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• Sharing the same file between different projects

  - by selsine

  Hi Everyone, For version control we currently use Visual Source Safe and are thinking of migrating to another version control system (SVN, Mercurial, Git). Currently we use Visual Source Safe's "Shared" file feature quite heavily. This allows us to share code between design and runtimes of a single product, and between multiple products as well. For example: **Product One** - Design Login.cpp Login.h Helper.cpp Helper.h - Runtime Login.cpp Login.h Helper.cpp Helper.h **Product Two** - Design Login.cpp Login.h - Launcher Login.cpp Login.h - Runtime Login.cpp Login.h In this example Login.cpp and Login.h contain common code that all of our projects need, Helper.cpp and Helper.h is only used in Product One. In Visual Source Safe they are shared between the specific projects, which means that whenever the files are updated in one project they are updated in any project they are shared with. This is a simple example but hopefully it explains why we use the shared feature: to reduce the amount of duplicated code and ensure that when a bug is fixed all projects automatically have access to the new fixed code. After researching alternatives to Visual Source Safe it seems that most version control systems do not have the idea of shared files, instead they seem to use the idea of sub repositories. (http://mercurial.selenic.com/wiki/subrepos http://svnbook.red-bean.com/en/1.0/ch07s03.html) My question (after all of that) is about what the best practices for achieving this are using other version control systems? Should we restructure our projects so that two copies of the files do not exist and an include directory is used instead? e.g. Product One Design Login.cpp Login.h Runtime Login.cpp Login.h Common Helper.cpp Helper.h This still leaves what to do with Login.cpp and Logon.h Should the shared files be moved to their own repository and then compiled into a lib or dll? This would make bug fixing more time consuming as the lib projects would have to be edited and then rebuilt. Should we use externals or sub repositories? Should we combine our projects (i.e. runtime, design, and launcher) into one large project? Any help would be appreciated. We have the feeling that our project design has evolved based on the tools that we used and now that we are thinking of switching tools it's difficult for us to see how we can best modify our practices. Or maybe we are the only people are there doing this...? Also, we use Visual Studio for all of our stuff. Thanks.

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• How do I disable the new invisible border feature (ruins Compiz' Grid plugin)?

  - by Ike

  A new feature was added recently that adds an invisible border around the windows to grab for resizing (although i thought the new resize grip solved any big issues). This annoys me because it destroys the usefulness of the grid plugin of compiz.. i'm not sure if the border is part of compiz or gnome, but i'd like to know how to disable it. i couldn't find any options in ccsm or the window settings in gnome. See the screenshot to see how much waste is caused. These windows should match up instead of having blank space surrounding all of them.

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• How to determine which cells in a grid intersect with a given triangle?

  - by Ray Dey

  I'm currently writing a 2D AI simulation, but I'm not completely certain how to check whether the position of an agent is within the field of view of another. Currently, my world partitioning is simple cell-space partitioning (a grid). I want to use a triangle to represent the field of view, but how can I calculate the cells that intersect with the triangle? Similar to this picture: The red areas are the cells I want to calculate, by checking whether the triangle intersects those cells. Thanks in advance. EDIT: Just to add to the confusion (or perhaps even make it easier). Each cell has a min and max vector where the min is the bottom left corner and the max is the top right corner.

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• After one has made many grid based puzzles how does one make then into a PDF ready for printing

  - by alan ross

  After one has generated many grid based puzzles like sudoku, kakuro or even plain crosswords and now one has to print them in a book. How does one make a pdf (book file) from them automatically. To explain the question better. One has the puzzle ready in computer format like ..35.6.89 for all nine rows. The dot being the empty cell. How does one convert then to a picture on a PDF page complete with box, automatically without doing them individually and then print a book from the pdf file. As can be seen there are other things also printed on the page all this is done automatically.

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• [Natty] Disable new invisible border feature? (ruins compiz grid)

  - by Ike

  a new "feature" was added recently that adds an invisible border around the windows to grab for resizing (although i thought the new resize grip solved any issues). this annoys me because it destroys the usefulness of the grid plugin of compiz.. i'm not sure if the border is part of compiz or gnome, but i'd like to know how to disable it. i couldn't find any options in ccsm or the window settings in gnome. see the screenshot to see how much waste is causes. these windows should match up instead of having blank space surrounding all of them.

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• Cannot see named Silverlight control in code

  - by Alexandra

  In my first few hours with Silverlight 3, as an avid WPF user, I am greatly disappointed at the many things it doesn't support. This seems like an odd issue to me and it's so generic that I cannot find anything online about it. I have the following XAML: <controls:TabControl x:Name="workspacesTabControl" Grid.Row="1" Background="AntiqueWhite" ItemsSource="{Binding Workspaces, ElementName=_root}"/> However, I cannot see the workspacesTabControl in code-behind. I thought maybe IntelliSense is just being mean and tried to go ahead and compile it anyway, but got an error: Error 1 The name 'workspacesTabControl' does not exist in the current context How do I access controls in code-behind? EDIT: I realized I've pasted the wrong error - I have two controls inside the UserControl called workspacesTabControl and menuStrip. I cannot get to either one of them by their name in the code-behind. Just in case, here is the XAML for the menuStrip: <controls:TreeView Grid.ColumnSpan="2" Height="100" x:Name="menuStrip" ItemContainerStyle="{StaticResource MenuStripStyle}" ItemsSource="{Binding Menu, ElementName=_root}"/> EDIT AGAIN: I'm not sure if this is helpful, but I've taken a look at the InitializeComponent() code and here's what I saw: [System.Diagnostics.DebuggerNonUserCodeAttribute()] public void InitializeComponent() { if (_contentLoaded) { return; } _contentLoaded = true; System.Windows.Application.LoadComponent(this, new System.Uri("/SapphireApplication;component/SapphireMain.xaml", System.UriKind.Relative)); } It seems that it simply loads the XAML when it runs (not before or during compilation) so the menuStrip and workspacesTabControl names don't actually get registered anywhere (as they usually are in WPF/win Forms). Could that attribute be a problem? And where do I get rid of this requirement for all the future UserControls I make?

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• Dojo DataGrid, programmatic creation

  - by djna

  I'm trying to create a DataGrid dynamically. Declarative creation is working fine: A source of data: <span dojoType="dojo.data.ItemFileReadStore" jsId="theStore" url="dataonly001.json"> </span> a simple layout: <script type="text/javascript" > var layout = [ { field: 'custId', name: 'Id', } // more items elided ... ]; </script> The grid: <body class="tundra" id="mainbody"> <div id="grid" dojoType="dojox.grid.DataGrid" store="theStore" structure="layout" autoWidth="true" ></div> </body> And I get the grid displayed nicely. Instead, I want to create the grid dynamically. For the sake of figuring out what's broken I've tried to use exactly the same layout and store, removing just teh grid declaration and adding this script: <script type="text/javascript" djConfig="parseOnLoad: true, debugAtAllCosts: true"> dojo.addOnLoad(function(){ // initialise and lay out home page console.log("Have a store:" + theStore); console.log("Have a structure:" + layout); var grid = new dojox.grid.DataGrid({ id:"grid", store : theStore, clientSort : "true", structure : layout }); grid.startup(); dojo.place(grid.domNode, dojo.body(), "first"); }); </script> The effect that I get is a completely empty rectangle is displayed. Using FireBug I can see that the DataGrid widget is created but that it has no rows or columns. So my guess is that the datastore or layout are not being passed correctly. However, it does appear that at the point of creation the values of theStore and layout are correct. Suggestions please, or indeed a working example of a programmic grid might solve the problem.

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• Setting CommandTarget to selected control in a TabControl

  - by Bart

  I have a WPF window with a few buttons and a tabcontrol having a tab for each 'document' the user is working on. The tabcontrol uses a DataTemplate to render the data in ItemSource of the tabcontrol. The question: If one of the buttons is clicked, the command should be executed on the control rendering the document in the active tab, but I've no idea what I should set CommandTarget to. I tried {Binding ElementName=nameOfControlInDataTemplate} but that obviously doesn't work. I tried to make my problem a bit more abstract with the following code (no ItemSource and Document objects, but the idea is still the same). <Button Command="ApplicationCommands.Save" CommandTarget="{Binding ElementName=nestedControl}">Save</Button> <TabControl x:Name="tabControl"> <TabControl.Items> <TabItem Header="Header1">Item 1</TabItem> <TabItem Header="Header2">Item 2</TabItem> <TabItem Header="Header3">Item 3</TabItem> </TabControl.Items> <TabControl.ContentTemplate> <DataTemplate> <CommandTest:NestedControl Name="nestedControl"/> </DataTemplate> </TabControl.ContentTemplate> </TabControl> I tested the code by replacing the complete tabcontrol with only one single NestedControl, and then the command button just works. To be complete, here is the code of NestedControl: <UserControl x:Class="CommandTest.NestedControl" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"> <Grid> <Label x:Name="label" Content="Not saved"/> </Grid> </UserControl> And code behind: public partial class NestedControl : UserControl { public NestedControl() { CommandBindings.Add(new CommandBinding(ApplicationCommands.Save, CommandBinding_Executed)); InitializeComponent(); } private void CommandBinding_Executed(object sender, ExecutedRoutedEventArgs e) { label.Content = "Saved"; } }

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• Binding DataTemplates (or another aproach)

  - by Bataglião

  Hi all, I'm having some troubles trying to dynamically generate content in WPF and after it bind data. I have the following scenario: TabControl - Dynamically generated TabItems through DataTemplate - inside TabItems, I have dynamic content generated by DataTemplate that I wish to bind (ListBox). The code follows: ::TabControl <TabControl Height="252" HorizontalAlignment="Left" Name="tabControl1" VerticalAlignment="Top" Width="458" Margin="12,12,12,12" ContentTemplate="{StaticResource tabItemContent}"></TabControl> ::The Template for TabControl to generate TabItems <DataTemplate x:Key="tabItemContent"> <Grid> <Grid.ColumnDefinitions> <ColumnDefinition Width="*" /> </Grid.ColumnDefinitions> <Grid.RowDefinitions> <RowDefinition Height="*" /> </Grid.RowDefinitions> <ListBox ItemTemplate="{StaticResource listBoxContent}" ItemsSource="{Binding}"> </ListBox> </Grid> </DataTemplate> ::The template for ListBox Inside each TabItem <DataTemplate x:Key="listBoxContent"> <Grid> <Grid.ColumnDefinitions> <ColumnDefinition Width="22"/> <ColumnDefinition Width="*" /> </Grid.ColumnDefinitions> <Image Grid.Column="0" Source="{Binding Path=PluginIcon}" /> <TextBlock Grid.Column="1" Text="{Binding Path=Text}" /> </Grid> </DataTemplate> So, when I try to do this on code inside a loop to create the tabitems: TabItem tabitem = tabControl1.Items[catIndex] as TabItem; tabitem.DataContext = plugins.ToList(); where 'plugins' is an Enumerable The ListBox is not bounded. I tried also to find the ListBox inside the TabItem to set the ItemSource property but no success at all. Someone have an idea on how to do that? Thanks in advance.

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• how to access control in templatefield gridview with custom id

  - by Mohsen.Tavoosi

  i have a customized gridview.my grid is able to sort for each column just by 1 click in the header without any setting and overloading methods such as sorting,etc by user(programmer).(i do this successfully and work fine) users(programmers) maybe add each column in grid.such as template field,hyperlinkfield,boundfield... . for sorting, i must access datafield of columns. i can access boundfield column by this code.i can access datafield and header text and ... sample: for (int j = 0; j < this.Columns.Count; j++) { BoundField bf; bf = this.Columns[j] as BoundField; if (bf != null) { string ht = bf.HeaderText; string df = bf.DataField; } } but i can access control in the templateField.such as ColumnBound. sample: <asp:Label ID="Label1" runat="server" Text='<%# Bind("Name") %>'></asp:Label> i want access "Name" (Bind ("Name") or Eval ("Name")) . how can i? there is a point: i dont now what is the ID (in this case "Label1") of control in templatefield. special thanks

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• ASP.Net Problem with Event Handlers and Control Creation Timing

  - by Oliver Weichhold

  What I am trying to achieve here is to display a number of LinkButtons in a RadGrid Column. The buttons are generated from a collection property member of the bound grid row item. The CollectionLinkButton control is nothing more than a asp:Panel derived control that populates its Child Controls from "DataItem.SomeCollection" and this is working fine. The problem I am facing is with this part: Collection='<%# DataBinder.Eval(Container, "DataItem.SomeCollection") %' This is because databound Collection Property is populated so late in the lifecycle of the page that the LinkButton Controls that the CollectionLinkButton class creates from the collection are not available yet during Postback when the Click event Handler is supposed to fire and I have currently no idea how to solve this problem. <radG:RadGrid ID="grid" runat="server" DataSourceID="ds_AB"> <MasterTableView> <Columns> <radG:GridTemplateColumn> <ItemTemplate> <local:CollectionLinkButton ID="LinkButton1" runat="server" CssClass="EntityLinkButton" Collection='<%# DataBinder.Eval(Container, "DataItem.SomeCollection") %>' CollectionProperty="Id" CollectionDisplayProperty="Name" Text='<%# DataBinder.Eval(Container, "DataItem.Name") %>'</local:CollectionLinkButton> </ItemTemplate> </radG:GridTemplateColumn>

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• how to display user name in login name control

  - by user569285

  I have a master page that holds the loginview content that appears on all subsequent pages based on the master page. i have a username control also nested in the loginview to display the name of the user when they are logged in. the code for the loginview from the master page is displayed as follows: <div class="loginView"> <asp:LoginView ID="MasterLoginView" runat="server"> <LoggedInTemplate> Welcome <span class="bold"><asp:LoginName ID="HeadLoginName" runat="server" /> <asp:Label ID="userNameLabel" runat="server" Text="Label"></asp:Label></span>! [ <asp:LoginStatus ID="HeadLoginStatus" runat="server" LogoutAction="Redirect" LogoutText="Log Out" LogoutPageUrl="~/Logout.aspx"/> ] <%--Welcome: <span class="bold"><asp:LoginName ID="MasterLoginName" runat="server" /> </span>!--%> </LoggedInTemplate> <AnonymousTemplate> Welcome: Guest [ <a href="~/Account/Login.aspx" ID="HeadLoginStatus" runat="server">Log In</a> ] </AnonymousTemplate> </asp:LoginView> <%--&nbsp;&nbsp; [&nbsp;<asp:LoginStatus ID="MasterLoginStatus" runat="server" LogoutAction="Redirect" LogoutPageUrl="~/Logout.aspx" />&nbsp;]&nbsp;&nbsp;--%> </div> Since VS2010 launches with a default login page in the accounts folder, i didnt think it necessary to create a separate log in page, so i just used the same log in page. please find the code for the login control below: <asp:Login ID="LoginUser" runat="server" EnableViewState="false" RenderOuterTable="false"> <LayoutTemplate> <span class="failureNotification"> <asp:Literal ID="FailureText" runat="server"></asp:Literal> </span> <asp:ValidationSummary ID="LoginUserValidationSummary" runat="server" CssClass="failureNotification" ValidationGroup="LoginUserValidationGroup"/> <div class="accountInfo"> <fieldset class="login"> <legend style="text-align:left; font-size:1.2em; color:White;">Account Information</legend> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="UserNameLabel" runat="server" AssociatedControlID="UserName">User ID:</asp:Label> <asp:TextBox ID="UserName" runat="server" CssClass="textEntry"></asp:TextBox> <asp:RequiredFieldValidator ID="UserNameRequired" runat="server" ControlToValidate="UserName" CssClass="failureNotification" ErrorMessage="User ID is required." ToolTip="User ID field is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="PasswordLabel" runat="server" AssociatedControlID="Password">Password:</asp:Label> <asp:TextBox ID="Password" runat="server" CssClass="passwordEntry" TextMode="Password"></asp:TextBox> <asp:RequiredFieldValidator ID="PasswordRequired" runat="server" ControlToValidate="Password" CssClass="failureNotification" ErrorMessage="Password is required." ToolTip="Password is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:CheckBox ID="RememberMe" runat="server"/> <asp:Label ID="RememberMeLabel" runat="server" AssociatedControlID="RememberMe" CssClass="inline">Keep me logged in</asp:Label> </p> </fieldset> <p class="submitButton"> <asp:Button ID="LoginButton" runat="server" CommandName="Login" Text="Log In" ValidationGroup="LoginUserValidationGroup" onclick="LoginButton_Click"/> </p> </div> </LayoutTemplate> </asp:Login> I then wrote my own code for authentication since i had my own database. the following displays the code in the login buttons click event.: public partial class Login : System.Web.UI.Page { //create string objects string userIDStr, pwrdStr; protected void LoginButton_Click(object sender, EventArgs e) { //assign textbox items to string objects userIDStr = LoginUser.UserName.ToString(); pwrdStr = LoginUser.Password.ToString(); //SQL connection string string strConn; strConn = WebConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ConnectionString; SqlConnection Conn = new SqlConnection(strConn); //SqlDataSource CSMDataSource = new SqlDataSource(); // CSMDataSource.ConnectionString = ConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ToString(); //SQL select statement for comparison string sqlUserData; sqlUserData = "SELECT StaffID, StaffPassword, StaffFName, StaffLName, StaffType FROM Staffs"; sqlUserData += " WHERE (StaffID ='" + userIDStr + "')"; sqlUserData += " AND (StaffPassword ='" + pwrdStr + "')"; SqlCommand com = new SqlCommand(sqlUserData, Conn); SqlDataReader rdr; string usrdesc; string lname; string fname; string staffname; try { //string CurrentData; //CurrentData = (string)com.ExecuteScalar(); Conn.Open(); rdr = com.ExecuteReader(); rdr.Read(); usrdesc = (string)rdr["StaffType"]; fname = (string)rdr["StaffFName"]; lname = (string)rdr["StaffLName"]; staffname = lname.ToString() + " " + fname.ToString(); LoginUser.UserName = staffname.ToString(); rdr.Close(); if (usrdesc.ToLower() == "administrator") { Response.Redirect("~/CaseAdmin.aspx", false); } else if (usrdesc.ToLower() == "manager") { Response.Redirect("~/CaseManager.aspx", false); } else if (usrdesc.ToLower() == "investigator") { Response.Redirect("~/Investigator.aspx", false); } else { Response.Redirect("~/Default.aspx", false); } } catch(Exception ex) { string script = "<script>alert('" + ex.Message + "');</script>"; } finally { Conn.Close(); } } My authentication works perfectly and the page gets redirected to the designated destination. However, the login view does not display the users name. i actually cant figure out how to pass the users name that i had picked from the database to the login name control to be displayed. taking a close look i also noticed the logout text that should be displayed after successful log in does not show. that leaves me wondering if the loggedin template control on the masterpage even fires at all or its still the anonymous template control that keeps displaying.? How do i get this to work as expected? Please help....

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• Binding between Usercontrol with listbox and parent control (MVVM)

  - by walkor

  I have a UserControl which contains a listbox and few buttons. <UserControl x:Class="ItemControls.ListBoxControl" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"> <Grid> <ListBox:ExtendedListBox SelectionMode="Single" ItemsSource="{Binding LBItems}" Height="184"> <ListBox.ItemTemplate> <DataTemplate> <CheckBox Content="{Binding}"/> </DataTemplate> </ListBox.ItemTemplate> </ListBox> <Button Command="RemoveCommand"/> </Grid> </UserControl> And the code behind: public static readonly DependencyProperty RemoveCommandProperty = DependencyProperty.Register("RemoveCommand", typeof(ICommand), typeof(ListBoxControl), null); public ICommand RemoveCommand { get { return (ICommand)GetValue(RemoveCommandProperty); } set { SetValue(RemoveCommandProperty, value); } } public static readonly DependencyProperty LBItemsProperty = DependencyProperty.Register("LBItems", typeof(IEnumerable), typeof(ListBoxControl), null); public IEnumerable LBItems { get { return (IEnumerable)GetValue(LBItemsProperty); } set { SetValue(LBItemsProperty, value); } } I'm using this control in the view like this: <ItemControls:ListBoxControl Height="240" Width="350" LBItems="{Binding Items, Converter={StaticResource ItemsConverter}, Mode=TwoWay}" RemoveCommand="{Binding RemoveCommand}"/> The command works fine, though the listbox binding doesn't. My question is - WHY?

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• How can I use a parent content control from a sub binding?

  - by MGSoto

  I have the following code currently: <DataTemplate DataType="{x:Type vm:SectionViewModel}"> <ScrollViewer> <ItemsControl ItemsSource="{Binding ViewModels}"> <Grid/> </ItemsControl> </ScrollViewer> </DataTemplate> <DataTemplate DataType="{x:Type vm:StringViewModel}"> <Label Name="Left" Grid.Row="0" Grid.Column="0" Content="{Binding Label}"/> <TextBox Name="Right" HorizontalAlignment="Stretch" Grid.Row="0" Grid.Column="1" Text="{Binding Value}"/> </DataTemplate> The ViewModels property bound to SectionViewModel ItemsControl is a list of StringViewModel. I want to insert each StringViewModel into some sort of content control in the ItemsControl. Originally I just had each StringViewModel to make its own Grid, but that left things unaligned. I'd like to insert these items into some sort of content control in ItemsControl, it doesn't necessarily have to be a grid, but it should be within the ItemsControl. How can I do this? I'm also following MVVM, using MVVM Light.

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• Disable a control inside a gridview

  - by saeed talaee

  Hi i want to disable link-bottoms control in a grid view with the condition of a special value . for example if the count for a row become 0 ,the link bottom for that row should be invisible . what should i do? where should i write the code? here is cod that i write in row command grid view but it works only of i push the link bottom!! but i want to apply this cod to my page before loading. please guide me int idx = Convert.ToInt32(e.CommandArgument); idx = idx - (GridView1.PageSize * GridView1.PageIndex); int ID = (int)GridView1.DataKeys[idx].Value; string connStr = ConfigurationManager.ConnectionStrings["dbconn"].ConnectionString; SqlConnection sqlconn = new SqlConnection(connStr); SqlCommand sqlcmd = new SqlCommand(); sqlcmd = new SqlCommand("SELECT count(ID) FROM ReviwerArticle where ArticleID=@ArticleID", sqlconn); sqlcmd.Parameters.AddWithValue("@ArticleID", ID); sqlconn.Open(); int count = ((int)sqlcmd.ExecuteScalar()); sqlconn.Close(); if (count == 0) { ((LinkButton)GridView1.Rows[idx].Cells[0].FindControl("LinkButton4") as LinkButton).Visible = false; }

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• Weird exception in linkbutton in a datalist

  - by user308806

  Dear all, I have written this datalist : <div class="story" runat="server"> <asp:DataList ID="DataList2" runat="server" Height="16px" Width="412px"> <SeparatorTemplate> <hr /> </SeparatorTemplate> <ItemTemplate> <asp:LinkButton ID="LinkButton1" runat ="server" Text='<%# Eval("Name") %>' PostBackUrl='<%#Eval("Url")%>' /> <br /> Description: <asp:Label ID="new" Text='<%#Eval("Description") %>' runat="server" /> </ItemTemplate> </asp:DataList> </div> It raises an exception saying that the linkbutton has to be placed in a tag that contains runat="server" although it exists. Here is the trace [HttpException (0x80004005): Le contrôle 'DataList2_ctl00_LinkButton1' de type 'LinkButton' doit être placé dans une balise form avec runat=server.] System.Web.UI.Page.VerifyRenderingInServerForm(Control control) +8689747 System.Web.UI.WebControls.LinkButton.AddAttributesToRender(HtmlTextWriter writer) +39 System.Web.UI.WebControls.WebControl.RenderBeginTag(HtmlTextWriter writer) +20 System.Web.UI.WebControls.WebControl.Render(HtmlTextWriter writer) +20 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +99 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +25 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +134 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +19 System.Web.UI.WebControls.WebControl.RenderContents(HtmlTextWriter writer) +10 System.Web.UI.WebControls.DataListItem.RenderItemInternal(HtmlTextWriter writer, Boolean extractRows, Boolean tableLayout) +51 System.Web.UI.WebControls.DataListItem.RenderItem(HtmlTextWriter writer, Boolean extractRows, Boolean tableLayout) +57 System.Web.UI.WebControls.DataList.System.Web.UI.WebControls.IRepeatInfoUser.RenderItem(ListItemType itemType, Int32 repeatIndex, RepeatInfo repeatInfo, HtmlTextWriter writer) +64 System.Web.UI.WebControls.RepeatInfo.RenderVerticalRepeater(HtmlTextWriter writer, IRepeatInfoUser user, Style controlStyle, WebControl baseControl) +262 System.Web.UI.WebControls.RepeatInfo.RenderRepeater(HtmlTextWriter writer, IRepeatInfoUser user, Style controlStyle, WebControl baseControl) +27 System.Web.UI.WebControls.DataList.RenderContents(HtmlTextWriter writer) +208 System.Web.UI.WebControls.BaseDataList.Render(HtmlTextWriter writer) +30 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +99 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +25 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +134 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +19 System.Web.UI.HtmlControls.HtmlContainerControl.Render(HtmlTextWriter writer) +32 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +99 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +25 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +134 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +19 System.Web.UI.Page.Render(HtmlTextWriter writer) +29 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +99 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +25 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +1266

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• What are the runtime debuggers available in AIX? for the C language?

  - by debugger

  What are the runtime debuggers available in AIX? for the C language? I know we have dbx - Crap gdb - Good but doesnt work. Any other?

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• WebLogic 12c hands-on bootcamps for partners – free of charge

  - by JuergenKress

  For all WebLogic Partner Community members we offer our WebLogic 12c hands-on Bootcamps – free of charge! If you want to become an Application Grid Specialized: Register Here! Country Date Location Registration Germany 3-5 April 2012 Oracle Düsseldorf Click here France 24-26 April 2012 Oracle Colombes Click here Spain 08-10 May 2012 Oracle Madrid Click here Netherlands 22-24 May 2012 Oracle Amsterdam Click here United Kingdom 06-08 June 2012 Oracle Reading Click here Italy 19-21 June 2012 Oracle Cinisello Balsamo Click here Portugal 10-12 July 2012 Oracle Lisbon Click here Skill requirements Attendees need to have the following skills as this is required by the product-set and to make sure they get the most out of the training: Basic knowledge in Java and JavaEE Understanding the Application Server concept Basic knowledge in older releases of WebLogic Server would be beneficial Member of WebLogic Partner Community for registration please vist http://www.oracle.com/partners/goto/wls-emea Hardware requirements Every participant works on his own notebook. The minimal hardware requirements are: 4Gb physical RAM (we will boot the image with 2Gb RAM) dual core CPU 15 GB HD Software requirements Please install Oracle VM VirtualBox 4.1.8 Follow-up and certification With the workshop registration you agree to the following next steps Follow-up training attend and pass the Oracle Application Grid Certified Implementation Specialist Registration For details and registration please visit Register Here Free WebLogic Certification (Free assessment voucher to become certified) For all WebLogic experts, we offer free vouchers worth $195 for the Oracle Application Grid Certified Implementation Specialist assessment. To demonstrate your WebLogic knowledge you first have to pass the free online assessment Oracle Application Grid PreSales Specialist. For free vouchers, please send an e-mail with the screenshot of your Oracle Application Grid PreSales certirficate to [email protected] including your Name, Company, E-mail and Country. Note: This offer is limited to partners from Europe Middle East and Africa. Partners from other countries please contact your Oracle partner manager. WebLogic Specialization To become specialized in Application Grid, please make sure that you access the: Application Grid Specialization Guide Application Grid Specialization Checklist If you have any questions please contact the Oracle Partner Business Center. WebLogic Partner Community For regular information become a member in the WebLogic Partner Community please visit: http://www.oracle.com/partners/goto/wls-emea ( OPN account required). If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Mix Forum Wiki Technorati Tags: WebLogic training,Java training,WebLogic 12c,WebLogic Community,OPN,WebLogic,Oracle,WebLogic Certification,Apps Grid Certification,Implementation Specialist,Apps Grid Specialist,Oracle education

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• Tomcat 6: Access Control Exception?

  - by iftrue

  I'm trying to setup a tomcat6 server, and I'm trying to match another setup someone else established. However, my deployment (default Ubuntu install) uses a policy.d/ directory structure, and the established server just uses a catalina.policy file. I've tried setting every entry in policy.d to match the given catalina.policy, but I still get the following stacktrace on boot (from localhost log). I have two questions, then. First, how do I get tomcat to use a single poilcy file, rather than the directory structure presented by policy.d/? Secondly, why, when I specify all files to use the same policy, do I still get the stack trace below? Stack trace: SEVERE: Servlet /myapp threw load() exception java.security.AccessControlException: access denied (java.lang.RuntimePermission accessClassInPackage.org.apache.jasper) at java.security.AccessControlContext.checkPermission(AccessControlContext.java:342) at java.security.AccessController.checkPermission(AccessController.java:553) at java.lang.SecurityManager.checkPermission(SecurityManager.java:549) at java.lang.SecurityManager.checkPackageAccess(SecurityManager.java:1529) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:291) at java.lang.ClassLoader.loadClass(ClassLoader.java:264) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1314) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1245) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:332) at org.apache.jasper.servlet.JspServlet.init(JspServlet.java:100) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at org.apache.catalina.security.SecurityUtil$1.run(SecurityUtil.java:244) at java.security.AccessController.doPrivileged(Native Method) at javax.security.auth.Subject.doAsPrivileged(Subject.java:537) at org.apache.catalina.security.SecurityUtil.execute(SecurityUtil.java:276) at org.apache.catalina.security.SecurityUtil.doAsPrivilege(SecurityUtil.java:162) at org.apache.catalina.security.SecurityUtil.doAsPrivilege(SecurityUtil.java:115) at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1166) at org.apache.catalina.core.StandardWrapper.load(StandardWrapper.java:992) at org.apache.catalina.core.StandardContext.loadOnStartup(StandardContext.java:4058) at org.apache.catalina.core.StandardContext.start(StandardContext.java:4367) at org.apache.catalina.core.ContainerBase.addChildInternal(ContainerBase.java:791) at org.apache.catalina.core.ContainerBase.access$000(ContainerBase.java:123) at org.apache.catalina.core.ContainerBase$PrivilegedAddChild.run(ContainerBase.java:145) at java.security.AccessController.doPrivileged(Native Method) at org.apache.catalina.core.ContainerBase.addChild(ContainerBase.java:769) at org.apache.catalina.core.StandardHost.addChild(StandardHost.java:525) at org.apache.catalina.startup.HostConfig.deployDirectory(HostConfig.java:978) at org.apache.catalina.startup.HostConfig.deployDirectories(HostConfig.java:941) at org.apache.catalina.startup.HostConfig.deployApps(HostConfig.java:499) at org.apache.catalina.startup.HostConfig.start(HostConfig.java:1201) at org.apache.catalina.startup.HostConfig.lifecycleEvent(HostConfig.java:318) at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(LifecycleSupport.java:117) at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1053) at org.apache.catalina.core.StandardHost.start(StandardHost.java:719) at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045) at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:443) at org.apache.catalina.core.StandardService.start(StandardService.java:516) at org.apache.catalina.core.StandardServer.start(StandardServer.java:710) at org.apache.catalina.startup.Catalina.start(Catalina.java:578) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:288) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at org.apache.commons.daemon.support.DaemonLoader.start(DaemonLoader.java:177) Policy.d grant codeBase "file:${java.home}/lib/-" { permission java.security.AllPermission; }; // These permissions apply to all shared system extensions grant codeBase "file:${java.home}/jre/lib/ext/-" { permission java.security.AllPermission; }; // These permissions apply to javac when ${java.home] points at $JAVA_HOME/jre grant codeBase "file:${java.home}/../lib/-" { permission java.security.AllPermission; }; // These permissions apply to all shared system extensions when // ${java.home} points at $JAVA_HOME/jre grant codeBase "file:${java.home}/lib/ext/-" { permission java.security.AllPermission; }; // ========== CATALINA CODE PERMISSIONS ======================================= // These permissions apply to the daemon code grant codeBase "file:${catalina.home}/bin/commons-daemon.jar" { permission java.security.AllPermission; }; // These permissions apply to the logging API grant codeBase "file:${catalina.home}/bin/tomcat-juli.jar" { permission java.util.PropertyPermission "java.util.logging.config.class", "read"; permission java.util.PropertyPermission "java.util.logging.config.file", "read"; permission java.io.FilePermission "${java.home}${file.separator}lib${file.separator}logging.properties", "read"; permission java.lang.RuntimePermission "shutdownHooks"; permission java.io.FilePermission "${catalina.base}${file.separator}conf${file.separator}logging.properties", "read"; permission java.util.PropertyPermission "catalina.base", "read"; permission java.util.logging.LoggingPermission "control"; permission java.io.FilePermission "${catalina.base}${file.separator}logs", "read, write"; permission java.io.FilePermission "${catalina.base}${file.separator}logs${file.separator}*", "read, write"; permission java.lang.RuntimePermission "getClassLoader"; // To enable per context logging configuration, permit read access to the appropriate file. // Be sure that the logging configuration is secure before enabling such access // eg for the examples web application: // permission java.io.FilePermission "${catalina.base}${file.separator}webapps${file.separator}examples${file.separator}WEB-INF${file.separator}classes${file.separator}logging.properties", "read"; }; // These permissions apply to the server startup code grant codeBase "file:${catalina.home}/bin/bootstrap.jar" { permission java.security.AllPermission; }; // These permissions apply to the servlet API classes // and those that are shared across all class loaders // located in the "lib" directory grant codeBase "file:${catalina.home}/lib/-" { permission java.security.AllPermission; }; // ========== WEB APPLICATION PERMISSIONS ===================================== // These permissions are granted by default to all web applications // In addition, a web application will be given a read FilePermission // and JndiPermission for all files and directories in its document root. grant { // Required for JNDI lookup of named JDBC DataSource's and // javamail named MimePart DataSource used to send mail permission java.util.PropertyPermission "java.home", "read"; permission java.util.PropertyPermission "java.naming.*", "read"; permission java.util.PropertyPermission "javax.sql.*", "read"; // OS Specific properties to allow read access permission java.util.PropertyPermission "os.name", "read"; permission java.util.PropertyPermission "os.version", "read"; permission java.util.PropertyPermission "os.arch", "read"; permission java.util.PropertyPermission "file.separator", "read"; permission java.util.PropertyPermission "path.separator", "read"; permission java.util.PropertyPermission "line.separator", "read"; // JVM properties to allow read access permission java.util.PropertyPermission "java.version", "read"; permission java.util.PropertyPermission "java.vendor", "read"; permission java.util.PropertyPermission "java.vendor.url", "read"; permission java.util.PropertyPermission "java.class.version", "read"; permission java.util.PropertyPermission "java.specification.version", "read"; permission java.util.PropertyPermission "java.specification.vendor", "read"; permission java.util.PropertyPermission "java.specification.name", "read"; permission java.util.PropertyPermission "java.vm.specification.version", "read"; permission java.util.PropertyPermission "java.vm.specification.vendor", "read"; permission java.util.PropertyPermission "java.vm.specification.name", "read"; permission java.util.PropertyPermission "java.vm.version", "read"; permission java.util.PropertyPermission "java.vm.vendor", "read"; permission java.util.PropertyPermission "java.vm.name", "read"; // Required for OpenJMX permission java.lang.RuntimePermission "getAttribute"; // Allow read of JAXP compliant XML parser debug permission java.util.PropertyPermission "jaxp.debug", "read"; // Precompiled JSPs need access to this package. permission java.lang.RuntimePermission "accessClassInPackage.org.apache.jasper.runtime"; permission java.lang.RuntimePermission "accessClassInPackage.org.apache.jasper.runtime.*"; // Precompiled JSPs need access to this system property. permission java.util.PropertyPermission "org.apache.jasper.runtime.BodyContentImpl.LIMIT_BUFFER", "read"; };

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• Implement QoS/Bandwidth Management or Upgrade Bandwidth?

  - by Michael

  A question that I'm faced with currently. Here's my setup: Cisco ASA 5510 15Mbps Internet Connection @ $1350/month The bandwidth was originally meant for 35-45 people but we've grown quite quickly to roughly 60-65 people. Needless to say, when I check bandwidth logs it's almost always spiked at 15Mbps. I did use Wireshark to do some poking around to see what was hogging up our bandwidth but with everything running through CDNs and Cloud Services it proved difficult to get a good grasp of where our bandwidth was going. So the question is do I ONLY implement bandwidth management through ASA OR upgrade the Internet to 50Mbps ($1600/month) and then implement bandwidth management through ASA? Any suggestions on how to segment the 15Mbps connection if we decided ONLY to go with the bandwidth management solution? Thanks. UPDATE 1 Installed PRTG and used packet content to monitor the traffic. As I suspected still pretty vague. My Top Connections include the following: a204-2-160-16.deploy.akamaitechnologies.com ec2-50-16-212-159.compute-1.amazonaws.com a204-2-160-48.deploy.akamaitechnologies.com a72-247-247-133.deploy.akamaitechnologies.com mediaserver-sv5-t1-1.pandora.com Other than the Pandora destination, the rest doesn't tell me much on how to properly control the bandwidth. Any thoughts or suggestions? Thanks. M

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• Limiting bandwidth on internal interface on Linux gateway

  - by Jack Scott

  I am responsible for a Linux-based (it runs Debian) branch office router that takes a single high-speed Internet connection (eth2) and turns it into about 20 internal networks, each with a seperate subnet (192.168.1.0/24 to 192.168.20.0/24) and a seperate VLAN (eth0.101 to eth0.120). I am trying to restrict bandwidth on one of the internal subnets that is consistently chewing up more bandwidth than it should. What is the best way to do this? My first try at this was with wondershaper, which I heard about on SuperUser here. Unfortunately, this is useful for exactly the opposite situation that I have... it's useful on the client side, not on the Internet side. My second attempt was using the script found at http://www.topwebhosts.org/tools/traffic-control.php, which I modified so the active part is: tc qdisc add dev eth0.113 root handle 13: htb default 100 tc class add dev eth0.113 parent 13: classid 13:1 htb rate 3mbps tc class add dev eth0.113 parent 13: classid 13:2 htb rate 3mbps tc filter add dev eth0.113 protocol ip parent 13:0 prio 1 u32 match ip dst 192.168.13.0/24 flowid 13:1 tc filter add dev eth0.113 protocol ip parent 13:0 prio 1 u32 match ip src 192.168.13.0/24 flowid 13:2 What I want this to do is restrict the bandwidth on VLAN 113 (subnet 192.168.13.0/24) to 3mbit up and 3mbit down. Unfortunately, it seems to have no effect at all! I'm very inexperienced with the tc command, so any help getting this working would be appreciated.

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• Is Windows Server 2008R2 NAP solution for NAC (endpoint security) valuable enough to be worth the hassles?

  - by Warren P

  I'm learning about Windows Server 2008 R2's NAP features. I understand what network access control (NAC) is and what role NAP plays in that, but I would like to know what limitations and problems it has, that people wish they knew before they rolled it out. Secondly, I'd like to know if anyone has had success rolling it out in a mid-size (multi-city corporate network with around 15 servers, 200 desktops) environment with most (99%) Windows XP SP3 and newer Windows clients (Vista, and Win7). Did it work with your anti-virus? (I'm guessing NAP works well with the big name anti-virus products, but we're using Trend micro.). Let's assume that the servers are all Windows Server 2008 R2. Our VPNs are cisco stuff, and have their own NAC features. Has NAP actually benefitted your organization, and was it wise to roll it out, or is it yet another in the long list of things that Windows Server 2008 R2 does, but that if you do move your servers up to it, you're probably not going to want to use. In what particular ways might the built-in NAP solution be the best one, and in what particular ways might no solution at all (the status quo pre-NAP) or a third-party endpoint security or NAC solution be considered a better fit? I found an article where a panel of security experts in 2007 say NAC is maybe "not worth it". Are things better now in 2010 with Win Server 2008 R2?

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• How to install subversion on 1&1 server with windows?

  - by Miles M.

  I would like to start using Unfuddle for my project on 1&1 server. I never used subversion and core control before. So, I read a lot of documentation about it but each time, I get lost at the very beginning : I've downloaded the latest version of subversion. But on every tutorial, the way to follow is different. First I sae, on a lot of tuts, that you have to enter command lines. Is that ONLY for Linux ? Like here : http://chwalisz.org/2007/08/05/subversion-on-11-shared-hosting/ I also find something completely different on some website, I think (correct me if I'm wrong) it is the Windows tuts, deeply different frm the linu one. So I found that : http://www.codinghorror.com/blog/2008/04/setting-up-subversion-on-windows.html http://geekswithblogs.net/emanish/archive/2006/06/14/81905.aspx http://better-scm.shlomifish.org/subversion/Svn-Win32-Inst-Guide.html And I don t understand : Do I still have to put the sibversion file on the server ? Do I have to install Apach ? where, on my computer or on my server ? I'm working ith WampServer so I thing I have already Apach installed right ? When they say it is for Windows, do they mean it is for windows servers or for your own OS ? 'Cause my servers are on linux. How could I install Subversion on a 1&1 linux server from my W7 OS computer ? Thanks, that's a lot of question but that realle messy in my mind, I can't find something clear ..

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• Remote desktop type software that the client need not install anything...

  - by allentown

  I am primarily a Macintosh user, and can usually walk a client though any troubles they may have because I have a Macintosh in front of me. If they are on a different OS, things are close enough, or I cam remember, that I can get by. When trying to help clients on Windows, I get stuck. I do not have access to windows, and even if I did, there are far too many versions of Outlook, all with their various esoteric settings and checkboxes, that I could never see exactly what they are seeing. I mostly need to just help them with email setup. Something like copilot.com may do the trick. What is the simplest remote control software out there, ideally, it would accomplish these: No software needed on remote end, or, a single .exe that they can toss when done. I need Mac based software on my end. I do have ARD, which support VNC Free :) If possible, it would be really nice Needs a port forwarding proxy run by the company. There is no way I can get the user to alter their router, or to even plug directly into their WAN for a short time. On the Mac, I just have them open iChat, and this is all built in, proxying through AIM, looking for the same for Windows and Mac.

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• Controlling clone access to multiple mercurial repos served via hgwebdir.cgi

  - by chrislawlor

  I'm trying to host multiple hg repositories to use for my clients. I need to control access to each repository individually - not just push access, but clone as well. I've got an .htaccess set which requires authentication globally: AuthUserFile /path/to/hgweb.passwd AuthGroupFile /dev/null AuthName "Chris Lawlor Client Mercurial Repositories" AuthType Basic <Limit GET POST PUT> Require valid-user </Limit> <FilesMatch "\.(htaccess|passwd|config|bak)$"> Order Allow,Deny Deny from all </FilesMatch> Then in each repository, I've got a .hg/hgrc file requiring a valid user [web] allow_push = <comma seperated user list> This almost does what I need. The problem is that I need to add ALL my clients to hgweb.passwd, which gives them clone access to ALL of the repositories. The only solution I can think of is to have another .htaccess and .passwd file in EACH repository. I don't really want to do that though, seems a little convoluted. I can already specify a list of authorized users for each repository in that repos' hgrc file with the allow_push setting. If only there were an allow_clone setting as well... All the documentation I've found for hgwebdir.cgi is incomplete. I've read: http://mercurial.selenic.com/wiki/HgWebDirStepByStep http://hgbook.red-bean.com/read/collaborating-with-other-people.html#sec:collab:cgi http://hgbook.red-bean.com/read/collaborating-with-other-people.html And others. I've yet to find a comprehensive list of hgrc settings. I guess this is as much an Apache question than a mercurial question. Unless I can find a better approach, I'll be going with a seperate .htaccess and .passwd file for each repo. This is a virtual host on Webfaction if it matters - set up roughly like this http://docs.webfaction.com/software/mercurial.html

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