage. What I have done to this point: download beta 10 DBI drivers, in 32 download beta 10 PHP extension (it contains 32 and x86_64) copy the required DLLs into the ads-lib location (eg /usr/local/ads/lib64) compile the Perl DBI driver with the path to the lib64's .so's Good compilation, good install, good use. The problem is that I always get : failed: [iAnywhere Solutions][Advantage SQL][ASA] Error 6060: Advantage Database Server not available on specified server. axServerConnect (SQL-HY000)(DBD: db_login/SQLConnect err=-1) Does anyone have any ideas? EDIT: fixed package name in post title EDIT: Updated title. It appears that it's not just the x64 perl, but the RHEL 5.4 underneath that may be interfering. As commented below, I managed to shoe-horn a x86 perl onto the system, and compile the DBD::Advantage 9.99, and later replacing that with 9.10, and none of these x86 would connect either. Neither library (9.99 or 9.10) in either bit-edness will connect from this x86_64 server to the windows server's UNC path. I have successfully mounted this share without problems, but still I cannot seem to connect to the 9.1. I have tried: \hostname\PATH \FQDN\PATH \IP\PATH and all of these variations with the port (default) 6262 included. My windows machine connects fine, with both 9.1 and 9.99 from strawberry perl.

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  • is there any IIS setting require for url rewriting?

    - by Samir
    Hello, i have used URL rewriting using global.asax file. url rewriting is working file on local machine but when i made it online its not working. void Application_BeginRequest(Object sender, EventArgs e) { var extension = Path.GetExtension(Request.PhysicalPath).ToLower(); if (File.Exists(Request.PhysicalPath)) { if (extension == ".html") { Response.WriteFile(Request.PhysicalPath); Response.End(); } return; } var path = Request.Path; if (!Context.Items.Contains("ORIGINAL_REQUEST")) Context.Items.Add("ORIGINAL_REQUEST", path); if (extension == ".html") { var resource = UrlRewriting.FindRequestedResource(); var command = UrlRewriting.GetExecutionPath(resource); Context.RewritePath(command, true); } } url is:ind205.cfmdeveloper.com when you click on about us ,demo,advertise page it will not display. so please let me know is there any IIS setting require, reply me soon thanks Samir

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  • Apache - Reverse Proxy and HTTP 302 status messsage

    - by Rob
    My team is trying to setup an Apache reverse proxy from a customer's site into one of our web applications. http://www.example.com/app1/some-path maps to http://internal1.example.com/some-path Inside our application we use struts and have redirect = true set on certain actions in order to provide certain functionality. The 302 status messages from these re-directs cause the user to break out of the proxy resulting in an error page for the end user. HTTP/1.1 302 Found Location: http://internal.example.com/some-path/redirect Is there any way to setup the reverse proxy in apache so that the redirects work correctly? http://www.example.com/app1/some-path/redirect

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  • How to allow the user to select an input file for my SQL AdventureWorks web application?

    - by salvationishere
    I have a SQL and VS 2008 web application that I need to capture the full file path (directories and file name) from the selected file on the client computer. So user selects a file and then clicks on one of the buttons which transfers control to my code for processing. So how do I get its file path? I can get the file name, but not the path. Maybe problem is that while testing this web app, I am using the server instead of client machine. And I learned that on a server you cannot read the full file path due to security concerns. Is this true? If I just want this to work on client machine, which method/class do you recommend? And then how can I test it? My web app allows the user to select an input file and then map columns from the input .MDF file with columns from the selected Adventureworks table. Finally, after they click on the "Append" button, it adds rows from the input file to that table. So I want to capture the path info after they click this button.

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  • Issue in creating Zip file using glob.glob

    - by infosyssec
    Hi, I am creating a Zip file from a folder (and subfolders). it works fine and creates a new .zip file also but I am having an issue while using glob.glob. It is reading all files from the desired folder (source folder) and writing to the new zip file but the problem is that it is, however, adding subdirectories, but not adding files form the subdirectories. I am giving user an option to select the filename and path as well as filetype also (Zip or Tar). I don;t get any problem while creating .tar.gz file, but when use creates .zip file, this problem comes across. Here is my code: for name in (Source_Dir): for name in glob.glob("/path/to/source/dir/*" ): myZip.write(name, os.path.basename(name), zipfile.ZIP_DEFLATED) myZip.close() Also, if I use code below: for dirpath, dirnames, filenames in os.walk(Source_Dir): myZip.write(os.path.join(dirpath, filename) os.path.basename(filename)) myZip.close() Now the 2nd code taks all files even if it inside the folder/ subfolders, creates a new .zip file and write to it without any directory strucure. It even does not take dir structure for main folder and simply write all files from main dir or subdir to that .zip file. Can anyone please help me or suggest me. I would prefer glob.glob rather than the 2nd option to use. Thanks in advance. Regards, Akash

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  • Can can I reference extended methods/params without having to cast from the base class object return

    - by Greg
    Hi, Is there away to not have a "cast" the top.First().Value() return to "Node", but rather have it automatically assume this (as opposed to NodeBase), so I then see extended attributes for the class I define in Node? That is is there a way to say: top.Nodes.First().Value.Path; as opposed to now having to go: ((Node)top.Nodes.First().Value).Path) thanks [TestMethod()] public void CreateNoteTest() { var top = new Topology(); Node node = top.CreateNode("a"); node.Path = "testpath"; Assert.AreEqual("testpath", ((Node)top.Nodes.First().Value).Path); // *** HERE *** } class Topology : TopologyBase<string, Node, Relationship> { } class Node : NodeBase<string> { public string Path { get; set; } } public class NodeBase<T> { public T Key { get; set; } public NodeBase() { } public NodeBase(T key) { Key = key; } } public class TopologyBase<TKey, TNode, TRelationship> where TNode : NodeBase<TKey>, new() where TRelationship : RelationshipBase<TKey>, new() { // Properties public Dictionary<TKey, NodeBase<TKey>> Nodes { get; private set; } public List<RelationshipBase<TKey>> Relationships { get; private set; } }

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  • Why linking doesn't work in my Xtext-based DSL?

    - by reprogrammer
    The following is the Xtext grammar for my DSL. Model: variableTypes=VariableTypes predicateTypes=PredicateTypes variableDeclarations= VariableDeclarations rules=Rules; VariableType: name=ID; VariableTypes: 'var types' (variableTypes+=VariableType)+; PredicateTypes: 'predicate types' (predicateTypes+=PredicateType)+; PredicateType: name=ID '(' (variableTypes+=[VariableType|ID])+ ')'; VariableDeclarations: 'vars' (variableDeclarations+=VariableDeclaration)+; VariableDeclaration: name=ID ':' type=[VariableType|ID]; Rules: 'rules' (rules+=Rule)+; Rule: head=Head ':-' body=Body; Head: predicate=Predicate; Body: (predicates+=Predicate)+; Predicate: predicateType=[PredicateType|ID] '(' (terms+=Term)+ ')'; Term: variable=Variable; Variable: variableDeclaration=[VariableDeclaration|ID]; terminal WS: (' ' | '\t' | '\r' | '\n' | ',')+; And, the following is a program in the above DSL. var types Node predicate types Edge(Node, Node) Path(Node, Node) vars x : Node y : Node z : Node rules Path(x, y) :- Edge(x, y) Path(x, y) :- Path(x, z) Path(z, y) When I used the generated Switch class to traverse the EMF object model corresponding to the above program, I realized that the nodes are not linked together properly. For example, the getPredicateType() method on a Predicate node returns null. Having read the Xtext user's guide, my impression is that the Xtext default linking semantics should work for my DSL. But, for some reason, the AST nodes of my DSL don't get linked together properly. Can anyone help me in diagnosing this problem?

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  • How to define paper in raphael JS liberary?

    - by cj333
    Hi, I want to learn raphael JS liberary to draw a square. I copied the official code, but it is not work, "paper is not defined on line 34". how to define it? The demo is on http://www.irunmywebsite.com/raphael/additionalhelp.php the left menu "animate" ,Thanks. <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <title>Raphaël · Gear</title> <style type="text/css"> body { background: #333; color: #fff; font: 300 100.1% "Helvetica Neue", Helvetica, "Arial Unicode MS", Arial, sans-serif; } #holder { height: 480px; left: 50%; margin: -240px 0 0 -320px; position: absolute; top: 50%; width: 640px; } #copy { bottom: 0; font: 300 .7em "Helvetica Neue", Helvetica, "Arial Unicode MS", Arial, sans-serif; position: absolute; right: 1em; text-align: right; } #copy a { color: #fff; } </style> <script src="raphael-min.js" type="text/javascript" charset="utf-8"></script> <script type="text/javascript" charset="utf-8"> var a = paper.circle(320, 100, 60).attr({fill:'#FF0000'}); a.animate({ 'translation': '0,300' }, 500, 'bounce'); var b = paper.circle(320, 100, 60).attr({fill:'#FFFF00'});; b.animate({ cx: 320, cy: 300 }, 500, 'bounce'); var path1=paper.path("M114 253").attr({"stroke": "#f00", "stroke-width":3}); path1.animate({path: "M114 253 L 234 253"},3000,function(){ var path2=paper.path("M234 253").attr({"stroke": "#f00","stroke-width":3}); path2.animate({path: "M234 253 L 234 134"},3000,function(){ var path3=paper.path("M234 134").attr({"stroke": "#f00","stroke-width":3}); path3.animate({path: "M234 134 L 97 134"},3000); }); }); </script> </head> <body> <div id="stroke"></div> </body> </html>

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  • GRID is not properly rendered in ExtJS 4 by using Store

    - by user548543
    Here is the Src code for HTML file <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4 /strict.dtd"> <html> <head> <title>MVC Architecture</title> <link rel="stylesheet" type="text/css" href="/bh/extjs/resources/css/ext-all.css" /> <script type="text/javascript" src="extjs/ext-debug.js"></script> <script type="text/javascript" src="Main.js"></script> </head> <body> </body> </html> File path: /bh/Main.js [Main File] Ext.require('Ext.container.Viewport'); Ext.application({ name: 'App', appFolder: 'app', controllers: ['UserController'], launch: function() { Ext.create('Ext.container.Viewport', { layout: 'border', items: [ { xtype: 'userList' } ] }); } }); File path: /app/controller/UserController.js [Controller] Ext.define('App.controller.UserController',{ extend: 'Ext.app.Controller', stores: ['UserStore'], models:['UserModel'], views:['user.UserList'], init: function() { this.getUserStoreStore().load(); } }); File path: /app/store/UserStore.js Ext.define('App.store.UserStore', { extend: 'Ext.data.Store', model: 'App.model.UserModel', proxy: { type: 'ajax', url: 'app/data/contact.json' } }); File path: /app/model/UserModel.js [Model] Ext.define('App.model.UserModel',{ extends:'Ext.data.Model', fields:[ {name: 'name', type: 'string'}, {name: 'age', type: 'string'}, {name: 'phone', type: 'string'}, {name: 'email', type: 'string'} ] }); File path: /app/view/UserList.js [View] Ext.define('App.view.user.UserList' ,{ extend: 'Ext.grid.Panel', alias:'widget.userList', title:'Contacts', region:'center', resizable:true, initComponent: function() { this.store = 'UserStore'; this.columns = [ {text: 'Name',flex:1,sortable: true,dataIndex: 'name'}, {text: 'Age',flex:1,sortable: true,dataIndex: 'age'}, {text: 'Phone',flex:1,sortable: true,dataIndex: 'phone'}, {text: 'Email',flex:1,sortable: true,dataIndex: 'email'} ]; this.callParent(arguments); } }); In fire bug it shows the JSON response as follows: [{ "name": "Aswini", "age": "32", "phone": "555-555-5555", "email": "[email protected]" }] Why the Data has not been displayed although I have a valid json response. Please help!!!

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  • Python logger dynamic filename

    - by sharjeel
    I want to configure my Python logger in such a way so that each instance of logger should log in a file having the same name as the name of the logger itself. e.g.: log_hm = logging.getLogger('healthmonitor') log_hm.info("Testing Log") # Should log to /some/path/healthmonitor.log log_sc = logging.getLogger('scripts') log_sc.debug("Testing Scripts") # Should log to /some/path/scripts.log log_cr = logging.getLogger('cron') log_cr.info("Testing cron") # Should log to /some/path/cron.log I want to keep it generic and dont want to hardcode all kind of logger names I can have. Is that possible?

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  • Re-factoring a CURL request to Ruby's RestClient

    - by user94154
    I'm having trouble translating this CURL request into Ruby using RestClient: system("curl --digest -u #{@user}:#{@pass} '#{@endpoint}/#{id}' --form image_file=@'#{path}' -X PUT") I keep getting 400 Bad Request errors. As far as I can tell, the request does get properly authenticated, but hangs up from the file upload part. Here are my best attempts, all of which get me those 400 errors: resource = RestClient::Resource.new "#{@endpoint}/#{id}", @user, @pass #attempt 1 resource.put :image_file => File.new(path, 'rb'), :content_type => 'image/jpg' #attempt 2 resource.put File.read(path), :content_type => 'image/jpg' #attempt 3 resource.put File.open(path) {|f| f.read}, :content_type => 'image/jpg'

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